\(\int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx\) [286]

Optimal result

Integrand size = 19, antiderivative size = 88 \[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=\frac {b \cos ^{-1+m}(e+f x) \cos ^2(e+f x)^{\frac {1-m}{2}} (b \csc (e+f x))^{-1+n} \operatorname {Hypergeometric2F1}\left (\frac {1-m}{2},\frac {1-n}{2},\frac {3-n}{2},\sin ^2(e+f x)\right )}{f (1-n)} \] Output:

b*cos(f*x+e)^(-1+m)*(cos(f*x+e)^2)^(1/2-1/2*m)*(b*csc(f*x+e))^(-1+n)*hyper 
geom([1/2-1/2*m, 1/2-1/2*n],[3/2-1/2*n],sin(f*x+e)^2)/f/(1-n)
 

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 6 vs. order 5 in optimal.

Time = 1.22 (sec) , antiderivative size = 314, normalized size of antiderivative = 3.57 \[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=-\frac {2 (-3+n) \operatorname {AppellF1}\left (\frac {1}{2}-\frac {n}{2},-m,1+m-n,\frac {3}{2}-\frac {n}{2},\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) \cos ^3\left (\frac {1}{2} (e+f x)\right ) \cos ^m(e+f x) (b \csc (e+f x))^n \sin \left (\frac {1}{2} (e+f x)\right )}{f (-1+n) \left ((-3+n) \operatorname {AppellF1}\left (\frac {1}{2}-\frac {n}{2},-m,1+m-n,\frac {3}{2}-\frac {n}{2},\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) \cos ^2\left (\frac {1}{2} (e+f x)\right )+2 \left (m \operatorname {AppellF1}\left (\frac {3}{2}-\frac {n}{2},1-m,1+m-n,\frac {5}{2}-\frac {n}{2},\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )+(1+m-n) \operatorname {AppellF1}\left (\frac {3}{2}-\frac {n}{2},-m,2+m-n,\frac {5}{2}-\frac {n}{2},\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )\right ) \sin ^2\left (\frac {1}{2} (e+f x)\right )\right )} \] Input:

Integrate[Cos[e + f*x]^m*(b*Csc[e + f*x])^n,x]
 

Output:

(-2*(-3 + n)*AppellF1[1/2 - n/2, -m, 1 + m - n, 3/2 - n/2, Tan[(e + f*x)/2 
]^2, -Tan[(e + f*x)/2]^2]*Cos[(e + f*x)/2]^3*Cos[e + f*x]^m*(b*Csc[e + f*x 
])^n*Sin[(e + f*x)/2])/(f*(-1 + n)*((-3 + n)*AppellF1[1/2 - n/2, -m, 1 + m 
 - n, 3/2 - n/2, Tan[(e + f*x)/2]^2, -Tan[(e + f*x)/2]^2]*Cos[(e + f*x)/2] 
^2 + 2*(m*AppellF1[3/2 - n/2, 1 - m, 1 + m - n, 5/2 - n/2, Tan[(e + f*x)/2 
]^2, -Tan[(e + f*x)/2]^2] + (1 + m - n)*AppellF1[3/2 - n/2, -m, 2 + m - n, 
 5/2 - n/2, Tan[(e + f*x)/2]^2, -Tan[(e + f*x)/2]^2])*Sin[(e + f*x)/2]^2))
 

Rubi [A] (verified)

Time = 0.36 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {3042, 3067, 3042, 3057}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \sin \left (e+f x+\frac {\pi }{2}\right )^m \left (-b \sec \left (e+f x+\frac {\pi }{2}\right )\right )^ndx\)

\(\Big \downarrow \) 3067

\(\displaystyle b^2 (b \sin (e+f x))^{n-1} (b \csc (e+f x))^{n-1} \int \cos ^m(e+f x) (b \sin (e+f x))^{-n}dx\)

\(\Big \downarrow \) 3042

\(\displaystyle b^2 (b \sin (e+f x))^{n-1} (b \csc (e+f x))^{n-1} \int \cos (e+f x)^m (b \sin (e+f x))^{-n}dx\)

\(\Big \downarrow \) 3057

\(\displaystyle \frac {b \cos ^{m-1}(e+f x) \cos ^2(e+f x)^{\frac {1-m}{2}} (b \csc (e+f x))^{n-1} \operatorname {Hypergeometric2F1}\left (\frac {1-m}{2},\frac {1-n}{2},\frac {3-n}{2},\sin ^2(e+f x)\right )}{f (1-n)}\)

