Integrand size = 16, antiderivative size = 81 \[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=-\frac {\sqrt {a} \arctan \left (\frac {\sqrt {a} \cot (c+d x)}{\sqrt {a+b+b \cot ^2(c+d x)}}\right )}{d}-\frac {\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \cot (c+d x)}{\sqrt {a+b+b \cot ^2(c+d x)}}\right )}{d} \] Output:
-a^(1/2)*arctan(a^(1/2)*cot(d*x+c)/(a+b+b*cot(d*x+c)^2)^(1/2))/d-b^(1/2)*a rctanh(b^(1/2)*cot(d*x+c)/(a+b+b*cot(d*x+c)^2)^(1/2))/d
Time = 0.20 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.84 \[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=\frac {\sqrt {2} \sqrt {a+b \csc ^2(c+d x)} \left (-\sqrt {-b} \text {arctanh}\left (\frac {\sqrt {2} \sqrt {-b} \cos (c+d x)}{\sqrt {-a-2 b+a \cos (2 (c+d x))}}\right )+\sqrt {a} \log \left (\sqrt {2} \sqrt {a} \cos (c+d x)+\sqrt {-a-2 b+a \cos (2 (c+d x))}\right )\right ) \sin (c+d x)}{d \sqrt {-a-2 b+a \cos (2 (c+d x))}} \] Input:
Integrate[Sqrt[a + b*Csc[c + d*x]^2],x]
Output:
(Sqrt[2]*Sqrt[a + b*Csc[c + d*x]^2]*(-(Sqrt[-b]*ArcTanh[(Sqrt[2]*Sqrt[-b]* Cos[c + d*x])/Sqrt[-a - 2*b + a*Cos[2*(c + d*x)]]]) + Sqrt[a]*Log[Sqrt[2]* Sqrt[a]*Cos[c + d*x] + Sqrt[-a - 2*b + a*Cos[2*(c + d*x)]]])*Sin[c + d*x]) /(d*Sqrt[-a - 2*b + a*Cos[2*(c + d*x)]])
Time = 0.24 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.96, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.438, Rules used = {3042, 4616, 301, 224, 219, 291, 216}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sqrt {a+b \csc ^2(c+d x)} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \sqrt {a+b \sec \left (c+d x+\frac {\pi }{2}\right )^2}dx\) |
\(\Big \downarrow \) 4616 |
\(\displaystyle -\frac {\int \frac {\sqrt {b \cot ^2(c+d x)+a+b}}{\cot ^2(c+d x)+1}d\cot (c+d x)}{d}\) |
\(\Big \downarrow \) 301 |
\(\displaystyle -\frac {b \int \frac {1}{\sqrt {b \cot ^2(c+d x)+a+b}}d\cot (c+d x)+a \int \frac {1}{\left (\cot ^2(c+d x)+1\right ) \sqrt {b \cot ^2(c+d x)+a+b}}d\cot (c+d x)}{d}\) |
\(\Big \downarrow \) 224 |
\(\displaystyle -\frac {a \int \frac {1}{\left (\cot ^2(c+d x)+1\right ) \sqrt {b \cot ^2(c+d x)+a+b}}d\cot (c+d x)+b \int \frac {1}{1-\frac {b \cot ^2(c+d x)}{b \cot ^2(c+d x)+a+b}}d\frac {\cot (c+d x)}{\sqrt {b \cot ^2(c+d x)+a+b}}}{d}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle -\frac {a \int \frac {1}{\left (\cot ^2(c+d x)+1\right ) \sqrt {b \cot ^2(c+d x)+a+b}}d\cot (c+d x)+\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \cot (c+d x)}{\sqrt {a+b \cot ^2(c+d x)+b}}\right )}{d}\) |
\(\Big \downarrow \) 291 |
\(\displaystyle -\frac {a \int \frac {1}{\frac {a \cot ^2(c+d x)}{b \cot ^2(c+d x)+a+b}+1}d\frac {\cot (c+d x)}{\sqrt {b \cot ^2(c+d x)+a+b}}+\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \cot (c+d x)}{\sqrt {a+b \cot ^2(c+d x)+b}}\right )}{d}\) |
\(\Big \downarrow \) 216 |
\(\displaystyle -\frac {\sqrt {a} \arctan \left (\frac {\sqrt {a} \cot (c+d x)}{\sqrt {a+b \cot ^2(c+d x)+b}}\right )+\sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \cot (c+d x)}{\sqrt {a+b \cot ^2(c+d x)+b}}\right )}{d}\) |
Input:
Int[Sqrt[a + b*Csc[c + d*x]^2],x]
Output:
-((Sqrt[a]*ArcTan[(Sqrt[a]*Cot[c + d*x])/Sqrt[a + b + b*Cot[c + d*x]^2]] + Sqrt[b]*ArcTanh[(Sqrt[b]*Cot[c + d*x])/Sqrt[a + b + b*Cot[c + d*x]^2]])/d )
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a , 0] || GtQ[b, 0])
