\(\int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 (A+B \cos (c+d x)+C \cos ^2(c+d x)) \, dx\) [447]

Optimal result
Mathematica [C] (warning: unable to verify)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [C] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [B] (verification not implemented)
Reduce [F]

Optimal result

Integrand size = 43, antiderivative size = 303 \[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {4 a^3 (221 A+195 B+175 C) E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{195 d}+\frac {4 a^3 (121 A+105 B+95 C) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{231 d}+\frac {4 a^3 (121 A+105 B+95 C) \sqrt {\cos (c+d x)} \sin (c+d x)}{231 d}+\frac {4 a^3 (221 A+195 B+175 C) \cos ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{585 d}+\frac {20 a^3 (286 A+273 B+236 C) \cos ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{9009 d}+\frac {2 C \cos ^{\frac {5}{2}}(c+d x) (a+a \cos (c+d x))^3 \sin (c+d x)}{13 d}+\frac {2 (13 B+6 C) \cos ^{\frac {5}{2}}(c+d x) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{143 a d}+\frac {2 (143 A+195 B+145 C) \cos ^{\frac {5}{2}}(c+d x) \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{1287 d} \] Output:

4/195*a^3*(221*A+195*B+175*C)*EllipticE(sin(1/2*d*x+1/2*c),2^(1/2))/d+4/23 
1*a^3*(121*A+105*B+95*C)*InverseJacobiAM(1/2*d*x+1/2*c,2^(1/2))/d+4/231*a^ 
3*(121*A+105*B+95*C)*cos(d*x+c)^(1/2)*sin(d*x+c)/d+4/585*a^3*(221*A+195*B+ 
175*C)*cos(d*x+c)^(3/2)*sin(d*x+c)/d+20/9009*a^3*(286*A+273*B+236*C)*cos(d 
*x+c)^(5/2)*sin(d*x+c)/d+2/13*C*cos(d*x+c)^(5/2)*(a+a*cos(d*x+c))^3*sin(d* 
x+c)/d+2/143*(13*B+6*C)*cos(d*x+c)^(5/2)*(a^2+a^2*cos(d*x+c))^2*sin(d*x+c) 
/a/d+2/1287*(143*A+195*B+145*C)*cos(d*x+c)^(5/2)*(a^3+a^3*cos(d*x+c))*sin( 
d*x+c)/d
                                                                                    
                                                                                    
 

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 7.57 (sec) , antiderivative size = 1426, normalized size of antiderivative = 4.71 \[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx =\text {Too large to display} \] Input:

Integrate[Cos[c + d*x]^(3/2)*(a + a*Cos[c + d*x])^3*(A + B*Cos[c + d*x] + 
C*Cos[c + d*x]^2),x]
 

Output:

