Integrand size = 24, antiderivative size = 105 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx=\frac {7 a^2 \sin (c+d x)}{9 d}-\frac {7 a^2 \sin ^3(c+d x)}{9 d}+\frac {7 a^2 \sin ^5(c+d x)}{15 d}-\frac {a^2 \sin ^7(c+d x)}{9 d}-\frac {2 i \cos ^9(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{9 d} \] Output:
7/9*a^2*sin(d*x+c)/d-7/9*a^2*sin(d*x+c)^3/d+7/15*a^2*sin(d*x+c)^5/d-1/9*a^ 2*sin(d*x+c)^7/d-2/9*I*cos(d*x+c)^9*(a^2+I*a^2*tan(d*x+c))/d
Time = 0.28 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.99 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx=-\frac {2 i a^2 \cos ^9(c+d x)}{9 d}+\frac {a^2 \sin (c+d x)}{d}-\frac {5 a^2 \sin ^3(c+d x)}{3 d}+\frac {9 a^2 \sin ^5(c+d x)}{5 d}-\frac {a^2 \sin ^7(c+d x)}{d}+\frac {2 a^2 \sin ^9(c+d x)}{9 d} \] Input:
Integrate[Cos[c + d*x]^9*(a + I*a*Tan[c + d*x])^2,x]
Output:
(((-2*I)/9)*a^2*Cos[c + d*x]^9)/d + (a^2*Sin[c + d*x])/d - (5*a^2*Sin[c + d*x]^3)/(3*d) + (9*a^2*Sin[c + d*x]^5)/(5*d) - (a^2*Sin[c + d*x]^7)/d + (2 *a^2*Sin[c + d*x]^9)/(9*d)
Time = 0.32 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.82, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {3042, 3977, 3042, 3113, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {(a+i a \tan (c+d x))^2}{\sec (c+d x)^9}dx\) |
\(\Big \downarrow \) 3977 |
\(\displaystyle \frac {7}{9} a^2 \int \cos ^7(c+d x)dx-\frac {2 i \cos ^9(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{9 d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {7}{9} a^2 \int \sin \left (c+d x+\frac {\pi }{2}\right )^7dx-\frac {2 i \cos ^9(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{9 d}\) |
\(\Big \downarrow \) 3113 |
\(\displaystyle -\frac {7 a^2 \int \left (-\sin ^6(c+d x)+3 \sin ^4(c+d x)-3 \sin ^2(c+d x)+1\right )d(-\sin (c+d x))}{9 d}-\frac {2 i \cos ^9(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{9 d}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {7 a^2 \left (\frac {1}{7} \sin ^7(c+d x)-\frac {3}{5} \sin ^5(c+d x)+\sin ^3(c+d x)-\sin (c+d x)\right )}{9 d}-\frac {2 i \cos ^9(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{9 d}\) |
Input:
Int[Cos[c + d*x]^9*(a + I*a*Tan[c + d*x])^2,x]
Output:
(-7*a^2*(-Sin[c + d*x] + Sin[c + d*x]^3 - (3*Sin[c + d*x]^5)/5 + Sin[c + d *x]^7/7))/(9*d) - (((2*I)/9)*Cos[c + d*x]^9*(a^2 + I*a^2*Tan[c + d*x]))/d
Int[sin[(c_.) + (d_.)*(x_)]^(n_), x_Symbol] :> Simp[-d^(-1) Subst[Int[Exp and[(1 - x^2)^((n - 1)/2), x], x], x, Cos[c + d*x]], x] /; FreeQ[{c, d}, x] && IGtQ[(n - 1)/2, 0]
Int[((d_.)*sec[(e_.) + (f_.)*(x_)])^(m_)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x _)])^(n_), x_Symbol] :> Simp[2*b*(d*Sec[e + f*x])^m*((a + b*Tan[e + f*x])^( n - 1)/(f*m)), x] - Simp[b^2*((m + 2*n - 2)/(d^2*m)) Int[(d*Sec[e + f*x]) ^(m + 2)*(a + b*Tan[e + f*x])^(n - 2), x], x] /; FreeQ[{a, b, d, e, f}, x] && EqQ[a^2 + b^2, 0] && GtQ[n, 1] && ((IGtQ[n/2, 0] && ILtQ[m - 1/2, 0]) || (EqQ[n, 2] && LtQ[m, 0]) || (LeQ[m, -1] && GtQ[m + n, 0]) || (ILtQ[m, 0] & & LtQ[m/2 + n - 1, 0] && IntegerQ[n]) || (EqQ[n, 3/2] && EqQ[m, -2^(-1)])) && IntegerQ[2*m]
Time = 124.66 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.25
method | result | size |
