\(\int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx\) [770]

Optimal result

Integrand size = 21, antiderivative size = 250 \[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\frac {a b^2 (7+2 m) \cos ^{1+m}(c+d x) \sin (c+d x)}{d (2+m) (3+m)}+\frac {b^2 \cos ^{1+m}(c+d x) (a+b \cos (c+d x)) \sin (c+d x)}{d (3+m)}-\frac {a \left (3 b^2 (1+m)+a^2 (2+m)\right ) \cos ^{1+m}(c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\cos ^2(c+d x)\right ) \sin (c+d x)}{d (1+m) (2+m) \sqrt {\sin ^2(c+d x)}}-\frac {b \left (b^2 (2+m)+3 a^2 (3+m)\right ) \cos ^{2+m}(c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},\cos ^2(c+d x)\right ) \sin (c+d x)}{d (2+m) (3+m) \sqrt {\sin ^2(c+d x)}} \] Output:

a*b^2*(7+2*m)*cos(d*x+c)^(1+m)*sin(d*x+c)/d/(2+m)/(3+m)+b^2*cos(d*x+c)^(1+ 
m)*(a+b*cos(d*x+c))*sin(d*x+c)/d/(3+m)-a*(3*b^2*(1+m)+a^2*(2+m))*cos(d*x+c 
)^(1+m)*hypergeom([1/2, 1/2+1/2*m],[3/2+1/2*m],cos(d*x+c)^2)*sin(d*x+c)/d/ 
(1+m)/(2+m)/(sin(d*x+c)^2)^(1/2)-b*(b^2*(2+m)+3*a^2*(3+m))*cos(d*x+c)^(2+m 
)*hypergeom([1/2, 1+1/2*m],[2+1/2*m],cos(d*x+c)^2)*sin(d*x+c)/d/(2+m)/(3+m 
)/(sin(d*x+c)^2)^(1/2)
 

Mathematica [A] (verified)

Time = 0.63 (sec) , antiderivative size = 197, normalized size of antiderivative = 0.79 \[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\frac {\cos ^{1+m}(c+d x) \csc (c+d x) \left (-\frac {a^3 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\cos ^2(c+d x)\right )}{1+m}+b \cos (c+d x) \left (-\frac {3 a^2 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},\cos ^2(c+d x)\right )}{2+m}+b \cos (c+d x) \left (-\frac {3 a \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},\cos ^2(c+d x)\right )}{3+m}-\frac {b \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {4+m}{2},\frac {6+m}{2},\cos ^2(c+d x)\right )}{4+m}\right )\right )\right ) \sqrt {\sin ^2(c+d x)}}{d} \] Input:

Integrate[Cos[c + d*x]^m*(a + b*Cos[c + d*x])^3,x]
 

Output:

(Cos[c + d*x]^(1 + m)*Csc[c + d*x]*(-((a^3*Hypergeometric2F1[1/2, (1 + m)/ 
2, (3 + m)/2, Cos[c + d*x]^2])/(1 + m)) + b*Cos[c + d*x]*((-3*a^2*Hypergeo 
metric2F1[1/2, (2 + m)/2, (4 + m)/2, Cos[c + d*x]^2])/(2 + m) + b*Cos[c + 
d*x]*((-3*a*Hypergeometric2F1[1/2, (3 + m)/2, (5 + m)/2, Cos[c + d*x]^2])/ 
(3 + m) - (b*Cos[c + d*x]*Hypergeometric2F1[1/2, (4 + m)/2, (6 + m)/2, Cos 
[c + d*x]^2])/(4 + m))))*Sqrt[Sin[c + d*x]^2])/d
 

Rubi [A] (verified)

Time = 0.85 (sec) , antiderivative size = 247, normalized size of antiderivative = 0.99, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.381, Rules used = {3042, 3272, 3042, 3502, 3042, 3227, 3042, 3122}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \sin \left (c+d x+\frac {\pi }{2}\right )^m \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^3dx\)

\(\Big \downarrow \) 3272

\(\displaystyle \frac {\int \cos ^m(c+d x) \left (a b^2 (2 m+7) \cos ^2(c+d x)+b \left (3 (m+3) a^2+b^2 (m+2)\right ) \cos (c+d x)+a \left ((m+3) a^2+b^2 (m+1)\right )\right )dx}{m+3}+\frac {b^2 \sin (c+d x) \cos ^{m+1}(c+d x) (a+b \cos (c+d x))}{d (m+3)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \sin \left (c+d x+\frac {\pi }{2}\right )^m \left (a b^2 (2 m+7) \sin \left (c+d x+\frac {\pi }{2}\right )^2+b \left (3 (m+3) a^2+b^2 (m+2)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )+a \left ((m+3) a^2+b^2 (m+1)\right )\right )dx}{m+3}+\frac {b^2 \sin (c+d x) \cos ^{m+1}(c+d x) (a+b \cos (c+d x))}{d (m+3)}\)

