\(\int \frac {\sec ^2(c+d x)}{(a+b \sin ^3(c+d x))^2} \, dx\) [335]

Optimal result
Mathematica [C] (warning: unable to verify)
Rubi [N/A]
Maple [N/A] (verified)
Fricas [C] (verification not implemented)
Sympy [F(-1)]
Maxima [F(-2)]
Giac [N/A]
Mupad [B] (verification not implemented)
Reduce [N/A]

Optimal result

Integrand size = 23, antiderivative size = 23 \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx=\text {Int}\left (\frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2},x\right ) \] Output:

Defer(Int)(sec(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x)
 

Mathematica [C] (warning: unable to verify)

Result contains complex when optimal does not.

Time = 2.53 (sec) , antiderivative size = 845, normalized size of antiderivative = 36.74 \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx =\text {Too large to display} \] Input:

Integrate[Sec[c + d*x]^2/(a + b*Sin[c + d*x]^3)^2,x]
 

Output:

(((-I)*b*RootSum[(-I)*b + (3*I)*b*#1^2 + 8*a*#1^3 - (3*I)*b*#1^4 + I*b*#1^ 
6 & , (16*a^2*b*ArcTan[Sin[c + d*x]/(Cos[c + d*x] - #1)] + 2*b^3*ArcTan[Si 
n[c + d*x]/(Cos[c + d*x] - #1)] - (8*I)*a^2*b*Log[1 - 2*Cos[c + d*x]*#1 + 
#1^2] - I*b^3*Log[1 - 2*Cos[c + d*x]*#1 + #1^2] + (20*I)*a^3*ArcTan[Sin[c 
+ d*x]/(Cos[c + d*x] - #1)]*#1 + (16*I)*a*b^2*ArcTan[Sin[c + d*x]/(Cos[c + 
 d*x] - #1)]*#1 + 10*a^3*Log[1 - 2*Cos[c + d*x]*#1 + #1^2]*#1 + 8*a*b^2*Lo 
g[1 - 2*Cos[c + d*x]*#1 + #1^2]*#1 - 120*a^2*b*ArcTan[Sin[c + d*x]/(Cos[c 
+ d*x] - #1)]*#1^2 + 12*b^3*ArcTan[Sin[c + d*x]/(Cos[c + d*x] - #1)]*#1^2 
+ (60*I)*a^2*b*Log[1 - 2*Cos[c + d*x]*#1 + #1^2]*#1^2 - (6*I)*b^3*Log[1 - 
2*Cos[c + d*x]*#1 + #1^2]*#1^2 - (20*I)*a^3*ArcTan[Sin[c + d*x]/(Cos[c + d 
*x] - #1)]*#1^3 - (16*I)*a*b^2*ArcTan[Sin[c + d*x]/(Cos[c + d*x] - #1)]*#1 
^3 - 10*a^3*Log[1 - 2*Cos[c + d*x]*#1 + #1^2]*#1^3 - 8*a*b^2*Log[1 - 2*Cos 
[c + d*x]*#1 + #1^2]*#1^3 + 16*a^2*b*ArcTan[Sin[c + d*x]/(Cos[c + d*x] - # 
1)]*#1^4 + 2*b^3*ArcTan[Sin[c + d*x]/(Cos[c + d*x] - #1)]*#1^4 - (8*I)*a^2 
*b*Log[1 - 2*Cos[c + d*x]*#1 + #1^2]*#1^4 - I*b^3*Log[1 - 2*Cos[c + d*x]*# 
1 + #1^2]*#1^4)/(b*#1 - (4*I)*a*#1^2 - 2*b*#1^3 + b*#1^5) & ])/(a*(a^2 - b 
^2)^2) + (18*Sin[(c + d*x)/2])/((a + b)^2*(Cos[(c + d*x)/2] - Sin[(c + d*x 
)/2])) + (18*Sin[(c + d*x)/2])/((a - b)^2*(Cos[(c + d*x)/2] + Sin[(c + d*x 
)/2])) + (12*b*Cos[c + d*x]*(-2*a^3 - 7*a*b^2 + 3*a*b^2*Cos[2*(c + d*x)] + 
 2*b*(2*a^2 + b^2)*Sin[c + d*x]))/(a*(a - b)^2*(a + b)^2*(4*a + 3*b*Sin...
 

