Integrand size = 23, antiderivative size = 140 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=\left (a^3 c-3 a b^2 c-3 a^2 b d+b^3 d\right ) x-\frac {\left (3 a^2 b c-b^3 c+a^3 d-3 a b^2 d\right ) \log (\cos (e+f x))}{f}+\frac {b \left (2 a b c+a^2 d-b^2 d\right ) \tan (e+f x)}{f}+\frac {(b c+a d) (a+b \tan (e+f x))^2}{2 f}+\frac {d (a+b \tan (e+f x))^3}{3 f} \] Output:
(a^3*c-3*a^2*b*d-3*a*b^2*c+b^3*d)*x-(a^3*d+3*a^2*b*c-3*a*b^2*d-b^3*c)*ln(c os(f*x+e))/f+b*(a^2*d+2*a*b*c-b^2*d)*tan(f*x+e)/f+1/2*(a*d+b*c)*(a+b*tan(f *x+e))^2/f+1/3*d*(a+b*tan(f*x+e))^3/f
Result contains complex when optimal does not.
Time = 0.73 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.93 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=\frac {3 (a+i b)^3 (-i c+d) \log (i-\tan (e+f x))+3 (a-i b)^3 (i c+d) \log (i+\tan (e+f x))+6 b \left (3 a b c+3 a^2 d-b^2 d\right ) \tan (e+f x)+3 b^2 (b c+3 a d) \tan ^2(e+f x)+2 b^3 d \tan ^3(e+f x)}{6 f} \] Input:
Integrate[(a + b*Tan[e + f*x])^3*(c + d*Tan[e + f*x]),x]
Output:
(3*(a + I*b)^3*((-I)*c + d)*Log[I - Tan[e + f*x]] + 3*(a - I*b)^3*(I*c + d )*Log[I + Tan[e + f*x]] + 6*b*(3*a*b*c + 3*a^2*d - b^2*d)*Tan[e + f*x] + 3 *b^2*(b*c + 3*a*d)*Tan[e + f*x]^2 + 2*b^3*d*Tan[e + f*x]^3)/(6*f)
Time = 0.61 (sec) , antiderivative size = 140, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {3042, 4011, 3042, 4011, 3042, 4008, 3042, 3956}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x))dx\) |
| \(\Big \downarrow \) 4011 |
| \(\displaystyle \int (a+b \tan (e+f x))^2 (a c-b d+(b c+a d) \tan (e+f x))dx+\frac {d (a+b \tan (e+f x))^3}{3 f}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int (a+b \tan (e+f x))^2 (a c-b d+(b c+a d) \tan (e+f x))dx+\frac {d (a+b \tan (e+f x))^3}{3 f}\) |
| \(\Big \downarrow \) 4011 |
| \(\displaystyle \int (a+b \tan (e+f x)) \left (c a^2-2 b d a-b^2 c+\left (d a^2+2 b c a-b^2 d\right ) \tan (e+f x)\right )dx+\frac {(a d+b c) (a+b \tan (e+f x))^2}{2 f}+\frac {d (a+b \tan (e+f x))^3}{3 f}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int (a+b \tan (e+f x)) \left (c a^2-2 b d a-b^2 c+\left (d a^2+2 b c a-b^2 d\right ) \tan (e+f x)\right )dx+\frac {(a d+b c) (a+b \tan (e+f x))^2}{2 f}+\frac {d (a+b \tan (e+f x))^3}{3 f}\) |
| \(\Big \downarrow \) 4008 |
| \(\displaystyle \left (a^3 d+3 a^2 b c-3 a b^2 d-b^3 c\right ) \int \tan (e+f x)dx+\frac {b \left (a^2 d+2 a b c-b^2 d\right ) \tan (e+f x)}{f}+x \left (a^3 c-3 a^2 b d-3 a b^2 c+b^3 d\right )+\frac {(a d+b c) (a+b \tan (e+f x))^2}{2 f}+\frac {d (a+b \tan (e+f x))^3}{3 f}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \left (a^3 d+3 a^2 b c-3 a b^2 d-b^3 c\right ) \int \tan (e+f x)dx+\frac {b \left (a^2 d+2 a b c-b^2 d\right ) \tan (e+f x)}{f}+x \left (a^3 c-3 a^2 b d-3 a b^2 c+b^3 d\right )+\frac {(a d+b c) (a+b \tan (e+f x))^2}{2 f}+\frac {d (a+b \tan (e+f x))^3}{3 f}\) |
| \(\Big \downarrow \) 3956 |
| \(\displaystyle \frac {b \left (a^2 d+2 a b c-b^2 d\right ) \tan (e+f x)}{f}-\frac {\left (a^3 d+3 a^2 b c-3 a b^2 d-b^3 c\right ) \log (\cos (e+f x))}{f}+x \left (a^3 c-3 a^2 b d-3 a b^2 c+b^3 d\right )+\frac {(a d+b c) (a+b \tan (e+f x))^2}{2 f}+\frac {d (a+b \tan (e+f x))^3}{3 f}\) |
