Integrand size = 27, antiderivative size = 116 \[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=-\frac {3 b (c+d x)^{2/3} \cos (a) \operatorname {CosIntegral}\left (\frac {b}{\sqrt [3]{c+d x}}\right )}{d (e (c+d x))^{2/3}}+\frac {3 (c+d x) \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{d (e (c+d x))^{2/3}}+\frac {3 b (c+d x)^{2/3} \sin (a) \text {Si}\left (\frac {b}{\sqrt [3]{c+d x}}\right )}{d (e (c+d x))^{2/3}} \] Output:
-3*b*(d*x+c)^(2/3)*cos(a)*Ci(b/(d*x+c)^(1/3))/d/(e*(d*x+c))^(2/3)+3*(d*x+c )*sin(a+b/(d*x+c)^(1/3))/d/(e*(d*x+c))^(2/3)+3*b*(d*x+c)^(2/3)*sin(a)*Si(b /(d*x+c)^(1/3))/d/(e*(d*x+c))^(2/3)
Time = 0.32 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.76 \[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=\frac {3 \left (-b (c+d x)^{2/3} \cos (a) \operatorname {CosIntegral}\left (\frac {b}{\sqrt [3]{c+d x}}\right )+(c+d x) \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )+b (c+d x)^{2/3} \sin (a) \text {Si}\left (\frac {b}{\sqrt [3]{c+d x}}\right )\right )}{d (e (c+d x))^{2/3}} \] Input:
Integrate[Sin[a + b/(c + d*x)^(1/3)]/(c*e + d*e*x)^(2/3),x]
Output:
(3*(-(b*(c + d*x)^(2/3)*Cos[a]*CosIntegral[b/(c + d*x)^(1/3)]) + (c + d*x) *Sin[a + b/(c + d*x)^(1/3)] + b*(c + d*x)^(2/3)*Sin[a]*SinIntegral[b/(c + d*x)^(1/3)]))/(d*(e*(c + d*x))^(2/3))
Time = 0.49 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.73, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3912, 30, 3042, 3778, 3042, 3784, 3042, 3780, 3783}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx\) |
\(\Big \downarrow \) 3912 |
\(\displaystyle -\frac {3 \int \frac {(c+d x)^{4/3} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(e (c+d x))^{2/3}}d\frac {1}{\sqrt [3]{c+d x}}}{d}\) |
\(\Big \downarrow \) 30 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \int (c+d x)^{2/3} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )d\frac {1}{\sqrt [3]{c+d x}}}{d (e (c+d x))^{2/3}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \int (c+d x)^{2/3} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )d\frac {1}{\sqrt [3]{c+d x}}}{d (e (c+d x))^{2/3}}\) |
\(\Big \downarrow \) 3778 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \left (b \int \sqrt [3]{c+d x} \cos \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )d\frac {1}{\sqrt [3]{c+d x}}-\sqrt [3]{c+d x} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )\right )}{d (e (c+d x))^{2/3}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \left (b \int \sqrt [3]{c+d x} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}+\frac {\pi }{2}\right )d\frac {1}{\sqrt [3]{c+d x}}-\sqrt [3]{c+d x} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )\right )}{d (e (c+d x))^{2/3}}\) |
\(\Big \downarrow \) 3784 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \left (b \left (\cos (a) \int \sqrt [3]{c+d x} \cos \left (\frac {b}{\sqrt [3]{c+d x}}\right )d\frac {1}{\sqrt [3]{c+d x}}-\sin (a) \int \sqrt [3]{c+d x} \sin \left (\frac {b}{\sqrt [3]{c+d x}}\right )d\frac {1}{\sqrt [3]{c+d x}}\right )-\sqrt [3]{c+d x} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )\right )}{d (e (c+d x))^{2/3}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \left (b \left (\cos (a) \int \sqrt [3]{c+d x} \sin \left (\frac {b}{\sqrt [3]{c+d x}}+\frac {\pi }{2}\right )d\frac {1}{\sqrt [3]{c+d x}}-\sin (a) \int \sqrt [3]{c+d x} \sin \left (\frac {b}{\sqrt [3]{c+d x}}\right )d\frac {1}{\sqrt [3]{c+d x}}\right )-\sqrt [3]{c+d x} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )\right )}{d (e (c+d x))^{2/3}}\) |
