\(\int x^3 \arcsin (a x)^{5/2} \, dx\) [109]

Optimal result

Integrand size = 12, antiderivative size = 205 \[ \int x^3 \arcsin (a x)^{5/2} \, dx=\frac {225 \sqrt {\arcsin (a x)}}{2048 a^4}-\frac {45 x^2 \sqrt {\arcsin (a x)}}{256 a^2}-\frac {15}{256} x^4 \sqrt {\arcsin (a x)}+\frac {15 x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{32 a}-\frac {3 \arcsin (a x)^{5/2}}{32 a^4}+\frac {1}{4} x^4 \arcsin (a x)^{5/2}+\frac {15 \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arcsin (a x)}\right )}{4096 a^4}-\frac {15 \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arcsin (a x)}}{\sqrt {\pi }}\right )}{256 a^4} \] Output:

225/2048*arcsin(a*x)^(1/2)/a^4-45/256*x^2*arcsin(a*x)^(1/2)/a^2-15/256*x^4 
*arcsin(a*x)^(1/2)+15/64*x*(-a^2*x^2+1)^(1/2)*arcsin(a*x)^(3/2)/a^3+5/32*x 
^3*(-a^2*x^2+1)^(1/2)*arcsin(a*x)^(3/2)/a-3/32*arcsin(a*x)^(5/2)/a^4+1/4*x 
^4*arcsin(a*x)^(5/2)+15/8192*2^(1/2)*Pi^(1/2)*FresnelC(2*2^(1/2)/Pi^(1/2)* 
arcsin(a*x)^(1/2))/a^4-15/256*Pi^(1/2)*FresnelC(2*arcsin(a*x)^(1/2)/Pi^(1/ 
2))/a^4
 

Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 0.02 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.64 \[ \int x^3 \arcsin (a x)^{5/2} \, dx=\frac {i \left (16 \sqrt {2} \sqrt {-i \arcsin (a x)} \Gamma \left (\frac {7}{2},-2 i \arcsin (a x)\right )-16 \sqrt {2} \sqrt {i \arcsin (a x)} \Gamma \left (\frac {7}{2},2 i \arcsin (a x)\right )-\sqrt {-i \arcsin (a x)} \Gamma \left (\frac {7}{2},-4 i \arcsin (a x)\right )+\sqrt {i \arcsin (a x)} \Gamma \left (\frac {7}{2},4 i \arcsin (a x)\right )\right )}{2048 a^4 \sqrt {\arcsin (a x)}} \] Input:

Integrate[x^3*ArcSin[a*x]^(5/2),x]
 

Output:

((I/2048)*(16*Sqrt[2]*Sqrt[(-I)*ArcSin[a*x]]*Gamma[7/2, (-2*I)*ArcSin[a*x] 
] - 16*Sqrt[2]*Sqrt[I*ArcSin[a*x]]*Gamma[7/2, (2*I)*ArcSin[a*x]] - Sqrt[(- 
I)*ArcSin[a*x]]*Gamma[7/2, (-4*I)*ArcSin[a*x]] + Sqrt[I*ArcSin[a*x]]*Gamma 
[7/2, (4*I)*ArcSin[a*x]]))/(a^4*Sqrt[ArcSin[a*x]])
 

Rubi [A] (verified)

Time = 2.00 (sec) , antiderivative size = 272, normalized size of antiderivative = 1.33, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.833, Rules used = {5140, 5210, 5140, 5210, 5140, 5152, 5224, 3042, 3793, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int x^3 \arcsin (a x)^{5/2} \, dx\)

\(\Big \downarrow \) 5140

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \int \frac {x^4 \arcsin (a x)^{3/2}}{\sqrt {1-a^2 x^2}}dx\)

\(\Big \downarrow \) 5210

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \int \frac {x^2 \arcsin (a x)^{3/2}}{\sqrt {1-a^2 x^2}}dx}{4 a^2}+\frac {3 \int x^3 \sqrt {\arcsin (a x)}dx}{8 a}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 5140

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \int \frac {x^2 \arcsin (a x)^{3/2}}{\sqrt {1-a^2 x^2}}dx}{4 a^2}+\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {1}{8} a \int \frac {x^4}{\sqrt {1-a^2 x^2} \sqrt {\arcsin (a x)}}dx\right )}{8 a}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 5210