Sqrt[Cos[c + d*x]]*(a + a*Cos[c + d*x])^3*Sec[c/2 + (d*x)/2]^6*(-1/390*((2 
21*A + 195*B + 175*C)*Cot[c])/d + ((2134*A + 1953*B + 1811*C)*Cos[d*x]*Sin 
[c])/(7392*d) + ((7592*A + 7800*B + 7825*C)*Cos[2*d*x]*Sin[2*c])/(74880*d) 
 + ((132*A + 189*B + 215*C)*Cos[3*d*x]*Sin[3*c])/(4928*d) + ((13*A + 39*B 
+ 59*C)*Cos[4*d*x]*Sin[4*c])/(3744*d) + ((B + 3*C)*Cos[5*d*x]*Sin[5*c])/(7 
04*d) + (C*Cos[6*d*x]*Sin[6*c])/(1664*d) + ((2134*A + 1953*B + 1811*C)*Cos 
[c]*Sin[d*x])/(7392*d) + ((7592*A + 7800*B + 7825*C)*Cos[2*c]*Sin[2*d*x])/ 
(74880*d) + ((132*A + 189*B + 215*C)*Cos[3*c]*Sin[3*d*x])/(4928*d) + ((13* 
A + 39*B + 59*C)*Cos[4*c]*Sin[4*d*x])/(3744*d) + ((B + 3*C)*Cos[5*c]*Sin[5 
*d*x])/(704*d) + (C*Cos[6*c]*Sin[6*d*x])/(1664*d)) - (11*A*(a + a*Cos[c + 
d*x])^3*Csc[c]*HypergeometricPFQ[{1/4, 1/2}, {5/4}, Sin[d*x - ArcTan[Cot[c 
]]]^2]*Sec[c/2 + (d*x)/2]^6*Sec[d*x - ArcTan[Cot[c]]]*Sqrt[1 - Sin[d*x - A 
rcTan[Cot[c]]]]*Sqrt[-(Sqrt[1 + Cot[c]^2]*Sin[c]*Sin[d*x - ArcTan[Cot[c]]] 
)]*Sqrt[1 + Sin[d*x - ArcTan[Cot[c]]]])/(42*d*Sqrt[1 + Cot[c]^2]) - (5*B*( 
a + a*Cos[c + d*x])^3*Csc[c]*HypergeometricPFQ[{1/4, 1/2}, {5/4}, Sin[d*x 
- ArcTan[Cot[c]]]^2]*Sec[c/2 + (d*x)/2]^6*Sec[d*x - ArcTan[Cot[c]]]*Sqrt[1 
 - Sin[d*x - ArcTan[Cot[c]]]]*Sqrt[-(Sqrt[1 + Cot[c]^2]*Sin[c]*Sin[d*x - A 
rcTan[Cot[c]]])]*Sqrt[1 + Sin[d*x - ArcTan[Cot[c]]]])/(22*d*Sqrt[1 + Cot[c 
]^2]) - (95*C*(a + a*Cos[c + d*x])^3*Csc[c]*HypergeometricPFQ[{1/4, 1/2}, 
{5/4}, Sin[d*x - ArcTan[Cot[c]]]^2]*Sec[c/2 + (d*x)/2]^6*Sec[d*x - ArcT...
 

Rubi [A] (verified)

Time = 1.90 (sec) , antiderivative size = 303, normalized size of antiderivative = 1.00, number of steps used = 20, number of rules used = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.465, Rules used = {3042, 3524, 27, 3042, 3455, 27, 3042, 3455, 3042, 3447, 3042, 3502, 27, 3042, 3227, 3042, 3115, 3042, 3119, 3120}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cos ^{\frac {3}{2}}(c+d x) (a \cos (c+d x)+a)^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \sin \left (c+d x+\frac {\pi }{2}\right )^{3/2} \left (a \sin \left (c+d x+\frac {\pi }{2}\right )+a\right )^3 \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )+C \sin \left (c+d x+\frac {\pi }{2}\right )^2\right )dx\)

\(\Big \downarrow \) 3524

\(\displaystyle \frac {2 \int \frac {1}{2} \cos ^{\frac {3}{2}}(c+d x) (\cos (c+d x) a+a)^3 (a (13 A+5 C)+a (13 B+6 C) \cos (c+d x))dx}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \cos ^{\frac {3}{2}}(c+d x) (\cos (c+d x) a+a)^3 (a (13 A+5 C)+a (13 B+6 C) \cos (c+d x))dx}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \sin \left (c+d x+\frac {\pi }{2}\right )^{3/2} \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^3 \left (a (13 A+5 C)+a (13 B+6 C) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3455

\(\displaystyle \frac {\frac {2}{11} \int \frac {1}{2} \cos ^{\frac {3}{2}}(c+d x) (\cos (c+d x) a+a)^2 \left ((143 A+65 B+85 C) a^2+(143 A+195 B+145 C) \cos (c+d x) a^2\right )dx+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {1}{11} \int \cos ^{\frac {3}{2}}(c+d x) (\cos (c+d x) a+a)^2 \left ((143 A+65 B+85 C) a^2+(143 A+195 B+145 C) \cos (c+d x) a^2\right )dx+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{11} \int \sin \left (c+d x+\frac {\pi }{2}\right )^{3/2} \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^2 \left ((143 A+65 B+85 C) a^2+(143 A+195 B+145 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^2\right )dx+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3455

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \int \cos ^{\frac {3}{2}}(c+d x) (\cos (c+d x) a+a) \left ((1001 A+780 B+745 C) a^3+5 (286 A+273 B+236 C) \cos (c+d x) a^3\right )dx+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \int \sin \left (c+d x+\frac {\pi }{2}\right )^{3/2} \left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right ) \left ((1001 A+780 B+745 C) a^3+5 (286 A+273 B+236 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^3\right )dx+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3447

