Integrand size = 31, antiderivative size = 198 \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx=b^3 (A b+4 a B) x+\frac {a \left (4 a^2 A b+8 A b^3+a^3 B+12 a b^2 B\right ) \text {arctanh}(\sin (c+d x))}{2 d}-\frac {b^2 \left (8 a A b+3 a^2 B-6 b^2 B\right ) \sin (c+d x)}{6 d}+\frac {a^2 \left (2 a^2 A+9 A b^2+9 a b B\right ) \tan (c+d x)}{3 d}+\frac {a (2 A b+a B) (a+b \cos (c+d x))^2 \sec (c+d x) \tan (c+d x)}{2 d}+\frac {a A (a+b \cos (c+d x))^3 \sec ^2(c+d x) \tan (c+d x)}{3 d} \] Output:
b^3*(A*b+4*B*a)*x+1/2*a*(4*A*a^2*b+8*A*b^3+B*a^3+12*B*a*b^2)*arctanh(sin(d *x+c))/d-1/6*b^2*(8*A*a*b+3*B*a^2-6*B*b^2)*sin(d*x+c)/d+1/3*a^2*(2*A*a^2+9 *A*b^2+9*B*a*b)*tan(d*x+c)/d+1/2*a*(2*A*b+B*a)*(a+b*cos(d*x+c))^2*sec(d*x+ c)*tan(d*x+c)/d+1/3*a*A*(a+b*cos(d*x+c))^3*sec(d*x+c)^2*tan(d*x+c)/d
Leaf count is larger than twice the leaf count of optimal. \(831\) vs. \(2(198)=396\).
Time = 10.29 (sec) , antiderivative size = 831, normalized size of antiderivative = 4.20 \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx =\text {Too large to display} \] Input:
Integrate[(a + b*Cos[c + d*x])^4*(A + B*Cos[c + d*x])*Sec[c + d*x]^4,x]
Output:
(b^3*(A*b + 4*a*B)*(c + d*x)*Cos[c + d*x]^4*(b + a*Sec[c + d*x])^4)/(d*(a + b*Cos[c + d*x])^4) + ((-4*a^3*A*b - 8*a*A*b^3 - a^4*B - 12*a^2*b^2*B)*Co s[c + d*x]^4*Log[Cos[(c + d*x)/2] - Sin[(c + d*x)/2]]*(b + a*Sec[c + d*x]) ^4)/(2*d*(a + b*Cos[c + d*x])^4) + ((4*a^3*A*b + 8*a*A*b^3 + a^4*B + 12*a^ 2*b^2*B)*Cos[c + d*x]^4*Log[Cos[(c + d*x)/2] + Sin[(c + d*x)/2]]*(b + a*Se c[c + d*x])^4)/(2*d*(a + b*Cos[c + d*x])^4) + ((a^4*A + 12*a^3*A*b + 3*a^4 *B)*Cos[c + d*x]^4*(b + a*Sec[c + d*x])^4)/(12*d*(a + b*Cos[c + d*x])^4*(C os[(c + d*x)/2] - Sin[(c + d*x)/2])^2) + (a^4*A*Cos[c + d*x]^4*(b + a*Sec[ c + d*x])^4*Sin[(c + d*x)/2])/(6*d*(a + b*Cos[c + d*x])^4*(Cos[(c + d*x)/2 ] - Sin[(c + d*x)/2])^3) + (a^4*A*Cos[c + d*x]^4*(b + a*Sec[c + d*x])^4*Si n[(c + d*x)/2])/(6*d*(a + b*Cos[c + d*x])^4*(Cos[(c + d*x)/2] + Sin[(c + d *x)/2])^3) + ((-(a^4*A) - 12*a^3*A*b - 3*a^4*B)*Cos[c + d*x]^4*(b + a*Sec[ c + d*x])^4)/(12*d*(a + b*Cos[c + d*x])^4*(Cos[(c + d*x)/2] + Sin[(c + d*x )/2])^2) + (2*Cos[c + d*x]^4*(b + a*Sec[c + d*x])^4*(a^4*A*Sin[(c + d*x)/2 ] + 9*a^2*A*b^2*Sin[(c + d*x)/2] + 6*a^3*b*B*Sin[(c + d*x)/2]))/(3*d*(a + b*Cos[c + d*x])^4*(Cos[(c + d*x)/2] - Sin[(c + d*x)/2])) + (2*Cos[c + d*x] ^4*(b + a*Sec[c + d*x])^4*(a^4*A*Sin[(c + d*x)/2] + 9*a^2*A*b^2*Sin[(c + d *x)/2] + 6*a^3*b*B*Sin[(c + d*x)/2]))/(3*d*(a + b*Cos[c + d*x])^4*(Cos[(c + d*x)/2] + Sin[(c + d*x)/2])) + (b^4*B*Cos[c + d*x]^4*(b + a*Sec[c + d*x] )^4*Sin[c + d*x])/(d*(a + b*Cos[c + d*x])^4)
Time = 1.47 (sec) , antiderivative size = 205, normalized size of antiderivative = 1.04, number of steps used = 14, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.452, Rules used = {3042, 3468, 3042, 3526, 3042, 3510, 25, 3042, 3502, 27, 3042, 3214, 3042, 4257}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \sec ^4(c+d x) (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^4 \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^4}dx\) |
| \(\Big \downarrow \) 3468 |
