\(\int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx\) [590]

Optimal result

Integrand size = 23, antiderivative size = 248 \[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=-\frac {(a+b) \arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} \left (a^2+b^2\right ) d}+\frac {(a+b) \arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2} \left (a^2+b^2\right ) d}-\frac {2 b^{9/2} \arctan \left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a}}\right )}{a^{7/2} \left (a^2+b^2\right ) d}-\frac {(a-b) \text {arctanh}\left (\frac {\sqrt {2} \sqrt {\tan (c+d x)}}{1+\tan (c+d x)}\right )}{\sqrt {2} \left (a^2+b^2\right ) d}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}+\frac {2 b}{3 a^2 d \tan ^{\frac {3}{2}}(c+d x)}+\frac {2 \left (a^2-b^2\right )}{a^3 d \sqrt {\tan (c+d x)}} \] Output:

1/2*(a+b)*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2)/(a^2+b^2)/d+1/2*(a+b 
)*arctan(1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2)/(a^2+b^2)/d-2*b^(9/2)*arctan( 
b^(1/2)*tan(d*x+c)^(1/2)/a^(1/2))/a^(7/2)/(a^2+b^2)/d-1/2*(a-b)*arctanh(2^ 
(1/2)*tan(d*x+c)^(1/2)/(1+tan(d*x+c)))*2^(1/2)/(a^2+b^2)/d-2/5/a/d/tan(d*x 
+c)^(5/2)+2/3*b/a^2/d/tan(d*x+c)^(3/2)+2*(a^2-b^2)/a^3/d/tan(d*x+c)^(1/2)
                                                                                    
                                                                                    
 

Mathematica [A] (verified)

Time = 2.48 (sec) , antiderivative size = 248, normalized size of antiderivative = 1.00 \[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=\frac {-15 \left (\frac {2 \sqrt {2} a^2 (a+b) \left (\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )-\arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )\right )}{a^2+b^2}+\frac {8 b^{9/2} \arctan \left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a}}\right )}{a^{3/2} \left (a^2+b^2\right )}-\frac {\sqrt {2} a^2 (a-b) \left (\log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )-\log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )\right )}{a^2+b^2}-\frac {8 (a-b) (a+b)}{a \sqrt {\tan (c+d x)}}\right )-\frac {24 a}{\tan ^{\frac {5}{2}}(c+d x)}+\frac {40 b}{\tan ^{\frac {3}{2}}(c+d x)}}{60 a^2 d} \] Input:

Integrate[1/(Tan[c + d*x]^(7/2)*(a + b*Tan[c + d*x])),x]
 

Output:

(-15*((2*Sqrt[2]*a^2*(a + b)*(ArcTan[1 - Sqrt[2]*Sqrt[Tan[c + d*x]]] - Arc 
Tan[1 + Sqrt[2]*Sqrt[Tan[c + d*x]]]))/(a^2 + b^2) + (8*b^(9/2)*ArcTan[(Sqr 
t[b]*Sqrt[Tan[c + d*x]])/Sqrt[a]])/(a^(3/2)*(a^2 + b^2)) - (Sqrt[2]*a^2*(a 
 - b)*(Log[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]] - Log[1 + Sqrt[2 
]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]))/(a^2 + b^2) - (8*(a - b)*(a + b))/( 
a*Sqrt[Tan[c + d*x]])) - (24*a)/Tan[c + d*x]^(5/2) + (40*b)/Tan[c + d*x]^( 
3/2))/(60*a^2*d)
 

Rubi [A] (verified)

Time = 1.50 (sec) , antiderivative size = 289, normalized size of antiderivative = 1.17, number of steps used = 26, number of rules used = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.087, Rules used = {3042, 4052, 27, 3042, 4132, 27, 3042, 4133, 27, 3042, 4136, 3042, 4017, 27, 1482, 1476, 1082, 217, 1479, 25, 27, 1103, 4117, 73, 218}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {1}{\tan (c+d x)^{7/2} (a+b \tan (c+d x))}dx\)

\(\Big \downarrow \) 4052

\(\displaystyle -\frac {2 \int \frac {5 \left (b \tan ^2(c+d x)+a \tan (c+d x)+b\right )}{2 \tan ^{\frac {5}{2}}(c+d x) (a+b \tan (c+d x))}dx}{5 a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\int \frac {b \tan ^2(c+d x)+a \tan (c+d x)+b}{\tan ^{\frac {5}{2}}(c+d x) (a+b \tan (c+d x))}dx}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {\int \frac {b \tan (c+d x)^2+a \tan (c+d x)+b}{\tan (c+d x)^{5/2} (a+b \tan (c+d x))}dx}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 4132

