\(\int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx\) [78]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [B] (warning: unable to verify)
Fricas [A] (verification not implemented)
Sympy [F]
Maxima [F(-1)]
Giac [A] (verification not implemented)
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 34, antiderivative size = 164 \[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=-\frac {a^2 \arctan \left (\frac {\sqrt {c} \tan (e+f x)}{\sqrt {2} \sqrt {c-c \sec (e+f x)}}\right )}{16 \sqrt {2} c^{7/2} f}-\frac {\left (a^2+a^2 \sec (e+f x)\right ) \tan (e+f x)}{3 f (c-c \sec (e+f x))^{7/2}}+\frac {a^2 \tan (e+f x)}{4 c f (c-c \sec (e+f x))^{5/2}}-\frac {a^2 \tan (e+f x)}{16 c^2 f (c-c \sec (e+f x))^{3/2}} \] Output:

-1/32*a^2*arctan(1/2*c^(1/2)*tan(f*x+e)*2^(1/2)/(c-c*sec(f*x+e))^(1/2))*2^ 
(1/2)/c^(7/2)/f-1/3*(a^2+a^2*sec(f*x+e))*tan(f*x+e)/f/(c-c*sec(f*x+e))^(7/ 
2)+1/4*a^2*tan(f*x+e)/c/f/(c-c*sec(f*x+e))^(5/2)-1/16*a^2*tan(f*x+e)/c^2/f 
/(c-c*sec(f*x+e))^(3/2)
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.52 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.39 \[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=-\frac {a^2 \operatorname {Hypergeometric2F1}\left (\frac {5}{2},4,\frac {7}{2},\frac {1}{2} (1+\sec (e+f x))\right ) (1+\sec (e+f x))^2 \tan (e+f x)}{40 c^3 f \sqrt {c-c \sec (e+f x)}} \] Input:

Integrate[(Sec[e + f*x]*(a + a*Sec[e + f*x])^2)/(c - c*Sec[e + f*x])^(7/2) 
,x]
 

Output:

-1/40*(a^2*Hypergeometric2F1[5/2, 4, 7/2, (1 + Sec[e + f*x])/2]*(1 + Sec[e 
 + f*x])^2*Tan[e + f*x])/(c^3*f*Sqrt[c - c*Sec[e + f*x]])
 

Rubi [A] (verified)

Time = 0.79 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.02, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.265, Rules used = {3042, 4445, 3042, 4445, 3042, 4283, 3042, 4282, 216}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sec (e+f x) (a \sec (e+f x)+a)^2}{(c-c \sec (e+f x))^{7/2}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\csc \left (e+f x+\frac {\pi }{2}\right ) \left (a \csc \left (e+f x+\frac {\pi }{2}\right )+a\right )^2}{\left (c-c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{7/2}}dx\)

\(\Big \downarrow \) 4445

\(\displaystyle -\frac {a \int \frac {\sec (e+f x) (\sec (e+f x) a+a)}{(c-c \sec (e+f x))^{5/2}}dx}{2 c}-\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \int \frac {\csc \left (e+f x+\frac {\pi }{2}\right ) \left (\csc \left (e+f x+\frac {\pi }{2}\right ) a+a\right )}{\left (c-c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{5/2}}dx}{2 c}-\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}\)

\(\Big \downarrow \) 4445

\(\displaystyle -\frac {a \left (-\frac {a \int \frac {\sec (e+f x)}{(c-c \sec (e+f x))^{3/2}}dx}{4 c}-\frac {a \tan (e+f x)}{2 f (c-c \sec (e+f x))^{5/2}}\right )}{2 c}-\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \left (-\frac {a \int \frac {\csc \left (e+f x+\frac {\pi }{2}\right )}{\left (c-c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}dx}{4 c}-\frac {a \tan (e+f x)}{2 f (c-c \sec (e+f x))^{5/2}}\right )}{2 c}-\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}\)

