\(\int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx\) [860]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [B] (verification not implemented)
Sympy [F(-1)]
Maxima [A] (verification not implemented)
Giac [A] (verification not implemented)
Mupad [B] (verification not implemented)
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 27, antiderivative size = 174 \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {3 a \csc (c+d x)}{d}-\frac {a \csc ^2(c+d x)}{2 d}-\frac {a \csc ^3(c+d x)}{3 d}-\frac {59 a \log (1-\sin (c+d x))}{16 d}+\frac {3 a \log (\sin (c+d x))}{d}+\frac {11 a \log (1+\sin (c+d x))}{16 d}+\frac {a^5}{8 d \left (a^2-a^2 \sin (c+d x)\right )^2}+\frac {5 a^5}{4 d \left (a^4-a^4 \sin (c+d x)\right )}-\frac {a^5}{8 d \left (a^4+a^4 \sin (c+d x)\right )} \] Output:

-3*a*csc(d*x+c)/d-1/2*a*csc(d*x+c)^2/d-1/3*a*csc(d*x+c)^3/d-59/16*a*ln(1-s 
in(d*x+c))/d+3*a*ln(sin(d*x+c))/d+11/16*a*ln(1+sin(d*x+c))/d+1/8*a^5/d/(a^ 
2-a^2*sin(d*x+c))^2+5/4*a^5/d/(a^4-a^4*sin(d*x+c))-1/8*a^5/d/(a^4+a^4*sin( 
d*x+c))
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.02 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.60 \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {a \csc ^2(c+d x)}{2 d}-\frac {a \csc ^3(c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {3}{2},3,-\frac {1}{2},\sin ^2(c+d x)\right )}{3 d}-\frac {3 a \log (\cos (c+d x))}{d}+\frac {3 a \log (\sin (c+d x))}{d}+\frac {a \sec ^2(c+d x)}{d}+\frac {a \sec ^4(c+d x)}{4 d} \] Input:

Integrate[Csc[c + d*x]^4*Sec[c + d*x]^5*(a + a*Sin[c + d*x]),x]
 

Output:

-1/2*(a*Csc[c + d*x]^2)/d - (a*Csc[c + d*x]^3*Hypergeometric2F1[-3/2, 3, - 
1/2, Sin[c + d*x]^2])/(3*d) - (3*a*Log[Cos[c + d*x]])/d + (3*a*Log[Sin[c + 
 d*x]])/d + (a*Sec[c + d*x]^2)/d + (a*Sec[c + d*x]^4)/(4*d)
 

Rubi [A] (verified)

Time = 0.36 (sec) , antiderivative size = 159, normalized size of antiderivative = 0.91, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {3042, 3315, 27, 99, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \csc ^4(c+d x) \sec ^5(c+d x) (a \sin (c+d x)+a) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {a \sin (c+d x)+a}{\sin (c+d x)^4 \cos (c+d x)^5}dx\)

\(\Big \downarrow \) 3315

\(\displaystyle \frac {a^5 \int \frac {\csc ^4(c+d x)}{(a-a \sin (c+d x))^3 (\sin (c+d x) a+a)^2}d(a \sin (c+d x))}{d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {a^9 \int \frac {\csc ^4(c+d x)}{a^4 (a-a \sin (c+d x))^3 (\sin (c+d x) a+a)^2}d(a \sin (c+d x))}{d}\)

\(\Big \downarrow \) 99

\(\displaystyle \frac {a^9 \int \left (\frac {\csc ^4(c+d x)}{a^9}+\frac {\csc ^3(c+d x)}{a^9}+\frac {3 \csc ^2(c+d x)}{a^9}+\frac {3 \csc (c+d x)}{a^9}+\frac {59}{16 a^8 (a-a \sin (c+d x))}+\frac {11}{16 a^8 (\sin (c+d x) a+a)}+\frac {5}{4 a^7 (a-a \sin (c+d x))^2}+\frac {1}{8 a^7 (\sin (c+d x) a+a)^2}+\frac {1}{4 a^6 (a-a \sin (c+d x))^3}\right )d(a \sin (c+d x))}{d}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {a^9 \left (-\frac {\csc ^3(c+d x)}{3 a^8}-\frac {\csc ^2(c+d x)}{2 a^8}-\frac {3 \csc (c+d x)}{a^8}+\frac {3 \log (a \sin (c+d x))}{a^8}-\frac {59 \log (a-a \sin (c+d x))}{16 a^8}+\frac {11 \log (a \sin (c+d x)+a)}{16 a^8}+\frac {5}{4 a^7 (a-a \sin (c+d x))}-\frac {1}{8 a^7 (a \sin (c+d x)+a)}+\frac {1}{8 a^6 (a-a \sin (c+d x))^2}\right )}{d}\)