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \int \cos ^{\frac {3}{2}}(c+d x) \left (5 (286 A+273 B+236 C) \cos ^2(c+d x) a^4+(1001 A+780 B+745 C) a^4+\left (5 (286 A+273 B+236 C) a^4+(1001 A+780 B+745 C) a^4\right ) \cos (c+d x)\right )dx+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \int \sin \left (c+d x+\frac {\pi }{2}\right )^{3/2} \left (5 (286 A+273 B+236 C) \sin \left (c+d x+\frac {\pi }{2}\right )^2 a^4+(1001 A+780 B+745 C) a^4+\left (5 (286 A+273 B+236 C) a^4+(1001 A+780 B+745 C) a^4\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3502

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {2}{7} \int \frac {1}{2} \cos ^{\frac {3}{2}}(c+d x) \left (117 (121 A+105 B+95 C) a^4+77 (221 A+195 B+175 C) \cos (c+d x) a^4\right )dx+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {1}{7} \int \cos ^{\frac {3}{2}}(c+d x) \left (117 (121 A+105 B+95 C) a^4+77 (221 A+195 B+175 C) \cos (c+d x) a^4\right )dx+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {1}{7} \int \sin \left (c+d x+\frac {\pi }{2}\right )^{3/2} \left (117 (121 A+105 B+95 C) a^4+77 (221 A+195 B+175 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^4\right )dx+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3227

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {1}{7} \left (117 a^4 (121 A+105 B+95 C) \int \cos ^{\frac {3}{2}}(c+d x)dx+77 a^4 (221 A+195 B+175 C) \int \cos ^{\frac {5}{2}}(c+d x)dx\right )+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {1}{7} \left (117 a^4 (121 A+105 B+95 C) \int \sin \left (c+d x+\frac {\pi }{2}\right )^{3/2}dx+77 a^4 (221 A+195 B+175 C) \int \sin \left (c+d x+\frac {\pi }{2}\right )^{5/2}dx\right )+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3115

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {1}{7} \left (77 a^4 (221 A+195 B+175 C) \left (\frac {3}{5} \int \sqrt {\cos (c+d x)}dx+\frac {2 \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x)}{5 d}\right )+117 a^4 (121 A+105 B+95 C) \left (\frac {1}{3} \int \frac {1}{\sqrt {\cos (c+d x)}}dx+\frac {2 \sin (c+d x) \sqrt {\cos (c+d x)}}{3 d}\right )\right )+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {1}{7} \left (77 a^4 (221 A+195 B+175 C) \left (\frac {3}{5} \int \sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}dx+\frac {2 \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x)}{5 d}\right )+117 a^4 (121 A+105 B+95 C) \left (\frac {1}{3} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx+\frac {2 \sin (c+d x) \sqrt {\cos (c+d x)}}{3 d}\right )\right )+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3119

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2}{9} \left (\frac {1}{7} \left (117 a^4 (121 A+105 B+95 C) \left (\frac {1}{3} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx+\frac {2 \sin (c+d x) \sqrt {\cos (c+d x)}}{3 d}\right )+77 a^4 (221 A+195 B+175 C) \left (\frac {6 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{5 d}+\frac {2 \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x)}{5 d}\right )\right )+\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}\right )+\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

\(\Big \downarrow \) 3120

\(\displaystyle \frac {\frac {1}{11} \left (\frac {2 (143 A+195 B+145 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{9 d}+\frac {2}{9} \left (\frac {10 a^4 (286 A+273 B+236 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x)}{7 d}+\frac {1}{7} \left (77 a^4 (221 A+195 B+175 C) \left (\frac {6 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{5 d}+\frac {2 \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x)}{5 d}\right )+117 a^4 (121 A+105 B+95 C) \left (\frac {2 \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{3 d}+\frac {2 \sin (c+d x) \sqrt {\cos (c+d x)}}{3 d}\right )\right )\right )\right )+\frac {2 (13 B+6 C) \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{11 d}}{13 a}+\frac {2 C \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) (a \cos (c+d x)+a)^3}{13 d}\)

Input:

Int[Cos[c + d*x]^(3/2)*(a + a*Cos[c + d*x])^3*(A + B*Cos[c + d*x] + C*Cos[ 
c + d*x]^2),x]
 

Output:

(2*C*Cos[c + d*x]^(5/2)*(a + a*Cos[c + d*x])^3*Sin[c + d*x])/(13*d) + ((2* 
(13*B + 6*C)*Cos[c + d*x]^(5/2)*(a^2 + a^2*Cos[c + d*x])^2*Sin[c + d*x])/( 
11*d) + ((2*(143*A + 195*B + 145*C)*Cos[c + d*x]^(5/2)*(a^4 + a^4*Cos[c + 
d*x])*Sin[c + d*x])/(9*d) + (2*((10*a^4*(286*A + 273*B + 236*C)*Cos[c + d* 
x]^(5/2)*Sin[c + d*x])/(7*d) + (117*a^4*(121*A + 105*B + 95*C)*((2*Ellipti 
cF[(c + d*x)/2, 2])/(3*d) + (2*Sqrt[Cos[c + d*x]]*Sin[c + d*x])/(3*d)) + 7 
7*a^4*(221*A + 195*B + 175*C)*((6*EllipticE[(c + d*x)/2, 2])/(5*d) + (2*Co 
s[c + d*x]^(3/2)*Sin[c + d*x])/(5*d)))/7))/9)/11)/(13*a)
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3115
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos[c + d* 
x]*((b*Sin[c + d*x])^(n - 1)/(d*n)), x] + Simp[b^2*((n - 1)/n)   Int[(b*Sin 
[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && IntegerQ[ 
2*n]
 

rule 3119
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* 
(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3120
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 
)*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3227
Int[((b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*sin[(e_.) + (f_.)*(x 
_)]), x_Symbol] :> Simp[c   Int[(b*Sin[e + f*x])^m, x], x] + Simp[d/b   Int 
[(b*Sin[e + f*x])^(m + 1), x], x] /; FreeQ[{b, c, d, e, f, m}, x]
 

rule 3447
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) 
+ (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Int[(a 
 + b*Sin[e + f*x])^m*(A*c + (B*c + A*d)*Sin[e + f*x] + B*d*Sin[e + f*x]^2), 
 x] /; FreeQ[{a, b, c, d, e, f, A, B, m}, x] && NeQ[b*c - a*d, 0]
 

rule 3455
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + 
(f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Sim 
p[(-b)*B*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*((c + d*Sin[e + f*x])^(n 
 + 1)/(d*f*(m + n + 1))), x] + Simp[1/(d*(m + n + 1))   Int[(a + b*Sin[e + 
f*x])^(m - 1)*(c + d*Sin[e + f*x])^n*Simp[a*A*d*(m + n + 1) + B*(a*c*(m - 1 
) + b*d*(n + 1)) + (A*b*d*(m + n + 1) - B*(b*c*m - a*d*(2*m + n)))*Sin[e + 
f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c - a*d, 
 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 1/2] &&  !LtQ[n, -1 
] && IntegerQ[2*m] && (IntegerQ[2*n] || EqQ[c, 0])
 

rule 3502
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) 
+ (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co 
s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m 
+ 2))   Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m 
 + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] 
 &&  !LtQ[m, -1]
 

rule 3524
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])^(n_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_. 
) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Cos[e + f*x]*(a + b*Sin[e + f*x] 
)^m*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(m + n + 2))), x] + Simp[1/(b*d*(m + 
 n + 2))   Int[(a + b*Sin[e + f*x])^m*(c + d*Sin[e + f*x])^n*Simp[A*b*d*(m 
+ n + 2) + C*(a*c*m + b*d*(n + 1)) + (C*(a*d*m - b*c*(m + 1)) + b*B*d*(m + 
n + 2))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, m, n} 
, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !Lt 
Q[m, -2^(-1)] && NeQ[m + n + 2, 0]
 
Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(575\) vs. \(2(278)=556\).

