Integrand size = 20, antiderivative size = 78 \[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=-\frac {c^2 \left (1-a^2 x^2\right )^{5/2}}{a \arcsin (a x)}-\frac {5 c^2 \text {Si}(\arcsin (a x))}{8 a}-\frac {15 c^2 \text {Si}(3 \arcsin (a x))}{16 a}-\frac {5 c^2 \text {Si}(5 \arcsin (a x))}{16 a} \] Output:
-c^2*(-a^2*x^2+1)^(5/2)/a/arcsin(a*x)-5/8*c^2*Si(arcsin(a*x))/a-15/16*c^2* Si(3*arcsin(a*x))/a-5/16*c^2*Si(5*arcsin(a*x))/a
Time = 0.26 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.90 \[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=-\frac {c^2 \left (16 \left (1-a^2 x^2\right )^{5/2}+10 \arcsin (a x) \text {Si}(\arcsin (a x))+15 \arcsin (a x) \text {Si}(3 \arcsin (a x))+5 \arcsin (a x) \text {Si}(5 \arcsin (a x))\right )}{16 a \arcsin (a x)} \] Input:
Integrate[(c - a^2*c*x^2)^2/ArcSin[a*x]^2,x]
Output:
-1/16*(c^2*(16*(1 - a^2*x^2)^(5/2) + 10*ArcSin[a*x]*SinIntegral[ArcSin[a*x ]] + 15*ArcSin[a*x]*SinIntegral[3*ArcSin[a*x]] + 5*ArcSin[a*x]*SinIntegral [5*ArcSin[a*x]]))/(a*ArcSin[a*x])
Time = 0.45 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.88, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {5166, 5224, 4906, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx\) |
\(\Big \downarrow \) 5166 |
\(\displaystyle -5 a c^2 \int \frac {x \left (1-a^2 x^2\right )^{3/2}}{\arcsin (a x)}dx-\frac {c^2 \left (1-a^2 x^2\right )^{5/2}}{a \arcsin (a x)}\) |
\(\Big \downarrow \) 5224 |
\(\displaystyle -\frac {5 c^2 \int \frac {a x \left (1-a^2 x^2\right )^2}{\arcsin (a x)}d\arcsin (a x)}{a}-\frac {c^2 \left (1-a^2 x^2\right )^{5/2}}{a \arcsin (a x)}\) |
\(\Big \downarrow \) 4906 |
\(\displaystyle -\frac {5 c^2 \int \left (\frac {a x}{8 \arcsin (a x)}+\frac {3 \sin (3 \arcsin (a x))}{16 \arcsin (a x)}+\frac {\sin (5 \arcsin (a x))}{16 \arcsin (a x)}\right )d\arcsin (a x)}{a}-\frac {c^2 \left (1-a^2 x^2\right )^{5/2}}{a \arcsin (a x)}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {c^2 \left (1-a^2 x^2\right )^{5/2}}{a \arcsin (a x)}-\frac {5 c^2 \left (\frac {1}{8} \text {Si}(\arcsin (a x))+\frac {3}{16} \text {Si}(3 \arcsin (a x))+\frac {1}{16} \text {Si}(5 \arcsin (a x))\right )}{a}\) |
Input:
Int[(c - a^2*c*x^2)^2/ArcSin[a*x]^2,x]
Output:
-((c^2*(1 - a^2*x^2)^(5/2))/(a*ArcSin[a*x])) - (5*c^2*(SinIntegral[ArcSin[ a*x]]/8 + (3*SinIntegral[3*ArcSin[a*x]])/16 + SinIntegral[5*ArcSin[a*x]]/1 6))/a
Int[Cos[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b _.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin[a + b*x ]^n*Cos[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] && IG tQ[p, 0]
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*((d_) + (e_.)*(x_)^2)^(p_.), x_ Symbol] :> Simp[Sqrt[1 - c^2*x^2]*(d + e*x^2)^p*((a + b*ArcSin[c*x])^(n + 1 )/(b*c*(n + 1))), x] + Simp[c*((2*p + 1)/(b*(n + 1)))*Simp[(d + e*x^2)^p/(1 - c^2*x^2)^p] Int[x*(1 - c^2*x^2)^(p - 1/2)*(a + b*ArcSin[c*x])^(n + 1), x], x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[c^2*d + e, 0] && LtQ[n, -1]
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^ 2)^(p_.), x_Symbol] :> Simp[(1/(b*c^(m + 1)))*Simp[(d + e*x^2)^p/(1 - c^2*x ^2)^p] Subst[Int[x^n*Sin[-a/b + x/b]^m*Cos[-a/b + x/b]^(2*p + 1), x], x, a + b*ArcSin[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && IGtQ[2*p + 2, 0] && IGtQ[m, 0]
Time = 0.07 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.06
method | result | size |
derivativedivides | \(-\frac {c^{2} \left (10 \,\operatorname {Si}\left (\arcsin \left (a x \right )\right ) \arcsin \left (a x \right )+15 \,\operatorname {Si}\left (3 \arcsin \left (a x \right )\right ) \arcsin \left (a x \right )+5 \,\operatorname {Si}\left (5 \arcsin \left (a x \right )\right ) \arcsin \left (a x \right )+10 \sqrt {-a^{2} x^{2}+1}+5 \cos \left (3 \arcsin \left (a x \right )\right )+\cos \left (5 \arcsin \left (a x \right )\right )\right )}{16 a \arcsin \left (a x \right )}\) | \(83\) |
