\(\int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx\) [311]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [C] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 33, antiderivative size = 462 \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx=-\frac {2 \left (110 a^4 A b-3069 a^2 A b^3-1617 A b^5-40 a^5 B-255 a^3 b^2 B-3705 a b^4 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{3465 b^3 d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}+\frac {2 \left (a^2-b^2\right ) \left (110 a^3 A b-1254 a A b^3-40 a^4 B-285 a^2 b^2 B-675 b^4 B\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )}{3465 b^3 d \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (110 a^3 A b-1254 a A b^3-40 a^4 B-285 a^2 b^2 B-675 b^4 B\right ) \sqrt {a+b \cos (c+d x)} \sin (c+d x)}{3465 b^2 d}-\frac {2 \left (110 a^2 A b-539 A b^3-40 a^3 B-335 a b^2 B\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{3465 b^2 d}-\frac {2 \left (22 a A b-8 a^2 B-81 b^2 B\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{693 b^2 d}+\frac {2 (11 A b-4 a B) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{99 b^2 d}+\frac {2 B \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{11 b d} \] Output:

-2/3465*(110*A*a^4*b-3069*A*a^2*b^3-1617*A*b^5-40*B*a^5-255*B*a^3*b^2-3705 
*B*a*b^4)*(a+b*cos(d*x+c))^(1/2)*EllipticE(sin(1/2*d*x+1/2*c),2^(1/2)*(b/( 
a+b))^(1/2))/b^3/d/((a+b*cos(d*x+c))/(a+b))^(1/2)+2/3465*(a^2-b^2)*(110*A* 
a^3*b-1254*A*a*b^3-40*B*a^4-285*B*a^2*b^2-675*B*b^4)*((a+b*cos(d*x+c))/(a+ 
b))^(1/2)*InverseJacobiAM(1/2*d*x+1/2*c,2^(1/2)*(b/(a+b))^(1/2))/b^3/d/(a+ 
b*cos(d*x+c))^(1/2)-2/3465*(110*A*a^3*b-1254*A*a*b^3-40*B*a^4-285*B*a^2*b^ 
2-675*B*b^4)*(a+b*cos(d*x+c))^(1/2)*sin(d*x+c)/b^2/d-2/3465*(110*A*a^2*b-5 
39*A*b^3-40*B*a^3-335*B*a*b^2)*(a+b*cos(d*x+c))^(3/2)*sin(d*x+c)/b^2/d-2/6 
93*(22*A*a*b-8*B*a^2-81*B*b^2)*(a+b*cos(d*x+c))^(5/2)*sin(d*x+c)/b^2/d+2/9 
9*(11*A*b-4*B*a)*(a+b*cos(d*x+c))^(7/2)*sin(d*x+c)/b^2/d+2/11*B*cos(d*x+c) 
*(a+b*cos(d*x+c))^(7/2)*sin(d*x+c)/b/d
 

Mathematica [A] (verified)

Time = 3.81 (sec) , antiderivative size = 357, normalized size of antiderivative = 0.77 \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx=\frac {16 \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \left (b^2 \left (1705 a^3 A b+2871 a A b^3+10 a^4 B+3315 a^2 b^2 B+675 b^4 B\right ) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )+\left (-110 a^4 A b+3069 a^2 A b^3+1617 A b^5+40 a^5 B+255 a^3 b^2 B+3705 a b^4 B\right ) \left ((a+b) E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )-a \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )\right )\right )+b (a+b \cos (c+d x)) \left (\left (880 a^3 A b+32868 a A b^3-320 a^4 B+18660 a^2 b^2 B+13050 b^4 B\right ) \sin (c+d x)+b \left (4 \left (1650 a^2 A b+1463 A b^3+30 a^3 B+3095 a b^2 B\right ) \sin (2 (c+d x))+5 b \left (\left (836 a A b+452 a^2 B+513 b^2 B\right ) \sin (3 (c+d x))+7 b ((22 A b+46 a B) \sin (4 (c+d x))+9 b B \sin (5 (c+d x)))\right )\right )\right )}{27720 b^3 d \sqrt {a+b \cos (c+d x)}} \] Input:

