Integrand size = 17, antiderivative size = 140 \[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=-\frac {\cot (c+d x)}{2 d}+\frac {i e^{-2 i a-2 i b x+2 i (c+d x)} \operatorname {Hypergeometric2F1}\left (2,1-\frac {b}{d},2-\frac {b}{d},e^{2 i (c+d x)}\right )}{2 (b-d)}-\frac {i e^{2 i a+2 i b x+2 i (c+d x)} \operatorname {Hypergeometric2F1}\left (2,\frac {b+d}{d},2+\frac {b}{d},e^{2 i (c+d x)}\right )}{2 (b+d)} \] Output:
-1/2*cot(d*x+c)/d+1/2*I*exp(-2*I*a-2*I*b*x+2*I*(d*x+c))*hypergeom([2, 1-b/ d],[2-b/d],exp(2*I*(d*x+c)))/(b-d)-1/2*I*exp(2*I*a+2*I*b*x+2*I*(d*x+c))*hy pergeom([2, (b+d)/d],[2+b/d],exp(2*I*(d*x+c)))/(b+d)
Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(290\) vs. \(2(140)=280\).
Time = 3.30 (sec) , antiderivative size = 290, normalized size of antiderivative = 2.07 \[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=\frac {-\frac {i b e^{-2 i (a-c)} \left (\frac {e^{-2 i (b-d) x} \operatorname {Hypergeometric2F1}\left (1,1-\frac {b}{d},2-\frac {b}{d},e^{2 i (c+d x)}\right )}{b-d}-\frac {e^{-2 i b x} \operatorname {Hypergeometric2F1}\left (1,-\frac {b}{d},1-\frac {b}{d},e^{2 i (c+d x)}\right )}{b}\right )}{-1+e^{2 i c}}+\frac {i e^{2 i (a+c)} \left ((b+d) e^{2 i b x} \operatorname {Hypergeometric2F1}\left (1,\frac {b}{d},\frac {b+d}{d},e^{2 i (c+d x)}\right )-b e^{2 i (b+d) x} \operatorname {Hypergeometric2F1}\left (1,\frac {b+d}{d},2+\frac {b}{d},e^{2 i (c+d x)}\right )\right )}{(b+d) \left (-1+e^{2 i c}\right )}+\csc (c) \csc (c+d x) \sin (d x)-\cos (2 a) \cos (2 b x) \csc (c) \csc (c+d x) \sin (d x)+\csc (c) \csc (c+d x) \sin (2 a) \sin (2 b x) \sin (d x)}{2 d} \] Input:
Integrate[Csc[c + d*x]^2*Sin[a + b*x]^2,x]
Output:
(((-I)*b*(Hypergeometric2F1[1, 1 - b/d, 2 - b/d, E^((2*I)*(c + d*x))]/((b - d)*E^((2*I)*(b - d)*x)) - Hypergeometric2F1[1, -(b/d), 1 - b/d, E^((2*I) *(c + d*x))]/(b*E^((2*I)*b*x))))/(E^((2*I)*(a - c))*(-1 + E^((2*I)*c))) + (I*E^((2*I)*(a + c))*((b + d)*E^((2*I)*b*x)*Hypergeometric2F1[1, b/d, (b + d)/d, E^((2*I)*(c + d*x))] - b*E^((2*I)*(b + d)*x)*Hypergeometric2F1[1, ( b + d)/d, 2 + b/d, E^((2*I)*(c + d*x))]))/((b + d)*(-1 + E^((2*I)*c))) + C sc[c]*Csc[c + d*x]*Sin[d*x] - Cos[2*a]*Cos[2*b*x]*Csc[c]*Csc[c + d*x]*Sin[ d*x] + Csc[c]*Csc[c + d*x]*Sin[2*a]*Sin[2*b*x]*Sin[d*x])/(2*d)
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sin ^2(a+b x) \csc ^2(c+d x) \, dx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int \sin ^2(a+b x) \csc ^2(c+d x)dx\) |
Input:
Int[Csc[c + d*x]^2*Sin[a + b*x]^2,x]
Output:
$Aborted
\[\int \csc \left (d x +c \right )^{2} \sin \left (b x +a \right )^{2}d x\]
Input:
int(csc(d*x+c)^2*sin(b*x+a)^2,x)
Output:
int(csc(d*x+c)^2*sin(b*x+a)^2,x)
\[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=\int { \csc \left (d x + c\right )^{2} \sin \left (b x + a\right )^{2} \,d x } \] Input:
