\(\int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx\) [75]

Optimal result

Integrand size = 25, antiderivative size = 507 \[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\frac {5 a b^{3/2} \arctan \left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{2 \left (-a^2+b^2\right )^{9/4} d e^{3/2}}-\frac {5 a b^{3/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{2 \left (-a^2+b^2\right )^{9/4} d e^{3/2}}-\frac {b}{\left (a^2-b^2\right ) d e (a+b \cos (c+d x)) \sqrt {e \sin (c+d x)}}+\frac {5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)}{\left (a^2-b^2\right )^2 d e \sqrt {e \sin (c+d x)}}-\frac {5 a^2 b \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {-a^2+b^2}},\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right ),2\right ) \sqrt {\sin (c+d x)}}{2 \left (a^2-b^2\right )^2 \left (b-\sqrt {-a^2+b^2}\right ) d e \sqrt {e \sin (c+d x)}}-\frac {5 a^2 b \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {-a^2+b^2}},\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right ),2\right ) \sqrt {\sin (c+d x)}}{2 \left (a^2-b^2\right )^2 \left (b+\sqrt {-a^2+b^2}\right ) d e \sqrt {e \sin (c+d x)}}-\frac {\left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{\left (a^2-b^2\right )^2 d e^2 \sqrt {\sin (c+d x)}} \] Output:

5/2*a*b^(3/2)*arctan(b^(1/2)*(e*sin(d*x+c))^(1/2)/(-a^2+b^2)^(1/4)/e^(1/2) 
)/(-a^2+b^2)^(9/4)/d/e^(3/2)-5/2*a*b^(3/2)*arctanh(b^(1/2)*(e*sin(d*x+c))^ 
(1/2)/(-a^2+b^2)^(1/4)/e^(1/2))/(-a^2+b^2)^(9/4)/d/e^(3/2)-b/(a^2-b^2)/d/e 
/(a+b*cos(d*x+c))/(e*sin(d*x+c))^(1/2)+(5*a*b-(2*a^2+3*b^2)*cos(d*x+c))/(a 
^2-b^2)^2/d/e/(e*sin(d*x+c))^(1/2)+5/2*a^2*b*EllipticPi(cos(1/2*c+1/4*Pi+1 
/2*d*x),2*b/(b-(-a^2+b^2)^(1/2)),2^(1/2))*sin(d*x+c)^(1/2)/(a^2-b^2)^2/(b- 
(-a^2+b^2)^(1/2))/d/e/(e*sin(d*x+c))^(1/2)+5/2*a^2*b*EllipticPi(cos(1/2*c+ 
1/4*Pi+1/2*d*x),2*b/(b+(-a^2+b^2)^(1/2)),2^(1/2))*sin(d*x+c)^(1/2)/(a^2-b^ 
2)^2/(b+(-a^2+b^2)^(1/2))/d/e/(e*sin(d*x+c))^(1/2)+(2*a^2+3*b^2)*EllipticE 
(cos(1/2*c+1/4*Pi+1/2*d*x),2^(1/2))*(e*sin(d*x+c))^(1/2)/(a^2-b^2)^2/d/e^2 
/sin(d*x+c)^(1/2)
 

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.