Integrate[Cos[c + d*x]^2*(a + b*Cos[c + d*x])^(5/2)*(A + B*Cos[c + d*x]),x 
]
 

Output:

(16*Sqrt[(a + b*Cos[c + d*x])/(a + b)]*(b^2*(1705*a^3*A*b + 2871*a*A*b^3 + 
 10*a^4*B + 3315*a^2*b^2*B + 675*b^4*B)*EllipticF[(c + d*x)/2, (2*b)/(a + 
b)] + (-110*a^4*A*b + 3069*a^2*A*b^3 + 1617*A*b^5 + 40*a^5*B + 255*a^3*b^2 
*B + 3705*a*b^4*B)*((a + b)*EllipticE[(c + d*x)/2, (2*b)/(a + b)] - a*Elli 
pticF[(c + d*x)/2, (2*b)/(a + b)])) + b*(a + b*Cos[c + d*x])*((880*a^3*A*b 
 + 32868*a*A*b^3 - 320*a^4*B + 18660*a^2*b^2*B + 13050*b^4*B)*Sin[c + d*x] 
 + b*(4*(1650*a^2*A*b + 1463*A*b^3 + 30*a^3*B + 3095*a*b^2*B)*Sin[2*(c + d 
*x)] + 5*b*((836*a*A*b + 452*a^2*B + 513*b^2*B)*Sin[3*(c + d*x)] + 7*b*((2 
2*A*b + 46*a*B)*Sin[4*(c + d*x)] + 9*b*B*Sin[5*(c + d*x)])))))/(27720*b^3* 
d*Sqrt[a + b*Cos[c + d*x]])
 

Rubi [A] (verified)

Time = 2.57 (sec) , antiderivative size = 480, normalized size of antiderivative = 1.04, number of steps used = 24, number of rules used = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.727, Rules used = {3042, 3469, 27, 3042, 3502, 27, 3042, 3232, 27, 3042, 3232, 27, 3042, 3232, 27, 3042, 3231, 3042, 3134, 3042, 3132, 3142, 3042, 3140}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \sin \left (c+d x+\frac {\pi }{2}\right )^2 \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2} \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx\)

\(\Big \downarrow \) 3469

\(\displaystyle \frac {2 \int \frac {1}{2} (a+b \cos (c+d x))^{5/2} \left ((11 A b-4 a B) \cos ^2(c+d x)+9 b B \cos (c+d x)+2 a B\right )dx}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int (a+b \cos (c+d x))^{5/2} \left ((11 A b-4 a B) \cos ^2(c+d x)+9 b B \cos (c+d x)+2 a B\right )dx}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2} \left ((11 A b-4 a B) \sin \left (c+d x+\frac {\pi }{2}\right )^2+9 b B \sin \left (c+d x+\frac {\pi }{2}\right )+2 a B\right )dx}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3502

\(\displaystyle \frac {\frac {2 \int \frac {1}{2} (a+b \cos (c+d x))^{5/2} \left (b (77 A b-10 a B)-\left (-8 B a^2+22 A b a-81 b^2 B\right ) \cos (c+d x)\right )dx}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\int (a+b \cos (c+d x))^{5/2} \left (b (77 A b-10 a B)-\left (-8 B a^2+22 A b a-81 b^2 B\right ) \cos (c+d x)\right )dx}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2} \left (b (77 A b-10 a B)+\left (8 B a^2-22 A b a+81 b^2 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3232

\(\displaystyle \frac {\frac {\frac {2}{7} \int \frac {1}{2} (a+b \cos (c+d x))^{3/2} \left (3 b \left (-10 B a^2+143 A b a+135 b^2 B\right )-\left (-40 B a^3+110 A b a^2-335 b^2 B a-539 A b^3\right ) \cos (c+d x)\right )dx-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {1}{7} \int (a+b \cos (c+d x))^{3/2} \left (3 b \left (-10 B a^2+143 A b a+135 b^2 B\right )-\left (-40 B a^3+110 A b a^2-335 b^2 B a-539 A b^3\right ) \cos (c+d x)\right )dx-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {1}{7} \int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2} \left (3 b \left (-10 B a^2+143 A b a+135 b^2 B\right )+\left (40 B a^3-110 A b a^2+335 b^2 B a+539 A b^3\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3232

