\(\int (a+b \cos (c+d x))^4 (A+C \cos ^2(c+d x)) \sec ^{\frac {13}{2}}(c+d x) \, dx\) [1383]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [F(-1)]
Fricas [C] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 35, antiderivative size = 417 \[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=-\frac {8 a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right ) \sqrt {\cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {\sec (c+d x)}}{15 d}+\frac {2 \left (77 b^4 (A+3 C)+66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {\sec (c+d x)}}{231 d}+\frac {8 a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right ) \sqrt {\sec (c+d x)} \sin (c+d x)}{15 d}+\frac {2 \left (64 A b^4+15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)\right ) \sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{693 d}+\frac {4 a b \left (96 A b^2+a^2 (673 A+891 C)\right ) \sec ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{3465 d}+\frac {2 \left (16 A b^2+3 a^2 (9 A+11 C)\right ) (a+b \cos (c+d x))^2 \sec ^{\frac {7}{2}}(c+d x) \sin (c+d x)}{231 d}+\frac {16 A b (a+b \cos (c+d x))^3 \sec ^{\frac {9}{2}}(c+d x) \sin (c+d x)}{99 d}+\frac {2 A (a+b \cos (c+d x))^4 \sec ^{\frac {11}{2}}(c+d x) \sin (c+d x)}{11 d} \] Output:

-8/15*a*b*(3*b^2*(3*A+5*C)+a^2*(7*A+9*C))*cos(d*x+c)^(1/2)*EllipticE(sin(1 
/2*d*x+1/2*c),2^(1/2))*sec(d*x+c)^(1/2)/d+2/231*(77*b^4*(A+3*C)+66*a^2*b^2 
*(5*A+7*C)+5*a^4*(9*A+11*C))*cos(d*x+c)^(1/2)*InverseJacobiAM(1/2*d*x+1/2* 
c,2^(1/2))*sec(d*x+c)^(1/2)/d+8/15*a*b*(3*b^2*(3*A+5*C)+a^2*(7*A+9*C))*sec 
(d*x+c)^(1/2)*sin(d*x+c)/d+2/693*(64*A*b^4+15*a^4*(9*A+11*C)+9*a^2*b^2*(10 
1*A+143*C))*sec(d*x+c)^(3/2)*sin(d*x+c)/d+4/3465*a*b*(96*A*b^2+a^2*(673*A+ 
891*C))*sec(d*x+c)^(5/2)*sin(d*x+c)/d+2/231*(16*A*b^2+3*a^2*(9*A+11*C))*(a 
+b*cos(d*x+c))^2*sec(d*x+c)^(7/2)*sin(d*x+c)/d+16/99*A*b*(a+b*cos(d*x+c))^ 
3*sec(d*x+c)^(9/2)*sin(d*x+c)/d+2/11*A*(a+b*cos(d*x+c))^4*sec(d*x+c)^(11/2 
)*sin(d*x+c)/d
 

Mathematica [A] (verified)

Time = 9.53 (sec) , antiderivative size = 425, normalized size of antiderivative = 1.02 \[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=\frac {\frac {2 \left (-2156 a^3 A b-2772 a A b^3-2772 a^3 b C-4620 a b^3 C\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{\sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}}+2 \left (225 a^4 A+1650 a^2 A b^2+385 A b^4+275 a^4 C+2310 a^2 b^2 C+1155 b^4 C\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {\sec (c+d x)}}{1155 d}+\frac {\sqrt {\sec (c+d x)} \left (\frac {8}{15} a b \left (7 a^2 A+9 A b^2+9 a^2 C+15 b^2 C\right ) \sin (c+d x)+\frac {2}{77} \sec ^3(c+d x) \left (9 a^4 A \sin (c+d x)+66 a^2 A b^2 \sin (c+d x)+11 a^4 C \sin (c+d x)\right )+\frac {8}{45} \sec ^2(c+d x) \left (7 a^3 A b \sin (c+d x)+9 a A b^3 \sin (c+d x)+9 a^3 b C \sin (c+d x)\right )+\frac {2}{231} \sec (c+d x) \left (45 a^4 A \sin (c+d x)+330 a^2 A b^2 \sin (c+d x)+77 A b^4 \sin (c+d x)+55 a^4 C \sin (c+d x)+462 a^2 b^2 C \sin (c+d x)\right )+\frac {8}{9} a^3 A b \sec ^3(c+d x) \tan (c+d x)+\frac {2}{11} a^4 A \sec ^4(c+d x) \tan (c+d x)\right )}{d} \] Input:

Integrate[(a + b*Cos[c + d*x])^4*(A + C*Cos[c + d*x]^2)*Sec[c + d*x]^(13/2 
),x]
 

Output:

((2*(-2156*a^3*A*b - 2772*a*A*b^3 - 2772*a^3*b*C - 4620*a*b^3*C)*EllipticE 
[(c + d*x)/2, 2])/(Sqrt[Cos[c + d*x]]*Sqrt[Sec[c + d*x]]) + 2*(225*a^4*A + 
 1650*a^2*A*b^2 + 385*A*b^4 + 275*a^4*C + 2310*a^2*b^2*C + 1155*b^4*C)*Sqr 
t[Cos[c + d*x]]*EllipticF[(c + d*x)/2, 2]*Sqrt[Sec[c + d*x]])/(1155*d) + ( 
Sqrt[Sec[c + d*x]]*((8*a*b*(7*a^2*A + 9*A*b^2 + 9*a^2*C + 15*b^2*C)*Sin[c 
+ d*x])/15 + (2*Sec[c + d*x]^3*(9*a^4*A*Sin[c + d*x] + 66*a^2*A*b^2*Sin[c 
+ d*x] + 11*a^4*C*Sin[c + d*x]))/77 + (8*Sec[c + d*x]^2*(7*a^3*A*b*Sin[c + 
 d*x] + 9*a*A*b^3*Sin[c + d*x] + 9*a^3*b*C*Sin[c + d*x]))/45 + (2*Sec[c + 
d*x]*(45*a^4*A*Sin[c + d*x] + 330*a^2*A*b^2*Sin[c + d*x] + 77*A*b^4*Sin[c 
+ d*x] + 55*a^4*C*Sin[c + d*x] + 462*a^2*b^2*C*Sin[c + d*x]))/231 + (8*a^3 
*A*b*Sec[c + d*x]^3*Tan[c + d*x])/9 + (2*a^4*A*Sec[c + d*x]^4*Tan[c + d*x] 
)/11))/d
 

Rubi [A] (verified)

Time = 2.71 (sec) , antiderivative size = 390, normalized size of antiderivative = 0.94, number of steps used = 24, number of rules used = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.686, Rules used = {3042, 4709, 3042, 3527, 27, 3042, 3526, 27, 3042, 3526, 27, 3042, 3510, 27, 3042, 3500, 27, 3042, 3227, 3042, 3116, 3042, 3119, 3120}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \sec ^{\frac {13}{2}}(c+d x) (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \sec (c+d x)^{13/2} (a+b \cos (c+d x))^4 \left (A+C \cos (c+d x)^2\right )dx\)

\(\Big \downarrow \) 4709

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \int \frac {(a+b \cos (c+d x))^4 \left (C \cos ^2(c+d x)+A\right )}{\cos ^{\frac {13}{2}}(c+d x)}dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \int \frac {\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^4 \left (C \sin \left (c+d x+\frac {\pi }{2}\right )^2+A\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{13/2}}dx\)

\(\Big \downarrow \) 3527

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {2}{11} \int \frac {(a+b \cos (c+d x))^3 \left (b (A+11 C) \cos ^2(c+d x)+a (9 A+11 C) \cos (c+d x)+8 A b\right )}{2 \cos ^{\frac {11}{2}}(c+d x)}dx+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \int \frac {(a+b \cos (c+d x))^3 \left (b (A+11 C) \cos ^2(c+d x)+a (9 A+11 C) \cos (c+d x)+8 A b\right )}{\cos ^{\frac {11}{2}}(c+d x)}dx+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \int \frac {\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^3 \left (b (A+11 C) \sin \left (c+d x+\frac {\pi }{2}\right )^2+a (9 A+11 C) \sin \left (c+d x+\frac {\pi }{2}\right )+8 A b\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{11/2}}dx+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3526

