\(\int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx\) [95]

Optimal result

Integrand size = 23, antiderivative size = 84 \[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx=-\frac {\sqrt {a} \text {arctanh}\left (\frac {\sqrt {a} \sec (e+f x)}{\sqrt {a-b+b \sec ^2(e+f x)}}\right )}{f}+\frac {\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \sec (e+f x)}{\sqrt {a-b+b \sec ^2(e+f x)}}\right )}{f} \] Output:

-a^(1/2)*arctanh(a^(1/2)*sec(f*x+e)/(a-b+b*sec(f*x+e)^2)^(1/2))/f+b^(1/2)* 
arctanh(b^(1/2)*sec(f*x+e)/(a-b+b*sec(f*x+e)^2)^(1/2))/f
 

Mathematica [B] (verified)

Leaf count is larger than twice the leaf count of optimal. \(170\) vs. \(2(84)=168\).

Time = 1.64 (sec) , antiderivative size = 170, normalized size of antiderivative = 2.02 \[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx=\frac {\sec (e+f x) \left (-\sqrt {a} \arctan \left (\frac {\sqrt {a} \sqrt {\sec ^2(e+f x)}}{\sqrt {-a-b \tan ^2(e+f x)}}\right ) \sqrt {-a-b \tan ^2(e+f x)}+\sqrt {a-b} \sqrt {b} \text {arcsinh}\left (\frac {\sqrt {b} \sqrt {\sec ^2(e+f x)}}{\sqrt {a-b}}\right ) \sqrt {\frac {a+b \tan ^2(e+f x)}{a-b}}\right )}{f \sqrt {\sec ^2(e+f x)} \sqrt {a+b \tan ^2(e+f x)}} \] Input:

Integrate[Csc[e + f*x]*Sqrt[a + b*Tan[e + f*x]^2],x]
 

Output:

(Sec[e + f*x]*(-(Sqrt[a]*ArcTan[(Sqrt[a]*Sqrt[Sec[e + f*x]^2])/Sqrt[-a - b 
*Tan[e + f*x]^2]]*Sqrt[-a - b*Tan[e + f*x]^2]) + Sqrt[a - b]*Sqrt[b]*ArcSi 
nh[(Sqrt[b]*Sqrt[Sec[e + f*x]^2])/Sqrt[a - b]]*Sqrt[(a + b*Tan[e + f*x]^2) 
/(a - b)]))/(f*Sqrt[Sec[e + f*x]^2]*Sqrt[a + b*Tan[e + f*x]^2])
 

Rubi [A] (verified)

Time = 0.47 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.98, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {3042, 4147, 25, 301, 224, 219, 291, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\sqrt {a+b \tan (e+f x)^2}}{\sin (e+f x)}dx\)

\(\Big \downarrow \) 4147

\(\displaystyle \frac {\int -\frac {\sqrt {b \sec ^2(e+f x)+a-b}}{1-\sec ^2(e+f x)}d\sec (e+f x)}{f}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {\int \frac {\sqrt {b \sec ^2(e+f x)+a-b}}{1-\sec ^2(e+f x)}d\sec (e+f x)}{f}\)

\(\Big \downarrow \) 301

\(\displaystyle \frac {b \int \frac {1}{\sqrt {b \sec ^2(e+f x)+a-b}}d\sec (e+f x)-a \int \frac {1}{\left (1-\sec ^2(e+f x)\right ) \sqrt {b \sec ^2(e+f x)+a-b}}d\sec (e+f x)}{f}\)

\(\Big \downarrow \) 224

\(\displaystyle \frac {b \int \frac {1}{1-\frac {b \sec ^2(e+f x)}{b \sec ^2(e+f x)+a-b}}d\frac {\sec (e+f x)}{\sqrt {b \sec ^2(e+f x)+a-b}}-a \int \frac {1}{\left (1-\sec ^2(e+f x)\right ) \sqrt {b \sec ^2(e+f x)+a-b}}d\sec (e+f x)}{f}\)

