\(\int \frac {\sin (c+d x)}{(a+b x^2)^3} \, dx\) [75]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [C] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 16, antiderivative size = 856 \[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx =\text {Too large to display} \] Output:

1/16*d*cos(d*x+c)/(-a)^(3/2)/b/((-a)^(1/2)-b^(1/2)*x)+1/16*d*cos(d*x+c)/(- 
a)^(3/2)/b/((-a)^(1/2)+b^(1/2)*x)-3/16*d*cos(c+(-a)^(1/2)*d/b^(1/2))*Ci((- 
a)^(1/2)*d/b^(1/2)-d*x)/a^2/b-3/16*d*cos(c-(-a)^(1/2)*d/b^(1/2))*Ci((-a)^( 
1/2)*d/b^(1/2)+d*x)/a^2/b-3/16*Ci((-a)^(1/2)*d/b^(1/2)+d*x)*sin(c-(-a)^(1/ 
2)*d/b^(1/2))/(-a)^(5/2)/b^(1/2)+1/16*d^2*Ci((-a)^(1/2)*d/b^(1/2)+d*x)*sin 
(c-(-a)^(1/2)*d/b^(1/2))/(-a)^(3/2)/b^(3/2)+3/16*Ci((-a)^(1/2)*d/b^(1/2)-d 
*x)*sin(c+(-a)^(1/2)*d/b^(1/2))/(-a)^(5/2)/b^(1/2)-1/16*d^2*Ci((-a)^(1/2)* 
d/b^(1/2)-d*x)*sin(c+(-a)^(1/2)*d/b^(1/2))/(-a)^(3/2)/b^(3/2)-1/16*sin(d*x 
+c)/(-a)^(3/2)/b^(1/2)/((-a)^(1/2)-b^(1/2)*x)^2-3/16*sin(d*x+c)/a^2/b^(1/2 
)/((-a)^(1/2)-b^(1/2)*x)+1/16*sin(d*x+c)/(-a)^(3/2)/b^(1/2)/((-a)^(1/2)+b^ 
(1/2)*x)^2+3/16*sin(d*x+c)/a^2/b^(1/2)/((-a)^(1/2)+b^(1/2)*x)+3/16*cos(c+( 
-a)^(1/2)*d/b^(1/2))*Si(-(-a)^(1/2)*d/b^(1/2)+d*x)/(-a)^(5/2)/b^(1/2)-1/16 
*d^2*cos(c+(-a)^(1/2)*d/b^(1/2))*Si(-(-a)^(1/2)*d/b^(1/2)+d*x)/(-a)^(3/2)/ 
b^(3/2)+3/16*d*sin(c+(-a)^(1/2)*d/b^(1/2))*Si(-(-a)^(1/2)*d/b^(1/2)+d*x)/a 
^2/b-3/16*cos(c-(-a)^(1/2)*d/b^(1/2))*Si((-a)^(1/2)*d/b^(1/2)+d*x)/(-a)^(5 
/2)/b^(1/2)+1/16*d^2*cos(c-(-a)^(1/2)*d/b^(1/2))*Si((-a)^(1/2)*d/b^(1/2)+d 
*x)/(-a)^(3/2)/b^(3/2)+3/16*d*sin(c-(-a)^(1/2)*d/b^(1/2))*Si((-a)^(1/2)*d/ 
b^(1/2)+d*x)/a^2/b
 

Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 5.81 (sec) , antiderivative size = 374, normalized size of antiderivative = 0.44 \[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx=\frac {e^{-i c-\frac {\sqrt {a} d}{\sqrt {b}}} \left (\left (3 b-3 \sqrt {a} \sqrt {b} d+a d^2\right ) e^{\frac {2 \sqrt {a} d}{\sqrt {b}}} \operatorname {ExpIntegralEi}\left (-\frac {\sqrt {a} d}{\sqrt {b}}-i d x\right )-\left (3 b+3 \sqrt {a} \sqrt {b} d+a d^2\right ) \operatorname {ExpIntegralEi}\left (\frac {\sqrt {a} d}{\sqrt {b}}-i d x\right )\right )+e^{i c-\frac {\sqrt {a} d}{\sqrt {b}}} \left (\left (3 b-3 \sqrt {a} \sqrt {b} d+a d^2\right ) e^{\frac {2 \sqrt {a} d}{\sqrt {b}}} \operatorname {ExpIntegralEi}\left (-\frac {\sqrt {a} d}{\sqrt {b}}+i d x\right )-\left (3 b+3 \sqrt {a} \sqrt {b} d+a d^2\right ) \operatorname {ExpIntegralEi}\left (\frac {\sqrt {a} d}{\sqrt {b}}+i d x\right )\right )+\frac {4 \sqrt {a} \sqrt {b} \cos (d x) \left (a d \left (a+b x^2\right ) \cos (c)+b x \left (5 a+3 b x^2\right ) \sin (c)\right )}{\left (a+b x^2\right )^2}-\frac {4 \sqrt {a} \sqrt {b} \left (-b x \left (5 a+3 b x^2\right ) \cos (c)+a d \left (a+b x^2\right ) \sin (c)\right ) \sin (d x)}{\left (a+b x^2\right )^2}}{32 a^{5/2} b^{3/2}} \] Input:

Integrate[Sin[c + d*x]/(a + b*x^2)^3,x]
 

Output:

(E^((-I)*c - (Sqrt[a]*d)/Sqrt[b])*((3*b - 3*Sqrt[a]*Sqrt[b]*d + a*d^2)*E^( 
(2*Sqrt[a]*d)/Sqrt[b])*ExpIntegralEi[-((Sqrt[a]*d)/Sqrt[b]) - I*d*x] - (3* 
b + 3*Sqrt[a]*Sqrt[b]*d + a*d^2)*ExpIntegralEi[(Sqrt[a]*d)/Sqrt[b] - I*d*x 
]) + E^(I*c - (Sqrt[a]*d)/Sqrt[b])*((3*b - 3*Sqrt[a]*Sqrt[b]*d + a*d^2)*E^ 
((2*Sqrt[a]*d)/Sqrt[b])*ExpIntegralEi[-((Sqrt[a]*d)/Sqrt[b]) + I*d*x] - (3 
*b + 3*Sqrt[a]*Sqrt[b]*d + a*d^2)*ExpIntegralEi[(Sqrt[a]*d)/Sqrt[b] + I*d* 
x]) + (4*Sqrt[a]*Sqrt[b]*Cos[d*x]*(a*d*(a + b*x^2)*Cos[c] + b*x*(5*a + 3*b 
*x^2)*Sin[c]))/(a + b*x^2)^2 - (4*Sqrt[a]*Sqrt[b]*(-(b*x*(5*a + 3*b*x^2)*C 
os[c]) + a*d*(a + b*x^2)*Sin[c])*Sin[d*x])/(a + b*x^2)^2)/(32*a^(5/2)*b^(3 
/2))
 

Rubi [A] (verified)

Time = 1.64 (sec) , antiderivative size = 856, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {3814, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx\)