Input:
Int[(a + b*Tan[e + f*x])^3*(c + d*Tan[e + f*x]),x]
Output:
(a^3*c - 3*a*b^2*c - 3*a^2*b*d + b^3*d)*x - ((3*a^2*b*c - b^3*c + a^3*d - 3*a*b^2*d)*Log[Cos[e + f*x]])/f + (b*(2*a*b*c + a^2*d - b^2*d)*Tan[e + f*x ])/f + ((b*c + a*d)*(a + b*Tan[e + f*x])^2)/(2*f) + (d*(a + b*Tan[e + f*x] )^3)/(3*f)
Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-Log[RemoveContent[Cos[c + d *x], x]]/d, x] /; FreeQ[{c, d}, x]
Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.) *(x_)]), x_Symbol] :> Simp[(a*c - b*d)*x, x] + (Simp[b*d*(Tan[e + f*x]/f), x] + Simp[(b*c + a*d) Int[Tan[e + f*x], x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[b*c + a*d, 0]
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[d*((a + b*Tan[e + f*x])^m/(f*m)), x] + Int [(a + b*Tan[e + f*x])^(m - 1)*Simp[a*c - b*d + (b*c + a*d)*Tan[e + f*x], x] , x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && GtQ[m, 0]
Time = 0.15 (sec) , antiderivative size = 141, normalized size of antiderivative = 1.01
| method | result | size |
| norman | \(\left (a^{3} c -3 a^{2} b d -3 a \,b^{2} c +b^{3} d \right ) x +\frac {b \left (3 a^{2} d +3 a b c -b^{2} d \right ) \tan \left (f x +e \right )}{f}+\frac {b^{2} \left (3 a d +b c \right ) \tan \left (f x +e \right )^{2}}{2 f}+\frac {b^{3} d \tan \left (f x +e \right )^{3}}{3 f}+\frac {\left (a^{3} d +3 a^{2} b c -3 a \,b^{2} d -b^{3} c \right ) \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f}\) | \(141\) |
| parts | \(a^{3} c x +\frac {\left (3 a \,b^{2} d +b^{3} c \right ) \left (\frac {\tan \left (f x +e \right )^{2}}{2}-\frac {\ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2}\right )}{f}+\frac {\left (3 a^{2} b d +3 a \,b^{2} c \right ) \left (\tan \left (f x +e \right )-\arctan \left (\tan \left (f x +e \right )\right )\right )}{f}+\frac {\left (a^{3} d +3 a^{2} b c \right ) \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f}+\frac {b^{3} d \left (\frac {\tan \left (f x +e \right )^{3}}{3}-\tan \left (f x +e \right )+\arctan \left (\tan \left (f x +e \right )\right )\right )}{f}\) | \(147\) |
| derivativedivides | \(\frac {\frac {b^{3} d \tan \left (f x +e \right )^{3}}{3}+\frac {3 a \,b^{2} d \tan \left (f x +e \right )^{2}}{2}+\frac {b^{3} c \tan \left (f x +e \right )^{2}}{2}+3 \tan \left (f x +e \right ) a^{2} b d +3 \tan \left (f x +e \right ) a \,b^{2} c -\tan \left (f x +e \right ) b^{3} d +\frac {\left (a^{3} d +3 a^{2} b c -3 a \,b^{2} d -b^{3} c \right ) \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2}+\left (a^{3} c -3 a^{2} b d -3 a \,b^{2} c +b^{3} d \right ) \arctan \left (\tan \left (f x +e \right )\right )}{f}\) | \(159\) |
| default | \(\frac {\frac {b^{3} d \tan \left (f x +e \right )^{3}}{3}+\frac {3 a \,b^{2} d \tan \left (f x +e \right )^{2}}{2}+\frac {b^{3} c \tan \left (f x +e \right )^{2}}{2}+3 \tan \left (f x +e \right ) a^{2} b d +3 \tan \left (f x +e \right ) a \,b^{2} c -\tan \left (f x +e \right ) b^{3} d +\frac {\left (a^{3} d +3 a^{2} b c -3 a \,b^{2} d -b^{3} c \right ) \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2}+\left (a^{3} c -3 a^{2} b d -3 a \,b^{2} c +b^{3} d \right ) \arctan \left (\tan \left (f x +e \right )\right )}{f}\) | \(159\) |
