Integrand size = 33, antiderivative size = 277 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {1}{8} \left (12 a^2 b B+3 b^3 B+4 a^3 (2 A+C)+3 a b^2 (4 A+3 C)\right ) x+\frac {\left (15 a^3 b B+60 a b^3 B-3 a^4 C+4 b^4 (5 A+4 C)+4 a^2 b^2 (20 A+13 C)\right ) \sin (c+d x)}{30 b d}+\frac {\left (30 a^2 b B+45 b^3 B-6 a^3 C+a b^2 (100 A+71 C)\right ) \cos (c+d x) \sin (c+d x)}{120 d}+\frac {\left (4 b^2 (5 A+4 C)+3 a (5 b B-a C)\right ) (a+b \cos (c+d x))^2 \sin (c+d x)}{60 b d}+\frac {(5 b B-a C) (a+b \cos (c+d x))^3 \sin (c+d x)}{20 b d}+\frac {C (a+b \cos (c+d x))^4 \sin (c+d x)}{5 b d} \] Output:
1/8*(12*B*a^2*b+3*B*b^3+4*a^3*(2*A+C)+3*a*b^2*(4*A+3*C))*x+1/30*(15*B*a^3* b+60*B*a*b^3-3*a^4*C+4*b^4*(5*A+4*C)+4*a^2*b^2*(20*A+13*C))*sin(d*x+c)/b/d +1/120*(30*B*a^2*b+45*B*b^3-6*a^3*C+a*b^2*(100*A+71*C))*cos(d*x+c)*sin(d*x +c)/d+1/60*(4*b^2*(5*A+4*C)+3*a*(5*B*b-C*a))*(a+b*cos(d*x+c))^2*sin(d*x+c) /b/d+1/20*(5*B*b-C*a)*(a+b*cos(d*x+c))^3*sin(d*x+c)/b/d+1/5*C*(a+b*cos(d*x +c))^4*sin(d*x+c)/b/d
Time = 3.30 (sec) , antiderivative size = 288, normalized size of antiderivative = 1.04 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {480 a^3 A c+720 a A b^2 c+720 a^2 b B c+180 b^3 B c+240 a^3 c C+540 a b^2 c C+480 a^3 A d x+720 a A b^2 d x+720 a^2 b B d x+180 b^3 B d x+240 a^3 C d x+540 a b^2 C d x+60 \left (8 a^3 B+18 a b^2 B+6 a^2 b (4 A+3 C)+b^3 (6 A+5 C)\right ) \sin (c+d x)+120 \left (3 a^2 b B+b^3 B+a^3 C+3 a b^2 (A+C)\right ) \sin (2 (c+d x))+40 A b^3 \sin (3 (c+d x))+120 a b^2 B \sin (3 (c+d x))+120 a^2 b C \sin (3 (c+d x))+50 b^3 C \sin (3 (c+d x))+15 b^3 B \sin (4 (c+d x))+45 a b^2 C \sin (4 (c+d x))+6 b^3 C \sin (5 (c+d x))}{480 d} \] Input:
Integrate[(a + b*Cos[c + d*x])^3*(A + B*Cos[c + d*x] + C*Cos[c + d*x]^2),x ]
Output:
(480*a^3*A*c + 720*a*A*b^2*c + 720*a^2*b*B*c + 180*b^3*B*c + 240*a^3*c*C + 540*a*b^2*c*C + 480*a^3*A*d*x + 720*a*A*b^2*d*x + 720*a^2*b*B*d*x + 180*b ^3*B*d*x + 240*a^3*C*d*x + 540*a*b^2*C*d*x + 60*(8*a^3*B + 18*a*b^2*B + 6* a^2*b*(4*A + 3*C) + b^3*(6*A + 5*C))*Sin[c + d*x] + 120*(3*a^2*b*B + b^3*B + a^3*C + 3*a*b^2*(A + C))*Sin[2*(c + d*x)] + 40*A*b^3*Sin[3*(c + d*x)] + 120*a*b^2*B*Sin[3*(c + d*x)] + 120*a^2*b*C*Sin[3*(c + d*x)] + 50*b^3*C*Si n[3*(c + d*x)] + 15*b^3*B*Sin[4*(c + d*x)] + 45*a*b^2*C*Sin[4*(c + d*x)] + 6*b^3*C*Sin[5*(c + d*x)])/(480*d)
Time = 0.90 (sec) , antiderivative size = 286, normalized size of antiderivative = 1.03, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.242, Rules used = {3042, 3502, 3042, 3232, 3042, 3232, 3042, 3213}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^3 \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )+C \sin \left (c+d x+\frac {\pi }{2}\right )^2\right )dx\) |
| \(\Big \downarrow \) 3502 |
| \(\displaystyle \frac {\int (a+b \cos (c+d x))^3 (b (5 A+4 C)+(5 b B-a C) \cos (c+d x))dx}{5 b}+\frac {C \sin (c+d x) (a+b \cos (c+d x))^4}{5 b d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^3 \left (b (5 A+4 C)+(5 b B-a C) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx}{5 b}+\frac {C \sin (c+d x) (a+b \cos (c+d x))^4}{5 b d}\) |