\(\Big \downarrow \) 3502

\(\displaystyle \frac {\frac {\int \cos ^m(c+d x) \left (a (m+3) \left ((m+2) a^2+3 b^2 (m+1)\right )+b (m+2) \left (3 (m+3) a^2+b^2 (m+2)\right ) \cos (c+d x)\right )dx}{m+2}+\frac {a b^2 (2 m+7) \sin (c+d x) \cos ^{m+1}(c+d x)}{d (m+2)}}{m+3}+\frac {b^2 \sin (c+d x) \cos ^{m+1}(c+d x) (a+b \cos (c+d x))}{d (m+3)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \sin \left (c+d x+\frac {\pi }{2}\right )^m \left (a (m+3) \left ((m+2) a^2+3 b^2 (m+1)\right )+b (m+2) \left (3 (m+3) a^2+b^2 (m+2)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{m+2}+\frac {a b^2 (2 m+7) \sin (c+d x) \cos ^{m+1}(c+d x)}{d (m+2)}}{m+3}+\frac {b^2 \sin (c+d x) \cos ^{m+1}(c+d x) (a+b \cos (c+d x))}{d (m+3)}\)

\(\Big \downarrow \) 3227

\(\displaystyle \frac {\frac {b (m+2) \left (3 a^2 (m+3)+b^2 (m+2)\right ) \int \cos ^{m+1}(c+d x)dx+a (m+3) \left (a^2 (m+2)+3 b^2 (m+1)\right ) \int \cos ^m(c+d x)dx}{m+2}+\frac {a b^2 (2 m+7) \sin (c+d x) \cos ^{m+1}(c+d x)}{d (m+2)}}{m+3}+\frac {b^2 \sin (c+d x) \cos ^{m+1}(c+d x) (a+b \cos (c+d x))}{d (m+3)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {a (m+3) \left (a^2 (m+2)+3 b^2 (m+1)\right ) \int \sin \left (c+d x+\frac {\pi }{2}\right )^mdx+b (m+2) \left (3 a^2 (m+3)+b^2 (m+2)\right ) \int \sin \left (c+d x+\frac {\pi }{2}\right )^{m+1}dx}{m+2}+\frac {a b^2 (2 m+7) \sin (c+d x) \cos ^{m+1}(c+d x)}{d (m+2)}}{m+3}+\frac {b^2 \sin (c+d x) \cos ^{m+1}(c+d x) (a+b \cos (c+d x))}{d (m+3)}\)

\(\Big \downarrow \) 3122

\(\displaystyle \frac {\frac {-\frac {a (m+3) \left (a^2 (m+2)+3 b^2 (m+1)\right ) \sin (c+d x) \cos ^{m+1}(c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m+1}{2},\frac {m+3}{2},\cos ^2(c+d x)\right )}{d (m+1) \sqrt {\sin ^2(c+d x)}}-\frac {b \left (3 a^2 (m+3)+b^2 (m+2)\right ) \sin (c+d x) \cos ^{m+2}(c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m+2}{2},\frac {m+4}{2},\cos ^2(c+d x)\right )}{d \sqrt {\sin ^2(c+d x)}}}{m+2}+\frac {a b^2 (2 m+7) \sin (c+d x) \cos ^{m+1}(c+d x)}{d (m+2)}}{m+3}+\frac {b^2 \sin (c+d x) \cos ^{m+1}(c+d x) (a+b \cos (c+d x))}{d (m+3)}\)

Input:

Int[Cos[c + d*x]^m*(a + b*Cos[c + d*x])^3,x]
 

Output:

(b^2*Cos[c + d*x]^(1 + m)*(a + b*Cos[c + d*x])*Sin[c + d*x])/(d*(3 + m)) + 
 ((a*b^2*(7 + 2*m)*Cos[c + d*x]^(1 + m)*Sin[c + d*x])/(d*(2 + m)) + (-((a* 
(3 + m)*(3*b^2*(1 + m) + a^2*(2 + m))*Cos[c + d*x]^(1 + m)*Hypergeometric2 
F1[1/2, (1 + m)/2, (3 + m)/2, Cos[c + d*x]^2]*Sin[c + d*x])/(d*(1 + m)*Sqr 
t[Sin[c + d*x]^2])) - (b*(b^2*(2 + m) + 3*a^2*(3 + m))*Cos[c + d*x]^(2 + m 
)*Hypergeometric2F1[1/2, (2 + m)/2, (4 + m)/2, Cos[c + d*x]^2]*Sin[c + d*x 
])/(d*Sqrt[Sin[c + d*x]^2]))/(2 + m))/(3 + m)
 