Input:

Int[Csc[c + d*x]^4*Sec[c + d*x]^5*(a + a*Sin[c + d*x]),x]
 

Output:

(a^9*((-3*Csc[c + d*x])/a^8 - Csc[c + d*x]^2/(2*a^8) - Csc[c + d*x]^3/(3*a 
^8) + (3*Log[a*Sin[c + d*x]])/a^8 - (59*Log[a - a*Sin[c + d*x]])/(16*a^8) 
+ (11*Log[a + a*Sin[c + d*x]])/(16*a^8) + 1/(8*a^6*(a - a*Sin[c + d*x])^2) 
 + 5/(4*a^7*(a - a*Sin[c + d*x])) - 1/(8*a^7*(a + a*Sin[c + d*x]))))/d
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 99
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], 
 x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | 
| (GtQ[m, 0] && GeQ[n, -1]))
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3315
Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_ 
.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Simp[1/(b^p* 
f)   Subst[Int[(a + x)^(m + (p - 1)/2)*(a - x)^((p - 1)/2)*(c + (d/b)*x)^n, 
 x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, c, d, m, n}, x] && Intege 
rQ[(p - 1)/2] && EqQ[a^2 - b^2, 0]
 
Maple [A] (verified)

Time = 1.06 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.84

method result size
derivativedivides \(\frac {a \left (\frac {1}{4 \sin \left (d x +c \right )^{2} \cos \left (d x +c \right )^{4}}+\frac {3}{4 \sin \left (d x +c \right )^{2} \cos \left (d x +c \right )^{2}}-\frac {3}{2 \sin \left (d x +c \right )^{2}}+3 \ln \left (\tan \left (d x +c \right )\right )\right )+a \left (\frac {1}{4 \sin \left (d x +c \right )^{3} \cos \left (d x +c \right )^{4}}-\frac {7}{12 \sin \left (d x +c \right )^{3} \cos \left (d x +c \right )^{2}}+\frac {35}{24 \sin \left (d x +c \right ) \cos \left (d x +c \right )^{2}}-\frac {35}{8 \sin \left (d x +c \right )}+\frac {35 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}\) \(147\)
default \(\frac {a \left (\frac {1}{4 \sin \left (d x +c \right )^{2} \cos \left (d x +c \right )^{4}}+\frac {3}{4 \sin \left (d x +c \right )^{2} \cos \left (d x +c \right )^{2}}-\frac {3}{2 \sin \left (d x +c \right )^{2}}+3 \ln \left (\tan \left (d x +c \right )\right )\right )+a \left (\frac {1}{4 \sin \left (d x +c \right )^{3} \cos \left (d x +c \right )^{4}}-\frac {7}{12 \sin \left (d x +c \right )^{3} \cos \left (d x +c \right )^{2}}+\frac {35}{24 \sin \left (d x +c \right ) \cos \left (d x +c \right )^{2}}-\frac {35}{8 \sin \left (d x +c \right )}+\frac {35 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}\) \(147\)
risch \(-\frac {i a \left (-138 i {\mathrm e}^{10 i \left (d x +c \right )}+105 \,{\mathrm e}^{11 i \left (d x +c \right )}+136 i {\mathrm e}^{8 i \left (d x +c \right )}-101 \,{\mathrm e}^{9 i \left (d x +c \right )}+260 i {\mathrm e}^{6 i \left (d x +c \right )}-158 \,{\mathrm e}^{7 i \left (d x +c \right )}+136 i {\mathrm e}^{4 i \left (d x +c \right )}+158 \,{\mathrm e}^{5 i \left (d x +c \right )}-138 i {\mathrm e}^{2 i \left (d x +c \right )}+101 \,{\mathrm e}^{3 i \left (d x +c \right )}-105 \,{\mathrm e}^{i \left (d x +c \right )}\right )}{12 \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{3} \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{2} \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )^{4} d}+\frac {11 a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{8 d}-\frac {59 a \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{8 d}+\frac {3 a \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}\) \(233\)
parallelrisch \(-\frac {\left (59 \left (2-\sin \left (3 d x +3 c \right )-\sin \left (d x +c \right )+2 \cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+11 \left (-2+\sin \left (d x +c \right )+\sin \left (3 d x +3 c \right )-2 \cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+24 \left (-2+\sin \left (d x +c \right )+\sin \left (3 d x +3 c \right )-2 \cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\frac {4 \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+26 \sec \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \csc \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3}+\left (\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right )+\frac {\cos \left (\frac {3 d x}{2}+\frac {3 c}{2}\right )}{12}+\frac {\cos \left (\frac {5 d x}{2}+\frac {5 c}{2}\right )}{12}+\frac {\cos \left (\frac {7 d x}{2}+\frac {7 c}{2}\right )}{12}+\frac {\cos \left (\frac {9 d x}{2}+\frac {9 c}{2}\right )}{12}\right ) \sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}-488 \cot \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \csc \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-\frac {2195 \left (\cos \left (d x +c \right )-\frac {606 \cos \left (2 d x +2 c \right )}{2195}+\frac {101 \cos \left (3 d x +3 c \right )}{2195}-\frac {610}{439}\right ) \cot \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3}\right ) a}{8 d \left (2-\sin \left (3 d x +3 c \right )-\sin \left (d x +c \right )+2 \cos \left (2 d x +2 c \right )\right )}\) \(339\)

