Integrand size = 41, antiderivative size = 216 \[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {a^3 (30 A+26 B+23 C) \text {arctanh}(\sin (c+d x))}{16 d}+\frac {a^3 (30 A+26 B+23 C) \tan (c+d x)}{10 d}+\frac {3 a^3 (30 A+26 B+23 C) \sec (c+d x) \tan (c+d x)}{80 d}+\frac {(30 A-6 B+7 C) (a+a \sec (c+d x))^3 \tan (c+d x)}{120 d}+\frac {C \sec ^2(c+d x) (a+a \sec (c+d x))^3 \tan (c+d x)}{6 d}+\frac {(2 B+C) (a+a \sec (c+d x))^4 \tan (c+d x)}{10 a d}+\frac {a^3 (30 A+26 B+23 C) \tan ^3(c+d x)}{120 d} \] Output:
1/16*a^3*(30*A+26*B+23*C)*arctanh(sin(d*x+c))/d+1/10*a^3*(30*A+26*B+23*C)* tan(d*x+c)/d+3/80*a^3*(30*A+26*B+23*C)*sec(d*x+c)*tan(d*x+c)/d+1/120*(30*A -6*B+7*C)*(a+a*sec(d*x+c))^3*tan(d*x+c)/d+1/6*C*sec(d*x+c)^2*(a+a*sec(d*x+ c))^3*tan(d*x+c)/d+1/10*(2*B+C)*(a+a*sec(d*x+c))^4*tan(d*x+c)/a/d+1/120*a^ 3*(30*A+26*B+23*C)*tan(d*x+c)^3/d
Time = 5.93 (sec) , antiderivative size = 134, normalized size of antiderivative = 0.62 \[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {a^3 \left (15 (30 A+26 B+23 C) \text {arctanh}(\sin (c+d x))+\left (16 (45 A+38 B+34 C)+15 (30 A+26 B+23 C) \sec (c+d x)+16 (15 A+19 B+17 C) \sec ^2(c+d x)+10 (6 A+18 B+23 C) \sec ^3(c+d x)+48 (B+3 C) \sec ^4(c+d x)+40 C \sec ^5(c+d x)\right ) \tan (c+d x)\right )}{240 d} \] Input:
Integrate[Sec[c + d*x]^2*(a + a*Sec[c + d*x])^3*(A + B*Sec[c + d*x] + C*Se c[c + d*x]^2),x]
Output:
(a^3*(15*(30*A + 26*B + 23*C)*ArcTanh[Sin[c + d*x]] + (16*(45*A + 38*B + 3 4*C) + 15*(30*A + 26*B + 23*C)*Sec[c + d*x] + 16*(15*A + 19*B + 17*C)*Sec[ c + d*x]^2 + 10*(6*A + 18*B + 23*C)*Sec[c + d*x]^3 + 48*(B + 3*C)*Sec[c + d*x]^4 + 40*C*Sec[c + d*x]^5)*Tan[c + d*x]))/(240*d)
Time = 0.97 (sec) , antiderivative size = 208, normalized size of antiderivative = 0.96, number of steps used = 9, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.220, Rules used = {3042, 4576, 3042, 4498, 3042, 4489, 3042, 4278, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \sec ^2(c+d x) (a \sec (c+d x)+a)^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \csc \left (c+d x+\frac {\pi }{2}\right )^2 \left (a \csc \left (c+d x+\frac {\pi }{2}\right )+a\right )^3 \left (A+B \csc \left (c+d x+\frac {\pi }{2}\right )+C \csc \left (c+d x+\frac {\pi }{2}\right )^2\right )dx\) |
| \(\Big \downarrow \) 4576 |
| \(\displaystyle \frac {\int \sec ^2(c+d x) (\sec (c+d x) a+a)^3 (2 a (3 A+C)+3 a (2 B+C) \sec (c+d x))dx}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \csc \left (c+d x+\frac {\pi }{2}\right )^2 \left (\csc \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^3 \left (2 a (3 A+C)+3 a (2 B+C) \csc \left (c+d x+\frac {\pi }{2}\right )\right )dx}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
| \(\Big \downarrow \) 4498 |
| \(\displaystyle \frac {\frac {\int \sec (c+d x) (\sec (c+d x) a+a)^3 \left (12 (2 B+C) a^2+(30 A-6 B+7 C) \sec (c+d x) a^2\right )dx}{5 a}+\frac {3 (2 B+C) \tan (c+d x) (a \sec (c+d x)+a)^4}{5 d}}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\int \csc \left (c+d x+\frac {\pi }{2}\right ) \left (\csc \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^3 \left (12 (2 B+C) a^2+(30 A-6 B+7 C) \csc \left (c+d x+\frac {\pi }{2}\right ) a^2\right )dx}{5 a}+\frac {3 (2 B+C) \tan (c+d x) (a \sec (c+d x)+a)^4}{5 d}}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