\(\Big \downarrow \) 4283

\(\displaystyle -\frac {a \left (-\frac {a \left (\frac {\int \frac {\sec (e+f x)}{\sqrt {c-c \sec (e+f x)}}dx}{4 c}-\frac {\tan (e+f x)}{2 f (c-c \sec (e+f x))^{3/2}}\right )}{4 c}-\frac {a \tan (e+f x)}{2 f (c-c \sec (e+f x))^{5/2}}\right )}{2 c}-\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \left (-\frac {a \left (\frac {\int \frac {\csc \left (e+f x+\frac {\pi }{2}\right )}{\sqrt {c-c \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{4 c}-\frac {\tan (e+f x)}{2 f (c-c \sec (e+f x))^{3/2}}\right )}{4 c}-\frac {a \tan (e+f x)}{2 f (c-c \sec (e+f x))^{5/2}}\right )}{2 c}-\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}\)

\(\Big \downarrow \) 4282

\(\displaystyle -\frac {a \left (-\frac {a \left (-\frac {\int \frac {1}{\frac {c^2 \tan ^2(e+f x)}{c-c \sec (e+f x)}+2 c}d\frac {c \tan (e+f x)}{\sqrt {c-c \sec (e+f x)}}}{2 c f}-\frac {\tan (e+f x)}{2 f (c-c \sec (e+f x))^{3/2}}\right )}{4 c}-\frac {a \tan (e+f x)}{2 f (c-c \sec (e+f x))^{5/2}}\right )}{2 c}-\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}\)

\(\Big \downarrow \) 216

\(\displaystyle -\frac {\tan (e+f x) \left (a^2 \sec (e+f x)+a^2\right )}{3 f (c-c \sec (e+f x))^{7/2}}-\frac {a \left (-\frac {a \left (-\frac {\arctan \left (\frac {\sqrt {c} \tan (e+f x)}{\sqrt {2} \sqrt {c-c \sec (e+f x)}}\right )}{2 \sqrt {2} c^{3/2} f}-\frac {\tan (e+f x)}{2 f (c-c \sec (e+f x))^{3/2}}\right )}{4 c}-\frac {a \tan (e+f x)}{2 f (c-c \sec (e+f x))^{5/2}}\right )}{2 c}\)

Input:

Int[(Sec[e + f*x]*(a + a*Sec[e + f*x])^2)/(c - c*Sec[e + f*x])^(7/2),x]
 

Output:

-1/3*((a^2 + a^2*Sec[e + f*x])*Tan[e + f*x])/(f*(c - c*Sec[e + f*x])^(7/2) 
) - (a*(-1/2*(a*Tan[e + f*x])/(f*(c - c*Sec[e + f*x])^(5/2)) - (a*(-1/2*Ar 
cTan[(Sqrt[c]*Tan[e + f*x])/(Sqrt[2]*Sqrt[c - c*Sec[e + f*x]])]/(Sqrt[2]*c 
^(3/2)*f) - Tan[e + f*x]/(2*f*(c - c*Sec[e + f*x])^(3/2))))/(4*c)))/(2*c)
 

Defintions of rubi rules used

rule 216
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A 
rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a 
, 0] || GtQ[b, 0])
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4282
Int[csc[(e_.) + (f_.)*(x_)]/Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)], x_S 
ymbol] :> Simp[-2/f   Subst[Int[1/(2*a + x^2), x], x, b*(Cot[e + f*x]/Sqrt[ 
a + b*Csc[e + f*x]])], x] /; FreeQ[{a, b, e, f}, x] && EqQ[a^2 - b^2, 0]
 

rule 4283
Int[csc[(e_.) + (f_.)*(x_)]*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_), x_ 
Symbol] :> Simp[b*Cot[e + f*x]*((a + b*Csc[e + f*x])^m/(a*f*(2*m + 1))), x] 
 + Simp[(m + 1)/(a*(2*m + 1))   Int[Csc[e + f*x]*(a + b*Csc[e + f*x])^(m + 
1), x], x] /; FreeQ[{a, b, e, f}, x] && EqQ[a^2 - b^2, 0] && LtQ[m, -2^(-1) 
] && IntegerQ[2*m]
 