| \(\displaystyle \frac {1}{3} \int (a+b \cos (c+d x))^2 \left (-b (a A-3 b B) \cos ^2(c+d x)+\left (2 A a^2+6 b B a+3 A b^2\right ) \cos (c+d x)+3 a (2 A b+a B)\right ) \sec ^3(c+d x)dx+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{3} \int \frac {\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^2 \left (-b (a A-3 b B) \sin \left (c+d x+\frac {\pi }{2}\right )^2+\left (2 A a^2+6 b B a+3 A b^2\right ) \sin \left (c+d x+\frac {\pi }{2}\right )+3 a (2 A b+a B)\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^3}dx+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3526 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \int (a+b \cos (c+d x)) \left (-b \left (3 B a^2+8 A b a-6 b^2 B\right ) \cos ^2(c+d x)+\left (3 B a^3+8 A b a^2+18 b^2 B a+6 A b^3\right ) \cos (c+d x)+2 a \left (2 A a^2+9 b B a+9 A b^2\right )\right ) \sec ^2(c+d x)dx+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \int \frac {\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right ) \left (-b \left (3 B a^2+8 A b a-6 b^2 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )^2+\left (3 B a^3+8 A b a^2+18 b^2 B a+6 A b^3\right ) \sin \left (c+d x+\frac {\pi }{2}\right )+2 a \left (2 A a^2+9 b B a+9 A b^2\right )\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^2}dx+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3510 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}-\int -\left (\left (6 (A b+4 a B) \cos (c+d x) b^3-\left (3 B a^2+8 A b a-6 b^2 B\right ) \cos ^2(c+d x) b^2+3 a \left (B a^3+4 A b a^2+12 b^2 B a+8 A b^3\right )\right ) \sec (c+d x)\right )dx\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (\int \left (6 (A b+4 a B) \cos (c+d x) b^3-\left (3 B a^2+8 A b a-6 b^2 B\right ) \cos ^2(c+d x) b^2+3 a \left (B a^3+4 A b a^2+12 b^2 B a+8 A b^3\right )\right ) \sec (c+d x)dx+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (\int \frac {6 (A b+4 a B) \sin \left (c+d x+\frac {\pi }{2}\right ) b^3-\left (3 B a^2+8 A b a-6 b^2 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )^2 b^2+3 a \left (B a^3+4 A b a^2+12 b^2 B a+8 A b^3\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )}dx+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3502 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (\int 3 \left (2 (A b+4 a B) \cos (c+d x) b^3+a \left (B a^3+4 A b a^2+12 b^2 B a+8 A b^3\right )\right ) \sec (c+d x)dx-\frac {b^2 \left (3 a^2 B+8 a A b-6 b^2 B\right ) \sin (c+d x)}{d}+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (3 \int \left (2 (A b+4 a B) \cos (c+d x) b^3+a \left (B a^3+4 A b a^2+12 b^2 B a+8 A b^3\right )\right ) \sec (c+d x)dx-\frac {b^2 \left (3 a^2 B+8 a A b-6 b^2 B\right ) \sin (c+d x)}{d}+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (3 \int \frac {2 (A b+4 a B) \sin \left (c+d x+\frac {\pi }{2}\right ) b^3+a \left (B a^3+4 A b a^2+12 b^2 B a+8 A b^3\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )}dx-\frac {b^2 \left (3 a^2 B+8 a A b-6 b^2 B\right ) \sin (c+d x)}{d}+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3214 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (3 \left (a \left (a^3 B+4 a^2 A b+12 a b^2 B+8 A b^3\right ) \int \sec (c+d x)dx+2 b^3 x (4 a B+A b)\right )-\frac {b^2 \left (3 a^2 B+8 a A b-6 b^2 B\right ) \sin (c+d x)}{d}+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (3 \left (a \left (a^3 B+4 a^2 A b+12 a b^2 B+8 A b^3\right ) \int \csc \left (c+d x+\frac {\pi }{2}\right )dx+2 b^3 x (4 a B+A b)\right )-\frac {b^2 \left (3 a^2 B+8 a A b-6 b^2 B\right ) \sin (c+d x)}{d}+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
