Integrand size = 16, antiderivative size = 147 \[ \int f^{a+c x^2} \cos (d+e x) \, dx=-\frac {e^{-i d+\frac {e^2}{4 c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {i e-2 c x \log (f)}{2 \sqrt {c} \sqrt {\log (f)}}\right )}{4 \sqrt {c} \sqrt {\log (f)}}+\frac {e^{i d+\frac {e^2}{4 c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {i e+2 c x \log (f)}{2 \sqrt {c} \sqrt {\log (f)}}\right )}{4 \sqrt {c} \sqrt {\log (f)}} \] Output:
-1/4*exp(-I*d+1/4*e^2/c/ln(f))*f^a*Pi^(1/2)*erfi(1/2*(I*e-2*c*x*ln(f))/c^( 1/2)/ln(f)^(1/2))/c^(1/2)/ln(f)^(1/2)+1/4*exp(I*d+1/4*e^2/c/ln(f))*f^a*Pi^ (1/2)*erfi(1/2*(I*e+2*c*x*ln(f))/c^(1/2)/ln(f)^(1/2))/c^(1/2)/ln(f)^(1/2)
Time = 0.10 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.79 \[ \int f^{a+c x^2} \cos (d+e x) \, dx=\frac {e^{\frac {e^2}{4 c \log (f)}} f^a \sqrt {\pi } \left (\text {erfi}\left (\frac {-i e+2 c x \log (f)}{2 \sqrt {c} \sqrt {\log (f)}}\right ) (\cos (d)-i \sin (d))+\text {erfi}\left (\frac {i e+2 c x \log (f)}{2 \sqrt {c} \sqrt {\log (f)}}\right ) (\cos (d)+i \sin (d))\right )}{4 \sqrt {c} \sqrt {\log (f)}} \] Input:
Integrate[f^(a + c*x^2)*Cos[d + e*x],x]
Output:
(E^(e^2/(4*c*Log[f]))*f^a*Sqrt[Pi]*(Erfi[((-I)*e + 2*c*x*Log[f])/(2*Sqrt[c ]*Sqrt[Log[f]])]*(Cos[d] - I*Sin[d]) + Erfi[(I*e + 2*c*x*Log[f])/(2*Sqrt[c ]*Sqrt[Log[f]])]*(Cos[d] + I*Sin[d])))/(4*Sqrt[c]*Sqrt[Log[f]])
Time = 0.37 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {4976, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int f^{a+c x^2} \cos (d+e x) \, dx\) |
\(\Big \downarrow \) 4976 |
\(\displaystyle \int \left (\frac {1}{2} e^{-i d-i e x} f^{a+c x^2}+\frac {1}{2} e^{i d+i e x} f^{a+c x^2}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {\sqrt {\pi } f^a e^{\frac {e^2}{4 c \log (f)}+i d} \text {erfi}\left (\frac {2 c x \log (f)+i e}{2 \sqrt {c} \sqrt {\log (f)}}\right )}{4 \sqrt {c} \sqrt {\log (f)}}-\frac {\sqrt {\pi } f^a e^{\frac {e^2}{4 c \log (f)}-i d} \text {erfi}\left (\frac {-2 c x \log (f)+i e}{2 \sqrt {c} \sqrt {\log (f)}}\right )}{4 \sqrt {c} \sqrt {\log (f)}}\) |
Input:
Int[f^(a + c*x^2)*Cos[d + e*x],x]
Output:
-1/4*(E^((-I)*d + e^2/(4*c*Log[f]))*f^a*Sqrt[Pi]*Erfi[(I*e - 2*c*x*Log[f]) /(2*Sqrt[c]*Sqrt[Log[f]])])/(Sqrt[c]*Sqrt[Log[f]]) + (E^(I*d + e^2/(4*c*Lo g[f]))*f^a*Sqrt[Pi]*Erfi[(I*e + 2*c*x*Log[f])/(2*Sqrt[c]*Sqrt[Log[f]])])/( 4*Sqrt[c]*Sqrt[Log[f]])
Int[Cos[v_]^(n_.)*(F_)^(u_), x_Symbol] :> Int[ExpandTrigToExp[F^u, Cos[v]^n , x], x] /; FreeQ[F, x] && (LinearQ[u, x] || PolyQ[u, x, 2]) && (LinearQ[v, x] || PolyQ[v, x, 2]) && IGtQ[n, 0]
