\(\int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx\) [636]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [F]
Fricas [F]
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 33, antiderivative size = 644 \[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=-\frac {c^6 \left (4 a^3 A b \left (15-8 m+m^2\right )+a^4 B \left (15-8 m+m^2\right )+4 a A b^3 \left (10-7 m+m^2\right )+6 a^2 b^2 B \left (10-7 m+m^2\right )+b^4 B \left (8-6 m+m^2\right )\right ) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {6-m}{2},\frac {8-m}{2},\cos ^2(e+f x)\right ) (c \sec (e+f x))^{-6+m} \sin (e+f x)}{f (2-m) (4-m) (6-m) \sqrt {\sin ^2(e+f x)}}-\frac {c^5 \left (a^4 A \left (8-6 m+m^2\right )+6 a^2 A b^2 \left (4-5 m+m^2\right )+4 a^3 b B \left (4-5 m+m^2\right )+A b^4 \left (3-4 m+m^2\right )+4 a b^3 B \left (3-4 m+m^2\right )\right ) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5-m}{2},\frac {7-m}{2},\cos ^2(e+f x)\right ) (c \sec (e+f x))^{-5+m} \sin (e+f x)}{f (1-m) (3-m) (5-m) \sqrt {\sin ^2(e+f x)}}-\frac {a c^5 \left (4 a^2 A b \left (3-4 m+m^2\right )+a^3 B \left (3-4 m+m^2\right )+2 A b^3 \left (4-2 m+m^2\right )+a b^2 B \left (8-13 m+5 m^2\right )\right ) (c \sec (e+f x))^{-5+m} \tan (e+f x)}{f (1-m) (2-m) (4-m)}-\frac {a^2 c^5 \left (2 a b B (1-m)^2+a^2 A (2-m)^2+A b^2 \left (6-m+m^2\right )\right ) \sec (e+f x) (c \sec (e+f x))^{-5+m} \tan (e+f x)}{f (1-m) (2-m) (3-m)}-\frac {a c^5 (a B (1-m)-A b (2+m)) (c \sec (e+f x))^{-5+m} (b+a \sec (e+f x))^2 \tan (e+f x)}{f (1-m) (2-m)}-\frac {a A c^5 (c \sec (e+f x))^{-5+m} (b+a \sec (e+f x))^3 \tan (e+f x)}{f (1-m)} \] Output:

-c^6*(4*a^3*A*b*(m^2-8*m+15)+a^4*B*(m^2-8*m+15)+4*a*A*b^3*(m^2-7*m+10)+6*a 
^2*b^2*B*(m^2-7*m+10)+b^4*B*(m^2-6*m+8))*hypergeom([1/2, 3-1/2*m],[4-1/2*m 
],cos(f*x+e)^2)*(c*sec(f*x+e))^(-6+m)*sin(f*x+e)/f/(2-m)/(4-m)/(6-m)/(sin( 
f*x+e)^2)^(1/2)-c^5*(a^4*A*(m^2-6*m+8)+6*a^2*A*b^2*(m^2-5*m+4)+4*a^3*b*B*( 
m^2-5*m+4)+A*b^4*(m^2-4*m+3)+4*a*b^3*B*(m^2-4*m+3))*hypergeom([1/2, 5/2-1/ 
2*m],[7/2-1/2*m],cos(f*x+e)^2)*(c*sec(f*x+e))^(-5+m)*sin(f*x+e)/f/(1-m)/(3 
-m)/(5-m)/(sin(f*x+e)^2)^(1/2)-a*c^5*(4*a^2*A*b*(m^2-4*m+3)+a^3*B*(m^2-4*m 
+3)+2*A*b^3*(m^2-2*m+4)+a*b^2*B*(5*m^2-13*m+8))*(c*sec(f*x+e))^(-5+m)*tan( 
f*x+e)/f/(1-m)/(2-m)/(4-m)-a^2*c^5*(2*a*b*B*(1-m)^2+a^2*A*(2-m)^2+A*b^2*(m 
^2-m+6))*sec(f*x+e)*(c*sec(f*x+e))^(-5+m)*tan(f*x+e)/f/(1-m)/(2-m)/(3-m)-a 
*c^5*(a*B*(1-m)-A*b*(2+m))*(c*sec(f*x+e))^(-5+m)*(b+a*sec(f*x+e))^2*tan(f* 
x+e)/f/(1-m)/(2-m)-a*A*c^5*(c*sec(f*x+e))^(-5+m)*(b+a*sec(f*x+e))^3*tan(f* 
x+e)/f/(1-m)
 