| parallelrisch | \(\frac {2 b^{3} d \tan \left (f x +e \right )^{3}+6 a^{3} c f x -18 a^{2} b d f x -18 a \,b^{2} c f x +6 b^{3} d f x +9 a \,b^{2} d \tan \left (f x +e \right )^{2}+3 b^{3} c \tan \left (f x +e \right )^{2}+3 \ln \left (1+\tan \left (f x +e \right )^{2}\right ) a^{3} d +9 \ln \left (1+\tan \left (f x +e \right )^{2}\right ) a^{2} b c -9 \ln \left (1+\tan \left (f x +e \right )^{2}\right ) a \,b^{2} d -3 \ln \left (1+\tan \left (f x +e \right )^{2}\right ) b^{3} c +18 \tan \left (f x +e \right ) a^{2} b d +18 \tan \left (f x +e \right ) a \,b^{2} c -6 \tan \left (f x +e \right ) b^{3} d}{6 f}\) | \(192\) |
| risch | \(a^{3} c x -3 a^{2} b d x -3 a \,b^{2} c x +b^{3} d x -\frac {2 i b^{3} c e}{f}-i b^{3} c x +3 i a^{2} b c x +i a^{3} d x -3 i a \,b^{2} d x +\frac {2 i a^{3} d e}{f}+\frac {2 i b \left (9 a^{2} d \,{\mathrm e}^{4 i \left (f x +e \right )}+9 a b c \,{\mathrm e}^{4 i \left (f x +e \right )}-6 b^{2} d \,{\mathrm e}^{4 i \left (f x +e \right )}-9 i a b d \,{\mathrm e}^{4 i \left (f x +e \right )}-3 i b^{2} c \,{\mathrm e}^{4 i \left (f x +e \right )}+18 a^{2} d \,{\mathrm e}^{2 i \left (f x +e \right )}+18 a b c \,{\mathrm e}^{2 i \left (f x +e \right )}-6 b^{2} d \,{\mathrm e}^{2 i \left (f x +e \right )}-9 i a b d \,{\mathrm e}^{2 i \left (f x +e \right )}-3 i b^{2} c \,{\mathrm e}^{2 i \left (f x +e \right )}+9 a^{2} d +9 a b c -4 b^{2} d \right )}{3 f \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{3}}+\frac {6 i a^{2} b c e}{f}-\frac {6 i a \,b^{2} d e}{f}-\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) a^{3} d}{f}-\frac {3 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) a^{2} b c}{f}+\frac {3 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) a \,b^{2} d}{f}+\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) b^{3} c}{f}\) | \(383\) |
Input:
int((a+b*tan(f*x+e))^3*(c+d*tan(f*x+e)),x,method=_RETURNVERBOSE)
Output:
(a^3*c-3*a^2*b*d-3*a*b^2*c+b^3*d)*x+b*(3*a^2*d+3*a*b*c-b^2*d)/f*tan(f*x+e) +1/2*b^2*(3*a*d+b*c)/f*tan(f*x+e)^2+1/3*b^3*d/f*tan(f*x+e)^3+1/2*(a^3*d+3* a^2*b*c-3*a*b^2*d-b^3*c)/f*ln(1+tan(f*x+e)^2)
Time = 0.09 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.05 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=\frac {2 \, b^{3} d \tan \left (f x + e\right )^{3} + 6 \, {\left ({\left (a^{3} - 3 \, a b^{2}\right )} c - {\left (3 \, a^{2} b - b^{3}\right )} d\right )} f x + 3 \, {\left (b^{3} c + 3 \, a b^{2} d\right )} \tan \left (f x + e\right )^{2} - 3 \, {\left ({\left (3 \, a^{2} b - b^{3}\right )} c + {\left (a^{3} - 3 \, a b^{2}\right )} d\right )} \log \left (\frac {1}{\tan \left (f x + e\right )^{2} + 1}\right ) + 6 \, {\left (3 \, a b^{2} c + {\left (3 \, a^{2} b - b^{3}\right )} d\right )} \tan \left (f x + e\right )}{6 \, f} \] Input:
integrate((a+b*tan(f*x+e))^3*(c+d*tan(f*x+e)),x, algorithm="fricas")
