Integrand size = 27, antiderivative size = 715 \[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\frac {3 a \tan (c+d x)}{4 d (e \sec (c+d x))^{4/3} \sqrt {a+a \sec (c+d x)}}+\frac {15 a \tan (c+d x)}{8 d e \sqrt [3]{e \sec (c+d x)} \sqrt {a+a \sec (c+d x)}}+\frac {15 a \tan (c+d x)}{8 d e \sqrt {a+a \sec (c+d x)} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )}-\frac {15 \sqrt [4]{3} \sqrt {2-\sqrt {3}} a^2 E\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}{\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}\right )|-7-4 \sqrt {3}\right ) \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right ) \sqrt {\frac {e^{2/3}+\sqrt [3]{e} \sqrt [3]{e \sec (c+d x)}+(e \sec (c+d x))^{2/3}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}} \tan (c+d x)}{16 d e^{5/3} (a-a \sec (c+d x)) \sqrt {a+a \sec (c+d x)} \sqrt {\frac {\sqrt [3]{e} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}}}+\frac {5\ 3^{3/4} a^2 \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}{\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}\right ),-7-4 \sqrt {3}\right ) \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right ) \sqrt {\frac {e^{2/3}+\sqrt [3]{e} \sqrt [3]{e \sec (c+d x)}+(e \sec (c+d x))^{2/3}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}} \tan (c+d x)}{4 \sqrt {2} d e^{5/3} (a-a \sec (c+d x)) \sqrt {a+a \sec (c+d x)} \sqrt {\frac {\sqrt [3]{e} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}}} \] Output:
3/4*a*tan(d*x+c)/d/(e*sec(d*x+c))^(4/3)/(a+a*sec(d*x+c))^(1/2)+15/8*a*tan( d*x+c)/d/e/(e*sec(d*x+c))^(1/3)/(a+a*sec(d*x+c))^(1/2)+15/8*a*tan(d*x+c)/d /e/(a+a*sec(d*x+c))^(1/2)/((1+3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3))-15/16 *3^(1/4)*(1/2*6^(1/2)-1/2*2^(1/2))*a^2*EllipticE(((1-3^(1/2))*e^(1/3)-(e*s ec(d*x+c))^(1/3))/((1+3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3)),I*3^(1/2)+2*I )*(e^(1/3)-(e*sec(d*x+c))^(1/3))*((e^(2/3)+e^(1/3)*(e*sec(d*x+c))^(1/3)+(e *sec(d*x+c))^(2/3))/((1+3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3))^2)^(1/2)*ta n(d*x+c)/d/e^(5/3)/(a-a*sec(d*x+c))/(a+a*sec(d*x+c))^(1/2)/(e^(1/3)*(e^(1/ 3)-(e*sec(d*x+c))^(1/3))/((1+3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3))^2)^(1/ 2)+5/8*3^(3/4)*a^2*EllipticF(((1-3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3))/(( 1+3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3)),I*3^(1/2)+2*I)*(e^(1/3)-(e*sec(d* x+c))^(1/3))*((e^(2/3)+e^(1/3)*(e*sec(d*x+c))^(1/3)+(e*sec(d*x+c))^(2/3))/ ((1+3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3))^2)^(1/2)*tan(d*x+c)*2^(1/2)/d/e ^(5/3)/(a-a*sec(d*x+c))/(a+a*sec(d*x+c))^(1/2)/(e^(1/3)*(e^(1/3)-(e*sec(d* x+c))^(1/3))/((1+3^(1/2))*e^(1/3)-(e*sec(d*x+c))^(1/3))^2)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.13 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.10 \[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\frac {2 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {7}{3},\frac {3}{2},1-\sec (c+d x)\right ) \sec ^{\frac {4}{3}}(c+d x) \sqrt {a (1+\sec (c+d x))} \tan \left (\frac {1}{2} (c+d x)\right )}{d (e \sec (c+d x))^{4/3}} \] Input:
Integrate[Sqrt[a + a*Sec[c + d*x]]/(e*Sec[c + d*x])^(4/3),x]
Output:
(2*Hypergeometric2F1[1/2, 7/3, 3/2, 1 - Sec[c + d*x]]*Sec[c + d*x]^(4/3)*S qrt[a*(1 + Sec[c + d*x])]*Tan[(c + d*x)/2])/(d*(e*Sec[c + d*x])^(4/3))