\(\displaystyle -\frac {-\frac {2 \int -\frac {3 \left (a^2-b^2-b^2 \tan ^2(c+d x)\right )}{2 \tan ^{\frac {3}{2}}(c+d x) (a+b \tan (c+d x))}dx}{3 a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\frac {\int \frac {a^2-b^2-b^2 \tan ^2(c+d x)}{\tan ^{\frac {3}{2}}(c+d x) (a+b \tan (c+d x))}dx}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {\frac {\int \frac {a^2-b^2-b^2 \tan (c+d x)^2}{\tan (c+d x)^{3/2} (a+b \tan (c+d x))}dx}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 4133

\(\displaystyle -\frac {\frac {-\frac {2 \int \frac {\tan (c+d x) a^3+b \left (a^2-b^2\right ) \tan ^2(c+d x)+b \left (a^2-b^2\right )}{2 \sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\frac {-\frac {\int \frac {\tan (c+d x) a^3+b \left (a^2-b^2\right ) \tan ^2(c+d x)+b \left (a^2-b^2\right )}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {\frac {-\frac {\int \frac {\tan (c+d x) a^3+b \left (a^2-b^2\right ) \tan (c+d x)^2+b \left (a^2-b^2\right )}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 4136

\(\displaystyle -\frac {\frac {-\frac {\frac {\int \frac {\tan (c+d x) a^4+b a^3}{\sqrt {\tan (c+d x)}}dx}{a^2+b^2}-\frac {b^5 \int \frac {\tan ^2(c+d x)+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {\frac {-\frac {\frac {\int \frac {\tan (c+d x) a^4+b a^3}{\sqrt {\tan (c+d x)}}dx}{a^2+b^2}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 4017

\(\displaystyle -\frac {\frac {-\frac {\frac {2 \int \frac {a^3 (b+a \tan (c+d x))}{\tan ^2(c+d x)+1}d\sqrt {\tan (c+d x)}}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \int \frac {b+a \tan (c+d x)}{\tan ^2(c+d x)+1}d\sqrt {\tan (c+d x)}}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 1482

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \int \frac {\tan (c+d x)+1}{\tan ^2(c+d x)+1}d\sqrt {\tan (c+d x)}-\frac {1}{2} (a-b) \int \frac {1-\tan (c+d x)}{\tan ^2(c+d x)+1}d\sqrt {\tan (c+d x)}\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 1476

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {1}{2} \int \frac {1}{\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}+\frac {1}{2} \int \frac {1}{\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}\right )-\frac {1}{2} (a-b) \int \frac {1-\tan (c+d x)}{\tan ^2(c+d x)+1}d\sqrt {\tan (c+d x)}\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 1082

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\int \frac {1}{-\tan (c+d x)-1}d\left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\tan (c+d x)-1}d\left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \int \frac {1-\tan (c+d x)}{\tan ^2(c+d x)+1}d\sqrt {\tan (c+d x)}\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 217

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \int \frac {1-\tan (c+d x)}{\tan ^2(c+d x)+1}d\sqrt {\tan (c+d x)}\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 1479

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \left (-\frac {\int -\frac {\sqrt {2}-2 \sqrt {\tan (c+d x)}}{\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}}{2 \sqrt {2}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\tan (c+d x)}}{\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}}{2 \sqrt {2}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\tan (c+d x)}}{\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}}{2 \sqrt {2}}+\frac {1}{2} \int \frac {\sqrt {2} \sqrt {\tan (c+d x)}+1}{\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1}d\sqrt {\tan (c+d x)}\right )\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 1103

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\log \left (\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {\tan (c+d x)^2+1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}dx}{a^2+b^2}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 4117

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\log \left (\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}-\frac {b^5 \int \frac {1}{\sqrt {\tan (c+d x)} (a+b \tan (c+d x))}d\tan (c+d x)}{d \left (a^2+b^2\right )}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 73

\(\displaystyle -\frac {\frac {-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\log \left (\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}-\frac {2 b^5 \int \frac {1}{a+b \tan (c+d x)}d\sqrt {\tan (c+d x)}}{d \left (a^2+b^2\right )}}{a}-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

