Integrand size = 16, antiderivative size = 36 \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=\frac {\cos (a+c) \csc ^2(c-b x)}{2 b}+\frac {\cot (c-b x) \sin (a+c)}{b} \] Output:
1/2*cos(a+c)*csc(b*x-c)^2/b-cot(b*x-c)*sin(a+c)/b
Time = 0.15 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.94 \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=-\frac {\csc (c) \csc ^2(c-b x) (\sin (a)-\cos (c-2 b x) \sin (a+c))}{2 b} \] Input:
Integrate[Cos[a + b*x]*Csc[c - b*x]^3,x]
Output:
-1/2*(Csc[c]*Csc[c - b*x]^2*(Sin[a] - Cos[c - 2*b*x]*Sin[a + c]))/b
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \cos (a+b x) \csc ^3(c-b x) \, dx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int \cos (a+b x) \csc ^3(c-b x)dx\) |
Input:
Int[Cos[a + b*x]*Csc[c - b*x]^3,x]
Output:
$Aborted
Time = 1.80 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.06
method | result | size |
parallelrisch | \(\frac {\sec \left (\frac {b x}{2}-\frac {c}{2}\right )^{2} \csc \left (\frac {b x}{2}-\frac {c}{2}\right )^{2} \cos \left (2 b x +a -c \right )}{8 b}\) | \(38\) |
default | \(\frac {1}{2 b \left (\cos \left (a \right ) \cos \left (c \right )-\sin \left (a \right ) \sin \left (c \right )\right ) \left (\tan \left (b x +a \right ) \cos \left (a \right ) \cos \left (c \right )-\tan \left (b x +a \right ) \sin \left (a \right ) \sin \left (c \right )-\sin \left (a \right ) \cos \left (c \right )-\cos \left (a \right ) \sin \left (c \right )\right )^{2}}\) | \(58\) |
risch | \(\frac {{\mathrm e}^{5 i \left (a +c \right )}-2 \,{\mathrm e}^{i \left (2 b x +5 a +3 c \right )}-{\mathrm e}^{3 i \left (a +c \right )}}{\left ({\mathrm e}^{2 i \left (a +c \right )}-{\mathrm e}^{2 i \left (b x +a \right )}\right )^{2} b}\) | \(60\) |
Input:
int(-cos(b*x+a)*csc(b*x-c)^3,x,method=_RETURNVERBOSE)
Output:
1/8/b*sec(1/2*b*x-1/2*c)^2*csc(1/2*b*x-1/2*c)^2*cos(2*b*x+a-c)
Leaf count of result is larger than twice the leaf count of optimal. 123 vs. \(2 (37) = 74\).
Time = 0.08 (sec) , antiderivative size = 123, normalized size of antiderivative = 3.42 \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=\frac {2 \, {\left (2 \, \cos \left (a + c\right )^{2} - 1\right )} \cos \left (b x + a\right ) \sin \left (b x + a\right ) \sin \left (a + c\right ) + 4 \, {\left (\cos \left (a + c\right )^{3} - \cos \left (a + c\right )\right )} \cos \left (b x + a\right )^{2} - 2 \, \cos \left (a + c\right )^{3} + \cos \left (a + c\right )}{2 \, {\left (2 \, b \cos \left (b x + a\right ) \cos \left (a + c\right ) \sin \left (b x + a\right ) \sin \left (a + c\right ) + {\left (2 \, b \cos \left (a + c\right )^{2} - b\right )} \cos \left (b x + a\right )^{2} - b \cos \left (a + c\right )^{2}\right )}} \] Input:
integrate(-cos(b*x+a)*csc(b*x-c)^3,x, algorithm="fricas")
Output:
1/2*(2*(2*cos(a + c)^2 - 1)*cos(b*x + a)*sin(b*x + a)*sin(a + c) + 4*(cos( a + c)^3 - cos(a + c))*cos(b*x + a)^2 - 2*cos(a + c)^3 + cos(a + c))/(2*b* cos(b*x + a)*cos(a + c)*sin(b*x + a)*sin(a + c) + (2*b*cos(a + c)^2 - b)*c os(b*x + a)^2 - b*cos(a + c)^2)
Timed out. \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=\text {Timed out} \] Input:
integrate(-cos(b*x+a)*csc(b*x-c)**3,x)
Output:
Timed out
Leaf count of result is larger than twice the leaf count of optimal. 432 vs. \(2 (37) = 74\).
