Integrand size = 12, antiderivative size = 72 \[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx=\frac {b \cos (x) \sin (x)}{a (a+b) \sqrt {a+b \sin ^2(x)}}+\frac {E\left (x\left |-\frac {b}{a}\right .\right ) \sqrt {a+b \sin ^2(x)}}{a (a+b) \sqrt {\frac {a+b \sin ^2(x)}{a}}} \] Output:
b*cos(x)*sin(x)/a/(a+b)/(a+b*sin(x)^2)^(1/2)+EllipticE(sin(x),(-b/a)^(1/2) )*(a+b*sin(x)^2)^(1/2)/a/(a+b)/((a+b*sin(x)^2)/a)^(1/2)
Time = 0.13 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.99 \[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx=\frac {2 a \sqrt {\frac {2 a+b-b \cos (2 x)}{a}} E\left (x\left |-\frac {b}{a}\right .\right )+\sqrt {2} b \sin (2 x)}{2 a (a+b) \sqrt {2 a+b-b \cos (2 x)}} \] Input:
Integrate[(a + b*Sin[x]^2)^(-3/2),x]
Output:
(2*a*Sqrt[(2*a + b - b*Cos[2*x])/a]*EllipticE[x, -(b/a)] + Sqrt[2]*b*Sin[2 *x])/(2*a*(a + b)*Sqrt[2*a + b - b*Cos[2*x]])
Time = 0.36 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.99, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {3042, 3663, 25, 3042, 3657, 3042, 3656}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {1}{\left (a+b \sin (x)^2\right )^{3/2}}dx\) |
\(\Big \downarrow \) 3663 |
\(\displaystyle \frac {b \sin (x) \cos (x)}{a (a+b) \sqrt {a+b \sin ^2(x)}}-\frac {\int -\sqrt {b \sin ^2(x)+a}dx}{a (a+b)}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {\int \sqrt {b \sin ^2(x)+a}dx}{a (a+b)}+\frac {b \sin (x) \cos (x)}{a (a+b) \sqrt {a+b \sin ^2(x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {\int \sqrt {b \sin (x)^2+a}dx}{a (a+b)}+\frac {b \sin (x) \cos (x)}{a (a+b) \sqrt {a+b \sin ^2(x)}}\) |
\(\Big \downarrow \) 3657 |
\(\displaystyle \frac {\sqrt {a+b \sin ^2(x)} \int \sqrt {\frac {b \sin ^2(x)}{a}+1}dx}{a (a+b) \sqrt {\frac {b \sin ^2(x)}{a}+1}}+\frac {b \sin (x) \cos (x)}{a (a+b) \sqrt {a+b \sin ^2(x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {\sqrt {a+b \sin ^2(x)} \int \sqrt {\frac {b \sin (x)^2}{a}+1}dx}{a (a+b) \sqrt {\frac {b \sin ^2(x)}{a}+1}}+\frac {b \sin (x) \cos (x)}{a (a+b) \sqrt {a+b \sin ^2(x)}}\) |
\(\Big \downarrow \) 3656 |
\(\displaystyle \frac {b \sin (x) \cos (x)}{a (a+b) \sqrt {a+b \sin ^2(x)}}+\frac {\sqrt {a+b \sin ^2(x)} E\left (x\left |-\frac {b}{a}\right .\right )}{a (a+b) \sqrt {\frac {b \sin ^2(x)}{a}+1}}\) |
Input:
Int[(a + b*Sin[x]^2)^(-3/2),x]
Output:
(b*Cos[x]*Sin[x])/(a*(a + b)*Sqrt[a + b*Sin[x]^2]) + (EllipticE[x, -(b/a)] *Sqrt[a + b*Sin[x]^2])/(a*(a + b)*Sqrt[1 + (b*Sin[x]^2)/a])
Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2], x_Symbol] :> Simp[(Sqrt[a ]/f)*EllipticE[e + f*x, -b/a], x] /; FreeQ[{a, b, e, f}, x] && GtQ[a, 0]
Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2], x_Symbol] :> Simp[Sqrt[a + b*Sin[e + f*x]^2]/Sqrt[1 + b*(Sin[e + f*x]^2/a)] Int[Sqrt[1 + (b*Sin[e + f*x]^2)/a], x], x] /; FreeQ[{a, b, e, f}, x] && !GtQ[a, 0]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2)^(p_), x_Symbol] :> Simp[(-b)*C os[e + f*x]*Sin[e + f*x]*((a + b*Sin[e + f*x]^2)^(p + 1)/(2*a*f*(p + 1)*(a + b))), x] + Simp[1/(2*a*(p + 1)*(a + b)) Int[(a + b*Sin[e + f*x]^2)^(p + 1)*Simp[2*a*(p + 1) + b*(2*p + 3) - 2*b*(p + 2)*Sin[e + f*x]^2, x], x], x] /; FreeQ[{a, b, e, f}, x] && NeQ[a + b, 0] && LtQ[p, -1]
Time = 0.81 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.00
method | result | size |
default | \(\frac {\sqrt {\frac {\cos \left (2 x \right )}{2}+\frac {1}{2}}\, \sqrt {-\frac {b \cos \left (x \right )^{2}}{a}+\frac {a +b}{a}}\, a \operatorname {EllipticE}\left (\sin \left (x \right ), \sqrt {-\frac {b}{a}}\right )+b \cos \left (x \right )^{2} \sin \left (x \right )}{a \left (a +b \right ) \cos \left (x \right ) \sqrt {a +b \sin \left (x \right )^{2}}}\) | \(72\) |
Input:
int(1/(a+b*sin(x)^2)^(3/2),x,method=_RETURNVERBOSE)
Output:
((cos(x)^2)^(1/2)*(-b/a*cos(x)^2+(a+b)/a)^(1/2)*a*EllipticE(sin(x),(-b/a)^ (1/2))+b*cos(x)^2*sin(x))/a/(a+b)/cos(x)/(a+b*sin(x)^2)^(1/2)
Result contains complex when optimal does not.