rule 4445
Int[csc[(e_.) + (f_.)*(x_)]*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_)*(cs 
c[(e_.) + (f_.)*(x_)]*(d_.) + (c_))^(n_.), x_Symbol] :> Simp[2*a*c*Cot[e + 
f*x]*(a + b*Csc[e + f*x])^m*((c + d*Csc[e + f*x])^(n - 1)/(b*f*(2*m + 1))), 
 x] - Simp[d*((2*n - 1)/(b*(2*m + 1)))   Int[Csc[e + f*x]*(a + b*Csc[e + f* 
x])^(m + 1)*(c + d*Csc[e + f*x])^(n - 1), x], x] /; FreeQ[{a, b, c, d, e, f 
}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] && IGtQ[n, 0] && LtQ[m, -2^ 
(-1)] && IntegerQ[2*m]
 
Maple [B] (warning: unable to verify)

Leaf count of result is larger than twice the leaf count of optimal. \(367\) vs. \(2(141)=282\).

Time = 4.74 (sec) , antiderivative size = 368, normalized size of antiderivative = 2.24

method result size
default \(\frac {a^{2} \sqrt {2}\, \left (\left (14 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{4}+8 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-6\right ) \sqrt {\frac {2 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1}{\left (\cos \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}}\, \cot \left (\frac {f x}{2}+\frac {e}{2}\right ) \csc \left (\frac {f x}{2}+\frac {e}{2}\right )^{4}+\ln \left (\frac {2 \sqrt {\frac {2 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1}{\left (\cos \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}}\, \cos \left (\frac {f x}{2}+\frac {e}{2}\right )+2 \sqrt {\frac {2 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1}{\left (\cos \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}}-4 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )-2}{\cos \left (\frac {f x}{2}+\frac {e}{2}\right )+1}\right ) \left (-3 \cot \left (\frac {f x}{2}+\frac {e}{2}\right )+3 \csc \left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\operatorname {arctanh}\left (\frac {2 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )-1}{\left (\cos \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right ) \sqrt {\frac {2 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1}{\left (\cos \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}}}\right ) \left (3 \cot \left (\frac {f x}{2}+\frac {e}{2}\right )-3 \csc \left (\frac {f x}{2}+\frac {e}{2}\right )\right )\right )}{192 c^{3} f \sqrt {-\frac {c \sin \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}}{2 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1}}\, \sqrt {\frac {2 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1}{\left (\cos \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}}}\) \(368\)
parts \(\text {Expression too large to display}\) \(1103\)

Input:

int(sec(f*x+e)*(a+a*sec(f*x+e))^2/(c-c*sec(f*x+e))^(7/2),x,method=_RETURNV 
ERBOSE)
 

Output:

1/192*a^2/c^3*2^(1/2)/f/(-c/(2*cos(1/2*f*x+1/2*e)^2-1)*sin(1/2*f*x+1/2*e)^ 
2)^(1/2)/((2*cos(1/2*f*x+1/2*e)^2-1)/(cos(1/2*f*x+1/2*e)+1)^2)^(1/2)*((14* 
cos(1/2*f*x+1/2*e)^4+8*cos(1/2*f*x+1/2*e)^2-6)*((2*cos(1/2*f*x+1/2*e)^2-1) 
/(cos(1/2*f*x+1/2*e)+1)^2)^(1/2)*cot(1/2*f*x+1/2*e)*csc(1/2*f*x+1/2*e)^4+l 
n(2*(((2*cos(1/2*f*x+1/2*e)^2-1)/(cos(1/2*f*x+1/2*e)+1)^2)^(1/2)*cos(1/2*f 
*x+1/2*e)+((2*cos(1/2*f*x+1/2*e)^2-1)/(cos(1/2*f*x+1/2*e)+1)^2)^(1/2)-2*co 
s(1/2*f*x+1/2*e)-1)/(cos(1/2*f*x+1/2*e)+1))*(-3*cot(1/2*f*x+1/2*e)+3*csc(1 
/2*f*x+1/2*e))+arctanh((2*cos(1/2*f*x+1/2*e)-1)/(cos(1/2*f*x+1/2*e)+1)/((2 
*cos(1/2*f*x+1/2*e)^2-1)/(cos(1/2*f*x+1/2*e)+1)^2)^(1/2))*(3*cot(1/2*f*x+1 
/2*e)-3*csc(1/2*f*x+1/2*e)))
 