| \(\Big \downarrow \) 4489 |
| \(\displaystyle \frac {\frac {\frac {3}{4} a^2 (30 A+26 B+23 C) \int \sec (c+d x) (\sec (c+d x) a+a)^3dx+\frac {a^2 (30 A-6 B+7 C) \tan (c+d x) (a \sec (c+d x)+a)^3}{4 d}}{5 a}+\frac {3 (2 B+C) \tan (c+d x) (a \sec (c+d x)+a)^4}{5 d}}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {\frac {3}{4} a^2 (30 A+26 B+23 C) \int \csc \left (c+d x+\frac {\pi }{2}\right ) \left (\csc \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^3dx+\frac {a^2 (30 A-6 B+7 C) \tan (c+d x) (a \sec (c+d x)+a)^3}{4 d}}{5 a}+\frac {3 (2 B+C) \tan (c+d x) (a \sec (c+d x)+a)^4}{5 d}}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
| \(\Big \downarrow \) 4278 |
| \(\displaystyle \frac {\frac {\frac {3}{4} a^2 (30 A+26 B+23 C) \int \left (a^3 \sec ^4(c+d x)+3 a^3 \sec ^3(c+d x)+3 a^3 \sec ^2(c+d x)+a^3 \sec (c+d x)\right )dx+\frac {a^2 (30 A-6 B+7 C) \tan (c+d x) (a \sec (c+d x)+a)^3}{4 d}}{5 a}+\frac {3 (2 B+C) \tan (c+d x) (a \sec (c+d x)+a)^4}{5 d}}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle \frac {\frac {\frac {a^2 (30 A-6 B+7 C) \tan (c+d x) (a \sec (c+d x)+a)^3}{4 d}+\frac {3}{4} a^2 (30 A+26 B+23 C) \left (\frac {5 a^3 \text {arctanh}(\sin (c+d x))}{2 d}+\frac {a^3 \tan ^3(c+d x)}{3 d}+\frac {4 a^3 \tan (c+d x)}{d}+\frac {3 a^3 \tan (c+d x) \sec (c+d x)}{2 d}\right )}{5 a}+\frac {3 (2 B+C) \tan (c+d x) (a \sec (c+d x)+a)^4}{5 d}}{6 a}+\frac {C \tan (c+d x) \sec ^2(c+d x) (a \sec (c+d x)+a)^3}{6 d}\) |
Input:
Int[Sec[c + d*x]^2*(a + a*Sec[c + d*x])^3*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2),x]
Output:
(C*Sec[c + d*x]^2*(a + a*Sec[c + d*x])^3*Tan[c + d*x])/(6*d) + ((3*(2*B + C)*(a + a*Sec[c + d*x])^4*Tan[c + d*x])/(5*d) + ((a^2*(30*A - 6*B + 7*C)*( a + a*Sec[c + d*x])^3*Tan[c + d*x])/(4*d) + (3*a^2*(30*A + 26*B + 23*C)*(( 5*a^3*ArcTanh[Sin[c + d*x]])/(2*d) + (4*a^3*Tan[c + d*x])/d + (3*a^3*Sec[c + d*x]*Tan[c + d*x])/(2*d) + (a^3*Tan[c + d*x]^3)/(3*d)))/4)/(5*a))/(6*a)
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_), x_Symbol] :> Int[ExpandTrig[(a + b*csc[e + f*x])^m*(d*csc[e + f *x])^n, x], x] /; FreeQ[{a, b, d, e, f, m, n}, x] && EqQ[a^2 - b^2, 0] && I GtQ[m, 0] && RationalQ[n]
Int[csc[(e_.) + (f_.)*(x_)]*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_)*(cs c[(e_.) + (f_.)*(x_)]*(B_.) + (A_)), x_Symbol] :> Simp[(-B)*Cot[e + f*x]*(( a + b*Csc[e + f*x])^m/(f*(m + 1))), x] + Simp[(a*B*m + A*b*(m + 1))/(b*(m + 1)) Int[Csc[e + f*x]*(a + b*Csc[e + f*x])^m, x], x] /; FreeQ[{a, b, A, B , e, f, m}, x] && NeQ[A*b - a*B, 0] && EqQ[a^2 - b^2, 0] && NeQ[a*B*m + A*b *(m + 1), 0] && !LtQ[m, -2^(-1)]