Mathematica [A] (verified)

Time = 4.63 (sec) , antiderivative size = 317, normalized size of antiderivative = 0.49 \[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=\frac {\cot (e+f x) \left (\frac {b^4 B \cos ^5(e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2} (-5+m),\frac {1}{2} (-3+m),\sec ^2(e+f x)\right )}{-5+m}+\frac {b^3 (A b+4 a B) \cos ^4(e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2} (-4+m),\frac {1}{2} (-2+m),\sec ^2(e+f x)\right )}{-4+m}+a \left (\frac {2 b^2 (2 A b+3 a B) \cos ^3(e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2} (-3+m),\frac {1}{2} (-1+m),\sec ^2(e+f x)\right )}{-3+m}+a \left (\frac {2 b (3 A b+2 a B) \cos ^2(e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2} (-2+m),\frac {m}{2},\sec ^2(e+f x)\right )}{-2+m}+a \left (\frac {(4 A b+a B) \cos (e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2} (-1+m),\frac {1+m}{2},\sec ^2(e+f x)\right )}{-1+m}+\frac {a A \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m}{2},\frac {2+m}{2},\sec ^2(e+f x)\right )}{m}\right )\right )\right )\right ) (c \sec (e+f x))^m \sqrt {-\tan ^2(e+f x)}}{f} \] Input:

Integrate[(a + b*Cos[e + f*x])^4*(A + B*Cos[e + f*x])*(c*Sec[e + f*x])^m,x 
]
 

Output:

(Cot[e + f*x]*((b^4*B*Cos[e + f*x]^5*Hypergeometric2F1[1/2, (-5 + m)/2, (- 
3 + m)/2, Sec[e + f*x]^2])/(-5 + m) + (b^3*(A*b + 4*a*B)*Cos[e + f*x]^4*Hy 
pergeometric2F1[1/2, (-4 + m)/2, (-2 + m)/2, Sec[e + f*x]^2])/(-4 + m) + a 
*((2*b^2*(2*A*b + 3*a*B)*Cos[e + f*x]^3*Hypergeometric2F1[1/2, (-3 + m)/2, 
 (-1 + m)/2, Sec[e + f*x]^2])/(-3 + m) + a*((2*b*(3*A*b + 2*a*B)*Cos[e + f 
*x]^2*Hypergeometric2F1[1/2, (-2 + m)/2, m/2, Sec[e + f*x]^2])/(-2 + m) + 
a*(((4*A*b + a*B)*Cos[e + f*x]*Hypergeometric2F1[1/2, (-1 + m)/2, (1 + m)/ 
2, Sec[e + f*x]^2])/(-1 + m) + (a*A*Hypergeometric2F1[1/2, m/2, (2 + m)/2, 
 Sec[e + f*x]^2])/m))))*(c*Sec[e + f*x])^m*Sqrt[-Tan[e + f*x]^2])/f
 

Rubi [A] (verified)

Time = 4.32 (sec) , antiderivative size = 617, normalized size of antiderivative = 0.96, number of steps used = 21, number of rules used = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.636, Rules used = {3042, 3439, 3042, 4514, 25, 3042, 4584, 3042, 4564, 25, 3042, 4535, 3042, 4259, 3042, 3122, 4534, 3042, 4259, 3042, 3122}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \left (a+b \sin \left (e+f x+\frac {\pi }{2}\right )\right )^4 \left (A+B \sin \left (e+f x+\frac {\pi }{2}\right )\right ) \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^mdx\)

\(\Big \downarrow \) 3439

\(\displaystyle c^5 \int (c \sec (e+f x))^{m-5} (b+a \sec (e+f x))^4 (B+A \sec (e+f x))dx\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left (b+a \csc \left (e+f x+\frac {\pi }{2}\right )\right )^4 \left (B+A \csc \left (e+f x+\frac {\pi }{2}\right )\right )dx\)