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a, b}, x] && !GtQ[a, 0]
Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*((c_) + (d_.)*(x_)^2)), x_Symbol] :> Subst [Int[1/(c - (b*c - a*d)*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]
Int[((a_) + (b_.)*(x_)^2)^(p_.)/((c_) + (d_.)*(x_)^2), x_Symbol] :> Simp[b/ d Int[(a + b*x^2)^(p - 1), x], x] - Simp[(b*c - a*d)/d Int[(a + b*x^2)^ (p - 1)/(c + d*x^2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[p, 0] && (EqQ[p, 1/2] || EqQ[Denominator[p], 4] || (EqQ[p, 2/3] && E qQ[b*c + 3*a*d, 0]))
Int[((a_) + (b_.)*sec[(e_.) + (f_.)*(x_)]^2)^(p_), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x], x]}, Simp[ff/f Subst[Int[(a + b + b*ff^2*x^2)^p /(1 + ff^2*x^2), x], x, Tan[e + f*x]/ff], x]] /; FreeQ[{a, b, e, f, p}, x] && NeQ[a + b, 0] && NeQ[p, -1]
Leaf count of result is larger than twice the leaf count of optimal. \(357\) vs. \(2(69)=138\).
Time = 0.36 (sec) , antiderivative size = 358, normalized size of antiderivative = 4.42
method | result | size |
default | \(-\frac {\sqrt {4}\, \sqrt {a +b \csc \left (d x +c \right )^{2}}\, \left (b \ln \left (\frac {4 a \left (1-\cos \left (d x +c \right )\right )^{2}+2 b \left (1-\cos \left (d x +c \right )\right )^{2}+4 \sqrt {b}\, \sqrt {\frac {a \sin \left (d x +c \right )^{2}+b}{\left (1+\cos \left (d x +c \right )\right )^{2}}}\, \sin \left (d x +c \right )^{2}+2 b \sin \left (d x +c \right )^{2}}{\left (1-\cos \left (d x +c \right )\right )^{2}}\right ) \sqrt {-a}+2 a \ln \left (4 \sqrt {-a}\, \sqrt {\frac {a \sin \left (d x +c \right )^{2}+b}{\left (1+\cos \left (d x +c \right )\right )^{2}}}\, \cos \left (d x +c \right )+4 \sqrt {-a}\, \sqrt {\frac {a \sin \left (d x +c \right )^{2}+b}{\left (1+\cos \left (d x +c \right )\right )^{2}}}-4 \cos \left (d x +c \right ) a \right ) \sqrt {b}-\ln \left (\frac {2 \sqrt {\frac {a \sin \left (d x +c \right )^{2}+b}{\left (1+\cos \left (d x +c \right )\right )^{2}}}\, \sqrt {b}\, \cos \left (d x +c \right )+2 \sqrt {b}\, \sqrt {\frac {a \sin \left (d x +c \right )^{2}+b}{\left (1+\cos \left (d x +c \right )\right )^{2}}}+2 \cos \left (d x +c \right ) a +2 a +2 b}{\sqrt {b}\, \left (1+\cos \left (d x +c \right )\right )}\right ) \sqrt {-a}\, b \right ) \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{4 d \sqrt {b}\, \sqrt {-a}\, \sqrt {\frac {a \sin \left (d x +c \right )^{2}+b}{\left (1+\cos \left (d x +c \right )\right )^{2}}}}\) | \(358\) |
Input:
int((a+b*csc(d*x+c)^2)^(1/2),x,method=_RETURNVERBOSE)
Output:
-1/4/d*4^(1/2)/b^(1/2)/(-a)^(1/2)*(a+b*csc(d*x+c)^2)^(1/2)*(b*ln(2/(1-cos( d*x+c))^2*(2*a*(1-cos(d*x+c))^2+b*(1-cos(d*x+c))^2+2*b^(1/2)*((a*sin(d*x+c )^2+b)/(1+cos(d*x+c))^2)^(1/2)*sin(d*x+c)^2+b*sin(d*x+c)^2))*(-a)^(1/2)+2* a*ln(4*(-a)^(1/2)*((a*sin(d*x+c)^2+b)/(1+cos(d*x+c))^2)^(1/2)*cos(d*x+c)+4 *(-a)^(1/2)*((a*sin(d*x+c)^2+b)/(1+cos(d*x+c))^2)^(1/2)-4*cos(d*x+c)*a)*b^ (1/2)-ln(2/b^(1/2)*(((a*sin(d*x+c)^2+b)/(1+cos(d*x+c))^2)^(1/2)*b^(1/2)*co s(d*x+c)+b^(1/2)*((a*sin(d*x+c)^2+b)/(1+cos(d*x+c))^2)^(1/2)+cos(d*x+c)*a+ a+b)/(1+cos(d*x+c)))*(-a)^(1/2)*b)/((a*sin(d*x+c)^2+b)/(1+cos(d*x+c))^2)^( 1/2)*(csc(d*x+c)-cot(d*x+c))
Leaf count of result is larger than twice the leaf count of optimal. 255 vs. \(2 (69) = 138\).