Int[csc[(e_.) + (f_.)*(x_)]^2*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_)*( csc[(e_.) + (f_.)*(x_)]*(B_.) + (A_)), x_Symbol] :> Simp[(-B)*Cot[e + f*x]* ((a + b*Csc[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m + 2)) Int [Csc[e + f*x]*(a + b*Csc[e + f*x])^m*Simp[b*B*(m + 1) + (A*b*(m + 2) - a*B) *Csc[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, m}, x] && NeQ[A*b - a *B, 0] && !LtQ[m, -1]
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. ))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a _))^(m_), x_Symbol] :> Simp[(-C)*Cot[e + f*x]*(a + b*Csc[e + f*x])^m*((d*Cs c[e + f*x])^n/(f*(m + n + 1))), x] + Simp[1/(b*(m + n + 1)) Int[(a + b*Cs c[e + f*x])^m*(d*Csc[e + f*x])^n*Simp[A*b*(m + n + 1) + b*C*n + (a*C*m + b* B*(m + n + 1))*Csc[e + f*x], x], x], x] /; FreeQ[{a, b, d, e, f, A, B, C, m , n}, x] && EqQ[a^2 - b^2, 0] && !LtQ[m, -2^(-1)] && !LtQ[n, -2^(-1)] && NeQ[m + n + 1, 0]
Time = 5.12 (sec) , antiderivative size = 251, normalized size of antiderivative = 1.16
| method | result | size |
| norman | \(\frac {-\frac {33 a^{3} \left (30 A +26 B +23 C \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{20 d}+\frac {17 a^{3} \left (30 A +26 B +23 C \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{24 d}-\frac {a^{3} \left (30 A +26 B +23 C \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11}}{8 d}+\frac {a^{3} \left (98 A +102 B +105 C \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{8 d}-\frac {a^{3} \left (1026 A +838 B +633 C \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{24 d}+\frac {a^{3} \left (1250 A +998 B +969 C \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{20 d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{6}}-\frac {a^{3} \left (30 A +26 B +23 C \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{16 d}+\frac {a^{3} \left (30 A +26 B +23 C \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{16 d}\) | \(251\) |
| parallelrisch | \(-\frac {15 \left (\left (\cos \left (6 d x +6 c \right )+6 \cos \left (4 d x +4 c \right )+15 \cos \left (2 d x +2 c \right )+10\right ) \left (A +\frac {13 B}{15}+\frac {23 C}{30}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-\left (\cos \left (6 d x +6 c \right )+6 \cos \left (4 d x +4 c \right )+15 \cos \left (2 d x +2 c \right )+10\right ) \left (A +\frac {13 B}{15}+\frac {23 C}{30}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (-\frac {208 B}{15}-\frac {184 A}{15}-16 C \right ) \sin \left (2 d x +2 c \right )+\left (-\frac {391 C}{45}-\frac {106 A}{15}-\frac {42 B}{5}\right ) \sin \left (3 d x +3 c \right )+\left (-\frac {544 C}{75}-\frac {128 A}{15}-\frac {608 B}{75}\right ) \sin \left (4 d x +4 c \right )+\left (-\frac {26 B}{15}-\frac {23 C}{15}-2 A \right ) \sin \left (5 d x +5 c \right )+\left (-\frac {8 A}{5}-\frac {304 B}{225}-\frac {272 C}{225}\right ) \sin \left (6 d x +6 c \right )-\frac {76 \left (\frac {25 B}{19}+A +\frac {75 C}{38}\right ) \sin \left (d x +c \right )}{15}\right ) a^{3}}{8 d \left (\cos \left (6 d x +6 c \right )+6 \cos \left (4 d x +4 c \right )+15 \cos \left (2 d x +2 c \right )+10\right )}\) | \(270\) |