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {2}{5} \int \frac {3}{2} \sqrt {a+b \cos (c+d x)} \left (b \left (-10 B a^3+605 A b a^2+1010 b^2 B a+539 A b^3\right )-\left (-40 B a^4+110 A b a^3-285 b^2 B a^2-1254 A b^3 a-675 b^4 B\right ) \cos (c+d x)\right )dx-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \int \sqrt {a+b \cos (c+d x)} \left (b \left (-10 B a^3+605 A b a^2+1010 b^2 B a+539 A b^3\right )-\left (-40 B a^4+110 A b a^3-285 b^2 B a^2-1254 A b^3 a-675 b^4 B\right ) \cos (c+d x)\right )dx-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \int \sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )} \left (b \left (-10 B a^3+605 A b a^2+1010 b^2 B a+539 A b^3\right )+\left (40 B a^4-110 A b a^3+285 b^2 B a^2+1254 A b^3 a+675 b^4 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3232

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {2}{3} \int \frac {b \left (10 B a^4+1705 A b a^3+3315 b^2 B a^2+2871 A b^3 a+675 b^4 B\right )-\left (-40 B a^5+110 A b a^4-255 b^2 B a^3-3069 A b^3 a^2-3705 b^4 B a-1617 A b^5\right ) \cos (c+d x)}{2 \sqrt {a+b \cos (c+d x)}}dx-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \int \frac {b \left (10 B a^4+1705 A b a^3+3315 b^2 B a^2+2871 A b^3 a+675 b^4 B\right )-\left (-40 B a^5+110 A b a^4-255 b^2 B a^3-3069 A b^3 a^2-3705 b^4 B a-1617 A b^5\right ) \cos (c+d x)}{\sqrt {a+b \cos (c+d x)}}dx-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \int \frac {b \left (10 B a^4+1705 A b a^3+3315 b^2 B a^2+2871 A b^3 a+675 b^4 B\right )+\left (40 B a^5-110 A b a^4+255 b^2 B a^3+3069 A b^3 a^2+3705 b^4 B a+1617 A b^5\right ) \sin \left (c+d x+\frac {\pi }{2}\right )}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3231

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \int \frac {1}{\sqrt {a+b \cos (c+d x)}}dx}{b}-\frac {\left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \int \sqrt {a+b \cos (c+d x)}dx}{b}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {\left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \int \sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}dx}{b}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3134

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {\left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \sqrt {a+b \cos (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}}dx}{b \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {\left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \sqrt {a+b \cos (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \sin \left (c+d x+\frac {\pi }{2}\right )}{a+b}}dx}{b \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3132

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}-\frac {2 \left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3142

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}}}dx}{b \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {\left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin \left (c+d x+\frac {\pi }{2}\right )}{a+b}}}dx}{b \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

\(\Big \downarrow \) 3140

\(\displaystyle \frac {\frac {\frac {1}{7} \left (\frac {3}{5} \left (\frac {1}{3} \left (\frac {2 \left (a^2-b^2\right ) \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )}{b d \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (-40 a^5 B+110 a^4 A b-255 a^3 b^2 B-3069 a^2 A b^3-3705 a b^4 B-1617 A b^5\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{b d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}\right )-\frac {2 \left (-40 a^4 B+110 a^3 A b-285 a^2 b^2 B-1254 a A b^3-675 b^4 B\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{3 d}\right )-\frac {2 \left (-40 a^3 B+110 a^2 A b-335 a b^2 B-539 A b^3\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{5 d}\right )-\frac {2 \left (-8 a^2 B+22 a A b-81 b^2 B\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 d}}{9 b}+\frac {2 (11 A b-4 a B) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{9 b d}}{11 b}+\frac {2 B \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{11 b d}\)

Input:

Int[Cos[c + d*x]^2*(a + b*Cos[c + d*x])^(5/2)*(A + B*Cos[c + d*x]),x]
 

Output:

(2*B*Cos[c + d*x]*(a + b*Cos[c + d*x])^(7/2)*Sin[c + d*x])/(11*b*d) + ((2* 
(11*A*b - 4*a*B)*(a + b*Cos[c + d*x])^(7/2)*Sin[c + d*x])/(9*b*d) + ((-2*( 
22*a*A*b - 8*a^2*B - 81*b^2*B)*(a + b*Cos[c + d*x])^(5/2)*Sin[c + d*x])/(7 
*d) + ((-2*(110*a^2*A*b - 539*A*b^3 - 40*a^3*B - 335*a*b^2*B)*(a + b*Cos[c 
 + d*x])^(3/2)*Sin[c + d*x])/(5*d) + (3*(((-2*(110*a^4*A*b - 3069*a^2*A*b^ 
3 - 1617*A*b^5 - 40*a^5*B - 255*a^3*b^2*B - 3705*a*b^4*B)*Sqrt[a + b*Cos[c 
 + d*x]]*EllipticE[(c + d*x)/2, (2*b)/(a + b)])/(b*d*Sqrt[(a + b*Cos[c + d 
*x])/(a + b)]) + (2*(a^2 - b^2)*(110*a^3*A*b - 1254*a*A*b^3 - 40*a^4*B - 2 
85*a^2*b^2*B - 675*b^4*B)*Sqrt[(a + b*Cos[c + d*x])/(a + b)]*EllipticF[(c 
+ d*x)/2, (2*b)/(a + b)])/(b*d*Sqrt[a + b*Cos[c + d*x]]))/3 - (2*(110*a^3* 
A*b - 1254*a*A*b^3 - 40*a^4*B - 285*a^2*b^2*B - 675*b^4*B)*Sqrt[a + b*Cos[ 
c + d*x]]*Sin[c + d*x])/(3*d)))/5)/7)/(9*b))/(11*b)
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3132
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[2*(Sqrt[a 
 + b]/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[{a, 
b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3134
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[a + 
b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c + d*x])/(a + b)]   Int[Sqrt[a/(a + b) + ( 
b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2 
, 0] &&  !GtQ[a + b, 0]
 

rule 3140
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/(d*S 
qrt[a + b]))*EllipticF[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[ 
{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3142
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[(a 
 + b*Sin[c + d*x])/(a + b)]/Sqrt[a + b*Sin[c + d*x]]   Int[1/Sqrt[a/(a + b) 
 + (b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - 
 b^2, 0] &&  !GtQ[a + b, 0]
 

rule 3231
Int[((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])/Sqrt[(a_) + (b_.)*sin[(e_.) + ( 
f_.)*(x_)]], x_Symbol] :> Simp[(b*c - a*d)/b   Int[1/Sqrt[a + b*Sin[e + f*x 
]], x], x] + Simp[d/b   Int[Sqrt[a + b*Sin[e + f*x]], x], x] /; FreeQ[{a, b 
, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]
 

rule 3232
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
(f_.)*(x_)]), x_Symbol] :> Simp[(-d)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/( 
f*(m + 1))), x] + Simp[1/(m + 1)   Int[(a + b*Sin[e + f*x])^(m - 1)*Simp[b* 
d*m + a*c*(m + 1) + (a*d*m + b*c*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ 
[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && GtQ[m, 
 0] && IntegerQ[2*m]
 

rule 3469
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + 
 (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Si 
mp[(-b)*B*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*((c + d*Sin[e + f*x])^( 
n + 1)/(d*f*(m + n + 1))), x] + Simp[1/(d*(m + n + 1))   Int[(a + b*Sin[e + 
 f*x])^(m - 2)*(c + d*Sin[e + f*x])^n*Simp[a^2*A*d*(m + n + 1) + b*B*(b*c*( 
m - 1) + a*d*(n + 1)) + (a*d*(2*A*b + a*B)*(m + n + 1) - b*B*(a*c - b*d*(m 
+ n)))*Sin[e + f*x] + b*(A*b*d*(m + n + 1) - B*(b*c*m - a*d*(2*m + n)))*Sin 
[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c 
 - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 1] &&  !(IGt 
Q[n, 1] && ( !IntegerQ[m] || (EqQ[a, 0] && NeQ[c, 0])))
 

rule 3502
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) 
+ (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co 
s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m 
+ 2))   Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m 
 + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] 
 &&  !LtQ[m, -1]
 
Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(1982\) vs. \(2(439)=878\).

