Integrand size = 15, antiderivative size = 109 \[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=\frac {2 x \sqrt {1+e^{2 i a} \left (c x^n\right )^{2 i b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{4} \left (1-\frac {2 i}{b n}\right ),\frac {1}{4} \left (5-\frac {2 i}{b n}\right ),-e^{2 i a} \left (c x^n\right )^{2 i b}\right ) \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )}}{2+i b n} \] Output:
2*x*(1+exp(2*I*a)*(c*x^n)^(2*I*b))^(1/2)*hypergeom([1/2, 1/4-1/2*I/b/n],[5 /4-1/2*I/b/n],-exp(2*I*a)*(c*x^n)^(2*I*b))*sec(a+b*ln(c*x^n))^(1/2)/(2+I*b *n)
Time = 0.24 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.91 \[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=-\frac {2 i \left (1+e^{2 i \left (a+b \log \left (c x^n\right )\right )}\right ) x \operatorname {Hypergeometric2F1}\left (1,\frac {3}{4}-\frac {i}{2 b n},\frac {5}{4}-\frac {i}{2 b n},-e^{2 i \left (a+b \log \left (c x^n\right )\right )}\right ) \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )}}{-2 i+b n} \] Input:
Integrate[Sqrt[Sec[a + b*Log[c*x^n]]],x]
Output:
((-2*I)*(1 + E^((2*I)*(a + b*Log[c*x^n])))*x*Hypergeometric2F1[1, 3/4 - (I /2)/(b*n), 5/4 - (I/2)/(b*n), -E^((2*I)*(a + b*Log[c*x^n]))]*Sqrt[Sec[a + b*Log[c*x^n]]])/(-2*I + b*n)
Time = 0.30 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {5014, 5018, 888}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx\) |
\(\Big \downarrow \) 5014 |
\(\displaystyle \frac {x \left (c x^n\right )^{-1/n} \int \left (c x^n\right )^{\frac {1}{n}-1} \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )}d\left (c x^n\right )}{n}\) |
\(\Big \downarrow \) 5018 |
\(\displaystyle \frac {x \left (c x^n\right )^{-\frac {1}{n}-\frac {i b}{2}} \sqrt {1+e^{2 i a} \left (c x^n\right )^{2 i b}} \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \int \frac {\left (c x^n\right )^{\frac {i b}{2}+\frac {1}{n}-1}}{\sqrt {e^{2 i a} \left (c x^n\right )^{2 i b}+1}}d\left (c x^n\right )}{n}\) |
\(\Big \downarrow \) 888 |
\(\displaystyle \frac {2 x \sqrt {1+e^{2 i a} \left (c x^n\right )^{2 i b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{4} \left (1-\frac {2 i}{b n}\right ),\frac {1}{4} \left (5-\frac {2 i}{b n}\right ),-e^{2 i a} \left (c x^n\right )^{2 i b}\right ) \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )}}{2+i b n}\) |
Input:
Int[Sqrt[Sec[a + b*Log[c*x^n]]],x]
Output:
(2*x*Sqrt[1 + E^((2*I)*a)*(c*x^n)^((2*I)*b)]*Hypergeometric2F1[1/2, (1 - ( 2*I)/(b*n))/4, (5 - (2*I)/(b*n))/4, -(E^((2*I)*a)*(c*x^n)^((2*I)*b))]*Sqrt [Sec[a + b*Log[c*x^n]]])/(2 + I*b*n)
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p *((c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/n, (m + 1)/n + 1 , (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] && !IGtQ[p, 0] && (ILt Q[p, 0] || GtQ[a, 0])
Int[Sec[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Si mp[x/(n*(c*x^n)^(1/n)) Subst[Int[x^(1/n - 1)*Sec[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[{a, b, c, d, n, p}, x] && (NeQ[c, 1] || NeQ[n, 1])
Int[((e_.)*(x_))^(m_.)*Sec[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Simp[Sec[d*(a + b*Log[x])]^p*((1 + E^(2*I*a*d)*x^(2*I*b*d))^p/x^(I*b*d*p )) Int[(e*x)^m*(x^(I*b*d*p)/(1 + E^(2*I*a*d)*x^(2*I*b*d))^p), x], x] /; F reeQ[{a, b, d, e, m, p}, x] && !IntegerQ[p]
\[\int \sqrt {\sec \left (a +b \ln \left (c \,x^{n}\right )\right )}d x\]
Input:
int(sec(a+b*ln(c*x^n))^(1/2),x)
Output:
int(sec(a+b*ln(c*x^n))^(1/2),x)
Exception generated. \[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=\text {Exception raised: TypeError} \] Input:
integrate(sec(a+b*log(c*x^n))^(1/2),x, algorithm="fricas")
Output:
Exception raised: TypeError >> Error detected within library code: inte grate: implementation incomplete (constant residues)
\[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=\int \sqrt {\sec {\left (a + b \log {\left (c x^{n} \right )} \right )}}\, dx \] Input:
integrate(sec(a+b*ln(c*x**n))**(1/2),x)
Output:
Integral(sqrt(sec(a + b*log(c*x**n))), x)
\[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=\int { \sqrt {\sec \left (b \log \left (c x^{n}\right ) + a\right )} \,d x } \] Input:
integrate(sec(a+b*log(c*x^n))^(1/2),x, algorithm="maxima")
Output:
integrate(sqrt(sec(b*log(c*x^n) + a)), x)
\[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=\int { \sqrt {\sec \left (b \log \left (c x^{n}\right ) + a\right )} \,d x } \] Input:
integrate(sec(a+b*log(c*x^n))^(1/2),x, algorithm="giac")
Output:
integrate(sqrt(sec(b*log(c*x^n) + a)), x)
Timed out. \[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=\int \sqrt {\frac {1}{\cos \left (a+b\,\ln \left (c\,x^n\right )\right )}} \,d x \] Input:
int((1/cos(a + b*log(c*x^n)))^(1/2),x)
Output:
int((1/cos(a + b*log(c*x^n)))^(1/2), x)
\[ \int \sqrt {\sec \left (a+b \log \left (c x^n\right )\right )} \, dx=\sqrt {\sec \left (\mathrm {log}\left (x^{n} c \right ) b +a \right )}\, x -\frac {\left (\int \sqrt {\sec \left (\mathrm {log}\left (x^{n} c \right ) b +a \right )}\, \tan \left (\mathrm {log}\left (x^{n} c \right ) b +a \right )d x \right ) b n}{2} \] Input:
int(sec(a+b*log(c*x^n))^(1/2),x)
Output:
(2*sqrt(sec(log(x**n*c)*b + a))*x - int(sqrt(sec(log(x**n*c)*b + a))*tan(l og(x**n*c)*b + a),x)*b*n)/2