\(\int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx\) [699]

Optimal result

Integrand size = 21, antiderivative size = 103 \[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\frac {a \operatorname {Hypergeometric2F1}\left (1,\frac {1+n}{2},\frac {3+n}{2},-\tan ^2(e+f x)\right ) (d \tan (e+f x))^{1+n}}{d f (1+n)}+\frac {b \operatorname {Hypergeometric2F1}\left (1,\frac {2+n}{2},\frac {4+n}{2},-\tan ^2(e+f x)\right ) (d \tan (e+f x))^{2+n}}{d^2 f (2+n)} \] Output:

a*hypergeom([1, 1/2+1/2*n],[3/2+1/2*n],-tan(f*x+e)^2)*(d*tan(f*x+e))^(1+n) 
/d/f/(1+n)+b*hypergeom([1, 1+1/2*n],[2+1/2*n],-tan(f*x+e)^2)*(d*tan(f*x+e) 
)^(2+n)/d^2/f/(2+n)
 

Mathematica [A] (verified)

Time = 0.20 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.96 \[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\frac {\tan (e+f x) (d \tan (e+f x))^n \left (a (2+n) \operatorname {Hypergeometric2F1}\left (1,\frac {1+n}{2},\frac {3+n}{2},-\tan ^2(e+f x)\right )+b (1+n) \operatorname {Hypergeometric2F1}\left (1,\frac {2+n}{2},\frac {4+n}{2},-\tan ^2(e+f x)\right ) \tan (e+f x)\right )}{f (1+n) (2+n)} \] Input:

Integrate[(d*Tan[e + f*x])^n*(a + b*Tan[e + f*x]),x]
 

Output:

(Tan[e + f*x]*(d*Tan[e + f*x])^n*(a*(2 + n)*Hypergeometric2F1[1, (1 + n)/2 
, (3 + n)/2, -Tan[e + f*x]^2] + b*(1 + n)*Hypergeometric2F1[1, (2 + n)/2, 
(4 + n)/2, -Tan[e + f*x]^2]*Tan[e + f*x]))/(f*(1 + n)*(2 + n))
 

Rubi [A] (verified)

Time = 0.33 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {3042, 4021, 3042, 3957, 278}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (a+b \tan (e+f x)) (d \tan (e+f x))^n \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int (a+b \tan (e+f x)) (d \tan (e+f x))^ndx\)

\(\Big \downarrow \) 4021

\(\displaystyle a \int (d \tan (e+f x))^ndx+\frac {b \int (d \tan (e+f x))^{n+1}dx}{d}\)

\(\Big \downarrow \) 3042

\(\displaystyle a \int (d \tan (e+f x))^ndx+\frac {b \int (d \tan (e+f x))^{n+1}dx}{d}\)

\(\Big \downarrow \) 3957

\(\displaystyle \frac {a d \int \frac {(d \tan (e+f x))^n}{\tan ^2(e+f x) d^2+d^2}d(d \tan (e+f x))}{f}+\frac {b \int \frac {(d \tan (e+f x))^{n+1}}{\tan ^2(e+f x) d^2+d^2}d(d \tan (e+f x))}{f}\)

\(\Big \downarrow \) 278

\(\displaystyle \frac {a (d \tan (e+f x))^{n+1} \operatorname {Hypergeometric2F1}\left (1,\frac {n+1}{2},\frac {n+3}{2},-\tan ^2(e+f x)\right )}{d f (n+1)}+\frac {b (d \tan (e+f x))^{n+2} \operatorname {Hypergeometric2F1}\left (1,\frac {n+2}{2},\frac {n+4}{2},-\tan ^2(e+f x)\right )}{d^2 f (n+2)}\)

Input:

Int[(d*Tan[e + f*x])^n*(a + b*Tan[e + f*x]),x]
 

Output:

(a*Hypergeometric2F1[1, (1 + n)/2, (3 + n)/2, -Tan[e + f*x]^2]*(d*Tan[e + 
f*x])^(1 + n))/(d*f*(1 + n)) + (b*Hypergeometric2F1[1, (2 + n)/2, (4 + n)/ 
2, -Tan[e + f*x]^2]*(d*Tan[e + f*x])^(2 + n))/(d^2*f*(2 + n))
 