| \(\Big \downarrow \) 4257 |
| \(\displaystyle \frac {1}{3} \left (\frac {1}{2} \left (-\frac {b^2 \left (3 a^2 B+8 a A b-6 b^2 B\right ) \sin (c+d x)}{d}+\frac {2 a^2 \left (2 a^2 A+9 a b B+9 A b^2\right ) \tan (c+d x)}{d}+3 \left (\frac {a \left (a^3 B+4 a^2 A b+12 a b^2 B+8 A b^3\right ) \text {arctanh}(\sin (c+d x))}{d}+2 b^3 x (4 a B+A b)\right )\right )+\frac {3 a (a B+2 A b) \tan (c+d x) \sec (c+d x) (a+b \cos (c+d x))^2}{2 d}\right )+\frac {a A \tan (c+d x) \sec ^2(c+d x) (a+b \cos (c+d x))^3}{3 d}\) |
Input:
Int[(a + b*Cos[c + d*x])^4*(A + B*Cos[c + d*x])*Sec[c + d*x]^4,x]
Output:
(a*A*(a + b*Cos[c + d*x])^3*Sec[c + d*x]^2*Tan[c + d*x])/(3*d) + ((3*a*(2* A*b + a*B)*(a + b*Cos[c + d*x])^2*Sec[c + d*x]*Tan[c + d*x])/(2*d) + (3*(2 *b^3*(A*b + 4*a*B)*x + (a*(4*a^2*A*b + 8*A*b^3 + a^3*B + 12*a*b^2*B)*ArcTa nh[Sin[c + d*x]])/d) - (b^2*(8*a*A*b + 3*a^2*B - 6*b^2*B)*Sin[c + d*x])/d + (2*a^2*(2*a^2*A + 9*A*b^2 + 9*a*b*B)*Tan[c + d*x])/d)/2)/3
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])/((c_.) + (d_.)*sin[(e_.) + (f_. )*(x_)]), x_Symbol] :> Simp[b*(x/d), x] - Simp[(b*c - a*d)/d Int[1/(c + d *Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Si mp[(-(b*c - a*d))*(B*c - A*d)*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(n + 1)*(c^2 - d^2))), x] + Simp[1/(d*(n + 1)*(c^2 - d^2)) Int[(a + b*Sin[e + f*x])^(m - 2)*(c + d*Sin[e + f*x])^(n + 1)*Simp[b*(b*c - a*d)*(B*c - A*d)*(m - 1) + a*d*(a*A*c + b*B*c - (A*b + a *B)*d)*(n + 1) + (b*(b*d*(B*c - A*d) + a*(A*c*d + B*(c^2 - 2*d^2)))*(n + 1) - a*(b*c - a*d)*(B*c - A*d)*(n + 2))*Sin[e + f*x] + b*(d*(A*b*c + a*B*c - a*A*d)*(m + n + 1) - b*B*(c^2*m + d^2*(n + 1)))*Sin[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2 , 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 1] && LtQ[n, -1]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m + 2)) Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] && !LtQ[m, -1]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f _.)*(x_)]^2), x_Symbol] :> Simp[(-(b*c - a*d))*(A*b^2 - a*b*B + a^2*C)*Cos[ e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b^2*f*(m + 1)*(a^2 - b^2))), x] - S imp[1/(b^2*(m + 1)*(a^2 - b^2)) Int[(a + b*Sin[e + f*x])^(m + 1)*Simp[b*( m + 1)*((b*B - a*C)*(b*c - a*d) - A*b*(a*c - b*d)) + (b*B*(a^2*d + b^2*d*(m + 1) - a*b*c*(m + 2)) + (b*c - a*d)*(A*b^2*(m + 2) + C*(a^2 + b^2*(m + 1)) ))*Sin[e + f*x] - b*C*d*(m + 1)*(a^2 - b^2)*Sin[e + f*x]^2, x], x], x] /; F reeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && LtQ[m, -1]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(c^2*C - B*c*d + A*d^2))*Cos[e + f*x ]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(n + 1)*(c^2 - d^2))), x] + Simp[1/(d*(n + 1)*(c^2 - d^2)) Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x])^(n + 1)*Simp[A*d*(b*d*m + a*c*(n + 1)) + (c*C - B* d)*(b*c*m + a*d*(n + 1)) - (d*(A*(a*d*(n + 2) - b*c*(n + 1)) + B*(b*d*(n + 1) - a*c*(n + 2))) - C*(b*c*d*(n + 1) - a*(c^2 + d^2*(n + 1))))*Sin[e + f*x ] + b*(d*(B*c - A*d)*(m + n + 2) - C*(c^2*(m + 1) + d^2*(n + 1)))*Sin[e + f *x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d , 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 0] && LtQ[n, -1]
Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]
Time = 19.66 (sec) , antiderivative size = 175, normalized size of antiderivative = 0.88
| method | result | size |
| parts | \(-\frac {a^{4} A \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}+\frac {\left (A \,b^{4}+4 B a \,b^{3}\right ) \left (d x +c \right )}{d}+\frac {\left (4 A a \,b^{3}+6 B \,a^{2} b^{2}\right ) \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {\left (6 A \,a^{2} b^{2}+4 B \,a^{3} b \right ) \tan \left (d x +c \right )}{d}+\frac {\left (4 A \,a^{3} b +B \,a^{4}\right ) \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}+\frac {B \,b^{4} \sin \left (d x +c \right )}{d}\) | \(175\) |
| derivativedivides | \(\frac {-a^{4} A \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+B \,a^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 A \,a^{3} b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 B \tan \left (d x +c \right ) a^{3} b +6 A \tan \left (d x +c \right ) a^{2} b^{2}+6 B \,a^{2} b^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+4 A a \,b^{3} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+4 B a \,b^{3} \left (d x +c \right )+A \,b^{4} \left (d x +c \right )+B \sin \left (d x +c \right ) b^{4}}{d}\) | \(209\) |
| default | \(\frac {-a^{4} A \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+B \,a^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 A \,a^{3} b \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 B \tan \left (d x +c \right ) a^{3} b +6 A \tan \left (d x +c \right ) a^{2} b^{2}+6 B \,a^{2} b^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+4 A a \,b^{3} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+4 B a \,b^{3} \left (d x +c \right )+A \,b^{4} \left (d x +c \right )+B \sin \left (d x +c \right ) b^{4}}{d}\) | \(209\) |
| parallelrisch | \(\frac {-36 a \left (A \,a^{2} b +2 A \,b^{3}+\frac {1}{4} a^{3} B +3 B a \,b^{2}\right ) \left (\cos \left (d x +c \right )+\frac {\cos \left (3 d x +3 c \right )}{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+36 a \left (A \,a^{2} b +2 A \,b^{3}+\frac {1}{4} a^{3} B +3 B a \,b^{2}\right ) \left (\cos \left (d x +c \right )+\frac {\cos \left (3 d x +3 c \right )}{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+6 b^{3} d x \left (A b +4 B a \right ) \cos \left (3 d x +3 c \right )+6 \left (4 A \,a^{3} b +B \,a^{4}+B \,b^{4}\right ) \sin \left (2 d x +2 c \right )+4 a^{2} \left (a^{2} A +9 A \,b^{2}+6 B a b \right ) \sin \left (3 d x +3 c \right )+3 B \sin \left (4 d x +4 c \right ) b^{4}+18 b^{3} d x \left (A b +4 B a \right ) \cos \left (d x +c \right )+12 \sin \left (d x +c \right ) a^{2} \left (a^{2} A +3 A \,b^{2}+2 B a b \right )}{6 d \left (3 \cos \left (d x +c \right )+\cos \left (3 d x +3 c \right )\right )}\) | \(293\) |