Output:
1/6*(2*b^3*d*tan(f*x + e)^3 + 6*((a^3 - 3*a*b^2)*c - (3*a^2*b - b^3)*d)*f* x + 3*(b^3*c + 3*a*b^2*d)*tan(f*x + e)^2 - 3*((3*a^2*b - b^3)*c + (a^3 - 3 *a*b^2)*d)*log(1/(tan(f*x + e)^2 + 1)) + 6*(3*a*b^2*c + (3*a^2*b - b^3)*d) *tan(f*x + e))/f
Time = 0.19 (sec) , antiderivative size = 240, normalized size of antiderivative = 1.71 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=\begin {cases} a^{3} c x + \frac {a^{3} d \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 f} + \frac {3 a^{2} b c \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 f} - 3 a^{2} b d x + \frac {3 a^{2} b d \tan {\left (e + f x \right )}}{f} - 3 a b^{2} c x + \frac {3 a b^{2} c \tan {\left (e + f x \right )}}{f} - \frac {3 a b^{2} d \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 f} + \frac {3 a b^{2} d \tan ^{2}{\left (e + f x \right )}}{2 f} - \frac {b^{3} c \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 f} + \frac {b^{3} c \tan ^{2}{\left (e + f x \right )}}{2 f} + b^{3} d x + \frac {b^{3} d \tan ^{3}{\left (e + f x \right )}}{3 f} - \frac {b^{3} d \tan {\left (e + f x \right )}}{f} & \text {for}\: f \neq 0 \\x \left (a + b \tan {\left (e \right )}\right )^{3} \left (c + d \tan {\left (e \right )}\right ) & \text {otherwise} \end {cases} \] Input:
integrate((a+b*tan(f*x+e))**3*(c+d*tan(f*x+e)),x)
Output:
Piecewise((a**3*c*x + a**3*d*log(tan(e + f*x)**2 + 1)/(2*f) + 3*a**2*b*c*l og(tan(e + f*x)**2 + 1)/(2*f) - 3*a**2*b*d*x + 3*a**2*b*d*tan(e + f*x)/f - 3*a*b**2*c*x + 3*a*b**2*c*tan(e + f*x)/f - 3*a*b**2*d*log(tan(e + f*x)**2 + 1)/(2*f) + 3*a*b**2*d*tan(e + f*x)**2/(2*f) - b**3*c*log(tan(e + f*x)** 2 + 1)/(2*f) + b**3*c*tan(e + f*x)**2/(2*f) + b**3*d*x + b**3*d*tan(e + f* x)**3/(3*f) - b**3*d*tan(e + f*x)/f, Ne(f, 0)), (x*(a + b*tan(e))**3*(c + d*tan(e)), True))
Time = 0.11 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.06 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=\frac {2 \, b^{3} d \tan \left (f x + e\right )^{3} + 3 \, {\left (b^{3} c + 3 \, a b^{2} d\right )} \tan \left (f x + e\right )^{2} + 6 \, {\left ({\left (a^{3} - 3 \, a b^{2}\right )} c - {\left (3 \, a^{2} b - b^{3}\right )} d\right )} {\left (f x + e\right )} + 3 \, {\left ({\left (3 \, a^{2} b - b^{3}\right )} c + {\left (a^{3} - 3 \, a b^{2}\right )} d\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right ) + 6 \, {\left (3 \, a b^{2} c + {\left (3 \, a^{2} b - b^{3}\right )} d\right )} \tan \left (f x + e\right )}{6 \, f} \] Input:
integrate((a+b*tan(f*x+e))^3*(c+d*tan(f*x+e)),x, algorithm="maxima")
Output:
1/6*(2*b^3*d*tan(f*x + e)^3 + 3*(b^3*c + 3*a*b^2*d)*tan(f*x + e)^2 + 6*((a ^3 - 3*a*b^2)*c - (3*a^2*b - b^3)*d)*(f*x + e) + 3*((3*a^2*b - b^3)*c + (a ^3 - 3*a*b^2)*d)*log(tan(f*x + e)^2 + 1) + 6*(3*a*b^2*c + (3*a^2*b - b^3)* d)*tan(f*x + e))/f
