Integrand size = 26, antiderivative size = 38 \[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\frac {\sqrt {-b x^2} \arcsin \left (\sqrt {1+b x^2}\right )^{1+n}}{b (1+n) x} \] Output:
(-b*x^2)^(1/2)*arcsin((b*x^2+1)^(1/2))^(1+n)/b/(1+n)/x
Time = 0.07 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00 \[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\frac {\sqrt {-b x^2} \arcsin \left (\sqrt {1+b x^2}\right )^{1+n}}{b (1+n) x} \] Input:
Integrate[ArcSin[Sqrt[1 + b*x^2]]^n/Sqrt[1 + b*x^2],x]
Output:
(Sqrt[-(b*x^2)]*ArcSin[Sqrt[1 + b*x^2]]^(1 + n))/(b*(1 + n)*x)
Time = 0.30 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {5333, 5152}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\arcsin \left (\sqrt {b x^2+1}\right )^n}{\sqrt {b x^2+1}} \, dx\) |
\(\Big \downarrow \) 5333 |
\(\displaystyle \frac {\sqrt {-b x^2} \int \frac {\arcsin \left (\sqrt {b x^2+1}\right )^n}{\sqrt {-b x^2}}d\sqrt {b x^2+1}}{b x}\) |
\(\Big \downarrow \) 5152 |
\(\displaystyle \frac {\sqrt {-b x^2} \arcsin \left (\sqrt {b x^2+1}\right )^{n+1}}{b (n+1) x}\) |
Input:
Int[ArcSin[Sqrt[1 + b*x^2]]^n/Sqrt[1 + b*x^2],x]
Output:
(Sqrt[-(b*x^2)]*ArcSin[Sqrt[1 + b*x^2]]^(1 + n))/(b*(1 + n)*x)
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_S ymbol] :> Simp[(1/(b*c*(n + 1)))*Simp[Sqrt[1 - c^2*x^2]/Sqrt[d + e*x^2]]*(a + b*ArcSin[c*x])^(n + 1), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && NeQ[n, -1]
Int[ArcSin[Sqrt[1 + (b_.)*(x_)^2]]^(n_.)/Sqrt[1 + (b_.)*(x_)^2], x_Symbol] :> Simp[Sqrt[(-b)*x^2]/(b*x) Subst[Int[ArcSin[x]^n/Sqrt[1 - x^2], x], x, Sqrt[1 + b*x^2]], x] /; FreeQ[{b, n}, x]
\[\int \frac {\arcsin \left (\sqrt {b \,x^{2}+1}\right )^{n}}{\sqrt {b \,x^{2}+1}}d x\]
Input:
int(arcsin((b*x^2+1)^(1/2))^n/(b*x^2+1)^(1/2),x)
Output:
int(arcsin((b*x^2+1)^(1/2))^n/(b*x^2+1)^(1/2),x)
Time = 0.11 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.08 \[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\frac {\sqrt {-b x^{2}} \arcsin \left (\sqrt {b x^{2} + 1}\right )^{n} \arcsin \left (\sqrt {b x^{2} + 1}\right )}{{\left (b n + b\right )} x} \] Input:
integrate(arcsin((b*x^2+1)^(1/2))^n/(b*x^2+1)^(1/2),x, algorithm="fricas")
Output:
sqrt(-b*x^2)*arcsin(sqrt(b*x^2 + 1))^n*arcsin(sqrt(b*x^2 + 1))/((b*n + b)* x)
\[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\begin {cases} \frac {2 x}{\pi } & \text {for}\: b = 0 \wedge n = -1 \\x \left (\frac {\pi }{2}\right )^{n} & \text {for}\: b = 0 \\\int \frac {1}{\sqrt {b x^{2} + 1} \operatorname {asin}{\left (\sqrt {b x^{2} + 1} \right )}}\, dx & \text {for}\: n = -1 \\\frac {\sqrt {- b x^{2}} \operatorname {asin}{\left (\sqrt {b x^{2} + 1} \right )} \operatorname {asin}^{n}{\left (\sqrt {b x^{2} + 1} \right )}}{b n x + b x} & \text {otherwise} \end {cases} \] Input:
integrate(asin((b*x**2+1)**(1/2))**n/(b*x**2+1)**(1/2),x)
Output:
Piecewise((2*x/pi, Eq(b, 0) & Eq(n, -1)), (x*(pi/2)**n, Eq(b, 0)), (Integr al(1/(sqrt(b*x**2 + 1)*asin(sqrt(b*x**2 + 1))), x), Eq(n, -1)), (sqrt(-b*x **2)*asin(sqrt(b*x**2 + 1))*asin(sqrt(b*x**2 + 1))**n/(b*n*x + b*x), True) )
Exception generated. \[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\text {Exception raised: RuntimeError} \] Input:
integrate(arcsin((b*x^2+1)^(1/2))^n/(b*x^2+1)^(1/2),x, algorithm="maxima")
Output:
Exception raised: RuntimeError >> ECL says: sign: argument cannot be imagi nary; found sqrt(-_SAGE_VAR_b)
Timed out. \[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\text {Timed out} \] Input:
integrate(arcsin((b*x^2+1)^(1/2))^n/(b*x^2+1)^(1/2),x, algorithm="giac")
Output:
Timed out
Timed out. \[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\int \frac {{\mathrm {asin}\left (\sqrt {b\,x^2+1}\right )}^n}{\sqrt {b\,x^2+1}} \,d x \] Input:
int(asin((b*x^2 + 1)^(1/2))^n/(b*x^2 + 1)^(1/2),x)
Output:
int(asin((b*x^2 + 1)^(1/2))^n/(b*x^2 + 1)^(1/2), x)
\[ \int \frac {\arcsin \left (\sqrt {1+b x^2}\right )^n}{\sqrt {1+b x^2}} \, dx=\int \frac {\mathit {asin} \left (\sqrt {b \,x^{2}+1}\right )^{n}}{\sqrt {b \,x^{2}+1}}d x \] Input:
int(asin((b*x^2+1)^(1/2))^n/(b*x^2+1)^(1/2),x)
Output:
int(asin(sqrt(b*x**2 + 1))**n/sqrt(b*x**2 + 1),x)