Time = 0.04 (sec) , antiderivative size = 432, normalized size of antiderivative = 12.00 \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=-\frac {{\left (2 \, \cos \left (2 \, b x + 2 \, a + 3 \, c\right ) - \cos \left (2 \, a + 5 \, c\right ) + \cos \left (3 \, c\right )\right )} \cos \left (4 \, b x + a\right ) - 2 \, {\left (2 \, \cos \left (2 \, b x + a + 2 \, c\right ) - \cos \left (a + 4 \, c\right )\right )} \cos \left (2 \, b x + 2 \, a + 3 \, c\right ) + 2 \, {\left (\cos \left (2 \, a + 5 \, c\right ) - \cos \left (3 \, c\right )\right )} \cos \left (2 \, b x + a + 2 \, c\right ) - \cos \left (2 \, a + 5 \, c\right ) \cos \left (a + 4 \, c\right ) + \cos \left (a + 4 \, c\right ) \cos \left (3 \, c\right ) + {\left (2 \, \sin \left (2 \, b x + 2 \, a + 3 \, c\right ) - \sin \left (2 \, a + 5 \, c\right ) + \sin \left (3 \, c\right )\right )} \sin \left (4 \, b x + a\right ) - 2 \, {\left (2 \, \sin \left (2 \, b x + a + 2 \, c\right ) - \sin \left (a + 4 \, c\right )\right )} \sin \left (2 \, b x + 2 \, a + 3 \, c\right ) + 2 \, {\left (\sin \left (2 \, a + 5 \, c\right ) - \sin \left (3 \, c\right )\right )} \sin \left (2 \, b x + a + 2 \, c\right ) - \sin \left (2 \, a + 5 \, c\right ) \sin \left (a + 4 \, c\right ) + \sin \left (a + 4 \, c\right ) \sin \left (3 \, c\right )}{b \cos \left (4 \, b x + a\right )^{2} + 4 \, b \cos \left (2 \, b x + a + 2 \, c\right )^{2} - 4 \, b \cos \left (2 \, b x + a + 2 \, c\right ) \cos \left (a + 4 \, c\right ) + b \cos \left (a + 4 \, c\right )^{2} + b \sin \left (4 \, b x + a\right )^{2} + 4 \, b \sin \left (2 \, b x + a + 2 \, c\right )^{2} - 4 \, b \sin \left (2 \, b x + a + 2 \, c\right ) \sin \left (a + 4 \, c\right ) + b \sin \left (a + 4 \, c\right )^{2} - 2 \, {\left (2 \, b \cos \left (2 \, b x + a + 2 \, c\right ) - b \cos \left (a + 4 \, c\right )\right )} \cos \left (4 \, b x + a\right ) - 2 \, {\left (2 \, b \sin \left (2 \, b x + a + 2 \, c\right ) - b \sin \left (a + 4 \, c\right )\right )} \sin \left (4 \, b x + a\right )} \] Input:
integrate(-cos(b*x+a)*csc(b*x-c)^3,x, algorithm="maxima")
Output:
-((2*cos(2*b*x + 2*a + 3*c) - cos(2*a + 5*c) + cos(3*c))*cos(4*b*x + a) - 2*(2*cos(2*b*x + a + 2*c) - cos(a + 4*c))*cos(2*b*x + 2*a + 3*c) + 2*(cos( 2*a + 5*c) - cos(3*c))*cos(2*b*x + a + 2*c) - cos(2*a + 5*c)*cos(a + 4*c) + cos(a + 4*c)*cos(3*c) + (2*sin(2*b*x + 2*a + 3*c) - sin(2*a + 5*c) + sin (3*c))*sin(4*b*x + a) - 2*(2*sin(2*b*x + a + 2*c) - sin(a + 4*c))*sin(2*b* x + 2*a + 3*c) + 2*(sin(2*a + 5*c) - sin(3*c))*sin(2*b*x + a + 2*c) - sin( 2*a + 5*c)*sin(a + 4*c) + sin(a + 4*c)*sin(3*c))/(b*cos(4*b*x + a)^2 + 4*b *cos(2*b*x + a + 2*c)^2 - 4*b*cos(2*b*x + a + 2*c)*cos(a + 4*c) + b*cos(a + 4*c)^2 + b*sin(4*b*x + a)^2 + 4*b*sin(2*b*x + a + 2*c)^2 - 4*b*sin(2*b*x + a + 2*c)*sin(a + 4*c) + b*sin(a + 4*c)^2 - 2*(2*b*cos(2*b*x + a + 2*c) - b*cos(a + 4*c))*cos(4*b*x + a) - 2*(2*b*sin(2*b*x + a + 2*c) - b*sin(a + 4*c))*sin(4*b*x + a))
Leaf count of result is larger than twice the leaf count of optimal. 327 vs. \(2 (37) = 74\).