Time = 45.36 (sec) , antiderivative size = 576, normalized size of antiderivative = 1.90

method result size
default \(-\frac {4 \sqrt {\left (-1+2 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\, a^{3} \left (-221760 C \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{14}+\left (131040 B +1058400 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{12} \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+\left (-80080 A -567840 B -2122400 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{10} \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+\left (314600 A +1004640 B +2331040 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{8} \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+\left (-487916 A -939120 B -1535860 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{6} \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+\left (386386 A +510510 B +633710 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+\left (-105534 A -114660 B -121230 C \right ) \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+23595 A \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1}\, \operatorname {EllipticF}\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )-51051 A \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1}\, \operatorname {EllipticE}\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+20475 B \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1}\, \operatorname {EllipticF}\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )-45045 B \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1}\, \operatorname {EllipticE}\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+18525 C \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1}\, \operatorname {EllipticF}\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )-40425 C \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1}\, \operatorname {EllipticE}\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )\right )}{45045 \sqrt {-2 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+\sin \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-1+2 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\, d}\) \(576\)
parts \(\text {Expression too large to display}\) \(1319\)

Input:

int(cos(d*x+c)^(3/2)*(a+a*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x, 
method=_RETURNVERBOSE)
 

Output:

-4/45045*((-1+2*cos(1/2*d*x+1/2*c)^2)*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^3*(-22 
1760*C*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1/2*c)^14+(131040*B+1058400*C)*sin(1 
/2*d*x+1/2*c)^12*cos(1/2*d*x+1/2*c)+(-80080*A-567840*B-2122400*C)*sin(1/2* 
d*x+1/2*c)^10*cos(1/2*d*x+1/2*c)+(314600*A+1004640*B+2331040*C)*sin(1/2*d* 
x+1/2*c)^8*cos(1/2*d*x+1/2*c)+(-487916*A-939120*B-1535860*C)*sin(1/2*d*x+1 
/2*c)^6*cos(1/2*d*x+1/2*c)+(386386*A+510510*B+633710*C)*sin(1/2*d*x+1/2*c) 
^4*cos(1/2*d*x+1/2*c)+(-105534*A-114660*B-121230*C)*sin(1/2*d*x+1/2*c)^2*c 
os(1/2*d*x+1/2*c)+23595*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*sin(1/2*d*x+1/2* 
c)^2-1)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),2^(1/2))-51051*A*(sin(1/2*d*x+1 
/2*c)^2)^(1/2)*(2*sin(1/2*d*x+1/2*c)^2-1)^(1/2)*EllipticE(cos(1/2*d*x+1/2* 
c),2^(1/2))+20475*B*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*sin(1/2*d*x+1/2*c)^2-1 
)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),2^(1/2))-45045*B*(sin(1/2*d*x+1/2*c)^ 
2)^(1/2)*(2*sin(1/2*d*x+1/2*c)^2-1)^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),2^( 
1/2))+18525*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*sin(1/2*d*x+1/2*c)^2-1)^(1/2 
)*EllipticF(cos(1/2*d*x+1/2*c),2^(1/2))-40425*C*(sin(1/2*d*x+1/2*c)^2)^(1/ 
2)*(2*sin(1/2*d*x+1/2*c)^2-1)^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),2^(1/2))) 
/(-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d*x+1/2*c)^2)^(1/2)/sin(1/2*d*x+1/2*c)/( 
-1+2*cos(1/2*d*x+1/2*c)^2)^(1/2)/d
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.13 (sec) , antiderivative size = 287, normalized size of antiderivative = 0.95 \[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=-\frac {2 \, {\left (195 i \, \sqrt {2} {\left (121 \, A + 105 \, B + 95 \, C\right )} a^{3} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) - 195 i \, \sqrt {2} {\left (121 \, A + 105 \, B + 95 \, C\right )} a^{3} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) - 231 i \, \sqrt {2} {\left (221 \, A + 195 \, B + 175 \, C\right )} a^{3} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right )\right ) + 231 i \, \sqrt {2} {\left (221 \, A + 195 \, B + 175 \, C\right )} a^{3} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right )\right ) - {\left (3465 \, C a^{3} \cos \left (d x + c\right )^{5} + 4095 \, {\left (B + 3 \, C\right )} a^{3} \cos \left (d x + c\right )^{4} + 385 \, {\left (13 \, A + 39 \, B + 50 \, C\right )} a^{3} \cos \left (d x + c\right )^{3} + 585 \, {\left (33 \, A + 42 \, B + 38 \, C\right )} a^{3} \cos \left (d x + c\right )^{2} + 154 \, {\left (221 \, A + 195 \, B + 175 \, C\right )} a^{3} \cos \left (d x + c\right ) + 390 \, {\left (121 \, A + 105 \, B + 95 \, C\right )} a^{3}\right )} \sqrt {\cos \left (d x + c\right )} \sin \left (d x + c\right )\right )}}{45045 \, d} \] Input:

integrate(cos(d*x+c)^(3/2)*(a+a*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c) 
^2),x, algorithm="fricas")
 

