Integrand size = 15, antiderivative size = 69 \[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=-\frac {i x^2}{2}+i x^2 \operatorname {Hypergeometric2F1}\left (1,-\frac {i}{b d n},1-\frac {i}{b d n},-e^{2 i a d} \left (c x^n\right )^{2 i b d}\right ) \] Output:
-1/2*I*x^2+I*x^2*hypergeom([1, -I/b/d/n],[1-I/b/d/n],-exp(2*I*a*d)*(c*x^n) ^(2*I*b*d))
Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(146\) vs. \(2(69)=138\).
Time = 4.45 (sec) , antiderivative size = 146, normalized size of antiderivative = 2.12 \[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\frac {x^2 \left (i e^{2 i d \left (a+b \log \left (c x^n\right )\right )} \operatorname {Hypergeometric2F1}\left (1,1-\frac {i}{b d n},2-\frac {i}{b d n},-e^{2 i d \left (a+b \log \left (c x^n\right )\right )}\right )+(-i+b d n) \operatorname {Hypergeometric2F1}\left (1,-\frac {i}{b d n},1-\frac {i}{b d n},-e^{2 i d \left (a+b \log \left (c x^n\right )\right )}\right )\right )}{-2-2 i b d n} \] Input:
Integrate[x*Tan[d*(a + b*Log[c*x^n])],x]
Output:
(x^2*(I*E^((2*I)*d*(a + b*Log[c*x^n]))*Hypergeometric2F1[1, 1 - I/(b*d*n), 2 - I/(b*d*n), -E^((2*I)*d*(a + b*Log[c*x^n]))] + (-I + b*d*n)*Hypergeome tric2F1[1, (-I)/(b*d*n), 1 - I/(b*d*n), -E^((2*I)*d*(a + b*Log[c*x^n]))])) /(-2 - (2*I)*b*d*n)
Time = 0.30 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.52, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {5008, 5006, 959, 888}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx\) |
\(\Big \downarrow \) 5008 |
\(\displaystyle \frac {x^2 \left (c x^n\right )^{-2/n} \int \left (c x^n\right )^{\frac {2}{n}-1} \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )d\left (c x^n\right )}{n}\) |
\(\Big \downarrow \) 5006 |
\(\displaystyle \frac {x^2 \left (c x^n\right )^{-2/n} \int \frac {\left (c x^n\right )^{\frac {2}{n}-1} \left (i-i e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )}{e^{2 i a d} \left (c x^n\right )^{2 i b d}+1}d\left (c x^n\right )}{n}\) |
\(\Big \downarrow \) 959 |
\(\displaystyle \frac {x^2 \left (c x^n\right )^{-2/n} \left (2 i \int \frac {\left (c x^n\right )^{\frac {2}{n}-1}}{e^{2 i a d} \left (c x^n\right )^{2 i b d}+1}d\left (c x^n\right )-\frac {1}{2} i n \left (c x^n\right )^{2/n}\right )}{n}\) |
\(\Big \downarrow \) 888 |
\(\displaystyle \frac {x^2 \left (c x^n\right )^{-2/n} \left (i n \left (c x^n\right )^{2/n} \operatorname {Hypergeometric2F1}\left (1,-\frac {i}{b d n},1-\frac {i}{b d n},-e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )-\frac {1}{2} i n \left (c x^n\right )^{2/n}\right )}{n}\) |
Input:
Int[x*Tan[d*(a + b*Log[c*x^n])],x]
Output:
(x^2*((-1/2*I)*n*(c*x^n)^(2/n) + I*n*(c*x^n)^(2/n)*Hypergeometric2F1[1, (- I)/(b*d*n), 1 - I/(b*d*n), -(E^((2*I)*a*d)*(c*x^n)^((2*I)*b*d))]))/(n*(c*x ^n)^(2/n))
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p *((c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/n, (m + 1)/n + 1 , (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] && !IGtQ[p, 0] && (ILt Q[p, 0] || GtQ[a, 0])
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n _)), x_Symbol] :> Simp[d*(e*x)^(m + 1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p + 1) + 1))), x] - Simp[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m + n*(p + 1) + 1)) Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0] && NeQ[m + n*(p + 1) + 1, 0]
Int[((e_.)*(x_))^(m_.)*Tan[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Int[(e*x)^m*((I - I*E^(2*I*a*d)*x^(2*I*b*d))/(1 + E^(2*I*a*d)*x^(2*I*b*d )))^p, x] /; FreeQ[{a, b, d, e, m, p}, x]
Int[((e_.)*(x_))^(m_.)*Tan[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_ .), x_Symbol] :> Simp[(e*x)^(m + 1)/(e*n*(c*x^n)^((m + 1)/n)) Subst[Int[x ^((m + 1)/n - 1)*Tan[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && (NeQ[c, 1] || NeQ[n, 1])
\[\int x \tan \left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )d x\]
Input:
int(x*tan(d*(a+b*ln(c*x^n))),x)
Output:
int(x*tan(d*(a+b*ln(c*x^n))),x)
\[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int { x \tan \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right ) \,d x } \] Input:
integrate(x*tan(d*(a+b*log(c*x^n))),x, algorithm="fricas")
Output:
integral(x*tan(b*d*log(c*x^n) + a*d), x)
\[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int x \tan {\left (a d + b d \log {\left (c x^{n} \right )} \right )}\, dx \] Input:
integrate(x*tan(d*(a+b*ln(c*x**n))),x)
Output:
Integral(x*tan(a*d + b*d*log(c*x**n)), x)
\[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int { x \tan \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right ) \,d x } \] Input:
integrate(x*tan(d*(a+b*log(c*x^n))),x, algorithm="maxima")
Output:
integrate(x*tan((b*log(c*x^n) + a)*d), x)
\[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int { x \tan \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right ) \,d x } \] Input:
integrate(x*tan(d*(a+b*log(c*x^n))),x, algorithm="giac")
Output:
integrate(x*tan((b*log(c*x^n) + a)*d), x)
Timed out. \[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int x\,\mathrm {tan}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right ) \,d x \] Input:
int(x*tan(d*(a + b*log(c*x^n))),x)
Output:
int(x*tan(d*(a + b*log(c*x^n))), x)
\[ \int x \tan \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int \tan \left (\mathrm {log}\left (x^{n} c \right ) b d +a d \right ) x d x \] Input:
int(x*tan(d*(a+b*log(c*x^n))),x)
Output:
int(tan(log(x**n*c)*b*d + a*d)*x,x)