integrate(csc(d*x+c)^2*sin(b*x+a)^2,x, algorithm="fricas")
Output:
integral(-(cos(b*x + a)^2 - 1)*csc(d*x + c)^2, x)
Timed out. \[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=\text {Timed out} \] Input:
integrate(csc(d*x+c)**2*sin(b*x+a)**2,x)
Output:
Timed out
\[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=\int { \csc \left (d x + c\right )^{2} \sin \left (b x + a\right )^{2} \,d x } \] Input:
integrate(csc(d*x+c)^2*sin(b*x+a)^2,x, algorithm="maxima")
Output:
-1/2*((sin(4*b*x + 4*a) - 2*sin(2*b*x + 2*a))*cos(2*(b + d)*x + 2*a + 2*c) + 2*(d*cos(2*(b + d)*x + 2*a + 2*c)^2 - 2*d*cos(2*(b + d)*x + 2*a + 2*c)* cos(2*b*x + 2*a) + d*cos(2*b*x + 2*a)^2 + d*sin(2*(b + d)*x + 2*a + 2*c)^2 - 2*d*sin(2*(b + d)*x + 2*a + 2*c)*sin(2*b*x + 2*a) + d*sin(2*b*x + 2*a)^ 2)*integrate(1/2*(b*cos(4*b*x + 4*a)*cos(2*b*x + 2*a) + b*sin((2*b + d)*x + 2*a + c)*sin(4*b*x + 4*a) + b*sin(4*b*x + 4*a)*sin(2*b*x + 2*a) + (b*cos (4*b*x + 4*a) - b)*cos((2*b + d)*x + 2*a + c) - b*cos(2*b*x + 2*a))/(d*cos ((2*b + d)*x + 2*a + c)^2 + 2*d*cos((2*b + d)*x + 2*a + c)*cos(2*b*x + 2*a ) + d*cos(2*b*x + 2*a)^2 + d*sin((2*b + d)*x + 2*a + c)^2 + 2*d*sin((2*b + d)*x + 2*a + c)*sin(2*b*x + 2*a) + d*sin(2*b*x + 2*a)^2), x) - 2*(d*cos(2 *(b + d)*x + 2*a + 2*c)^2 - 2*d*cos(2*(b + d)*x + 2*a + 2*c)*cos(2*b*x + 2 *a) + d*cos(2*b*x + 2*a)^2 + d*sin(2*(b + d)*x + 2*a + 2*c)^2 - 2*d*sin(2* (b + d)*x + 2*a + 2*c)*sin(2*b*x + 2*a) + d*sin(2*b*x + 2*a)^2)*integrate( -1/2*(b*cos(4*b*x + 4*a)*cos(2*b*x + 2*a) - b*sin((2*b + d)*x + 2*a + c)*s in(4*b*x + 4*a) + b*sin(4*b*x + 4*a)*sin(2*b*x + 2*a) - (b*cos(4*b*x + 4*a ) - b)*cos((2*b + d)*x + 2*a + c) - b*cos(2*b*x + 2*a))/(d*cos((2*b + d)*x + 2*a + c)^2 - 2*d*cos((2*b + d)*x + 2*a + c)*cos(2*b*x + 2*a) + d*cos(2* b*x + 2*a)^2 + d*sin((2*b + d)*x + 2*a + c)^2 - 2*d*sin((2*b + d)*x + 2*a + c)*sin(2*b*x + 2*a) + d*sin(2*b*x + 2*a)^2), x) - (cos(4*b*x + 4*a) - 2* cos(2*b*x + 2*a) + 1)*sin(2*(b + d)*x + 2*a + 2*c) - cos(2*b*x + 2*a)*s...
\[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=\int { \csc \left (d x + c\right )^{2} \sin \left (b x + a\right )^{2} \,d x } \] Input:
integrate(csc(d*x+c)^2*sin(b*x+a)^2,x, algorithm="giac")
Output:
integrate(csc(d*x + c)^2*sin(b*x + a)^2, x)
Timed out. \[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=\int \frac {{\sin \left (a+b\,x\right )}^2}{{\sin \left (c+d\,x\right )}^2} \,d x \] Input:
int(sin(a + b*x)^2/sin(c + d*x)^2,x)
Output:
int(sin(a + b*x)^2/sin(c + d*x)^2, x)
\[ \int \csc ^2(c+d x) \sin ^2(a+b x) \, dx=\int \csc \left (d x +c \right )^{2} \sin \left (b x +a \right )^{2}d x \] Input:
int(csc(d*x+c)^2*sin(b*x+a)^2,x)
Output:
int(csc(c + d*x)**2*sin(a + b*x)**2,x)