\(\Big \downarrow \) 218

\(\displaystyle -\frac {\frac {-\frac {2 \left (a^2-b^2\right )}{a d \sqrt {\tan (c+d x)}}-\frac {\frac {2 a^3 \left (\frac {1}{2} (a+b) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} (a-b) \left (\frac {\log \left (\tan (c+d x)+\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\tan (c+d x)-\sqrt {2} \sqrt {\tan (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d \left (a^2+b^2\right )}-\frac {2 b^{9/2} \arctan \left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a}}\right )}{\sqrt {a} d \left (a^2+b^2\right )}}{a}}{a}-\frac {2 b}{3 a d \tan ^{\frac {3}{2}}(c+d x)}}{a}-\frac {2}{5 a d \tan ^{\frac {5}{2}}(c+d x)}\)

Input:

Int[1/(Tan[c + d*x]^(7/2)*(a + b*Tan[c + d*x])),x]
 

Output:

-(((-(((-2*b^(9/2)*ArcTan[(Sqrt[b]*Sqrt[Tan[c + d*x]])/Sqrt[a]])/(Sqrt[a]* 
(a^2 + b^2)*d) + (2*a^3*(((a + b)*(-(ArcTan[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] 
]/Sqrt[2]) + ArcTan[1 + Sqrt[2]*Sqrt[Tan[c + d*x]]]/Sqrt[2]))/2 - ((a - b) 
*(-1/2*Log[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]/Sqrt[2] + Log[1 
+ Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]/(2*Sqrt[2])))/2))/((a^2 + b^2 
)*d))/a) - (2*(a^2 - b^2))/(a*d*Sqrt[Tan[c + d*x]]))/a - (2*b)/(3*a*d*Tan[ 
c + d*x]^(3/2)))/a) - 2/(5*a*d*Tan[c + d*x]^(5/2))
 

Defintions of rubi rules used

rule 25

Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 73

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 217

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 218

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R 
t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
 

rule 1082

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 1482

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
a*c, 2]}, Simp[(d*q + a*e)/(2*a*c)   Int[(q + c*x^2)/(a + c*x^4), x], x] + 
Simp[(d*q - a*e)/(2*a*c)   Int[(q - c*x^2)/(a + c*x^4), x], x]] /; FreeQ[{a 
, c, d, e}, x] && NeQ[c*d^2 + a*e^2, 0] && NeQ[c*d^2 - a*e^2, 0] && NegQ[(- 
a)*c]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4017

Int[((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])/Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_ 
)]], x_Symbol] :> Simp[2/f   Subst[Int[(b*c + d*x^2)/(b^2 + x^4), x], x, Sq 
rt[b*Tan[e + f*x]]], x] /; FreeQ[{b, c, d, e, f}, x] && NeQ[c^2 - d^2, 0] & 
& NeQ[c^2 + d^2, 0]
 

rule 4052

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)])^(n_), x_Symbol] :> Simp[b^2*(a + b*Tan[e + f*x])^(m + 1)*((c 
+ d*Tan[e + f*x])^(n + 1)/(f*(m + 1)*(a^2 + b^2)*(b*c - a*d))), x] + Simp[1 
/((m + 1)*(a^2 + b^2)*(b*c - a*d))   Int[(a + b*Tan[e + f*x])^(m + 1)*(c + 
d*Tan[e + f*x])^n*Simp[a*(b*c - a*d)*(m + 1) - b^2*d*(m + n + 2) - b*(b*c - 
 a*d)*(m + 1)*Tan[e + f*x] - b^2*d*(m + n + 2)*Tan[e + f*x]^2, x], x], x] / 
; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] 
 && NeQ[c^2 + d^2, 0] && IntegerQ[2*m] && LtQ[m, -1] && (LtQ[n, 0] || Integ 
erQ[m]) &&  !(ILtQ[n, -1] && ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4117