\(\Big \downarrow \) 4514

\(\displaystyle c^5 \left (-\frac {\int -(c \sec (e+f x))^{m-5} (b+a \sec (e+f x))^2 \left (a (a B (1-m)-A b (m+2)) \sec ^2(e+f x)+\left (A (2-m) a^2+b (A b+2 a B) (1-m)\right ) \sec (e+f x)+b (b B (1-m)+a A (5-m))\right )dx}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 25

\(\displaystyle c^5 \left (\frac {\int (c \sec (e+f x))^{m-5} (b+a \sec (e+f x))^2 \left (a (a B (1-m)-A b (m+2)) \sec ^2(e+f x)+\left (A (2-m) a^2+b (A b+2 a B) (1-m)\right ) \sec (e+f x)+b (b B (1-m)+a A (5-m))\right )dx}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \left (\frac {\int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left (b+a \csc \left (e+f x+\frac {\pi }{2}\right )\right )^2 \left (a (a B (1-m)-A b (m+2)) \csc \left (e+f x+\frac {\pi }{2}\right )^2+\left (A (2-m) a^2+b (A b+2 a B) (1-m)\right ) \csc \left (e+f x+\frac {\pi }{2}\right )+b (b B (1-m)+a A (5-m))\right )dx}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 4584

\(\displaystyle c^5 \left (\frac {-\frac {\int (c \sec (e+f x))^{m-5} (b+a \sec (e+f x)) \left (-a \left (A \left (m^2-m+6\right ) b^2+2 a B (1-m)^2 b+a^2 A (2-m)^2\right ) \sec ^2(e+f x)-\left (B \left (m^2-4 m+3\right ) a^3+A b \left (3 m^2-12 m+8\right ) a^2+3 b^2 B \left (m^2-3 m+2\right ) a+A b^3 \left (m^2-3 m+2\right )\right ) \sec (e+f x)+b \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right )\right )dx}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \left (\frac {-\frac {\int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left (b+a \csc \left (e+f x+\frac {\pi }{2}\right )\right ) \left (-a \left (A \left (m^2-m+6\right ) b^2+2 a B (1-m)^2 b+a^2 A (2-m)^2\right ) \csc \left (e+f x+\frac {\pi }{2}\right )^2+\left (-B \left (m^2-4 m+3\right ) a^3-A b \left (3 m^2-12 m+8\right ) a^2-3 b^2 B \left (m^2-3 m+2\right ) a-A b^3 \left (m^2-3 m+2\right )\right ) \csc \left (e+f x+\frac {\pi }{2}\right )+b \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right )\right )dx}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 4564

\(\displaystyle c^5 \left (\frac {-\frac {\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}-\frac {\int -(c \sec (e+f x))^{m-5} \left ((3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right ) b^2-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \sec ^2(e+f x)-(2-m) \left (A \left (m^2-6 m+8\right ) a^4+4 b B \left (m^2-5 m+4\right ) a^3+6 A b^2 \left (m^2-5 m+4\right ) a^2+4 b^3 B \left (m^2-4 m+3\right ) a+A b^4 \left (m^2-4 m+3\right )\right ) \sec (e+f x)\right )dx}{3-m}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 25

\(\displaystyle c^5 \left (\frac {-\frac {\frac {\int (c \sec (e+f x))^{m-5} \left ((3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right ) b^2-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \sec ^2(e+f x)-(2-m) \left (A \left (m^2-6 m+8\right ) a^4+4 b B \left (m^2-5 m+4\right ) a^3+6 A b^2 \left (m^2-5 m+4\right ) a^2+4 b^3 B \left (m^2-4 m+3\right ) a+A b^4 \left (m^2-4 m+3\right )\right ) \sec (e+f x)\right )dx}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \left (\frac {-\frac {\frac {\int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left ((3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right ) b^2-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \csc \left (e+f x+\frac {\pi }{2}\right )^2-(2-m) \left (A \left (m^2-6 m+8\right ) a^4+4 b B \left (m^2-5 m+4\right ) a^3+6 A b^2 \left (m^2-5 m+4\right ) a^2+4 b^3 B \left (m^2-4 m+3\right ) a+A b^4 \left (m^2-4 m+3\right )\right ) \csc \left (e+f x+\frac {\pi }{2}\right )\right )dx}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 4535