| parts | \(\frac {\left (3 a^{3} A +B \,a^{3}\right ) \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}-\frac {\left (B \,a^{3}+3 a^{3} C \right ) \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )}{d}+\frac {\left (a^{3} A +3 B \,a^{3}+3 a^{3} C \right ) \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}-\frac {\left (3 a^{3} A +3 B \,a^{3}+a^{3} C \right ) \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}+\frac {a^{3} A \tan \left (d x +c \right )}{d}+\frac {a^{3} C \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}\) | \(277\) |
| derivativedivides | \(\frac {a^{3} A \tan \left (d x +c \right )+B \,a^{3} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-a^{3} C \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+3 a^{3} A \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-3 B \,a^{3} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+3 a^{3} C \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-3 a^{3} A \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+3 B \,a^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-3 a^{3} C \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+a^{3} A \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-B \,a^{3} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+a^{3} C \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}\) | \(438\) |
| default | \(\frac {a^{3} A \tan \left (d x +c \right )+B \,a^{3} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-a^{3} C \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+3 a^{3} A \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-3 B \,a^{3} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+3 a^{3} C \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-3 a^{3} A \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+3 B \,a^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-3 a^{3} C \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+a^{3} A \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-B \,a^{3} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+a^{3} C \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}\) | \(438\) |
| risch | \(-\frac {i a^{3} \left (-2640 A \,{\mathrm e}^{8 i \left (d x +c \right )}-5440 C \,{\mathrm e}^{6 i \left (d x +c \right )}-544 C -720 A -608 B +450 A \,{\mathrm e}^{11 i \left (d x +c \right )}+345 C \,{\mathrm e}^{11 i \left (d x +c \right )}-240 A \,{\mathrm e}^{10 i \left (d x +c \right )}-1440 B \,{\mathrm e}^{8 i \left (d x +c \right )}+390 B \,{\mathrm e}^{11 i \left (d x +c \right )}-6080 B \,{\mathrm e}^{6 i \left (d x +c \right )}-7200 A \,{\mathrm e}^{6 i \left (d x +c \right )}-8160 A \,{\mathrm e}^{4 i \left (d x +c \right )}-7680 C \,{\mathrm e}^{4 i \left (d x +c \right )}-4080 A \,{\mathrm e}^{2 i \left (d x +c \right )}-3264 C \,{\mathrm e}^{2 i \left (d x +c \right )}+1140 A \,{\mathrm e}^{7 i \left (d x +c \right )}-1140 A \,{\mathrm e}^{5 i \left (d x +c \right )}-1590 A \,{\mathrm e}^{3 i \left (d x +c \right )}-450 A \,{\mathrm e}^{i \left (d x +c \right )}+2250 C \,{\mathrm e}^{7 i \left (d x +c \right )}-2250 C \,{\mathrm e}^{5 i \left (d x +c \right )}-1955 C \,{\mathrm e}^{3 