Input:

int(csc(d*x+c)^4*sec(d*x+c)^5*(a+a*sin(d*x+c)),x,method=_RETURNVERBOSE)
 

Output:

1/d*(a*(1/4/sin(d*x+c)^2/cos(d*x+c)^4+3/4/sin(d*x+c)^2/cos(d*x+c)^2-3/2/si 
n(d*x+c)^2+3*ln(tan(d*x+c)))+a*(1/4/sin(d*x+c)^3/cos(d*x+c)^4-7/12/sin(d*x 
+c)^3/cos(d*x+c)^2+35/24/sin(d*x+c)/cos(d*x+c)^2-35/8/sin(d*x+c)+35/8*ln(s 
ec(d*x+c)+tan(d*x+c))))
 

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 343 vs. \(2 (162) = 324\).

Time = 0.09 (sec) , antiderivative size = 343, normalized size of antiderivative = 1.97 \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {138 \, a \cos \left (d x + c\right )^{4} - 172 \, a \cos \left (d x + c\right )^{2} - 144 \, {\left (a \cos \left (d x + c\right )^{6} - 2 \, a \cos \left (d x + c\right )^{4} + a \cos \left (d x + c\right )^{2} + {\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right ) - 33 \, {\left (a \cos \left (d x + c\right )^{6} - 2 \, a \cos \left (d x + c\right )^{4} + a \cos \left (d x + c\right )^{2} + {\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 177 \, {\left (a \cos \left (d x + c\right )^{6} - 2 \, a \cos \left (d x + c\right )^{4} + a \cos \left (d x + c\right )^{2} + {\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (105 \, a \cos \left (d x + c\right )^{4} - 104 \, a \cos \left (d x + c\right )^{2} + 3 \, a\right )} \sin \left (d x + c\right ) + 18 \, a}{48 \, {\left (d \cos \left (d x + c\right )^{6} - 2 \, d \cos \left (d x + c\right )^{4} + d \cos \left (d x + c\right )^{2} + {\left (d \cos \left (d x + c\right )^{4} - d \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )}} \] Input:

integrate(csc(d*x+c)^4*sec(d*x+c)^5*(a+a*sin(d*x+c)),x, algorithm="fricas" 
)
 

Output:

-1/48*(138*a*cos(d*x + c)^4 - 172*a*cos(d*x + c)^2 - 144*(a*cos(d*x + c)^6 
 - 2*a*cos(d*x + c)^4 + a*cos(d*x + c)^2 + (a*cos(d*x + c)^4 - a*cos(d*x + 
 c)^2)*sin(d*x + c))*log(1/2*sin(d*x + c)) - 33*(a*cos(d*x + c)^6 - 2*a*co 
s(d*x + c)^4 + a*cos(d*x + c)^2 + (a*cos(d*x + c)^4 - a*cos(d*x + c)^2)*si 
n(d*x + c))*log(sin(d*x + c) + 1) + 177*(a*cos(d*x + c)^6 - 2*a*cos(d*x + 
c)^4 + a*cos(d*x + c)^2 + (a*cos(d*x + c)^4 - a*cos(d*x + c)^2)*sin(d*x + 
c))*log(-sin(d*x + c) + 1) - 2*(105*a*cos(d*x + c)^4 - 104*a*cos(d*x + c)^ 
2 + 3*a)*sin(d*x + c) + 18*a)/(d*cos(d*x + c)^6 - 2*d*cos(d*x + c)^4 + d*c 
os(d*x + c)^2 + (d*cos(d*x + c)^4 - d*cos(d*x + c)^2)*sin(d*x + c))
 

Sympy [F(-1)]

Timed out. \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=\text {Timed out} \] Input:

integrate(csc(d*x+c)**4*sec(d*x+c)**5*(a+a*sin(d*x+c)),x)
 

Output:

Timed out
 

Maxima [A] (verification not implemented)

Time = 0.03 (sec) , antiderivative size = 138, normalized size of antiderivative = 0.79 \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=\frac {33 \, a \log \left (\sin \left (d x + c\right ) + 1\right ) - 177 \, a \log \left (\sin \left (d x + c\right ) - 1\right ) + 144 \, a \log \left (\sin \left (d x + c\right )\right ) - \frac {2 \, {\left (105 \, a \sin \left (d x + c\right )^{5} - 69 \, a \sin \left (d x + c\right )^{4} - 106 \, a \sin \left (d x + c\right )^{3} + 52 \, a \sin \left (d x + c\right )^{2} + 4 \, a \sin \left (d x + c\right ) + 8 \, a\right )}}{\sin \left (d x + c\right )^{6} - \sin \left (d x + c\right )^{5} - \sin \left (d x + c\right )^{4} + \sin \left (d x + c\right )^{3}}}{48 \, d} \] Input:

integrate(csc(d*x+c)^4*sec(d*x+c)^5*(a+a*sin(d*x+c)),x, algorithm="maxima" 
)
 

Output:

1/48*(33*a*log(sin(d*x + c) + 1) - 177*a*log(sin(d*x + c) - 1) + 144*a*log 
(sin(d*x + c)) - 2*(105*a*sin(d*x + c)^5 - 69*a*sin(d*x + c)^4 - 106*a*sin 
(d*x + c)^3 + 52*a*sin(d*x + c)^2 + 4*a*sin(d*x + c) + 8*a)/(sin(d*x + c)^ 
6 - sin(d*x + c)^5 - sin(d*x + c)^4 + sin(d*x + c)^3))/d
 

Giac [A] (verification not implemented)

Time = 0.13 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.75 \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=\frac {1}{48} \, a {\left (\frac {33 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{d} - \frac {177 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{d} + \frac {144 \, \log \left ({\left | \sin \left (d x + c\right ) \right |}\right )}{d} - \frac {2 \, {\left (105 \, \sin \left (d x + c\right )^{5} - 69 \, \sin \left (d x + c\right )^{4} - 106 \, \sin \left (d x + c\right )^{3} + 52 \, \sin \left (d x + c\right )^{2} + 4 \, \sin \left (d x + c\right ) + 8\right )}}{d {\left (\sin \left (d x + c\right ) + 1\right )} {\left (\sin \left (d x + c\right ) - 1\right )}^{2} \sin \left (d x + c\right )^{3}}\right )} \] Input:

integrate(csc(d*x+c)^4*sec(d*x+c)^5*(a+a*sin(d*x+c)),x, algorithm="giac")
 

Output:

1/48*a*(33*log(abs(sin(d*x + c) + 1))/d - 177*log(abs(sin(d*x + c) - 1))/d 
 + 144*log(abs(sin(d*x + c)))/d - 2*(105*sin(d*x + c)^5 - 69*sin(d*x + c)^ 
4 - 106*sin(d*x + c)^3 + 52*sin(d*x + c)^2 + 4*sin(d*x + c) + 8)/(d*(sin(d 
*x + c) + 1)*(sin(d*x + c) - 1)^2*sin(d*x + c)^3))
 

Mupad [B] (verification not implemented)