Time = 0.65 (sec) , antiderivative size = 717, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.296, Rules used = {3042, 4293, 61, 61, 73, 832, 759, 2416}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt {a \sec (c+d x)+a}}{(e \sec (c+d x))^{4/3}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {\sqrt {a \csc \left (c+d x+\frac {\pi }{2}\right )+a}}{\left (e \csc \left (c+d x+\frac {\pi }{2}\right )\right )^{4/3}}dx\) |
\(\Big \downarrow \) 4293 |
\(\displaystyle -\frac {a^2 e \tan (c+d x) \int \frac {1}{(e \sec (c+d x))^{7/3} \sqrt {a-a \sec (c+d x)}}d\sec (c+d x)}{d \sqrt {a-a \sec (c+d x)} \sqrt {a \sec (c+d x)+a}}\) |
\(\Big \downarrow \) 61 |
\(\displaystyle -\frac {a^2 e \tan (c+d x) \left (\frac {5 \int \frac {1}{(e \sec (c+d x))^{4/3} \sqrt {a-a \sec (c+d x)}}d\sec (c+d x)}{8 e}-\frac {3 \sqrt {a-a \sec (c+d x)}}{4 a e (e \sec (c+d x))^{4/3}}\right )}{d \sqrt {a-a \sec (c+d x)} \sqrt {a \sec (c+d x)+a}}\) |
\(\Big \downarrow \) 61 |
\(\displaystyle -\frac {a^2 e \tan (c+d x) \left (\frac {5 \left (-\frac {\int \frac {1}{\sqrt [3]{e \sec (c+d x)} \sqrt {a-a \sec (c+d x)}}d\sec (c+d x)}{2 e}-\frac {3 \sqrt {a-a \sec (c+d x)}}{a e \sqrt [3]{e \sec (c+d x)}}\right )}{8 e}-\frac {3 \sqrt {a-a \sec (c+d x)}}{4 a e (e \sec (c+d x))^{4/3}}\right )}{d \sqrt {a-a \sec (c+d x)} \sqrt {a \sec (c+d x)+a}}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle -\frac {a^2 e \tan (c+d x) \left (\frac {5 \left (-\frac {3 \int \frac {\sqrt [3]{e \sec (c+d x)}}{\sqrt {a-a \sec (c+d x)}}d\sqrt [3]{e \sec (c+d x)}}{2 e^2}-\frac {3 \sqrt {a-a \sec (c+d x)}}{a e \sqrt [3]{e \sec (c+d x)}}\right )}{8 e}-\frac {3 \sqrt {a-a \sec (c+d x)}}{4 a e (e \sec (c+d x))^{4/3}}\right )}{d \sqrt {a-a \sec (c+d x)} \sqrt {a \sec (c+d x)+a}}\) |
\(\Big \downarrow \) 832 |
\(\displaystyle -\frac {a^2 e \tan (c+d x) \left (\frac {5 \left (-\frac {3 \left (\left (1-\sqrt {3}\right ) \sqrt [3]{e} \int \frac {1}{\sqrt {a-a \sec (c+d x)}}d\sqrt [3]{e \sec (c+d x)}-\int \frac {\left (1-\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}{\sqrt {a-a \sec (c+d x)}}d\sqrt [3]{e \sec (c+d x)}\right )}{2 e^2}-\frac {3 \sqrt {a-a \sec (c+d x)}}{a e \sqrt [3]{e \sec (c+d x)}}\right )}{8 e}-\frac {3 \sqrt {a-a \sec (c+d x)}}{4 a e (e \sec (c+d x))^{4/3}}\right )}{d \sqrt {a-a \sec (c+d x)} \sqrt {a \sec (c+d x)+a}}\) |
\(\Big \downarrow \) 759 |
\(\displaystyle -\frac {a^2 e \tan (c+d x) \left (\frac {5 \left (-\frac {3 \left (-\int \frac {\left (1-\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}{\sqrt {a-a \sec (c+d x)}}d\sqrt [3]{e \sec (c+d x)}-\frac {2 \left (1-\sqrt {3}\right ) \sqrt {2+\sqrt {3}} \sqrt [3]{e} \sqrt {\frac {\sqrt [3]{e} \sqrt [3]{e \sec (c+d x)}+(e \sec (c+d x))^{2/3}+e^{2/3}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right ) \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}{\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}\right ),-7-4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {a-a \sec (c+d x)} \sqrt {\frac {\sqrt [3]{e} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}}}\right )}{2 e^2}-\frac {3 \sqrt {a-a \sec (c+d x)}}{a e \sqrt [3]{e \sec (c+d x)}}\right )}{8 e}-\frac {3 \sqrt {a-a \sec (c+d x)}}{4 a e (e \sec (c+d x))^{4/3}}\right )}{d \sqrt {a-a \sec (c+d x)} \sqrt {a \sec (c+d x)+a}}\) |
\(\Big \downarrow \) 2416 |