Time = 0.28 (sec) , antiderivative size = 182, normalized size of antiderivative = 1.30 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=\frac {{\left (a^{3} c - 3 \, a b^{2} c - 3 \, a^{2} b d + b^{3} d\right )} {\left (f x + e\right )}}{f} + \frac {{\left (3 \, a^{2} b c - b^{3} c + a^{3} d - 3 \, a b^{2} d\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right )}{2 \, f} + \frac {2 \, b^{3} d f^{2} \tan \left (f x + e\right )^{3} + 3 \, b^{3} c f^{2} \tan \left (f x + e\right )^{2} + 9 \, a b^{2} d f^{2} \tan \left (f x + e\right )^{2} + 18 \, a b^{2} c f^{2} \tan \left (f x + e\right ) + 18 \, a^{2} b d f^{2} \tan \left (f x + e\right ) - 6 \, b^{3} d f^{2} \tan \left (f x + e\right )}{6 \, f^{3}} \] Input:
integrate((a+b*tan(f*x+e))^3*(c+d*tan(f*x+e)),x, algorithm="giac")
Output:
(a^3*c - 3*a*b^2*c - 3*a^2*b*d + b^3*d)*(f*x + e)/f + 1/2*(3*a^2*b*c - b^3 *c + a^3*d - 3*a*b^2*d)*log(tan(f*x + e)^2 + 1)/f + 1/6*(2*b^3*d*f^2*tan(f *x + e)^3 + 3*b^3*c*f^2*tan(f*x + e)^2 + 9*a*b^2*d*f^2*tan(f*x + e)^2 + 18 *a*b^2*c*f^2*tan(f*x + e) + 18*a^2*b*d*f^2*tan(f*x + e) - 6*b^3*d*f^2*tan( f*x + e))/f^3
Time = 2.31 (sec) , antiderivative size = 141, normalized size of antiderivative = 1.01 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=x\,\left (c\,a^3-3\,d\,a^2\,b-3\,c\,a\,b^2+d\,b^3\right )-\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (b^3\,d-3\,a\,b\,\left (a\,d+b\,c\right )\right )}{f}+\frac {{\mathrm {tan}\left (e+f\,x\right )}^2\,\left (\frac {c\,b^3}{2}+\frac {3\,a\,d\,b^2}{2}\right )}{f}+\frac {\ln \left ({\mathrm {tan}\left (e+f\,x\right )}^2+1\right )\,\left (\frac {d\,a^3}{2}+\frac {3\,c\,a^2\,b}{2}-\frac {3\,d\,a\,b^2}{2}-\frac {c\,b^3}{2}\right )}{f}+\frac {b^3\,d\,{\mathrm {tan}\left (e+f\,x\right )}^3}{3\,f} \] Input:
int((a + b*tan(e + f*x))^3*(c + d*tan(e + f*x)),x)
Output:
x*(a^3*c + b^3*d - 3*a*b^2*c - 3*a^2*b*d) - (tan(e + f*x)*(b^3*d - 3*a*b*( a*d + b*c)))/f + (tan(e + f*x)^2*((b^3*c)/2 + (3*a*b^2*d)/2))/f + (log(tan (e + f*x)^2 + 1)*((a^3*d)/2 - (b^3*c)/2 + (3*a^2*b*c)/2 - (3*a*b^2*d)/2))/ f + (b^3*d*tan(e + f*x)^3)/(3*f)
Time = 0.26 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.36 \[ \int (a+b \tan (e+f x))^3 (c+d \tan (e+f x)) \, dx=\frac {3 \,\mathrm {log}\left (\tan \left (f x +e \right )^{2}+1\right ) a^{3} d +9 \,\mathrm {log}\left (\tan \left (f x +e \right )^{2}+1\right ) a^{2} b c -9 \,\mathrm {log}\left (\tan \left (f x +e \right )^{2}+1\right ) a \,b^{2} d -3 \,\mathrm {log}\left (\tan \left (f x +e \right )^{2}+1\right ) b^{3} c +2 \tan \left (f x +e \right )^{3} b^{3} d +9 \tan \left (f x +e \right )^{2} a \,b^{2} d +3 \tan \left (f x +e \right )^{2} b^{3} c +18 \tan \left (f x +e \right ) a^{2} b d +18 \tan \left (f x +e \right ) a \,b^{2} c -6 \tan \left (f x +e \right ) b^{3} d +6 a^{3} c f x -18 a^{2} b d f x -18 a \,b^{2} c f x +6 b^{3} d f x}{6 f} \] Input:
int((a+b*tan(f*x+e))^3*(c+d*tan(f*x+e)),x)
Output:
(3*log(tan(e + f*x)**2 + 1)*a**3*d + 9*log(tan(e + f*x)**2 + 1)*a**2*b*c - 9*log(tan(e + f*x)**2 + 1)*a*b**2*d - 3*log(tan(e + f*x)**2 + 1)*b**3*c + 2*tan(e + f*x)**3*b**3*d + 9*tan(e + f*x)**2*a*b**2*d + 3*tan(e + f*x)**2 *b**3*c + 18*tan(e + f*x)*a**2*b*d + 18*tan(e + f*x)*a*b**2*c - 6*tan(e + f*x)*b**3*d + 6*a**3*c*f*x - 18*a**2*b*d*f*x - 18*a*b**2*c*f*x + 6*b**3*d* f*x)/(6*f)