Fricas [A] (verification not implemented)

Time = 0.19 (sec) , antiderivative size = 517, normalized size of antiderivative = 3.15 \[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=\left [-\frac {3 \, \sqrt {2} {\left (a^{2} \cos \left (f x + e\right )^{3} - 3 \, a^{2} \cos \left (f x + e\right )^{2} + 3 \, a^{2} \cos \left (f x + e\right ) - a^{2}\right )} \sqrt {-c} \log \left (\frac {2 \, \sqrt {2} {\left (\cos \left (f x + e\right )^{2} + \cos \left (f x + e\right )\right )} \sqrt {-c} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} + {\left (3 \, c \cos \left (f x + e\right ) + c\right )} \sin \left (f x + e\right )}{{\left (\cos \left (f x + e\right ) - 1\right )} \sin \left (f x + e\right )}\right ) \sin \left (f x + e\right ) - 4 \, {\left (7 \, a^{2} \cos \left (f x + e\right )^{4} + 29 \, a^{2} \cos \left (f x + e\right )^{3} + 25 \, a^{2} \cos \left (f x + e\right )^{2} + 3 \, a^{2} \cos \left (f x + e\right )\right )} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}}}{192 \, {\left (c^{4} f \cos \left (f x + e\right )^{3} - 3 \, c^{4} f \cos \left (f x + e\right )^{2} + 3 \, c^{4} f \cos \left (f x + e\right ) - c^{4} f\right )} \sin \left (f x + e\right )}, \frac {3 \, \sqrt {2} {\left (a^{2} \cos \left (f x + e\right )^{3} - 3 \, a^{2} \cos \left (f x + e\right )^{2} + 3 \, a^{2} \cos \left (f x + e\right ) - a^{2}\right )} \sqrt {c} \arctan \left (\frac {\sqrt {2} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{\sqrt {c} \sin \left (f x + e\right )}\right ) \sin \left (f x + e\right ) + 2 \, {\left (7 \, a^{2} \cos \left (f x + e\right )^{4} + 29 \, a^{2} \cos \left (f x + e\right )^{3} + 25 \, a^{2} \cos \left (f x + e\right )^{2} + 3 \, a^{2} \cos \left (f x + e\right )\right )} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}}}{96 \, {\left (c^{4} f \cos \left (f x + e\right )^{3} - 3 \, c^{4} f \cos \left (f x + e\right )^{2} + 3 \, c^{4} f \cos \left (f x + e\right ) - c^{4} f\right )} \sin \left (f x + e\right )}\right ] \] Input:

integrate(sec(f*x+e)*(a+a*sec(f*x+e))^2/(c-c*sec(f*x+e))^(7/2),x, algorith 
m="fricas")
 

Output:

[-1/192*(3*sqrt(2)*(a^2*cos(f*x + e)^3 - 3*a^2*cos(f*x + e)^2 + 3*a^2*cos( 
f*x + e) - a^2)*sqrt(-c)*log((2*sqrt(2)*(cos(f*x + e)^2 + cos(f*x + e))*sq 
rt(-c)*sqrt((c*cos(f*x + e) - c)/cos(f*x + e)) + (3*c*cos(f*x + e) + c)*si 
n(f*x + e))/((cos(f*x + e) - 1)*sin(f*x + e)))*sin(f*x + e) - 4*(7*a^2*cos 
(f*x + e)^4 + 29*a^2*cos(f*x + e)^3 + 25*a^2*cos(f*x + e)^2 + 3*a^2*cos(f* 
x + e))*sqrt((c*cos(f*x + e) - c)/cos(f*x + e)))/((c^4*f*cos(f*x + e)^3 - 
3*c^4*f*cos(f*x + e)^2 + 3*c^4*f*cos(f*x + e) - c^4*f)*sin(f*x + e)), 1/96 
*(3*sqrt(2)*(a^2*cos(f*x + e)^3 - 3*a^2*cos(f*x + e)^2 + 3*a^2*cos(f*x + e 
) - a^2)*sqrt(c)*arctan(sqrt(2)*sqrt((c*cos(f*x + e) - c)/cos(f*x + e))*co 
s(f*x + e)/(sqrt(c)*sin(f*x + e)))*sin(f*x + e) + 2*(7*a^2*cos(f*x + e)^4 
+ 29*a^2*cos(f*x + e)^3 + 25*a^2*cos(f*x + e)^2 + 3*a^2*cos(f*x + e))*sqrt 
((c*cos(f*x + e) - c)/cos(f*x + e)))/((c^4*f*cos(f*x + e)^3 - 3*c^4*f*cos( 
f*x + e)^2 + 3*c^4*f*cos(f*x + e) - c^4*f)*sin(f*x + e))]
 

Sympy [F]

\[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=a^{2} \left (\int \frac {\sec {\left (e + f x \right )}}{- c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec ^{3}{\left (e + f x \right )} + 3 c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec ^{2}{\left (e + f x \right )} - 3 c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec {\left (e + f x \right )} + c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c}}\, dx + \int \frac {2 \sec ^{2}{\left (e + f x \right )}}{- c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec ^{3}{\left (e + f x \right )} + 3 c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec ^{2}{\left (e + f x \right )} - 3 c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec {\left (e + f x \right )} + c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c}}\, dx + \int \frac {\sec ^{3}{\left (e + f x \right )}}{- c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec ^{3}{\left (e + f x \right )} + 3 c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec ^{2}{\left (e + f x \right )} - 3 c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c} \sec {\left (e + f x \right )} + c^{3} \sqrt {- c \sec {\left (e + f x \right )} + c}}\, dx\right ) \] Input:

integrate(sec(f*x+e)*(a+a*sec(f*x+e))**2/(c-c*sec(f*x+e))**(7/2),x)
 

Output:

a**2*(Integral(sec(e + f*x)/(-c**3*sqrt(-c*sec(e + f*x) + c)*sec(e + f*x)* 
*3 + 3*c**3*sqrt(-c*sec(e + f*x) + c)*sec(e + f*x)**2 - 3*c**3*sqrt(-c*sec 
(e + f*x) + c)*sec(e + f*x) + c**3*sqrt(-c*sec(e + f*x) + c)), x) + Integr 
al(2*sec(e + f*x)**2/(-c**3*sqrt(-c*sec(e + f*x) + c)*sec(e + f*x)**3 + 3* 
c**3*sqrt(-c*sec(e + f*x) + c)*sec(e + f*x)**2 - 3*c**3*sqrt(-c*sec(e + f* 
x) + c)*sec(e + f*x) + c**3*sqrt(-c*sec(e + f*x) + c)), x) + Integral(sec( 
e + f*x)**3/(-c**3*sqrt(-c*sec(e + f*x) + c)*sec(e + f*x)**3 + 3*c**3*sqrt 
(-c*sec(e + f*x) + c)*sec(e + f*x)**2 - 3*c**3*sqrt(-c*sec(e + f*x) + c)*s 
ec(e + f*x) + c**3*sqrt(-c*sec(e + f*x) + c)), x))
 

Maxima [F(-1)]

Timed out. \[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=\text {Timed out} \] Input:

integrate(sec(f*x+e)*(a+a*sec(f*x+e))^2/(c-c*sec(f*x+e))^(7/2),x, algorith 
m="maxima")
 

Output:

Timed out
 

Giac [A] (verification not implemented)