Rubi [N/A]

Not integrable

Time = 0.22 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {3042, 3707}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {1}{\cos (c+d x)^2 \left (a+b \sin (c+d x)^3\right )^2}dx\)

\(\Big \downarrow \) 3707

\(\displaystyle \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2}dx\)

Input:

Int[Sec[c + d*x]^2/(a + b*Sin[c + d*x]^3)^2,x]
 

Output:

$Aborted
 

Defintions of rubi rules used

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3707
Int[(cos[(e_.) + (f_.)*(x_)]*(d_.))^(m_.)*((a_) + (b_.)*((c_.)*sin[(e_.) + 
(f_.)*(x_)])^(n_))^(p_.), x_Symbol] :> Unintegrable[(d*Cos[e + f*x])^m*(a + 
 b*(c*Sin[e + f*x])^n)^p, x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x]
 
Maple [N/A] (verified)

Time = 7.60 (sec) , antiderivative size = 398, normalized size of antiderivative = 17.30

method result size
derivativedivides \(\frac {-\frac {1}{\left (a -b \right )^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}+\frac {2 b \left (\frac {-\frac {\left (2 a^{2}+b^{2}\right ) b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{3 a}+\left (-\frac {a^{2}}{3}+\frac {4 b^{2}}{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}-\frac {4 b \left (a^{2}+2 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 a}+\left (-\frac {2 a^{2}}{3}-\frac {10 b^{2}}{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+\frac {\left (2 a^{2}+b^{2}\right ) b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{3 a}-\frac {a^{2}}{3}-\frac {2 b^{2}}{3}}{a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+3 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3} b +3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a +a}+\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (a \,\textit {\_Z}^{6}+3 a \,\textit {\_Z}^{4}+8 b \,\textit {\_Z}^{3}+3 a \,\textit {\_Z}^{2}+a \right )}{\sum }\frac {\left (b \left (-11 a^{2}+2 b^{2}\right ) \textit {\_R}^{4}+2 a \left (5 a^{2}+4 b^{2}\right ) \textit {\_R}^{3}-54 a^{2} b \,\textit {\_R}^{2}+2 a \left (5 a^{2}+4 b^{2}\right ) \textit {\_R} -11 a^{2} b +2 b^{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-\textit {\_R} \right )}{\textit {\_R}^{5} a +2 \textit {\_R}^{3} a +4 \textit {\_R}^{2} b +a \textit {\_R}}}{18 a}\right )}{\left (a -b \right )^{2} \left (a +b \right )^{2}}-\frac {1}{\left (a +b \right )^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}}{d}\) \(398\)
default \(\frac {-\frac {1}{\left (a -b \right )^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}+\frac {2 b \left (\frac {-\frac {\left (2 a^{2}+b^{2}\right ) b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{3 a}+\left (-\frac {a^{2}}{3}+\frac {4 b^{2}}{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}-\frac {4 b \left (a^{2}+2 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 a}+\left (-\frac {2 a^{2}}{3}-\frac {10 b^{2}}{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+\frac {\left (2 a^{2}+b^{2}\right ) b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{3 a}-\frac {a^{2}}{3}-\frac {2 b^{2}}{3}}{a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+3 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3} b +3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a +a}+\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (a \,\textit {\_Z}^{6}+3 a \,\textit {\_Z}^{4}+8 b \,\textit {\_Z}^{3}+3 a \,\textit {\_Z}^{2}+a \right )}{\sum }\frac {\left (b \left (-11 a^{2}+2 b^{2}\right ) \textit {\_R}^{4}+2 a \left (5 a^{2}+4 b^{2}\right ) \textit {\_R}^{3}-54 a^{2} b \,\textit {\_R}^{2}+2 a \left (5 a^{2}+4 b^{2}\right ) \textit {\_R} -11 a^{2} b +2 b^{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-\textit {\_R} \right )}{\textit {\_R}^{5} a +2 \textit {\_R}^{3} a +4 \textit {\_R}^{2} b +a \textit {\_R}}}{18 a}\right )}{\left (a -b \right )^{2} \left (a +b \right )^{2}}-\frac {1}{\left (a +b \right )^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}}{d}\) \(398\)
risch \(\text {Expression too large to display}\) \(5261\)

Input:

int(sec(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x,method=_RETURNVERBOSE)
 

Output:

1/d*(-1/(a-b)^2/(tan(1/2*d*x+1/2*c)+1)+2*b/(a-b)^2/(a+b)^2*((-1/3*(2*a^2+b 
^2)*b/a*tan(1/2*d*x+1/2*c)^5+(-1/3*a^2+4/3*b^2)*tan(1/2*d*x+1/2*c)^4-4/3*b 
*(a^2+2*b^2)/a*tan(1/2*d*x+1/2*c)^3+(-2/3*a^2-10/3*b^2)*tan(1/2*d*x+1/2*c) 
^2+1/3*(2*a^2+b^2)*b/a*tan(1/2*d*x+1/2*c)-1/3*a^2-2/3*b^2)/(a*tan(1/2*d*x+ 
1/2*c)^6+3*a*tan(1/2*d*x+1/2*c)^4+8*tan(1/2*d*x+1/2*c)^3*b+3*tan(1/2*d*x+1 
/2*c)^2*a+a)+1/18/a*sum((b*(-11*a^2+2*b^2)*_R^4+2*a*(5*a^2+4*b^2)*_R^3-54* 
a^2*b*_R^2+2*a*(5*a^2+4*b^2)*_R-11*a^2*b+2*b^3)/(_R^5*a+2*_R^3*a+4*_R^2*b+ 
_R*a)*ln(tan(1/2*d*x+1/2*c)-_R),_R=RootOf(_Z^6*a+3*_Z^4*a+8*_Z^3*b+3*_Z^2* 
a+a)))-1/(a+b)^2/(tan(1/2*d*x+1/2*c)-1))
 

Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 3 vs. order 1.

Time = 40.61 (sec) , antiderivative size = 102913, normalized size of antiderivative = 4474.48 \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx=\text {Too large to display} \] Input:

integrate(sec(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x, algorithm="fricas")
 

Output:

Too large to include
 

Sympy [F(-1)]

Timed out. \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx=\text {Timed out} \] Input:

integrate(sec(d*x+c)**2/(a+b*sin(d*x+c)**3)**2,x)
                                                                                    
                                                                                    
 

Output:

Timed out
 

Maxima [F(-2)]

Exception generated. \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx=\text {Exception raised: RuntimeError} \] Input:

integrate(sec(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x, algorithm="maxima")
 

Output:

Exception raised: RuntimeError >> ECL says: THROW: The catch RAT-ERR is un 
defined.
 

Giac [N/A]

Not integrable

Time = 3.08 (sec) , antiderivative size = 3, normalized size of antiderivative = 0.13 \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx=\int { \frac {\sec \left (d x + c\right )^{2}}{{\left (b \sin \left (d x + c\right )^{3} + a\right )}^{2}} \,d x } \] Input:

integrate(sec(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x, algorithm="giac")
 

Output:

sage0*x
 

Mupad [B] (verification not implemented)

Time = 41.90 (sec) , antiderivative size = 3148, normalized size of antiderivative = 136.87 \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx=\text {Too large to display} \] Input:

int(1/(cos(c + d*x)^2*(a + b*sin(c + d*x)^3)^2),x)
 

Output:

symsum(log(5479612416*a^8*b^36 - 180486144*a^6*b^38 - root(5314410*a^16*b^ 
4*d^6 - 5314410*a^14*b^6*d^6 - 2657205*a^18*b^2*d^6 + 2657205*a^12*b^8*d^6 
 - 531441*a^10*b^10*d^6 + 531441*a^20*d^6 + 11514555*a^12*b^4*d^4 + 206671 
5*a^14*b^2*d^4 + 1062882*a^10*b^6*d^4 - 295245*a^8*b^8*d^4 + 984150*a^8*b^ 
4*d^2 - 98415*a^6*b^6*d^2 + 15625*a^4*b^4 - 2000*a^2*b^6 + 64*b^8, d, k)*( 
tan(c/2 + (d*x)/2)*(764411904*a^6*b^40 - 27805483008*a^8*b^38 + 4372973568 
00*a^10*b^36 - 3672461721600*a^12*b^34 + 19250011791360*a^14*b^32 - 691506 
35753472*a^16*b^30 + 180165872001024*a^18*b^28 - 352655758540800*a^20*b^26 
 + 529923028377600*a^22*b^24 - 618699706859520*a^24*b^22 + 563713761042432 
*a^26*b^20 - 399760062234624*a^28*b^18 + 218398602240000*a^30*b^16 - 90108 
039168000*a^32*b^14 + 27130620764160*a^34*b^12 - 5617221156864*a^36*b^10 + 
 713536708608*a^38*b^8 - 41803776000*a^40*b^6) - root(5314410*a^16*b^4*d^6 
 - 5314410*a^14*b^6*d^6 - 2657205*a^18*b^2*d^6 + 2657205*a^12*b^8*d^6 - 53 
1441*a^10*b^10*d^6 + 531441*a^20*d^6 + 11514555*a^12*b^4*d^4 + 2066715*a^1 
4*b^2*d^4 + 1062882*a^10*b^6*d^4 - 295245*a^8*b^8*d^4 + 984150*a^8*b^4*d^2 
 - 98415*a^6*b^6*d^2 + 15625*a^4*b^4 - 2000*a^2*b^6 + 64*b^8, d, k)*(root( 
5314410*a^16*b^4*d^6 - 5314410*a^14*b^6*d^6 - 2657205*a^18*b^2*d^6 + 26572 
05*a^12*b^8*d^6 - 531441*a^10*b^10*d^6 + 531441*a^20*d^6 + 11514555*a^12*b 
^4*d^4 + 2066715*a^14*b^2*d^4 + 1062882*a^10*b^6*d^4 - 295245*a^8*b^8*d^4 
+ 984150*a^8*b^4*d^2 - 98415*a^6*b^6*d^2 + 15625*a^4*b^4 - 2000*a^2*b^6...
 

