\(\int \frac {(c+d \tan (e+f x))^{3/2} (A+B \tan (e+f x)+C \tan ^2(e+f x))}{\sqrt {a+b \tan (e+f x)}} \, dx\) [137]

Optimal result

Integrand size = 49, antiderivative size = 382 \[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=-\frac {(i A+B-i C) (c-i d)^{3/2} \text {arctanh}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {a-i b} f}-\frac {(B-i (A-C)) (c+i d)^{3/2} \text {arctanh}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {a+i b} f}+\frac {\left (3 a^2 C d^2-2 a b d (3 c C+2 B d)+b^2 \left (3 c^2 C+12 B c d+8 (A-C) d^2\right )\right ) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{4 b^{5/2} \sqrt {d} f}+\frac {(3 b c C+4 b B d-3 a C d) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 b^2 f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f} \] Output:

-(I*A+B-I*C)*(c-I*d)^(3/2)*arctanh((c-I*d)^(1/2)*(a+b*tan(f*x+e))^(1/2)/(a 
-I*b)^(1/2)/(c+d*tan(f*x+e))^(1/2))/(a-I*b)^(1/2)/f-(B-I*(A-C))*(c+I*d)^(3 
/2)*arctanh((c+I*d)^(1/2)*(a+b*tan(f*x+e))^(1/2)/(a+I*b)^(1/2)/(c+d*tan(f* 
x+e))^(1/2))/(a+I*b)^(1/2)/f+1/4*(3*a^2*C*d^2-2*a*b*d*(2*B*d+3*C*c)+b^2*(3 
*c^2*C+12*B*c*d+8*(A-C)*d^2))*arctanh(d^(1/2)*(a+b*tan(f*x+e))^(1/2)/b^(1/ 
2)/(c+d*tan(f*x+e))^(1/2))/b^(5/2)/d^(1/2)/f+1/4*(4*B*b*d-3*C*a*d+3*C*b*c) 
*(a+b*tan(f*x+e))^(1/2)*(c+d*tan(f*x+e))^(1/2)/b^2/f+1/2*C*(a+b*tan(f*x+e) 
)^(1/2)*(c+d*tan(f*x+e))^(3/2)/b/f
 

Mathematica [A] (verified)

Time = 6.55 (sec) , antiderivative size = 580, normalized size of antiderivative = 1.52 \[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=\frac {-\frac {4 \left (-b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )+\sqrt {-b^2} \left (c^2 C+2 B c d-C d^2+A \left (-c^2+d^2\right )\right )\right ) \text {arctanh}\left (\frac {\sqrt {-c+\frac {\sqrt {-b^2} d}{b}} \sqrt {a+b \tan (e+f x)}}{\sqrt {-a+\sqrt {-b^2}} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {-a+\sqrt {-b^2}} \sqrt {-c+\frac {\sqrt {-b^2} d}{b}}}-\frac {4 \left (b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )+\sqrt {-b^2} \left (c^2 C+2 B c d-C d^2+A \left (-c^2+d^2\right )\right )\right ) \text {arctanh}\left (\frac {\sqrt {c+\frac {\sqrt {-b^2} d}{b}} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+\sqrt {-b^2}} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {a+\sqrt {-b^2}} \sqrt {c+\frac {\sqrt {-b^2} d}{b}}}+\frac {(3 b c C+4 b B d-3 a C d) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b}+2 C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}+\frac {\sqrt {c-\frac {a d}{b}} \left (3 a^2 C d^2-2 a b d (3 c C+2 B d)+b^2 \left (3 c^2 C+12 B c d+8 (A-C) d^2\right )\right ) \text {arcsinh}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c-\frac {a d}{b}}}\right ) \sqrt {\frac {b (c+d \tan (e+f x))}{b c-a d}}}{b^{3/2} \sqrt {d} \sqrt {c+d \tan (e+f x)}}}{4 b f} \] Input:

Integrate[((c + d*Tan[e + f*x])^(3/2)*(A + B*Tan[e + f*x] + C*Tan[e + f*x] 
^2))/Sqrt[a + b*Tan[e + f*x]],x]
 

Output:

((-4*(-(b*(2*c*(A - C)*d + B*(c^2 - d^2))) + Sqrt[-b^2]*(c^2*C + 2*B*c*d - 
 C*d^2 + A*(-c^2 + d^2)))*ArcTanh[(Sqrt[-c + (Sqrt[-b^2]*d)/b]*Sqrt[a + b* 
Tan[e + f*x]])/(Sqrt[-a + Sqrt[-b^2]]*Sqrt[c + d*Tan[e + f*x]])])/(Sqrt[-a 
 + Sqrt[-b^2]]*Sqrt[-c + (Sqrt[-b^2]*d)/b]) - (4*(b*(2*c*(A - C)*d + B*(c^ 
2 - d^2)) + Sqrt[-b^2]*(c^2*C + 2*B*c*d - C*d^2 + A*(-c^2 + d^2)))*ArcTanh 
[(Sqrt[c + (Sqrt[-b^2]*d)/b]*Sqrt[a + b*Tan[e + f*x]])/(Sqrt[a + Sqrt[-b^2 
]]*Sqrt[c + d*Tan[e + f*x]])])/(Sqrt[a + Sqrt[-b^2]]*Sqrt[c + (Sqrt[-b^2]* 
d)/b]) + ((3*b*c*C + 4*b*B*d - 3*a*C*d)*Sqrt[a + b*Tan[e + f*x]]*Sqrt[c + 
d*Tan[e + f*x]])/b + 2*C*Sqrt[a + b*Tan[e + f*x]]*(c + d*Tan[e + f*x])^(3/ 
2) + (Sqrt[c - (a*d)/b]*(3*a^2*C*d^2 - 2*a*b*d*(3*c*C + 2*B*d) + b^2*(3*c^ 
2*C + 12*B*c*d + 8*(A - C)*d^2))*ArcSinh[(Sqrt[d]*Sqrt[a + b*Tan[e + f*x]] 
)/(Sqrt[b]*Sqrt[c - (a*d)/b])]*Sqrt[(b*(c + d*Tan[e + f*x]))/(b*c - a*d)]) 
/(b^(3/2)*Sqrt[d]*Sqrt[c + d*Tan[e + f*x]]))/(4*b*f)
 

Rubi [A] (verified)

Time = 3.78 (sec) , antiderivative size = 393, normalized size of antiderivative = 1.03, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.224, Rules used = {3042, 4130, 27, 3042, 4130, 27, 25, 3042, 4138, 2348, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan (e+f x)^2\right )}{\sqrt {a+b \tan (e+f x)}}dx\)

\(\Big \downarrow \) 4130

\(\displaystyle \frac {\int \frac {\sqrt {c+d \tan (e+f x)} \left ((3 b c C-3 a d C+4 b B d) \tan ^2(e+f x)+4 b (B c+(A-C) d) \tan (e+f x)+4 A b c-C (b c+3 a d)\right )}{2 \sqrt {a+b \tan (e+f x)}}dx}{2 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {\sqrt {c+d \tan (e+f x)} \left ((3 b c C-3 a d C+4 b B d) \tan ^2(e+f x)+4 b (B c+(A-C) d) \tan (e+f x)+4 A b c-b c C-3 a C d\right )}{\sqrt {a+b \tan (e+f x)}}dx}{4 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \frac {\sqrt {c+d \tan (e+f x)} \left ((3 b c C-3 a d C+4 b B d) \tan (e+f x)^2+4 b (B c+(A-C) d) \tan (e+f x)+4 A b c-b c C-3 a C d\right )}{\sqrt {a+b \tan (e+f x)}}dx}{4 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 4130

\(\displaystyle \frac {\frac {\int -\frac {-8 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) \tan (e+f x) b^2-2 c (4 A b c-C (b c+3 a d)) b-\left (8 d (B c+(A-C) d) b^2+(b c-a d) (3 b c C-3 a d C+4 b B d)\right ) \tan ^2(e+f x)+(b c+a d) (3 b c C-3 a d C+4 b B d)}{2 \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}dx}{b}+\frac {(-3 a C d+4 b B d+3 b c C) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}}{4 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {(-3 a C d+4 b B d+3 b c C) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}-\frac {\int -\frac {8 A c^2 b^2-c (5 c C+4 B d) b^2+8 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) \tan (e+f x) b^2-2 a d (3 c C+2 B d) b+3 a^2 C d^2+\left (8 d (B c+(A-C) d) b^2+(b c-a d) (3 b c C-3 a d C+4 b B d)\right ) \tan ^2(e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}dx}{2 b}}{4 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {\frac {\int \frac {8 A c^2 b^2-c (5 c C+4 B d) b^2+8 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) \tan (e+f x) b^2-2 a d (3 c C+2 B d) b+3 a^2 C d^2+\left (8 d (B c+(A-C) d) b^2+(b c-a d) (3 b c C-3 a d C+4 b B d)\right ) \tan ^2(e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}dx}{2 b}+\frac {(-3 a C d+4 b B d+3 b c C) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}}{4 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \frac {8 A c^2 b^2-c (5 c C+4 B d) b^2+8 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) \tan (e+f x) b^2-2 a d (3 c C+2 B d) b+3 a^2 C d^2+\left (8 d (B c+(A-C) d) b^2+(b c-a d) (3 b c C-3 a d C+4 b B d)\right ) \tan (e+f x)^2}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}dx}{2 b}+\frac {(-3 a C d+4 b B d+3 b c C) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}}{4 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 4138