\(\displaystyle c^5 \left (\frac {-\frac {\frac {\int (c \sec (e+f x))^{m-5} \left (b^2 (3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right )-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \sec ^2(e+f x)\right )dx-\frac {(2-m) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) \int (c \sec (e+f x))^{m-4}dx}{c}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \left (\frac {-\frac {\frac {\int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left (b^2 (3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right )-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \csc \left (e+f x+\frac {\pi }{2}\right )^2\right )dx-\frac {(2-m) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) \int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-4}dx}{c}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 4259

\(\displaystyle c^5 \left (\frac {-\frac {\frac {\int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left (b^2 (3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right )-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \csc \left (e+f x+\frac {\pi }{2}\right )^2\right )dx-\frac {(2-m) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) \left (\frac {\cos (e+f x)}{c}\right )^m (c \sec (e+f x))^m \int \left (\frac {\cos (e+f x)}{c}\right )^{4-m}dx}{c}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \left (\frac {-\frac {\frac {\int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left (b^2 (3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right )-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \csc \left (e+f x+\frac {\pi }{2}\right )^2\right )dx-\frac {(2-m) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) \left (\frac {\cos (e+f x)}{c}\right )^m (c \sec (e+f x))^m \int \left (\frac {\sin \left (e+f x+\frac {\pi }{2}\right )}{c}\right )^{4-m}dx}{c}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3122

\(\displaystyle c^5 \left (\frac {-\frac {\frac {\int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5} \left (b^2 (3-m) \left (-B \left (m^2-6 m+5\right ) a^2+2 A b (5-m) m a-b^2 B \left (m^2-3 m+2\right )\right )-a (3-m) \left (B \left (m^2-4 m+3\right ) a^3+4 A b \left (m^2-4 m+3\right ) a^2+b^2 B \left (5 m^2-13 m+8\right ) a+2 A b^3 \left (m^2-2 m+4\right )\right ) \csc \left (e+f x+\frac {\pi }{2}\right )^2\right )dx+\frac {(2-m) \sin (e+f x) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) (c \sec (e+f x))^{m-5} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5-m}{2},\frac {7-m}{2},\cos ^2(e+f x)\right )}{f (5-m) \sqrt {\sin ^2(e+f x)}}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 4534

\(\displaystyle c^5 \left (\frac {-\frac {\frac {-\frac {\left (m^2-4 m+3\right ) \left (a^4 B \left (m^2-8 m+15\right )+4 a^3 A b \left (m^2-8 m+15\right )+6 a^2 b^2 B \left (m^2-7 m+10\right )+4 a A b^3 \left (m^2-7 m+10\right )+b^4 B \left (m^2-6 m+8\right )\right ) \int (c \sec (e+f x))^{m-5}dx}{4-m}+\frac {a (3-m) \tan (e+f x) \left (a^3 B \left (m^2-4 m+3\right )+4 a^2 A b \left (m^2-4 m+3\right )+a b^2 B \left (5 m^2-13 m+8\right )+2 A b^3 \left (m^2-2 m+4\right )\right ) (c \sec (e+f x))^{m-5}}{f (4-m)}+\frac {(2-m) \sin (e+f x) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) (c \sec (e+f x))^{m-5} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5-m}{2},\frac {7-m}{2},\cos ^2(e+f x)\right )}{f (5-m) \sqrt {\sin ^2(e+f x)}}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \left (\frac {-\frac {\frac {-\frac {\left (m^2-4 m+3\right ) \left (a^4 B \left (m^2-8 m+15\right )+4 a^3 A b \left (m^2-8 m+15\right )+6 a^2 b^2 B \left (m^2-7 m+10\right )+4 a A b^3 \left (m^2-7 m+10\right )+b^4 B \left (m^2-6 m+8\right )\right ) \int \left (c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{m-5}dx}{4-m}+\frac {a (3-m) \tan (e+f x) \left (a^3 B \left (m^2-4 m+3\right )+4 a^2 A b \left (m^2-4 m+3\right )+a b^2 B \left (5 m^2-13 m+8\right )+2 A b^3 \left (m^2-2 m+4\right )\right ) (c \sec (e+f x))^{m-5}}{f (4-m)}+\frac {(2-m) \sin (e+f x) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) (c \sec (e+f x))^{m-5} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5-m}{2},\frac {7-m}{2},\cos ^2(e+f x)\right )}{f (5-m) \sqrt {\sin ^2(e+f x)}}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 4259