| risch | \(A \,b^{4} x +4 B a \,b^{3} x -\frac {i B \,b^{4} {\mathrm e}^{i \left (d x +c \right )}}{2 d}+\frac {i {\mathrm e}^{-i \left (d x +c \right )} B \,b^{4}}{2 d}-\frac {i a^{2} \left (12 A a b \,{\mathrm e}^{5 i \left (d x +c \right )}+3 B \,a^{2} {\mathrm e}^{5 i \left (d x +c \right )}-36 A \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-24 B a b \,{\mathrm e}^{4 i \left (d x +c \right )}-12 A \,a^{2} {\mathrm e}^{2 i \left (d x +c \right )}-72 A \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-48 B a b \,{\mathrm e}^{2 i \left (d x +c \right )}-12 A a b \,{\mathrm e}^{i \left (d x +c \right )}-3 B \,a^{2} {\mathrm e}^{i \left (d x +c \right )}-4 a^{2} A -36 A \,b^{2}-24 B a b \right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{3}}-\frac {2 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) A b}{d}-\frac {4 a \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) A \,b^{3}}{d}-\frac {a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B}{2 d}-\frac {6 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B \,b^{2}}{d}+\frac {2 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) A b}{d}+\frac {4 a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) A \,b^{3}}{d}+\frac {a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B}{2 d}+\frac {6 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B \,b^{2}}{d}\) | \(411\) |
| norman | \(\frac {\left (-A \,b^{4}-4 B a \,b^{3}\right ) x +\left (-6 A \,b^{4}-24 B a \,b^{3}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}+\left (-2 A \,b^{4}-8 B a \,b^{3}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+\left (-2 A \,b^{4}-8 B a \,b^{3}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{12}+\left (A \,b^{4}+4 B a \,b^{3}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{16}+\left (2 A \,b^{4}+8 B a \,b^{3}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+\left (2 A \,b^{4}+8 B a \,b^{3}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{14}+\left (6 A \,b^{4}+24 B a \,b^{3}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}-\frac {\left (2 a^{4} A -4 A \,a^{3} b +12 A \,a^{2} b^{2}-B \,a^{4}+8 B \,a^{3} b -2 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{15}}{d}-\frac {\left (2 a^{4} A +4 A \,a^{3} b +12 A \,a^{2} b^{2}+B \,a^{4}+8 B \,a^{3} b +2 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}-\frac {\left (26 a^{4} A -60 A \,a^{3} b +108 A \,a^{2} b^{2}-15 B \,a^{4}+72 B \,a^{3} b -6 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{13}}{3 d}-\frac {\left (26 a^{4} A +60 A \,a^{3} b +108 A \,a^{2} b^{2}+15 B \,a^{4}+72 B \,a^{3} b +6 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 d}-\frac {\left (46 a^{4} A -108 A \,a^{3} b +36 A \,a^{2} b^{2}-27 B \,a^{4}+24 B \,a^{3} b +18 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11}}{3 d}-\frac {\left (46 a^{4} A +108 A \,a^{3} b +36 A \,a^{2} b^{2}+27 B \,a^{4}+24 B \,a^{3} b -18 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{3 d}-\frac {\left (50 a^{4} A -60 A \,a^{3} b -180 A \,a^{2} b^{2}-15 B \,a^{4}-120 B \,a^{3} b +18 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{3 d}-\frac {\left (50 a^{4} A +60 A \,a^{3} b -180 A \,a^{2} b^{2}+15 B \,a^{4}-120 B \,a^{3} b -18 B \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{3 d}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{5} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{3}}-\frac {a \left (4 A \,a^{2} b +8 A \,b^{3}+a^{3} B +12 B a \,b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{2 d}+\frac {a \left (4 A \,a^{2} b +8 A \,b^{3}+a^{3} B +12 B a \,b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{2 d}\) | \(787\) |