\(\Big \downarrow \) 219

\(\displaystyle \frac {\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \sec (e+f x)}{\sqrt {a+b \sec ^2(e+f x)-b}}\right )-a \int \frac {1}{\left (1-\sec ^2(e+f x)\right ) \sqrt {b \sec ^2(e+f x)+a-b}}d\sec (e+f x)}{f}\)

\(\Big \downarrow \) 291

\(\displaystyle \frac {\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \sec (e+f x)}{\sqrt {a+b \sec ^2(e+f x)-b}}\right )-a \int \frac {1}{1-\frac {a \sec ^2(e+f x)}{b \sec ^2(e+f x)+a-b}}d\frac {\sec (e+f x)}{\sqrt {b \sec ^2(e+f x)+a-b}}}{f}\)

\(\Big \downarrow \) 219

\(\displaystyle \frac {\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \sec (e+f x)}{\sqrt {a+b \sec ^2(e+f x)-b}}\right )-\sqrt {a} \text {arctanh}\left (\frac {\sqrt {a} \sec (e+f x)}{\sqrt {a+b \sec ^2(e+f x)-b}}\right )}{f}\)

Input:

Int[Csc[e + f*x]*Sqrt[a + b*Tan[e + f*x]^2],x]
 

Output:

(-(Sqrt[a]*ArcTanh[(Sqrt[a]*Sec[e + f*x])/Sqrt[a - b + b*Sec[e + f*x]^2]]) 
 + Sqrt[b]*ArcTanh[(Sqrt[b]*Sec[e + f*x])/Sqrt[a - b + b*Sec[e + f*x]^2]]) 
/f
 

Defintions of rubi rules used

rule 25

Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 219

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 224

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], 
x, x/Sqrt[a + b*x^2]] /; FreeQ[{a, b}, x] &&  !GtQ[a, 0]
 

rule 291

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*((c_) + (d_.)*(x_)^2)), x_Symbol] :> Subst 
[Int[1/(c - (b*c - a*d)*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a, b, c, 
d}, x] && NeQ[b*c - a*d, 0]
 

rule 301

Int[((a_) + (b_.)*(x_)^2)^(p_.)/((c_) + (d_.)*(x_)^2), x_Symbol] :> Simp[b/ 
d   Int[(a + b*x^2)^(p - 1), x], x] - Simp[(b*c - a*d)/d   Int[(a + b*x^2)^ 
(p - 1)/(c + d*x^2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] 
&& GtQ[p, 0] && (EqQ[p, 1/2] || EqQ[Denominator[p], 4] || (EqQ[p, 2/3] && E 
qQ[b*c + 3*a*d, 0]))
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4147

Int[sin[(e_.) + (f_.)*(x_)]^(m_.)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)]^2)^ 
(p_.), x_Symbol] :> With[{ff = FreeFactors[Sec[e + f*x], x]}, Simp[1/(f*ff^ 
m)   Subst[Int[(-1 + ff^2*x^2)^((m - 1)/2)*((a - b + b*ff^2*x^2)^p/x^(m + 1 
)), x], x, Sec[e + f*x]/ff], x]] /; FreeQ[{a, b, e, f, p}, x] && IntegerQ[( 
m - 1)/2]
 

Maple [B] (warning: unable to verify)

Leaf count of result is larger than twice the leaf count of optimal. \(405\) vs. \(2(72)=144\).

Time = 6.28 (sec) , antiderivative size = 406, normalized size of antiderivative = 4.83