Time = 7.12 (sec) , antiderivative size = 865, normalized size of antiderivative = 1.71 \[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\frac {\sin ^2(c+d x) \left (-\frac {2 \left (-2 a b+a^2 \cos (c+d x)+b^2 \cos (c+d x)\right ) \csc (c+d x)}{\left (a^2-b^2\right )^2}+\frac {b^3 \sin (c+d x)}{\left (a^2-b^2\right )^2 (a+b \cos (c+d x))}\right )}{d (e \sin (c+d x))^{3/2}}-\frac {\sin ^{\frac {3}{2}}(c+d x) \left (\frac {\left (2 a^2 b+3 b^3\right ) \cos ^2(c+d x) \left (3 \sqrt {2} a \left (a^2-b^2\right )^{3/4} \left (2 \arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-2 \arctan \left (1+\frac {\sqrt {2} \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-\log \left (\sqrt {a^2-b^2}-\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\sin (c+d x)}+b \sin (c+d x)\right )+\log \left (\sqrt {a^2-b^2}+\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\sin (c+d x)}+b \sin (c+d x)\right )\right )+8 b^{5/2} \operatorname {AppellF1}\left (\frac {3}{4},-\frac {1}{2},1,\frac {7}{4},\sin ^2(c+d x),\frac {b^2 \sin ^2(c+d x)}{-a^2+b^2}\right ) \sin ^{\frac {3}{2}}(c+d x)\right ) \left (a+b \sqrt {1-\sin ^2(c+d x)}\right )}{12 b^{3/2} \left (-a^2+b^2\right ) (a+b \cos (c+d x)) \left (1-\sin ^2(c+d x)\right )}+\frac {2 \left (2 a^3+8 a b^2\right ) \cos (c+d x) \left (\frac {\left (\frac {1}{8}+\frac {i}{8}\right ) \left (2 \arctan \left (1-\frac {(1+i) \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{-a^2+b^2}}\right )-2 \arctan \left (1+\frac {(1+i) \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{-a^2+b^2}}\right )-\log \left (\sqrt {-a^2+b^2}-(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\sin (c+d x)}+i b \sin (c+d x)\right )+\log \left (\sqrt {-a^2+b^2}+(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\sin (c+d x)}+i b \sin (c+d x)\right )\right )}{\sqrt {b} \sqrt [4]{-a^2+b^2}}+\frac {a \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},1,\frac {7}{4},\sin ^2(c+d x),\frac {b^2 \sin ^2(c+d x)}{-a^2+b^2}\right ) \sin ^{\frac {3}{2}}(c+d x)}{3 \left (a^2-b^2\right )}\right ) \left (a+b \sqrt {1-\sin ^2(c+d x)}\right )}{(a+b \cos (c+d x)) \sqrt {1-\sin ^2(c+d x)}}\right )}{2 (a-b)^2 (a+b)^2 d (e \sin (c+d x))^{3/2}} \] Input:

Integrate[1/((a + b*Cos[c + d*x])^2*(e*Sin[c + d*x])^(3/2)),x]
 

Output:

(Sin[c + d*x]^2*((-2*(-2*a*b + a^2*Cos[c + d*x] + b^2*Cos[c + d*x])*Csc[c 
+ d*x])/(a^2 - b^2)^2 + (b^3*Sin[c + d*x])/((a^2 - b^2)^2*(a + b*Cos[c + d 
*x]))))/(d*(e*Sin[c + d*x])^(3/2)) - (Sin[c + d*x]^(3/2)*(((2*a^2*b + 3*b^ 
3)*Cos[c + d*x]^2*(3*Sqrt[2]*a*(a^2 - b^2)^(3/4)*(2*ArcTan[1 - (Sqrt[2]*Sq 
rt[b]*Sqrt[Sin[c + d*x]])/(a^2 - b^2)^(1/4)] - 2*ArcTan[1 + (Sqrt[2]*Sqrt[ 
b]*Sqrt[Sin[c + d*x]])/(a^2 - b^2)^(1/4)] - Log[Sqrt[a^2 - b^2] - Sqrt[2]* 
Sqrt[b]*(a^2 - b^2)^(1/4)*Sqrt[Sin[c + d*x]] + b*Sin[c + d*x]] + Log[Sqrt[ 
a^2 - b^2] + Sqrt[2]*Sqrt[b]*(a^2 - b^2)^(1/4)*Sqrt[Sin[c + d*x]] + b*Sin[ 
c + d*x]]) + 8*b^(5/2)*AppellF1[3/4, -1/2, 1, 7/4, Sin[c + d*x]^2, (b^2*Si 
n[c + d*x]^2)/(-a^2 + b^2)]*Sin[c + d*x]^(3/2))*(a + b*Sqrt[1 - Sin[c + d* 
x]^2]))/(12*b^(3/2)*(-a^2 + b^2)*(a + b*Cos[c + d*x])*(1 - Sin[c + d*x]^2) 
) + (2*(2*a^3 + 8*a*b^2)*Cos[c + d*x]*(((1/8 + I/8)*(2*ArcTan[1 - ((1 + I) 
*Sqrt[b]*Sqrt[Sin[c + d*x]])/(-a^2 + b^2)^(1/4)] - 2*ArcTan[1 + ((1 + I)*S 
qrt[b]*Sqrt[Sin[c + d*x]])/(-a^2 + b^2)^(1/4)] - Log[Sqrt[-a^2 + b^2] - (1 
 + I)*Sqrt[b]*(-a^2 + b^2)^(1/4)*Sqrt[Sin[c + d*x]] + I*b*Sin[c + d*x]] + 
Log[Sqrt[-a^2 + b^2] + (1 + I)*Sqrt[b]*(-a^2 + b^2)^(1/4)*Sqrt[Sin[c + d*x 
]] + I*b*Sin[c + d*x]]))/(Sqrt[b]*(-a^2 + b^2)^(1/4)) + (a*AppellF1[3/4, 1 
/2, 1, 7/4, Sin[c + d*x]^2, (b^2*Sin[c + d*x]^2)/(-a^2 + b^2)]*Sin[c + d*x 
]^(3/2))/(3*(a^2 - b^2)))*(a + b*Sqrt[1 - Sin[c + d*x]^2]))/((a + b*Cos[c 
+ d*x])*Sqrt[1 - Sin[c + d*x]^2])))/(2*(a - b)^2*(a + b)^2*d*(e*Sin[c +...
 

