Integrand size = 19, antiderivative size = 100 \[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=-\frac {3 a \text {arctanh}(\cos (c+d x))}{8 d}-\frac {b \cot ^2(c+d x)}{d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {3 a \cot (c+d x) \csc (c+d x)}{8 d}-\frac {a \cot (c+d x) \csc ^3(c+d x)}{4 d}+\frac {b \log (\tan (c+d x))}{d} \] Output:
-3/8*a*arctanh(cos(d*x+c))/d-b*cot(d*x+c)^2/d-1/4*b*cot(d*x+c)^4/d-3/8*a*c ot(d*x+c)*csc(d*x+c)/d-1/4*a*cot(d*x+c)*csc(d*x+c)^3/d+b*ln(tan(d*x+c))/d
Time = 0.02 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.76 \[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=-\frac {3 a \csc ^2\left (\frac {1}{2} (c+d x)\right )}{32 d}-\frac {a \csc ^4\left (\frac {1}{2} (c+d x)\right )}{64 d}-\frac {b \csc ^2(c+d x)}{2 d}-\frac {b \csc ^4(c+d x)}{4 d}-\frac {3 a \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{8 d}-\frac {b \log (\cos (c+d x))}{d}+\frac {3 a \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )}{8 d}+\frac {b \log (\sin (c+d x))}{d}+\frac {3 a \sec ^2\left (\frac {1}{2} (c+d x)\right )}{32 d}+\frac {a \sec ^4\left (\frac {1}{2} (c+d x)\right )}{64 d} \] Input:
Integrate[Csc[c + d*x]^5*(a + b*Sec[c + d*x]),x]
Output:
(-3*a*Csc[(c + d*x)/2]^2)/(32*d) - (a*Csc[(c + d*x)/2]^4)/(64*d) - (b*Csc[ c + d*x]^2)/(2*d) - (b*Csc[c + d*x]^4)/(4*d) - (3*a*Log[Cos[(c + d*x)/2]]) /(8*d) - (b*Log[Cos[c + d*x]])/d + (3*a*Log[Sin[(c + d*x)/2]])/(8*d) + (b* Log[Sin[c + d*x]])/d + (3*a*Sec[(c + d*x)/2]^2)/(32*d) + (a*Sec[(c + d*x)/ 2]^4)/(64*d)
Time = 0.63 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.01, number of steps used = 19, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.947, Rules used = {3042, 4360, 25, 25, 3042, 25, 3313, 25, 3042, 3100, 243, 49, 2009, 4255, 3042, 4255, 3042, 4257}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {a-b \csc \left (c+d x-\frac {\pi }{2}\right )}{\cos \left (c+d x-\frac {\pi }{2}\right )^5}dx\) |
| \(\Big \downarrow \) 4360 |
| \(\displaystyle \int -\left (\csc ^5(c+d x) \sec (c+d x) (-a \cos (c+d x)-b)\right )dx\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle -\int -\left ((b+a \cos (c+d x)) \csc ^5(c+d x) \sec (c+d x)\right )dx\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \int \csc ^5(c+d x) \sec (c+d x) (a \cos (c+d x)+b)dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int -\frac {b-a \sin \left (c+d x-\frac {\pi }{2}\right )}{\sin \left (c+d x-\frac {\pi }{2}\right ) \cos \left (c+d x-\frac {\pi }{2}\right )^5}dx\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle -\int \frac {b-a \sin \left (\frac {1}{2} (2 c-\pi )+d x\right )}{\cos \left (\frac {1}{2} (2 c-\pi )+d x\right )^5 \sin \left (\frac {1}{2} (2 c-\pi )+d x\right )}dx\) |
| \(\Big \downarrow \) 3313 |
| \(\displaystyle a \int \csc ^5(c+d x)dx-b \int -\csc ^5(c+d x) \sec (c+d x)dx\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle a \int \csc ^5(c+d x)dx+b \int \csc ^5(c+d x) \sec (c+d x)dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a \int \csc (c+d x)^5dx+b \int \csc (c+d x)^5 \sec (c+d x)dx\) |
| \(\Big \downarrow \) 3100 |
| \(\displaystyle a \int \csc (c+d x)^5dx+\frac {b \int \cot ^5(c+d x) \left (\tan ^2(c+d x)+1\right )^2d\tan (c+d x)}{d}\) |
| \(\Big \downarrow \) 243 |
