\(\int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx\) [268]

Optimal result
Mathematica [F]
Rubi [A] (warning: unable to verify)
Maple [F]
Fricas [F(-1)]
Sympy [F]
Maxima [F(-2)]
Giac [F(-2)]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 28, antiderivative size = 84 \[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx=\frac {3 \operatorname {AppellF1}\left (\frac {4}{3},\frac {5}{2},1,\frac {7}{3},-i \tan (c+d x),i \tan (c+d x)\right ) \sqrt {1+i \tan (c+d x)} \tan ^{\frac {4}{3}}(c+d x)}{4 a d \sqrt {a+i a \tan (c+d x)}} \] Output:

3/4*AppellF1(4/3,5/2,1,7/3,-I*tan(d*x+c),I*tan(d*x+c))*(1+I*tan(d*x+c))^(1 
/2)*tan(d*x+c)^(4/3)/a/d/(a+I*a*tan(d*x+c))^(1/2)
                                                                                    
                                                                                    
 

Mathematica [F]

\[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx=\int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx \] Input:

Integrate[Tan[c + d*x]^(1/3)/(a + I*a*Tan[c + d*x])^(3/2),x]
 

Output:

Integrate[Tan[c + d*x]^(1/3)/(a + I*a*Tan[c + d*x])^(3/2), x]
 

Rubi [A] (warning: unable to verify)

Time = 0.34 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.07, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3042, 4047, 25, 27, 148, 27, 1013, 1012}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}}dx\)

\(\Big \downarrow \) 4047

\(\displaystyle \frac {i a^2 \int -\frac {\sqrt [3]{\tan (c+d x)}}{a (a-i a \tan (c+d x)) (i \tan (c+d x) a+a)^{5/2}}d(i a \tan (c+d x))}{d}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {i a^2 \int \frac {\sqrt [3]{\tan (c+d x)}}{a (a-i a \tan (c+d x)) (i \tan (c+d x) a+a)^{5/2}}d(i a \tan (c+d x))}{d}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {i a \int \frac {\sqrt [3]{\tan (c+d x)}}{(a-i a \tan (c+d x)) (i \tan (c+d x) a+a)^{5/2}}d(i a \tan (c+d x))}{d}\)

\(\Big \downarrow \) 148

\(\displaystyle \frac {3 a^2 \int -\frac {i a^2 \tan ^3(c+d x)}{\left (1-a^3 \tan ^3(c+d x)\right ) \left (\tan ^3(c+d x) a^4+a\right )^{5/2}}d\sqrt [3]{\tan (c+d x)}}{d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {3 a \int -\frac {i a^3 \tan ^3(c+d x)}{\left (1-a^3 \tan ^3(c+d x)\right ) \left (\tan ^3(c+d x) a^4+a\right )^{5/2}}d\sqrt [3]{\tan (c+d x)}}{d}\)

\(\Big \downarrow \) 1013

\(\displaystyle \frac {3 \sqrt {a^3 \tan ^3(c+d x)+1} \int -\frac {i a^3 \tan ^3(c+d x)}{\left (1-a^3 \tan ^3(c+d x)\right ) \left (a^3 \tan ^3(c+d x)+1\right )^{5/2}}d\sqrt [3]{\tan (c+d x)}}{a d \sqrt {a^4 \tan ^3(c+d x)+a}}\)

\(\Big \downarrow \) 1012

\(\displaystyle \frac {3 a^3 \tan ^4(c+d x) \sqrt {a^3 \tan ^3(c+d x)+1} \operatorname {AppellF1}\left (\frac {4}{3},1,\frac {5}{2},\frac {7}{3},a^3 \tan ^3(c+d x),-a^3 \tan ^3(c+d x)\right )}{4 d \sqrt {a^4 \tan ^3(c+d x)+a}}\)

Input:

Int[Tan[c + d*x]^(1/3)/(a + I*a*Tan[c + d*x])^(3/2),x]
 

Output:

(3*a^3*AppellF1[4/3, 1, 5/2, 7/3, a^3*Tan[c + d*x]^3, -(a^3*Tan[c + d*x]^3 
)]*Tan[c + d*x]^4*Sqrt[1 + a^3*Tan[c + d*x]^3])/(4*d*Sqrt[a + a^4*Tan[c + 
d*x]^3])
 

Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 148
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))^(p_.), 
x_] :> With[{k = Denominator[m]}, Simp[k/b   Subst[Int[x^(k*(m + 1) - 1)*(c 
 + d*(x^k/b))^n*(e + f*(x^k/b))^p, x], x, (b*x)^(1/k)], x]] /; FreeQ[{b, c, 
 d, e, f, n, p}, x] && FractionQ[m] && IntegerQ[p]
 

rule 1012
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ 
))^(q_), x_Symbol] :> Simp[a^p*c^q*((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m 
+ 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; FreeQ[{a, 
 b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n 
 - 1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
 

rule 1013
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ 
))^(q_), x_Symbol] :> Simp[a^IntPart[p]*((a + b*x^n)^FracPart[p]/(1 + b*(x^ 
n/a))^FracPart[p])   Int[(e*x)^m*(1 + b*(x^n/a))^p*(c + d*x^n)^q, x], x] /; 
 FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] & 
& NeQ[m, n - 1] &&  !(IntegerQ[p] || GtQ[a, 0])
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4047
Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
(f_.)*(x_)])^(n_), x_Symbol] :> Simp[a*(b/f)   Subst[Int[(a + x)^(m - 1)*(( 
c + (d/b)*x)^n/(b^2 + a*x)), x], x, b*Tan[e + f*x]], x] /; FreeQ[{a, b, c, 
d, e, f, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 + b^2, 0] && NeQ[c^2 + d 
^2, 0]
 