Time = 0.53 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.82
method | result | size |
risch | \(\frac {\sqrt {\pi }\, f^{a} {\mathrm e}^{-\frac {4 i d \ln \left (f \right ) c -e^{2}}{4 \ln \left (f \right ) c}} \operatorname {erf}\left (\sqrt {-c \ln \left (f \right )}\, x +\frac {i e}{2 \sqrt {-c \ln \left (f \right )}}\right )}{4 \sqrt {-c \ln \left (f \right )}}-\frac {\sqrt {\pi }\, f^{a} {\mathrm e}^{\frac {4 i d \ln \left (f \right ) c +e^{2}}{4 \ln \left (f \right ) c}} \operatorname {erf}\left (-\sqrt {-c \ln \left (f \right )}\, x +\frac {i e}{2 \sqrt {-c \ln \left (f \right )}}\right )}{4 \sqrt {-c \ln \left (f \right )}}\) | \(121\) |
Input:
int(f^(c*x^2+a)*cos(e*x+d),x,method=_RETURNVERBOSE)
Output:
1/4*Pi^(1/2)*f^a*exp(-1/4*(4*I*d*ln(f)*c-e^2)/ln(f)/c)/(-c*ln(f))^(1/2)*er f((-c*ln(f))^(1/2)*x+1/2*I*e/(-c*ln(f))^(1/2))-1/4*Pi^(1/2)*f^a*exp(1/4*(4 *I*d*ln(f)*c+e^2)/ln(f)/c)/(-c*ln(f))^(1/2)*erf(-(-c*ln(f))^(1/2)*x+1/2*I* e/(-c*ln(f))^(1/2))
Time = 0.08 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.97 \[ \int f^{a+c x^2} \cos (d+e x) \, dx=-\frac {\sqrt {\pi } \sqrt {-c \log \left (f\right )} \operatorname {erf}\left (\frac {{\left (2 \, c x \log \left (f\right ) + i \, e\right )} \sqrt {-c \log \left (f\right )}}{2 \, c \log \left (f\right )}\right ) e^{\left (\frac {4 \, a c \log \left (f\right )^{2} + 4 i \, c d \log \left (f\right ) + e^{2}}{4 \, c \log \left (f\right )}\right )} + \sqrt {\pi } \sqrt {-c \log \left (f\right )} \operatorname {erf}\left (\frac {{\left (2 \, c x \log \left (f\right ) - i \, e\right )} \sqrt {-c \log \left (f\right )}}{2 \, c \log \left (f\right )}\right ) e^{\left (\frac {4 \, a c \log \left (f\right )^{2} - 4 i \, c d \log \left (f\right ) + e^{2}}{4 \, c \log \left (f\right )}\right )}}{4 \, c \log \left (f\right )} \] Input:
integrate(f^(c*x^2+a)*cos(e*x+d),x, algorithm="fricas")
Output:
-1/4*(sqrt(pi)*sqrt(-c*log(f))*erf(1/2*(2*c*x*log(f) + I*e)*sqrt(-c*log(f) )/(c*log(f)))*e^(1/4*(4*a*c*log(f)^2 + 4*I*c*d*log(f) + e^2)/(c*log(f))) + sqrt(pi)*sqrt(-c*log(f))*erf(1/2*(2*c*x*log(f) - I*e)*sqrt(-c*log(f))/(c* log(f)))*e^(1/4*(4*a*c*log(f)^2 - 4*I*c*d*log(f) + e^2)/(c*log(f))))/(c*lo g(f))
\[ \int f^{a+c x^2} \cos (d+e x) \, dx=\int f^{a + c x^{2}} \cos {\left (d + e x \right )}\, dx \] Input:
integrate(f**(c*x**2+a)*cos(e*x+d),x)
Output:
Integral(f**(a + c*x**2)*cos(d + e*x), x)
