Integrand size = 19, antiderivative size = 53 \[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\frac {3 \operatorname {Hypergeometric2F1}\left (-\frac {1}{6},\frac {1}{2},\frac {5}{6},\cos ^2(c+d x)\right ) \sin (c+d x)}{d \sqrt [3]{b \cos (c+d x)} \sqrt {\sin ^2(c+d x)}} \] Output:
3*hypergeom([-1/6, 1/2],[5/6],cos(d*x+c)^2)*sin(d*x+c)/d/(b*cos(d*x+c))^(1 /3)/(sin(d*x+c)^2)^(1/2)
Time = 0.06 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.02 \[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\frac {3 b \cot (c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {1}{6},\frac {1}{2},\frac {5}{6},\cos ^2(c+d x)\right ) \sqrt {\sin ^2(c+d x)}}{d (b \cos (c+d x))^{4/3}} \] Input:
Integrate[Sec[c + d*x]/(b*Cos[c + d*x])^(1/3),x]
Output:
(3*b*Cot[c + d*x]*Hypergeometric2F1[-1/6, 1/2, 5/6, Cos[c + d*x]^2]*Sqrt[S in[c + d*x]^2])/(d*(b*Cos[c + d*x])^(4/3))
Time = 0.22 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {3042, 2030, 3122}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {1}{\sin \left (c+d x+\frac {\pi }{2}\right ) \sqrt [3]{b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx\) |
\(\Big \downarrow \) 2030 |
\(\displaystyle b \int \frac {1}{\left (b \sin \left (\frac {1}{2} (2 c+\pi )+d x\right )\right )^{4/3}}dx\) |
\(\Big \downarrow \) 3122 |
\(\displaystyle \frac {3 \sin (c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {1}{6},\frac {1}{2},\frac {5}{6},\cos ^2(c+d x)\right )}{d \sqrt {\sin ^2(c+d x)} \sqrt [3]{b \cos (c+d x)}}\) |
Input:
Int[Sec[c + d*x]/(b*Cos[c + d*x])^(1/3),x]
Output:
(3*Hypergeometric2F1[-1/6, 1/2, 5/6, Cos[c + d*x]^2]*Sin[c + d*x])/(d*(b*C os[c + d*x])^(1/3)*Sqrt[Sin[c + d*x]^2])
Int[(Fx_.)*(v_)^(m_.)*((b_)*(v_))^(n_), x_Symbol] :> Simp[1/b^m Int[(b*v) ^(m + n)*Fx, x], x] /; FreeQ[{b, n}, x] && IntegerQ[m]
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*(( b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]))*Hypergeometric2 F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2], x] /; FreeQ[{b, c, d, n}, x] && !IntegerQ[2*n]
\[\int \frac {\sec \left (d x +c \right )}{\left (\cos \left (d x +c \right ) b \right )^{\frac {1}{3}}}d x\]
Input:
int(sec(d*x+c)/(cos(d*x+c)*b)^(1/3),x)
Output:
int(sec(d*x+c)/(cos(d*x+c)*b)^(1/3),x)
\[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\int { \frac {\sec \left (d x + c\right )}{\left (b \cos \left (d x + c\right )\right )^{\frac {1}{3}}} \,d x } \] Input:
integrate(sec(d*x+c)/(b*cos(d*x+c))^(1/3),x, algorithm="fricas")
Output:
integral((b*cos(d*x + c))^(2/3)*sec(d*x + c)/(b*cos(d*x + c)), x)
\[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\int \frac {\sec {\left (c + d x \right )}}{\sqrt [3]{b \cos {\left (c + d x \right )}}}\, dx \] Input:
integrate(sec(d*x+c)/(b*cos(d*x+c))**(1/3),x)
Output:
Integral(sec(c + d*x)/(b*cos(c + d*x))**(1/3), x)
\[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\int { \frac {\sec \left (d x + c\right )}{\left (b \cos \left (d x + c\right )\right )^{\frac {1}{3}}} \,d x } \] Input:
integrate(sec(d*x+c)/(b*cos(d*x+c))^(1/3),x, algorithm="maxima")
Output:
integrate(sec(d*x + c)/(b*cos(d*x + c))^(1/3), x)
\[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\int { \frac {\sec \left (d x + c\right )}{\left (b \cos \left (d x + c\right )\right )^{\frac {1}{3}}} \,d x } \] Input:
integrate(sec(d*x+c)/(b*cos(d*x+c))^(1/3),x, algorithm="giac")
Output:
integrate(sec(d*x + c)/(b*cos(d*x + c))^(1/3), x)
Timed out. \[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\int \frac {1}{\cos \left (c+d\,x\right )\,{\left (b\,\cos \left (c+d\,x\right )\right )}^{1/3}} \,d x \] Input:
int(1/(cos(c + d*x)*(b*cos(c + d*x))^(1/3)),x)
Output:
int(1/(cos(c + d*x)*(b*cos(c + d*x))^(1/3)), x)
\[ \int \frac {\sec (c+d x)}{\sqrt [3]{b \cos (c+d x)}} \, dx=\frac {\int \frac {\sec \left (d x +c \right )}{\cos \left (d x +c \right )^{\frac {1}{3}}}d x}{b^{\frac {1}{3}}} \] Input:
int(sec(d*x+c)/(b*cos(d*x+c))^(1/3),x)
Output:
int(sec(c + d*x)/cos(c + d*x)**(1/3),x)/b**(1/3)