\(\int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx\) [304]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [C] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 33, antiderivative size = 378 \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx=-\frac {2 \left (18 a^3 A b-246 a A b^3-8 a^4 B-33 a^2 b^2 B-147 b^4 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{315 b^3 d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}+\frac {2 \left (a^2-b^2\right ) \left (18 a^2 A b-75 A b^3-8 a^3 B-39 a b^2 B\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )}{315 b^3 d \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (18 a^2 A b-75 A b^3-8 a^3 B-39 a b^2 B\right ) \sqrt {a+b \cos (c+d x)} \sin (c+d x)}{315 b^2 d}-\frac {2 \left (18 a A b-8 a^2 B-49 b^2 B\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{315 b^2 d}+\frac {2 (9 A b-4 a B) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{63 b^2 d}+\frac {2 B \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{9 b d} \] Output:

-2/315*(18*A*a^3*b-246*A*a*b^3-8*B*a^4-33*B*a^2*b^2-147*B*b^4)*(a+b*cos(d* 
x+c))^(1/2)*EllipticE(sin(1/2*d*x+1/2*c),2^(1/2)*(b/(a+b))^(1/2))/b^3/d/(( 
a+b*cos(d*x+c))/(a+b))^(1/2)+2/315*(a^2-b^2)*(18*A*a^2*b-75*A*b^3-8*B*a^3- 
39*B*a*b^2)*((a+b*cos(d*x+c))/(a+b))^(1/2)*InverseJacobiAM(1/2*d*x+1/2*c,2 
^(1/2)*(b/(a+b))^(1/2))/b^3/d/(a+b*cos(d*x+c))^(1/2)-2/315*(18*A*a^2*b-75* 
A*b^3-8*B*a^3-39*B*a*b^2)*(a+b*cos(d*x+c))^(1/2)*sin(d*x+c)/b^2/d-2/315*(1 
8*A*a*b-8*B*a^2-49*B*b^2)*(a+b*cos(d*x+c))^(3/2)*sin(d*x+c)/b^2/d+2/63*(9* 
A*b-4*B*a)*(a+b*cos(d*x+c))^(5/2)*sin(d*x+c)/b^2/d+2/9*B*cos(d*x+c)*(a+b*c 
os(d*x+c))^(5/2)*sin(d*x+c)/b/d
 

Mathematica [A] (verified)

Time = 3.12 (sec) , antiderivative size = 291, normalized size of antiderivative = 0.77 \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx=\frac {8 \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \left (b^2 \left (153 a^2 A b+75 A b^3+2 a^3 B+186 a b^2 B\right ) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )+\left (-18 a^3 A b+246 a A b^3+8 a^4 B+33 a^2 b^2 B+147 b^4 B\right ) \left ((a+b) E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )-a \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )\right )\right )+b (a+b \cos (c+d x)) \left (\left (72 a^2 A b+690 A b^3-32 a^3 B+804 a b^2 B\right ) \sin (c+d x)+b \left (2 \left (144 a A b+6 a^2 B+133 b^2 B\right ) \sin (2 (c+d x))+5 b (2 (9 A b+10 a B) \sin (3 (c+d x))+7 b B \sin (4 (c+d x)))\right )\right )}{1260 b^3 d \sqrt {a+b \cos (c+d x)}} \] Input:

Integrate[Cos[c + d*x]^2*(a + b*Cos[c + d*x])^(3/2)*(A + B*Cos[c + d*x]),x 
]
 

Output:

(8*Sqrt[(a + b*Cos[c + d*x])/(a + b)]*(b^2*(153*a^2*A*b + 75*A*b^3 + 2*a^3 
*B + 186*a*b^2*B)*EllipticF[(c + d*x)/2, (2*b)/(a + b)] + (-18*a^3*A*b + 2 
46*a*A*b^3 + 8*a^4*B + 33*a^2*b^2*B + 147*b^4*B)*((a + b)*EllipticE[(c + d 
*x)/2, (2*b)/(a + b)] - a*EllipticF[(c + d*x)/2, (2*b)/(a + b)])) + b*(a + 
 b*Cos[c + d*x])*((72*a^2*A*b + 690*A*b^3 - 32*a^3*B + 804*a*b^2*B)*Sin[c 
+ d*x] + b*(2*(144*a*A*b + 6*a^2*B + 133*b^2*B)*Sin[2*(c + d*x)] + 5*b*(2* 
(9*A*b + 10*a*B)*Sin[3*(c + d*x)] + 7*b*B*Sin[4*(c + d*x)]))))/(1260*b^3*d 
*Sqrt[a + b*Cos[c + d*x]])
 