Defintions of rubi rules used

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3122

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*(( 
b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]))*Hypergeometric2 
F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2], x] /; FreeQ[{b, c, d, n}, x] 
 &&  !IntegerQ[2*n]
 

rule 3227

Int[((b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*sin[(e_.) + (f_.)*(x 
_)]), x_Symbol] :> Simp[c   Int[(b*Sin[e + f*x])^m, x], x] + Simp[d/b   Int 
[(b*Sin[e + f*x])^(m + 1), x], x] /; FreeQ[{b, c, d, e, f, m}, x]
 

rule 3272

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b^2)*Cos[e + f*x]*(a + b*Sin[e + f* 
x])^(m - 2)*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(m + n))), x] + Simp[1/(d*(m 
 + n))   Int[(a + b*Sin[e + f*x])^(m - 3)*(c + d*Sin[e + f*x])^n*Simp[a^3*d 
*(m + n) + b^2*(b*c*(m - 2) + a*d*(n + 1)) - b*(a*b*c - b^2*d*(m + n - 1) - 
 3*a^2*d*(m + n))*Sin[e + f*x] - b^2*(b*c*(m - 1) - a*d*(3*m + 2*n - 2))*Si 
n[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a* 
d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 2] && (IntegerQ[m 
] || IntegersQ[2*m, 2*n]) &&  !(IGtQ[n, 2] && ( !IntegerQ[m] || (EqQ[a, 0] 
&& NeQ[c, 0])))
 

rule 3502

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) 
+ (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co 
s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m 
+ 2))   Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m 
 + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] 
 &&  !LtQ[m, -1]
 

Maple [F]

\[\int \cos \left (d x +c \right )^{m} \left (a +\cos \left (d x +c \right ) b \right )^{3}d x\]

Input:

int(cos(d*x+c)^m*(a+cos(d*x+c)*b)^3,x)
 

Output:

int(cos(d*x+c)^m*(a+cos(d*x+c)*b)^3,x)
 

Fricas [F]

\[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\int { {\left (b \cos \left (d x + c\right ) + a\right )}^{3} \cos \left (d x + c\right )^{m} \,d x } \] Input:

integrate(cos(d*x+c)^m*(a+b*cos(d*x+c))^3,x, algorithm="fricas")
 

Output:

integral((b^3*cos(d*x + c)^3 + 3*a*b^2*cos(d*x + c)^2 + 3*a^2*b*cos(d*x + 
c) + a^3)*cos(d*x + c)^m, x)
 

Sympy [F(-1)]

Timed out. \[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\text {Timed out} \] Input:

integrate(cos(d*x+c)**m*(a+b*cos(d*x+c))**3,x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\int { {\left (b \cos \left (d x + c\right ) + a\right )}^{3} \cos \left (d x + c\right )^{m} \,d x } \] Input:

integrate(cos(d*x+c)^m*(a+b*cos(d*x+c))^3,x, algorithm="maxima")
 

Output:

integrate((b*cos(d*x + c) + a)^3*cos(d*x + c)^m, x)
 

Giac [F]

\[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\int { {\left (b \cos \left (d x + c\right ) + a\right )}^{3} \cos \left (d x + c\right )^{m} \,d x } \] Input:

integrate(cos(d*x+c)^m*(a+b*cos(d*x+c))^3,x, algorithm="giac")
 

Output:

integrate((b*cos(d*x + c) + a)^3*cos(d*x + c)^m, x)
 

Mupad [F(-1)]

Timed out. \[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\int {\cos \left (c+d\,x\right )}^m\,{\left (a+b\,\cos \left (c+d\,x\right )\right )}^3 \,d x \] Input:

int(cos(c + d*x)^m*(a + b*cos(c + d*x))^3,x)
 

Output:

int(cos(c + d*x)^m*(a + b*cos(c + d*x))^3, x)
 

Reduce [F]

\[ \int \cos ^m(c+d x) (a+b \cos (c+d x))^3 \, dx=\left (\int \cos \left (d x +c \right )^{m}d x \right ) a^{3}+3 \left (\int \cos \left (d x +c \right )^{m} \cos \left (d x +c \right )d x \right ) a^{2} b +\left (\int \cos \left (d x +c \right )^{m} \cos \left (d x +c \right )^{3}d x \right ) b^{3}+3 \left (\int \cos \left (d x +c \right )^{m} \cos \left (d x +c \right )^{2}d x \right ) a \,b^{2} \] Input:

int(cos(d*x+c)^m*(a+b*cos(d*x+c))^3,x)
 

Output:

int(cos(c + d*x)**m,x)*a**3 + 3*int(cos(c + d*x)**m*cos(c + d*x),x)*a**2*b 
 + int(cos(c + d*x)**m*cos(c + d*x)**3,x)*b**3 + 3*int(cos(c + d*x)**m*cos 
(c + d*x)**2,x)*a*b**2