Rubi [A] (warning: unable to verify)

Time = 2.30 (sec) , antiderivative size = 490, normalized size of antiderivative = 0.97, number of steps used = 22, number of rules used = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.840, Rules used = {3042, 3173, 27, 3042, 3345, 27, 3042, 3346, 3042, 3121, 3042, 3119, 3180, 266, 827, 218, 221, 3042, 3286, 3042, 3284}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(e \sin (c+d x))^{3/2} (a+b \cos (c+d x))^2} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {1}{\left (e \cos \left (c+d x-\frac {\pi }{2}\right )\right )^{3/2} \left (a-b \sin \left (c+d x-\frac {\pi }{2}\right )\right )^2}dx\)

\(\Big \downarrow \) 3173

\(\displaystyle -\frac {\int -\frac {2 a-3 b \cos (c+d x)}{2 (a+b \cos (c+d x)) (e \sin (c+d x))^{3/2}}dx}{a^2-b^2}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {2 a-3 b \cos (c+d x)}{(a+b \cos (c+d x)) (e \sin (c+d x))^{3/2}}dx}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \frac {2 a+3 b \sin \left (c+d x-\frac {\pi }{2}\right )}{\left (e \cos \left (c+d x-\frac {\pi }{2}\right )\right )^{3/2} \left (a-b \sin \left (c+d x-\frac {\pi }{2}\right )\right )}dx}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3345

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {2 \int \frac {\left (2 a \left (a^2+4 b^2\right )+b \left (2 a^2+3 b^2\right ) \cos (c+d x)\right ) \sqrt {e \sin (c+d x)}}{2 (a+b \cos (c+d x))}dx}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {\int \frac {\left (2 a \left (a^2+4 b^2\right )+b \left (2 a^2+3 b^2\right ) \cos (c+d x)\right ) \sqrt {e \sin (c+d x)}}{a+b \cos (c+d x)}dx}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {\int \frac {\sqrt {-e \cos \left (c+d x+\frac {\pi }{2}\right )} \left (2 a \left (a^2+4 b^2\right )+b \left (2 a^2+3 b^2\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )}{a+b \sin \left (c+d x+\frac {\pi }{2}\right )}dx}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3346

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {\left (2 a^2+3 b^2\right ) \int \sqrt {e \sin (c+d x)}dx+5 a b^2 \int \frac {\sqrt {e \sin (c+d x)}}{a+b \cos (c+d x)}dx}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {\left (2 a^2+3 b^2\right ) \int \sqrt {e \sin (c+d x)}dx+5 a b^2 \int \frac {\sqrt {e \cos \left (c+d x-\frac {\pi }{2}\right )}}{a-b \sin \left (c+d x-\frac {\pi }{2}\right )}dx}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3121