i \left (d x +c \right )}-345 C \,{\mathrm e}^{i \left (d x +c \right )}-390 B \,{\mathrm e}^{i \left (d x +c \right )}-480 C \,{\mathrm e}^{8 i \left (d x +c \right )}-3648 B \,{\mathrm e}^{2 i \left (d x +c \right )}-1500 B \,{\mathrm e}^{5 i \left (d x +c \right )}-7680 B \,{\mathrm e}^{4 i \left (d x +c \right )}-1890 B \,{\mathrm e}^{3 i \left (d x +c \right )}+1590 A \,{\mathrm e}^{9 i \left (d x +c \right )}+1890 B \,{\mathrm e}^{9 i \left (d x +c \right )}+1955 C \,{\mathrm e}^{9 i \left (d x +c \right )}+1500 B \,{\mathrm e}^{7 i \left (d x +c \right )}\right )}{120 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{6}}-\frac {15 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) A}{8 d}-\frac {13 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B}{8 d}-\frac {23 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) C}{16 d}+\frac {15 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) A}{8 d}+\frac {13 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B}{8 d}+\frac {23 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) C}{16 d}\) | \(538\) |
Input:
int(sec(d*x+c)^2*(a+a*sec(d*x+c))^3*(A+B*sec(d*x+c)+C*sec(d*x+c)^2),x,meth od=_RETURNVERBOSE)
Output:
(-33/20*a^3*(30*A+26*B+23*C)/d*tan(1/2*d*x+1/2*c)^7+17/24*a^3*(30*A+26*B+2 3*C)/d*tan(1/2*d*x+1/2*c)^9-1/8*a^3*(30*A+26*B+23*C)/d*tan(1/2*d*x+1/2*c)^ 11+1/8*a^3*(98*A+102*B+105*C)/d*tan(1/2*d*x+1/2*c)-1/24*a^3*(1026*A+838*B+ 633*C)/d*tan(1/2*d*x+1/2*c)^3+1/20*a^3*(1250*A+998*B+969*C)/d*tan(1/2*d*x+ 1/2*c)^5)/(tan(1/2*d*x+1/2*c)^2-1)^6-1/16*a^3*(30*A+26*B+23*C)/d*ln(tan(1/ 2*d*x+1/2*c)-1)+1/16*a^3*(30*A+26*B+23*C)/d*ln(tan(1/2*d*x+1/2*c)+1)
Time = 0.09 (sec) , antiderivative size = 203, normalized size of antiderivative = 0.94 \[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {15 \, {\left (30 \, A + 26 \, B + 23 \, C\right )} a^{3} \cos \left (d x + c\right )^{6} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \, {\left (30 \, A + 26 \, B + 23 \, C\right )} a^{3} \cos \left (d x + c\right )^{6} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (16 \, {\left (45 \, A + 38 \, B + 34 \, C\right )} a^{3} \cos \left (d x + c\right )^{5} + 15 \, {\left (30 \, A + 26 \, B + 23 \, C\right )} a^{3} \cos \left (d x + c\right )^{4} + 16 \, {\left (15 \, A + 19 \, B + 17 \, C\right )} a^{3} \cos \left (d x + c\right )^{3} + 10 \, {\left (6 \, A + 18 \, B + 23 \, C\right )} a^{3} \cos \left (d x + c\right )^{2} + 48 \, {\left (B + 3 \, C\right )} a^{3} \cos \left (d x + c\right ) + 40 \, C a^{3}\right )} \sin \left (d x + c\right )}{480 \, d \cos \left (d x + c\right )^{6}} \] Input:
integrate(sec(d*x+c)^2*(a+a*sec(d*x+c))^3*(A+B*sec(d*x+c)+C*sec(d*x+c)^2), x, algorithm="fricas")
Output:
1/480*(15*(30*A + 26*B + 23*C)*a^3*cos(d*x + c)^6*log(sin(d*x + c) + 1) - 15*(30*A + 26*B + 23*C)*a^3*cos(d*x + c)^6*log(-sin(d*x + c) + 1) + 2*(16* (45*A + 38*B + 34*C)*a^3*cos(d*x + c)^5 + 15*(30*A + 26*B + 23*C)*a^3*cos( d*x + c)^4 + 16*(15*A + 19*B + 17*C)*a^3*cos(d*x + c)^3 + 10*(6*A + 18*B + 23*C)*a^3*cos(d*x + c)^2 + 48*(B + 3*C)*a^3*cos(d*x + c) + 40*C*a^3)*sin( d*x + c))/(d*cos(d*x + c)^6)