Time = 39.42 (sec) , antiderivative size = 1983, normalized size of antiderivative = 4.29

method result size
default \(\text {Expression too large to display}\) \(1983\)
parts \(\text {Expression too large to display}\) \(2137\)

Input:

int(cos(d*x+c)^2*(a+cos(d*x+c)*b)^(5/2)*(A+B*cos(d*x+c)),x,method=_RETURNV 
ERBOSE)
 

Output:

-2/3465*((2*b*cos(1/2*d*x+1/2*c)^2+a-b)*sin(1/2*d*x+1/2*c)^2)^(1/2)*(-40*B 
*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b) 
)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^6+675*b^6*B*(si 
n(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1 
/2)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))+40*B*(sin(1/2*d*x+1/2 
*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE 
(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^6-1617*A*(sin(1/2*d*x+1/2*c)^2)^ 
(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/ 
2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*b^6+(-12320*A*b^6-35840*B*a*b^5-50400*B*b 
^6)*sin(1/2*d*x+1/2*c)^10*cos(1/2*d*x+1/2*c)+(22880*A*a*b^5+24640*A*b^6+21 
920*B*a^2*b^4+71680*B*a*b^5+56880*B*b^6)*sin(1/2*d*x+1/2*c)^8*cos(1/2*d*x+ 
1/2*c)+(-14960*A*a^2*b^4-34320*A*a*b^5-22792*A*b^6-4640*B*a^3*b^3-32880*B* 
a^2*b^4-66160*B*a*b^5-34920*B*b^6)*sin(1/2*d*x+1/2*c)^6*cos(1/2*d*x+1/2*c) 
+(3520*A*a^3*b^3+14960*A*a^2*b^4+26488*A*a*b^5+10472*A*b^6-20*B*a^4*b^2+46 
40*B*a^3*b^3+25120*B*a^2*b^4+30320*B*a*b^5+13860*B*b^6)*sin(1/2*d*x+1/2*c) 
^4*cos(1/2*d*x+1/2*c)+(-110*A*a^4*b^2-1760*A*a^3*b^3-7326*A*a^2*b^4-7524*A 
*a*b^5-1848*A*b^6+40*B*a^5*b+10*B*a^4*b^2-3210*B*a^3*b^3-7080*B*a^2*b^4-66 
90*B*a*b^5-2790*B*b^6)*sin(1/2*d*x+1/2*c)^2*cos(1/2*d*x+1/2*c)+110*A*(sin( 
1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2 
)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^5*b+110*A*(sin(1/2...
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.15 (sec) , antiderivative size = 726, normalized size of antiderivative = 1.57 \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx =\text {Too large to display} \] Input:

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)),x, algorith 
m="fricas")
 

Output:

-2/10395*(sqrt(1/2)*(-80*I*B*a^6 + 220*I*A*a^5*b - 480*I*B*a^4*b^2 - 1023* 
I*A*a^3*b^3 + 2535*I*B*a^2*b^4 + 5379*I*A*a*b^5 + 2025*I*B*b^6)*sqrt(b)*we 
ierstrassPInverse(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/ 
3*(3*b*cos(d*x + c) + 3*I*b*sin(d*x + c) + 2*a)/b) + sqrt(1/2)*(80*I*B*a^6 
 - 220*I*A*a^5*b + 480*I*B*a^4*b^2 + 1023*I*A*a^3*b^3 - 2535*I*B*a^2*b^4 - 
 5379*I*A*a*b^5 - 2025*I*B*b^6)*sqrt(b)*weierstrassPInverse(4/3*(4*a^2 - 3 
*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/3*(3*b*cos(d*x + c) - 3*I*b*sin( 
d*x + c) + 2*a)/b) + 3*sqrt(1/2)*(-40*I*B*a^5*b + 110*I*A*a^4*b^2 - 255*I* 
B*a^3*b^3 - 3069*I*A*a^2*b^4 - 3705*I*B*a*b^5 - 1617*I*A*b^6)*sqrt(b)*weie 
rstrassZeta(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, weierstr 
assPInverse(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/3*(3*b 
*cos(d*x + c) + 3*I*b*sin(d*x + c) + 2*a)/b)) + 3*sqrt(1/2)*(40*I*B*a^5*b 
- 110*I*A*a^4*b^2 + 255*I*B*a^3*b^3 + 3069*I*A*a^2*b^4 + 3705*I*B*a*b^5 + 
1617*I*A*b^6)*sqrt(b)*weierstrassZeta(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^ 
3 - 9*a*b^2)/b^3, weierstrassPInverse(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*a^ 
3 - 9*a*b^2)/b^3, 1/3*(3*b*cos(d*x + c) - 3*I*b*sin(d*x + c) + 2*a)/b)) - 
3*(315*B*b^6*cos(d*x + c)^4 - 20*B*a^4*b^2 + 55*A*a^3*b^3 + 1025*B*a^2*b^4 
 + 1793*A*a*b^5 + 675*B*b^6 + 35*(23*B*a*b^5 + 11*A*b^6)*cos(d*x + c)^3 + 
5*(113*B*a^2*b^4 + 209*A*a*b^5 + 81*B*b^6)*cos(d*x + c)^2 + (15*B*a^3*b^3 
+ 825*A*a^2*b^4 + 1145*B*a*b^5 + 539*A*b^6)*cos(d*x + c))*sqrt(b*cos(d*...
 

Sympy [F(-1)]

Timed out. \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx=\text {Timed out} \] Input:

integrate(cos(d*x+c)**2*(a+b*cos(d*x+c))**(5/2)*(A+B*cos(d*x+c)),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx=\int { {\left (B \cos \left (d x + c\right ) + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {5}{2}} \cos \left (d x + c\right )^{2} \,d x } \] Input:

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)),x, algorith 
m="maxima")
 

Output:

integrate((B*cos(d*x + c) + A)*(b*cos(d*x + c) + a)^(5/2)*cos(d*x + c)^2, 
x)
 

Giac [F]

\[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx=\int { {\left (B \cos \left (d x + c\right ) + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {5}{2}} \cos \left (d x + c\right )^{2} \,d x } \] Input:

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)),x, algorith 
m="giac")
 

Output:

integrate((B*cos(d*x + c) + A)*(b*cos(d*x + c) + a)^(5/2)*cos(d*x + c)^2, 
x)
                                                                                    
                                                                                    
 

Mupad [F(-1)]

Timed out. \[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx=\int {\cos \left (c+d\,x\right )}^2\,\left (A+B\,\cos \left (c+d\,x\right )\right )\,{\left (a+b\,\cos \left (c+d\,x\right )\right )}^{5/2} \,d x \] Input:

int(cos(c + d*x)^2*(A + B*cos(c + d*x))*(a + b*cos(c + d*x))^(5/2),x)
 

Output:

int(cos(c + d*x)^2*(A + B*cos(c + d*x))*(a + b*cos(c + d*x))^(5/2), x)
 

Reduce [F]

\[ \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+B \cos (c+d x)) \, dx=\left (\int \sqrt {\cos \left (d x +c \right ) b +a}\, \cos \left (d x +c \right )^{5}d x \right ) b^{3}+3 \left (\int \sqrt {\cos \left (d x +c \right ) b +a}\, \cos \left (d x +c \right )^{4}d x \right ) a \,b^{2}+3 \left (\int \sqrt {\cos \left (d x +c \right ) b +a}\, \cos \left (d x +c \right )^{3}d x \right ) a^{2} b +\left (\int \sqrt {\cos \left (d x +c \right ) b +a}\, \cos \left (d x +c \right )^{2}d x \right ) a^{3} \] Input:

int(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)),x)
 

Output:

int(sqrt(cos(c + d*x)*b + a)*cos(c + d*x)**5,x)*b**3 + 3*int(sqrt(cos(c + 
d*x)*b + a)*cos(c + d*x)**4,x)*a*b**2 + 3*int(sqrt(cos(c + d*x)*b + a)*cos 
(c + d*x)**3,x)*a**2*b + int(sqrt(cos(c + d*x)*b + a)*cos(c + d*x)**2,x)*a 
**3