| \(\displaystyle a \int \csc (c+d x)^5dx+\frac {b \int \cot ^3(c+d x) \left (\tan ^2(c+d x)+1\right )^2d\tan ^2(c+d x)}{2 d}\) |
| \(\Big \downarrow \) 49 |
| \(\displaystyle a \int \csc (c+d x)^5dx+\frac {b \int \left (\cot ^3(c+d x)+2 \cot ^2(c+d x)+\cot (c+d x)\right )d\tan ^2(c+d x)}{2 d}\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle a \int \csc (c+d x)^5dx+\frac {b \left (-\frac {1}{2} \cot ^2(c+d x)-2 \cot (c+d x)+\log \left (\tan ^2(c+d x)\right )\right )}{2 d}\) |
| \(\Big \downarrow \) 4255 |
| \(\displaystyle a \left (\frac {3}{4} \int \csc ^3(c+d x)dx-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 d}\right )+\frac {b \left (-\frac {1}{2} \cot ^2(c+d x)-2 \cot (c+d x)+\log \left (\tan ^2(c+d x)\right )\right )}{2 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a \left (\frac {3}{4} \int \csc (c+d x)^3dx-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 d}\right )+\frac {b \left (-\frac {1}{2} \cot ^2(c+d x)-2 \cot (c+d x)+\log \left (\tan ^2(c+d x)\right )\right )}{2 d}\) |
| \(\Big \downarrow \) 4255 |
| \(\displaystyle a \left (\frac {3}{4} \left (\frac {1}{2} \int \csc (c+d x)dx-\frac {\cot (c+d x) \csc (c+d x)}{2 d}\right )-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 d}\right )+\frac {b \left (-\frac {1}{2} \cot ^2(c+d x)-2 \cot (c+d x)+\log \left (\tan ^2(c+d x)\right )\right )}{2 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a \left (\frac {3}{4} \left (\frac {1}{2} \int \csc (c+d x)dx-\frac {\cot (c+d x) \csc (c+d x)}{2 d}\right )-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 d}\right )+\frac {b \left (-\frac {1}{2} \cot ^2(c+d x)-2 \cot (c+d x)+\log \left (\tan ^2(c+d x)\right )\right )}{2 d}\) |
| \(\Big \downarrow \) 4257 |
| \(\displaystyle a \left (\frac {3}{4} \left (-\frac {\text {arctanh}(\cos (c+d x))}{2 d}-\frac {\cot (c+d x) \csc (c+d x)}{2 d}\right )-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 d}\right )+\frac {b \left (-\frac {1}{2} \cot ^2(c+d x)-2 \cot (c+d x)+\log \left (\tan ^2(c+d x)\right )\right )}{2 d}\) |
Input:
Int[Csc[c + d*x]^5*(a + b*Sec[c + d*x]),x]
Output:
a*(-1/4*(Cot[c + d*x]*Csc[c + d*x]^3)/d + (3*(-1/2*ArcTanh[Cos[c + d*x]]/d - (Cot[c + d*x]*Csc[c + d*x])/(2*d)))/4) + (b*(-2*Cot[c + d*x] - Cot[c + d*x]^2/2 + Log[Tan[c + d*x]^2]))/(2*d)
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int [ExpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 0] && IGtQ[m + n + 2, 0]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/2 Subst[In t[x^((m - 1)/2)*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, m, p}, x] && I ntegerQ[(m - 1)/2]
Int[csc[(e_.) + (f_.)*(x_)]^(m_.)*sec[(e_.) + (f_.)*(x_)]^(n_.), x_Symbol] :> Simp[1/f Subst[Int[(1 + x^2)^((m + n)/2 - 1)/x^m, x], x, Tan[e + f*x]] , x] /; FreeQ[{e, f}, x] && IntegersQ[m, n, (m + n)/2]
Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((a_ ) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[a Int[Cos[e + f*x]^ p*(d*Sin[e + f*x])^n, x], x] + Simp[b/d Int[Cos[e + f*x]^p*(d*Sin[e + f*x ])^(n + 1), x], x] /; FreeQ[{a, b, d, e, f, n, p}, x] && IntegerQ[(p - 1)/2 ] && IntegerQ[n] && ((LtQ[p, 0] && NeQ[a^2 - b^2, 0]) || LtQ[0, n, p - 1] | | LtQ[p + 1, -n, 2*p + 1])
Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(-b)*Cos[c + d* x]*((b*Csc[c + d*x])^(n - 1)/(d*(n - 1))), x] + Simp[b^2*((n - 2)/(n - 1)) Int[(b*Csc[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && IntegerQ[2*n]
Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_.), x_Symbol] :> Int[(g*Cos[e + f*x])^p*((b + a*Sin[e + f*x])^m/Si n[e + f*x]^m), x] /; FreeQ[{a, b, e, f, g, p}, x] && IntegerQ[m]
Time = 0.31 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.83
| method | result | size |
| derivativedivides | \(\frac {a \left (\left (-\frac {\csc \left (d x +c \right )^{3}}{4}-\frac {3 \csc \left (d x +c \right )}{8}\right ) \cot \left (d x +c \right )+\frac {3 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{8}\right )+b \left (-\frac {1}{4 \sin \left (d x +c \right )^{4}}-\frac {1}{2 \sin \left (d x +c \right )^{2}}+\ln \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(83\) |
| default | \(\frac {a \left (\left (-\frac {\csc \left (d x +c \right )^{3}}{4}-\frac {3 \csc \left (d x +c \right )}{8}\right ) \cot \left (d x +c \right )+\frac {3 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{8}\right )+b \left (-\frac {1}{4 \sin \left (d x +c \right )^{4}}-\frac {1}{2 \sin \left (d x +c \right )^{2}}+\ln \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(83\) |
| parallelrisch | \(\frac {-64 b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-64 b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (24 a +64 b \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-a -b \right ) \cot \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+\left (-8 a -12 b \right ) \cot \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} \left (a -b \right )+8 a -12 b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{64 d}\) | \(129\) |
| norman | \(\frac {-\frac {a +b}{64 d}+\frac {\left (a -b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{64 d}+\frac {\left (2 a -3 b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{16 d}-\frac {\left (2 a +3 b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{16 d}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}-\frac {b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d}-\frac {b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d}+\frac {\left (3 a +8 b \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}\) | \(148\) |
| risch | \(\frac {3 a \,{\mathrm e}^{7 i \left (d x +c \right )}+8 b \,{\mathrm e}^{6 i \left (d x +c \right )}-11 a \,{\mathrm e}^{5 i \left (d x +c \right )}-32 b \,{\mathrm e}^{4 i \left (d x +c \right )}-11 a \,{\mathrm e}^{3 i \left (d x +c \right )}+8 b \,{\mathrm e}^{2 i \left (d x +c \right )}+3 a \,{\mathrm e}^{i \left (d x +c \right )}}{4 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{4}}+\frac {3 a \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{8 d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right ) b}{d}-\frac {3 a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{8 d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right ) b}{d}-\frac {b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}\) | \(193\) |
Input:
int(csc(d*x+c)^5*(a+b*sec(d*x+c)),x,method=_RETURNVERBOSE)
Output:
1/d*(a*((-1/4*csc(d*x+c)^3-3/8*csc(d*x+c))*cot(d*x+c)+3/8*ln(csc(d*x+c)-co t(d*x+c)))+b*(-1/4/sin(d*x+c)^4-1/2/sin(d*x+c)^2+ln(tan(d*x+c))))
Leaf count of result is larger than twice the leaf count of optimal. 201 vs. \(2 (92) = 184\).