Defintions of rubi rules used

rule 278

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[a^p*(( 
c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/2, (m + 1)/2 + 1, ( 
-b)*(x^2/a)], x] /; FreeQ[{a, b, c, m, p}, x] &&  !IGtQ[p, 0] && (ILtQ[p, 0 
] || GtQ[a, 0])
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3957

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[b/d   Subst[Int 
[x^n/(b^2 + x^2), x], x, b*Tan[c + d*x]], x] /; FreeQ[{b, c, d, n}, x] && 
!IntegerQ[n]
 

rule 4021

Int[((b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*tan[(e_.) + (f_.)*(x 
_)]), x_Symbol] :> Simp[c   Int[(b*Tan[e + f*x])^m, x], x] + Simp[d/b   Int 
[(b*Tan[e + f*x])^(m + 1), x], x] /; FreeQ[{b, c, d, e, f, m}, x] && NeQ[c^ 
2 + d^2, 0] &&  !IntegerQ[2*m]
 

Maple [F]

\[\int \left (d \tan \left (f x +e \right )\right )^{n} \left (a +b \tan \left (f x +e \right )\right )d x\]

Input:

int((d*tan(f*x+e))^n*(a+b*tan(f*x+e)),x)
 

Output:

int((d*tan(f*x+e))^n*(a+b*tan(f*x+e)),x)
 

Fricas [F]

\[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\int { {\left (b \tan \left (f x + e\right ) + a\right )} \left (d \tan \left (f x + e\right )\right )^{n} \,d x } \] Input:

integrate((d*tan(f*x+e))^n*(a+b*tan(f*x+e)),x, algorithm="fricas")
 

Output:

integral((b*tan(f*x + e) + a)*(d*tan(f*x + e))^n, x)
 

Sympy [F]

\[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\int \left (d \tan {\left (e + f x \right )}\right )^{n} \left (a + b \tan {\left (e + f x \right )}\right )\, dx \] Input:

integrate((d*tan(f*x+e))**n*(a+b*tan(f*x+e)),x)
 

Output:

Integral((d*tan(e + f*x))**n*(a + b*tan(e + f*x)), x)
 

Maxima [F]

\[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\int { {\left (b \tan \left (f x + e\right ) + a\right )} \left (d \tan \left (f x + e\right )\right )^{n} \,d x } \] Input:

integrate((d*tan(f*x+e))^n*(a+b*tan(f*x+e)),x, algorithm="maxima")
 

Output:

integrate((b*tan(f*x + e) + a)*(d*tan(f*x + e))^n, x)
 

Giac [F]

\[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\int { {\left (b \tan \left (f x + e\right ) + a\right )} \left (d \tan \left (f x + e\right )\right )^{n} \,d x } \] Input:

integrate((d*tan(f*x+e))^n*(a+b*tan(f*x+e)),x, algorithm="giac")
 

Output:

integrate((b*tan(f*x + e) + a)*(d*tan(f*x + e))^n, x)
 

Mupad [F(-1)]

Timed out. \[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\int {\left (d\,\mathrm {tan}\left (e+f\,x\right )\right )}^n\,\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right ) \,d x \] Input:

int((d*tan(e + f*x))^n*(a + b*tan(e + f*x)),x)
 

Output:

int((d*tan(e + f*x))^n*(a + b*tan(e + f*x)), x)
 

Reduce [F]

\[ \int (d \tan (e+f x))^n (a+b \tan (e+f x)) \, dx=\frac {d^{n} \left (\tan \left (f x +e \right )^{n} b +\left (\int \tan \left (f x +e \right )^{n}d x \right ) a f n -\left (\int \frac {\tan \left (f x +e \right )^{n}}{\tan \left (f x +e \right )}d x \right ) b f n \right )}{f n} \] Input:

int((d*tan(f*x+e))^n*(a+b*tan(f*x+e)),x)
 

Output:

(d**n*(tan(e + f*x)**n*b + int(tan(e + f*x)**n,x)*a*f*n - int(tan(e + f*x) 
**n/tan(e + f*x),x)*b*f*n))/(f*n)