\(\displaystyle -\frac {a^2 e \tan (c+d x) \left (\frac {5 \left (-\frac {3 \left (-\frac {2 \left (1-\sqrt {3}\right ) \sqrt {2+\sqrt {3}} \sqrt [3]{e} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right ) \sqrt {\frac {\sqrt [3]{e} \sqrt [3]{e \sec (c+d x)}+(e \sec (c+d x))^{2/3}+e^{2/3}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}{\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}\right ),-7-4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {a-a \sec (c+d x)} \sqrt {\frac {\sqrt [3]{e} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}}}-\frac {\sqrt [4]{3} \sqrt {2-\sqrt {3}} \sqrt [3]{e} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right ) \sqrt {\frac {\sqrt [3]{e} \sqrt [3]{e \sec (c+d x)}+(e \sec (c+d x))^{2/3}+e^{2/3}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}} E\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}{\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}}\right )|-7-4 \sqrt {3}\right )}{\sqrt {a-a \sec (c+d x)} \sqrt {\frac {\sqrt [3]{e} \left (\sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )^2}}}+\frac {2 e \sqrt {a-a \sec (c+d x)}}{a \left (\left (1+\sqrt {3}\right ) \sqrt [3]{e}-\sqrt [3]{e \sec (c+d x)}\right )}\right )}{2 e^2}-\frac {3 \sqrt {a-a \sec (c+d x)}}{a e \sqrt [3]{e \sec (c+d x)}}\right )}{8 e}-\frac {3 \sqrt {a-a \sec (c+d x)}}{4 a e (e \sec (c+d x))^{4/3}}\right )}{d \sqrt {a-a \sec (c+d x)} \sqrt {a \sec (c+d x)+a}}\) |
Input:
Int[Sqrt[a + a*Sec[c + d*x]]/(e*Sec[c + d*x])^(4/3),x]
Output:
-((a^2*e*((-3*Sqrt[a - a*Sec[c + d*x]])/(4*a*e*(e*Sec[c + d*x])^(4/3)) + ( 5*((-3*Sqrt[a - a*Sec[c + d*x]])/(a*e*(e*Sec[c + d*x])^(1/3)) - (3*((2*e*S qrt[a - a*Sec[c + d*x]])/(a*((1 + Sqrt[3])*e^(1/3) - (e*Sec[c + d*x])^(1/3 ))) - (3^(1/4)*Sqrt[2 - Sqrt[3]]*e^(1/3)*EllipticE[ArcSin[((1 - Sqrt[3])*e ^(1/3) - (e*Sec[c + d*x])^(1/3))/((1 + Sqrt[3])*e^(1/3) - (e*Sec[c + d*x]) ^(1/3))], -7 - 4*Sqrt[3]]*(e^(1/3) - (e*Sec[c + d*x])^(1/3))*Sqrt[(e^(2/3) + e^(1/3)*(e*Sec[c + d*x])^(1/3) + (e*Sec[c + d*x])^(2/3))/((1 + Sqrt[3]) *e^(1/3) - (e*Sec[c + d*x])^(1/3))^2])/(Sqrt[a - a*Sec[c + d*x]]*Sqrt[(e^( 1/3)*(e^(1/3) - (e*Sec[c + d*x])^(1/3)))/((1 + Sqrt[3])*e^(1/3) - (e*Sec[c + d*x])^(1/3))^2]) - (2*(1 - Sqrt[3])*Sqrt[2 + Sqrt[3]]*e^(1/3)*EllipticF [ArcSin[((1 - Sqrt[3])*e^(1/3) - (e*Sec[c + d*x])^(1/3))/((1 + Sqrt[3])*e^ (1/3) - (e*Sec[c + d*x])^(1/3))], -7 - 4*Sqrt[3]]*(e^(1/3) - (e*Sec[c + d* x])^(1/3))*Sqrt[(e^(2/3) + e^(1/3)*(e*Sec[c + d*x])^(1/3) + (e*Sec[c + d*x ])^(2/3))/((1 + Sqrt[3])*e^(1/3) - (e*Sec[c + d*x])^(1/3))^2])/(3^(1/4)*Sq rt[a - a*Sec[c + d*x]]*Sqrt[(e^(1/3)*(e^(1/3) - (e*Sec[c + d*x])^(1/3)))/( (1 + Sqrt[3])*e^(1/3) - (e*Sec[c + d*x])^(1/3))^2])))/(2*e^2)))/(8*e))*Tan [c + d*x])/(d*Sqrt[a - a*Sec[c + d*x]]*Sqrt[a + a*Sec[c + d*x]]))
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^(n + 1)/((b*c - a*d)*(m + 1))), x] - Simp[d*(( m + n + 2)/((b*c - a*d)*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && LtQ[m, -1] && !(LtQ[n, -1] && (EqQ[a, 0 ] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d , m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 + Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s *x + r^2*x^2)/((1 + Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[s* ((s + r*x)/((1 + Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 - Sqrt[3])*s + r*x)/((1 + Sqrt[3])*s + r*x)], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x] & & PosQ[a]
Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3] ], s = Denom[Rt[b/a, 3]]}, Simp[(-(1 - Sqrt[3]))*(s/r) Int[1/Sqrt[a + b*x ^3], x], x] + Simp[1/r Int[((1 - Sqrt[3])*s + r*x)/Sqrt[a + b*x^3], x], x ]] /; FreeQ[{a, b}, x] && PosQ[a]
Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N umer[Simplify[(1 - Sqrt[3])*(d/c)]], s = Denom[Simplify[(1 - Sqrt[3])*(d/c) ]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 + Sqrt[3])*s + r*x))), x] - S imp[3^(1/4)*Sqrt[2 - Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/( (1 + Sqrt[3])*s + r*x)^2]/(r^2*Sqrt[a + b*x^3]*Sqrt[s*((s + r*x)/((1 + Sqrt [3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 - Sqrt[3])*s + r*x)/((1 + Sqrt[3]) *s + r*x)], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && PosQ[a] && Eq Q[b*c^3 - 2*(5 - 3*Sqrt[3])*a*d^3, 0]
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)], x_Symbol] :> Simp[a^2*d*(Cot[e + f*x]/(f*Sqrt[a + b*Csc[e + f*x]] *Sqrt[a - b*Csc[e + f*x]])) Subst[Int[(d*x)^(n - 1)/Sqrt[a - b*x], x], x, Csc[e + f*x]], x] /; FreeQ[{a, b, d, e, f, n}, x] && EqQ[a^2 - b^2, 0]
\[\int \frac {\sqrt {a +a \sec \left (d x +c \right )}}{\left (e \sec \left (d x +c \right )\right )^{\frac {4}{3}}}d x\]
Input:
int((a+a*sec(d*x+c))^(1/2)/(e*sec(d*x+c))^(4/3),x)
Output:
int((a+a*sec(d*x+c))^(1/2)/(e*sec(d*x+c))^(4/3),x)
\[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\int { \frac {\sqrt {a \sec \left (d x + c\right ) + a}}{\left (e \sec \left (d x + c\right )\right )^{\frac {4}{3}}} \,d x } \] Input:
integrate((a+a*sec(d*x+c))^(1/2)/(e*sec(d*x+c))^(4/3),x, algorithm="fricas ")
Output:
integral(sqrt(a*sec(d*x + c) + a)*(e*sec(d*x + c))^(2/3)/(e^2*sec(d*x + c) ^2), x)
\[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\int \frac {\sqrt {a \left (\sec {\left (c + d x \right )} + 1\right )}}{\left (e \sec {\left (c + d x \right )}\right )^{\frac {4}{3}}}\, dx \] Input:
integrate((a+a*sec(d*x+c))**(1/2)/(e*sec(d*x+c))**(4/3),x)
Output:
Integral(sqrt(a*(sec(c + d*x) + 1))/(e*sec(c + d*x))**(4/3), x)
\[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\int { \frac {\sqrt {a \sec \left (d x + c\right ) + a}}{\left (e \sec \left (d x + c\right )\right )^{\frac {4}{3}}} \,d x } \] Input:
integrate((a+a*sec(d*x+c))^(1/2)/(e*sec(d*x+c))^(4/3),x, algorithm="maxima ")
Output:
integrate(sqrt(a*sec(d*x + c) + a)/(e*sec(d*x + c))^(4/3), x)
\[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\int { \frac {\sqrt {a \sec \left (d x + c\right ) + a}}{\left (e \sec \left (d x + c\right )\right )^{\frac {4}{3}}} \,d x } \] Input:
integrate((a+a*sec(d*x+c))^(1/2)/(e*sec(d*x+c))^(4/3),x, algorithm="giac")
Output:
integrate(sqrt(a*sec(d*x + c) + a)/(e*sec(d*x + c))^(4/3), x)
Timed out. \[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\int \frac {\sqrt {a+\frac {a}{\cos \left (c+d\,x\right )}}}{{\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^{4/3}} \,d x \] Input:
int((a + a/cos(c + d*x))^(1/2)/(e/cos(c + d*x))^(4/3),x)
Output:
int((a + a/cos(c + d*x))^(1/2)/(e/cos(c + d*x))^(4/3), x)
\[ \int \frac {\sqrt {a+a \sec (c+d x)}}{(e \sec (c+d x))^{4/3}} \, dx=\frac {\sqrt {a}\, \left (\int \frac {\sqrt {\sec \left (d x +c \right )+1}}{\sec \left (d x +c \right )^{\frac {4}{3}}}d x \right )}{e^{\frac {4}{3}}} \] Input:
int((a+a*sec(d*x+c))^(1/2)/(e*sec(d*x+c))^(4/3),x)
Output:
(sqrt(a)*int(sqrt(sec(c + d*x) + 1)/(sec(c + d*x)**(1/3)*sec(c + d*x)),x)) /(e**(1/3)*e)