default | \(-\frac {c^{2} \left (10 \,\operatorname {Si}\left (\arcsin \left (a x \right )\right ) \arcsin \left (a x \right )+15 \,\operatorname {Si}\left (3 \arcsin \left (a x \right )\right ) \arcsin \left (a x \right )+5 \,\operatorname {Si}\left (5 \arcsin \left (a x \right )\right ) \arcsin \left (a x \right )+10 \sqrt {-a^{2} x^{2}+1}+5 \cos \left (3 \arcsin \left (a x \right )\right )+\cos \left (5 \arcsin \left (a x \right )\right )\right )}{16 a \arcsin \left (a x \right )}\) | \(83\) |
Input:
int((-a^2*c*x^2+c)^2/arcsin(a*x)^2,x,method=_RETURNVERBOSE)
Output:
-1/16/a*c^2*(10*Si(arcsin(a*x))*arcsin(a*x)+15*Si(3*arcsin(a*x))*arcsin(a* x)+5*Si(5*arcsin(a*x))*arcsin(a*x)+10*(-a^2*x^2+1)^(1/2)+5*cos(3*arcsin(a* x))+cos(5*arcsin(a*x)))/arcsin(a*x)
\[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=\int { \frac {{\left (a^{2} c x^{2} - c\right )}^{2}}{\arcsin \left (a x\right )^{2}} \,d x } \] Input:
integrate((-a^2*c*x^2+c)^2/arcsin(a*x)^2,x, algorithm="fricas")
Output:
integral((a^4*c^2*x^4 - 2*a^2*c^2*x^2 + c^2)/arcsin(a*x)^2, x)
\[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=c^{2} \left (\int \left (- \frac {2 a^{2} x^{2}}{\operatorname {asin}^{2}{\left (a x \right )}}\right )\, dx + \int \frac {a^{4} x^{4}}{\operatorname {asin}^{2}{\left (a x \right )}}\, dx + \int \frac {1}{\operatorname {asin}^{2}{\left (a x \right )}}\, dx\right ) \] Input:
integrate((-a**2*c*x**2+c)**2/asin(a*x)**2,x)
Output:
c**2*(Integral(-2*a**2*x**2/asin(a*x)**2, x) + Integral(a**4*x**4/asin(a*x )**2, x) + Integral(asin(a*x)**(-2), x))
\[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=\int { \frac {{\left (a^{2} c x^{2} - c\right )}^{2}}{\arcsin \left (a x\right )^{2}} \,d x } \] Input:
integrate((-a^2*c*x^2+c)^2/arcsin(a*x)^2,x, algorithm="maxima")
Output:
(a*arctan2(a*x, sqrt(a*x + 1)*sqrt(-a*x + 1))*integrate(5*(a^3*c^2*x^3 - a *c^2*x)*sqrt(a*x + 1)*sqrt(-a*x + 1)/arctan2(a*x, sqrt(a*x + 1)*sqrt(-a*x + 1)), x) - (a^4*c^2*x^4 - 2*a^2*c^2*x^2 + c^2)*sqrt(a*x + 1)*sqrt(-a*x + 1))/(a*arctan2(a*x, sqrt(a*x + 1)*sqrt(-a*x + 1)))
Time = 0.15 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.04 \[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=-\frac {{\left (a^{2} x^{2} - 1\right )}^{2} \sqrt {-a^{2} x^{2} + 1} c^{2}}{a \arcsin \left (a x\right )} - \frac {5 \, c^{2} \operatorname {Si}\left (5 \, \arcsin \left (a x\right )\right )}{16 \, a} - \frac {15 \, c^{2} \operatorname {Si}\left (3 \, \arcsin \left (a x\right )\right )}{16 \, a} - \frac {5 \, c^{2} \operatorname {Si}\left (\arcsin \left (a x\right )\right )}{8 \, a} \] Input:
integrate((-a^2*c*x^2+c)^2/arcsin(a*x)^2,x, algorithm="giac")
Output:
-(a^2*x^2 - 1)^2*sqrt(-a^2*x^2 + 1)*c^2/(a*arcsin(a*x)) - 5/16*c^2*sin_int egral(5*arcsin(a*x))/a - 15/16*c^2*sin_integral(3*arcsin(a*x))/a - 5/8*c^2 *sin_integral(arcsin(a*x))/a
Timed out. \[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=\int \frac {{\left (c-a^2\,c\,x^2\right )}^2}{{\mathrm {asin}\left (a\,x\right )}^2} \,d x \] Input:
int((c - a^2*c*x^2)^2/asin(a*x)^2,x)
Output:
int((c - a^2*c*x^2)^2/asin(a*x)^2, x)
\[ \int \frac {\left (c-a^2 c x^2\right )^2}{\arcsin (a x)^2} \, dx=c^{2} \left (\left (\int \frac {x^{4}}{\mathit {asin} \left (a x \right )^{2}}d x \right ) a^{4}-2 \left (\int \frac {x^{2}}{\mathit {asin} \left (a x \right )^{2}}d x \right ) a^{2}+\int \frac {1}{\mathit {asin} \left (a x \right )^{2}}d x \right ) \] Input:
int((-a^2*c*x^2+c)^2/asin(a*x)^2,x)
Output:
c**2*(int(x**4/asin(a*x)**2,x)*a**4 - 2*int(x**2/asin(a*x)**2,x)*a**2 + in t(1/asin(a*x)**2,x))