| \(\Big \downarrow \) 3232 |
| \(\displaystyle \frac {\frac {1}{4} \int (a+b \cos (c+d x))^2 \left (b (20 a A+15 b B+13 a C)+\left (4 (5 A+4 C) b^2+3 a (5 b B-a C)\right ) \cos (c+d x)\right )dx+\frac {(5 b B-a C) \sin (c+d x) (a+b \cos (c+d x))^3}{4 d}}{5 b}+\frac {C \sin (c+d x) (a+b \cos (c+d x))^4}{5 b d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^2 \left (b (20 a A+15 b B+13 a C)+\left (4 (5 A+4 C) b^2+3 a (5 b B-a C)\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx+\frac {(5 b B-a C) \sin (c+d x) (a+b \cos (c+d x))^3}{4 d}}{5 b}+\frac {C \sin (c+d x) (a+b \cos (c+d x))^4}{5 b d}\) |
| \(\Big \downarrow \) 3232 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {1}{3} \int (a+b \cos (c+d x)) \left (b \left ((60 A+33 C) a^2+75 b B a+8 b^2 (5 A+4 C)\right )+\left (-6 C a^3+30 b B a^2+b^2 (100 A+71 C) a+45 b^3 B\right ) \cos (c+d x)\right )dx+\frac {\sin (c+d x) \left (3 a (5 b B-a C)+4 b^2 (5 A+4 C)\right ) (a+b \cos (c+d x))^2}{3 d}\right )+\frac {(5 b B-a C) \sin (c+d x) (a+b \cos (c+d x))^3}{4 d}}{5 b}+\frac {C \sin (c+d x) (a+b \cos (c+d x))^4}{5 b d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {1}{3} \int \left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right ) \left (b \left ((60 A+33 C) a^2+75 b B a+8 b^2 (5 A+4 C)\right )+\left (-6 C a^3+30 b B a^2+b^2 (100 A+71 C) a+45 b^3 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )\right )dx+\frac {\sin (c+d x) \left (3 a (5 b B-a C)+4 b^2 (5 A+4 C)\right ) (a+b \cos (c+d x))^2}{3 d}\right )+\frac {(5 b B-a C) \sin (c+d x) (a+b \cos (c+d x))^3}{4 d}}{5 b}+\frac {C \sin (c+d x) (a+b \cos (c+d x))^4}{5 b d}\) |
| \(\Big \downarrow \) 3213 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {1}{3} \left (\frac {b \sin (c+d x) \cos (c+d x) \left (-6 a^3 C+30 a^2 b B+a b^2 (100 A+71 C)+45 b^3 B\right )}{2 d}+\frac {15}{2} b x \left (4 a^3 (2 A+C)+12 a^2 b B+3 a b^2 (4 A+3 C)+3 b^3 B\right )+\frac {2 \sin (c+d x) \left (-3 a^4 C+15 a^3 b B+4 a^2 b^2 (20 A+13 C)+60 a b^3 B+4 b^4 (5 A+4 C)\right )}{d}\right )+\frac {\sin (c+d x) \left (3 a (5 b B-a C)+4 b^2 (5 A+4 C)\right ) (a+b \cos (c+d x))^2}{3 d}\right )+\frac {(5 b B-a C) \sin (c+d x) (a+b \cos (c+d x))^3}{4 d}}{5 b}+\frac {C \sin (c+d x) (a+b \cos (c+d x))^4}{5 b d}\) |
Input:
Int[(a + b*Cos[c + d*x])^3*(A + B*Cos[c + d*x] + C*Cos[c + d*x]^2),x]
Output:
(C*(a + b*Cos[c + d*x])^4*Sin[c + d*x])/(5*b*d) + (((5*b*B - a*C)*(a + b*C os[c + d*x])^3*Sin[c + d*x])/(4*d) + (((4*b^2*(5*A + 4*C) + 3*a*(5*b*B - a *C))*(a + b*Cos[c + d*x])^2*Sin[c + d*x])/(3*d) + ((15*b*(12*a^2*b*B + 3*b ^3*B + 4*a^3*(2*A + C) + 3*a*b^2*(4*A + 3*C))*x)/2 + (2*(15*a^3*b*B + 60*a *b^3*B - 3*a^4*C + 4*b^4*(5*A + 4*C) + 4*a^2*b^2*(20*A + 13*C))*Sin[c + d* x])/d + (b*(30*a^2*b*B + 45*b^3*B - 6*a^3*C + a*b^2*(100*A + 71*C))*Cos[c + d*x]*Sin[c + d*x])/(2*d))/3)/4)/(5*b)