Rubi [A] (verified)

Time = 2.07 (sec) , antiderivative size = 394, normalized size of antiderivative = 1.04, number of steps used = 21, number of rules used = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.636, Rules used = {3042, 3469, 27, 3042, 3502, 27, 3042, 3232, 27, 3042, 3232, 27, 3042, 3231, 3042, 3134, 3042, 3132, 3142, 3042, 3140}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \sin \left (c+d x+\frac {\pi }{2}\right )^2 \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2} \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx\)

\(\Big \downarrow \) 3469

\(\displaystyle \frac {2 \int \frac {1}{2} (a+b \cos (c+d x))^{3/2} \left ((9 A b-4 a B) \cos ^2(c+d x)+7 b B \cos (c+d x)+2 a B\right )dx}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int (a+b \cos (c+d x))^{3/2} \left ((9 A b-4 a B) \cos ^2(c+d x)+7 b B \cos (c+d x)+2 a B\right )dx}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2} \left ((9 A b-4 a B) \sin \left (c+d x+\frac {\pi }{2}\right )^2+7 b B \sin \left (c+d x+\frac {\pi }{2}\right )+2 a B\right )dx}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3502

\(\displaystyle \frac {\frac {2 \int \frac {1}{2} (a+b \cos (c+d x))^{3/2} \left (3 b (15 A b-2 a B)-\left (-8 B a^2+18 A b a-49 b^2 B\right ) \cos (c+d x)\right )dx}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\int (a+b \cos (c+d x))^{3/2} \left (3 b (15 A b-2 a B)-\left (-8 B a^2+18 A b a-49 b^2 B\right ) \cos (c+d x)\right )dx}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2} \left (3 b (15 A b-2 a B)+\left (8 B a^2-18 A b a+49 b^2 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3232

\(\displaystyle \frac {\frac {\frac {2}{5} \int \frac {3}{2} \sqrt {a+b \cos (c+d x)} \left (b \left (-2 B a^2+57 A b a+49 b^2 B\right )-\left (-8 B a^3+18 A b a^2-39 b^2 B a-75 A b^3\right ) \cos (c+d x)\right )dx-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {3}{5} \int \sqrt {a+b \cos (c+d x)} \left (b \left (-2 B a^2+57 A b a+49 b^2 B\right )-\left (-8 B a^3+18 A b a^2-39 b^2 B a-75 A b^3\right ) \cos (c+d x)\right )dx-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {3}{5} \int \sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )} \left (b \left (-2 B a^2+57 A b a+49 b^2 B\right )+\left (8 B a^3-18 A b a^2+39 b^2 B a+75 A b^3\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3232

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {2}{3} \int \frac {b \left (2 B a^3+153 A b a^2+186 b^2 B a+75 A b^3\right )-\left (-8 B a^4+18 A b a^3-33 b^2 B a^2-246 A b^3 a-147 b^4 B\right ) \cos (c+d x)}{2 \sqrt {a+b \cos (c+d x)}}dx-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \int \frac {b \left (2 B a^3+153 A b a^2+186 b^2 B a+75 A b^3\right )-\left (-8 B a^4+18 A b a^3-33 b^2 B a^2-246 A b^3 a-147 b^4 B\right ) \cos (c+d x)}{\sqrt {a+b \cos (c+d x)}}dx-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \int \frac {b \left (2 B a^3+153 A b a^2+186 b^2 B a+75 A b^3\right )+\left (8 B a^4-18 A b a^3+33 b^2 B a^2+246 A b^3 a+147 b^4 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3231

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \int \frac {1}{\sqrt {a+b \cos (c+d x)}}dx}{b}-\frac {\left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \int \sqrt {a+b \cos (c+d x)}dx}{b}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {\left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \int \sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}dx}{b}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3134

