Integrand size = 41, antiderivative size = 229 \[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {64 a^3 (165 A+143 B+125 C) \sin (c+d x)}{3465 d \sqrt {a+a \cos (c+d x)}}+\frac {16 a^2 (165 A+143 B+125 C) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{3465 d}+\frac {2 a (165 A+143 B+125 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{1155 d}+\frac {2 (99 A-22 B+26 C) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{693 d}+\frac {2 C \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{11 d}+\frac {2 (11 B+5 C) (a+a \cos (c+d x))^{7/2} \sin (c+d x)}{99 a d} \] Output:
64/3465*a^3*(165*A+143*B+125*C)*sin(d*x+c)/d/(a+a*cos(d*x+c))^(1/2)+16/346 5*a^2*(165*A+143*B+125*C)*(a+a*cos(d*x+c))^(1/2)*sin(d*x+c)/d+2/1155*a*(16 5*A+143*B+125*C)*(a+a*cos(d*x+c))^(3/2)*sin(d*x+c)/d+2/693*(99*A-22*B+26*C )*(a+a*cos(d*x+c))^(5/2)*sin(d*x+c)/d+2/11*C*cos(d*x+c)^2*(a+a*cos(d*x+c)) ^(5/2)*sin(d*x+c)/d+2/99*(11*B+5*C)*(a+a*cos(d*x+c))^(7/2)*sin(d*x+c)/a/d
Time = 1.21 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.64 \[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {a^2 \sqrt {a (1+\cos (c+d x))} (137280 A+124366 B+114640 C+(66660 A+68552 B+69890 C) \cos (c+d x)+16 (990 A+1397 B+1625 C) \cos (2 (c+d x))+1980 A \cos (3 (c+d x))+5720 B \cos (3 (c+d x))+8675 C \cos (3 (c+d x))+770 B \cos (4 (c+d x))+2240 C \cos (4 (c+d x))+315 C \cos (5 (c+d x))) \tan \left (\frac {1}{2} (c+d x)\right )}{27720 d} \] Input:
Integrate[Cos[c + d*x]*(a + a*Cos[c + d*x])^(5/2)*(A + B*Cos[c + d*x] + C* Cos[c + d*x]^2),x]
Output:
(a^2*Sqrt[a*(1 + Cos[c + d*x])]*(137280*A + 124366*B + 114640*C + (66660*A + 68552*B + 69890*C)*Cos[c + d*x] + 16*(990*A + 1397*B + 1625*C)*Cos[2*(c + d*x)] + 1980*A*Cos[3*(c + d*x)] + 5720*B*Cos[3*(c + d*x)] + 8675*C*Cos[ 3*(c + d*x)] + 770*B*Cos[4*(c + d*x)] + 2240*C*Cos[4*(c + d*x)] + 315*C*Co s[5*(c + d*x)])*Tan[(c + d*x)/2])/(27720*d)
Time = 1.28 (sec) , antiderivative size = 237, normalized size of antiderivative = 1.03, number of steps used = 16, number of rules used = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.390, Rules used = {3042, 3524, 27, 3042, 3447, 3042, 3502, 27, 3042, 3230, 3042, 3126, 3042, 3126, 3042, 3125}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \cos (c+d x) (a \cos (c+d x)+a)^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \sin \left (c+d x+\frac {\pi }{2}\right ) \left (a \sin \left (c+d x+\frac {\pi }{2}\right )+a\right )^{5/2} \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )+C \sin \left (c+d x+\frac {\pi }{2}\right )^2\right )dx\) |
| \(\Big \downarrow \) 3524 |
| \(\displaystyle \frac {2 \int \frac {1}{2} \cos (c+d x) (\cos (c+d x) a+a)^{5/2} (a (11 A+4 C)+a (11 B+5 C) \cos (c+d x))dx}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\int \cos (c+d x) (\cos (c+d x) a+a)^{5/2} (a (11 A+4 C)+a (11 B+5 C) \cos (c+d x))dx}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \sin \left (c+d x+\frac {\pi }{2}\right ) \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{5/2} \left (a (11 A+4 C)+a (11 B+5 C) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3447 |
| \(\displaystyle \frac {\int (\cos (c+d x) a+a)^{5/2} \left (a (11 B+5 C) \cos ^2(c+d x)+a (11 A+4 C) \cos (c+d x)\right )dx}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{5/2} \left (a (11 B+5 C) \sin \left (c+d x+\frac {\pi }{2}\right )^2+a (11 A+4 C) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3502 |