Input:
int((a+cos(d*x+c)*b)^4*(A+B*cos(d*x+c))*sec(d*x+c)^4,x,method=_RETURNVERBO SE)
Output:
-a^4*A/d*(-2/3-1/3*sec(d*x+c)^2)*tan(d*x+c)+(A*b^4+4*B*a*b^3)/d*(d*x+c)+(4 *A*a*b^3+6*B*a^2*b^2)/d*ln(sec(d*x+c)+tan(d*x+c))+(6*A*a^2*b^2+4*B*a^3*b)/ d*tan(d*x+c)+(4*A*a^3*b+B*a^4)/d*(1/2*sec(d*x+c)*tan(d*x+c)+1/2*ln(sec(d*x +c)+tan(d*x+c)))+B*b^4/d*sin(d*x+c)
Time = 0.10 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.11 \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx=\frac {12 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d x \cos \left (d x + c\right )^{3} + 3 \, {\left (B a^{4} + 4 \, A a^{3} b + 12 \, B a^{2} b^{2} + 8 \, A a b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, {\left (B a^{4} + 4 \, A a^{3} b + 12 \, B a^{2} b^{2} + 8 \, A a b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (6 \, B b^{4} \cos \left (d x + c\right )^{3} + 2 \, A a^{4} + 4 \, {\left (A a^{4} + 6 \, B a^{3} b + 9 \, A a^{2} b^{2}\right )} \cos \left (d x + c\right )^{2} + 3 \, {\left (B a^{4} + 4 \, A a^{3} b\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{12 \, d \cos \left (d x + c\right )^{3}} \] Input:
integrate((a+b*cos(d*x+c))^4*(A+B*cos(d*x+c))*sec(d*x+c)^4,x, algorithm="f ricas")
Output:
1/12*(12*(4*B*a*b^3 + A*b^4)*d*x*cos(d*x + c)^3 + 3*(B*a^4 + 4*A*a^3*b + 1 2*B*a^2*b^2 + 8*A*a*b^3)*cos(d*x + c)^3*log(sin(d*x + c) + 1) - 3*(B*a^4 + 4*A*a^3*b + 12*B*a^2*b^2 + 8*A*a*b^3)*cos(d*x + c)^3*log(-sin(d*x + c) + 1) + 2*(6*B*b^4*cos(d*x + c)^3 + 2*A*a^4 + 4*(A*a^4 + 6*B*a^3*b + 9*A*a^2* b^2)*cos(d*x + c)^2 + 3*(B*a^4 + 4*A*a^3*b)*cos(d*x + c))*sin(d*x + c))/(d *cos(d*x + c)^3)
Timed out. \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx=\text {Timed out} \] Input:
integrate((a+b*cos(d*x+c))**4*(A+B*cos(d*x+c))*sec(d*x+c)**4,x)
Output:
Timed out
Time = 0.04 (sec) , antiderivative size = 245, normalized size of antiderivative = 1.24 \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx=\frac {4 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} A a^{4} + 48 \, {\left (d x + c\right )} B a b^{3} + 12 \, {\left (d x + c\right )} A b^{4} - 3 \, B a^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 12 \, A a^{3} b {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 36 \, B a^{2} b^{2} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 24 \, A a b^{3} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 12 \, B b^{4} \sin \left (d x + c\right ) + 48 \, B a^{3} b \tan \left (d x + c\right ) + 72 \, A a^{2} b^{2} \tan \left (d x + c\right )}{12 \, d} \] Input:
integrate((a+b*cos(d*x+c))^4*(A+B*cos(d*x+c))*sec(d*x+c)^4,x, algorithm="m axima")
Output:
1/12*(4*(tan(d*x + c)^3 + 3*tan(d*x + c))*A*a^4 + 48*(d*x + c)*B*a*b^3 + 1 2*(d*x + c)*A*b^4 - 3*B*a^4*(2*sin(d*x + c)/(sin(d*x + c)^2 - 1) - log(sin (d*x + c) + 1) + log(sin(d*x + c) - 1)) - 12*A*a^3*b*(2*sin(d*x + c)/(sin( d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) + 36*B*a^ 2*b^2*(log(sin(d*x + c) + 1) - log(sin(d*x + c) - 1)) + 24*A*a*b^3*(log(si n(d*x + c) + 1) - log(sin(d*x + c) - 1)) + 12*B*b^4*sin(d*x + c) + 48*B*a^ 3*b*tan(d*x + c) + 72*A*a^2*b^2*tan(d*x + c))/d
Leaf count of result is larger than twice the leaf count of optimal. 387 vs. \(2 (188) = 376\).