derivativedivides | \(\frac {-a^{2} \left (-\frac {\cos \left (d x +c \right )^{8} \sin \left (d x +c \right )}{9}+\frac {\left (\frac {16}{5}+\cos \left (d x +c \right )^{6}+\frac {6 \cos \left (d x +c \right )^{4}}{5}+\frac {8 \cos \left (d x +c \right )^{2}}{5}\right ) \sin \left (d x +c \right )}{63}\right )-\frac {2 i a^{2} \cos \left (d x +c \right )^{9}}{9}+\frac {a^{2} \left (\frac {128}{35}+\cos \left (d x +c \right )^{8}+\frac {8 \cos \left (d x +c \right )^{6}}{7}+\frac {48 \cos \left (d x +c \right )^{4}}{35}+\frac {64 \cos \left (d x +c \right )^{2}}{35}\right ) \sin \left (d x +c \right )}{9}}{d}\) | \(131\) |
default | \(\frac {-a^{2} \left (-\frac {\cos \left (d x +c \right )^{8} \sin \left (d x +c \right )}{9}+\frac {\left (\frac {16}{5}+\cos \left (d x +c \right )^{6}+\frac {6 \cos \left (d x +c \right )^{4}}{5}+\frac {8 \cos \left (d x +c \right )^{2}}{5}\right ) \sin \left (d x +c \right )}{63}\right )-\frac {2 i a^{2} \cos \left (d x +c \right )^{9}}{9}+\frac {a^{2} \left (\frac {128}{35}+\cos \left (d x +c \right )^{8}+\frac {8 \cos \left (d x +c \right )^{6}}{7}+\frac {48 \cos \left (d x +c \right )^{4}}{35}+\frac {64 \cos \left (d x +c \right )^{2}}{35}\right ) \sin \left (d x +c \right )}{9}}{d}\) | \(131\) |
risch | \(-\frac {i a^{2} {\mathrm e}^{9 i \left (d x +c \right )}}{1152 d}-\frac {i a^{2} {\mathrm e}^{7 i \left (d x +c \right )}}{128 d}-\frac {7 i a^{2} \cos \left (d x +c \right )}{64 d}+\frac {7 a^{2} \sin \left (d x +c \right )}{16 d}-\frac {i a^{2} \cos \left (5 d x +5 c \right )}{32 d}+\frac {11 a^{2} \sin \left (5 d x +5 c \right )}{320 d}-\frac {7 i a^{2} \cos \left (3 d x +3 c \right )}{96 d}+\frac {7 a^{2} \sin \left (3 d x +3 c \right )}{64 d}\) | \(137\) |
Input:
int(cos(d*x+c)^9*(a+I*a*tan(d*x+c))^2,x,method=_RETURNVERBOSE)
Output:
1/d*(-a^2*(-1/9*cos(d*x+c)^8*sin(d*x+c)+1/63*(16/5+cos(d*x+c)^6+6/5*cos(d* x+c)^4+8/5*cos(d*x+c)^2)*sin(d*x+c))-2/9*I*a^2*cos(d*x+c)^9+1/9*a^2*(128/3 5+cos(d*x+c)^8+8/7*cos(d*x+c)^6+48/35*cos(d*x+c)^4+64/35*cos(d*x+c)^2)*sin (d*x+c))
Time = 0.10 (sec) , antiderivative size = 118, normalized size of antiderivative = 1.12 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx=\frac {{\left (-5 i \, a^{2} e^{\left (14 i \, d x + 14 i \, c\right )} - 45 i \, a^{2} e^{\left (12 i \, d x + 12 i \, c\right )} - 189 i \, a^{2} e^{\left (10 i \, d x + 10 i \, c\right )} - 525 i \, a^{2} e^{\left (8 i \, d x + 8 i \, c\right )} - 1575 i \, a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} + 945 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} + 105 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + 9 i \, a^{2}\right )} e^{\left (-5 i \, d x - 5 i \, c\right )}}{5760 \, d} \] Input:
integrate(cos(d*x+c)^9*(a+I*a*tan(d*x+c))^2,x, algorithm="fricas")
Output:
1/5760*(-5*I*a^2*e^(14*I*d*x + 14*I*c) - 45*I*a^2*e^(12*I*d*x + 12*I*c) - 189*I*a^2*e^(10*I*d*x + 10*I*c) - 525*I*a^2*e^(8*I*d*x + 8*I*c) - 1575*I*a ^2*e^(6*I*d*x + 6*I*c) + 945*I*a^2*e^(4*I*d*x + 4*I*c) + 105*I*a^2*e^(2*I* d*x + 2*I*c) + 9*I*a^2)*e^(-5*I*d*x - 5*I*c)/d
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 314 vs. \(2 (94) = 188\).