| \(\displaystyle \frac {\frac {2 \int \frac {1}{2} (\cos (c+d x) a+a)^{5/2} \left (7 (11 B+5 C) a^2+(99 A-22 B+26 C) \cos (c+d x) a^2\right )dx}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\frac {\int (\cos (c+d x) a+a)^{5/2} \left (7 (11 B+5 C) a^2+(99 A-22 B+26 C) \cos (c+d x) a^2\right )dx}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{5/2} \left (7 (11 B+5 C) a^2+(99 A-22 B+26 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^2\right )dx}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3230 |
| \(\displaystyle \frac {\frac {\frac {3}{7} a^2 (165 A+143 B+125 C) \int (\cos (c+d x) a+a)^{5/2}dx+\frac {2 a^2 (99 A-22 B+26 C) \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {3}{7} a^2 (165 A+143 B+125 C) \int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{5/2}dx+\frac {2 a^2 (99 A-22 B+26 C) \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3126 |
| \(\displaystyle \frac {\frac {\frac {3}{7} a^2 (165 A+143 B+125 C) \left (\frac {8}{5} a \int (\cos (c+d x) a+a)^{3/2}dx+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )+\frac {2 a^2 (99 A-22 B+26 C) \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {3}{7} a^2 (165 A+143 B+125 C) \left (\frac {8}{5} a \int \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^{3/2}dx+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )+\frac {2 a^2 (99 A-22 B+26 C) \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3126 |
| \(\displaystyle \frac {\frac {\frac {3}{7} a^2 (165 A+143 B+125 C) \left (\frac {8}{5} a \left (\frac {4}{3} a \int \sqrt {\cos (c+d x) a+a}dx+\frac {2 a \sin (c+d x) \sqrt {a \cos (c+d x)+a}}{3 d}\right )+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )+\frac {2 a^2 (99 A-22 B+26 C) \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {3}{7} a^2 (165 A+143 B+125 C) \left (\frac {8}{5} a \left (\frac {4}{3} a \int \sqrt {\sin \left (c+d x+\frac {\pi }{2}\right ) a+a}dx+\frac {2 a \sin (c+d x) \sqrt {a \cos (c+d x)+a}}{3 d}\right )+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )+\frac {2 a^2 (99 A-22 B+26 C) \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
| \(\Big \downarrow \) 3125 |
| \(\displaystyle \frac {\frac {\frac {2 a^2 (99 A-22 B+26 C) \sin (c+d x) (a \cos (c+d x)+a)^{5/2}}{7 d}+\frac {3}{7} a^2 (165 A+143 B+125 C) \left (\frac {8}{5} a \left (\frac {8 a^2 \sin (c+d x)}{3 d \sqrt {a \cos (c+d x)+a}}+\frac {2 a \sin (c+d x) \sqrt {a \cos (c+d x)+a}}{3 d}\right )+\frac {2 a \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{5 d}\right )}{9 a}+\frac {2 (11 B+5 C) \sin (c+d x) (a \cos (c+d x)+a)^{7/2}}{9 d}}{11 a}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a \cos (c+d x)+a)^{5/2}}{11 d}\) |
Input:
Int[Cos[c + d*x]*(a + a*Cos[c + d*x])^(5/2)*(A + B*Cos[c + d*x] + C*Cos[c + d*x]^2),x]
Output:
(2*C*Cos[c + d*x]^2*(a + a*Cos[c + d*x])^(5/2)*Sin[c + d*x])/(11*d) + ((2* (11*B + 5*C)*(a + a*Cos[c + d*x])^(7/2)*Sin[c + d*x])/(9*d) + ((2*a^2*(99* A - 22*B + 26*C)*(a + a*Cos[c + d*x])^(5/2)*Sin[c + d*x])/(7*d) + (3*a^2*( 165*A + 143*B + 125*C)*((2*a*(a + a*Cos[c + d*x])^(3/2)*Sin[c + d*x])/(5*d ) + (8*a*((8*a^2*Sin[c + d*x])/(3*d*Sqrt[a + a*Cos[c + d*x]]) + (2*a*Sqrt[ a + a*Cos[c + d*x]]*Sin[c + d*x])/(3*d)))/5))/7)/(9*a))/(11*a)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[-2*b*(Cos [c + d*x]/(d*Sqrt[a + b*Sin[c + d*x]])), x] /; FreeQ[{a, b, c, d}, x] && Eq Q[a^2 - b^2, 0]