Input:

Int[Cos[e + f*x]^m*(b*Csc[e + f*x])^n,x]
 

Output:

(b*Cos[e + f*x]^(-1 + m)*(Cos[e + f*x]^2)^((1 - m)/2)*(b*Csc[e + f*x])^(-1 
 + n)*Hypergeometric2F1[(1 - m)/2, (1 - n)/2, (3 - n)/2, Sin[e + f*x]^2])/ 
(f*(1 - n))
 

Defintions of rubi rules used

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3057

Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[b^(2*IntPart[(n - 1)/2] + 1)*(b*Cos[e + f*x])^(2*Frac 
Part[(n - 1)/2])*((a*Sin[e + f*x])^(m + 1)/(a*f*(m + 1)*(Cos[e + f*x]^2)^Fr 
acPart[(n - 1)/2]))*Hypergeometric2F1[(1 + m)/2, (1 - n)/2, (3 + m)/2, Sin[ 
e + f*x]^2], x] /; FreeQ[{a, b, e, f, m, n}, x]
 

rule 3067

Int[((b_.)*sec[(e_.) + (f_.)*(x_)])^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[b^2*(b*Cos[e + f*x])^(n - 1)*(b*Sec[e + f*x])^(n - 1) 
   Int[(a*Sin[e + f*x])^m/(b*Cos[e + f*x])^n, x], x] /; FreeQ[{a, b, e, f, 
m, n}, x] &&  !IntegerQ[m] &&  !IntegerQ[n]
 

Maple [F]

\[\int \cos \left (f x +e \right )^{m} \left (b \csc \left (f x +e \right )\right )^{n}d x\]

Input:

int(cos(f*x+e)^m*(b*csc(f*x+e))^n,x)
 

Output:

int(cos(f*x+e)^m*(b*csc(f*x+e))^n,x)
 

Fricas [F]

\[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=\int { \left (b \csc \left (f x + e\right )\right )^{n} \cos \left (f x + e\right )^{m} \,d x } \] Input:

integrate(cos(f*x+e)^m*(b*csc(f*x+e))^n,x, algorithm="fricas")
 

Output:

integral((b*csc(f*x + e))^n*cos(f*x + e)^m, x)
 

Sympy [F]

\[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=\int \left (b \csc {\left (e + f x \right )}\right )^{n} \cos ^{m}{\left (e + f x \right )}\, dx \] Input:

integrate(cos(f*x+e)**m*(b*csc(f*x+e))**n,x)
 

Output:

Integral((b*csc(e + f*x))**n*cos(e + f*x)**m, x)
 

Maxima [F]

\[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=\int { \left (b \csc \left (f x + e\right )\right )^{n} \cos \left (f x + e\right )^{m} \,d x } \] Input:

integrate(cos(f*x+e)^m*(b*csc(f*x+e))^n,x, algorithm="maxima")
 

Output:

integrate((b*csc(f*x + e))^n*cos(f*x + e)^m, x)
 

Giac [F]

\[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=\int { \left (b \csc \left (f x + e\right )\right )^{n} \cos \left (f x + e\right )^{m} \,d x } \] Input:

integrate(cos(f*x+e)^m*(b*csc(f*x+e))^n,x, algorithm="giac")
 

Output:

integrate((b*csc(f*x + e))^n*cos(f*x + e)^m, x)
 

Mupad [F(-1)]

Timed out. \[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=\int {\cos \left (e+f\,x\right )}^m\,{\left (\frac {b}{\sin \left (e+f\,x\right )}\right )}^n \,d x \] Input:

int(cos(e + f*x)^m*(b/sin(e + f*x))^n,x)
 

Output:

int(cos(e + f*x)^m*(b/sin(e + f*x))^n, x)
 

Reduce [F]

\[ \int \cos ^m(e+f x) (b \csc (e+f x))^n \, dx=b^{n} \left (\int \csc \left (f x +e \right )^{n} \cos \left (f x +e \right )^{m}d x \right ) \] Input:

int(cos(f*x+e)^m*(b*csc(f*x+e))^n,x)
 

Output:

b**n*int(csc(e + f*x)**n*cos(e + f*x)**m,x)