Time = 0.09 (sec) , antiderivative size = 201, normalized size of antiderivative = 2.01 \[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=\frac {6 \, a \cos \left (d x + c\right )^{3} + 8 \, b \cos \left (d x + c\right )^{2} - 10 \, a \cos \left (d x + c\right ) - 16 \, {\left (b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + b\right )} \log \left (-\cos \left (d x + c\right )\right ) - {\left ({\left (3 \, a - 8 \, b\right )} \cos \left (d x + c\right )^{4} - 2 \, {\left (3 \, a - 8 \, b\right )} \cos \left (d x + c\right )^{2} + 3 \, a - 8 \, b\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + {\left ({\left (3 \, a + 8 \, b\right )} \cos \left (d x + c\right )^{4} - 2 \, {\left (3 \, a + 8 \, b\right )} \cos \left (d x + c\right )^{2} + 3 \, a + 8 \, b\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 12 \, b}{16 \, {\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )}} \] Input:
integrate(csc(d*x+c)^5*(a+b*sec(d*x+c)),x, algorithm="fricas")
Output:
1/16*(6*a*cos(d*x + c)^3 + 8*b*cos(d*x + c)^2 - 10*a*cos(d*x + c) - 16*(b* cos(d*x + c)^4 - 2*b*cos(d*x + c)^2 + b)*log(-cos(d*x + c)) - ((3*a - 8*b) *cos(d*x + c)^4 - 2*(3*a - 8*b)*cos(d*x + c)^2 + 3*a - 8*b)*log(1/2*cos(d* x + c) + 1/2) + ((3*a + 8*b)*cos(d*x + c)^4 - 2*(3*a + 8*b)*cos(d*x + c)^2 + 3*a + 8*b)*log(-1/2*cos(d*x + c) + 1/2) - 12*b)/(d*cos(d*x + c)^4 - 2*d *cos(d*x + c)^2 + d)
\[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=\int \left (a + b \sec {\left (c + d x \right )}\right ) \csc ^{5}{\left (c + d x \right )}\, dx \] Input:
integrate(csc(d*x+c)**5*(a+b*sec(d*x+c)),x)
Output:
Integral((a + b*sec(c + d*x))*csc(c + d*x)**5, x)
Time = 0.03 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.10 \[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=-\frac {{\left (3 \, a - 8 \, b\right )} \log \left (\cos \left (d x + c\right ) + 1\right ) - {\left (3 \, a + 8 \, b\right )} \log \left (\cos \left (d x + c\right ) - 1\right ) + 16 \, b \log \left (\cos \left (d x + c\right )\right ) - \frac {2 \, {\left (3 \, a \cos \left (d x + c\right )^{3} + 4 \, b \cos \left (d x + c\right )^{2} - 5 \, a \cos \left (d x + c\right ) - 6 \, b\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1}}{16 \, d} \] Input:
integrate(csc(d*x+c)^5*(a+b*sec(d*x+c)),x, algorithm="maxima")
Output:
-1/16*((3*a - 8*b)*log(cos(d*x + c) + 1) - (3*a + 8*b)*log(cos(d*x + c) - 1) + 16*b*log(cos(d*x + c)) - 2*(3*a*cos(d*x + c)^3 + 4*b*cos(d*x + c)^2 - 5*a*cos(d*x + c) - 6*b)/(cos(d*x + c)^4 - 2*cos(d*x + c)^2 + 1))/d
