\(\int \frac {\sin (a+b x)}{c+d x^2} \, dx\) [33]

Optimal result

Integrand size = 16, antiderivative size = 213 \[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=-\frac {\operatorname {CosIntegral}\left (\frac {b \sqrt {-c}}{\sqrt {d}}+b x\right ) \sin \left (a-\frac {b \sqrt {-c}}{\sqrt {d}}\right )}{2 \sqrt {-c} \sqrt {d}}+\frac {\operatorname {CosIntegral}\left (\frac {b \sqrt {-c}}{\sqrt {d}}-b x\right ) \sin \left (a+\frac {b \sqrt {-c}}{\sqrt {d}}\right )}{2 \sqrt {-c} \sqrt {d}}-\frac {\cos \left (a+\frac {b \sqrt {-c}}{\sqrt {d}}\right ) \text {Si}\left (\frac {b \sqrt {-c}}{\sqrt {d}}-b x\right )}{2 \sqrt {-c} \sqrt {d}}-\frac {\cos \left (a-\frac {b \sqrt {-c}}{\sqrt {d}}\right ) \text {Si}\left (\frac {b \sqrt {-c}}{\sqrt {d}}+b x\right )}{2 \sqrt {-c} \sqrt {d}} \] Output:

-1/2*Ci(b*(-c)^(1/2)/d^(1/2)+b*x)*sin(a-b*(-c)^(1/2)/d^(1/2))/(-c)^(1/2)/d 
^(1/2)+1/2*Ci(b*(-c)^(1/2)/d^(1/2)-b*x)*sin(a+b*(-c)^(1/2)/d^(1/2))/(-c)^( 
1/2)/d^(1/2)+1/2*cos(a+b*(-c)^(1/2)/d^(1/2))*Si(-b*(-c)^(1/2)/d^(1/2)+b*x) 
/(-c)^(1/2)/d^(1/2)-1/2*cos(a-b*(-c)^(1/2)/d^(1/2))*Si(b*(-c)^(1/2)/d^(1/2 
)+b*x)/(-c)^(1/2)/d^(1/2)
 

Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 0.74 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.77 \[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=\frac {e^{-i a-\frac {b \sqrt {c}}{\sqrt {d}}} \left (e^{\frac {2 b \sqrt {c}}{\sqrt {d}}} \operatorname {ExpIntegralEi}\left (-\frac {b \sqrt {c}}{\sqrt {d}}-i b x\right )-\operatorname {ExpIntegralEi}\left (\frac {b \sqrt {c}}{\sqrt {d}}-i b x\right )+e^{2 i a} \left (e^{\frac {2 b \sqrt {c}}{\sqrt {d}}} \operatorname {ExpIntegralEi}\left (-\frac {b \sqrt {c}}{\sqrt {d}}+i b x\right )-\operatorname {ExpIntegralEi}\left (\frac {b \sqrt {c}}{\sqrt {d}}+i b x\right )\right )\right )}{4 \sqrt {c} \sqrt {d}} \] Input:

Integrate[Sin[a + b*x]/(c + d*x^2),x]
 

Output:

(E^((-I)*a - (b*Sqrt[c])/Sqrt[d])*(E^((2*b*Sqrt[c])/Sqrt[d])*ExpIntegralEi 
[-((b*Sqrt[c])/Sqrt[d]) - I*b*x] - ExpIntegralEi[(b*Sqrt[c])/Sqrt[d] - I*b 
*x] + E^((2*I)*a)*(E^((2*b*Sqrt[c])/Sqrt[d])*ExpIntegralEi[-((b*Sqrt[c])/S 
qrt[d]) + I*b*x] - ExpIntegralEi[(b*Sqrt[c])/Sqrt[d] + I*b*x])))/(4*Sqrt[c 
]*Sqrt[d])
 

Rubi [A] (verified)

Time = 0.65 (sec) , antiderivative size = 213, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {3814, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sin (a+b x)}{c+d x^2} \, dx\)

\(\Big \downarrow \) 3814

\(\displaystyle \int \left (\frac {\sqrt {-c} \sin (a+b x)}{2 c \left (\sqrt {-c}-\sqrt {d} x\right )}+\frac {\sqrt {-c} \sin (a+b x)}{2 c \left (\sqrt {-c}+\sqrt {d} x\right )}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {\sin \left (a-\frac {b \sqrt {-c}}{\sqrt {d}}\right ) \operatorname {CosIntegral}\left (x b+\frac {\sqrt {-c} b}{\sqrt {d}}\right )}{2 \sqrt {-c} \sqrt {d}}+\frac {\sin \left (a+\frac {b \sqrt {-c}}{\sqrt {d}}\right ) \operatorname {CosIntegral}\left (\frac {b \sqrt {-c}}{\sqrt {d}}-b x\right )}{2 \sqrt {-c} \sqrt {d}}-\frac {\cos \left (a+\frac {b \sqrt {-c}}{\sqrt {d}}\right ) \text {Si}\left (\frac {b \sqrt {-c}}{\sqrt {d}}-b x\right )}{2 \sqrt {-c} \sqrt {d}}-\frac {\cos \left (a-\frac {b \sqrt {-c}}{\sqrt {d}}\right ) \text {Si}\left (x b+\frac {\sqrt {-c} b}{\sqrt {d}}\right )}{2 \sqrt {-c} \sqrt {d}}\)