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos [c + d*x]*((a + b*Sin[c + d*x])^(n - 1)/(d*n)), x] + Simp[a*((2*n - 1)/n) Int[(a + b*Sin[c + d*x])^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && EqQ[ a^2 - b^2, 0] && IGtQ[n - 1/2, 0]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-d)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/( f*(m + 1))), x] + Simp[(a*d*m + b*c*(m + 1))/(b*(m + 1)) Int[(a + b*Sin[e + f*x])^m, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && !LtQ[m, -2^(-1)]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Int[(a + b*Sin[e + f*x])^m*(A*c + (B*c + A*d)*Sin[e + f*x] + B*d*Sin[e + f*x]^2), x] /; FreeQ[{a, b, c, d, e, f, A, B, m}, x] && NeQ[b*c - a*d, 0]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m + 2)) Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] && !LtQ[m, -1]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_. ) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Cos[e + f*x]*(a + b*Sin[e + f*x] )^m*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(m + n + 2))), x] + Simp[1/(b*d*(m + n + 2)) Int[(a + b*Sin[e + f*x])^m*(c + d*Sin[e + f*x])^n*Simp[A*b*d*(m + n + 2) + C*(a*c*m + b*d*(n + 1)) + (C*(a*d*m - b*c*(m + 1)) + b*B*d*(m + n + 2))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, m, n} , x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && !Lt Q[m, -2^(-1)] && NeQ[m + n + 2, 0]
Time = 14.90 (sec) , antiderivative size = 154, normalized size of antiderivative = 0.67
| method | result | size |
| default | \(\frac {8 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (-2520 C \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}+\left (1540 B +10780 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}+\left (-990 A -5940 B -18810 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+\left (3465 A +9009 B +17325 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+\left (-4620 A -6930 B -9240 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+3465 A +3465 B +3465 C \right ) \sqrt {2}}{3465 \sqrt {a \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\, d}\) | \(154\) |
| parts | \(\frac {8 A \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (6 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+3 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+4 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+8\right ) \sqrt {2}}{21 \sqrt {a \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\, d}+\frac {8 B \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (140 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}-20 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+39 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+52 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+104\right ) \sqrt {2}}{315 \sqrt {a \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\, d}+\frac {8 C \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (504 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}-364 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}+178 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+75 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+100 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+200\right ) \sqrt {2}}{693 \sqrt {a \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\, d}\) | \(299\) |
Input:
int(cos(d*x+c)*(a+a*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x,me thod=_RETURNVERBOSE)
Output:
8/3465*cos(1/2*d*x+1/2*c)*a^3*sin(1/2*d*x+1/2*c)*(-2520*C*sin(1/2*d*x+1/2* c)^10+(1540*B+10780*C)*sin(1/2*d*x+1/2*c)^8+(-990*A-5940*B-18810*C)*sin(1/ 2*d*x+1/2*c)^6+(3465*A+9009*B+17325*C)*sin(1/2*d*x+1/2*c)^4+(-4620*A-6930* B-9240*C)*sin(1/2*d*x+1/2*c)^2+3465*A+3465*B+3465*C)*2^(1/2)/(a*cos(1/2*d* x+1/2*c)^2)^(1/2)/d
Time = 0.08 (sec) , antiderivative size = 148, normalized size of antiderivative = 0.65 \[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {2 \, {\left (315 \, C a^{2} \cos \left (d x + c\right )^{5} + 35 \, {\left (11 \, B + 32 \, C\right )} a^{2} \cos \left (d x + c\right )^{4} + 5 \, {\left (99 \, A + 286 \, B + 355 \, C\right )} a^{2} \cos \left (d x + c\right )^{3} + 3 \, {\left (660 \, A + 803 \, B + 710 \, C\right )} a^{2} \cos \left (d x + c\right )^{2} + {\left (3795 \, A + 3212 \, B + 2840 \, C\right )} a^{2} \cos \left (d x + c\right ) + 2 \, {\left (3795 \, A + 3212 \, B + 2840 \, C\right )} a^{2}\right )} \sqrt {a \cos \left (d x + c\right ) + a} \sin \left (d x + c\right )}{3465 \, {\left (d \cos \left (d x + c\right ) + d\right )}} \] Input:
integrate(cos(d*x+c)*(a+a*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)+C*cos(d*x+c)^2 ),x, algorithm="fricas")
Output:
2/3465*(315*C*a^2*cos(d*x + c)^5 + 35*(11*B + 32*C)*a^2*cos(d*x + c)^4 + 5 *(99*A + 286*B + 355*C)*a^2*cos(d*x + c)^3 + 3*(660*A + 803*B + 710*C)*a^2 *cos(d*x + c)^2 + (3795*A + 3212*B + 2840*C)*a^2*cos(d*x + c) + 2*(3795*A + 3212*B + 2840*C)*a^2)*sqrt(a*cos(d*x + c) + a)*sin(d*x + c)/(d*cos(d*x + c) + d)
Timed out. \[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\text {Timed out} \] Input:
integrate(cos(d*x+c)*(a+a*cos(d*x+c))**(5/2)*(A+B*cos(d*x+c)+C*cos(d*x+c)* *2),x)
Output:
Timed out
Time = 0.35 (sec) , antiderivative size = 282, normalized size of antiderivative = 1.23 \[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {660 \, {\left (3 \, \sqrt {2} a^{2} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 21 \, \sqrt {2} a^{2} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 77 \, \sqrt {2} a^{2} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 315 \, \sqrt {2} a^{2} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} A \sqrt {a} + 22 \, {\left (35 \, \sqrt {2} a^{2} \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 225 \, \sqrt {2} a^{2} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 756 \, \sqrt {2} a^{2} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 2100 \, \sqrt {2} a^{2} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 8190 \, \sqrt {2} a^{2} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} B \sqrt {a} + 5 \, {\left (63 \, \sqrt {2} a^{2} \sin \left (\frac {11}{2} \, d x + \frac {11}{2} \, c\right ) + 385 \, \sqrt {2} a^{2} \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 1287 \, \sqrt {2} a^{2} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 3465 \, \sqrt {2} a^{2} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 8778 \, \sqrt {2} a^{2} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 31878 \, \sqrt {2} a^{2} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} C \sqrt {a}}{55440 \, d} \] Input:
integrate(cos(d*x+c)*(a+a*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)+C*cos(d*x+c)^2 ),x, algorithm="maxima")
Output:
1/55440*(660*(3*sqrt(2)*a^2*sin(7/2*d*x + 7/2*c) + 21*sqrt(2)*a^2*sin(5/2* d*x + 5/2*c) + 77*sqrt(2)*a^2*sin(3/2*d*x + 3/2*c) + 315*sqrt(2)*a^2*sin(1 /2*d*x + 1/2*c))*A*sqrt(a) + 22*(35*sqrt(2)*a^2*sin(9/2*d*x + 9/2*c) + 225 *sqrt(2)*a^2*sin(7/2*d*x + 7/2*c) + 756*sqrt(2)*a^2*sin(5/2*d*x + 5/2*c) + 2100*sqrt(2)*a^2*sin(3/2*d*x + 3/2*c) + 8190*sqrt(2)*a^2*sin(1/2*d*x + 1/ 2*c))*B*sqrt(a) + 5*(63*sqrt(2)*a^2*sin(11/2*d*x + 11/2*c) + 385*sqrt(2)*a ^2*sin(9/2*d*x + 9/2*c) + 1287*sqrt(2)*a^2*sin(7/2*d*x + 7/2*c) + 3465*sqr t(2)*a^2*sin(5/2*d*x + 5/2*c) + 8778*sqrt(2)*a^2*sin(3/2*d*x + 3/2*c) + 31 878*sqrt(2)*a^2*sin(1/2*d*x + 1/2*c))*C*sqrt(a))/d