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*tan[(e_.) 
+ (f_.)*(x_)])^(n_.)*((A_) + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> 
 Simp[A/f   Subst[Int[(a + b*x)^m*(c + d*x)^n, x], x, Tan[e + f*x]], x] /; 
FreeQ[{a, b, c, d, e, f, A, C, m, n}, x] && EqQ[A, C]
 

rule 4132

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) 
 + (f_.)*(x_)]^2), x_Symbol] :> Simp[(A*b^2 - a*(b*B - a*C))*(a + b*Tan[e + 
 f*x])^(m + 1)*((c + d*Tan[e + f*x])^(n + 1)/(f*(m + 1)*(b*c - a*d)*(a^2 + 
b^2))), x] + Simp[1/((m + 1)*(b*c - a*d)*(a^2 + b^2))   Int[(a + b*Tan[e + 
f*x])^(m + 1)*(c + d*Tan[e + f*x])^n*Simp[A*(a*(b*c - a*d)*(m + 1) - b^2*d* 
(m + n + 2)) + (b*B - a*C)*(b*c*(m + 1) + a*d*(n + 1)) - (m + 1)*(b*c - a*d 
)*(A*b - a*B - b*C)*Tan[e + f*x] - d*(A*b^2 - a*(b*B - a*C))*(m + n + 2)*Ta 
n[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ 
[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] && LtQ[m, -1] && 
!(ILtQ[n, -1] && ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4133

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> 
Simp[(A*b^2 + a^2*C)*(a + b*Tan[e + f*x])^(m + 1)*((c + d*Tan[e + f*x])^(n 
+ 1)/(f*(m + 1)*(b*c - a*d)*(a^2 + b^2))), x] + Simp[1/((m + 1)*(b*c - a*d) 
*(a^2 + b^2))   Int[(a + b*Tan[e + f*x])^(m + 1)*(c + d*Tan[e + f*x])^n*Sim 
p[A*(a*(b*c - a*d)*(m + 1) - b^2*d*(m + n + 2)) - a*C*(b*c*(m + 1) + a*d*(n 
 + 1)) - (m + 1)*(b*c - a*d)*(A*b - b*C)*Tan[e + f*x] - d*(A*b^2 + a^2*C)*( 
m + n + 2)*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, C, n}, 
 x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] && LtQ[m 
, -1] &&  !(ILtQ[n, -1] && ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4136

Int[(((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) 
+ (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2))/((a_.) + (b_.)*tan[(e_.) 
+ (f_.)*(x_)]), x_Symbol] :> Simp[1/(a^2 + b^2)   Int[(c + d*Tan[e + f*x])^ 
n*Simp[b*B + a*(A - C) + (a*B - b*(A - C))*Tan[e + f*x], x], x], x] + Simp[ 
(A*b^2 - a*b*B + a^2*C)/(a^2 + b^2)   Int[(c + d*Tan[e + f*x])^n*((1 + Tan[ 
e + f*x]^2)/(a + b*Tan[e + f*x])), x], x] /; FreeQ[{a, b, c, d, e, f, A, B, 
 C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] & 
&  !GtQ[n, 0] &&  !LeQ[n, -1]
 

Maple [A] (verified)

Time = 0.13 (sec) , antiderivative size = 277, normalized size of antiderivative = 1.12

method	result	size
derivativedivides	\(\frac {\frac {\frac {b \sqrt {2}\, \left (\ln \left (\frac {\tan \left (d x +c \right )+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}{\tan \left (d x +c \right )-\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}\right )+2 \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )+2 \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )\right )}{4}+\frac {a \sqrt {2}\, \left (\ln \left (\frac {\tan \left (d x +c \right )-\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}{\tan \left (d x +c \right )+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}\right )+2 \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )+2 \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )\right )}{4}}{a^{2}+b^{2}}-\frac {2 b^{5} \arctan \left (\frac {b \sqrt {\tan \left (d x +c \right )}}{\sqrt {a b}}\right )}{a^{3} \left (a^{2}+b^{2}\right ) \sqrt {a b}}-\frac {2}{5 a \tan \left (d x +c \right )^{\frac {5}{2}}}-\frac {2 \left (-a^{2}+b^{2}\right )}{a^{3} \sqrt {\tan \left (d x +c \right )}}+\frac {2 b}{3 a^{2} \tan \left (d x +c \right )^{\frac {3}{2}}}}{d}\)	\(277\)
default	\(\frac {\frac {\frac {b \sqrt {2}\, \left (\ln \left (\frac {\tan \left (d x +c \right )+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}{\tan \left (d x +c \right )-\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}\right )+2 \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )+2 \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )\right )}{4}+\frac {a \sqrt {2}\, \left (\ln \left (\frac {\tan \left (d x +c \right )-\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}{\tan \left (d x +c \right )+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}+1}\right )+2 \arctan \left (1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )+2 \arctan \left (-1+\sqrt {2}\, \sqrt {\tan \left (d x +c \right )}\right )\right )}{4}}{a^{2}+b^{2}}-\frac {2 b^{5} \arctan \left (\frac {b \sqrt {\tan \left (d x +c \right )}}{\sqrt {a b}}\right )}{a^{3} \left (a^{2}+b^{2}\right ) \sqrt {a b}}-\frac {2}{5 a \tan \left (d x +c \right )^{\frac {5}{2}}}-\frac {2 \left (-a^{2}+b^{2}\right )}{a^{3} \sqrt {\tan \left (d x +c \right )}}+\frac {2 b}{3 a^{2} \tan \left (d x +c \right )^{\frac {3}{2}}}}{d}\)	\(277\)