Output:

-2/45045*(195*I*sqrt(2)*(121*A + 105*B + 95*C)*a^3*weierstrassPInverse(-4, 
 0, cos(d*x + c) + I*sin(d*x + c)) - 195*I*sqrt(2)*(121*A + 105*B + 95*C)* 
a^3*weierstrassPInverse(-4, 0, cos(d*x + c) - I*sin(d*x + c)) - 231*I*sqrt 
(2)*(221*A + 195*B + 175*C)*a^3*weierstrassZeta(-4, 0, weierstrassPInverse 
(-4, 0, cos(d*x + c) + I*sin(d*x + c))) + 231*I*sqrt(2)*(221*A + 195*B + 1 
75*C)*a^3*weierstrassZeta(-4, 0, weierstrassPInverse(-4, 0, cos(d*x + c) - 
 I*sin(d*x + c))) - (3465*C*a^3*cos(d*x + c)^5 + 4095*(B + 3*C)*a^3*cos(d* 
x + c)^4 + 385*(13*A + 39*B + 50*C)*a^3*cos(d*x + c)^3 + 585*(33*A + 42*B 
+ 38*C)*a^3*cos(d*x + c)^2 + 154*(221*A + 195*B + 175*C)*a^3*cos(d*x + c) 
+ 390*(121*A + 105*B + 95*C)*a^3)*sqrt(cos(d*x + c))*sin(d*x + c))/d
 

Sympy [F(-1)]

Timed out. \[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\text {Timed out} \] Input:

integrate(cos(d*x+c)**(3/2)*(a+a*cos(d*x+c))**3*(A+B*cos(d*x+c)+C*cos(d*x+ 
c)**2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\int { {\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} {\left (a \cos \left (d x + c\right ) + a\right )}^{3} \cos \left (d x + c\right )^{\frac {3}{2}} \,d x } \] Input:

integrate(cos(d*x+c)^(3/2)*(a+a*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c) 
^2),x, algorithm="maxima")
 

Output:

integrate((C*cos(d*x + c)^2 + B*cos(d*x + c) + A)*(a*cos(d*x + c) + a)^3*c 
os(d*x + c)^(3/2), x)
 

Giac [F]

\[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\int { {\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} {\left (a \cos \left (d x + c\right ) + a\right )}^{3} \cos \left (d x + c\right )^{\frac {3}{2}} \,d x } \] Input:

integrate(cos(d*x+c)^(3/2)*(a+a*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c) 
^2),x, algorithm="giac")
 

Output:

integrate((C*cos(d*x + c)^2 + B*cos(d*x + c) + A)*(a*cos(d*x + c) + a)^3*c 
os(d*x + c)^(3/2), x)
                                                                                    
                                                                                    
 

Mupad [B] (verification not implemented)

Time = 1.22 (sec) , antiderivative size = 544, normalized size of antiderivative = 1.80 \[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx =\text {Too large to display} \] Input:

int(cos(c + d*x)^(3/2)*(a + a*cos(c + d*x))^3*(A + B*cos(c + d*x) + C*cos( 
c + d*x)^2),x)
 

Output:

(A*a^3*((2*cos(c + d*x)^(1/2)*sin(c + d*x))/3 + (2*ellipticF(c/2 + (d*x)/2 
, 2))/3))/d - (6*A*a^3*cos(c + d*x)^(7/2)*sin(c + d*x)*hypergeom([1/2, 7/4 
], 11/4, cos(c + d*x)^2))/(7*d*(sin(c + d*x)^2)^(1/2)) - (2*A*a^3*cos(c + 
d*x)^(9/2)*sin(c + d*x)*hypergeom([1/2, 9/4], 13/4, cos(c + d*x)^2))/(3*d* 
(sin(c + d*x)^2)^(1/2)) - (2*A*a^3*cos(c + d*x)^(11/2)*sin(c + d*x)*hyperg 
eom([1/2, 11/4], 15/4, cos(c + d*x)^2))/(11*d*(sin(c + d*x)^2)^(1/2)) - (2 
*B*a^3*cos(c + d*x)^(7/2)*sin(c + d*x)*hypergeom([1/2, 7/4], 11/4, cos(c + 
 d*x)^2))/(7*d*(sin(c + d*x)^2)^(1/2)) - (2*B*a^3*cos(c + d*x)^(9/2)*sin(c 
 + d*x)*hypergeom([1/2, 9/4], 13/4, cos(c + d*x)^2))/(3*d*(sin(c + d*x)^2) 
^(1/2)) - (6*B*a^3*cos(c + d*x)^(11/2)*sin(c + d*x)*hypergeom([1/2, 11/4], 
 15/4, cos(c + d*x)^2))/(11*d*(sin(c + d*x)^2)^(1/2)) - (2*B*a^3*cos(c + d 
*x)^(13/2)*sin(c + d*x)*hypergeom([1/2, 13/4], 17/4, cos(c + d*x)^2))/(13* 
d*(sin(c + d*x)^2)^(1/2)) - (2*C*a^3*cos(c + d*x)^(9/2)*sin(c + d*x)*hyper 
geom([1/2, 9/4], 13/4, cos(c + d*x)^2))/(9*d*(sin(c + d*x)^2)^(1/2)) - (6* 
C*a^3*cos(c + d*x)^(11/2)*sin(c + d*x)*hypergeom([1/2, 11/4], 15/4, cos(c 
+ d*x)^2))/(11*d*(sin(c + d*x)^2)^(1/2)) - (6*C*a^3*cos(c + d*x)^(13/2)*si 
n(c + d*x)*hypergeom([1/2, 13/4], 17/4, cos(c + d*x)^2))/(13*d*(sin(c + d* 
x)^2)^(1/2)) - (2*C*a^3*cos(c + d*x)^(15/2)*sin(c + d*x)*hypergeom([1/2, 1 
5/4], 19/4, cos(c + d*x)^2))/(15*d*(sin(c + d*x)^2)^(1/2))
 

Reduce [F]

\[ \int \cos ^{\frac {3}{2}}(c+d x) (a+a \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=a^{3} \left (\left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )d x \right ) a +\left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{6}d x \right ) c +\left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{5}d x \right ) b +3 \left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{5}d x \right ) c +\left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{4}d x \right ) a +3 \left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{4}d x \right ) b +3 \left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{4}d x \right ) c +3 \left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{3}d x \right ) a +3 \left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{3}d x \right ) b +\left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{3}d x \right ) c +3 \left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{2}d x \right ) a +\left (\int \sqrt {\cos \left (d x +c \right )}\, \cos \left (d x +c \right )^{2}d x \right ) b \right ) \] Input:

int(cos(d*x+c)^(3/2)*(a+a*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x)
 

Output:

a**3*(int(sqrt(cos(c + d*x))*cos(c + d*x),x)*a + int(sqrt(cos(c + d*x))*co 
s(c + d*x)**6,x)*c + int(sqrt(cos(c + d*x))*cos(c + d*x)**5,x)*b + 3*int(s 
qrt(cos(c + d*x))*cos(c + d*x)**5,x)*c + int(sqrt(cos(c + d*x))*cos(c + d* 
x)**4,x)*a + 3*int(sqrt(cos(c + d*x))*cos(c + d*x)**4,x)*b + 3*int(sqrt(co 
s(c + d*x))*cos(c + d*x)**4,x)*c + 3*int(sqrt(cos(c + d*x))*cos(c + d*x)** 
3,x)*a + 3*int(sqrt(cos(c + d*x))*cos(c + d*x)**3,x)*b + int(sqrt(cos(c + 
d*x))*cos(c + d*x)**3,x)*c + 3*int(sqrt(cos(c + d*x))*cos(c + d*x)**2,x)*a 
 + int(sqrt(cos(c + d*x))*cos(c + d*x)**2,x)*b)