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \left (\frac {\int \frac {\arcsin (a x)^{3/2}}{\sqrt {1-a^2 x^2}}dx}{2 a^2}+\frac {3 \int x \sqrt {\arcsin (a x)}dx}{4 a}-\frac {x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{2 a^2}\right )}{4 a^2}+\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {1}{8} a \int \frac {x^4}{\sqrt {1-a^2 x^2} \sqrt {\arcsin (a x)}}dx\right )}{8 a}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 5140

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \left (\frac {3 \left (\frac {1}{2} x^2 \sqrt {\arcsin (a x)}-\frac {1}{4} a \int \frac {x^2}{\sqrt {1-a^2 x^2} \sqrt {\arcsin (a x)}}dx\right )}{4 a}+\frac {\int \frac {\arcsin (a x)^{3/2}}{\sqrt {1-a^2 x^2}}dx}{2 a^2}-\frac {x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{2 a^2}\right )}{4 a^2}+\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {1}{8} a \int \frac {x^4}{\sqrt {1-a^2 x^2} \sqrt {\arcsin (a x)}}dx\right )}{8 a}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 5152

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {1}{8} a \int \frac {x^4}{\sqrt {1-a^2 x^2} \sqrt {\arcsin (a x)}}dx\right )}{8 a}+\frac {3 \left (\frac {3 \left (\frac {1}{2} x^2 \sqrt {\arcsin (a x)}-\frac {1}{4} a \int \frac {x^2}{\sqrt {1-a^2 x^2} \sqrt {\arcsin (a x)}}dx\right )}{4 a}+\frac {\arcsin (a x)^{5/2}}{5 a^3}-\frac {x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{2 a^2}\right )}{4 a^2}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 5224

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {\int \frac {a^4 x^4}{\sqrt {\arcsin (a x)}}d\arcsin (a x)}{8 a^4}\right )}{8 a}+\frac {3 \left (\frac {3 \left (\frac {1}{2} x^2 \sqrt {\arcsin (a x)}-\frac {\int \frac {a^2 x^2}{\sqrt {\arcsin (a x)}}d\arcsin (a x)}{4 a^2}\right )}{4 a}+\frac {\arcsin (a x)^{5/2}}{5 a^3}-\frac {x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{2 a^2}\right )}{4 a^2}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {\int \frac {\sin (\arcsin (a x))^4}{\sqrt {\arcsin (a x)}}d\arcsin (a x)}{8 a^4}\right )}{8 a}+\frac {3 \left (\frac {3 \left (\frac {1}{2} x^2 \sqrt {\arcsin (a x)}-\frac {\int \frac {\sin (\arcsin (a x))^2}{\sqrt {\arcsin (a x)}}d\arcsin (a x)}{4 a^2}\right )}{4 a}+\frac {\arcsin (a x)^{5/2}}{5 a^3}-\frac {x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{2 a^2}\right )}{4 a^2}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 3793

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {\int \left (-\frac {\cos (2 \arcsin (a x))}{2 \sqrt {\arcsin (a x)}}+\frac {\cos (4 \arcsin (a x))}{8 \sqrt {\arcsin (a x)}}+\frac {3}{8 \sqrt {\arcsin (a x)}}\right )d\arcsin (a x)}{8 a^4}\right )}{8 a}+\frac {3 \left (\frac {3 \left (\frac {1}{2} x^2 \sqrt {\arcsin (a x)}-\frac {\int \left (\frac {1}{2 \sqrt {\arcsin (a x)}}-\frac {\cos (2 \arcsin (a x))}{2 \sqrt {\arcsin (a x)}}\right )d\arcsin (a x)}{4 a^2}\right )}{4 a}+\frac {\arcsin (a x)^{5/2}}{5 a^3}-\frac {x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{2 a^2}\right )}{4 a^2}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}\right )\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {1}{4} x^4 \arcsin (a x)^{5/2}-\frac {5}{8} a \left (\frac {3 \left (\frac {1}{4} x^4 \sqrt {\arcsin (a x)}-\frac {\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arcsin (a x)}\right )-\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arcsin (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arcsin (a x)}}{8 a^4}\right )}{8 a}-\frac {x^3 \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{4 a^2}+\frac {3 \left (\frac {\arcsin (a x)^{5/2}}{5 a^3}+\frac {3 \left (\frac {1}{2} x^2 \sqrt {\arcsin (a x)}-\frac {\sqrt {\arcsin (a x)}-\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arcsin (a x)}}{\sqrt {\pi }}\right )}{4 a^2}\right )}{4 a}-\frac {x \sqrt {1-a^2 x^2} \arcsin (a x)^{3/2}}{2 a^2}\right )}{4 a^2}\right )\)