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {2}{9} \int \frac {(a+b \cos (c+d x))^2 \left (b^2 (17 A+99 C) \cos ^2(c+d x)+2 a b (73 A+99 C) \cos (c+d x)+3 \left (3 (9 A+11 C) a^2+16 A b^2\right )\right )}{2 \cos ^{\frac {9}{2}}(c+d x)}dx+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \int \frac {(a+b \cos (c+d x))^2 \left (b^2 (17 A+99 C) \cos ^2(c+d x)+2 a b (73 A+99 C) \cos (c+d x)+3 \left (3 (9 A+11 C) a^2+16 A b^2\right )\right )}{\cos ^{\frac {9}{2}}(c+d x)}dx+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \int \frac {\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^2 \left (b^2 (17 A+99 C) \sin \left (c+d x+\frac {\pi }{2}\right )^2+2 a b (73 A+99 C) \sin \left (c+d x+\frac {\pi }{2}\right )+3 \left (3 (9 A+11 C) a^2+16 A b^2\right )\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{9/2}}dx+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3526

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {2}{7} \int \frac {(a+b \cos (c+d x)) \left (b \left (9 (9 A+11 C) a^2+b^2 (167 A+693 C)\right ) \cos ^2(c+d x)+a \left (45 (9 A+11 C) a^2+b^2 (1381 A+2079 C)\right ) \cos (c+d x)+2 b \left ((673 A+891 C) a^2+96 A b^2\right )\right )}{2 \cos ^{\frac {7}{2}}(c+d x)}dx+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \int \frac {(a+b \cos (c+d x)) \left (b \left (9 (9 A+11 C) a^2+b^2 (167 A+693 C)\right ) \cos ^2(c+d x)+a \left (45 (9 A+11 C) a^2+b^2 (1381 A+2079 C)\right ) \cos (c+d x)+2 b \left ((673 A+891 C) a^2+96 A b^2\right )\right )}{\cos ^{\frac {7}{2}}(c+d x)}dx+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \int \frac {\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right ) \left (b \left (9 (9 A+11 C) a^2+b^2 (167 A+693 C)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )^2+a \left (45 (9 A+11 C) a^2+b^2 (1381 A+2079 C)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )+2 b \left ((673 A+891 C) a^2+96 A b^2\right )\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{7/2}}dx+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3510

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}-\frac {2}{5} \int -\frac {5 b^2 \left (9 (9 A+11 C) a^2+b^2 (167 A+693 C)\right ) \cos ^2(c+d x)+924 a b \left ((7 A+9 C) a^2+3 b^2 (3 A+5 C)\right ) \cos (c+d x)+15 \left (15 (9 A+11 C) a^4+9 b^2 (101 A+143 C) a^2+64 A b^4\right )}{2 \cos ^{\frac {5}{2}}(c+d x)}dx\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \int \frac {5 b^2 \left (9 (9 A+11 C) a^2+b^2 (167 A+693 C)\right ) \cos ^2(c+d x)+924 a b \left ((7 A+9 C) a^2+3 b^2 (3 A+5 C)\right ) \cos (c+d x)+15 \left (15 (9 A+11 C) a^4+9 b^2 (101 A+143 C) a^2+64 A b^4\right )}{\cos ^{\frac {5}{2}}(c+d x)}dx+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \int \frac {5 b^2 \left (9 (9 A+11 C) a^2+b^2 (167 A+693 C)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )^2+924 a b \left ((7 A+9 C) a^2+3 b^2 (3 A+5 C)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )+15 \left (15 (9 A+11 C) a^4+9 b^2 (101 A+143 C) a^2+64 A b^4\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{5/2}}dx+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3500

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (\frac {2}{3} \int \frac {9 \left (308 a b \left ((7 A+9 C) a^2+3 b^2 (3 A+5 C)\right )+5 \left (5 (9 A+11 C) a^4+66 b^2 (5 A+7 C) a^2+77 b^4 (A+3 C)\right ) \cos (c+d x)\right )}{2 \cos ^{\frac {3}{2}}(c+d x)}dx+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (3 \int \frac {308 a b \left ((7 A+9 C) a^2+3 b^2 (3 A+5 C)\right )+5 \left (5 (9 A+11 C) a^4+66 b^2 (5 A+7 C) a^2+77 b^4 (A+3 C)\right ) \cos (c+d x)}{\cos ^{\frac {3}{2}}(c+d x)}dx+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (3 \int \frac {308 a b \left ((7 A+9 C) a^2+3 b^2 (3 A+5 C)\right )+5 \left (5 (9 A+11 C) a^4+66 b^2 (5 A+7 C) a^2+77 b^4 (A+3 C)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{3/2}}dx+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3227