Time = 0.26 (sec) , antiderivative size = 1341, normalized size of antiderivative = 16.56 \[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=\text {Too large to display} \] Input:
integrate((a+b*csc(d*x+c)^2)^(1/2),x, algorithm="fricas")
Output:
[1/8*(sqrt(-a)*log(128*a^4*cos(d*x + c)^8 - 256*(a^4 + a^3*b)*cos(d*x + c) ^6 + 160*(a^4 + 2*a^3*b + a^2*b^2)*cos(d*x + c)^4 + a^4 + 4*a^3*b + 6*a^2* b^2 + 4*a*b^3 + b^4 - 32*(a^4 + 3*a^3*b + 3*a^2*b^2 + a*b^3)*cos(d*x + c)^ 2 - 8*(16*a^3*cos(d*x + c)^7 - 24*(a^3 + a^2*b)*cos(d*x + c)^5 + 10*(a^3 + 2*a^2*b + a*b^2)*cos(d*x + c)^3 - (a^3 + 3*a^2*b + 3*a*b^2 + b^3)*cos(d*x + c))*sqrt(-a)*sqrt((a*cos(d*x + c)^2 - a - b)/(cos(d*x + c)^2 - 1))*sin( d*x + c)) + 2*sqrt(b)*log(2*((a^2 - 6*a*b + b^2)*cos(d*x + c)^4 - 2*(a^2 - 2*a*b - 3*b^2)*cos(d*x + c)^2 + 4*((a - b)*cos(d*x + c)^3 - (a + b)*cos(d *x + c))*sqrt(b)*sqrt((a*cos(d*x + c)^2 - a - b)/(cos(d*x + c)^2 - 1))*sin (d*x + c) + a^2 + 2*a*b + b^2)/(cos(d*x + c)^4 - 2*cos(d*x + c)^2 + 1)))/d , -1/8*(4*sqrt(-b)*arctan(-1/2*((a - b)*cos(d*x + c)^2 - a - b)*sqrt(-b)*s qrt((a*cos(d*x + c)^2 - a - b)/(cos(d*x + c)^2 - 1))*sin(d*x + c)/(a*b*cos (d*x + c)^3 - (a*b + b^2)*cos(d*x + c))) - sqrt(-a)*log(128*a^4*cos(d*x + c)^8 - 256*(a^4 + a^3*b)*cos(d*x + c)^6 + 160*(a^4 + 2*a^3*b + a^2*b^2)*co s(d*x + c)^4 + a^4 + 4*a^3*b + 6*a^2*b^2 + 4*a*b^3 + b^4 - 32*(a^4 + 3*a^3 *b + 3*a^2*b^2 + a*b^3)*cos(d*x + c)^2 - 8*(16*a^3*cos(d*x + c)^7 - 24*(a^ 3 + a^2*b)*cos(d*x + c)^5 + 10*(a^3 + 2*a^2*b + a*b^2)*cos(d*x + c)^3 - (a ^3 + 3*a^2*b + 3*a*b^2 + b^3)*cos(d*x + c))*sqrt(-a)*sqrt((a*cos(d*x + c)^ 2 - a - b)/(cos(d*x + c)^2 - 1))*sin(d*x + c)))/d, 1/4*(sqrt(a)*arctan(1/4 *(8*a^2*cos(d*x + c)^4 - 8*(a^2 + a*b)*cos(d*x + c)^2 + a^2 + 2*a*b + b...
\[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=\int \sqrt {a + b \csc ^{2}{\left (c + d x \right )}}\, dx \] Input:
integrate((a+b*csc(d*x+c)**2)**(1/2),x)
Output:
Integral(sqrt(a + b*csc(c + d*x)**2), x)
Result contains complex when optimal does not.