Time = 0.13 (sec) , antiderivative size = 854, normalized size of antiderivative = 11.86 \[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx =\text {Too large to display} \] Input:
integrate(1/(a+b*sin(x)^2)^(3/2),x, algorithm="fricas")
Output:
1/2*(2*sqrt(-b*cos(x)^2 + a + b)*b^3*cos(x)*sin(x) - (2*(I*b^3*cos(x)^2 - I*a*b^2 - I*b^3)*sqrt(-b)*sqrt((a^2 + a*b)/b^2) - (2*I*a^2*b + 3*I*a*b^2 + I*b^3 + (-2*I*a*b^2 - I*b^3)*cos(x)^2)*sqrt(-b))*sqrt((2*b*sqrt((a^2 + a* b)/b^2) + 2*a + b)/b)*elliptic_e(arcsin(sqrt((2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b)*(cos(x) + I*sin(x))), (8*a^2 + 8*a*b + b^2 - 4*(2*a*b + b^2)*s qrt((a^2 + a*b)/b^2))/b^2) - (2*(-I*b^3*cos(x)^2 + I*a*b^2 + I*b^3)*sqrt(- b)*sqrt((a^2 + a*b)/b^2) - (-2*I*a^2*b - 3*I*a*b^2 - I*b^3 + (2*I*a*b^2 + I*b^3)*cos(x)^2)*sqrt(-b))*sqrt((2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b)*e lliptic_e(arcsin(sqrt((2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b)*(cos(x) - I *sin(x))), (8*a^2 + 8*a*b + b^2 - 4*(2*a*b + b^2)*sqrt((a^2 + a*b)/b^2))/b ^2) + 2*(2*(-I*a^2*b - 2*I*a*b^2 - I*b^3 + (I*a*b^2 + I*b^3)*cos(x)^2)*sqr t(-b)*sqrt((a^2 + a*b)/b^2) + (2*I*a^3 + 3*I*a^2*b + I*a*b^2 + (-2*I*a^2*b - I*a*b^2)*cos(x)^2)*sqrt(-b))*sqrt((2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b) /b)*elliptic_f(arcsin(sqrt((2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b)*(cos(x ) + I*sin(x))), (8*a^2 + 8*a*b + b^2 - 4*(2*a*b + b^2)*sqrt((a^2 + a*b)/b^ 2))/b^2) + 2*(2*(I*a^2*b + 2*I*a*b^2 + I*b^3 + (-I*a*b^2 - I*b^3)*cos(x)^2 )*sqrt(-b)*sqrt((a^2 + a*b)/b^2) + (-2*I*a^3 - 3*I*a^2*b - I*a*b^2 + (2*I* a^2*b + I*a*b^2)*cos(x)^2)*sqrt(-b))*sqrt((2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b)*elliptic_f(arcsin(sqrt((2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b)*( cos(x) - I*sin(x))), (8*a^2 + 8*a*b + b^2 - 4*(2*a*b + b^2)*sqrt((a^2 +...
\[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx=\int \frac {1}{\left (a + b \sin ^{2}{\left (x \right )}\right )^{\frac {3}{2}}}\, dx \] Input:
integrate(1/(a+b*sin(x)**2)**(3/2),x)
Output:
Integral((a + b*sin(x)**2)**(-3/2), x)
\[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx=\int { \frac {1}{{\left (b \sin \left (x\right )^{2} + a\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate(1/(a+b*sin(x)^2)^(3/2),x, algorithm="maxima")
Output:
integrate((b*sin(x)^2 + a)^(-3/2), x)
\[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx=\int { \frac {1}{{\left (b \sin \left (x\right )^{2} + a\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate(1/(a+b*sin(x)^2)^(3/2),x, algorithm="giac")
Output:
integrate((b*sin(x)^2 + a)^(-3/2), x)
Timed out. \[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx=\int \frac {1}{{\left (b\,{\sin \left (x\right )}^2+a\right )}^{3/2}} \,d x \] Input:
int(1/(a + b*sin(x)^2)^(3/2),x)
Output:
int(1/(a + b*sin(x)^2)^(3/2), x)
\[ \int \frac {1}{\left (a+b \sin ^2(x)\right )^{3/2}} \, dx=\int \frac {\sqrt {\sin \left (x \right )^{2} b +a}}{\sin \left (x \right )^{4} b^{2}+2 \sin \left (x \right )^{2} a b +a^{2}}d x \] Input:
int(1/(a+b*sin(x)^2)^(3/2),x)
Output:
int(sqrt(sin(x)**2*b + a)/(sin(x)**4*b**2 + 2*sin(x)**2*a*b + a**2),x)