\(\Big \downarrow \) 3814

\(\displaystyle \int \left (-\frac {3 b \sin (c+d x)}{8 a^2 \left (-a b-b^2 x^2\right )}-\frac {3 b \sin (c+d x)}{16 a^2 \left (\sqrt {-a} \sqrt {b}-b x\right )^2}-\frac {3 b \sin (c+d x)}{16 a^2 \left (\sqrt {-a} \sqrt {b}+b x\right )^2}-\frac {b^{3/2} \sin (c+d x)}{8 (-a)^{3/2} \left (\sqrt {-a} \sqrt {b}-b x\right )^3}-\frac {b^{3/2} \sin (c+d x)}{8 (-a)^{3/2} \left (\sqrt {-a} \sqrt {b}+b x\right )^3}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\operatorname {CosIntegral}\left (x d+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \sin \left (c-\frac {\sqrt {-a} d}{\sqrt {b}}\right ) d^2}{16 (-a)^{3/2} b^{3/2}}-\frac {\operatorname {CosIntegral}\left (\frac {\sqrt {-a} d}{\sqrt {b}}-d x\right ) \sin \left (c+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) d^2}{16 (-a)^{3/2} b^{3/2}}+\frac {\cos \left (c+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \text {Si}\left (\frac {\sqrt {-a} d}{\sqrt {b}}-d x\right ) d^2}{16 (-a)^{3/2} b^{3/2}}+\frac {\cos \left (c-\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \text {Si}\left (x d+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) d^2}{16 (-a)^{3/2} b^{3/2}}+\frac {\cos (c+d x) d}{16 (-a)^{3/2} b \left (\sqrt {-a}-\sqrt {b} x\right )}+\frac {\cos (c+d x) d}{16 (-a)^{3/2} b \left (\sqrt {b} x+\sqrt {-a}\right )}-\frac {3 \cos \left (c+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \operatorname {CosIntegral}\left (\frac {\sqrt {-a} d}{\sqrt {b}}-d x\right ) d}{16 a^2 b}-\frac {3 \cos \left (c-\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \operatorname {CosIntegral}\left (x d+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) d}{16 a^2 b}-\frac {3 \sin \left (c+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \text {Si}\left (\frac {\sqrt {-a} d}{\sqrt {b}}-d x\right ) d}{16 a^2 b}+\frac {3 \sin \left (c-\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \text {Si}\left (x d+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) d}{16 a^2 b}-\frac {3 \operatorname {CosIntegral}\left (x d+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \sin \left (c-\frac {\sqrt {-a} d}{\sqrt {b}}\right )}{16 (-a)^{5/2} \sqrt {b}}+\frac {3 \operatorname {CosIntegral}\left (\frac {\sqrt {-a} d}{\sqrt {b}}-d x\right ) \sin \left (c+\frac {\sqrt {-a} d}{\sqrt {b}}\right )}{16 (-a)^{5/2} \sqrt {b}}-\frac {3 \sin (c+d x)}{16 a^2 \sqrt {b} \left (\sqrt {-a}-\sqrt {b} x\right )}+\frac {3 \sin (c+d x)}{16 a^2 \sqrt {b} \left (\sqrt {b} x+\sqrt {-a}\right )}-\frac {\sin (c+d x)}{16 (-a)^{3/2} \sqrt {b} \left (\sqrt {-a}-\sqrt {b} x\right )^2}+\frac {\sin (c+d x)}{16 (-a)^{3/2} \sqrt {b} \left (\sqrt {b} x+\sqrt {-a}\right )^2}-\frac {3 \cos \left (c+\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \text {Si}\left (\frac {\sqrt {-a} d}{\sqrt {b}}-d x\right )}{16 (-a)^{5/2} \sqrt {b}}-\frac {3 \cos \left (c-\frac {\sqrt {-a} d}{\sqrt {b}}\right ) \text {Si}\left (x d+\frac {\sqrt {-a} d}{\sqrt {b}}\right )}{16 (-a)^{5/2} \sqrt {b}}\)

Input:

Int[Sin[c + d*x]/(a + b*x^2)^3,x]
 

Output:

(d*Cos[c + d*x])/(16*(-a)^(3/2)*b*(Sqrt[-a] - Sqrt[b]*x)) + (d*Cos[c + d*x 
])/(16*(-a)^(3/2)*b*(Sqrt[-a] + Sqrt[b]*x)) - (3*d*Cos[c + (Sqrt[-a]*d)/Sq 
rt[b]]*CosIntegral[(Sqrt[-a]*d)/Sqrt[b] - d*x])/(16*a^2*b) - (3*d*Cos[c - 
(Sqrt[-a]*d)/Sqrt[b]]*CosIntegral[(Sqrt[-a]*d)/Sqrt[b] + d*x])/(16*a^2*b) 
- (3*CosIntegral[(Sqrt[-a]*d)/Sqrt[b] + d*x]*Sin[c - (Sqrt[-a]*d)/Sqrt[b]] 
)/(16*(-a)^(5/2)*Sqrt[b]) + (d^2*CosIntegral[(Sqrt[-a]*d)/Sqrt[b] + d*x]*S 
in[c - (Sqrt[-a]*d)/Sqrt[b]])/(16*(-a)^(3/2)*b^(3/2)) + (3*CosIntegral[(Sq 
rt[-a]*d)/Sqrt[b] - d*x]*Sin[c + (Sqrt[-a]*d)/Sqrt[b]])/(16*(-a)^(5/2)*Sqr 
t[b]) - (d^2*CosIntegral[(Sqrt[-a]*d)/Sqrt[b] - d*x]*Sin[c + (Sqrt[-a]*d)/ 
Sqrt[b]])/(16*(-a)^(3/2)*b^(3/2)) - Sin[c + d*x]/(16*(-a)^(3/2)*Sqrt[b]*(S 
qrt[-a] - Sqrt[b]*x)^2) - (3*Sin[c + d*x])/(16*a^2*Sqrt[b]*(Sqrt[-a] - Sqr 
t[b]*x)) + Sin[c + d*x]/(16*(-a)^(3/2)*Sqrt[b]*(Sqrt[-a] + Sqrt[b]*x)^2) + 
 (3*Sin[c + d*x])/(16*a^2*Sqrt[b]*(Sqrt[-a] + Sqrt[b]*x)) - (3*Cos[c + (Sq 
rt[-a]*d)/Sqrt[b]]*SinIntegral[(Sqrt[-a]*d)/Sqrt[b] - d*x])/(16*(-a)^(5/2) 
*Sqrt[b]) + (d^2*Cos[c + (Sqrt[-a]*d)/Sqrt[b]]*SinIntegral[(Sqrt[-a]*d)/Sq 
rt[b] - d*x])/(16*(-a)^(3/2)*b^(3/2)) - (3*d*Sin[c + (Sqrt[-a]*d)/Sqrt[b]] 
*SinIntegral[(Sqrt[-a]*d)/Sqrt[b] - d*x])/(16*a^2*b) - (3*Cos[c - (Sqrt[-a 
]*d)/Sqrt[b]]*SinIntegral[(Sqrt[-a]*d)/Sqrt[b] + d*x])/(16*(-a)^(5/2)*Sqrt 
[b]) + (d^2*Cos[c - (Sqrt[-a]*d)/Sqrt[b]]*SinIntegral[(Sqrt[-a]*d)/Sqrt[b] 
 + d*x])/(16*(-a)^(3/2)*b^(3/2)) + (3*d*Sin[c - (Sqrt[-a]*d)/Sqrt[b]]*S...
 

Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3814
Int[((a_) + (b_.)*(x_)^(n_))^(p_)*Sin[(c_.) + (d_.)*(x_)], x_Symbol] :> Int 
[ExpandIntegrand[Sin[c + d*x], (a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d}, 
 x] && ILtQ[p, 0] && IGtQ[n, 0] && (EqQ[n, 2] || EqQ[p, -1])
 
Maple [A] (verified)