\(\displaystyle c^5 \left (\frac {-\frac {\frac {-\frac {\left (m^2-4 m+3\right ) \left (a^4 B \left (m^2-8 m+15\right )+4 a^3 A b \left (m^2-8 m+15\right )+6 a^2 b^2 B \left (m^2-7 m+10\right )+4 a A b^3 \left (m^2-7 m+10\right )+b^4 B \left (m^2-6 m+8\right )\right ) \left (\frac {\cos (e+f x)}{c}\right )^m (c \sec (e+f x))^m \int \left (\frac {\cos (e+f x)}{c}\right )^{5-m}dx}{4-m}+\frac {a (3-m) \tan (e+f x) \left (a^3 B \left (m^2-4 m+3\right )+4 a^2 A b \left (m^2-4 m+3\right )+a b^2 B \left (5 m^2-13 m+8\right )+2 A b^3 \left (m^2-2 m+4\right )\right ) (c \sec (e+f x))^{m-5}}{f (4-m)}+\frac {(2-m) \sin (e+f x) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) (c \sec (e+f x))^{m-5} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5-m}{2},\frac {7-m}{2},\cos ^2(e+f x)\right )}{f (5-m) \sqrt {\sin ^2(e+f x)}}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle c^5 \left (\frac {-\frac {\frac {-\frac {\left (m^2-4 m+3\right ) \left (a^4 B \left (m^2-8 m+15\right )+4 a^3 A b \left (m^2-8 m+15\right )+6 a^2 b^2 B \left (m^2-7 m+10\right )+4 a A b^3 \left (m^2-7 m+10\right )+b^4 B \left (m^2-6 m+8\right )\right ) \left (\frac {\cos (e+f x)}{c}\right )^m (c \sec (e+f x))^m \int \left (\frac {\sin \left (e+f x+\frac {\pi }{2}\right )}{c}\right )^{5-m}dx}{4-m}+\frac {a (3-m) \tan (e+f x) \left (a^3 B \left (m^2-4 m+3\right )+4 a^2 A b \left (m^2-4 m+3\right )+a b^2 B \left (5 m^2-13 m+8\right )+2 A b^3 \left (m^2-2 m+4\right )\right ) (c \sec (e+f x))^{m-5}}{f (4-m)}+\frac {(2-m) \sin (e+f x) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) (c \sec (e+f x))^{m-5} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5-m}{2},\frac {7-m}{2},\cos ^2(e+f x)\right )}{f (5-m) \sqrt {\sin ^2(e+f x)}}}{3-m}+\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

\(\Big \downarrow \) 3122

\(\displaystyle c^5 \left (\frac {-\frac {\frac {a^2 \tan (e+f x) \sec (e+f x) \left (a^2 A (2-m)^2+2 a b B (1-m)^2+A b^2 \left (m^2-m+6\right )\right ) (c \sec (e+f x))^{m-5}}{f (3-m)}+\frac {\frac {a (3-m) \tan (e+f x) \left (a^3 B \left (m^2-4 m+3\right )+4 a^2 A b \left (m^2-4 m+3\right )+a b^2 B \left (5 m^2-13 m+8\right )+2 A b^3 \left (m^2-2 m+4\right )\right ) (c \sec (e+f x))^{m-5}}{f (4-m)}+\frac {c \left (m^2-4 m+3\right ) \sin (e+f x) \left (a^4 B \left (m^2-8 m+15\right )+4 a^3 A b \left (m^2-8 m+15\right )+6 a^2 b^2 B \left (m^2-7 m+10\right )+4 a A b^3 \left (m^2-7 m+10\right )+b^4 B \left (m^2-6 m+8\right )\right ) (c \sec (e+f x))^{m-6} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {6-m}{2},\frac {8-m}{2},\cos ^2(e+f x)\right )}{f (4-m) (6-m) \sqrt {\sin ^2(e+f x)}}+\frac {(2-m) \sin (e+f x) \left (a^4 A \left (m^2-6 m+8\right )+4 a^3 b B \left (m^2-5 m+4\right )+6 a^2 A b^2 \left (m^2-5 m+4\right )+4 a b^3 B \left (m^2-4 m+3\right )+A b^4 \left (m^2-4 m+3\right )\right ) (c \sec (e+f x))^{m-5} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5-m}{2},\frac {7-m}{2},\cos ^2(e+f x)\right )}{f (5-m) \sqrt {\sin ^2(e+f x)}}}{3-m}}{2-m}-\frac {a \tan (e+f x) (a B (1-m)-A b (m+2)) (a \sec (e+f x)+b)^2 (c \sec (e+f x))^{m-5}}{f (2-m)}}{1-m}-\frac {a A \tan (e+f x) (a \sec (e+f x)+b)^3 (c \sec (e+f x))^{m-5}}{f (1-m)}\right )\)