\[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=a^{3} \left (\int A \sec ^{2}{\left (c + d x \right )}\, dx + \int 3 A \sec ^{3}{\left (c + d x \right )}\, dx + \int 3 A \sec ^{4}{\left (c + d x \right )}\, dx + \int A \sec ^{5}{\left (c + d x \right )}\, dx + \int B \sec ^{3}{\left (c + d x \right )}\, dx + \int 3 B \sec ^{4}{\left (c + d x \right )}\, dx + \int 3 B \sec ^{5}{\left (c + d x \right )}\, dx + \int B \sec ^{6}{\left (c + d x \right )}\, dx + \int C \sec ^{4}{\left (c + d x \right )}\, dx + \int 3 C \sec ^{5}{\left (c + d x \right )}\, dx + \int 3 C \sec ^{6}{\left (c + d x \right )}\, dx + \int C \sec ^{7}{\left (c + d x \right )}\, dx\right ) \] Input:
integrate(sec(d*x+c)**2*(a+a*sec(d*x+c))**3*(A+B*sec(d*x+c)+C*sec(d*x+c)** 2),x)
Output:
a**3*(Integral(A*sec(c + d*x)**2, x) + Integral(3*A*sec(c + d*x)**3, x) + Integral(3*A*sec(c + d*x)**4, x) + Integral(A*sec(c + d*x)**5, x) + Integr al(B*sec(c + d*x)**3, x) + Integral(3*B*sec(c + d*x)**4, x) + Integral(3*B *sec(c + d*x)**5, x) + Integral(B*sec(c + d*x)**6, x) + Integral(C*sec(c + d*x)**4, x) + Integral(3*C*sec(c + d*x)**5, x) + Integral(3*C*sec(c + d*x )**6, x) + Integral(C*sec(c + d*x)**7, x))
Leaf count of result is larger than twice the leaf count of optimal. 559 vs. \(2 (202) = 404\).
Time = 0.05 (sec) , antiderivative size = 559, normalized size of antiderivative = 2.59 \[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx =\text {Too large to display} \] Input:
integrate(sec(d*x+c)^2*(a+a*sec(d*x+c))^3*(A+B*sec(d*x+c)+C*sec(d*x+c)^2), x, algorithm="maxima")
Output:
1/480*(480*(tan(d*x + c)^3 + 3*tan(d*x + c))*A*a^3 + 32*(3*tan(d*x + c)^5 + 10*tan(d*x + c)^3 + 15*tan(d*x + c))*B*a^3 + 480*(tan(d*x + c)^3 + 3*tan (d*x + c))*B*a^3 + 96*(3*tan(d*x + c)^5 + 10*tan(d*x + c)^3 + 15*tan(d*x + c))*C*a^3 + 160*(tan(d*x + c)^3 + 3*tan(d*x + c))*C*a^3 - 5*C*a^3*(2*(15* sin(d*x + c)^5 - 40*sin(d*x + c)^3 + 33*sin(d*x + c))/(sin(d*x + c)^6 - 3* sin(d*x + c)^4 + 3*sin(d*x + c)^2 - 1) - 15*log(sin(d*x + c) + 1) + 15*log (sin(d*x + c) - 1)) - 30*A*a^3*(2*(3*sin(d*x + c)^3 - 5*sin(d*x + c))/(sin (d*x + c)^4 - 2*sin(d*x + c)^2 + 1) - 3*log(sin(d*x + c) + 1) + 3*log(sin( d*x + c) - 1)) - 90*B*a^3*(2*(3*sin(d*x + c)^3 - 5*sin(d*x + c))/(sin(d*x + c)^4 - 2*sin(d*x + c)^2 + 1) - 3*log(sin(d*x + c) + 1) + 3*log(sin(d*x + c) - 1)) - 90*C*a^3*(2*(3*sin(d*x + c)^3 - 5*sin(d*x + c))/(sin(d*x + c)^ 4 - 2*sin(d*x + c)^2 + 1) - 3*log(sin(d*x + c) + 1) + 3*log(sin(d*x + c) - 1)) - 360*A*a^3*(2*sin(d*x + c)/(sin(d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) - 120*B*a^3*(2*sin(d*x + c)/(sin(d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) + 480*A*a^3*tan(d*x + c))/d