Time = 1.51 (sec) , antiderivative size = 598, normalized size of antiderivative = 0.70

method result size
derivativedivides \(d^{5} \left (-\frac {\sin \left (d x +c \right ) \left (5 a c \,d^{2}-5 a \,d^{2} \left (d x +c \right )+3 b \,c^{3}-9 b \,c^{2} \left (d x +c \right )+9 b c \left (d x +c \right )^{2}-3 b \left (d x +c \right )^{3}\right )}{8 a^{2} d^{4} \left (d^{2} a +b \,c^{2}-2 b c \left (d x +c \right )+b \left (d x +c \right )^{2}\right )^{2}}+\frac {\cos \left (d x +c \right )}{8 a b \,d^{2} \left (d^{2} a +b \,c^{2}-2 b c \left (d x +c \right )+b \left (d x +c \right )^{2}\right )}-\frac {\left (d^{2} a +3 b \right ) \left (\operatorname {Si}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}+b c}{b}\right )+\operatorname {Ci}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}+b c}{b}\right )\right )}{16 a^{2} d^{4} b^{2} \left (-\frac {d \sqrt {-a b}+b c}{b}+c \right )}-\frac {\left (d^{2} a +3 b \right ) \left (\operatorname {Si}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}-b c}{b}\right )-\operatorname {Ci}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}-b c}{b}\right )\right )}{16 a^{2} d^{4} b^{2} \left (\frac {d \sqrt {-a b}-b c}{b}+c \right )}-\frac {3 \left (-\operatorname {Si}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}+b c}{b}\right )+\operatorname {Ci}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}+b c}{b}\right )\right )}{16 a^{2} d^{4} b}-\frac {3 \left (\operatorname {Si}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}-b c}{b}\right )+\operatorname {Ci}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}-b c}{b}\right )\right )}{16 a^{2} d^{4} b}\right )\) \(598\)
default \(d^{5} \left (-\frac {\sin \left (d x +c \right ) \left (5 a c \,d^{2}-5 a \,d^{2} \left (d x +c \right )+3 b \,c^{3}-9 b \,c^{2} \left (d x +c \right )+9 b c \left (d x +c \right )^{2}-3 b \left (d x +c \right )^{3}\right )}{8 a^{2} d^{4} \left (d^{2} a +b \,c^{2}-2 b c \left (d x +c \right )+b \left (d x +c \right )^{2}\right )^{2}}+\frac {\cos \left (d x +c \right )}{8 a b \,d^{2} \left (d^{2} a +b \,c^{2}-2 b c \left (d x +c \right )+b \left (d x +c \right )^{2}\right )}-\frac {\left (d^{2} a +3 b \right ) \left (\operatorname {Si}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}+b c}{b}\right )+\operatorname {Ci}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}+b c}{b}\right )\right )}{16 a^{2} d^{4} b^{2} \left (-\frac {d \sqrt {-a b}+b c}{b}+c \right )}-\frac {\left (d^{2} a +3 b \right ) \left (\operatorname {Si}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}-b c}{b}\right )-\operatorname {Ci}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}-b c}{b}\right )\right )}{16 a^{2} d^{4} b^{2} \left (\frac {d \sqrt {-a b}-b c}{b}+c \right )}-\frac {3 \left (-\operatorname {Si}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}+b c}{b}\right )+\operatorname {Ci}\left (d x +c -\frac {d \sqrt {-a b}+b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}+b c}{b}\right )\right )}{16 a^{2} d^{4} b}-\frac {3 \left (\operatorname {Si}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \sin \left (\frac {d \sqrt {-a b}-b c}{b}\right )+\operatorname {Ci}\left (d x +c +\frac {d \sqrt {-a b}-b c}{b}\right ) \cos \left (\frac {d \sqrt {-a b}-b c}{b}\right )\right )}{16 a^{2} d^{4} b}\right )\) \(598\)