Time = 0.25 (sec) , antiderivative size = 387, normalized size of antiderivative = 1.95 \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx=\frac {\frac {12 \, B b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1} + 6 \, {\left (4 \, B a b^{3} + A b^{4}\right )} {\left (d x + c\right )} + 3 \, {\left (B a^{4} + 4 \, A a^{3} b + 12 \, B a^{2} b^{2} + 8 \, A a b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, {\left (B a^{4} + 4 \, A a^{3} b + 12 \, B a^{2} b^{2} + 8 \, A a b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (6 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 12 \, A a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 24 \, B a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 36 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 4 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 48 \, B a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 72 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 6 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 12 \, A a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24 \, B a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 36 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{3}}}{6 \, d} \] Input:
integrate((a+b*cos(d*x+c))^4*(A+B*cos(d*x+c))*sec(d*x+c)^4,x, algorithm="g iac")
Output:
1/6*(12*B*b^4*tan(1/2*d*x + 1/2*c)/(tan(1/2*d*x + 1/2*c)^2 + 1) + 6*(4*B*a *b^3 + A*b^4)*(d*x + c) + 3*(B*a^4 + 4*A*a^3*b + 12*B*a^2*b^2 + 8*A*a*b^3) *log(abs(tan(1/2*d*x + 1/2*c) + 1)) - 3*(B*a^4 + 4*A*a^3*b + 12*B*a^2*b^2 + 8*A*a*b^3)*log(abs(tan(1/2*d*x + 1/2*c) - 1)) - 2*(6*A*a^4*tan(1/2*d*x + 1/2*c)^5 - 3*B*a^4*tan(1/2*d*x + 1/2*c)^5 - 12*A*a^3*b*tan(1/2*d*x + 1/2* c)^5 + 24*B*a^3*b*tan(1/2*d*x + 1/2*c)^5 + 36*A*a^2*b^2*tan(1/2*d*x + 1/2* c)^5 - 4*A*a^4*tan(1/2*d*x + 1/2*c)^3 - 48*B*a^3*b*tan(1/2*d*x + 1/2*c)^3 - 72*A*a^2*b^2*tan(1/2*d*x + 1/2*c)^3 + 6*A*a^4*tan(1/2*d*x + 1/2*c) + 3*B *a^4*tan(1/2*d*x + 1/2*c) + 12*A*a^3*b*tan(1/2*d*x + 1/2*c) + 24*B*a^3*b*t an(1/2*d*x + 1/2*c) + 36*A*a^2*b^2*tan(1/2*d*x + 1/2*c))/(tan(1/2*d*x + 1/ 2*c)^2 - 1)^3)/d
Time = 44.90 (sec) , antiderivative size = 636, normalized size of antiderivative = 3.21 \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx =\text {Too large to display} \] Input:
int(((A + B*cos(c + d*x))*(a + b*cos(c + d*x))^4)/cos(c + d*x)^4,x)
Output:
((A*a^4*sin(3*c + 3*d*x))/6 + (B*a^4*sin(2*c + 2*d*x))/4 + (B*b^4*sin(2*c + 2*d*x))/4 + (B*b^4*sin(4*c + 4*d*x))/8 + (A*a^4*sin(c + d*x))/2 + B*a^3* b*sin(c + d*x) + (3*A*b^4*cos(c + d*x)*atan(sin(c/2 + (d*x)/2)/cos(c/2 + ( d*x)/2)))/2 - (B*a^4*cos(c + d*x)*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + ( d*x)/2))*3i)/4 + A*a^3*b*sin(2*c + 2*d*x) + (3*A*a^2*b^2*sin(c + d*x))/2 + B*a^3*b*sin(3*c + 3*d*x) + (A*b^4*atan(sin(c/2 + (d*x)/2)/cos(c/2 + (d*x) /2))*cos(3*c + 3*d*x))/2 - (B*a^4*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + ( d*x)/2))*cos(3*c + 3*d*x)*1i)/4 + (3*A*a^2*b^2*sin(3*c + 3*d*x))/2 - A*a*b ^3*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + (d*x)/2))*cos(3*c + 