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (3 \left (308 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \int \frac {1}{\cos ^{\frac {3}{2}}(c+d x)}dx+5 \left (5 a^4 (9 A+11 C)+66 a^2 b^2 (5 A+7 C)+77 b^4 (A+3 C)\right ) \int \frac {1}{\sqrt {\cos (c+d x)}}dx\right )+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (3 \left (308 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \int \frac {1}{\sin \left (c+d x+\frac {\pi }{2}\right )^{3/2}}dx+5 \left (5 a^4 (9 A+11 C)+66 a^2 b^2 (5 A+7 C)+77 b^4 (A+3 C)\right ) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx\right )+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3116

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (3 \left (308 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\int \sqrt {\cos (c+d x)}dx\right )+5 \left (5 a^4 (9 A+11 C)+66 a^2 b^2 (5 A+7 C)+77 b^4 (A+3 C)\right ) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx\right )+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (3 \left (308 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\int \sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}dx\right )+5 \left (5 a^4 (9 A+11 C)+66 a^2 b^2 (5 A+7 C)+77 b^4 (A+3 C)\right ) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx\right )+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3119

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {1}{7} \left (\frac {1}{5} \left (3 \left (5 \left (5 a^4 (9 A+11 C)+66 a^2 b^2 (5 A+7 C)+77 b^4 (A+3 C)\right ) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx+308 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\frac {2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d}\right )\right )+\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

\(\Big \downarrow \) 3120

\(\displaystyle \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} \left (\frac {1}{11} \left (\frac {1}{9} \left (\frac {6 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}+\frac {1}{7} \left (\frac {4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{5 d \cos ^{\frac {5}{2}}(c+d x)}+\frac {1}{5} \left (\frac {10 \left (15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)+64 A b^4\right ) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}+3 \left (308 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\frac {2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d}\right )+\frac {10 \left (5 a^4 (9 A+11 C)+66 a^2 b^2 (5 A+7 C)+77 b^4 (A+3 C)\right ) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{d}\right )\right )\right )\right )+\frac {16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}\right )+\frac {2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\right )\)

Input:

Int[(a + b*Cos[c + d*x])^4*(A + C*Cos[c + d*x]^2)*Sec[c + d*x]^(13/2),x]
 

Output:

Sqrt[Cos[c + d*x]]*Sqrt[Sec[c + d*x]]*((2*A*(a + b*Cos[c + d*x])^4*Sin[c + 
 d*x])/(11*d*Cos[c + d*x]^(11/2)) + ((16*A*b*(a + b*Cos[c + d*x])^3*Sin[c 
+ d*x])/(9*d*Cos[c + d*x]^(9/2)) + ((6*(16*A*b^2 + 3*a^2*(9*A + 11*C))*(a 
+ b*Cos[c + d*x])^2*Sin[c + d*x])/(7*d*Cos[c + d*x]^(7/2)) + ((4*a*b*(96*A 
*b^2 + a^2*(673*A + 891*C))*Sin[c + d*x])/(5*d*Cos[c + d*x]^(5/2)) + ((10* 
(64*A*b^4 + 15*a^4*(9*A + 11*C) + 9*a^2*b^2*(101*A + 143*C))*Sin[c + d*x]) 
/(d*Cos[c + d*x]^(3/2)) + 3*((10*(77*b^4*(A + 3*C) + 66*a^2*b^2*(5*A + 7*C 
) + 5*a^4*(9*A + 11*C))*EllipticF[(c + d*x)/2, 2])/d + 308*a*b*(3*b^2*(3*A 
 + 5*C) + a^2*(7*A + 9*C))*((-2*EllipticE[(c + d*x)/2, 2])/d + (2*Sin[c + 
d*x])/(d*Sqrt[Cos[c + d*x]]))))/5)/7)/9)/11)
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3116
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*(( 
b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1))), x] + Simp[(n + 2)/(b^2*(n + 1))   I 
nt[(b*Sin[c + d*x])^(n + 2), x], x] /; FreeQ[{b, c, d}, x] && LtQ[n, -1] && 
 IntegerQ[2*n]
 

rule 3119
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* 
(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3120
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 
)*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3227
Int[((b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*sin[(e_.) + (f_.)*(x 
_)]), x_Symbol] :> Simp[c   Int[(b*Sin[e + f*x])^m, x], x] + Simp[d/b   Int 
[(b*Sin[e + f*x])^(m + 1), x], x] /; FreeQ[{b, c, d, e, f, m}, x]
 