Input:

Int[x^3*ArcSin[a*x]^(5/2),x]
 

Output:

(x^4*ArcSin[a*x]^(5/2))/4 - (5*a*(-1/4*(x^3*Sqrt[1 - a^2*x^2]*ArcSin[a*x]^ 
(3/2))/a^2 + (3*((x^4*Sqrt[ArcSin[a*x]])/4 - ((3*Sqrt[ArcSin[a*x]])/4 + (S 
qrt[Pi/2]*FresnelC[2*Sqrt[2/Pi]*Sqrt[ArcSin[a*x]]])/8 - (Sqrt[Pi]*FresnelC 
[(2*Sqrt[ArcSin[a*x]])/Sqrt[Pi]])/2)/(8*a^4)))/(8*a) + (3*(-1/2*(x*Sqrt[1 
- a^2*x^2]*ArcSin[a*x]^(3/2))/a^2 + ArcSin[a*x]^(5/2)/(5*a^3) + (3*((x^2*S 
qrt[ArcSin[a*x]])/2 - (Sqrt[ArcSin[a*x]] - (Sqrt[Pi]*FresnelC[(2*Sqrt[ArcS 
in[a*x]])/Sqrt[Pi]])/2)/(4*a^2)))/(4*a)))/(4*a^2)))/8
 

Defintions of rubi rules used

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3793

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> In 
t[ExpandTrigReduce[(c + d*x)^m, Sin[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f 
, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1]))
 

rule 5140

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[x 
^(m + 1)*((a + b*ArcSin[c*x])^n/(m + 1)), x] - Simp[b*c*(n/(m + 1))   Int[x 
^(m + 1)*((a + b*ArcSin[c*x])^(n - 1)/Sqrt[1 - c^2*x^2]), x], x] /; FreeQ[{ 
a, b, c}, x] && IGtQ[m, 0] && GtQ[n, 0]
 

rule 5152

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_S 
ymbol] :> Simp[(1/(b*c*(n + 1)))*Simp[Sqrt[1 - c^2*x^2]/Sqrt[d + e*x^2]]*(a 
 + b*ArcSin[c*x])^(n + 1), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d 
+ e, 0] && NeQ[n, -1]
 

rule 5210

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_)*((d_) + (e_. 
)*(x_)^2)^(p_), x_Symbol] :> Simp[f*(f*x)^(m - 1)*(d + e*x^2)^(p + 1)*((a + 
 b*ArcSin[c*x])^n/(e*(m + 2*p + 1))), x] + (Simp[f^2*((m - 1)/(c^2*(m + 2*p 
 + 1)))   Int[(f*x)^(m - 2)*(d + e*x^2)^p*(a + b*ArcSin[c*x])^n, x], x] + S 
imp[b*f*(n/(c*(m + 2*p + 1)))*Simp[(d + e*x^2)^p/(1 - c^2*x^2)^p]   Int[(f* 
x)^(m - 1)*(1 - c^2*x^2)^(p + 1/2)*(a + b*ArcSin[c*x])^(n - 1), x], x]) /; 
FreeQ[{a, b, c, d, e, f, p}, x] && EqQ[c^2*d + e, 0] && GtQ[n, 0] && IGtQ[m 
, 1] && NeQ[m + 2*p + 1, 0]
 

rule 5224

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^ 
2)^(p_.), x_Symbol] :> Simp[(1/(b*c^(m + 1)))*Simp[(d + e*x^2)^p/(1 - c^2*x 
^2)^p]   Subst[Int[x^n*Sin[-a/b + x/b]^m*Cos[-a/b + x/b]^(2*p + 1), x], x, 
a + b*ArcSin[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] 
 && IGtQ[2*p + 2, 0] && IGtQ[m, 0]
 

Maple [A] (verified)