\(\displaystyle \frac {\frac {\int \frac {8 A c^2 b^2-c (5 c C+4 B d) b^2+8 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) \tan (e+f x) b^2-2 a d (3 c C+2 B d) b+3 a^2 C d^2+\left (8 d (B c+(A-C) d) b^2+(b c-a d) (3 b c C-3 a d C+4 b B d)\right ) \tan ^2(e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (\tan ^2(e+f x)+1\right )}d\tan (e+f x)}{2 b f}+\frac {(-3 a C d+4 b B d+3 b c C) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}}{4 b}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}\)

\(\Big \downarrow \) 2348

\(\displaystyle \frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}+\frac {\frac {(-3 a C d+4 b B d+3 b c C) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}+\frac {\int \left (\frac {8 A d^2 b^2-8 C d^2 b^2+3 c^2 C b^2+12 B c d b^2-4 a B d^2 b-6 a c C d b+3 a^2 C d^2}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}+\frac {-8 B c^2 b^2+8 B d^2 b^2-16 A c d b^2+16 c C d b^2+i \left (8 A c^2 b^2-8 A d^2 b^2+8 C d^2 b^2-8 c^2 C b^2-16 B c d b^2\right )}{2 (i-\tan (e+f x)) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}+\frac {8 B c^2 b^2-8 B d^2 b^2+16 A c d b^2-16 c C d b^2+i \left (8 A c^2 b^2-8 A d^2 b^2+8 C d^2 b^2-8 c^2 C b^2-16 B c d b^2\right )}{2 (\tan (e+f x)+i) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}\right )d\tan (e+f x)}{2 b f}}{4 b}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 b f}+\frac {\frac {(-3 a C d+4 b B d+3 b c C) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}+\frac {\frac {2 \left (3 a^2 C d^2-2 a b d (2 B d+3 c C)+b^2 \left (8 d^2 (A-C)+12 B c d+3 c^2 C\right )\right ) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {b} \sqrt {d}}-\frac {8 b^2 (c-i d)^{3/2} (i A+B-i C) \text {arctanh}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {a-i b}}-\frac {8 b^2 (c+i d)^{3/2} (B-i (A-C)) \text {arctanh}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {a+i b}}}{2 b f}}{4 b}\)

Input:

Int[((c + d*Tan[e + f*x])^(3/2)*(A + B*Tan[e + f*x] + C*Tan[e + f*x]^2))/S 
qrt[a + b*Tan[e + f*x]],x]
 

Output:

(C*Sqrt[a + b*Tan[e + f*x]]*(c + d*Tan[e + f*x])^(3/2))/(2*b*f) + (((-8*b^ 
2*(I*A + B - I*C)*(c - I*d)^(3/2)*ArcTanh[(Sqrt[c - I*d]*Sqrt[a + b*Tan[e 
+ f*x]])/(Sqrt[a - I*b]*Sqrt[c + d*Tan[e + f*x]])])/Sqrt[a - I*b] - (8*b^2 
*(B - I*(A - C))*(c + I*d)^(3/2)*ArcTanh[(Sqrt[c + I*d]*Sqrt[a + b*Tan[e + 
 f*x]])/(Sqrt[a + I*b]*Sqrt[c + d*Tan[e + f*x]])])/Sqrt[a + I*b] + (2*(3*a 
^2*C*d^2 - 2*a*b*d*(3*c*C + 2*B*d) + b^2*(3*c^2*C + 12*B*c*d + 8*(A - C)*d 
^2))*ArcTanh[(Sqrt[d]*Sqrt[a + b*Tan[e + f*x]])/(Sqrt[b]*Sqrt[c + d*Tan[e 
+ f*x]])])/(Sqrt[b]*Sqrt[d]))/(2*b*f) + ((3*b*c*C + 4*b*B*d - 3*a*C*d)*Sqr 
t[a + b*Tan[e + f*x]]*Sqrt[c + d*Tan[e + f*x]])/(b*f))/(4*b)
 