rule 3500
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + 
 (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(A*b^2 
 - a*b*B + a^2*C))*Cos[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 1)* 
(a^2 - b^2))), x] + Simp[1/(b*(m + 1)*(a^2 - b^2))   Int[(a + b*Sin[e + f*x 
])^(m + 1)*Simp[b*(a*A - b*B + a*C)*(m + 1) - (A*b^2 - a*b*B + a^2*C + b*(A 
*b - a*B + b*C)*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, 
B, C}, x] && LtQ[m, -1] && NeQ[a^2 - b^2, 0]
 

rule 3510
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f 
_.)*(x_)]^2), x_Symbol] :> Simp[(-(b*c - a*d))*(A*b^2 - a*b*B + a^2*C)*Cos[ 
e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b^2*f*(m + 1)*(a^2 - b^2))), x] - S 
imp[1/(b^2*(m + 1)*(a^2 - b^2))   Int[(a + b*Sin[e + f*x])^(m + 1)*Simp[b*( 
m + 1)*((b*B - a*C)*(b*c - a*d) - A*b*(a*c - b*d)) + (b*B*(a^2*d + b^2*d*(m 
 + 1) - a*b*c*(m + 2)) + (b*c - a*d)*(A*b^2*(m + 2) + C*(a^2 + b^2*(m + 1)) 
))*Sin[e + f*x] - b*C*d*(m + 1)*(a^2 - b^2)*Sin[e + f*x]^2, x], x], x] /; F 
reeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 
 0] && LtQ[m, -1]
 

rule 3526
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) 
 + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(c^2*C - B*c*d + A*d^2))*Cos[e + f*x 
]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(n + 1)*(c^2 - 
d^2))), x] + Simp[1/(d*(n + 1)*(c^2 - d^2))   Int[(a + b*Sin[e + f*x])^(m - 
 1)*(c + d*Sin[e + f*x])^(n + 1)*Simp[A*d*(b*d*m + a*c*(n + 1)) + (c*C - B* 
d)*(b*c*m + a*d*(n + 1)) - (d*(A*(a*d*(n + 2) - b*c*(n + 1)) + B*(b*d*(n + 
1) - a*c*(n + 2))) - C*(b*c*d*(n + 1) - a*(c^2 + d^2*(n + 1))))*Sin[e + f*x 
] + b*(d*(B*c - A*d)*(m + n + 2) - C*(c^2*(m + 1) + d^2*(n + 1)))*Sin[e + f 
*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d 
, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 0] && LtQ[n, -1]
 

rule 3527
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> 
Simp[(-(c^2*C + A*d^2))*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + 
 f*x])^(n + 1)/(d*f*(n + 1)*(c^2 - d^2))), x] + Simp[1/(d*(n + 1)*(c^2 - d^ 
2))   Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x])^(n + 1)*Simp[A* 
d*(b*d*m + a*c*(n + 1)) + c*C*(b*c*m + a*d*(n + 1)) - (A*d*(a*d*(n + 2) - b 
*c*(n + 1)) - C*(b*c*d*(n + 1) - a*(c^2 + d^2*(n + 1))))*Sin[e + f*x] - b*( 
A*d^2*(m + n + 2) + C*(c^2*(m + 1) + d^2*(n + 1)))*Sin[e + f*x]^2, x], x], 
x] /; FreeQ[{a, b, c, d, e, f, A, C}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - 
b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 0] && LtQ[n, -1]
 

rule 4709
Int[(u_)*((c_.)*sec[(a_.) + (b_.)*(x_)])^(m_.), x_Symbol] :> Simp[(c*Sec[a 
+ b*x])^m*(c*Cos[a + b*x])^m   Int[ActivateTrig[u]/(c*Cos[a + b*x])^m, x], 
x] /; FreeQ[{a, b, c, m}, x] &&  !IntegerQ[m] && KnownSineIntegrandQ[u, x]
 
Maple [F(-1)]

Timed out.

hanged

Input:

int((a+b*cos(d*x+c))^4*(A+C*cos(d*x+c)^2)*sec(d*x+c)^(13/2),x)
 