Time = 0.10 (sec) , antiderivative size = 154, normalized size of antiderivative = 0.75

method	result	size
default	\(\frac {-1024 \arcsin \left (a x \right )^{\frac {5}{2}} \sqrt {\pi }\, \cos \left (2 \arcsin \left (a x \right )\right )+256 \arcsin \left (a x \right )^{\frac {5}{2}} \sqrt {\pi }\, \cos \left (4 \arcsin \left (a x \right )\right )+1280 \arcsin \left (a x \right )^{\frac {3}{2}} \sqrt {\pi }\, \sin \left (2 \arcsin \left (a x \right )\right )-160 \arcsin \left (a x \right )^{\frac {3}{2}} \sqrt {\pi }\, \sin \left (4 \arcsin \left (a x \right )\right )+15 \pi \sqrt {2}\, \operatorname {FresnelC}\left (\frac {2 \sqrt {2}\, \sqrt {\arcsin \left (a x \right )}}{\sqrt {\pi }}\right )+960 \sqrt {\arcsin \left (a x \right )}\, \sqrt {\pi }\, \cos \left (2 \arcsin \left (a x \right )\right )-60 \sqrt {\arcsin \left (a x \right )}\, \sqrt {\pi }\, \cos \left (4 \arcsin \left (a x \right )\right )-480 \pi \,\operatorname {FresnelC}\left (\frac {2 \sqrt {\arcsin \left (a x \right )}}{\sqrt {\pi }}\right )}{8192 a^{4} \sqrt {\pi }}\)	\(154\)

Input:

int(x^3*arcsin(a*x)^(5/2),x,method=_RETURNVERBOSE)
 

Output:

1/8192/a^4*(-1024*arcsin(a*x)^(5/2)*Pi^(1/2)*cos(2*arcsin(a*x))+256*arcsin 
(a*x)^(5/2)*Pi^(1/2)*cos(4*arcsin(a*x))+1280*arcsin(a*x)^(3/2)*Pi^(1/2)*si 
n(2*arcsin(a*x))-160*arcsin(a*x)^(3/2)*Pi^(1/2)*sin(4*arcsin(a*x))+15*Pi*2 
^(1/2)*FresnelC(2*2^(1/2)/Pi^(1/2)*arcsin(a*x)^(1/2))+960*arcsin(a*x)^(1/2 
)*Pi^(1/2)*cos(2*arcsin(a*x))-60*arcsin(a*x)^(1/2)*Pi^(1/2)*cos(4*arcsin(a 
*x))-480*Pi*FresnelC(2*arcsin(a*x)^(1/2)/Pi^(1/2)))/Pi^(1/2)
 

Fricas [F(-2)]

Exception generated. \[ \int x^3 \arcsin (a x)^{5/2} \, dx=\text {Exception raised: TypeError} \] Input:

integrate(x^3*arcsin(a*x)^(5/2),x, algorithm="fricas")
 

Output:

Exception raised: TypeError >>  Error detected within library code:   inte 
grate: implementation incomplete (constant residues)
 

Sympy [F]

\[ \int x^3 \arcsin (a x)^{5/2} \, dx=\int x^{3} \operatorname {asin}^{\frac {5}{2}}{\left (a x \right )}\, dx \] Input:

integrate(x**3*asin(a*x)**(5/2),x)
 

Output:

Integral(x**3*asin(a*x)**(5/2), x)
 

Maxima [F(-2)]

Exception generated. \[ \int x^3 \arcsin (a x)^{5/2} \, dx=\text {Exception raised: RuntimeError} \] Input:

integrate(x^3*arcsin(a*x)^(5/2),x, algorithm="maxima")
                                                                                    
                                                                                    
 

Output:

Exception raised: RuntimeError >> ECL says: expt: undefined: 0 to a negati 
ve exponent.
 