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.) *(x_)]), x_Symbol] :> Simp[(2*a*c + b*d)*(x/2), x] + (-Simp[(b*c + a*d)*(Co s[e + f*x]/f), x] - Simp[b*d*Cos[e + f*x]*(Sin[e + f*x]/(2*f)), x]) /; Free Q[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-d)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/( f*(m + 1))), x] + Simp[1/(m + 1) Int[(a + b*Sin[e + f*x])^(m - 1)*Simp[b* d*m + a*c*(m + 1) + (a*d*m + b*c*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ [{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && GtQ[m, 0] && IntegerQ[2*m]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m + 2)) Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] && !LtQ[m, -1]
Time = 146.96 (sec) , antiderivative size = 199, normalized size of antiderivative = 0.72
| method | result | size |
| parallelrisch | \(\frac {120 \left (B \,b^{3}+3 a \left (A +C \right ) b^{2}+3 B \,a^{2} b +a^{3} C \right ) \sin \left (2 d x +2 c \right )+40 b \left (\left (A +\frac {5 C}{4}\right ) b^{2}+3 B a b +3 a^{2} C \right ) \sin \left (3 d x +3 c \right )+15 \left (B \,b^{3}+3 C a \,b^{2}\right ) \sin \left (4 d x +4 c \right )+6 C \,b^{3} \sin \left (5 d x +5 c \right )+60 \left (b^{3} \left (6 A +5 C \right )+18 B a \,b^{2}+24 a^{2} \left (A +\frac {3 C}{4}\right ) b +8 B \,a^{3}\right ) \sin \left (d x +c \right )+480 x d \left (\frac {3 B \,b^{3}}{8}+\frac {3 a \left (A +\frac {3 C}{4}\right ) b^{2}}{2}+\frac {3 B \,a^{2} b}{2}+a^{3} \left (A +\frac {C}{2}\right )\right )}{480 d}\) | \(199\) |
| parts | \(x A \,a^{3}+\frac {\left (3 A \,a^{2} b +B \,a^{3}\right ) \sin \left (d x +c \right )}{d}+\frac {\left (B \,b^{3}+3 C a \,b^{2}\right ) \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )}{d}+\frac {\left (A \,b^{3}+3 B a \,b^{2}+3 a^{2} b C \right ) \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )}{3 d}+\frac {\left (3 a A \,b^{2}+3 B \,a^{2} b +a^{3} C \right ) \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )}{d}+\frac {C \,b^{3} \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5 d}\) | \(203\) |
| derivativedivides | \(\frac {\frac {C \,b^{3} \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}+B \,b^{3} \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+3 C a \,b^{2} \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+\frac {A \,b^{3} \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )}{3}+B a \,b^{2} \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )+a^{2} b C \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )+3 a A \,b^{2} \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+3 B \,a^{2} b \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+a^{3} C \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+3 A \,a^{2} b \sin \left (d x +c \right )+B \,a^{3} \sin \left (d x +c \right )+A \,a^{3} \left (d x +c \right )}{d}\) | \(301\) |