risch \(-\frac {d^{2} \sqrt {a b}\, {\mathrm e}^{\frac {i b c +d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (\frac {i b c +d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b^{2}}+\frac {d^{2} \sqrt {a b}\, {\mathrm e}^{\frac {i b c -d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (\frac {i b c -d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b^{2}}+\frac {3 d \,{\mathrm e}^{\frac {i b c +d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (\frac {i b c +d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b}+\frac {3 d \,{\mathrm e}^{\frac {i b c -d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (\frac {i b c -d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b}-\frac {3 \sqrt {a b}\, {\mathrm e}^{\frac {i b c +d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (\frac {i b c +d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{3} b}+\frac {3 \,{\mathrm e}^{\frac {i b c -d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (\frac {i b c -d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right ) \sqrt {a b}}{32 a^{3} b}+\frac {d^{2} \sqrt {a b}\, {\mathrm e}^{-\frac {i b c +d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (-\frac {i b c +d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b^{2}}-\frac {d^{2} \sqrt {a b}\, {\mathrm e}^{-\frac {i b c -d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (-\frac {i b c -d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b^{2}}+\frac {3 d \,{\mathrm e}^{-\frac {i b c +d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (-\frac {i b c +d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b}+\frac {3 d \,{\mathrm e}^{-\frac {i b c -d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (-\frac {i b c -d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{2} b}+\frac {3 \sqrt {a b}\, {\mathrm e}^{-\frac {i b c +d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (-\frac {i b c +d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right )}{32 a^{3} b}-\frac {3 \,{\mathrm e}^{-\frac {i b c -d \sqrt {a b}}{b}} \operatorname {expIntegral}_{1}\left (-\frac {i b c -d \sqrt {a b}-b \left (i d x +i c \right )}{b}\right ) \sqrt {a b}}{32 a^{3} b}-\frac {d^{3} \left (x^{2} d^{2} b +d^{2} a \right ) \cos \left (d x +c \right )}{8 a b \left (-b^{2} x^{4} d^{4}-2 a b \,d^{4} x^{2}-a^{2} d^{4}\right )}-\frac {d \left (3 d^{3} x^{3} b +5 a \,d^{3} x \right ) \sin \left (d x +c \right )}{8 a^{2} \left (-b^{2} x^{4} d^{4}-2 a b \,d^{4} x^{2}-a^{2} d^{4}\right )}\) \(902\)