3*d*x)*2i - A*a^3*b*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + (d*x)/2))*cos(3*c + 3*d*x)* 1i + 2*B*a*b^3*atan(sin(c/2 + (d*x)/2)/cos(c/2 + (d*x)/2))*cos(3*c + 3*d*x ) - B*a^2*b^2*cos(c + d*x)*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + (d*x)/2) )*9i - B*a^2*b^2*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + (d*x)/2))*cos(3*c + 3*d*x)*3i - A*a*b^3*cos(c + d*x)*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + (d*x)/2))*6i - A*a^3*b*cos(c + d*x)*atan((sin(c/2 + (d*x)/2)*1i)/cos(c/2 + (d*x)/2))*3i + 6*B*a*b^3*cos(c + d*x)*atan(sin(c/2 + (d*x)/2)/cos(c/2 + ( d*x)/2)))/(d*((3*cos(c + d*x))/4 + cos(3*c + 3*d*x)/4))
Time = 0.18 (sec) , antiderivative size = 402, normalized size of antiderivative = 2.03 \[ \int (a+b \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^4(c+d x) \, dx=\frac {-15 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \sin \left (d x +c \right )^{2} a^{4} b -60 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \sin \left (d x +c \right )^{2} a^{2} b^{3}+15 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) a^{4} b +60 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) a^{2} b^{3}+15 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \sin \left (d x +c \right )^{2} a^{4} b +60 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \sin \left (d x +c \right )^{2} a^{2} b^{3}-15 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) a^{4} b -60 \cos \left (d x +c \right ) \mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) a^{2} b^{3}+6 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{3} b^{5}+30 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} a \,b^{4} d x -15 \cos \left (d x +c \right ) \sin \left (d x +c \right ) a^{4} b -6 \cos \left (d x +c \right ) \sin \left (d x +c \right ) b^{5}-30 \cos \left (d x +c \right ) a \,b^{4} d x +4 \sin \left (d x +c \right )^{3} a^{5}+60 \sin \left (d x +c \right )^{3} a^{3} b^{2}-6 \sin \left (d x +c \right ) a^{5}-60 \sin \left (d x +c \right ) a^{3} b^{2}}{6 \cos \left (d x +c \right ) d \left (\sin \left (d x +c \right )^{2}-1\right )} \] Input:
int((a+b*cos(d*x+c))^4*(A+B*cos(d*x+c))*sec(d*x+c)^4,x)
Output:
( - 15*cos(c + d*x)*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**2*a**4*b - 60* cos(c + d*x)*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**2*a**2*b**3 + 15*cos( c + d*x)*log(tan((c + d*x)/2) - 1)*a**4*b + 60*cos(c + d*x)*log(tan((c + d *x)/2) - 1)*a**2*b**3 + 15*cos(c + d*x)*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**2*a**4*b + 60*cos(c + d*x)*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**2 *a**2*b**3 - 15*cos(c + d*x)*log(tan((c + d*x)/2) + 1)*a**4*b - 60*cos(c + d*x)*log(tan((c + d*x)/2) + 1)*a**2*b**3 + 6*cos(c + d*x)*sin(c + d*x)**3 *b**5 + 30*cos(c + d*x)*sin(c + d*x)**2*a*b**4*d*x - 15*cos(c + d*x)*sin(c + d*x)*a**4*b - 6*cos(c + d*x)*sin(c + d*x)*b**5 - 30*cos(c + d*x)*a*b**4 *d*x + 4*sin(c + d*x)**3*a**5 + 60*sin(c + d*x)**3*a**3*b**2 - 6*sin(c + d *x)*a**5 - 60*sin(c + d*x)*a**3*b**2)/(6*cos(c + d*x)*d*(sin(c + d*x)**2 - 1))