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {\frac {\left (2 a^2+3 b^2\right ) \sqrt {e \sin (c+d x)} \int \sqrt {\sin (c+d x)}dx}{\sqrt {\sin (c+d x)}}+5 a b^2 \int \frac {\sqrt {e \cos \left (c+d x-\frac {\pi }{2}\right )}}{a-b \sin \left (c+d x-\frac {\pi }{2}\right )}dx}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {\frac {\left (2 a^2+3 b^2\right ) \sqrt {e \sin (c+d x)} \int \sqrt {\sin (c+d x)}dx}{\sqrt {\sin (c+d x)}}+5 a b^2 \int \frac {\sqrt {e \cos \left (c+d x-\frac {\pi }{2}\right )}}{a-b \sin \left (c+d x-\frac {\pi }{2}\right )}dx}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3119

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \int \frac {\sqrt {e \cos \left (c+d x-\frac {\pi }{2}\right )}}{a-b \sin \left (c+d x-\frac {\pi }{2}\right )}dx+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3180

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {b e \int \frac {\sqrt {e \sin (c+d x)}}{b^2 \sin ^2(c+d x) e^2+\left (a^2-b^2\right ) e^2}d(e \sin (c+d x))}{d}-\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 266

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {2 b e \int \frac {e^2 \sin ^2(c+d x)}{b^2 e^4 \sin ^4(c+d x)+\left (a^2-b^2\right ) e^2}d\sqrt {e \sin (c+d x)}}{d}-\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 827

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {2 b e \left (\frac {\int \frac {1}{b e^2 \sin ^2(c+d x)+\sqrt {b^2-a^2} e}d\sqrt {e \sin (c+d x)}}{2 b}-\frac {\int \frac {1}{\sqrt {b^2-a^2} e-b e^2 \sin ^2(c+d x)}d\sqrt {e \sin (c+d x)}}{2 b}\right )}{d}-\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 218

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\int \frac {1}{\sqrt {b^2-a^2} e-b e^2 \sin ^2(c+d x)}d\sqrt {e \sin (c+d x)}}{2 b}\right )}{d}-\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 221

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}-\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}-\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3286

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {a e \sqrt {\sin (c+d x)} \int \frac {1}{\sqrt {\sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b \sqrt {e \sin (c+d x)}}+\frac {a e \sqrt {\sin (c+d x)} \int \frac {1}{\sqrt {\sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b \sqrt {e \sin (c+d x)}}-\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {a e \sqrt {\sin (c+d x)} \int \frac {1}{\sqrt {\sin (c+d x)} \left (\sqrt {b^2-a^2}-b \sin (c+d x)\right )}dx}{2 b \sqrt {e \sin (c+d x)}}+\frac {a e \sqrt {\sin (c+d x)} \int \frac {1}{\sqrt {\sin (c+d x)} \left (b \sin (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b \sqrt {e \sin (c+d x)}}-\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

\(\Big \downarrow \) 3284

\(\displaystyle \frac {\frac {2 \left (5 a b-\left (2 a^2+3 b^2\right ) \cos (c+d x)\right )}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)}}-\frac {5 a b^2 \left (-\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \sin (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}+\frac {a e \sqrt {\sin (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {b^2-a^2}},\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right ),2\right )}{b d \left (b-\sqrt {b^2-a^2}\right ) \sqrt {e \sin (c+d x)}}+\frac {a e \sqrt {\sin (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {b^2-a^2}},\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right ),2\right )}{b d \left (\sqrt {b^2-a^2}+b\right ) \sqrt {e \sin (c+d x)}}\right )+\frac {2 \left (2 a^2+3 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{d \sqrt {\sin (c+d x)}}}{e^2 \left (a^2-b^2\right )}}{2 \left (a^2-b^2\right )}-\frac {b}{d e \left (a^2-b^2\right ) \sqrt {e \sin (c+d x)} (a+b \cos (c+d x))}\)

Input:

Int[1/((a + b*Cos[c + d*x])^2*(e*Sin[c + d*x])^(3/2)),x]
 

Output:

-(b/((a^2 - b^2)*d*e*(a + b*Cos[c + d*x])*Sqrt[e*Sin[c + d*x]])) + ((2*(5* 
a*b - (2*a^2 + 3*b^2)*Cos[c + d*x]))/((a^2 - b^2)*d*e*Sqrt[e*Sin[c + d*x]] 
) - ((2*(2*a^2 + 3*b^2)*EllipticE[(c - Pi/2 + d*x)/2, 2]*Sqrt[e*Sin[c + d* 
x]])/(d*Sqrt[Sin[c + d*x]]) + 5*a*b^2*((-2*b*e*(ArcTan[(Sqrt[b]*Sqrt[e]*Si 
n[c + d*x])/(-a^2 + b^2)^(1/4)]/(2*b^(3/2)*(-a^2 + b^2)^(1/4)*Sqrt[e]) - A 
rcTanh[(Sqrt[b]*Sqrt[e]*Sin[c + d*x])/(-a^2 + b^2)^(1/4)]/(2*b^(3/2)*(-a^2 
 + b^2)^(1/4)*Sqrt[e])))/d + (a*e*EllipticPi[(2*b)/(b - Sqrt[-a^2 + b^2]), 
 (c - Pi/2 + d*x)/2, 2]*Sqrt[Sin[c + d*x]])/(b*(b - Sqrt[-a^2 + b^2])*d*Sq 
rt[e*Sin[c + d*x]]) + (a*e*EllipticPi[(2*b)/(b + Sqrt[-a^2 + b^2]), (c - P 
i/2 + d*x)/2, 2]*Sqrt[Sin[c + d*x]])/(b*(b + Sqrt[-a^2 + b^2])*d*Sqrt[e*Si 
n[c + d*x]])))/((a^2 - b^2)*e^2))/(2*(a^2 - b^2))
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 218

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R 
t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
 

rule 221

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 266

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De 
nominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) 
^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I 
ntBinomialQ[a, b, c, 2, m, p, x]
 

rule 827

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 
 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2*b)   Int[1/(r + s*x^2), x], 
x] - Simp[s/(2*b)   Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !GtQ 
[a/b, 0]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3119

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* 
(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3121

Int[((b_)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*Sin[c + d*x]) 
^n/Sin[c + d*x]^n   Int[Sin[c + d*x]^n, x], x] /; FreeQ[{b, c, d}, x] && Lt 
Q[-1, n, 1] && IntegerQ[2*n]
 

rule 3173

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x 
_)])^(m_), x_Symbol] :> Simp[(-b)*(g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + 
f*x])^(m + 1)/(f*g*(a^2 - b^2)*(m + 1))), x] + Simp[1/((a^2 - b^2)*(m + 1)) 
   Int[(g*Cos[e + f*x])^p*(a + b*Sin[e + f*x])^(m + 1)*(a*(m + 1) - b*(m + 
p + 2)*Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f, g, p}, x] && NeQ[a^2 - b 
^2, 0] && LtQ[m, -1] && IntegersQ[2*m, 2*p]
 

rule 3180

Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(g_.)]/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_ 
)]), x_Symbol] :> With[{q = Rt[-a^2 + b^2, 2]}, Simp[a*(g/(2*b))   Int[1/(S 
qrt[g*Cos[e + f*x]]*(q + b*Cos[e + f*x])), x], x] + (-Simp[a*(g/(2*b))   In 
t[1/(Sqrt[g*Cos[e + f*x]]*(q - b*Cos[e + f*x])), x], x] + Simp[b*(g/f)   Su 
bst[Int[Sqrt[x]/(g^2*(a^2 - b^2) + b^2*x^2), x], x, g*Cos[e + f*x]], x])] / 
; FreeQ[{a, b, e, f, g}, x] && NeQ[a^2 - b^2, 0]
 

rule 3284

Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) 
 + (f_.)*(x_)]]), x_Symbol] :> Simp[(2/(f*(a + b)*Sqrt[c + d]))*EllipticPi[ 
2*(b/(a + b)), (1/2)*(e - Pi/2 + f*x), 2*(d/(c + d))], x] /; FreeQ[{a, b, c 
, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 
0] && GtQ[c + d, 0]
 