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.05 (sec) , antiderivative size = 204, normalized size of antiderivative = 1.39 \[ \int f^{a+c x^2} \cos (d+e x) \, dx=-\frac {\sqrt {\pi } {\left (f^{a} {\left (\cos \left (d\right ) - i \, \sin \left (d\right )\right )} \operatorname {erf}\left (x \overline {\sqrt {-c \log \left (f\right )}} + \frac {1}{2} i \, e \overline {\frac {1}{\sqrt {-c \log \left (f\right )}}}\right ) e^{\left (\frac {e^{2}}{4 \, c \log \left (f\right )}\right )} + f^{a} {\left (\cos \left (d\right ) + i \, \sin \left (d\right )\right )} \operatorname {erf}\left (x \overline {\sqrt {-c \log \left (f\right )}} - \frac {1}{2} i \, e \overline {\frac {1}{\sqrt {-c \log \left (f\right )}}}\right ) e^{\left (\frac {e^{2}}{4 \, c \log \left (f\right )}\right )} - f^{a} {\left (\cos \left (d\right ) + i \, \sin \left (d\right )\right )} \operatorname {erf}\left (\frac {2 \, c x \log \left (f\right ) + i \, e}{2 \, \sqrt {-c \log \left (f\right )}}\right ) e^{\left (\frac {e^{2}}{4 \, c \log \left (f\right )}\right )} - f^{a} {\left (\cos \left (d\right ) - i \, \sin \left (d\right )\right )} \operatorname {erf}\left (\frac {2 \, c x \log \left (f\right ) - i \, e}{2 \, \sqrt {-c \log \left (f\right )}}\right ) e^{\left (\frac {e^{2}}{4 \, c \log \left (f\right )}\right )}\right )} \sqrt {-c \log \left (f\right )}}{8 \, c \log \left (f\right )} \] Input:
integrate(f^(c*x^2+a)*cos(e*x+d),x, algorithm="maxima")
Output:
-1/8*sqrt(pi)*(f^a*(cos(d) - I*sin(d))*erf(x*conjugate(sqrt(-c*log(f))) + 1/2*I*e*conjugate(1/sqrt(-c*log(f))))*e^(1/4*e^2/(c*log(f))) + f^a*(cos(d) + I*sin(d))*erf(x*conjugate(sqrt(-c*log(f))) - 1/2*I*e*conjugate(1/sqrt(- c*log(f))))*e^(1/4*e^2/(c*log(f))) - f^a*(cos(d) + I*sin(d))*erf(1/2*(2*c* x*log(f) + I*e)/sqrt(-c*log(f)))*e^(1/4*e^2/(c*log(f))) - f^a*(cos(d) - I* sin(d))*erf(1/2*(2*c*x*log(f) - I*e)/sqrt(-c*log(f)))*e^(1/4*e^2/(c*log(f) )))*sqrt(-c*log(f))/(c*log(f))
\[ \int f^{a+c x^2} \cos (d+e x) \, dx=\int { f^{c x^{2} + a} \cos \left (e x + d\right ) \,d x } \] Input:
integrate(f^(c*x^2+a)*cos(e*x+d),x, algorithm="giac")
Output:
integrate(f^(c*x^2 + a)*cos(e*x + d), x)
Timed out. \[ \int f^{a+c x^2} \cos (d+e x) \, dx=\int f^{c\,x^2+a}\,\cos \left (d+e\,x\right ) \,d x \] Input:
int(f^(a + c*x^2)*cos(d + e*x),x)
Output:
int(f^(a + c*x^2)*cos(d + e*x), x)
\[ \int f^{a+c x^2} \cos (d+e x) \, dx=f^{a} \left (\int f^{c \,x^{2}} \cos \left (e x +d \right )d x \right ) \] Input:
int(f^(c*x^2+a)*cos(e*x+d),x)
Output:
f**a*int(f**(c*x**2)*cos(d + e*x),x)