Input:

int(1/tan(d*x+c)^(7/2)/(a+b*tan(d*x+c)),x,method=_RETURNVERBOSE)
 

Output:

1/d*(2/(a^2+b^2)*(1/8*b*2^(1/2)*(ln((tan(d*x+c)+2^(1/2)*tan(d*x+c)^(1/2)+1 
)/(tan(d*x+c)-2^(1/2)*tan(d*x+c)^(1/2)+1))+2*arctan(1+2^(1/2)*tan(d*x+c)^( 
1/2))+2*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2)))+1/8*a*2^(1/2)*(ln((tan(d*x+c) 
-2^(1/2)*tan(d*x+c)^(1/2)+1)/(tan(d*x+c)+2^(1/2)*tan(d*x+c)^(1/2)+1))+2*ar 
ctan(1+2^(1/2)*tan(d*x+c)^(1/2))+2*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))))-2 
/a^3*b^5/(a^2+b^2)/(a*b)^(1/2)*arctan(b*tan(d*x+c)^(1/2)/(a*b)^(1/2))-2/5/ 
a/tan(d*x+c)^(5/2)-2/a^3*(-a^2+b^2)/tan(d*x+c)^(1/2)+2/3*b/a^2/tan(d*x+c)^ 
(3/2))
 

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 849 vs. \(2 (210) = 420\).

Time = 0.23 (sec) , antiderivative size = 1728, normalized size of antiderivative = 6.97 \[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=\text {Too large to display} \] Input:

integrate(1/tan(d*x+c)^(7/2)/(a+b*tan(d*x+c)),x, algorithm="fricas")
 

Output:

[1/30*(30*b^4*sqrt(-b/a)*log(-(2*a*sqrt(-b/a)*sqrt(tan(d*x + c)) - b*tan(d 
*x + c) + a)/(b*tan(d*x + c) + a))*tan(d*x + c)^3 + 30*sqrt(1/2)*(a^5 + a^ 
3*b^2)*d*sqrt((a^2 + 2*a*b + b^2)/((a^4 + 2*a^2*b^2 + b^4)*d^2))*arctan((( 
a^4 + 2*a^2*b^2 + b^4)*d^2*sqrt((a^2 + 2*a*b + b^2)/((a^4 + 2*a^2*b^2 + b^ 
4)*d^2))*sqrt((a^2 - 2*a*b + b^2)/((a^4 + 2*a^2*b^2 + b^4)*d^2)) + 2*sqrt( 
1/2)*(a^3 - a^2*b + a*b^2 - b^3)*d*sqrt((a^2 + 2*a*b + b^2)/((a^4 + 2*a^2* 
b^2 + b^4)*d^2))*sqrt(tan(d*x + c)))/(a^2 - b^2))*tan(d*x + c)^3 + 30*sqrt 
(1/2)*(a^5 + a^3*b^2)*d*sqrt((a^2 + 2*a*b + b^2)/((a^4 + 2*a^2*b^2 + b^4)* 
d^2))*arctan(-((a^4 + 2*a^2*b^2 + b^4)*d^2*sqrt((a^2 + 2*a*b + b^2)/((a^4 
+ 2*a^2*b^2 + b^4)*d^2))*sqrt((a^2 - 2*a*b + b^2)/((a^4 + 2*a^2*b^2 + b^4) 
*d^2)) - 2*sqrt(1/2)*(a^3 - a^2*b + a*b^2 - b^3)*d*sqrt((a^2 + 2*a*b + b^2 
)/((a^4 + 2*a^2*b^2 + b^4)*d^2))*sqrt(tan(d*x + c)))/(a^2 - b^2))*tan(d*x 
+ c)^3 + 15*sqrt(1/2)*(a^5 + a^3*b^2)*d*sqrt((a^2 - 2*a*b + b^2)/((a^4 + 2 
*a^2*b^2 + b^4)*d^2))*log(2*sqrt(1/2)*(a^2 + b^2)*d*sqrt((a^2 - 2*a*b + b^ 
2)/((a^4 + 2*a^2*b^2 + b^4)*d^2))*sqrt(tan(d*x + c)) - (a - b)*tan(d*x + c 
) - a + b)*tan(d*x + c)^3 - 15*sqrt(1/2)*(a^5 + a^3*b^2)*d*sqrt((a^2 - 2*a 
*b + b^2)/((a^4 + 2*a^2*b^2 + b^4)*d^2))*log(-2*sqrt(1/2)*(a^2 + b^2)*d*sq 
rt((a^2 - 2*a*b + b^2)/((a^4 + 2*a^2*b^2 + b^4)*d^2))*sqrt(tan(d*x + c)) - 
 (a - b)*tan(d*x + c) - a + b)*tan(d*x + c)^3 - 4*(3*a^4 + 3*a^2*b^2 - 15* 
(a^4 - b^4)*tan(d*x + c)^2 - 5*(a^3*b + a*b^3)*tan(d*x + c))*sqrt(tan(d...
 