Time = 0.16 (sec) , antiderivative size = 327, normalized size of antiderivative = 9.08 \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=\frac {\tan \left (\frac {1}{2} \, a\right )^{6} \tan \left (\frac {1}{2} \, c\right )^{6} + 3 \, \tan \left (\frac {1}{2} \, a\right )^{6} \tan \left (\frac {1}{2} \, c\right )^{4} + 3 \, \tan \left (\frac {1}{2} \, a\right )^{4} \tan \left (\frac {1}{2} \, c\right )^{6} + 3 \, \tan \left (\frac {1}{2} \, a\right )^{6} \tan \left (\frac {1}{2} \, c\right )^{2} + 9 \, \tan \left (\frac {1}{2} \, a\right )^{4} \tan \left (\frac {1}{2} \, c\right )^{4} + 3 \, \tan \left (\frac {1}{2} \, a\right )^{2} \tan \left (\frac {1}{2} \, c\right )^{6} + \tan \left (\frac {1}{2} \, a\right )^{6} + 9 \, \tan \left (\frac {1}{2} \, a\right )^{4} \tan \left (\frac {1}{2} \, c\right )^{2} + 9 \, \tan \left (\frac {1}{2} \, a\right )^{2} \tan \left (\frac {1}{2} \, c\right )^{4} + \tan \left (\frac {1}{2} \, c\right )^{6} + 3 \, \tan \left (\frac {1}{2} \, a\right )^{4} + 9 \, \tan \left (\frac {1}{2} \, a\right )^{2} \tan \left (\frac {1}{2} \, c\right )^{2} + 3 \, \tan \left (\frac {1}{2} \, c\right )^{4} + 3 \, \tan \left (\frac {1}{2} \, a\right )^{2} + 3 \, \tan \left (\frac {1}{2} \, c\right )^{2} + 1}{2 \, {\left (\tan \left (b x + a\right ) \tan \left (\frac {1}{2} \, a\right )^{2} \tan \left (\frac {1}{2} \, c\right )^{2} - \tan \left (b x + a\right ) \tan \left (\frac {1}{2} \, a\right )^{2} - 4 \, \tan \left (b x + a\right ) \tan \left (\frac {1}{2} \, a\right ) \tan \left (\frac {1}{2} \, c\right ) + 2 \, \tan \left (\frac {1}{2} \, a\right )^{2} \tan \left (\frac {1}{2} \, c\right ) - \tan \left (b x + a\right ) \tan \left (\frac {1}{2} \, c\right )^{2} + 2 \, \tan \left (\frac {1}{2} \, a\right ) \tan \left (\frac {1}{2} \, c\right )^{2} + \tan \left (b x + a\right ) - 2 \, \tan \left (\frac {1}{2} \, a\right ) - 2 \, \tan \left (\frac {1}{2} \, c\right )\right )}^{2} {\left (\tan \left (\frac {1}{2} \, a\right )^{2} \tan \left (\frac {1}{2} \, c\right )^{2} - \tan \left (\frac {1}{2} \, a\right )^{2} - 4 \, \tan \left (\frac {1}{2} \, a\right ) \tan \left (\frac {1}{2} \, c\right ) - \tan \left (\frac {1}{2} \, c\right )^{2} + 1\right )} b} \] Input:
integrate(-cos(b*x+a)*csc(b*x-c)^3,x, algorithm="giac")
Output:
1/2*(tan(1/2*a)^6*tan(1/2*c)^6 + 3*tan(1/2*a)^6*tan(1/2*c)^4 + 3*tan(1/2*a )^4*tan(1/2*c)^6 + 3*tan(1/2*a)^6*tan(1/2*c)^2 + 9*tan(1/2*a)^4*tan(1/2*c) ^4 + 3*tan(1/2*a)^2*tan(1/2*c)^6 + tan(1/2*a)^6 + 9*tan(1/2*a)^4*tan(1/2*c )^2 + 9*tan(1/2*a)^2*tan(1/2*c)^4 + tan(1/2*c)^6 + 3*tan(1/2*a)^4 + 9*tan( 1/2*a)^2*tan(1/2*c)^2 + 3*tan(1/2*c)^4 + 3*tan(1/2*a)^2 + 3*tan(1/2*c)^2 + 1)/((tan(b*x + a)*tan(1/2*a)^2*tan(1/2*c)^2 - tan(b*x + a)*tan(1/2*a)^2 - 4*tan(b*x + a)*tan(1/2*a)*tan(1/2*c) + 2*tan(1/2*a)^2*tan(1/2*c) - tan(b* x + a)*tan(1/2*c)^2 + 2*tan(1/2*a)*tan(1/2*c)^2 + tan(b*x + a) - 2*tan(1/2 *a) - 2*tan(1/2*c))^2*(tan(1/2*a)^2*tan(1/2*c)^2 - tan(1/2*a)^2 - 4*tan(1/ 2*a)*tan(1/2*c) - tan(1/2*c)^2 + 1)*b)
Timed out. \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=\text {Hanged} \] Input:
int(cos(a + b*x)/sin(c - b*x)^3,x)
Output:
\text{Hanged}
Time = 0.17 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.31 \[ \int \cos (a+b x) \csc ^3(c-b x) \, dx=\frac {\cos \left (b x -c \right ) \cos \left (b x +a \right )-\sin \left (b x -c \right ) \sin \left (b x +a \right )}{2 \sin \left (b x -c \right )^{2} b} \] Input:
int(-cos(b*x+a)*csc(b*x-c)^3,x)
Output:
(cos(b*x - c)*cos(a + b*x) - sin(b*x - c)*sin(a + b*x))/(2*sin(b*x - c)**2 *b)