Output:

int((a+b*cos(d*x+c))^4*(A+C*cos(d*x+c)^2)*sec(d*x+c)^(13/2),x)
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.14 (sec) , antiderivative size = 451, normalized size of antiderivative = 1.08 \[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=-\frac {15 \, \sqrt {2} {\left (5 i \, {\left (9 \, A + 11 \, C\right )} a^{4} + 66 i \, {\left (5 \, A + 7 \, C\right )} a^{2} b^{2} + 77 i \, {\left (A + 3 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{5} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + 15 \, \sqrt {2} {\left (-5 i \, {\left (9 \, A + 11 \, C\right )} a^{4} - 66 i \, {\left (5 \, A + 7 \, C\right )} a^{2} b^{2} - 77 i \, {\left (A + 3 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{5} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) + 924 \, \sqrt {2} {\left (i \, {\left (7 \, A + 9 \, C\right )} a^{3} b + 3 i \, {\left (3 \, A + 5 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{5} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right )\right ) + 924 \, \sqrt {2} {\left (-i \, {\left (7 \, A + 9 \, C\right )} a^{3} b - 3 i \, {\left (3 \, A + 5 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{5} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right )\right ) - \frac {2 \, {\left (1540 \, A a^{3} b \cos \left (d x + c\right ) + 924 \, {\left ({\left (7 \, A + 9 \, C\right )} a^{3} b + 3 \, {\left (3 \, A + 5 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{5} + 315 \, A a^{4} + 15 \, {\left (5 \, {\left (9 \, A + 11 \, C\right )} a^{4} + 66 \, {\left (5 \, A + 7 \, C\right )} a^{2} b^{2} + 77 \, A b^{4}\right )} \cos \left (d x + c\right )^{4} + 308 \, {\left ({\left (7 \, A + 9 \, C\right )} a^{3} b + 9 \, A a b^{3}\right )} \cos \left (d x + c\right )^{3} + 45 \, {\left ({\left (9 \, A + 11 \, C\right )} a^{4} + 66 \, A a^{2} b^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{\sqrt {\cos \left (d x + c\right )}}}{3465 \, d \cos \left (d x + c\right )^{5}} \] Input:

integrate((a+b*cos(d*x+c))^4*(A+C*cos(d*x+c)^2)*sec(d*x+c)^(13/2),x, algor 
ithm="fricas")
 

Output:

-1/3465*(15*sqrt(2)*(5*I*(9*A + 11*C)*a^4 + 66*I*(5*A + 7*C)*a^2*b^2 + 77* 
I*(A + 3*C)*b^4)*cos(d*x + c)^5*weierstrassPInverse(-4, 0, cos(d*x + c) + 
I*sin(d*x + c)) + 15*sqrt(2)*(-5*I*(9*A + 11*C)*a^4 - 66*I*(5*A + 7*C)*a^2 
*b^2 - 77*I*(A + 3*C)*b^4)*cos(d*x + c)^5*weierstrassPInverse(-4, 0, cos(d 
*x + c) - I*sin(d*x + c)) + 924*sqrt(2)*(I*(7*A + 9*C)*a^3*b + 3*I*(3*A + 
5*C)*a*b^3)*cos(d*x + c)^5*weierstrassZeta(-4, 0, weierstrassPInverse(-4, 
0, cos(d*x + c) + I*sin(d*x + c))) + 924*sqrt(2)*(-I*(7*A + 9*C)*a^3*b - 3 
*I*(3*A + 5*C)*a*b^3)*cos(d*x + c)^5*weierstrassZeta(-4, 0, weierstrassPIn 
verse(-4, 0, cos(d*x + c) - I*sin(d*x + c))) - 2*(1540*A*a^3*b*cos(d*x + c 
) + 924*((7*A + 9*C)*a^3*b + 3*(3*A + 5*C)*a*b^3)*cos(d*x + c)^5 + 315*A*a 
^4 + 15*(5*(9*A + 11*C)*a^4 + 66*(5*A + 7*C)*a^2*b^2 + 77*A*b^4)*cos(d*x + 
 c)^4 + 308*((7*A + 9*C)*a^3*b + 9*A*a*b^3)*cos(d*x + c)^3 + 45*((9*A + 11 
*C)*a^4 + 66*A*a^2*b^2)*cos(d*x + c)^2)*sin(d*x + c)/sqrt(cos(d*x + c)))/( 
d*cos(d*x + c)^5)
 

Sympy [F(-1)]

Timed out. \[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=\text {Timed out} \] Input:

integrate((a+b*cos(d*x+c))**4*(A+C*cos(d*x+c)**2)*sec(d*x+c)**(13/2),x)
 

Output:

Timed out
                                                                                    
                                                                                    
 