Time = 0.55 (sec) , antiderivative size = 3217, normalized size of antiderivative = 39.72 \[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=\text {Too large to display} \] Input:
integrate((a+b*csc(d*x+c)^2)^(1/2),x, algorithm="maxima")
Output:
-1/2*(2*sqrt(a)*b^(3/2)*arctan2(a*sin(2*d*x + 2*c) + (a^2*cos(4*d*x + 4*c) ^2 + a^2*sin(4*d*x + 4*c)^2 + 4*(a^2 + 4*a*b + 4*b^2)*cos(2*d*x + 2*c)^2 - 4*(a^2 + 2*a*b)*sin(4*d*x + 4*c)*sin(2*d*x + 2*c) + 4*(a^2 + 4*a*b + 4*b^ 2)*sin(2*d*x + 2*c)^2 + a^2 + 2*(a^2 - 2*(a^2 + 2*a*b)*cos(2*d*x + 2*c))*c os(4*d*x + 4*c) - 4*(a^2 + 2*a*b)*cos(2*d*x + 2*c))^(1/4)*sqrt(a)*sin(1/2* arctan2(a*sin(4*d*x + 4*c) - 2*(a + 2*b)*sin(2*d*x + 2*c), a*cos(4*d*x + 4 *c) - 2*(a + 2*b)*cos(2*d*x + 2*c) + a)), a*cos(2*d*x + 2*c) + (a^2*cos(4* d*x + 4*c)^2 + a^2*sin(4*d*x + 4*c)^2 + 4*(a^2 + 4*a*b + 4*b^2)*cos(2*d*x + 2*c)^2 - 4*(a^2 + 2*a*b)*sin(4*d*x + 4*c)*sin(2*d*x + 2*c) + 4*(a^2 + 4* a*b + 4*b^2)*sin(2*d*x + 2*c)^2 + a^2 + 2*(a^2 - 2*(a^2 + 2*a*b)*cos(2*d*x + 2*c))*cos(4*d*x + 4*c) - 4*(a^2 + 2*a*b)*cos(2*d*x + 2*c))^(1/4)*sqrt(a )*cos(1/2*arctan2(a*sin(4*d*x + 4*c) - 2*(a + 2*b)*sin(2*d*x + 2*c), a*cos (4*d*x + 4*c) - 2*(a + 2*b)*cos(2*d*x + 2*c) + a)) - a - 2*b) - a^(3/2)*sq rt(b)*arctan2(2*(a^2*cos(4*d*x + 4*c)^2 + a^2*sin(4*d*x + 4*c)^2 + 4*(a^2 + 4*a*b + 4*b^2)*cos(2*d*x + 2*c)^2 - 4*(a^2 + 2*a*b)*sin(4*d*x + 4*c)*sin (2*d*x + 2*c) + 4*(a^2 + 4*a*b + 4*b^2)*sin(2*d*x + 2*c)^2 + a^2 + 2*(a^2 - 2*(a^2 + 2*a*b)*cos(2*d*x + 2*c))*cos(4*d*x + 4*c) - 4*(a^2 + 2*a*b)*cos (2*d*x + 2*c))^(1/4)*sqrt(a)*sin(1/2*arctan2(a*sin(4*d*x + 4*c) - 2*(a + 2 *b)*sin(2*d*x + 2*c), a*cos(4*d*x + 4*c) - 2*(a + 2*b)*cos(2*d*x + 2*c) + a)), 2*(a^2*cos(4*d*x + 4*c)^2 + a^2*sin(4*d*x + 4*c)^2 + 4*(a^2 + 4*a*...
Exception generated. \[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=\text {Exception raised: TypeError} \] Input:
integrate((a+b*csc(d*x+c)^2)^(1/2),x, algorithm="giac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:Degree mismatch inside factorisatio n over extensionDegree mismatch inside factorisation over extensionDegree mismatch
Timed out. \[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=\int \sqrt {a+\frac {b}{{\sin \left (c+d\,x\right )}^2}} \,d x \] Input:
int((a + b/sin(c + d*x)^2)^(1/2),x)
Output:
int((a + b/sin(c + d*x)^2)^(1/2), x)
\[ \int \sqrt {a+b \csc ^2(c+d x)} \, dx=\int \sqrt {\csc \left (d x +c \right )^{2} b +a}d x \] Input:
int((a+b*csc(d*x+c)^2)^(1/2),x)
Output:
int(sqrt(csc(c + d*x)**2*b + a),x)