Giac [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.20 (sec) , antiderivative size = 297, normalized size of antiderivative = 1.45 \[ \int x^3 \arcsin (a x)^{5/2} \, dx=\frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (4 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} - \frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (2 i \, \arcsin \left (a x\right )\right )}}{16 \, a^{4}} - \frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (-2 i \, \arcsin \left (a x\right )\right )}}{16 \, a^{4}} + \frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (-4 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} + \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (4 i \, \arcsin \left (a x\right )\right )}}{512 \, a^{4}} - \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (2 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} + \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (-2 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} - \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (-4 i \, \arcsin \left (a x\right )\right )}}{512 \, a^{4}} - \frac {\left (15 i + 15\right ) \, \sqrt {2} \sqrt {\pi } \operatorname {erf}\left (\left (i - 1\right ) \, \sqrt {2} \sqrt {\arcsin \left (a x\right )}\right )}{32768 \, a^{4}} + \frac {\left (15 i - 15\right ) \, \sqrt {2} \sqrt {\pi } \operatorname {erf}\left (-\left (i + 1\right ) \, \sqrt {2} \sqrt {\arcsin \left (a x\right )}\right )}{32768 \, a^{4}} + \frac {\left (15 i + 15\right ) \, \sqrt {\pi } \operatorname {erf}\left (\left (i - 1\right ) \, \sqrt {\arcsin \left (a x\right )}\right )}{1024 \, a^{4}} - \frac {\left (15 i - 15\right ) \, \sqrt {\pi } \operatorname {erf}\left (-\left (i + 1\right ) \, \sqrt {\arcsin \left (a x\right )}\right )}{1024 \, a^{4}} - \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (4 i \, \arcsin \left (a x\right )\right )}}{4096 \, a^{4}} + \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (2 i \, \arcsin \left (a x\right )\right )}}{256 \, a^{4}} + \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (-2 i \, \arcsin \left (a x\right )\right )}}{256 \, a^{4}} - \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (-4 i \, \arcsin \left (a x\right )\right )}}{4096 \, a^{4}} \] Input:

integrate(x^3*arcsin(a*x)^(5/2),x, algorithm="giac")
 

Output:

1/64*arcsin(a*x)^(5/2)*e^(4*I*arcsin(a*x))/a^4 - 1/16*arcsin(a*x)^(5/2)*e^ 
(2*I*arcsin(a*x))/a^4 - 1/16*arcsin(a*x)^(5/2)*e^(-2*I*arcsin(a*x))/a^4 + 
1/64*arcsin(a*x)^(5/2)*e^(-4*I*arcsin(a*x))/a^4 + 5/512*I*arcsin(a*x)^(3/2 
)*e^(4*I*arcsin(a*x))/a^4 - 5/64*I*arcsin(a*x)^(3/2)*e^(2*I*arcsin(a*x))/a 
^4 + 5/64*I*arcsin(a*x)^(3/2)*e^(-2*I*arcsin(a*x))/a^4 - 5/512*I*arcsin(a* 
x)^(3/2)*e^(-4*I*arcsin(a*x))/a^4 - (15/32768*I + 15/32768)*sqrt(2)*sqrt(p 
i)*erf((I - 1)*sqrt(2)*sqrt(arcsin(a*x)))/a^4 + (15/32768*I - 15/32768)*sq 
rt(2)*sqrt(pi)*erf(-(I + 1)*sqrt(2)*sqrt(arcsin(a*x)))/a^4 + (15/1024*I + 
15/1024)*sqrt(pi)*erf((I - 1)*sqrt(arcsin(a*x)))/a^4 - (15/1024*I - 15/102 
4)*sqrt(pi)*erf(-(I + 1)*sqrt(arcsin(a*x)))/a^4 - 15/4096*sqrt(arcsin(a*x) 
)*e^(4*I*arcsin(a*x))/a^4 + 15/256*sqrt(arcsin(a*x))*e^(2*I*arcsin(a*x))/a 
^4 + 15/256*sqrt(arcsin(a*x))*e^(-2*I*arcsin(a*x))/a^4 - 15/4096*sqrt(arcs 
in(a*x))*e^(-4*I*arcsin(a*x))/a^4
 

Mupad [F(-1)]

Timed out. \[ \int x^3 \arcsin (a x)^{5/2} \, dx=\int x^3\,{\mathrm {asin}\left (a\,x\right )}^{5/2} \,d x \] Input:

int(x^3*asin(a*x)^(5/2),x)
 

Output:

int(x^3*asin(a*x)^(5/2), x)
 

Reduce [F]

\[ \int x^3 \arcsin (a x)^{5/2} \, dx=\int \sqrt {\mathit {asin} \left (a x \right )}\, \mathit {asin} \left (a x \right )^{2} x^{3}d x \] Input:

int(x^3*asin(a*x)^(5/2),x)
 

Output:

int(sqrt(asin(a*x))*asin(a*x)**2*x**3,x)