Integrand size = 30, antiderivative size = 99 \[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\frac {\operatorname {AppellF1}(1+n p,1-m,1,2+n p,-i \tan (e+f x),i \tan (e+f x)) (1+i \tan (e+f x))^{-m} \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m}{f (1+n p)} \] Output:
AppellF1(n*p+1,1-m,1,n*p+2,-I*tan(f*x+e),I*tan(f*x+e))*tan(f*x+e)*(c*(d*ta n(f*x+e))^p)^n*(a+I*a*tan(f*x+e))^m/f/(n*p+1)/((1+I*tan(f*x+e))^m)
\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx \] Input:
Integrate[(c*(d*Tan[e + f*x])^p)^n*(a + I*a*Tan[e + f*x])^m,x]
Output:
Integrate[(c*(d*Tan[e + f*x])^p)^n*(a + I*a*Tan[e + f*x])^m, x]
Time = 0.45 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {3042, 4061, 3042, 4047, 25, 27, 152, 150}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (a+i a \tan (e+f x))^m \left (c (d \tan (e+f x))^p\right )^n \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int (a+i a \tan (e+f x))^m \left (c (d \tan (e+f x))^p\right )^ndx\) |
\(\Big \downarrow \) 4061 |
\(\displaystyle (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n \int (d \tan (e+f x))^{n p} (i \tan (e+f x) a+a)^mdx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n \int (d \tan (e+f x))^{n p} (i \tan (e+f x) a+a)^mdx\) |
\(\Big \downarrow \) 4047 |
\(\displaystyle \frac {i a^2 (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n \int -\frac {(d \tan (e+f x))^{n p} (i \tan (e+f x) a+a)^{m-1}}{a (a-i a \tan (e+f x))}d(i a \tan (e+f x))}{f}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {i a^2 (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n \int \frac {(d \tan (e+f x))^{n p} (i \tan (e+f x) a+a)^{m-1}}{a (a-i a \tan (e+f x))}d(i a \tan (e+f x))}{f}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {i a (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n \int \frac {(d \tan (e+f x))^{n p} (i \tan (e+f x) a+a)^{m-1}}{a-i a \tan (e+f x)}d(i a \tan (e+f x))}{f}\) |
\(\Big \downarrow \) 152 |
\(\displaystyle -\frac {i (1+i \tan (e+f x))^{-m} (a+i a \tan (e+f x))^m (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n \int \frac {(i \tan (e+f x)+1)^{m-1} (d \tan (e+f x))^{n p}}{a-i a \tan (e+f x)}d(i a \tan (e+f x))}{f}\) |
\(\Big \downarrow \) 150 |
\(\displaystyle \frac {\tan (e+f x) (1+i \tan (e+f x))^{-m} (a+i a \tan (e+f x))^m \operatorname {AppellF1}(n p+1,1-m,1,n p+2,-i \tan (e+f x),i \tan (e+f x)) \left (c (d \tan (e+f x))^p\right )^n}{f (n p+1)}\) |
Input:
Int[(c*(d*Tan[e + f*x])^p)^n*(a + I*a*Tan[e + f*x])^m,x]
Output:
(AppellF1[1 + n*p, 1 - m, 1, 2 + n*p, (-I)*Tan[e + f*x], I*Tan[e + f*x]]*T an[e + f*x]*(c*(d*Tan[e + f*x])^p)^n*(a + I*a*Tan[e + f*x])^m)/(f*(1 + n*p )*(1 + I*Tan[e + f*x])^m)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^n*e^p*((b*x)^(m + 1)/(b*(m + 1)))*AppellF1[m + 1, -n, -p, m + 2 , (-d)*(x/c), (-f)*(x/e)], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !In tegerQ[m] && !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^IntPart[n]*((c + d*x)^FracPart[n]/(1 + d*(x/c))^FracPart[n]) Int[(b*x)^m*(1 + d*(x/c))^n*(e + f*x)^p, x], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !IntegerQ[m] && !IntegerQ[n] && !GtQ[c, 0]
Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[a*(b/f) Subst[Int[(a + x)^(m - 1)*(( c + (d/b)*x)^n/(b^2 + a*x)), x], x, b*Tan[e + f*x]], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 + b^2, 0] && NeQ[c^2 + d ^2, 0]