Input:

Int[Sin[a + b*x]/(c + d*x^2),x]
 

Output:

-1/2*(CosIntegral[(b*Sqrt[-c])/Sqrt[d] + b*x]*Sin[a - (b*Sqrt[-c])/Sqrt[d] 
])/(Sqrt[-c]*Sqrt[d]) + (CosIntegral[(b*Sqrt[-c])/Sqrt[d] - b*x]*Sin[a + ( 
b*Sqrt[-c])/Sqrt[d]])/(2*Sqrt[-c]*Sqrt[d]) - (Cos[a + (b*Sqrt[-c])/Sqrt[d] 
]*SinIntegral[(b*Sqrt[-c])/Sqrt[d] - b*x])/(2*Sqrt[-c]*Sqrt[d]) - (Cos[a - 
 (b*Sqrt[-c])/Sqrt[d]]*SinIntegral[(b*Sqrt[-c])/Sqrt[d] + b*x])/(2*Sqrt[-c 
]*Sqrt[d])
 

Defintions of rubi rules used

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3814

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*Sin[(c_.) + (d_.)*(x_)], x_Symbol] :> Int 
[ExpandIntegrand[Sin[c + d*x], (a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d}, 
 x] && ILtQ[p, 0] && IGtQ[n, 0] && (EqQ[n, 2] || EqQ[p, -1])
 

Maple [A] (verified)

Time = 0.32 (sec) , antiderivative size = 233, normalized size of antiderivative = 1.09

method	result	size
derivativedivides	\(b \left (-\frac {-\operatorname {Si}\left (-b x -a +\frac {b \sqrt {-c d}+a d}{d}\right ) \cos \left (\frac {b \sqrt {-c d}+a d}{d}\right )+\operatorname {Ci}\left (b x +a -\frac {b \sqrt {-c d}+a d}{d}\right ) \sin \left (\frac {b \sqrt {-c d}+a d}{d}\right )}{2 d \left (-\frac {b \sqrt {-c d}+a d}{d}+a \right )}-\frac {-\operatorname {Si}\left (-b x -a -\frac {b \sqrt {-c d}-a d}{d}\right ) \cos \left (\frac {b \sqrt {-c d}-a d}{d}\right )-\operatorname {Ci}\left (b x +a +\frac {b \sqrt {-c d}-a d}{d}\right ) \sin \left (\frac {b \sqrt {-c d}-a d}{d}\right )}{2 d \left (\frac {b \sqrt {-c d}-a d}{d}+a \right )}\right )\)	\(233\)
default	\(b \left (-\frac {-\operatorname {Si}\left (-b x -a +\frac {b \sqrt {-c d}+a d}{d}\right ) \cos \left (\frac {b \sqrt {-c d}+a d}{d}\right )+\operatorname {Ci}\left (b x +a -\frac {b \sqrt {-c d}+a d}{d}\right ) \sin \left (\frac {b \sqrt {-c d}+a d}{d}\right )}{2 d \left (-\frac {b \sqrt {-c d}+a d}{d}+a \right )}-\frac {-\operatorname {Si}\left (-b x -a -\frac {b \sqrt {-c d}-a d}{d}\right ) \cos \left (\frac {b \sqrt {-c d}-a d}{d}\right )-\operatorname {Ci}\left (b x +a +\frac {b \sqrt {-c d}-a d}{d}\right ) \sin \left (\frac {b \sqrt {-c d}-a d}{d}\right )}{2 d \left (\frac {b \sqrt {-c d}-a d}{d}+a \right )}\right )\)	\(233\)
risch	\(\frac {\sqrt {c d}\, \operatorname {expIntegral}_{1}\left (-\frac {i a d +b \sqrt {c d}-\left (i b x +i a \right ) d}{d}\right ) {\mathrm e}^{-\frac {i a d +b \sqrt {c d}}{d}}}{4 c d}-\frac {\sqrt {c d}\, \operatorname {expIntegral}_{1}\left (-\frac {i a d -b \sqrt {c d}-\left (i b x +i a \right ) d}{d}\right ) {\mathrm e}^{-\frac {i a d -b \sqrt {c d}}{d}}}{4 c d}-\frac {\sqrt {c d}\, \operatorname {expIntegral}_{1}\left (\frac {i a d +b \sqrt {c d}-\left (i b x +i a \right ) d}{d}\right ) {\mathrm e}^{\frac {i a d +b \sqrt {c d}}{d}}}{4 c d}+\frac {\sqrt {c d}\, \operatorname {expIntegral}_{1}\left (\frac {i a d -b \sqrt {c d}-\left (i b x +i a \right ) d}{d}\right ) {\mathrm e}^{\frac {i a d -b \sqrt {c d}}{d}}}{4 c d}\)	\(262\)