Time = 0.43 (sec) , antiderivative size = 314, normalized size of antiderivative = 2.99 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx=\begin {cases} \frac {\left (- 126663739519795200 i a^{2} d^{7} e^{18 i c} e^{9 i d x} - 1139973655678156800 i a^{2} d^{7} e^{16 i c} e^{7 i d x} - 4787889353848258560 i a^{2} d^{7} e^{14 i c} e^{5 i d x} - 13299692649578496000 i a^{2} d^{7} e^{12 i c} e^{3 i d x} - 39899077948735488000 i a^{2} d^{7} e^{10 i c} e^{i d x} + 23939446769241292800 i a^{2} d^{7} e^{8 i c} e^{- i d x} + 2659938529915699200 i a^{2} d^{7} e^{6 i c} e^{- 3 i d x} + 227994731135631360 i a^{2} d^{7} e^{4 i c} e^{- 5 i d x}\right ) e^{- 9 i c}}{145916627926804070400 d^{8}} & \text {for}\: d^{8} e^{9 i c} \neq 0 \\\frac {x \left (a^{2} e^{14 i c} + 7 a^{2} e^{12 i c} + 21 a^{2} e^{10 i c} + 35 a^{2} e^{8 i c} + 35 a^{2} e^{6 i c} + 21 a^{2} e^{4 i c} + 7 a^{2} e^{2 i c} + a^{2}\right ) e^{- 5 i c}}{128} & \text {otherwise} \end {cases} \] Input:
integrate(cos(d*x+c)**9*(a+I*a*tan(d*x+c))**2,x)
Output:
Piecewise(((-126663739519795200*I*a**2*d**7*exp(18*I*c)*exp(9*I*d*x) - 113 9973655678156800*I*a**2*d**7*exp(16*I*c)*exp(7*I*d*x) - 478788935384825856 0*I*a**2*d**7*exp(14*I*c)*exp(5*I*d*x) - 13299692649578496000*I*a**2*d**7* exp(12*I*c)*exp(3*I*d*x) - 39899077948735488000*I*a**2*d**7*exp(10*I*c)*ex p(I*d*x) + 23939446769241292800*I*a**2*d**7*exp(8*I*c)*exp(-I*d*x) + 26599 38529915699200*I*a**2*d**7*exp(6*I*c)*exp(-3*I*d*x) + 227994731135631360*I *a**2*d**7*exp(4*I*c)*exp(-5*I*d*x))*exp(-9*I*c)/(145916627926804070400*d* *8), Ne(d**8*exp(9*I*c), 0)), (x*(a**2*exp(14*I*c) + 7*a**2*exp(12*I*c) + 21*a**2*exp(10*I*c) + 35*a**2*exp(8*I*c) + 35*a**2*exp(6*I*c) + 21*a**2*ex p(4*I*c) + 7*a**2*exp(2*I*c) + a**2)*exp(-5*I*c)/128, True))
Time = 0.04 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.13 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx=-\frac {70 i \, a^{2} \cos \left (d x + c\right )^{9} - {\left (35 \, \sin \left (d x + c\right )^{9} - 135 \, \sin \left (d x + c\right )^{7} + 189 \, \sin \left (d x + c\right )^{5} - 105 \, \sin \left (d x + c\right )^{3}\right )} a^{2} - {\left (35 \, \sin \left (d x + c\right )^{9} - 180 \, \sin \left (d x + c\right )^{7} + 378 \, \sin \left (d x + c\right )^{5} - 420 \, \sin \left (d x + c\right )^{3} + 315 \, \sin \left (d x + c\right )\right )} a^{2}}{315 \, d} \] Input:
integrate(cos(d*x+c)^9*(a+I*a*tan(d*x+c))^2,x, algorithm="maxima")
Output:
-1/315*(70*I*a^2*cos(d*x + c)^9 - (35*sin(d*x + c)^9 - 135*sin(d*x + c)^7 + 189*sin(d*x + c)^5 - 105*sin(d*x + c)^3)*a^2 - (35*sin(d*x + c)^9 - 180* sin(d*x + c)^7 + 378*sin(d*x + c)^5 - 420*sin(d*x + c)^3 + 315*sin(d*x + c ))*a^2)/d
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 669 vs. \(2 (91) = 182\).