| default | \(\frac {\frac {C \,b^{3} \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}+B \,b^{3} \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+3 C a \,b^{2} \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+\frac {A \,b^{3} \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )}{3}+B a \,b^{2} \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )+a^{2} b C \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )+3 a A \,b^{2} \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+3 B \,a^{2} b \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+a^{3} C \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+3 A \,a^{2} b \sin \left (d x +c \right )+B \,a^{3} \sin \left (d x +c \right )+A \,a^{3} \left (d x +c \right )}{d}\) | \(301\) |
| risch | \(x A \,a^{3}+\frac {3 x a A \,b^{2}}{2}+\frac {3 x B \,a^{2} b}{2}+\frac {3 x B \,b^{3}}{8}+\frac {a^{3} C x}{2}+\frac {9 a \,b^{2} C x}{8}+\frac {3 \sin \left (d x +c \right ) A \,a^{2} b}{d}+\frac {3 \sin \left (d x +c \right ) A \,b^{3}}{4 d}+\frac {a^{3} B \sin \left (d x +c \right )}{d}+\frac {9 \sin \left (d x +c \right ) B a \,b^{2}}{4 d}+\frac {9 \sin \left (d x +c \right ) a^{2} b C}{4 d}+\frac {5 \sin \left (d x +c \right ) C \,b^{3}}{8 d}+\frac {C \,b^{3} \sin \left (5 d x +5 c \right )}{80 d}+\frac {\sin \left (4 d x +4 c \right ) B \,b^{3}}{32 d}+\frac {3 \sin \left (4 d x +4 c \right ) C a \,b^{2}}{32 d}+\frac {\sin \left (3 d x +3 c \right ) A \,b^{3}}{12 d}+\frac {\sin \left (3 d x +3 c \right ) B a \,b^{2}}{4 d}+\frac {\sin \left (3 d x +3 c \right ) a^{2} b C}{4 d}+\frac {5 \sin \left (3 d x +3 c \right ) C \,b^{3}}{48 d}+\frac {3 \sin \left (2 d x +2 c \right ) a A \,b^{2}}{4 d}+\frac {3 \sin \left (2 d x +2 c \right ) B \,a^{2} b}{4 d}+\frac {\sin \left (2 d x +2 c \right ) B \,b^{3}}{4 d}+\frac {\sin \left (2 d x +2 c \right ) a^{3} C}{4 d}+\frac {3 \sin \left (2 d x +2 c \right ) C a \,b^{2}}{4 d}\) | \(360\) |
| norman | \(\frac {\left (A \,a^{3}+\frac {3}{2} a A \,b^{2}+\frac {3}{2} B \,a^{2} b +\frac {3}{8} B \,b^{3}+\frac {1}{2} a^{3} C +\frac {9}{8} C a \,b^{2}\right ) x +\left (A \,a^{3}+\frac {3}{2} a A \,b^{2}+\frac {3}{2} B \,a^{2} b +\frac {3}{8} B \,b^{3}+\frac {1}{2} a^{3} C +\frac {9}{8} C a \,b^{2}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}+\left (5 A \,a^{3}+\frac {15}{2} a A \,b^{2}+\frac {15}{2} B \,a^{2} b +\frac {15}{8} B \,b^{3}+\frac {5}{2} a^{3} C +\frac {45}{8} C a \,b^{2}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+\left (5 A \,a^{3}+\frac {15}{2} a A \,b^{2}+\frac {15}{2} B \,a^{2} b +\frac {15}{8} B \,b^{3}+\frac {5}{2} a^{3} C +\frac {45}{8} C a \,b^{2}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}+\left (10 A \,a^{3}+15 a A \,b^{2}+15 B \,a^{2} b +\frac {15}{4} B \,b^{3}+5 a^{3} C +\frac {45}{4} C a \,b^{2}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+\left (10 A \,a^{3}+15 a A \,b^{2}+15 B \,a^{2} b +\frac {15}{4} B \,b^{3}+5 a^{3} C +\frac {45}{4} C a \,b^{2}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+\frac {4 \left (135 A \,a^{2} b +25 A \,b^{3}+45 B \,a^{3}+75 B a \,b^{2}+75 a^{2} b C +29 C \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{15 d}+\frac {\left (24 A \,a^{2} b -12 a A \,b^{2}+8 A \,b^{3}+8 B \,a^{3}-12 B \,a^{2} b +24 B a \,b^{2}-5 B \,b^{3}-4 a^{3} C +24 a^{2} b C -15 C a \,b^{2}+8 C \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{4 d}+\frac {\left (24 A \,a^{2} b +12 a A \,b^{2}+8 A \,b^{3}+8 B \,a^{3}+12 B \,a^{2} b +24 B a \,b^{2}+5 B \,b^{3}+4 a^{3} C +24 a^{2} b C +15 C a \,b^{2}+8 C \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 d}+\frac {\left (144 A \,a^{2} b -36 a A \,b^{2}+32 A \,b^{3}+48 B \,a^{3}-36 B \,a^{2} b +96 B a \,b^{2}-3 B \,b^{3}-12 a^{3} C +96 a^{2} b C -9 C a \,b^{2}+16 C \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{6 d}+\frac {\left (144 A \,a^{2} b +36 a A \,b^{2}+32 A \,b^{3}+48 B \,a^{3}+36 B \,a^{2} b +96 B a \,b^{2}+3 B \,b^{3}+12 a^{3} C +96 a^{2} b C +9 C a \,b^{2}+16 C \,b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{6 d}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{5}}\) | \(733\) |
| orering | \(\text {Expression too large to display}\) | \(10006\) |
Input:
int((a+b*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x,method=_RETURNVER BOSE)
Output:
1/480*(120*(B*b^3+3*a*(A+C)*b^2+3*B*a^2*b+a^3*C)*sin(2*d*x+2*c)+40*b*((A+5 /4*C)*b^2+3*B*a*b+3*a^2*C)*sin(3*d*x+3*c)+15*(B*b^3+3*C*a*b^2)*sin(4*d*x+4 *c)+6*C*b^3*sin(5*d*x+5*c)+60*(b^3*(6*A+5*C)+18*B*a*b^2+24*a^2*(A+3/4*C)*b +8*B*a^3)*sin(d*x+c)+480*x*d*(3/8*B*b^3+3/2*a*(A+3/4*C)*b^2+3/2*B*a^2*b+a^ 3*(A+1/2*C)))/d
Time = 0.10 (sec) , antiderivative size = 207, normalized size of antiderivative = 0.75 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {15 \, {\left (4 \, {\left (2 \, A + C\right )} a^{3} + 12 \, B a^{2} b + 3 \, {\left (4 \, A + 3 \, C\right )} a b^{2} + 3 \, B b^{3}\right )} d x + {\left (24 \, C b^{3} \cos \left (d x + c\right )^{4} + 120 \, B a^{3} + 120 \, {\left (3 \, A + 2 \, C\right )} a^{2} b + 240 \, B a b^{2} + 16 \, {\left (5 \, A + 4 \, C\right )} b^{3} + 30 \, {\left (3 \, C a b^{2} + B b^{3}\right )} \cos \left (d x + c\right )^{3} + 8 \, {\left (15 \, C a^{2} b + 15 \, B a b^{2} + {\left (5 \, A + 4 \, C\right )} b^{3}\right )} \cos \left (d x + c\right )^{2} + 15 \, {\left (4 \, C a^{3} + 12 \, B a^{2} b + 3 \, {\left (4 \, A + 3 \, C\right )} a b^{2} + 3 \, B b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{120 \, d} \] Input:
integrate((a+b*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x, algorithm= "fricas")
Output:
1/120*(15*(4*(2*A + C)*a^3 + 12*B*a^2*b + 3*(4*A + 3*C)*a*b^2 + 3*B*b^3)*d *x + (24*C*b^3*cos(d*x + c)^4 + 120*B*a^3 + 120*(3*A + 2*C)*a^2*b + 240*B* a*b^2 + 16*(5*A + 4*C)*b^3 + 30*(3*C*a*b^2 + B*b^3)*cos(d*x + c)^3 + 8*(15 *C*a^2*b + 15*B*a*b^2 + (5*A + 4*C)*b^3)*cos(d*x + c)^2 + 15*(4*C*a^3 + 12 *B*a^2*b + 3*(4*A + 3*C)*a*b^2 + 3*B*b^3)*cos(d*x + c))*sin(d*x + c))/d
Leaf count of result is larger than twice the leaf count of optimal. 685 vs. \(2 (265) = 530\).