Time = 0.12 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.19 \[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=-\frac {{\left (3 \, a - 8 \, b\right )} \log \left ({\left | \cos \left (d x + c\right ) + 1 \right |}\right )}{16 \, d} + \frac {{\left (3 \, a + 8 \, b\right )} \log \left ({\left | \cos \left (d x + c\right ) - 1 \right |}\right )}{16 \, d} - \frac {b \log \left ({\left | \cos \left (d x + c\right ) \right |}\right )}{d} + \frac {3 \, a \cos \left (d x + c\right )^{3} + 4 \, b \cos \left (d x + c\right )^{2} - 5 \, a \cos \left (d x + c\right ) - 6 \, b}{8 \, d {\left (\cos \left (d x + c\right ) + 1\right )}^{2} {\left (\cos \left (d x + c\right ) - 1\right )}^{2}} \] Input:
integrate(csc(d*x+c)^5*(a+b*sec(d*x+c)),x, algorithm="giac")
Output:
-1/16*(3*a - 8*b)*log(abs(cos(d*x + c) + 1))/d + 1/16*(3*a + 8*b)*log(abs( cos(d*x + c) - 1))/d - b*log(abs(cos(d*x + c)))/d + 1/8*(3*a*cos(d*x + c)^ 3 + 4*b*cos(d*x + c)^2 - 5*a*cos(d*x + c) - 6*b)/(d*(cos(d*x + c) + 1)^2*( cos(d*x + c) - 1)^2)
Time = 10.97 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.17 \[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=\frac {\ln \left (\cos \left (c+d\,x\right )-1\right )\,\left (\frac {3\,a}{16}+\frac {b}{2}\right )}{d}-\frac {-\frac {3\,a\,{\cos \left (c+d\,x\right )}^3}{8}-\frac {b\,{\cos \left (c+d\,x\right )}^2}{2}+\frac {5\,a\,\cos \left (c+d\,x\right )}{8}+\frac {3\,b}{4}}{d\,\left ({\cos \left (c+d\,x\right )}^4-2\,{\cos \left (c+d\,x\right )}^2+1\right )}-\frac {\ln \left (\cos \left (c+d\,x\right )+1\right )\,\left (\frac {3\,a}{16}-\frac {b}{2}\right )}{d}-\frac {b\,\ln \left (\cos \left (c+d\,x\right )\right )}{d} \] Input:
int((a + b/cos(c + d*x))/sin(c + d*x)^5,x)
Output:
(log(cos(c + d*x) - 1)*((3*a)/16 + b/2))/d - ((3*b)/4 + (5*a*cos(c + d*x)) /8 - (3*a*cos(c + d*x)^3)/8 - (b*cos(c + d*x)^2)/2)/(d*(cos(c + d*x)^4 - 2 *cos(c + d*x)^2 + 1)) - (log(cos(c + d*x) + 1)*((3*a)/16 - b/2))/d - (b*lo g(cos(c + d*x)))/d
Time = 0.17 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.53 \[ \int \csc ^5(c+d x) (a+b \sec (c+d x)) \, dx=\frac {-12 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} a -8 \cos \left (d x +c \right ) a -32 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \sin \left (d x +c \right )^{4} b -32 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \sin \left (d x +c \right )^{4} b +12 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{4} a +32 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{4} b +11 \sin \left (d x +c \right )^{4} b -16 \sin \left (d x +c \right )^{2} b -8 b}{32 \sin \left (d x +c \right )^{4} d} \] Input:
int(csc(d*x+c)^5*(a+b*sec(d*x+c)),x)
Output:
( - 12*cos(c + d*x)*sin(c + d*x)**2*a - 8*cos(c + d*x)*a - 32*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**4*b - 32*log(tan((c + d*x)/2) + 1)*sin(c + d*x )**4*b + 12*log(tan((c + d*x)/2))*sin(c + d*x)**4*a + 32*log(tan((c + d*x) /2))*sin(c + d*x)**4*b + 11*sin(c + d*x)**4*b - 16*sin(c + d*x)**2*b - 8*b )/(32*sin(c + d*x)**4*d)