Time = 0.29 (sec) , antiderivative size = 392, normalized size of antiderivative = 1.81 \[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {15 \, {\left (30 \, A a^{3} + 26 \, B a^{3} + 23 \, C a^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 15 \, {\left (30 \, A a^{3} + 26 \, B a^{3} + 23 \, C a^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (450 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 390 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 345 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 2550 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 2210 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 1955 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 5940 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 5148 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 4554 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 7500 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 5988 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 5814 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 5130 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 4190 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 3165 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 1470 \, A a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1530 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1575 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{6}}}{240 \, d} \] Input:
integrate(sec(d*x+c)^2*(a+a*sec(d*x+c))^3*(A+B*sec(d*x+c)+C*sec(d*x+c)^2), x, algorithm="giac")
Output:
1/240*(15*(30*A*a^3 + 26*B*a^3 + 23*C*a^3)*log(abs(tan(1/2*d*x + 1/2*c) + 1)) - 15*(30*A*a^3 + 26*B*a^3 + 23*C*a^3)*log(abs(tan(1/2*d*x + 1/2*c) - 1 )) - 2*(450*A*a^3*tan(1/2*d*x + 1/2*c)^11 + 390*B*a^3*tan(1/2*d*x + 1/2*c) ^11 + 345*C*a^3*tan(1/2*d*x + 1/2*c)^11 - 2550*A*a^3*tan(1/2*d*x + 1/2*c)^ 9 - 2210*B*a^3*tan(1/2*d*x + 1/2*c)^9 - 1955*C*a^3*tan(1/2*d*x + 1/2*c)^9 + 5940*A*a^3*tan(1/2*d*x + 1/2*c)^7 + 5148*B*a^3*tan(1/2*d*x + 1/2*c)^7 + 4554*C*a^3*tan(1/2*d*x + 1/2*c)^7 - 7500*A*a^3*tan(1/2*d*x + 1/2*c)^5 - 59 88*B*a^3*tan(1/2*d*x + 1/2*c)^5 - 5814*C*a^3*tan(1/2*d*x + 1/2*c)^5 + 5130 *A*a^3*tan(1/2*d*x + 1/2*c)^3 + 4190*B*a^3*tan(1/2*d*x + 1/2*c)^3 + 3165*C *a^3*tan(1/2*d*x + 1/2*c)^3 - 1470*A*a^3*tan(1/2*d*x + 1/2*c) - 1530*B*a^3 *tan(1/2*d*x + 1/2*c) - 1575*C*a^3*tan(1/2*d*x + 1/2*c))/(tan(1/2*d*x + 1/ 2*c)^2 - 1)^6)/d
Time = 16.65 (sec) , antiderivative size = 337, normalized size of antiderivative = 1.56 \[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx=\frac {a^3\,\mathrm {atanh}\left (\frac {a^3\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (30\,A+26\,B+23\,C\right )}{4\,\left (\frac {15\,A\,a^3}{2}+\frac {13\,B\,a^3}{2}+\frac {23\,C\,a^3}{4}\right )}\right )\,\left (30\,A+26\,B+23\,C\right )}{8\,d}-\frac {\left (\frac {15\,A\,a^3}{4}+\frac {13\,B\,a^3}{4}+\frac {23\,C\,a^3}{8}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+\left (-\frac {85\,A\,a^3}{4}-\frac {221\,B\,a^3}{12}-\frac {391\,C\,a^3}{24}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+\left (\frac {99\,A\,a^3}{2}+\frac {429\,B\,a^3}{10}+\frac {759\,C\,a^3}{20}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (-\frac {125\,A\,a^3}{2}-\frac {499\,B\,a^3}{10}-\frac {969\,C\,a^3}{20}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (\frac {171\,A\,a^3}{4}+\frac {419\,B\,a^3}{12}+\frac {211\,C\,a^3}{8}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (-\frac {49\,A\,a^3}{4}-\frac {51\,B\,a^3}{4}-\frac {105\,C\,a^3}{8}\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-20\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \] Input:
int(((a + a/cos(c + d*x))^3*(A + B/cos(c + d*x) + C/cos(c + d*x)^2))/cos(c + d*x)^2,x)
Output:
(a^3*atanh((a^3*tan(c/2 + (d*x)/2)*(30*A + 26*B + 23*C))/(4*((15*A*a^3)/2 + (13*B*a^3)/2 + (23*C*a^3)/4)))*(30*A + 26*B + 23*C))/(8*d) - (tan(c/2 + (d*x)/2)^11*((15*A*a^3)/4 + (13*B*a^3)/4 + (23*C*a^3)/8) - tan(c/2 + (d*x) /2)^9*((85*A*a^3)/4 + (221*B*a^3)/12 + (391*C*a^3)/24) + tan(c/2 + (d*x)/2 )^3*((171*A*a^3)/4 + (419*B*a^3)/12 + (211*C*a^3)/8) + tan(c/2 + (d*x)/2)^ 7*((99*A*a^3)/2 + (429*B*a^3)/10 + (759*C*a^3)/20) - tan(c/2 + (d*x)/2)^5* ((125*A*a^3)/2 + (499*B*a^3)/10 + (969*C*a^3)/20) - tan(c/2 + (d*x)/2)*((4 9*A*a^3)/4 + (51*B*a^3)/4 + (105*C*a^3)/8))/(d*(15*tan(c/2 + (d*x)/2)^4 - 6*tan(c/2 + (d*x)/2)^2 - 20*tan(c/2 + (d*x)/2)^6 + 15*tan(c/2 + (d*x)/2)^8 - 6*tan(c/2 + (d*x)/2)^10 + tan(c/2 + (d*x)/2)^12 + 1))
Time = 0.16 (sec) , antiderivative size = 785, normalized size of antiderivative = 3.63 \[ \int \sec ^2(c+d x) (a+a \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx =\text {Too large to display} \] Input:
int(sec(d*x+c)^2*(a+a*sec(d*x+c))^3*(A+B*sec(d*x+c)+C*sec(d*x+c)^2),x)
Output:
(a**3*( - 720*cos(c + d*x)*sin(c + d*x)**5*a - 608*cos(c + d*x)*sin(c + d* x)**5*b - 544*cos(c + d*x)*sin(c + d*x)**5*c + 1680*cos(c + d*x)*sin(c + d *x)**3*a + 1520*cos(c + d*x)*sin(c + d*x)**3*b + 1360*cos(c + d*x)*sin(c + d*x)**3*c - 960*cos(c + d*x)*sin(c + d*x)*a - 960*cos(c + d*x)*sin(c + d* x)*b - 960*cos(c + d*x)*sin(c + d*x)*c - 450*log(tan((c + d*x)/2) - 1)*sin (c + d*x)**6*a - 390*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**6*b - 345*log (tan((c + d*x)/2) - 1)*sin(c + d*x)**6*c + 1350*log(tan((c + d*x)/2) - 1)* sin(c + d*x)**4*a + 1170*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**4*b + 103 5*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**4*c - 1350*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**2*a - 1170*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**2*b - 1035*log(tan((c + d*x)/2) - 1)*sin(c + d*x)**2*c + 450*log(tan((c + d*x) /2) - 1)*a + 390*log(tan((c + d*x)/2) - 1)*b + 345*log(tan((c + d*x)/2) - 1)*c + 450*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**6*a + 390*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**6*b + 345*log(tan((c + d*x)/2) + 1)*sin(c + d*x )**6*c - 1350*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**4*a - 1170*log(tan(( c + d*x)/2) + 1)*sin(c + d*x)**4*b - 1035*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**4*c + 1350*log(tan((c + d*x)/2) + 1)*sin(c + d*x)**2*a + 1170*log( tan((c + d*x)/2) + 1)*sin(c + d*x)**2*b + 1035*log(tan((c + d*x)/2) + 1)*s in(c + d*x)**2*c - 450*log(tan((c + d*x)/2) + 1)*a - 390*log(tan((c + d*x) /2) + 1)*b - 345*log(tan((c + d*x)/2) + 1)*c - 450*sin(c + d*x)**5*a - ...