Maple [F]

\[\int \frac {\tan \left (d x +c \right )^{\frac {1}{3}}}{\left (a +i a \tan \left (d x +c \right )\right )^{\frac {3}{2}}}d x\]

Input:

int(tan(d*x+c)^(1/3)/(a+I*a*tan(d*x+c))^(3/2),x)
 

Output:

int(tan(d*x+c)^(1/3)/(a+I*a*tan(d*x+c))^(3/2),x)
 

Fricas [F(-1)]

Timed out. \[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx=\text {Timed out} \] Input:

integrate(tan(d*x+c)^(1/3)/(a+I*a*tan(d*x+c))^(3/2),x, algorithm="fricas")
 

Output:

Timed out
 

Sympy [F]

\[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx=\int \frac {\sqrt [3]{\tan {\left (c + d x \right )}}}{\left (i a \left (\tan {\left (c + d x \right )} - i\right )\right )^{\frac {3}{2}}}\, dx \] Input:

integrate(tan(d*x+c)**(1/3)/(a+I*a*tan(d*x+c))**(3/2),x)
 

Output:

Integral(tan(c + d*x)**(1/3)/(I*a*(tan(c + d*x) - I))**(3/2), x)
 

Maxima [F(-2)]

Exception generated. \[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx=\text {Exception raised: RuntimeError} \] Input:

integrate(tan(d*x+c)^(1/3)/(a+I*a*tan(d*x+c))^(3/2),x, algorithm="maxima")
 

Output:

Exception raised: RuntimeError >> ECL says: THROW: The catch RAT-ERR is un 
defined.
 

Giac [F(-2)]

Exception generated. \[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx=\text {Exception raised: TypeError} \] Input:

integrate(tan(d*x+c)^(1/3)/(a+I*a*tan(d*x+c))^(3/2),x, algorithm="giac")
 

Output:

Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:Degree mismatch inside factorisatio 
n over extensionUnable to transpose Error: Bad Argument ValueDone
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx=\int \frac {{\mathrm {tan}\left (c+d\,x\right )}^{1/3}}{{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{3/2}} \,d x \] Input:

int(tan(c + d*x)^(1/3)/(a + a*tan(c + d*x)*1i)^(3/2),x)
 

Output:

int(tan(c + d*x)^(1/3)/(a + a*tan(c + d*x)*1i)^(3/2), x)
 

Reduce [F]

\[ \int \frac {\sqrt [3]{\tan (c+d x)}}{(a+i a \tan (c+d x))^{3/2}} \, dx =\text {Too large to display} \] Input:

int(tan(d*x+c)^(1/3)/(a+I*a*tan(d*x+c))^(3/2),x)
 

Output:

(sqrt(a)*( - 12*tan(c + d*x)**(1/3)*sqrt(tan(c + d*x)*i + 1)*i - 141854339 
2358400000*int(( - tan(c + d*x)**(1/3)*sqrt(tan(c + d*x)*i + 1)*tan(c + d* 
x)**2)/(67549685350400000*tan(c + d*x)**3*a**2*i + 67549685350400000*tan(c 
 + d*x)**2*a**2 + 67549685350400000*tan(c + d*x)*a**2*i + 6754968535040000 
0*a**2),x)*tan(c + d*x)**2*a**2*d - 1418543392358400000*int(( - tan(c + d* 
x)**(1/3)*sqrt(tan(c + d*x)*i + 1)*tan(c + d*x)**2)/(67549685350400000*tan 
(c + d*x)**3*a**2*i + 67549685350400000*tan(c + d*x)**2*a**2 + 67549685350 
400000*tan(c + d*x)*a**2*i + 67549685350400000*a**2),x)*a**2*d + 202649056 
0512000000*int(( - tan(c + d*x)**(1/3)*sqrt(tan(c + d*x)*i + 1)*tan(c + d* 
x))/(67549685350400000*tan(c + d*x)**3*a**2*i + 67549685350400000*tan(c + 
d*x)**2*a**2 + 67549685350400000*tan(c + d*x)*a**2*i + 67549685350400000*a 
**2),x)*tan(c + d*x)**2*a**2*d*i + 2026490560512000000*int(( - tan(c + d*x 
)**(1/3)*sqrt(tan(c + d*x)*i + 1)*tan(c + d*x))/(67549685350400000*tan(c + 
 d*x)**3*a**2*i + 67549685350400000*tan(c + d*x)**2*a**2 + 675496853504000 
00*tan(c + d*x)*a**2*i + 67549685350400000*a**2),x)*a**2*d*i - 40529811210 
2400000*int(( - tan(c + d*x)**(1/3)*sqrt(tan(c + d*x)*i + 1))/(67549685350 
400000*tan(c + d*x)**4*a**2*i + 67549685350400000*tan(c + d*x)**3*a**2 + 6 
7549685350400000*tan(c + d*x)**2*a**2*i + 67549685350400000*tan(c + d*x)*a 
**2),x)*tan(c + d*x)**2*a**2*d*i - 405298112102400000*int(( - tan(c + d*x) 
**(1/3)*sqrt(tan(c + d*x)*i + 1))/(67549685350400000*tan(c + d*x)**4*a*...