Input:

int(sin(b*x+a)/(d*x^2+c),x,method=_RETURNVERBOSE)
 

Output:

b*(-1/2/d/(-(b*(-c*d)^(1/2)+a*d)/d+a)*(-Si(-b*x-a+(b*(-c*d)^(1/2)+a*d)/d)* 
cos((b*(-c*d)^(1/2)+a*d)/d)+Ci(b*x+a-(b*(-c*d)^(1/2)+a*d)/d)*sin((b*(-c*d) 
^(1/2)+a*d)/d))-1/2/d/((b*(-c*d)^(1/2)-a*d)/d+a)*(-Si(-b*x-a-(b*(-c*d)^(1/ 
2)-a*d)/d)*cos((b*(-c*d)^(1/2)-a*d)/d)-Ci(b*x+a+(b*(-c*d)^(1/2)-a*d)/d)*si 
n((b*(-c*d)^(1/2)-a*d)/d)))
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.09 (sec) , antiderivative size = 187, normalized size of antiderivative = 0.88 \[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=\frac {\sqrt {\frac {b^{2} c}{d}} {\rm Ei}\left (i \, b x - \sqrt {\frac {b^{2} c}{d}}\right ) e^{\left (i \, a + \sqrt {\frac {b^{2} c}{d}}\right )} - \sqrt {\frac {b^{2} c}{d}} {\rm Ei}\left (i \, b x + \sqrt {\frac {b^{2} c}{d}}\right ) e^{\left (i \, a - \sqrt {\frac {b^{2} c}{d}}\right )} + \sqrt {\frac {b^{2} c}{d}} {\rm Ei}\left (-i \, b x - \sqrt {\frac {b^{2} c}{d}}\right ) e^{\left (-i \, a + \sqrt {\frac {b^{2} c}{d}}\right )} - \sqrt {\frac {b^{2} c}{d}} {\rm Ei}\left (-i \, b x + \sqrt {\frac {b^{2} c}{d}}\right ) e^{\left (-i \, a - \sqrt {\frac {b^{2} c}{d}}\right )}}{4 \, b c} \] Input:

integrate(sin(b*x+a)/(d*x^2+c),x, algorithm="fricas")
 

Output:

1/4*(sqrt(b^2*c/d)*Ei(I*b*x - sqrt(b^2*c/d))*e^(I*a + sqrt(b^2*c/d)) - sqr 
t(b^2*c/d)*Ei(I*b*x + sqrt(b^2*c/d))*e^(I*a - sqrt(b^2*c/d)) + sqrt(b^2*c/ 
d)*Ei(-I*b*x - sqrt(b^2*c/d))*e^(-I*a + sqrt(b^2*c/d)) - sqrt(b^2*c/d)*Ei( 
-I*b*x + sqrt(b^2*c/d))*e^(-I*a - sqrt(b^2*c/d)))/(b*c)
 

Sympy [F]

\[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=\int \frac {\sin {\left (a + b x \right )}}{c + d x^{2}}\, dx \] Input:

integrate(sin(b*x+a)/(d*x**2+c),x)
                                                                                    
                                                                                    
 

Output:

Integral(sin(a + b*x)/(c + d*x**2), x)
 

Maxima [F]

\[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=\int { \frac {\sin \left (b x + a\right )}{d x^{2} + c} \,d x } \] Input:

integrate(sin(b*x+a)/(d*x^2+c),x, algorithm="maxima")
 

Output:

integrate(sin(b*x + a)/(d*x^2 + c), x)
 

Giac [F]

\[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=\int { \frac {\sin \left (b x + a\right )}{d x^{2} + c} \,d x } \] Input:

integrate(sin(b*x+a)/(d*x^2+c),x, algorithm="giac")
 

Output:

integrate(sin(b*x + a)/(d*x^2 + c), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=\int \frac {\sin \left (a+b\,x\right )}{d\,x^2+c} \,d x \] Input:

int(sin(a + b*x)/(c + d*x^2),x)
 

Output:

int(sin(a + b*x)/(c + d*x^2), x)
 

Reduce [F]

\[ \int \frac {\sin (a+b x)}{c+d x^2} \, dx=\int \frac {\sin \left (b x +a \right )}{d \,x^{2}+c}d x \] Input:

int(sin(b*x+a)/(d*x^2+c),x)
 

Output:

int(sin(a + b*x)/(c + d*x**2),x)