Sympy [F]

\[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=\int \frac {1}{\left (a + b \tan {\left (c + d x \right )}\right ) \tan ^{\frac {7}{2}}{\left (c + d x \right )}}\, dx \] Input:

integrate(1/tan(d*x+c)**(7/2)/(a+b*tan(d*x+c)),x)
 

Output:

Integral(1/((a + b*tan(c + d*x))*tan(c + d*x)**(7/2)), x)
 

Maxima [A] (verification not implemented)

Time = 0.14 (sec) , antiderivative size = 223, normalized size of antiderivative = 0.90 \[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=-\frac {\frac {120 \, b^{5} \arctan \left (\frac {b \sqrt {\tan \left (d x + c\right )}}{\sqrt {a b}}\right )}{{\left (a^{5} + a^{3} b^{2}\right )} \sqrt {a b}} - \frac {15 \, {\left (2 \, \sqrt {2} {\left (a + b\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, \sqrt {\tan \left (d x + c\right )}\right )}\right ) + 2 \, \sqrt {2} {\left (a + b\right )} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, \sqrt {\tan \left (d x + c\right )}\right )}\right ) - \sqrt {2} {\left (a - b\right )} \log \left (\sqrt {2} \sqrt {\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right ) + \sqrt {2} {\left (a - b\right )} \log \left (-\sqrt {2} \sqrt {\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right )\right )}}{a^{2} + b^{2}} - \frac {8 \, {\left (5 \, a b \tan \left (d x + c\right ) + 15 \, {\left (a^{2} - b^{2}\right )} \tan \left (d x + c\right )^{2} - 3 \, a^{2}\right )}}{a^{3} \tan \left (d x + c\right )^{\frac {5}{2}}}}{60 \, d} \] Input:

integrate(1/tan(d*x+c)^(7/2)/(a+b*tan(d*x+c)),x, algorithm="maxima")
 

Output:

-1/60*(120*b^5*arctan(b*sqrt(tan(d*x + c))/sqrt(a*b))/((a^5 + a^3*b^2)*sqr 
t(a*b)) - 15*(2*sqrt(2)*(a + b)*arctan(1/2*sqrt(2)*(sqrt(2) + 2*sqrt(tan(d 
*x + c)))) + 2*sqrt(2)*(a + b)*arctan(-1/2*sqrt(2)*(sqrt(2) - 2*sqrt(tan(d 
*x + c)))) - sqrt(2)*(a - b)*log(sqrt(2)*sqrt(tan(d*x + c)) + tan(d*x + c) 
 + 1) + sqrt(2)*(a - b)*log(-sqrt(2)*sqrt(tan(d*x + c)) + tan(d*x + c) + 1 
))/(a^2 + b^2) - 8*(5*a*b*tan(d*x + c) + 15*(a^2 - b^2)*tan(d*x + c)^2 - 3 
*a^2)/(a^3*tan(d*x + c)^(5/2)))/d
 

Giac [F(-2)]

Exception generated. \[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=\text {Exception raised: TypeError} \] Input:

integrate(1/tan(d*x+c)^(7/2)/(a+b*tan(d*x+c)),x, algorithm="giac")
 