Input:

Int[(a + b*Cos[e + f*x])^4*(A + B*Cos[e + f*x])*(c*Sec[e + f*x])^m,x]
 

Output:

c^5*(-((a*A*(c*Sec[e + f*x])^(-5 + m)*(b + a*Sec[e + f*x])^3*Tan[e + f*x]) 
/(f*(1 - m))) + (-((a*(a*B*(1 - m) - A*b*(2 + m))*(c*Sec[e + f*x])^(-5 + m 
)*(b + a*Sec[e + f*x])^2*Tan[e + f*x])/(f*(2 - m))) - ((a^2*(2*a*b*B*(1 - 
m)^2 + a^2*A*(2 - m)^2 + A*b^2*(6 - m + m^2))*Sec[e + f*x]*(c*Sec[e + f*x] 
)^(-5 + m)*Tan[e + f*x])/(f*(3 - m)) + ((c*(3 - 4*m + m^2)*(4*a^3*A*b*(15 
- 8*m + m^2) + a^4*B*(15 - 8*m + m^2) + 4*a*A*b^3*(10 - 7*m + m^2) + 6*a^2 
*b^2*B*(10 - 7*m + m^2) + b^4*B*(8 - 6*m + m^2))*Hypergeometric2F1[1/2, (6 
 - m)/2, (8 - m)/2, Cos[e + f*x]^2]*(c*Sec[e + f*x])^(-6 + m)*Sin[e + f*x] 
)/(f*(4 - m)*(6 - m)*Sqrt[Sin[e + f*x]^2]) + ((2 - m)*(a^4*A*(8 - 6*m + m^ 
2) + 6*a^2*A*b^2*(4 - 5*m + m^2) + 4*a^3*b*B*(4 - 5*m + m^2) + A*b^4*(3 - 
4*m + m^2) + 4*a*b^3*B*(3 - 4*m + m^2))*Hypergeometric2F1[1/2, (5 - m)/2, 
(7 - m)/2, Cos[e + f*x]^2]*(c*Sec[e + f*x])^(-5 + m)*Sin[e + f*x])/(f*(5 - 
 m)*Sqrt[Sin[e + f*x]^2]) + (a*(3 - m)*(4*a^2*A*b*(3 - 4*m + m^2) + a^3*B* 
(3 - 4*m + m^2) + 2*A*b^3*(4 - 2*m + m^2) + a*b^2*B*(8 - 13*m + 5*m^2))*(c 
*Sec[e + f*x])^(-5 + m)*Tan[e + f*x])/(f*(4 - m)))/(3 - m))/(2 - m))/(1 - 
m))
 

Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3122
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*(( 
b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]))*Hypergeometric2 
F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2], x] /; FreeQ[{b, c, d, n}, x] 
 &&  !IntegerQ[2*n]
 

rule 3439
Int[(csc[(e_.) + (f_.)*(x_)]*(g_.))^(p_.)*((a_.) + (b_.)*sin[(e_.) + (f_.)* 
(x_)])^(m_.)*((c_) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Sim 
p[g^(m + n)   Int[(g*Csc[e + f*x])^(p - m - n)*(b + a*Csc[e + f*x])^m*(d + 
c*Csc[e + f*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && NeQ[b*c 
- a*d, 0] &&  !IntegerQ[p] && IntegerQ[m] && IntegerQ[n]
 

rule 4259
Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(b*Csc[c + d*x] 
)^(n - 1)*((Sin[c + d*x]/b)^(n - 1)   Int[1/(Sin[c + d*x]/b)^n, x]), x] /; 
FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]
 

