\(\int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx\) [142]

Optimal result

Integrand size = 34, antiderivative size = 224 \[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=-\frac {2 \left (1+e^{2 i (d+e x)}\right ) F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)}}{\left (1-e^{2 i (d+e x)}\right ) (i e+2 b c \log (F))}+\frac {8 b c \sqrt {1+e^{2 i (d+e x)}} F^{c (a+b x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {-e-2 i b c \log (F)}{4 e},\frac {1}{4} \left (3-\frac {2 i b c \log (F)}{e}\right ),-e^{2 i (d+e x)}\right ) \log (F) \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)}}{\left (1-e^{2 i (d+e x)}\right ) \left (e^2+4 b^2 c^2 \log ^2(F)\right )} \] Output:

-2*(1+exp(2*I*(e*x+d)))*F^(c*(b*x+a))*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^ 
(1/2)/(1-exp(2*I*(e*x+d)))/(I*e+2*b*c*ln(F))+8*b*c*(1+exp(2*I*(e*x+d)))^(1 
/2)*F^(c*(b*x+a))*hypergeom([1/2, 1/4*(-e-2*I*b*c*ln(F))/e],[3/4-1/2*I*b*c 
*ln(F)/e],-exp(2*I*(e*x+d)))*ln(F)*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^(1/ 
2)/(1-exp(2*I*(e*x+d)))/(e^2+4*b^2*c^2*ln(F)^2)
 

Mathematica [A] (warning: unable to verify)

Time = 3.04 (sec) , antiderivative size = 260, normalized size of antiderivative = 1.16 \[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=-\frac {2 F^{c (a+b x)} g \sqrt {f \sin (d+e x)} (-i \cos (d+e x)+\sin (d+e x)) (i \cos (d+e x)+\sin (d+e x)) \left (\operatorname {Hypergeometric2F1}\left (1,\frac {e-2 i b c \log (F)}{4 e},\frac {3}{4}-\frac {i b c \log (F)}{2 e},-\cos (2 (d+e x))-i \sin (2 (d+e x))\right ) (3 e-2 i b c \log (F))+\operatorname {Hypergeometric2F1}\left (1,\frac {5}{4}-\frac {i b c \log (F)}{2 e},\frac {7}{4}-\frac {i b c \log (F)}{2 e},-\cos (2 (d+e x))-i \sin (2 (d+e x))\right ) (e+2 i b c \log (F)) (\cos (2 (d+e x))+i \sin (2 (d+e x)))\right )}{(3 e-2 i b c \log (F)) (e+2 i b c \log (F)) \sqrt {g \tan (d+e x)}} \] Input:

Integrate[F^(c*(a + b*x))*Sqrt[f*Sin[d + e*x]]*Sqrt[g*Tan[d + e*x]],x]
 

Output:

(-2*F^(c*(a + b*x))*g*Sqrt[f*Sin[d + e*x]]*((-I)*Cos[d + e*x] + Sin[d + e* 
x])*(I*Cos[d + e*x] + Sin[d + e*x])*(Hypergeometric2F1[1, (e - (2*I)*b*c*L 
og[F])/(4*e), 3/4 - ((I/2)*b*c*Log[F])/e, -Cos[2*(d + e*x)] - I*Sin[2*(d + 
 e*x)]]*(3*e - (2*I)*b*c*Log[F]) + Hypergeometric2F1[1, 5/4 - ((I/2)*b*c*L 
og[F])/e, 7/4 - ((I/2)*b*c*Log[F])/e, -Cos[2*(d + e*x)] - I*Sin[2*(d + e*x 
)]]*(e + (2*I)*b*c*Log[F])*(Cos[2*(d + e*x)] + I*Sin[2*(d + e*x)])))/((3*e 
 - (2*I)*b*c*Log[F])*(e + (2*I)*b*c*Log[F])*Sqrt[g*Tan[d + e*x]])
 

Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx\)

\(\Big \downarrow \) 7271

\(\displaystyle \frac {\sqrt {f \sin (d+e x)} \int F^{c (a+b x)} \sqrt {\sin (d+e x)} \sqrt {g \tan (d+e x)}dx}{\sqrt {\sin (d+e x)}}\)

\(\Big \downarrow \) 7271

\(\displaystyle \frac {\sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \int F^{c (a+b x)} \sqrt {\sin (d+e x)} \sqrt {\tan (d+e x)}dx}{\sqrt {\sin (d+e x)} \sqrt {\tan (d+e x)}}\)

