Integrand size = 15, antiderivative size = 141 \[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=-\frac {4 i e^{-i a-i b x+3 i (c+d x)} \operatorname {Hypergeometric2F1}\left (3,\frac {1}{2} \left (3-\frac {b}{d}\right ),\frac {1}{2} \left (5-\frac {b}{d}\right ),e^{2 i (c+d x)}\right )}{b-3 d}-\frac {4 i e^{i a+i b x+3 i (c+d x)} \operatorname {Hypergeometric2F1}\left (3,\frac {1}{2} \left (3+\frac {b}{d}\right ),\frac {1}{2} \left (5+\frac {b}{d}\right ),e^{2 i (c+d x)}\right )}{b+3 d} \] Output:
-4*I*exp(-I*a-I*b*x+3*I*(d*x+c))*hypergeom([3, 3/2-1/2*b/d],[5/2-1/2*b/d], exp(2*I*(d*x+c)))/(b-3*d)-4*I*exp(I*a+I*b*x+3*I*(d*x+c))*hypergeom([3, 3/2 +1/2*b/d],[5/2+1/2*b/d],exp(2*I*(d*x+c)))/(b+3*d)
Time = 1.92 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.21 \[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=-\frac {8 i (b+d) e^{-i (a-c+(b-d) x)} \operatorname {Hypergeometric2F1}\left (1,\frac {-b+d}{2 d},\frac {3}{2}-\frac {b}{2 d},e^{2 i (c+d x)}\right )+8 i (b-d) e^{i (a+c+(b+d) x)} \operatorname {Hypergeometric2F1}\left (1,\frac {b+d}{2 d},\frac {1}{2} \left (3+\frac {b}{d}\right ),e^{2 i (c+d x)}\right )+4 \csc ^2(c+d x) ((-b+d) \sin (a-c+b x-d x)+(b+d) \sin (a+c+(b+d) x))}{16 d^2} \] Input:
Integrate[Csc[c + d*x]^3*Sin[a + b*x],x]
Output:
-1/16*(((8*I)*(b + d)*Hypergeometric2F1[1, (-b + d)/(2*d), 3/2 - b/(2*d), E^((2*I)*(c + d*x))])/E^(I*(a - c + (b - d)*x)) + (8*I)*(b - d)*E^(I*(a + c + (b + d)*x))*Hypergeometric2F1[1, (b + d)/(2*d), (3 + b/d)/2, E^((2*I)* (c + d*x))] + 4*Csc[c + d*x]^2*((-b + d)*Sin[a - c + b*x - d*x] + (b + d)* Sin[a + c + (b + d)*x]))/d^2
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sin (a+b x) \csc ^3(c+d x) \, dx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int \sin (a+b x) \csc ^3(c+d x)dx\) |
Input:
Int[Csc[c + d*x]^3*Sin[a + b*x],x]
Output:
$Aborted
\[\int \csc \left (d x +c \right )^{3} \sin \left (b x +a \right )d x\]
Input:
int(csc(d*x+c)^3*sin(b*x+a),x)
Output:
int(csc(d*x+c)^3*sin(b*x+a),x)
\[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=\int { \csc \left (d x + c\right )^{3} \sin \left (b x + a\right ) \,d x } \] Input:
integrate(csc(d*x+c)^3*sin(b*x+a),x, algorithm="fricas")
Output:
integral(csc(d*x + c)^3*sin(b*x + a), x)
Timed out. \[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=\text {Timed out} \] Input:
integrate(csc(d*x+c)**3*sin(b*x+a),x)
Output:
Timed out
\[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=\int { \csc \left (d x + c\right )^{3} \sin \left (b x + a\right ) \,d x } \] Input:
integrate(csc(d*x+c)^3*sin(b*x+a),x, algorithm="maxima")
Output:
-1/2*((b - d)*cos(b*x + a)*sin((2*b + d)*x + 2*a + c) - (b - d)*cos((2*b + d)*x + 2*a + c)*sin(b*x + a) + (b - d)*cos(3*d*x + 3*c)*sin(b*x + a) - (b + d)*cos(d*x + c)*sin(b*x + a) - (b - d)*cos(b*x + a)*sin(3*d*x + 3*c) + (b + d)*cos(b*x + a)*sin(d*x + c) - (2*(b + d)*sin((b + 2*d)*x + a + 2*c) - (b + d)*sin(b*x + a))*cos((2*b + 3*d)*x + 2*a + 3*c) - ((b + d)*sin((2*b + 3*d)*x + 2*a + 3*c) - (b - d)*sin((2*b + d)*x + 2*a + c) + (b - d)*sin( 3*d*x + 3*c) - (b + d)*sin(d*x + c))*cos((b + 4*d)*x + a + 4*c) - 2*((b - d)*sin((2*b + d)*x + 2*a + c) - (b - d)*sin(3*d*x + 3*c) + (b + d)*sin(d*x + c))*cos((b + 2*d)*x + a + 2*c) - 2*(d^2*cos((b + 4*d)*x + a + 4*c)^2 + 4*d^2*cos((b + 2*d)*x + a + 2*c)^2 - 4*d^2*cos((b + 2*d)*x + a + 2*c)*cos( b*x + a) + d^2*cos(b*x + a)^2 + d^2*sin((b + 4*d)*x + a + 4*c)^2 + 4*d^2*s in((b + 2*d)*x + a + 2*c)^2 - 4*d^2*sin((b + 2*d)*x + a + 2*c)*sin(b*x + a ) + d^2*sin(b*x + a)^2 - 2*(2*d^2*cos((b + 2*d)*x + a + 2*c) - d^2*cos(b*x + a))*cos((b + 4*d)*x + a + 4*c) - 2*(2*d^2*sin((b + 2*d)*x + a + 2*c) - d^2*sin(b*x + a))*sin((b + 4*d)*x + a + 4*c))*integrate(-1/4*((b^2 - d^2)* cos(2*b*x + 2*a)*cos(b*x + a) + (b^2 - d^2)*sin((b + d)*x + a + c)*sin(2*b *x + 2*a) + (b^2 - d^2)*sin(2*b*x + 2*a)*sin(b*x + a) - (b^2 - d^2 - (b^2 - d^2)*cos(2*b*x + 2*a))*cos((b + d)*x + a + c) - (b^2 - d^2)*cos(b*x + a) )/(d^2*cos((b + d)*x + a + c)^2 + 2*d^2*cos((b + d)*x + a + c)*cos(b*x + a ) + d^2*cos(b*x + a)^2 + d^2*sin((b + d)*x + a + c)^2 + 2*d^2*sin((b + ...
\[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=\int { \csc \left (d x + c\right )^{3} \sin \left (b x + a\right ) \,d x } \] Input:
integrate(csc(d*x+c)^3*sin(b*x+a),x, algorithm="giac")
Output:
integrate(csc(d*x + c)^3*sin(b*x + a), x)
Timed out. \[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=\int \frac {\sin \left (a+b\,x\right )}{{\sin \left (c+d\,x\right )}^3} \,d x \] Input:
int(sin(a + b*x)/sin(c + d*x)^3,x)
Output:
int(sin(a + b*x)/sin(c + d*x)^3, x)
\[ \int \csc ^3(c+d x) \sin (a+b x) \, dx=\int \csc \left (d x +c \right )^{3} \sin \left (b x +a \right )d x \] Input:
int(csc(d*x+c)^3*sin(b*x+a),x)
Output:
int(csc(c + d*x)**3*sin(a + b*x),x)