Time = 0.37 (sec) , antiderivative size = 669, normalized size of antiderivative = 6.37 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx =\text {Too large to display} \] Input:
integrate(cos(d*x+c)^9*(a+I*a*tan(d*x+c))^2,x, algorithm="giac")
Output:
-1/92160*(18585*a^2*e^(9*I*d*x + 3*I*c)*log(I*e^(I*d*x + I*c) + 1) + 37170 *a^2*e^(7*I*d*x + I*c)*log(I*e^(I*d*x + I*c) + 1) + 18585*a^2*e^(5*I*d*x - I*c)*log(I*e^(I*d*x + I*c) + 1) + 14625*a^2*e^(9*I*d*x + 3*I*c)*log(I*e^( I*d*x + I*c) - 1) + 29250*a^2*e^(7*I*d*x + I*c)*log(I*e^(I*d*x + I*c) - 1) + 14625*a^2*e^(5*I*d*x - I*c)*log(I*e^(I*d*x + I*c) - 1) - 18585*a^2*e^(9 *I*d*x + 3*I*c)*log(-I*e^(I*d*x + I*c) + 1) - 37170*a^2*e^(7*I*d*x + I*c)* log(-I*e^(I*d*x + I*c) + 1) - 18585*a^2*e^(5*I*d*x - I*c)*log(-I*e^(I*d*x + I*c) + 1) - 14625*a^2*e^(9*I*d*x + 3*I*c)*log(-I*e^(I*d*x + I*c) - 1) - 29250*a^2*e^(7*I*d*x + I*c)*log(-I*e^(I*d*x + I*c) - 1) - 14625*a^2*e^(5*I *d*x - I*c)*log(-I*e^(I*d*x + I*c) - 1) - 3960*a^2*e^(9*I*d*x + 3*I*c)*log (I*e^(I*d*x) + e^(-I*c)) - 7920*a^2*e^(7*I*d*x + I*c)*log(I*e^(I*d*x) + e^ (-I*c)) - 3960*a^2*e^(5*I*d*x - I*c)*log(I*e^(I*d*x) + e^(-I*c)) + 3960*a^ 2*e^(9*I*d*x + 3*I*c)*log(-I*e^(I*d*x) + e^(-I*c)) + 7920*a^2*e^(7*I*d*x + I*c)*log(-I*e^(I*d*x) + e^(-I*c)) + 3960*a^2*e^(5*I*d*x - I*c)*log(-I*e^( I*d*x) + e^(-I*c)) + 80*I*a^2*e^(18*I*d*x + 12*I*c) + 880*I*a^2*e^(16*I*d* x + 10*I*c) + 4544*I*a^2*e^(14*I*d*x + 8*I*c) + 15168*I*a^2*e^(12*I*d*x + 6*I*c) + 45024*I*a^2*e^(10*I*d*x + 4*I*c) + 43680*I*a^2*e^(8*I*d*x + 2*I*c ) - 18624*I*a^2*e^(4*I*d*x - 2*I*c) - 1968*I*a^2*e^(2*I*d*x - 4*I*c) - 672 0*I*a^2*e^(6*I*d*x) - 144*I*a^2*e^(-6*I*c))/(d*e^(9*I*d*x + 3*I*c) + 2*d*e ^(7*I*d*x + I*c) + d*e^(5*I*d*x - I*c))
Time = 2.27 (sec) , antiderivative size = 330, normalized size of antiderivative = 3.14 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx=\frac {2\,a^2\,\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-2{}\mathrm {i}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}+\frac {1024\,a^2\,\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-\mathrm {i}\right )}{9\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^9}-\frac {8\,a^2\,\left (5\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-12{}\mathrm {i}\right )}{3\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^2}-\frac {512\,a^2\,\left (8\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-9{}\mathrm {i}\right )}{9\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^8}+\frac {128\,a^2\,\left (19\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-24{}\mathrm {i}\right )}{3\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^7}-\frac {64\,a^2\,\left (19\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-35{}\mathrm {i}\right )}{5\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^4}+\frac {56\,a^2\,\left (19\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-40{}\mathrm {i}\right )}{15\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^3}-\frac {128\,a^2\,\left (59\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-84{}\mathrm {i}\right )}{9\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^6}+\frac {32\,a^2\,\left (781\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-1260{}\mathrm {i}\right )}{45\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^5} \] Input:
int(cos(c + d*x)^9*(a + a*tan(c + d*x)*1i)^2,x)
Output:
(2*a^2*(tan(c/2 + (d*x)/2) - 2i))/(d*(tan(c/2 + (d*x)/2)^2 + 1)) + (1024*a ^2*(tan(c/2 + (d*x)/2) - 1i))/(9*d*(tan(c/2 + (d*x)/2)^2 + 1)^9) - (8*a^2* (5*tan(c/2 + (d*x)/2) - 12i))/(3*d*(tan(c/2 + (d*x)/2)^2 + 1)^2) - (512*a^ 2*(8*tan(c/2 + (d*x)/2) - 9i))/(9*d*(tan(c/2 + (d*x)/2)^2 + 1)^8) + (128*a ^2*(19*tan(c/2 + (d*x)/2) - 24i))/(3*d*(tan(c/2 + (d*x)/2)^2 + 1)^7) - (64 *a^2*(19*tan(c/2 + (d*x)/2) - 35i))/(5*d*(tan(c/2 + (d*x)/2)^2 + 1)^4) + ( 56*a^2*(19*tan(c/2 + (d*x)/2) - 40i))/(15*d*(tan(c/2 + (d*x)/2)^2 + 1)^3) - (128*a^2*(59*tan(c/2 + (d*x)/2) - 84i))/(9*d*(tan(c/2 + (d*x)/2)^2 + 1)^ 6) + (32*a^2*(781*tan(c/2 + (d*x)/2) - 1260i))/(45*d*(tan(c/2 + (d*x)/2)^2 + 1)^5)
Time = 0.16 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.30 \[ \int \cos ^9(c+d x) (a+i a \tan (c+d x))^2 \, dx=\frac {a^{2} \left (-10 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{8} i +40 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{6} i -60 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{4} i +40 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} i -10 \cos \left (d x +c \right ) i +10 \sin \left (d x +c \right )^{9}-45 \sin \left (d x +c \right )^{7}+81 \sin \left (d x +c \right )^{5}-75 \sin \left (d x +c \right )^{3}+45 \sin \left (d x +c \right )+10 i \right )}{45 d} \] Input:
int(cos(d*x+c)^9*(a+I*a*tan(d*x+c))^2,x)
Output:
(a**2*( - 10*cos(c + d*x)*sin(c + d*x)**8*i + 40*cos(c + d*x)*sin(c + d*x) **6*i - 60*cos(c + d*x)*sin(c + d*x)**4*i + 40*cos(c + d*x)*sin(c + d*x)** 2*i - 10*cos(c + d*x)*i + 10*sin(c + d*x)**9 - 45*sin(c + d*x)**7 + 81*sin (c + d*x)**5 - 75*sin(c + d*x)**3 + 45*sin(c + d*x) + 10*i))/(45*d)