Defintions of rubi rules used

rule 25

Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2348

Int[(Px_)*((c_) + (d_.)*(x_))^(m_.)*((e_) + (f_.)*(x_))^(n_.)*((a_.) + (b_. 
)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[Px*(c + d*x)^m*(e + f*x)^ 
n*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && PolyQ[P 
x, x] && (IntegerQ[p] || (IntegerQ[2*p] && IntegerQ[m] && ILtQ[n, 0])) && 
!(IGtQ[m, 0] && IGtQ[n, 0])
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4130

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*tan[(e_.) 
+ (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_. 
) + (f_.)*(x_)]^2), x_Symbol] :> Simp[C*(a + b*Tan[e + f*x])^m*((c + d*Tan[ 
e + f*x])^(n + 1)/(d*f*(m + n + 1))), x] + Simp[1/(d*(m + n + 1))   Int[(a 
+ b*Tan[e + f*x])^(m - 1)*(c + d*Tan[e + f*x])^n*Simp[a*A*d*(m + n + 1) - C 
*(b*c*m + a*d*(n + 1)) + d*(A*b + a*B - b*C)*(m + n + 1)*Tan[e + f*x] - (C* 
m*(b*c - a*d) - b*B*d*(m + n + 1))*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, 
b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && 
 NeQ[c^2 + d^2, 0] && GtQ[m, 0] &&  !(IGtQ[n, 0] && ( !IntegerQ[m] || (EqQ[ 
c, 0] && NeQ[a, 0])))
 

rule 4138

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) 
 + (f_.)*(x_)]^2), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x], x]}, S 
imp[ff/f   Subst[Int[(a + b*ff*x)^m*(c + d*ff*x)^n*((A + B*ff*x + C*ff^2*x^ 
2)/(1 + ff^2*x^2)), x], x, Tan[e + f*x]/ff], x]] /; FreeQ[{a, b, c, d, e, f 
, A, B, C, m, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + 
 d^2, 0]
 

Maple [F(-1)]

Timed out.

\[\int \frac {\left (c +d \tan \left (f x +e \right )\right )^{\frac {3}{2}} \left (A +B \tan \left (f x +e \right )+C \tan \left (f x +e \right )^{2}\right )}{\sqrt {a +b \tan \left (f x +e \right )}}d x\]

Input:

int((c+d*tan(f*x+e))^(3/2)*(A+B*tan(f*x+e)+C*tan(f*x+e)^2)/(a+b*tan(f*x+e) 
)^(1/2),x)
 

Output:

int((c+d*tan(f*x+e))^(3/2)*(A+B*tan(f*x+e)+C*tan(f*x+e)^2)/(a+b*tan(f*x+e) 
)^(1/2),x)
 

Fricas [F(-1)]

Timed out. \[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=\text {Timed out} \] Input:

integrate((c+d*tan(f*x+e))^(3/2)*(A+B*tan(f*x+e)+C*tan(f*x+e)^2)/(a+b*tan( 
f*x+e))^(1/2),x, algorithm="fricas")
 

Output:

Timed out
 

Sympy [F]

\[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=\int \frac {\left (c + d \tan {\left (e + f x \right )}\right )^{\frac {3}{2}} \left (A + B \tan {\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )}{\sqrt {a + b \tan {\left (e + f x \right )}}}\, dx \] Input:

integrate((c+d*tan(f*x+e))**(3/2)*(A+B*tan(f*x+e)+C*tan(f*x+e)**2)/(a+b*ta 
n(f*x+e))**(1/2),x)
 

Output:

Integral((c + d*tan(e + f*x))**(3/2)*(A + B*tan(e + f*x) + C*tan(e + f*x)* 
*2)/sqrt(a + b*tan(e + f*x)), x)
 