Time = 0.56 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.81 \[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=\frac {\sqrt {2} {\left (\frac {3 \, a^{2} \arctan \left (\frac {\sqrt {c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - c}}{\sqrt {c}}\right )}{c^{\frac {7}{2}}} + \frac {3 \, {\left (c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - c\right )}^{\frac {5}{2}} a^{2} + 8 \, {\left (c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - c\right )}^{\frac {3}{2}} a^{2} c - 3 \, \sqrt {c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - c} a^{2} c^{2}}{c^{6} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{6}}\right )}}{96 \, f} \] Input:

integrate(sec(f*x+e)*(a+a*sec(f*x+e))^2/(c-c*sec(f*x+e))^(7/2),x, algorith 
m="giac")
 

Output:

1/96*sqrt(2)*(3*a^2*arctan(sqrt(c*tan(1/2*f*x + 1/2*e)^2 - c)/sqrt(c))/c^( 
7/2) + (3*(c*tan(1/2*f*x + 1/2*e)^2 - c)^(5/2)*a^2 + 8*(c*tan(1/2*f*x + 1/ 
2*e)^2 - c)^(3/2)*a^2*c - 3*sqrt(c*tan(1/2*f*x + 1/2*e)^2 - c)*a^2*c^2)/(c 
^6*tan(1/2*f*x + 1/2*e)^6))/f
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=\int \frac {{\left (a+\frac {a}{\cos \left (e+f\,x\right )}\right )}^2}{\cos \left (e+f\,x\right )\,{\left (c-\frac {c}{\cos \left (e+f\,x\right )}\right )}^{7/2}} \,d x \] Input:

int((a + a/cos(e + f*x))^2/(cos(e + f*x)*(c - c/cos(e + f*x))^(7/2)),x)
 

Output:

int((a + a/cos(e + f*x))^2/(cos(e + f*x)*(c - c/cos(e + f*x))^(7/2)), x)
 

Reduce [F]

\[ \int \frac {\sec (e+f x) (a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^{7/2}} \, dx=\frac {\sqrt {c}\, a^{2} \left (\int \frac {\sqrt {-\sec \left (f x +e \right )+1}\, \sec \left (f x +e \right )^{3}}{\sec \left (f x +e \right )^{4}-4 \sec \left (f x +e \right )^{3}+6 \sec \left (f x +e \right )^{2}-4 \sec \left (f x +e \right )+1}d x +2 \left (\int \frac {\sqrt {-\sec \left (f x +e \right )+1}\, \sec \left (f x +e \right )^{2}}{\sec \left (f x +e \right )^{4}-4 \sec \left (f x +e \right )^{3}+6 \sec \left (f x +e \right )^{2}-4 \sec \left (f x +e \right )+1}d x \right )+\int \frac {\sqrt {-\sec \left (f x +e \right )+1}\, \sec \left (f x +e \right )}{\sec \left (f x +e \right )^{4}-4 \sec \left (f x +e \right )^{3}+6 \sec \left (f x +e \right )^{2}-4 \sec \left (f x +e \right )+1}d x \right )}{c^{4}} \] Input:

int(sec(f*x+e)*(a+a*sec(f*x+e))^2/(c-c*sec(f*x+e))^(7/2),x)
 

Output:

(sqrt(c)*a**2*(int((sqrt( - sec(e + f*x) + 1)*sec(e + f*x)**3)/(sec(e + f* 
x)**4 - 4*sec(e + f*x)**3 + 6*sec(e + f*x)**2 - 4*sec(e + f*x) + 1),x) + 2 
*int((sqrt( - sec(e + f*x) + 1)*sec(e + f*x)**2)/(sec(e + f*x)**4 - 4*sec( 
e + f*x)**3 + 6*sec(e + f*x)**2 - 4*sec(e + f*x) + 1),x) + int((sqrt( - se 
c(e + f*x) + 1)*sec(e + f*x))/(sec(e + f*x)**4 - 4*sec(e + f*x)**3 + 6*sec 
(e + f*x)**2 - 4*sec(e + f*x) + 1),x)))/c**4