Time = 0.31 (sec) , antiderivative size = 685, normalized size of antiderivative = 2.47 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx =\text {Too large to display} \] Input:
integrate((a+b*cos(d*x+c))**3*(A+B*cos(d*x+c)+C*cos(d*x+c)**2),x)
Output:
Piecewise((A*a**3*x + 3*A*a**2*b*sin(c + d*x)/d + 3*A*a*b**2*x*sin(c + d*x )**2/2 + 3*A*a*b**2*x*cos(c + d*x)**2/2 + 3*A*a*b**2*sin(c + d*x)*cos(c + d*x)/(2*d) + 2*A*b**3*sin(c + d*x)**3/(3*d) + A*b**3*sin(c + d*x)*cos(c + d*x)**2/d + B*a**3*sin(c + d*x)/d + 3*B*a**2*b*x*sin(c + d*x)**2/2 + 3*B*a **2*b*x*cos(c + d*x)**2/2 + 3*B*a**2*b*sin(c + d*x)*cos(c + d*x)/(2*d) + 2 *B*a*b**2*sin(c + d*x)**3/d + 3*B*a*b**2*sin(c + d*x)*cos(c + d*x)**2/d + 3*B*b**3*x*sin(c + d*x)**4/8 + 3*B*b**3*x*sin(c + d*x)**2*cos(c + d*x)**2/ 4 + 3*B*b**3*x*cos(c + d*x)**4/8 + 3*B*b**3*sin(c + d*x)**3*cos(c + d*x)/( 8*d) + 5*B*b**3*sin(c + d*x)*cos(c + d*x)**3/(8*d) + C*a**3*x*sin(c + d*x) **2/2 + C*a**3*x*cos(c + d*x)**2/2 + C*a**3*sin(c + d*x)*cos(c + d*x)/(2*d ) + 2*C*a**2*b*sin(c + d*x)**3/d + 3*C*a**2*b*sin(c + d*x)*cos(c + d*x)**2 /d + 9*C*a*b**2*x*sin(c + d*x)**4/8 + 9*C*a*b**2*x*sin(c + d*x)**2*cos(c + d*x)**2/4 + 9*C*a*b**2*x*cos(c + d*x)**4/8 + 9*C*a*b**2*sin(c + d*x)**3*c os(c + d*x)/(8*d) + 15*C*a*b**2*sin(c + d*x)*cos(c + d*x)**3/(8*d) + 8*C*b **3*sin(c + d*x)**5/(15*d) + 4*C*b**3*sin(c + d*x)**3*cos(c + d*x)**2/(3*d ) + C*b**3*sin(c + d*x)*cos(c + d*x)**4/d, Ne(d, 0)), (x*(a + b*cos(c))**3 *(A + B*cos(c) + C*cos(c)**2), True))
Time = 0.05 (sec) , antiderivative size = 288, normalized size of antiderivative = 1.04 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {480 \, {\left (d x + c\right )} A a^{3} + 120 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{3} + 360 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{2} b - 480 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a^{2} b + 360 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a b^{2} - 480 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B a b^{2} + 45 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} C a b^{2} - 160 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} A b^{3} + 15 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} B b^{3} + 32 \, {\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} C b^{3} + 480 \, B a^{3} \sin \left (d x + c\right ) + 1440 \, A a^{2} b \sin \left (d x + c\right )}{480 \, d} \] Input:
integrate((a+b*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x, algorithm= "maxima")
Output:
1/480*(480*(d*x + c)*A*a^3 + 120*(2*d*x + 2*c + sin(2*d*x + 2*c))*C*a^3 + 360*(2*d*x + 2*c + sin(2*d*x + 2*c))*B*a^2*b - 480*(sin(d*x + c)^3 - 3*sin (d*x + c))*C*a^2*b + 360*(2*d*x + 2*c + sin(2*d*x + 2*c))*A*a*b^2 - 480*(s in(d*x + c)^3 - 3*sin(d*x + c))*B*a*b^2 + 45*(12*d*x + 12*c + sin(4*d*x + 4*c) + 8*sin(2*d*x + 2*c))*C*a*b^2 - 160*(sin(d*x + c)^3 - 3*sin(d*x + c)) *A*b^3 + 15*(12*d*x + 12*c + sin(4*d*x + 4*c) + 8*sin(2*d*x + 2*c))*B*b^3 + 32*(3*sin(d*x + c)^5 - 10*sin(d*x + c)^3 + 15*sin(d*x + c))*C*b^3 + 480* B*a^3*sin(d*x + c) + 1440*A*a^2*b*sin(d*x + c))/d
Time = 0.14 (sec) , antiderivative size = 227, normalized size of antiderivative = 0.82 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {C b^{3} \sin \left (5 \, d x + 5 \, c\right )}{80 \, d} + \frac {1}{8} \, {\left (8 \, A a^{3} + 4 \, C a^{3} + 12 \, B a^{2} b + 12 \, A a b^{2} + 9 \, C a b^{2} + 3 \, B b^{3}\right )} x + \frac {{\left (3 \, C a b^{2} + B b^{3}\right )} \sin \left (4 \, d x + 4 \, c\right )}{32 \, d} + \frac {{\left (12 \, C a^{2} b + 12 \, B a b^{2} + 4 \, A b^{3} + 5 \, C b^{3}\right )} \sin \left (3 \, d x + 3 \, c\right )}{48 \, d} + \frac {{\left (C a^{3} + 3 \, B a^{2} b + 3 \, A a b^{2} + 3 \, C a b^{2} + B b^{3}\right )} \sin \left (2 \, d x + 2 \, c\right )}{4 \, d} + \frac {{\left (8 \, B a^{3} + 24 \, A a^{2} b + 18 \, C a^{2} b + 18 \, B a b^{2} + 6 \, A b^{3} + 5 \, C b^{3}\right )} \sin \left (d x + c\right )}{8 \, d} \] Input:
integrate((a+b*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x, algorithm= "giac")
Output:
1/80*C*b^3*sin(5*d*x + 5*c)/d + 1/8*(8*A*a^3 + 4*C*a^3 + 12*B*a^2*b + 12*A *a*b^2 + 9*C*a*b^2 + 3*B*b^3)*x + 1/32*(3*C*a*b^2 + B*b^3)*sin(4*d*x + 4*c )/d + 1/48*(12*C*a^2*b + 12*B*a*b^2 + 4*A*b^3 + 5*C*b^3)*sin(3*d*x + 3*c)/ d + 1/4*(C*a^3 + 3*B*a^2*b + 3*A*a*b^2 + 3*C*a*b^2 + B*b^3)*sin(2*d*x + 2* c)/d + 1/8*(8*B*a^3 + 24*A*a^2*b + 18*C*a^2*b + 18*B*a*b^2 + 6*A*b^3 + 5*C *b^3)*sin(d*x + c)/d
Time = 1.29 (sec) , antiderivative size = 359, normalized size of antiderivative = 1.30 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=A\,a^3\,x+\frac {3\,B\,b^3\,x}{8}+\frac {C\,a^3\,x}{2}+\frac {3\,A\,a\,b^2\,x}{2}+\frac {3\,B\,a^2\,b\,x}{2}+\frac {9\,C\,a\,b^2\,x}{8}+\frac {3\,A\,b^3\,\sin \left (c+d\,x\right )}{4\,d}+\frac {B\,a^3\,\sin \left (c+d\,x\right )}{d}+\frac {5\,C\,b^3\,\sin \left (c+d\,x\right )}{8\,d}+\frac {A\,b^3\,\sin \left (3\,c+3\,d\,x\right )}{12\,d}+\frac {B\,b^3\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {C\,a^3\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {B\,b^3\,\sin \left (4\,c+4\,d\,x\right )}{32\,d}+\frac {5\,C\,b^3\,\sin \left (3\,c+3\,d\,x\right )}{48\,d}+\frac {C\,b^3\,\sin \left (5\,c+5\,d\,x\right )}{80\,d}+\frac {3\,A\,a\,b^2\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {3\,B\,a^2\,b\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {B\,a\,b^2\,\sin \left (3\,c+3\,d\,x\right )}{4\,d}+\frac {3\,C\,a\,b^2\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {C\,a^2\,b\,\sin \left (3\,c+3\,d\,x\right )}{4\,d}+\frac {3\,C\,a\,b^2\,\sin \left (4\,c+4\,d\,x\right )}{32\,d}+\frac {3\,A\,a^2\,b\,\sin \left (c+d\,x\right )}{d}+\frac {9\,B\,a\,b^2\,\sin \left (c+d\,x\right )}{4\,d}+\frac {9\,C\,a^2\,b\,\sin \left (c+d\,x\right )}{4\,d} \] Input:
int((a + b*cos(c + d*x))^3*(A + B*cos(c + d*x) + C*cos(c + d*x)^2),x)
Output:
A*a^3*x + (3*B*b^3*x)/8 + (C*a^3*x)/2 + (3*A*a*b^2*x)/2 + (3*B*a^2*b*x)/2 + (9*C*a*b^2*x)/8 + (3*A*b^3*sin(c + d*x))/(4*d) + (B*a^3*sin(c + d*x))/d + (5*C*b^3*sin(c + d*x))/(8*d) + (A*b^3*sin(3*c + 3*d*x))/(12*d) + (B*b^3* sin(2*c + 2*d*x))/(4*d) + (C*a^3*sin(2*c + 2*d*x))/(4*d) + (B*b^3*sin(4*c + 4*d*x))/(32*d) + (5*C*b^3*sin(3*c + 3*d*x))/(48*d) + (C*b^3*sin(5*c + 5* d*x))/(80*d) + (3*A*a*b^2*sin(2*c + 2*d*x))/(4*d) + (3*B*a^2*b*sin(2*c + 2 *d*x))/(4*d) + (B*a*b^2*sin(3*c + 3*d*x))/(4*d) + (3*C*a*b^2*sin(2*c + 2*d *x))/(4*d) + (C*a^2*b*sin(3*c + 3*d*x))/(4*d) + (3*C*a*b^2*sin(4*c + 4*d*x ))/(32*d) + (3*A*a^2*b*sin(c + d*x))/d + (9*B*a*b^2*sin(c + d*x))/(4*d) + (9*C*a^2*b*sin(c + d*x))/(4*d)
Time = 0.18 (sec) , antiderivative size = 267, normalized size of antiderivative = 0.96 \[ \int (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx=\frac {-90 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{3} a \,b^{2} c -30 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{3} b^{4}+60 \cos \left (d x +c \right ) \sin \left (d x +c \right ) a^{3} c +360 \cos \left (d x +c \right ) \sin \left (d x +c \right ) a^{2} b^{2}+225 \cos \left (d x +c \right ) \sin \left (d x +c \right ) a \,b^{2} c +75 \cos \left (d x +c \right ) \sin \left (d x +c \right ) b^{4}+24 \sin \left (d x +c \right )^{5} b^{3} c -120 \sin \left (d x +c \right )^{3} a^{2} b c -160 \sin \left (d x +c \right )^{3} a \,b^{3}-80 \sin \left (d x +c \right )^{3} b^{3} c +480 \sin \left (d x +c \right ) a^{3} b +360 \sin \left (d x +c \right ) a^{2} b c +480 \sin \left (d x +c \right ) a \,b^{3}+120 \sin \left (d x +c \right ) b^{3} c +120 a^{4} d x +60 a^{3} c d x +360 a^{2} b^{2} d x +135 a \,b^{2} c d x +45 b^{4} d x}{120 d} \] Input:
int((a+b*cos(d*x+c))^3*(A+B*cos(d*x+c)+C*cos(d*x+c)^2),x)
Output:
( - 90*cos(c + d*x)*sin(c + d*x)**3*a*b**2*c - 30*cos(c + d*x)*sin(c + d*x )**3*b**4 + 60*cos(c + d*x)*sin(c + d*x)*a**3*c + 360*cos(c + d*x)*sin(c + d*x)*a**2*b**2 + 225*cos(c + d*x)*sin(c + d*x)*a*b**2*c + 75*cos(c + d*x) *sin(c + d*x)*b**4 + 24*sin(c + d*x)**5*b**3*c - 120*sin(c + d*x)**3*a**2* b*c - 160*sin(c + d*x)**3*a*b**3 - 80*sin(c + d*x)**3*b**3*c + 480*sin(c + d*x)*a**3*b + 360*sin(c + d*x)*a**2*b*c + 480*sin(c + d*x)*a*b**3 + 120*s in(c + d*x)*b**3*c + 120*a**4*d*x + 60*a**3*c*d*x + 360*a**2*b**2*d*x + 13 5*a*b**2*c*d*x + 45*b**4*d*x)/(120*d)