Reduce [N/A]

Not integrable

Time = 1.21 (sec) , antiderivative size = 47824, normalized size of antiderivative = 2079.30 \[ \int \frac {\sec ^2(c+d x)}{\left (a+b \sin ^3(c+d x)\right )^2} \, dx =\text {Too large to display} \] Input:

int(sec(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x)
 

Output:

(346560*cos(c + d*x)*int(tan((c + d*x)/2)**4/(19*tan((c + d*x)/2)**16*a**6 
 + 680*tan((c + d*x)/2)**16*a**4*b**2 - 240*tan((c + d*x)/2)**16*a**2*b**4 
 + 76*tan((c + d*x)/2)**14*a**6 + 2720*tan((c + d*x)/2)**14*a**4*b**2 - 96 
0*tan((c + d*x)/2)**14*a**2*b**4 + 304*tan((c + d*x)/2)**13*a**5*b + 10880 
*tan((c + d*x)/2)**13*a**3*b**3 - 3840*tan((c + d*x)/2)**13*a*b**5 + 76*ta 
n((c + d*x)/2)**12*a**6 + 2720*tan((c + d*x)/2)**12*a**4*b**2 - 960*tan((c 
 + d*x)/2)**12*a**2*b**4 + 304*tan((c + d*x)/2)**11*a**5*b + 10880*tan((c 
+ d*x)/2)**11*a**3*b**3 - 3840*tan((c + d*x)/2)**11*a*b**5 - 76*tan((c + d 
*x)/2)**10*a**6 - 1504*tan((c + d*x)/2)**10*a**4*b**2 + 44480*tan((c + d*x 
)/2)**10*a**2*b**4 - 15360*tan((c + d*x)/2)**10*b**6 - 608*tan((c + d*x)/2 
)**9*a**5*b - 21760*tan((c + d*x)/2)**9*a**3*b**3 + 7680*tan((c + d*x)/2)* 
*9*a*b**5 - 190*tan((c + d*x)/2)**8*a**6 - 9232*tan((c + d*x)/2)**8*a**4*b 
**2 - 84640*tan((c + d*x)/2)**8*a**2*b**4 + 30720*tan((c + d*x)/2)**8*b**6 
 - 608*tan((c + d*x)/2)**7*a**5*b - 21760*tan((c + d*x)/2)**7*a**3*b**3 + 
7680*tan((c + d*x)/2)**7*a*b**5 - 76*tan((c + d*x)/2)**6*a**6 - 1504*tan(( 
c + d*x)/2)**6*a**4*b**2 + 44480*tan((c + d*x)/2)**6*a**2*b**4 - 15360*tan 
((c + d*x)/2)**6*b**6 + 304*tan((c + d*x)/2)**5*a**5*b + 10880*tan((c + d* 
x)/2)**5*a**3*b**3 - 3840*tan((c + d*x)/2)**5*a*b**5 + 76*tan((c + d*x)/2) 
**4*a**6 + 2720*tan((c + d*x)/2)**4*a**4*b**2 - 960*tan((c + d*x)/2)**4*a* 
*2*b**4 + 304*tan((c + d*x)/2)**3*a**5*b + 10880*tan((c + d*x)/2)**3*a*...