rule 4514
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + ( 
a_))^(m_)*(csc[(e_.) + (f_.)*(x_)]*(B_.) + (A_)), x_Symbol] :> Simp[(-b)*B* 
Cot[e + f*x]*(a + b*Csc[e + f*x])^(m - 1)*((d*Csc[e + f*x])^n/(f*(m + n))), 
 x] + Simp[1/(m + n)   Int[(a + b*Csc[e + f*x])^(m - 2)*(d*Csc[e + f*x])^n* 
Simp[a^2*A*(m + n) + a*b*B*n + (a*(2*A*b + a*B)*(m + n) + b^2*B*(m + n - 1) 
)*Csc[e + f*x] + b*(A*b*(m + n) + a*B*(2*m + n - 1))*Csc[e + f*x]^2, x], x] 
, x] /; FreeQ[{a, b, d, e, f, A, B, n}, x] && NeQ[A*b - a*B, 0] && NeQ[a^2 
- b^2, 0] && GtQ[m, 1] &&  !(IGtQ[n, 1] &&  !IntegerQ[m])
 

rule 4534
Int[(csc[(e_.) + (f_.)*(x_)]*(b_.))^(m_.)*(csc[(e_.) + (f_.)*(x_)]^2*(C_.) 
+ (A_)), x_Symbol] :> Simp[(-C)*Cot[e + f*x]*((b*Csc[e + f*x])^m/(f*(m + 1) 
)), x] + Simp[(C*m + A*(m + 1))/(m + 1)   Int[(b*Csc[e + f*x])^m, x], x] /; 
 FreeQ[{b, e, f, A, C, m}, x] && NeQ[C*m + A*(m + 1), 0] &&  !LeQ[m, -1]
 

rule 4535
Int[(csc[(e_.) + (f_.)*(x_)]*(b_.))^(m_.)*((A_.) + csc[(e_.) + (f_.)*(x_)]* 
(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_.)), x_Symbol] :> Simp[B/b   Int[(b*Cs 
c[e + f*x])^(m + 1), x], x] + Int[(b*Csc[e + f*x])^m*(A + C*Csc[e + f*x]^2) 
, x] /; FreeQ[{b, e, f, A, B, C, m}, x]
 

rule 4564
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. 
))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + ( 
a_)), x_Symbol] :> Simp[(-b)*C*Csc[e + f*x]*Cot[e + f*x]*((d*Csc[e + f*x])^ 
n/(f*(n + 2))), x] + Simp[1/(n + 2)   Int[(d*Csc[e + f*x])^n*Simp[A*a*(n + 
2) + (B*a*(n + 2) + b*(C*(n + 1) + A*(n + 2)))*Csc[e + f*x] + (a*C + B*b)*( 
n + 2)*Csc[e + f*x]^2, x], x], x] /; FreeQ[{a, b, d, e, f, A, B, C, n}, x] 
&&  !LtQ[n, -1]
 

rule 4584
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. 
))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a 
_))^(m_), x_Symbol] :> Simp[(-C)*Cot[e + f*x]*(a + b*Csc[e + f*x])^m*((d*Cs 
c[e + f*x])^n/(f*(m + n + 1))), x] + Simp[1/(m + n + 1)   Int[(a + b*Csc[e 
+ f*x])^(m - 1)*(d*Csc[e + f*x])^n*Simp[a*A*(m + n + 1) + a*C*n + ((A*b + a 
*B)*(m + n + 1) + b*C*(m + n))*Csc[e + f*x] + (b*B*(m + n + 1) + a*C*m)*Csc 
[e + f*x]^2, x], x], x] /; FreeQ[{a, b, d, e, f, A, B, C, n}, x] && NeQ[a^2 
 - b^2, 0] && GtQ[m, 0] &&  !LeQ[n, -1]
 
Maple [F]

\[\int \left (a +b \cos \left (f x +e \right )\right )^{4} \left (A +B \cos \left (f x +e \right )\right ) \left (c \sec \left (f x +e \right )\right )^{m}d x\]

Input:

int((a+b*cos(f*x+e))^4*(A+B*cos(f*x+e))*(c*sec(f*x+e))^m,x)
 

Output:

int((a+b*cos(f*x+e))^4*(A+B*cos(f*x+e))*(c*sec(f*x+e))^m,x)
 

Fricas [F]

\[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=\int { {\left (B \cos \left (f x + e\right ) + A\right )} {\left (b \cos \left (f x + e\right ) + a\right )}^{4} \left (c \sec \left (f x + e\right )\right )^{m} \,d x } \] Input:

integrate((a+b*cos(f*x+e))^4*(A+B*cos(f*x+e))*(c*sec(f*x+e))^m,x, algorith 
m="fricas")
 