Time = 26.92 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.83 \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=\frac {3\,a\,\ln \left (\sin \left (c+d\,x\right )\right )}{d}-\frac {\frac {35\,a\,{\sin \left (c+d\,x\right )}^5}{8}-\frac {23\,a\,{\sin \left (c+d\,x\right )}^4}{8}-\frac {53\,a\,{\sin \left (c+d\,x\right )}^3}{12}+\frac {13\,a\,{\sin \left (c+d\,x\right )}^2}{6}+\frac {a\,\sin \left (c+d\,x\right )}{6}+\frac {a}{3}}{d\,\left ({\sin \left (c+d\,x\right )}^6-{\sin \left (c+d\,x\right )}^5-{\sin \left (c+d\,x\right )}^4+{\sin \left (c+d\,x\right )}^3\right )}-\frac {59\,a\,\ln \left (\sin \left (c+d\,x\right )-1\right )}{16\,d}+\frac {11\,a\,\ln \left (\sin \left (c+d\,x\right )+1\right )}{16\,d} \] Input:

int((a + a*sin(c + d*x))/(cos(c + d*x)^5*sin(c + d*x)^4),x)
 

Output:

(3*a*log(sin(c + d*x)))/d - (a/3 + (a*sin(c + d*x))/6 + (13*a*sin(c + d*x) 
^2)/6 - (53*a*sin(c + d*x)^3)/12 - (23*a*sin(c + d*x)^4)/8 + (35*a*sin(c + 
 d*x)^5)/8)/(d*(sin(c + d*x)^3 - sin(c + d*x)^4 - sin(c + d*x)^5 + sin(c + 
 d*x)^6)) - (59*a*log(sin(c + d*x) - 1))/(16*d) + (11*a*log(sin(c + d*x) + 
 1))/(16*d)
 

Reduce [B] (verification not implemented)

Time = 0.18 (sec) , antiderivative size = 360, normalized size of antiderivative = 2.07 \[ \int \csc ^4(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx=\frac {a \left (-354 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \sin \left (d x +c \right )^{6}+354 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \sin \left (d x +c \right )^{5}+354 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \sin \left (d x +c \right )^{4}-354 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \sin \left (d x +c \right )^{3}+66 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \sin \left (d x +c \right )^{6}-66 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \sin \left (d x +c \right )^{5}-66 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \sin \left (d x +c \right )^{4}+66 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \sin \left (d x +c \right )^{3}+144 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{6}-144 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{5}-144 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{4}+144 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{3}+19 \sin \left (d x +c \right )^{6}-229 \sin \left (d x +c \right )^{5}+119 \sin \left (d x +c \right )^{4}+231 \sin \left (d x +c \right )^{3}-104 \sin \left (d x +c \right )^{2}-8 \sin \left (d x +c \right )-16\right )}{48 \sin \left (d x +c \right )^{3} d \left (\sin \left (d x +c \right )^{3}-\sin \left (d x +c \right )^{2}-\sin \left (d x +c \right )+1\right )} \] Input:

int(csc(d*x+c)^4*sec(d*x+c)^5*(a+a*sin(d*x+c)),x)
 

Output:

(a*( - 354*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**6 + 354*log(tan((c + d* 
x)/2) - 1)*sin(c + d*x)**5 + 354*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**4 
 - 354*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**3 + 66*log(tan((c + d*x)/2) 
 + 1)*sin(c + d*x)**6 - 66*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**5 - 66* 
log(tan((c + d*x)/2) + 1)*sin(c + d*x)**4 + 66*log(tan((c + d*x)/2) + 1)*s 
in(c + d*x)**3 + 144*log(tan((c + d*x)/2))*sin(c + d*x)**6 - 144*log(tan(( 
c + d*x)/2))*sin(c + d*x)**5 - 144*log(tan((c + d*x)/2))*sin(c + d*x)**4 + 
 144*log(tan((c + d*x)/2))*sin(c + d*x)**3 + 19*sin(c + d*x)**6 - 229*sin( 
c + d*x)**5 + 119*sin(c + d*x)**4 + 231*sin(c + d*x)**3 - 104*sin(c + d*x) 
**2 - 8*sin(c + d*x) - 16))/(48*sin(c + d*x)**3*d*(sin(c + d*x)**3 - sin(c 
 + d*x)**2 - sin(c + d*x) + 1))