Maxima [F]

\[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=\int { {\left (C \cos \left (d x + c\right )^{2} + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{4} \sec \left (d x + c\right )^{\frac {13}{2}} \,d x } \] Input:

integrate((a+b*cos(d*x+c))^4*(A+C*cos(d*x+c)^2)*sec(d*x+c)^(13/2),x, algor 
ithm="maxima")
 

Output:

integrate((C*cos(d*x + c)^2 + A)*(b*cos(d*x + c) + a)^4*sec(d*x + c)^(13/2 
), x)
 

Giac [F]

\[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=\int { {\left (C \cos \left (d x + c\right )^{2} + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{4} \sec \left (d x + c\right )^{\frac {13}{2}} \,d x } \] Input:

integrate((a+b*cos(d*x+c))^4*(A+C*cos(d*x+c)^2)*sec(d*x+c)^(13/2),x, algor 
ithm="giac")
 

Output:

integrate((C*cos(d*x + c)^2 + A)*(b*cos(d*x + c) + a)^4*sec(d*x + c)^(13/2 
), x)
 

Mupad [F(-1)]

Timed out. \[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=\int \left (C\,{\cos \left (c+d\,x\right )}^2+A\right )\,{\left (\frac {1}{\cos \left (c+d\,x\right )}\right )}^{13/2}\,{\left (a+b\,\cos \left (c+d\,x\right )\right )}^4 \,d x \] Input:

int((A + C*cos(c + d*x)^2)*(1/cos(c + d*x))^(13/2)*(a + b*cos(c + d*x))^4, 
x)
 

Output:

int((A + C*cos(c + d*x)^2)*(1/cos(c + d*x))^(13/2)*(a + b*cos(c + d*x))^4, 
 x)
 

Reduce [F]

\[ \int (a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right ) \sec ^{\frac {13}{2}}(c+d x) \, dx=4 \left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right ) \sec \left (d x +c \right )^{6}d x \right ) a^{4} b +\left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{6} \sec \left (d x +c \right )^{6}d x \right ) b^{4} c +4 \left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{5} \sec \left (d x +c \right )^{6}d x \right ) a \,b^{3} c +6 \left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{4} \sec \left (d x +c \right )^{6}d x \right ) a^{2} b^{2} c +\left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{4} \sec \left (d x +c \right )^{6}d x \right ) a \,b^{4}+4 \left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{3} \sec \left (d x +c \right )^{6}d x \right ) a^{3} b c +4 \left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{3} \sec \left (d x +c \right )^{6}d x \right ) a^{2} b^{3}+\left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{2} \sec \left (d x +c \right )^{6}d x \right ) a^{4} c +6 \left (\int \sqrt {\sec \left (d x +c \right )}\, \cos \left (d x +c \right )^{2} \sec \left (d x +c \right )^{6}d x \right ) a^{3} b^{2}+\left (\int \sqrt {\sec \left (d x +c \right )}\, \sec \left (d x +c \right )^{6}d x \right ) a^{5} \] Input:

int((a+b*cos(d*x+c))^4*(A+C*cos(d*x+c)^2)*sec(d*x+c)^(13/2),x)
 

Output:

4*int(sqrt(sec(c + d*x))*cos(c + d*x)*sec(c + d*x)**6,x)*a**4*b + int(sqrt 
(sec(c + d*x))*cos(c + d*x)**6*sec(c + d*x)**6,x)*b**4*c + 4*int(sqrt(sec( 
c + d*x))*cos(c + d*x)**5*sec(c + d*x)**6,x)*a*b**3*c + 6*int(sqrt(sec(c + 
 d*x))*cos(c + d*x)**4*sec(c + d*x)**6,x)*a**2*b**2*c + int(sqrt(sec(c + d 
*x))*cos(c + d*x)**4*sec(c + d*x)**6,x)*a*b**4 + 4*int(sqrt(sec(c + d*x))* 
cos(c + d*x)**3*sec(c + d*x)**6,x)*a**3*b*c + 4*int(sqrt(sec(c + d*x))*cos 
(c + d*x)**3*sec(c + d*x)**6,x)*a**2*b**3 + int(sqrt(sec(c + d*x))*cos(c + 
 d*x)**2*sec(c + d*x)**6,x)*a**4*c + 6*int(sqrt(sec(c + d*x))*cos(c + d*x) 
**2*sec(c + d*x)**6,x)*a**3*b**2 + int(sqrt(sec(c + d*x))*sec(c + d*x)**6, 
x)*a**5