Input:

int(sin(d*x+c)/(b*x^2+a)^3,x,method=_RETURNVERBOSE)
 

Output:

d^5*(-1/8*sin(d*x+c)*(5*a*c*d^2-5*a*d^2*(d*x+c)+3*b*c^3-9*b*c^2*(d*x+c)+9* 
b*c*(d*x+c)^2-3*b*(d*x+c)^3)/a^2/d^4/(d^2*a+b*c^2-2*b*c*(d*x+c)+b*(d*x+c)^ 
2)^2+1/8*cos(d*x+c)/a/b/d^2/(d^2*a+b*c^2-2*b*c*(d*x+c)+b*(d*x+c)^2)-1/16*( 
a*d^2+3*b)/a^2/d^4/b^2/(-(d*(-a*b)^(1/2)+b*c)/b+c)*(Si(d*x+c-(d*(-a*b)^(1/ 
2)+b*c)/b)*cos((d*(-a*b)^(1/2)+b*c)/b)+Ci(d*x+c-(d*(-a*b)^(1/2)+b*c)/b)*si 
n((d*(-a*b)^(1/2)+b*c)/b))-1/16*(a*d^2+3*b)/a^2/d^4/b^2/((d*(-a*b)^(1/2)-b 
*c)/b+c)*(Si(d*x+c+(d*(-a*b)^(1/2)-b*c)/b)*cos((d*(-a*b)^(1/2)-b*c)/b)-Ci( 
d*x+c+(d*(-a*b)^(1/2)-b*c)/b)*sin((d*(-a*b)^(1/2)-b*c)/b))-3/16/a^2/d^4/b* 
(-Si(d*x+c-(d*(-a*b)^(1/2)+b*c)/b)*sin((d*(-a*b)^(1/2)+b*c)/b)+Ci(d*x+c-(d 
*(-a*b)^(1/2)+b*c)/b)*cos((d*(-a*b)^(1/2)+b*c)/b))-3/16/a^2/d^4/b*(Si(d*x+ 
c+(d*(-a*b)^(1/2)-b*c)/b)*sin((d*(-a*b)^(1/2)-b*c)/b)+Ci(d*x+c+(d*(-a*b)^( 
1/2)-b*c)/b)*cos((d*(-a*b)^(1/2)-b*c)/b)))
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.12 (sec) , antiderivative size = 611, normalized size of antiderivative = 0.71 \[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx=-\frac {{\left (3 \, a b^{2} d^{2} x^{4} + 6 \, a^{2} b d^{2} x^{2} + 3 \, a^{3} d^{2} - {\left (a^{3} d^{2} + {\left (a b^{2} d^{2} + 3 \, b^{3}\right )} x^{4} + 3 \, a^{2} b + 2 \, {\left (a^{2} b d^{2} + 3 \, a b^{2}\right )} x^{2}\right )} \sqrt {\frac {a d^{2}}{b}}\right )} {\rm Ei}\left (i \, d x - \sqrt {\frac {a d^{2}}{b}}\right ) e^{\left (i \, c + \sqrt {\frac {a d^{2}}{b}}\right )} + {\left (3 \, a b^{2} d^{2} x^{4} + 6 \, a^{2} b d^{2} x^{2} + 3 \, a^{3} d^{2} + {\left (a^{3} d^{2} + {\left (a b^{2} d^{2} + 3 \, b^{3}\right )} x^{4} + 3 \, a^{2} b + 2 \, {\left (a^{2} b d^{2} + 3 \, a b^{2}\right )} x^{2}\right )} \sqrt {\frac {a d^{2}}{b}}\right )} {\rm Ei}\left (i \, d x + \sqrt {\frac {a d^{2}}{b}}\right ) e^{\left (i \, c - \sqrt {\frac {a d^{2}}{b}}\right )} + {\left (3 \, a b^{2} d^{2} x^{4} + 6 \, a^{2} b d^{2} x^{2} + 3 \, a^{3} d^{2} - {\left (a^{3} d^{2} + {\left (a b^{2} d^{2} + 3 \, b^{3}\right )} x^{4} + 3 \, a^{2} b + 2 \, {\left (a^{2} b d^{2} + 3 \, a b^{2}\right )} x^{2}\right )} \sqrt {\frac {a d^{2}}{b}}\right )} {\rm Ei}\left (-i \, d x - \sqrt {\frac {a d^{2}}{b}}\right ) e^{\left (-i \, c + \sqrt {\frac {a d^{2}}{b}}\right )} + {\left (3 \, a b^{2} d^{2} x^{4} + 6 \, a^{2} b d^{2} x^{2} + 3 \, a^{3} d^{2} + {\left (a^{3} d^{2} + {\left (a b^{2} d^{2} + 3 \, b^{3}\right )} x^{4} + 3 \, a^{2} b + 2 \, {\left (a^{2} b d^{2} + 3 \, a b^{2}\right )} x^{2}\right )} \sqrt {\frac {a d^{2}}{b}}\right )} {\rm Ei}\left (-i \, d x + \sqrt {\frac {a d^{2}}{b}}\right ) e^{\left (-i \, c - \sqrt {\frac {a d^{2}}{b}}\right )} - 4 \, {\left (a^{2} b d^{2} x^{2} + a^{3} d^{2}\right )} \cos \left (d x + c\right ) - 4 \, {\left (3 \, a b^{2} d x^{3} + 5 \, a^{2} b d x\right )} \sin \left (d x + c\right )}{32 \, {\left (a^{3} b^{3} d x^{4} + 2 \, a^{4} b^{2} d x^{2} + a^{5} b d\right )}} \] Input:

integrate(sin(d*x+c)/(b*x^2+a)^3,x, algorithm="fricas")
 

Output:

-1/32*((3*a*b^2*d^2*x^4 + 6*a^2*b*d^2*x^2 + 3*a^3*d^2 - (a^3*d^2 + (a*b^2* 
d^2 + 3*b^3)*x^4 + 3*a^2*b + 2*(a^2*b*d^2 + 3*a*b^2)*x^2)*sqrt(a*d^2/b))*E 
i(I*d*x - sqrt(a*d^2/b))*e^(I*c + sqrt(a*d^2/b)) + (3*a*b^2*d^2*x^4 + 6*a^ 
2*b*d^2*x^2 + 3*a^3*d^2 + (a^3*d^2 + (a*b^2*d^2 + 3*b^3)*x^4 + 3*a^2*b + 2 
*(a^2*b*d^2 + 3*a*b^2)*x^2)*sqrt(a*d^2/b))*Ei(I*d*x + sqrt(a*d^2/b))*e^(I* 
c - sqrt(a*d^2/b)) + (3*a*b^2*d^2*x^4 + 6*a^2*b*d^2*x^2 + 3*a^3*d^2 - (a^3 
*d^2 + (a*b^2*d^2 + 3*b^3)*x^4 + 3*a^2*b + 2*(a^2*b*d^2 + 3*a*b^2)*x^2)*sq 
rt(a*d^2/b))*Ei(-I*d*x - sqrt(a*d^2/b))*e^(-I*c + sqrt(a*d^2/b)) + (3*a*b^ 
2*d^2*x^4 + 6*a^2*b*d^2*x^2 + 3*a^3*d^2 + (a^3*d^2 + (a*b^2*d^2 + 3*b^3)*x 
^4 + 3*a^2*b + 2*(a^2*b*d^2 + 3*a*b^2)*x^2)*sqrt(a*d^2/b))*Ei(-I*d*x + sqr 
t(a*d^2/b))*e^(-I*c - sqrt(a*d^2/b)) - 4*(a^2*b*d^2*x^2 + a^3*d^2)*cos(d*x 
 + c) - 4*(3*a*b^2*d*x^3 + 5*a^2*b*d*x)*sin(d*x + c))/(a^3*b^3*d*x^4 + 2*a 
^4*b^2*d*x^2 + a^5*b*d)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx=\text {Timed out} \] Input:

integrate(sin(d*x+c)/(b*x**2+a)**3,x)
                                                                                    
                                                                                    
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx=\int { \frac {\sin \left (d x + c\right )}{{\left (b x^{2} + a\right )}^{3}} \,d x } \] Input:

integrate(sin(d*x+c)/(b*x^2+a)^3,x, algorithm="maxima")
 

Output:

integrate(sin(d*x + c)/(b*x^2 + a)^3, x)
 

Giac [F]

\[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx=\int { \frac {\sin \left (d x + c\right )}{{\left (b x^{2} + a\right )}^{3}} \,d x } \] Input:

integrate(sin(d*x+c)/(b*x^2+a)^3,x, algorithm="giac")
 

Output:

integrate(sin(d*x + c)/(b*x^2 + a)^3, x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx=\int \frac {\sin \left (c+d\,x\right )}{{\left (b\,x^2+a\right )}^3} \,d x \] Input:

int(sin(c + d*x)/(a + b*x^2)^3,x)
 

Output:

int(sin(c + d*x)/(a + b*x^2)^3, x)
 

Reduce [F]

\[ \int \frac {\sin (c+d x)}{\left (a+b x^2\right )^3} \, dx=\int \frac {\sin \left (d x +c \right )}{b^{3} x^{6}+3 a \,b^{2} x^{4}+3 a^{2} b \,x^{2}+a^{3}}d x \] Input:

int(sin(d*x+c)/(b*x^2+a)^3,x)
 

Output:

int(sin(c + d*x)/(a**3 + 3*a**2*b*x**2 + 3*a*b**2*x**4 + b**3*x**6),x)