Int[((c_.)*((d_.)*tan[(e_.) + (f_.)*(x_)])^(p_))^(n_)*((a_.) + (b_.)*tan[(e _.) + (f_.)*(x_)])^(m_.), x_Symbol] :> Simp[c^IntPart[n]*((c*(d*Tan[e + f*x ])^p)^FracPart[n]/(d*Tan[e + f*x])^(p*FracPart[n])) Int[(a + b*Tan[e + f* x])^m*(d*Tan[e + f*x])^(n*p), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && !IntegerQ[n] && !IntegerQ[m]
\[\int \left (c \left (d \tan \left (f x +e \right )\right )^{p}\right )^{n} \left (a +i a \tan \left (f x +e \right )\right )^{m}d x\]
Input:
int((c*(d*tan(f*x+e))^p)^n*(a+I*a*tan(f*x+e))^m,x)
Output:
int((c*(d*tan(f*x+e))^p)^n*(a+I*a*tan(f*x+e))^m,x)
\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\int { \left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n} {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \] Input:
integrate((c*(d*tan(f*x+e))^p)^n*(a+I*a*tan(f*x+e))^m,x, algorithm="fricas ")
Output:
integral((2*a*e^(2*I*f*x + 2*I*e)/(e^(2*I*f*x + 2*I*e) + 1))^m*e^(n*p*log( (-I*d*e^(2*I*f*x + 2*I*e) + I*d)/(e^(2*I*f*x + 2*I*e) + 1)) + n*log(c)), x )
\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\int \left (c \left (d \tan {\left (e + f x \right )}\right )^{p}\right )^{n} \left (i a \left (\tan {\left (e + f x \right )} - i\right )\right )^{m}\, dx \] Input:
integrate((c*(d*tan(f*x+e))**p)**n*(a+I*a*tan(f*x+e))**m,x)
Output:
Integral((c*(d*tan(e + f*x))**p)**n*(I*a*(tan(e + f*x) - I))**m, x)
\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\int { \left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n} {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \] Input:
integrate((c*(d*tan(f*x+e))^p)^n*(a+I*a*tan(f*x+e))^m,x, algorithm="maxima ")
Output:
integrate(((d*tan(f*x + e))^p*c)^n*(I*a*tan(f*x + e) + a)^m, x)
\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\int { \left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n} {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \] Input:
integrate((c*(d*tan(f*x+e))^p)^n*(a+I*a*tan(f*x+e))^m,x, algorithm="giac")
Output:
integrate(((d*tan(f*x + e))^p*c)^n*(I*a*tan(f*x + e) + a)^m, x)
Timed out. \[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\int {\left (c\,{\left (d\,\mathrm {tan}\left (e+f\,x\right )\right )}^p\right )}^n\,{\left (a+a\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^m \,d x \] Input:
int((c*(d*tan(e + f*x))^p)^n*(a + a*tan(e + f*x)*1i)^m,x)
Output:
int((c*(d*tan(e + f*x))^p)^n*(a + a*tan(e + f*x)*1i)^m, x)
\[ \int \left (c (d \tan (e+f x))^p\right )^n (a+i a \tan (e+f x))^m \, dx=\frac {d^{n p} c^{n} i \left (-\tan \left (f x +e \right )^{n p} \left (\tan \left (f x +e \right ) a i +a \right )^{m}+\left (\int \frac {\tan \left (f x +e \right )^{n p} \left (\tan \left (f x +e \right ) a i +a \right )^{m}}{\tan \left (f x +e \right )}d x \right ) f n p +\left (\int \tan \left (f x +e \right )^{n p} \left (\tan \left (f x +e \right ) a i +a \right )^{m} \tan \left (f x +e \right )d x \right ) f m +\left (\int \tan \left (f x +e \right )^{n p} \left (\tan \left (f x +e \right ) a i +a \right )^{m} \tan \left (f x +e \right )d x \right ) f n p \right )}{f m} \] Input:
int((c*(d*tan(f*x+e))^p)^n*(a+I*a*tan(f*x+e))^m,x)
Output:
(d**(n*p)*c**n*i*( - tan(e + f*x)**(n*p)*(tan(e + f*x)*a*i + a)**m + int(( tan(e + f*x)**(n*p)*(tan(e + f*x)*a*i + a)**m)/tan(e + f*x),x)*f*n*p + int (tan(e + f*x)**(n*p)*(tan(e + f*x)*a*i + a)**m*tan(e + f*x),x)*f*m + int(t an(e + f*x)**(n*p)*(tan(e + f*x)*a*i + a)**m*tan(e + f*x),x)*f*n*p))/(f*m)