method	result	size
default	\(-\frac {\sqrt {a +b \tan \left (f x +e \right )^{2}}\, \left (\left (1-\cos \left (f x +e \right )\right )^{2} \csc \left (f x +e \right )^{2}-1\right ) \left (2 \sqrt {b}\, \ln \left (\frac {4 \left (1-\cos \left (f x +e \right )\right )^{2} b \csc \left (f x +e \right )^{2}+8 \sqrt {b}\, \sqrt {\frac {a \cos \left (f x +e \right )^{2}+b \sin \left (f x +e \right )^{2}}{\left (\cos \left (f x +e \right )+1\right )^{2}}}+4 b}{\left (1-\cos \left (f x +e \right )\right )^{2} \csc \left (f x +e \right )^{2}-1}\right ) \sqrt {a}-\ln \left (\frac {2 \sqrt {a}\, \sqrt {\frac {a \cos \left (f x +e \right )^{2}+b \sin \left (f x +e \right )^{2}}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \cos \left (f x +e \right )+2 \sqrt {\frac {a \cos \left (f x +e \right )^{2}+b \sin \left (f x +e \right )^{2}}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \sqrt {a}-2 a \cos \left (f x +e \right )+2 \cos \left (f x +e \right ) b +2 b}{\sqrt {a}\, \left (\cos \left (f x +e \right )+1\right )}\right ) a -a \ln \left (\frac {-2 a \left (1-\cos \left (f x +e \right )\right )^{2}+4 \left (1-\cos \left (f x +e \right )\right )^{2} b +4 \sqrt {\frac {a \cos \left (f x +e \right )^{2}+b \sin \left (f x +e \right )^{2}}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \sqrt {a}\, \sin \left (f x +e \right )^{2}+2 a \sin \left (f x +e \right )^{2}}{\left (1-\cos \left (f x +e \right )\right )^{2}}\right )\right )}{4 f \sqrt {a}\, \sqrt {\frac {a \cos \left (f x +e \right )^{2}+b \sin \left (f x +e \right )^{2}}{\left (\cos \left (f x +e \right )+1\right )^{2}}}}\)	\(406\)

Input:

int(csc(f*x+e)*(a+b*tan(f*x+e)^2)^(1/2),x,method=_RETURNVERBOSE)
 

Output:

-1/4/f/a^(1/2)*(a+b*tan(f*x+e)^2)^(1/2)*((1-cos(f*x+e))^2*csc(f*x+e)^2-1)* 
(2*b^(1/2)*ln(4*((1-cos(f*x+e))^2*b*csc(f*x+e)^2+2*b^(1/2)*((a*cos(f*x+e)^ 
2+b*sin(f*x+e)^2)/(cos(f*x+e)+1)^2)^(1/2)+b)/((1-cos(f*x+e))^2*csc(f*x+e)^ 
2-1))*a^(1/2)-ln(2/a^(1/2)*(a^(1/2)*((a*cos(f*x+e)^2+b*sin(f*x+e)^2)/(cos( 
f*x+e)+1)^2)^(1/2)*cos(f*x+e)+((a*cos(f*x+e)^2+b*sin(f*x+e)^2)/(cos(f*x+e) 
+1)^2)^(1/2)*a^(1/2)-a*cos(f*x+e)+cos(f*x+e)*b+b)/(cos(f*x+e)+1))*a-a*ln(2 
/(1-cos(f*x+e))^2*(-a*(1-cos(f*x+e))^2+2*(1-cos(f*x+e))^2*b+2*((a*cos(f*x+ 
e)^2+b*sin(f*x+e)^2)/(cos(f*x+e)+1)^2)^(1/2)*a^(1/2)*sin(f*x+e)^2+a*sin(f* 
x+e)^2)))/((a*cos(f*x+e)^2+b*sin(f*x+e)^2)/(cos(f*x+e)+1)^2)^(1/2)
 

Fricas [A] (verification not implemented)

Time = 0.17 (sec) , antiderivative size = 579, normalized size of antiderivative = 6.89 \[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx =\text {Too large to display} \] Input:

integrate(csc(f*x+e)*(a+b*tan(f*x+e)^2)^(1/2),x, algorithm="fricas")
 

Output:

[1/2*(sqrt(a)*log(-2*((a - b)*cos(f*x + e)^2 - 2*sqrt(a)*sqrt(((a - b)*cos 
(f*x + e)^2 + b)/cos(f*x + e)^2)*cos(f*x + e) + a + b)/(cos(f*x + e)^2 - 1 
)) + sqrt(b)*log(-((a - b)*cos(f*x + e)^2 + 2*sqrt(b)*sqrt(((a - b)*cos(f* 
x + e)^2 + b)/cos(f*x + e)^2)*cos(f*x + e) + 2*b)/cos(f*x + e)^2))/f, 1/2* 
(2*sqrt(-b)*arctan(-sqrt(-b)*sqrt(((a - b)*cos(f*x + e)^2 + b)/cos(f*x + e 
)^2)*cos(f*x + e)/((a - b)*cos(f*x + e)^2 + b)) + sqrt(a)*log(-2*((a - b)* 
cos(f*x + e)^2 - 2*sqrt(a)*sqrt(((a - b)*cos(f*x + e)^2 + b)/cos(f*x + e)^ 
2)*cos(f*x + e) + a + b)/(cos(f*x + e)^2 - 1)))/f, -1/2*(2*sqrt(-a)*arctan 
(-sqrt(-a)*sqrt(((a - b)*cos(f*x + e)^2 + b)/cos(f*x + e)^2)*cos(f*x + e)/ 
((a - b)*cos(f*x + e)^2 + b)) - sqrt(b)*log(-((a - b)*cos(f*x + e)^2 + 2*s 
qrt(b)*sqrt(((a - b)*cos(f*x + e)^2 + b)/cos(f*x + e)^2)*cos(f*x + e) + 2* 
b)/cos(f*x + e)^2))/f, -(sqrt(-a)*arctan(-sqrt(-a)*sqrt(((a - b)*cos(f*x + 
 e)^2 + b)/cos(f*x + e)^2)*cos(f*x + e)/((a - b)*cos(f*x + e)^2 + b)) - sq 
rt(-b)*arctan(-sqrt(-b)*sqrt(((a - b)*cos(f*x + e)^2 + b)/cos(f*x + e)^2)* 
cos(f*x + e)/((a - b)*cos(f*x + e)^2 + b)))/f]
 

Sympy [F]

\[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx=\int \sqrt {a + b \tan ^{2}{\left (e + f x \right )}} \csc {\left (e + f x \right )}\, dx \] Input:

integrate(csc(f*x+e)*(a+b*tan(f*x+e)**2)**(1/2),x)
 

Output:

Integral(sqrt(a + b*tan(e + f*x)**2)*csc(e + f*x), x)
 

Maxima [F]

\[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx=\int { \sqrt {b \tan \left (f x + e\right )^{2} + a} \csc \left (f x + e\right ) \,d x } \] Input:

integrate(csc(f*x+e)*(a+b*tan(f*x+e)^2)^(1/2),x, algorithm="maxima")
 

Output:

integrate(sqrt(b*tan(f*x + e)^2 + a)*csc(f*x + e), x)
 

Giac [F(-2)]

Exception generated. \[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx=\text {Exception raised: TypeError} \] Input:

integrate(csc(f*x+e)*(a+b*tan(f*x+e)^2)^(1/2),x, algorithm="giac")
 

Output:

Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:Degree mismatch inside factorisatio 
n over extensionDegree mismatch inside factorisation over extensionDegree 
mismatch
 

Mupad [F(-1)]

Timed out. \[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx=\int \frac {\sqrt {b\,{\mathrm {tan}\left (e+f\,x\right )}^2+a}}{\sin \left (e+f\,x\right )} \,d x \] Input:

int((a + b*tan(e + f*x)^2)^(1/2)/sin(e + f*x),x)
 

Output:

int((a + b*tan(e + f*x)^2)^(1/2)/sin(e + f*x), x)
 

Reduce [F]

\[ \int \csc (e+f x) \sqrt {a+b \tan ^2(e+f x)} \, dx=\int \sqrt {\tan \left (f x +e \right )^{2} b +a}\, \csc \left (f x +e \right )d x \] Input:

int(csc(f*x+e)*(a+b*tan(f*x+e)^2)^(1/2),x)
 

Output:

int(sqrt(tan(e + f*x)**2*b + a)*csc(e + f*x),x)