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {\left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \sqrt {a+b \cos (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}}dx}{b \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {\left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \sqrt {a+b \cos (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \sin \left (c+d x+\frac {\pi }{2}\right )}{a+b}}dx}{b \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3132

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {2 \left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3142

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}}}dx}{b \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin \left (c+d x+\frac {\pi }{2}\right )}{a+b}}}dx}{b \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

\(\Big \downarrow \) 3140

\(\displaystyle \frac {\frac {\frac {3}{5} \left (\frac {1}{3} \left (\frac {2 \left (a^2-b^2\right ) \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )}{b d \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (-8 a^4 B+18 a^3 A b-33 a^2 b^2 B-246 a A b^3-147 b^4 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-8 a^3 B+18 a^2 A b-39 a b^2 B-75 A b^3\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-8 a^2 B+18 a A b-49 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}}{7 b}+\frac {2 (9 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d}}{9 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{9 b d}\)

Input:

Int[Cos[c + d*x]^2*(a + b*Cos[c + d*x])^(3/2)*(A + B*Cos[c + d*x]),x]
 

Output:

(2*B*Cos[c + d*x]*(a + b*Cos[c + d*x])^(5/2)*Sin[c + d*x])/(9*b*d) + ((2*( 
9*A*b - 4*a*B)*(a + b*Cos[c + d*x])^(5/2)*Sin[c + d*x])/(7*b*d) + ((-2*(18 
*a*A*b - 8*a^2*B - 49*b^2*B)*(a + b*Cos[c + d*x])^(3/2)*Sin[c + d*x])/(5*d 
) + (3*(((-2*(18*a^3*A*b - 246*a*A*b^3 - 8*a^4*B - 33*a^2*b^2*B - 147*b^4* 
B)*Sqrt[a + b*Cos[c + d*x]]*EllipticE[(c + d*x)/2, (2*b)/(a + b)])/(b*d*Sq 
rt[(a + b*Cos[c + d*x])/(a + b)]) + (2*(a^2 - b^2)*(18*a^2*A*b - 75*A*b^3 
- 8*a^3*B - 39*a*b^2*B)*Sqrt[(a + b*Cos[c + d*x])/(a + b)]*EllipticF[(c + 
d*x)/2, (2*b)/(a + b)])/(b*d*Sqrt[a + b*Cos[c + d*x]]))/3 - (2*(18*a^2*A*b 
 - 75*A*b^3 - 8*a^3*B - 39*a*b^2*B)*Sqrt[a + b*Cos[c + d*x]]*Sin[c + d*x]) 
/(3*d)))/5)/(7*b))/(9*b)
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3132
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[2*(Sqrt[a 
 + b]/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[{a, 
b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3134
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[a + 
b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c + d*x])/(a + b)]   Int[Sqrt[a/(a + b) + ( 
b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2 
, 0] &&  !GtQ[a + b, 0]
 

rule 3140
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/(d*S 
qrt[a + b]))*EllipticF[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[ 
{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3142
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[(a 
 + b*Sin[c + d*x])/(a + b)]/Sqrt[a + b*Sin[c + d*x]]   Int[1/Sqrt[a/(a + b) 
 + (b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - 
 b^2, 0] &&  !GtQ[a + b, 0]
 

rule 3231
Int[((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])/Sqrt[(a_) + (b_.)*sin[(e_.) + ( 
f_.)*(x_)]], x_Symbol] :> Simp[(b*c - a*d)/b   Int[1/Sqrt[a + b*Sin[e + f*x 
]], x], x] + Simp[d/b   Int[Sqrt[a + b*Sin[e + f*x]], x], x] /; FreeQ[{a, b 
, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]
 

rule 3232
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
(f_.)*(x_)]), x_Symbol] :> Simp[(-d)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/( 
f*(m + 1))), x] + Simp[1/(m + 1)   Int[(a + b*Sin[e + f*x])^(m - 1)*Simp[b* 
d*m + a*c*(m + 1) + (a*d*m + b*c*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ 
[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && GtQ[m, 
 0] && IntegerQ[2*m]
 