\(\Big \downarrow \) 7292

\(\displaystyle \frac {\sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \int F^{a c+b x c} \sqrt {\sin (d+e x)} \sqrt {\tan (d+e x)}dx}{\sqrt {\sin (d+e x)} \sqrt {\tan (d+e x)}}\)

\(\Big \downarrow \) 7299

\(\displaystyle \frac {\sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \int F^{a c+b x c} \sqrt {\sin (d+e x)} \sqrt {\tan (d+e x)}dx}{\sqrt {\sin (d+e x)} \sqrt {\tan (d+e x)}}\)

Input:

Int[F^(c*(a + b*x))*Sqrt[f*Sin[d + e*x]]*Sqrt[g*Tan[d + e*x]],x]
 

Output:

$Aborted
 

Defintions of rubi rules used

rule 7271

Int[(u_.)*((a_.)*(v_)^(m_.))^(p_), x_Symbol] :> Simp[a^IntPart[p]*((a*v^m)^ 
FracPart[p]/v^(m*FracPart[p]))   Int[u*v^(m*p), x], x] /; FreeQ[{a, m, p}, 
x] &&  !IntegerQ[p] &&  !FreeQ[v, x] &&  !(EqQ[a, 1] && EqQ[m, 1]) &&  !(Eq 
Q[v, x] && EqQ[m, 1])
 

rule 7292

Int[u_, x_Symbol] :> With[{v = NormalizeIntegrand[u, x]}, Int[v, x] /; v =! 
= u]
 

rule 7299

Int[u_, x_] :> CannotIntegrate[u, x]
 

Maple [F]

\[\int F^{c \left (b x +a \right )} \sqrt {f \sin \left (e x +d \right )}\, \sqrt {g \tan \left (e x +d \right )}d x\]

Input:

int(F^(c*(b*x+a))*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^(1/2),x)
 

Output:

int(F^(c*(b*x+a))*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^(1/2),x)
 

Fricas [F]

\[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=\int { \sqrt {f \sin \left (e x + d\right )} \sqrt {g \tan \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:

integrate(F^(c*(b*x+a))*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^(1/2),x, algor 
ithm="fricas")
 

Output:

integral(sqrt(f*sin(e*x + d))*sqrt(g*tan(e*x + d))*F^(b*c*x + a*c), x)
 

Sympy [F(-1)]

Timed out. \[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=\text {Timed out} \] Input:

integrate(F**(c*(b*x+a))*(f*sin(e*x+d))**(1/2)*(g*tan(e*x+d))**(1/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=\int { \sqrt {f \sin \left (e x + d\right )} \sqrt {g \tan \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:

integrate(F^(c*(b*x+a))*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^(1/2),x, algor 
ithm="maxima")
 

Output:

integrate(sqrt(f*sin(e*x + d))*sqrt(g*tan(e*x + d))*F^((b*x + a)*c), x)
 

Giac [F]

\[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=\int { \sqrt {f \sin \left (e x + d\right )} \sqrt {g \tan \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:

integrate(F^(c*(b*x+a))*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^(1/2),x, algor 
ithm="giac")
 

Output:

integrate(sqrt(f*sin(e*x + d))*sqrt(g*tan(e*x + d))*F^((b*x + a)*c), x)
 

Mupad [F(-1)]

Timed out. \[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=\int F^{c\,\left (a+b\,x\right )}\,\sqrt {f\,\sin \left (d+e\,x\right )}\,\sqrt {g\,\mathrm {tan}\left (d+e\,x\right )} \,d x \] Input:

int(F^(c*(a + b*x))*(f*sin(d + e*x))^(1/2)*(g*tan(d + e*x))^(1/2),x)
 

Output:

int(F^(c*(a + b*x))*(f*sin(d + e*x))^(1/2)*(g*tan(d + e*x))^(1/2), x)
 

Reduce [F]

\[ \int F^{c (a+b x)} \sqrt {f \sin (d+e x)} \sqrt {g \tan (d+e x)} \, dx=\sqrt {g}\, f^{a c +\frac {1}{2}} \left (\int f^{b c x} \sqrt {\tan \left (e x +d \right )}\, \sqrt {\sin \left (e x +d \right )}d x \right ) \] Input:

int(F^(c*(b*x+a))*(f*sin(e*x+d))^(1/2)*(g*tan(e*x+d))^(1/2),x)
 

Output:

sqrt(g)*f**((2*a*c + 1)/2)*int(f**(b*c*x)*sqrt(tan(d + e*x))*sqrt(sin(d + 
e*x)),x)