Time = 3.62 (sec) , antiderivative size = 321, normalized size of antiderivative = 1.40 \[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {\sqrt {2} {\left (315 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {11}{2} \, d x + \frac {11}{2} \, c\right ) + 385 \, {\left (2 \, B a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 5 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 495 \, {\left (4 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 10 \, B a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 13 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 693 \, {\left (20 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 24 \, B a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 25 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 2310 \, {\left (22 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 20 \, B a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 19 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 6930 \, {\left (30 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 26 \, B a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 23 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \sqrt {a}}{55440 \, d} \] Input:
integrate(cos(d*x+c)*(a+a*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)+C*cos(d*x+c)^2 ),x, algorithm="giac")
Output:
1/55440*sqrt(2)*(315*C*a^2*sgn(cos(1/2*d*x + 1/2*c))*sin(11/2*d*x + 11/2*c ) + 385*(2*B*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 5*C*a^2*sgn(cos(1/2*d*x + 1/2 *c)))*sin(9/2*d*x + 9/2*c) + 495*(4*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 10*B *a^2*sgn(cos(1/2*d*x + 1/2*c)) + 13*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(7 /2*d*x + 7/2*c) + 693*(20*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 24*B*a^2*sgn(c os(1/2*d*x + 1/2*c)) + 25*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(5/2*d*x + 5 /2*c) + 2310*(22*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 20*B*a^2*sgn(cos(1/2*d* x + 1/2*c)) + 19*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(3/2*d*x + 3/2*c) + 6 930*(30*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 26*B*a^2*sgn(cos(1/2*d*x + 1/2*c )) + 23*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(1/2*d*x + 1/2*c))*sqrt(a)/d
Timed out. \[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\int \cos \left (c+d\,x\right )\,{\left (a+a\,\cos \left (c+d\,x\right )\right )}^{5/2}\,\left (C\,{\cos \left (c+d\,x\right )}^2+B\,\cos \left (c+d\,x\right )+A\right ) \,d x \] Input:
int(cos(c + d*x)*(a + a*cos(c + d*x))^(5/2)*(A + B*cos(c + d*x) + C*cos(c + d*x)^2),x)
Output:
int(cos(c + d*x)*(a + a*cos(c + d*x))^(5/2)*(A + B*cos(c + d*x) + C*cos(c + d*x)^2), x)
\[ \int \cos (c+d x) (a+a \cos (c+d x))^{5/2} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\sqrt {a}\, a^{2} \left (\left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )d x \right ) a +\left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{5}d x \right ) c +\left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{4}d x \right ) b +2 \left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{4}d x \right ) c +\left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{3}d x \right ) a +2 \left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{3}d x \right ) b +\left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{3}d x \right ) c +2 \left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{2}d x \right ) a +\left (\int \sqrt {\cos \left (d x +c \right )+1}\, \cos \left (d x +c \right )^{2}d x \right ) b \right ) \] Input:
int(cos(d*x+c)*(a+a*cos(d*x+c))^(5/2)*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x)
Output:
sqrt(a)*a**2*(int(sqrt(cos(c + d*x) + 1)*cos(c + d*x),x)*a + int(sqrt(cos( c + d*x) + 1)*cos(c + d*x)**5,x)*c + int(sqrt(cos(c + d*x) + 1)*cos(c + d* x)**4,x)*b + 2*int(sqrt(cos(c + d*x) + 1)*cos(c + d*x)**4,x)*c + int(sqrt( cos(c + d*x) + 1)*cos(c + d*x)**3,x)*a + 2*int(sqrt(cos(c + d*x) + 1)*cos( c + d*x)**3,x)*b + int(sqrt(cos(c + d*x) + 1)*cos(c + d*x)**3,x)*c + 2*int (sqrt(cos(c + d*x) + 1)*cos(c + d*x)**2,x)*a + int(sqrt(cos(c + d*x) + 1)* cos(c + d*x)**2,x)*b)