rule 3469
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + 
 (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Si 
mp[(-b)*B*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*((c + d*Sin[e + f*x])^( 
n + 1)/(d*f*(m + n + 1))), x] + Simp[1/(d*(m + n + 1))   Int[(a + b*Sin[e + 
 f*x])^(m - 2)*(c + d*Sin[e + f*x])^n*Simp[a^2*A*d*(m + n + 1) + b*B*(b*c*( 
m - 1) + a*d*(n + 1)) + (a*d*(2*A*b + a*B)*(m + n + 1) - b*B*(a*c - b*d*(m 
+ n)))*Sin[e + f*x] + b*(A*b*d*(m + n + 1) - B*(b*c*m - a*d*(2*m + n)))*Sin 
[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c 
 - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 1] &&  !(IGt 
Q[n, 1] && ( !IntegerQ[m] || (EqQ[a, 0] && NeQ[c, 0])))
 

rule 3502
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) 
+ (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co 
s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m 
+ 2))   Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m 
 + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] 
 &&  !LtQ[m, -1]
 
Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(1634\) vs. \(2(359)=718\).

Time = 25.27 (sec) , antiderivative size = 1635, normalized size of antiderivative = 4.33

method result size
default \(\text {Expression too large to display}\) \(1635\)
parts \(\text {Expression too large to display}\) \(1824\)

Input:

int(cos(d*x+c)^2*(a+cos(d*x+c)*b)^(3/2)*(A+B*cos(d*x+c)),x,method=_RETURNV 
ERBOSE)
 

Output:

-2/315*((2*b*cos(1/2*d*x+1/2*c)^2+a-b)*sin(1/2*d*x+1/2*c)^2)^(1/2)*(-1120* 
B*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1/2*c)^10*b^5+(720*A*b^5+1360*B*a*b^4+224 
0*B*b^5)*sin(1/2*d*x+1/2*c)^8*cos(1/2*d*x+1/2*c)+(-936*A*a*b^4-1080*A*b^5- 
424*B*a^2*b^3-2040*B*a*b^4-2072*B*b^5)*sin(1/2*d*x+1/2*c)^6*cos(1/2*d*x+1/ 
2*c)+(324*A*a^2*b^3+936*A*a*b^4+840*A*b^5-4*B*a^3*b^2+424*B*a^2*b^3+1568*B 
*a*b^4+952*B*b^5)*sin(1/2*d*x+1/2*c)^4*cos(1/2*d*x+1/2*c)+(-18*A*a^3*b^2-1 
62*A*a^2*b^3-384*A*a*b^4-240*A*b^5+8*B*a^4*b+2*B*a^3*b^2-282*B*a^2*b^3-444 
*B*a*b^4-168*B*b^5)*sin(1/2*d*x+1/2*c)^2*cos(1/2*d*x+1/2*c)+18*A*(sin(1/2* 
d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*El 
lipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^4*b-93*A*(sin(1/2*d*x+1/2 
*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticF 
(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^2*b^3+75*A*b^5*(sin(1/2*d*x+1/2* 
c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticF( 
cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))-18*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*( 
-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1 
/2*c),(-2*b/(a-b))^(1/2))*a^4*b+18*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a 
-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),( 
-2*b/(a-b))^(1/2))*a^3*b^2+246*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)* 
sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b 
/(a-b))^(1/2))*a^2*b^3-246*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*s...
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.14 (sec) , antiderivative size = 639, normalized size of antiderivative = 1.69 \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx =\text {Too large to display} \] Input:

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(3/2)*(A+B*cos(d*x+c)),x, algorith 
m="fricas")
 

Output:

-2/945*(sqrt(1/2)*(-16*I*B*a^5 + 36*I*A*a^4*b - 60*I*B*a^3*b^2 - 33*I*A*a^ 
2*b^3 + 264*I*B*a*b^4 + 225*I*A*b^5)*sqrt(b)*weierstrassPInverse(4/3*(4*a^ 
2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/3*(3*b*cos(d*x + c) + 3*I*b 
*sin(d*x + c) + 2*a)/b) + sqrt(1/2)*(16*I*B*a^5 - 36*I*A*a^4*b + 60*I*B*a^ 
3*b^2 + 33*I*A*a^2*b^3 - 264*I*B*a*b^4 - 225*I*A*b^5)*sqrt(b)*weierstrassP 
Inverse(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/3*(3*b*cos 
(d*x + c) - 3*I*b*sin(d*x + c) + 2*a)/b) + 3*sqrt(1/2)*(-8*I*B*a^4*b + 18* 
I*A*a^3*b^2 - 33*I*B*a^2*b^3 - 246*I*A*a*b^4 - 147*I*B*b^5)*sqrt(b)*weiers 
trassZeta(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, weierstras 
sPInverse(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/3*(3*b*c 
os(d*x + c) + 3*I*b*sin(d*x + c) + 2*a)/b)) + 3*sqrt(1/2)*(8*I*B*a^4*b - 1 
8*I*A*a^3*b^2 + 33*I*B*a^2*b^3 + 246*I*A*a*b^4 + 147*I*B*b^5)*sqrt(b)*weie 
rstrassZeta(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, weierstr 
assPInverse(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/3*(3*b 
*cos(d*x + c) - 3*I*b*sin(d*x + c) + 2*a)/b)) - 3*(35*B*b^5*cos(d*x + c)^3 
 - 4*B*a^3*b^2 + 9*A*a^2*b^3 + 88*B*a*b^4 + 75*A*b^5 + 5*(10*B*a*b^4 + 9*A 
*b^5)*cos(d*x + c)^2 + (3*B*a^2*b^3 + 72*A*a*b^4 + 49*B*b^5)*cos(d*x + c)) 
*sqrt(b*cos(d*x + c) + a)*sin(d*x + c))/(b^4*d)
 

Sympy [F(-1)]

Timed out. \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx=\text {Timed out} \] Input:

integrate(cos(d*x+c)**2*(a+b*cos(d*x+c))**(3/2)*(A+B*cos(d*x+c)),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx=\int { {\left (B \cos \left (d x + c\right ) + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \cos \left (d x + c\right )^{2} \,d x } \] Input:

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(3/2)*(A+B*cos(d*x+c)),x, algorith 
m="maxima")
 

Output:

integrate((B*cos(d*x + c) + A)*(b*cos(d*x + c) + a)^(3/2)*cos(d*x + c)^2, 
x)
 

Giac [F]

\[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx=\int { {\left (B \cos \left (d x + c\right ) + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \cos \left (d x + c\right )^{2} \,d x } \] Input:

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(3/2)*(A+B*cos(d*x+c)),x, algorith 
m="giac")
 

Output:

integrate((B*cos(d*x + c) + A)*(b*cos(d*x + c) + a)^(3/2)*cos(d*x + c)^2, 
x)
                                                                                    
                                                                                    
 

Mupad [F(-1)]

Timed out. \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx=\int {\cos \left (c+d\,x\right )}^2\,\left (A+B\,\cos \left (c+d\,x\right )\right )\,{\left (a+b\,\cos \left (c+d\,x\right )\right )}^{3/2} \,d x \] Input:

int(cos(c + d*x)^2*(A + B*cos(c + d*x))*(a + b*cos(c + d*x))^(3/2),x)
 

Output:

int(cos(c + d*x)^2*(A + B*cos(c + d*x))*(a + b*cos(c + d*x))^(3/2), x)
 

Reduce [F]

\[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx=\left (\int \sqrt {\cos \left (d x +c \right ) b +a}\, \cos \left (d x +c \right )^{4}d x \right ) b^{2}+2 \left (\int \sqrt {\cos \left (d x +c \right ) b +a}\, \cos \left (d x +c \right )^{3}d x \right ) a b +\left (\int \sqrt {\cos \left (d x +c \right ) b +a}\, \cos \left (d x +c \right )^{2}d x \right ) a^{2} \] Input:

int(cos(d*x+c)^2*(a+b*cos(d*x+c))^(3/2)*(A+B*cos(d*x+c)),x)
 

Output:

int(sqrt(cos(c + d*x)*b + a)*cos(c + d*x)**4,x)*b**2 + 2*int(sqrt(cos(c + 
d*x)*b + a)*cos(c + d*x)**3,x)*a*b + int(sqrt(cos(c + d*x)*b + a)*cos(c + 
d*x)**2,x)*a**2