Output:

Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const 
index_m & i,const vecteur & l) Error: Bad Argument Value
 

Mupad [B] (verification not implemented)

Time = 4.35 (sec) , antiderivative size = 4207, normalized size of antiderivative = 16.96 \[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=\text {Too large to display} \] Input:

int(1/(tan(c + d*x)^(7/2)*(a + b*tan(c + d*x))),x)
 

Output:

atan(((tan(c + d*x)^(1/2)*(64*a^21*b^11*d^5 - 32*a^27*b^5*d^5) + (-1i/(4*( 
b^2*d^2 - a^2*d^2 + a*b*d^2*2i)))^(1/2)*((-1i/(4*(b^2*d^2 - a^2*d^2 + a*b* 
d^2*2i)))^(1/2)*(tan(c + d*x)^(1/2)*(512*a^22*b^12*d^7 - 448*a^28*b^6*d^7 
+ 128*a^30*b^4*d^7 + 64*a^32*b^2*d^7) + (-1i/(4*(b^2*d^2 - a^2*d^2 + a*b*d 
^2*2i)))^(1/2)*(512*a^24*b^11*d^8 - tan(c + d*x)^(1/2)*(-1i/(4*(b^2*d^2 - 
a^2*d^2 + a*b*d^2*2i)))^(1/2)*(512*a^27*b^9*d^9 + 512*a^29*b^7*d^9 - 512*a 
^31*b^5*d^9 - 512*a^33*b^3*d^9) + 512*a^26*b^9*d^8 - 128*a^28*b^7*d^8 + 25 
6*a^30*b^5*d^8 + 384*a^32*b^3*d^8)) - 128*a^21*b^12*d^6 + 512*a^23*b^10*d^ 
6 + 32*a^29*b^4*d^6 + 32*a^31*b^2*d^6))*(-1i/(4*(b^2*d^2 - a^2*d^2 + a*b*d 
^2*2i)))^(1/2)*1i + (tan(c + d*x)^(1/2)*(64*a^21*b^11*d^5 - 32*a^27*b^5*d^ 
5) - (-1i/(4*(b^2*d^2 - a^2*d^2 + a*b*d^2*2i)))^(1/2)*(512*a^23*b^10*d^6 - 
 128*a^21*b^12*d^6 - (-1i/(4*(b^2*d^2 - a^2*d^2 + a*b*d^2*2i)))^(1/2)*(tan 
(c + d*x)^(1/2)*(512*a^22*b^12*d^7 - 448*a^28*b^6*d^7 + 128*a^30*b^4*d^7 + 
 64*a^32*b^2*d^7) - (-1i/(4*(b^2*d^2 - a^2*d^2 + a*b*d^2*2i)))^(1/2)*(tan( 
c + d*x)^(1/2)*(-1i/(4*(b^2*d^2 - a^2*d^2 + a*b*d^2*2i)))^(1/2)*(512*a^27* 
b^9*d^9 + 512*a^29*b^7*d^9 - 512*a^31*b^5*d^9 - 512*a^33*b^3*d^9) + 512*a^ 
24*b^11*d^8 + 512*a^26*b^9*d^8 - 128*a^28*b^7*d^8 + 256*a^30*b^5*d^8 + 384 
*a^32*b^3*d^8)) + 32*a^29*b^4*d^6 + 32*a^31*b^2*d^6))*(-1i/(4*(b^2*d^2 - a 
^2*d^2 + a*b*d^2*2i)))^(1/2)*1i)/((tan(c + d*x)^(1/2)*(64*a^21*b^11*d^5 - 
32*a^27*b^5*d^5) + (-1i/(4*(b^2*d^2 - a^2*d^2 + a*b*d^2*2i)))^(1/2)*((-...
 

Reduce [F]

\[ \int \frac {1}{\tan ^{\frac {7}{2}}(c+d x) (a+b \tan (c+d x))} \, dx=\int \frac {\sqrt {\tan \left (d x +c \right )}}{\tan \left (d x +c \right )^{5} b +\tan \left (d x +c \right )^{4} a}d x \] Input:

int(1/tan(d*x+c)^(7/2)/(a+b*tan(d*x+c)),x)
 

Output:

int(sqrt(tan(c + d*x))/(tan(c + d*x)**5*b + tan(c + d*x)**4*a),x)