Maxima [F]

\[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=\int { \frac {{\left (C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A\right )} {\left (d \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}}}{\sqrt {b \tan \left (f x + e\right ) + a}} \,d x } \] Input:

integrate((c+d*tan(f*x+e))^(3/2)*(A+B*tan(f*x+e)+C*tan(f*x+e)^2)/(a+b*tan( 
f*x+e))^(1/2),x, algorithm="maxima")
 

Output:

integrate((C*tan(f*x + e)^2 + B*tan(f*x + e) + A)*(d*tan(f*x + e) + c)^(3/ 
2)/sqrt(b*tan(f*x + e) + a), x)
 

Giac [F]

\[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=\int { \frac {{\left (C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A\right )} {\left (d \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}}}{\sqrt {b \tan \left (f x + e\right ) + a}} \,d x } \] Input:

integrate((c+d*tan(f*x+e))^(3/2)*(A+B*tan(f*x+e)+C*tan(f*x+e)^2)/(a+b*tan( 
f*x+e))^(1/2),x, algorithm="giac")
 

Output:

integrate((C*tan(f*x + e)^2 + B*tan(f*x + e) + A)*(d*tan(f*x + e) + c)^(3/ 
2)/sqrt(b*tan(f*x + e) + a), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=\text {Hanged} \] Input:

int(((c + d*tan(e + f*x))^(3/2)*(A + B*tan(e + f*x) + C*tan(e + f*x)^2))/( 
a + b*tan(e + f*x))^(1/2),x)
 

Output:

\text{Hanged}
 

Reduce [F]

\[ \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx=\left (\int \frac {\sqrt {d \tan \left (f x +e \right )+c}\, \sqrt {\tan \left (f x +e \right ) b +a}\, \tan \left (f x +e \right )^{3}}{\tan \left (f x +e \right ) b +a}d x \right ) c d +\left (\int \frac {\sqrt {d \tan \left (f x +e \right )+c}\, \sqrt {\tan \left (f x +e \right ) b +a}\, \tan \left (f x +e \right )^{2}}{\tan \left (f x +e \right ) b +a}d x \right ) b d +\left (\int \frac {\sqrt {d \tan \left (f x +e \right )+c}\, \sqrt {\tan \left (f x +e \right ) b +a}\, \tan \left (f x +e \right )^{2}}{\tan \left (f x +e \right ) b +a}d x \right ) c^{2}+\left (\int \frac {\sqrt {d \tan \left (f x +e \right )+c}\, \sqrt {\tan \left (f x +e \right ) b +a}\, \tan \left (f x +e \right )}{\tan \left (f x +e \right ) b +a}d x \right ) a d +\left (\int \frac {\sqrt {d \tan \left (f x +e \right )+c}\, \sqrt {\tan \left (f x +e \right ) b +a}\, \tan \left (f x +e \right )}{\tan \left (f x +e \right ) b +a}d x \right ) b c +\left (\int \frac {\sqrt {d \tan \left (f x +e \right )+c}\, \sqrt {\tan \left (f x +e \right ) b +a}}{\tan \left (f x +e \right ) b +a}d x \right ) a c \] Input:

int((c+d*tan(f*x+e))^(3/2)*(A+B*tan(f*x+e)+C*tan(f*x+e)^2)/(a+b*tan(f*x+e) 
)^(1/2),x)
 

Output:

int((sqrt(tan(e + f*x)*d + c)*sqrt(tan(e + f*x)*b + a)*tan(e + f*x)**3)/(t 
an(e + f*x)*b + a),x)*c*d + int((sqrt(tan(e + f*x)*d + c)*sqrt(tan(e + f*x 
)*b + a)*tan(e + f*x)**2)/(tan(e + f*x)*b + a),x)*b*d + int((sqrt(tan(e + 
f*x)*d + c)*sqrt(tan(e + f*x)*b + a)*tan(e + f*x)**2)/(tan(e + f*x)*b + a) 
,x)*c**2 + int((sqrt(tan(e + f*x)*d + c)*sqrt(tan(e + f*x)*b + a)*tan(e + 
f*x))/(tan(e + f*x)*b + a),x)*a*d + int((sqrt(tan(e + f*x)*d + c)*sqrt(tan 
(e + f*x)*b + a)*tan(e + f*x))/(tan(e + f*x)*b + a),x)*b*c + int((sqrt(tan 
(e + f*x)*d + c)*sqrt(tan(e + f*x)*b + a))/(tan(e + f*x)*b + a),x)*a*c