Output:

integral((B*b^4*cos(f*x + e)^5 + A*a^4 + (4*B*a*b^3 + A*b^4)*cos(f*x + e)^ 
4 + 2*(3*B*a^2*b^2 + 2*A*a*b^3)*cos(f*x + e)^3 + 2*(2*B*a^3*b + 3*A*a^2*b^ 
2)*cos(f*x + e)^2 + (B*a^4 + 4*A*a^3*b)*cos(f*x + e))*(c*sec(f*x + e))^m, 
x)
 

Sympy [F(-1)]

Timed out. \[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=\text {Timed out} \] Input:

integrate((a+b*cos(f*x+e))**4*(A+B*cos(f*x+e))*(c*sec(f*x+e))**m,x)
 

Output:

Timed out
 

Maxima [F]

\[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=\int { {\left (B \cos \left (f x + e\right ) + A\right )} {\left (b \cos \left (f x + e\right ) + a\right )}^{4} \left (c \sec \left (f x + e\right )\right )^{m} \,d x } \] Input:

integrate((a+b*cos(f*x+e))^4*(A+B*cos(f*x+e))*(c*sec(f*x+e))^m,x, algorith 
m="maxima")
 

Output:

integrate((B*cos(f*x + e) + A)*(b*cos(f*x + e) + a)^4*(c*sec(f*x + e))^m, 
x)
 

Giac [F]

\[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=\int { {\left (B \cos \left (f x + e\right ) + A\right )} {\left (b \cos \left (f x + e\right ) + a\right )}^{4} \left (c \sec \left (f x + e\right )\right )^{m} \,d x } \] Input:

integrate((a+b*cos(f*x+e))^4*(A+B*cos(f*x+e))*(c*sec(f*x+e))^m,x, algorith 
m="giac")
 

Output:

integrate((B*cos(f*x + e) + A)*(b*cos(f*x + e) + a)^4*(c*sec(f*x + e))^m, 
x)
 

Mupad [F(-1)]

Timed out. \[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=\int {\left (\frac {c}{\cos \left (e+f\,x\right )}\right )}^m\,\left (A+B\,\cos \left (e+f\,x\right )\right )\,{\left (a+b\,\cos \left (e+f\,x\right )\right )}^4 \,d x \] Input:

int((c/cos(e + f*x))^m*(A + B*cos(e + f*x))*(a + b*cos(e + f*x))^4,x)
                                                                                    
                                                                                    
 

Output:

int((c/cos(e + f*x))^m*(A + B*cos(e + f*x))*(a + b*cos(e + f*x))^4, x)
 

Reduce [F]

\[ \int (a+b \cos (e+f x))^4 (A+B \cos (e+f x)) (c \sec (e+f x))^m \, dx=c^{m} \left (\left (\int \sec \left (f x +e \right )^{m}d x \right ) a^{5}+5 \left (\int \sec \left (f x +e \right )^{m} \cos \left (f x +e \right )d x \right ) a^{4} b +\left (\int \sec \left (f x +e \right )^{m} \cos \left (f x +e \right )^{5}d x \right ) b^{5}+5 \left (\int \sec \left (f x +e \right )^{m} \cos \left (f x +e \right )^{4}d x \right ) a \,b^{4}+10 \left (\int \sec \left (f x +e \right )^{m} \cos \left (f x +e \right )^{3}d x \right ) a^{2} b^{3}+10 \left (\int \sec \left (f x +e \right )^{m} \cos \left (f x +e \right )^{2}d x \right ) a^{3} b^{2}\right ) \] Input:

int((a+b*cos(f*x+e))^4*(A+B*cos(f*x+e))*(c*sec(f*x+e))^m,x)
 

Output:

c**m*(int(sec(e + f*x)**m,x)*a**5 + 5*int(sec(e + f*x)**m*cos(e + f*x),x)* 
a**4*b + int(sec(e + f*x)**m*cos(e + f*x)**5,x)*b**5 + 5*int(sec(e + f*x)* 
*m*cos(e + f*x)**4,x)*a*b**4 + 10*int(sec(e + f*x)**m*cos(e + f*x)**3,x)*a 
**2*b**3 + 10*int(sec(e + f*x)**m*cos(e + f*x)**2,x)*a**3*b**2)