rule 3286

Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) 
 + (f_.)*(x_)]]), x_Symbol] :> Simp[Sqrt[(c + d*Sin[e + f*x])/(c + d)]/Sqrt 
[c + d*Sin[e + f*x]]   Int[1/((a + b*Sin[e + f*x])*Sqrt[c/(c + d) + (d/(c + 
 d))*Sin[e + f*x]]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a* 
d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !GtQ[c + d, 0]
 

rule 3345

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x 
_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(g*Co 
s[e + f*x])^(p + 1)*(a + b*Sin[e + f*x])^(m + 1)*((b*c - a*d - (a*c - b*d)* 
Sin[e + f*x])/(f*g*(a^2 - b^2)*(p + 1))), x] + Simp[1/(g^2*(a^2 - b^2)*(p + 
 1))   Int[(g*Cos[e + f*x])^(p + 2)*(a + b*Sin[e + f*x])^m*Simp[c*(a^2*(p + 
 2) - b^2*(m + p + 2)) + a*b*d*m + b*(a*c - b*d)*(m + p + 3)*Sin[e + f*x], 
x], x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && NeQ[a^2 - b^2, 0] && Lt 
Q[p, -1] && IntegerQ[2*m]
 

rule 3346

Int[((cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((c_.) + (d_.)*sin[(e_.) + (f_.)* 
(x_)]))/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[d/b   Int 
[(g*Cos[e + f*x])^p, x], x] + Simp[(b*c - a*d)/b   Int[(g*Cos[e + f*x])^p/( 
a + b*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[a^2 - 
 b^2, 0]
 

Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(2001\) vs. \(2(446)=892\).

Time = 2.92 (sec) , antiderivative size = 2002, normalized size of antiderivative = 3.95

method	result	size
default	\(\text {Expression too large to display}\)	\(2002\)

Input:

int(1/(a+cos(d*x+c)*b)^2/(e*sin(d*x+c))^(3/2),x,method=_RETURNVERBOSE)
 

Output:

(-4*e^3*a*b*(-b^2/e^4/(a-b)^2/(a+b)^2*(1/4*(e*sin(d*x+c))^(3/2)/(-b^2*cos( 
d*x+c)^2*e^2+a^2*e^2)+5/32/b^2/(e^2*(a^2-b^2)/b^2)^(1/4)*2^(1/2)*(ln((e*si 
n(d*x+c)-(e^2*(a^2-b^2)/b^2)^(1/4)*(e*sin(d*x+c))^(1/2)*2^(1/2)+(e^2*(a^2- 
b^2)/b^2)^(1/2))/(e*sin(d*x+c)+(e^2*(a^2-b^2)/b^2)^(1/4)*(e*sin(d*x+c))^(1 
/2)*2^(1/2)+(e^2*(a^2-b^2)/b^2)^(1/2)))+2*arctan(2^(1/2)/(e^2*(a^2-b^2)/b^ 
2)^(1/4)*(e*sin(d*x+c))^(1/2)+1)+2*arctan(2^(1/2)/(e^2*(a^2-b^2)/b^2)^(1/4 
)*(e*sin(d*x+c))^(1/2)-1)))-1/e^4/(a^2-b^2)^2/(e*sin(d*x+c))^(1/2))-1/4/e* 
a^2*(-8*a^4*cos(d*x+c)^2-4*a^4*(1-sin(d*x+c))^(1/2)*(2+2*sin(d*x+c))^(1/2) 
*sin(d*x+c)^(1/2)*EllipticF((1-sin(d*x+c))^(1/2),1/2*2^(1/2))-2*a^2*b^2*(1 
-sin(d*x+c))^(1/2)*(2+2*sin(d*x+c))^(1/2)*sin(d*x+c)^(1/2)*EllipticF((1-si 
n(d*x+c))^(1/2),1/2*2^(1/2))+6*b^4*(1-sin(d*x+c))^(1/2)*(2+2*sin(d*x+c))^( 
1/2)*sin(d*x+c)^(1/2)*EllipticF((1-sin(d*x+c))^(1/2),1/2*2^(1/2))+5*(-a^2+ 
b^2)^(1/2)*(1-sin(d*x+c))^(1/2)*(2+2*sin(d*x+c))^(1/2)*sin(d*x+c)^(1/2)*El 
lipticPi((1-sin(d*x+c))^(1/2),-b/(-b+(-a^2+b^2)^(1/2)),1/2*2^(1/2))*a^2*b- 
5*(-a^2+b^2)^(1/2)*(1-sin(d*x+c))^(1/2)*(2+2*sin(d*x+c))^(1/2)*sin(d*x+c)^ 
(1/2)*EllipticPi((1-sin(d*x+c))^(1/2),b/(b+(-a^2+b^2)^(1/2)),1/2*2^(1/2))* 
a^2*b+12*(1-sin(d*x+c))^(1/2)*(2+2*sin(d*x+c))^(1/2)*sin(d*x+c)^(5/2)*Elli 
pticE((1-sin(d*x+c))^(1/2),1/2*2^(1/2))*b^4-6*(1-sin(d*x+c))^(1/2)*(2+2*si 
n(d*x+c))^(1/2)*sin(d*x+c)^(5/2)*EllipticF((1-sin(d*x+c))^(1/2),1/2*2^(1/2 
))*b^4+5*(1-sin(d*x+c))^(1/2)*(2+2*sin(d*x+c))^(1/2)*sin(d*x+c)^(5/2)*E...
 