\(\Big \downarrow \) 3780 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \left (b \left (\cos (a) \int \sqrt [3]{c+d x} \sin \left (\frac {b}{\sqrt [3]{c+d x}}+\frac {\pi }{2}\right )d\frac {1}{\sqrt [3]{c+d x}}-\sin (a) \text {Si}\left (\frac {b}{\sqrt [3]{c+d x}}\right )\right )-\sqrt [3]{c+d x} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )\right )}{d (e (c+d x))^{2/3}}\) |
\(\Big \downarrow \) 3783 |
\(\displaystyle -\frac {3 (c+d x)^{2/3} \left (b \left (\cos (a) \operatorname {CosIntegral}\left (\frac {b}{\sqrt [3]{c+d x}}\right )-\sin (a) \text {Si}\left (\frac {b}{\sqrt [3]{c+d x}}\right )\right )-\sqrt [3]{c+d x} \sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )\right )}{d (e (c+d x))^{2/3}}\) |
Input:
Int[Sin[a + b/(c + d*x)^(1/3)]/(c*e + d*e*x)^(2/3),x]
Output:
(-3*(c + d*x)^(2/3)*(-((c + d*x)^(1/3)*Sin[a + b/(c + d*x)^(1/3)]) + b*(Co s[a]*CosIntegral[b/(c + d*x)^(1/3)] - Sin[a]*SinIntegral[b/(c + d*x)^(1/3) ])))/(d*(e*(c + d*x))^(2/3))
Int[(u_.)*((a_.)*(x_))^(m_.)*((b_.)*(x_)^(i_.))^(p_), x_Symbol] :> Simp[b^I ntPart[p]*((b*x^i)^FracPart[p]/(a^(i*IntPart[p])*(a*x)^(i*FracPart[p]))) Int[u*(a*x)^(m + i*p), x], x] /; FreeQ[{a, b, i, m, p}, x] && IntegerQ[i] & & !IntegerQ[p]
Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[(c + d*x)^(m + 1)*(Sin[e + f*x]/(d*(m + 1))), x] - Simp[f/(d*(m + 1)) Int[( c + d*x)^(m + 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && LtQ[m, - 1]
Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[SinInte gral[e + f*x]/d, x] /; FreeQ[{c, d, e, f}, x] && EqQ[d*e - c*f, 0]
Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosInte gral[e - Pi/2 + f*x]/d, x] /; FreeQ[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]
Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[Cos[(d* e - c*f)/d] Int[Sin[c*(f/d) + f*x]/(c + d*x), x], x] + Simp[Sin[(d*e - c* f)/d] Int[Cos[c*(f/d) + f*x]/(c + d*x), x], x] /; FreeQ[{c, d, e, f}, x] && NeQ[d*e - c*f, 0]
Int[((g_.) + (h_.)*(x_))^(m_.)*((a_.) + (b_.)*Sin[(c_.) + (d_.)*((e_.) + (f _.)*(x_))^(n_)])^(p_.), x_Symbol] :> Simp[1/(n*f) Subst[Int[ExpandIntegra nd[(a + b*Sin[c + d*x])^p, x^(1/n - 1)*(g - e*(h/f) + h*(x^(1/n)/f))^m, x], x], x, (e + f*x)^n], x] /; FreeQ[{a, b, c, d, e, f, g, h, m}, x] && IGtQ[p , 0] && IntegerQ[1/n]
\[\int \frac {\sin \left (a +\frac {b}{\left (d x +c \right )^{\frac {1}{3}}}\right )}{\left (d e x +c e \right )^{\frac {2}{3}}}d x\]
Input:
int(sin(a+b/(d*x+c)^(1/3))/(d*e*x+c*e)^(2/3),x)
Output:
int(sin(a+b/(d*x+c)^(1/3))/(d*e*x+c*e)^(2/3),x)
\[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=\int { \frac {\sin \left (a + \frac {b}{{\left (d x + c\right )}^{\frac {1}{3}}}\right )}{{\left (d e x + c e\right )}^{\frac {2}{3}}} \,d x } \] Input:
integrate(sin(a+b/(d*x+c)^(1/3))/(d*e*x+c*e)^(2/3),x, algorithm="fricas")
Output:
integral(sin((a*d*x + a*c + (d*x + c)^(2/3)*b)/(d*x + c))/(d*e*x + c*e)^(2 /3), x)
\[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=\int \frac {\sin {\left (a + \frac {b}{\sqrt [3]{c + d x}} \right )}}{\left (e \left (c + d x\right )\right )^{\frac {2}{3}}}\, dx \] Input:
integrate(sin(a+b/(d*x+c)**(1/3))/(d*e*x+c*e)**(2/3),x)
Output:
Integral(sin(a + b/(c + d*x)**(1/3))/(e*(c + d*x))**(2/3), x)
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.25 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.34 \[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=-\frac {3 \, {\left ({\left ({\left ({\rm Ei}\left (i \, b \overline {\frac {1}{{\left (d x + c\right )}^{\frac {1}{3}}}}\right ) + {\rm Ei}\left (-i \, b \overline {\frac {1}{{\left (d x + c\right )}^{\frac {1}{3}}}}\right ) + {\rm Ei}\left (\frac {i \, b}{{\left (d x + c\right )}^{\frac {1}{3}}}\right ) + {\rm Ei}\left (-\frac {i \, b}{{\left (d x + c\right )}^{\frac {1}{3}}}\right )\right )} \cos \left (a\right ) + {\left (i \, {\rm Ei}\left (i \, b \overline {\frac {1}{{\left (d x + c\right )}^{\frac {1}{3}}}}\right ) - i \, {\rm Ei}\left (-i \, b \overline {\frac {1}{{\left (d x + c\right )}^{\frac {1}{3}}}}\right ) + i \, {\rm Ei}\left (\frac {i \, b}{{\left (d x + c\right )}^{\frac {1}{3}}}\right ) - i \, {\rm Ei}\left (-\frac {i \, b}{{\left (d x + c\right )}^{\frac {1}{3}}}\right )\right )} \sin \left (a\right )\right )} b e^{\frac {1}{3}} - 4 \, {\left (d x + c\right )}^{\frac {1}{3}} e^{\frac {1}{3}} \sin \left (\frac {{\left (d x + c\right )}^{\frac {1}{3}} a + b}{{\left (d x + c\right )}^{\frac {1}{3}}}\right )\right )}}{4 \, d e} \] Input:
integrate(sin(a+b/(d*x+c)^(1/3))/(d*e*x+c*e)^(2/3),x, algorithm="maxima")
Output:
-3/4*(((Ei(I*b*conjugate((d*x + c)^(-1/3))) + Ei(-I*b*conjugate((d*x + c)^ (-1/3))) + Ei(I*b/(d*x + c)^(1/3)) + Ei(-I*b/(d*x + c)^(1/3)))*cos(a) + (I *Ei(I*b*conjugate((d*x + c)^(-1/3))) - I*Ei(-I*b*conjugate((d*x + c)^(-1/3 ))) + I*Ei(I*b/(d*x + c)^(1/3)) - I*Ei(-I*b/(d*x + c)^(1/3)))*sin(a))*b*e^ (1/3) - 4*(d*x + c)^(1/3)*e^(1/3)*sin(((d*x + c)^(1/3)*a + b)/(d*x + c)^(1 /3)))/(d*e)
\[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=\int { \frac {\sin \left (a + \frac {b}{{\left (d x + c\right )}^{\frac {1}{3}}}\right )}{{\left (d e x + c e\right )}^{\frac {2}{3}}} \,d x } \] Input:
integrate(sin(a+b/(d*x+c)^(1/3))/(d*e*x+c*e)^(2/3),x, algorithm="giac")
Output:
integrate(sin(a + b/(d*x + c)^(1/3))/(d*e*x + c*e)^(2/3), x)
Timed out. \[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=\int \frac {\sin \left (a+\frac {b}{{\left (c+d\,x\right )}^{1/3}}\right )}{{\left (c\,e+d\,e\,x\right )}^{2/3}} \,d x \] Input:
int(sin(a + b/(c + d*x)^(1/3))/(c*e + d*e*x)^(2/3),x)
Output:
int(sin(a + b/(c + d*x)^(1/3))/(c*e + d*e*x)^(2/3), x)
\[ \int \frac {\sin \left (a+\frac {b}{\sqrt [3]{c+d x}}\right )}{(c e+d e x)^{2/3}} \, dx=\frac {\int \frac {\sin \left (\frac {\left (d x +c \right )^{\frac {1}{3}} a +b}{\left (d x +c \right )^{\frac {1}{3}}}\right )}{\left (d x +c \right )^{\frac {2}{3}}}d x}{e^{\frac {2}{3}}} \] Input:
int(sin(a+b/(d*x+c)^(1/3))/(d*e*x+c*e)^(2/3),x)
Output:
int(sin(((c + d*x)**(1/3)*a + b)/(c + d*x)**(1/3))/(c + d*x)**(2/3),x)/e** (2/3)