Fricas [F(-1)]

Timed out. \[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\text {Timed out} \] Input:

integrate(1/(a+b*cos(d*x+c))^2/(e*sin(d*x+c))^(3/2),x, algorithm="fricas")
 

Output:

Timed out
 

Sympy [F]

\[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\int \frac {1}{\left (e \sin {\left (c + d x \right )}\right )^{\frac {3}{2}} \left (a + b \cos {\left (c + d x \right )}\right )^{2}}\, dx \] Input:

integrate(1/(a+b*cos(d*x+c))**2/(e*sin(d*x+c))**(3/2),x)
 

Output:

Integral(1/((e*sin(c + d*x))**(3/2)*(a + b*cos(c + d*x))**2), x)
 

Maxima [F(-1)]

Timed out. \[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\text {Timed out} \] Input:

integrate(1/(a+b*cos(d*x+c))^2/(e*sin(d*x+c))^(3/2),x, algorithm="maxima")
 

Output:

Timed out
 

Giac [F]

\[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\int { \frac {1}{{\left (b \cos \left (d x + c\right ) + a\right )}^{2} \left (e \sin \left (d x + c\right )\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(a+b*cos(d*x+c))^2/(e*sin(d*x+c))^(3/2),x, algorithm="giac")
 

Output:

integrate(1/((b*cos(d*x + c) + a)^2*(e*sin(d*x + c))^(3/2)), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\int \frac {1}{{\left (e\,\sin \left (c+d\,x\right )\right )}^{3/2}\,{\left (a+b\,\cos \left (c+d\,x\right )\right )}^2} \,d x \] Input:

int(1/((e*sin(c + d*x))^(3/2)*(a + b*cos(c + d*x))^2),x)
 

Output:

int(1/((e*sin(c + d*x))^(3/2)*(a + b*cos(c + d*x))^2), x)
 

Reduce [F]

\[ \int \frac {1}{(a+b \cos (c+d x))^2 (e \sin (c+d x))^{3/2}} \, dx=\frac {\sqrt {e}\, \left (\int \frac {\sqrt {\sin \left (d x +c \right )}}{\cos \left (d x +c \right )^{2} \sin \left (d x +c \right )^{2} b^{2}+2 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} a b +\sin \left (d x +c \right )^{2} a^{2}}d x \right )}{e^{2}} \] Input:

int(1/(a+b*cos(d*x+c))^2/(e*sin(d*x+c))^(3/2),x)
 

Output:

(sqrt(e)*int(sqrt(sin(c + d*x))/(cos(c + d*x)**2*sin(c + d*x)**2*b**2 + 2* 
cos(c + d*x)*sin(c + d*x)**2*a*b + sin(c + d*x)**2*a**2),x))/e**2