Integrand size = 24, antiderivative size = 76 \[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=-i a \arcsin (a x)^2-\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}+2 a \arcsin (a x) \log \left (1-e^{2 i \arcsin (a x)}\right )-i a \operatorname {PolyLog}\left (2,e^{2 i \arcsin (a x)}\right ) \] Output:
-I*a*arcsin(a*x)^2-(-a^2*x^2+1)^(1/2)*arcsin(a*x)^2/x+2*a*arcsin(a*x)*ln(1 -(I*a*x+(-a^2*x^2+1)^(1/2))^2)-I*a*polylog(2,(I*a*x+(-a^2*x^2+1)^(1/2))^2)
Time = 0.21 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.95 \[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=\arcsin (a x) \left (-\frac {\left (i a x+\sqrt {1-a^2 x^2}\right ) \arcsin (a x)}{x}+2 a \log \left (1-e^{2 i \arcsin (a x)}\right )\right )-i a \operatorname {PolyLog}\left (2,e^{2 i \arcsin (a x)}\right ) \] Input:
Integrate[ArcSin[a*x]^2/(x^2*Sqrt[1 - a^2*x^2]),x]
Output:
ArcSin[a*x]*(-(((I*a*x + Sqrt[1 - a^2*x^2])*ArcSin[a*x])/x) + 2*a*Log[1 - E^((2*I)*ArcSin[a*x])]) - I*a*PolyLog[2, E^((2*I)*ArcSin[a*x])]
Time = 0.53 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.16, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {5186, 5136, 3042, 25, 4200, 25, 2620, 2715, 2838}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx\) |
\(\Big \downarrow \) 5186 |
\(\displaystyle 2 a \int \frac {\arcsin (a x)}{x}dx-\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}\) |
\(\Big \downarrow \) 5136 |
\(\displaystyle 2 a \int \frac {\sqrt {1-a^2 x^2} \arcsin (a x)}{a x}d\arcsin (a x)-\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle 2 a \int -\arcsin (a x) \tan \left (\arcsin (a x)+\frac {\pi }{2}\right )d\arcsin (a x)-\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -2 a \int \arcsin (a x) \tan \left (\arcsin (a x)+\frac {\pi }{2}\right )d\arcsin (a x)-\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}\) |
\(\Big \downarrow \) 4200 |
\(\displaystyle -\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}+2 a \left (2 i \int -\frac {e^{2 i \arcsin (a x)} \arcsin (a x)}{1-e^{2 i \arcsin (a x)}}d\arcsin (a x)-\frac {1}{2} i \arcsin (a x)^2\right )\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}+2 a \left (-2 i \int \frac {e^{2 i \arcsin (a x)} \arcsin (a x)}{1-e^{2 i \arcsin (a x)}}d\arcsin (a x)-\frac {1}{2} i \arcsin (a x)^2\right )\) |
\(\Big \downarrow \) 2620 |
\(\displaystyle -\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}+2 a \left (-2 i \left (\frac {1}{2} i \arcsin (a x) \log \left (1-e^{2 i \arcsin (a x)}\right )-\frac {1}{2} i \int \log \left (1-e^{2 i \arcsin (a x)}\right )d\arcsin (a x)\right )-\frac {1}{2} i \arcsin (a x)^2\right )\) |
\(\Big \downarrow \) 2715 |
\(\displaystyle -\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}+2 a \left (-2 i \left (\frac {1}{2} i \arcsin (a x) \log \left (1-e^{2 i \arcsin (a x)}\right )-\frac {1}{4} \int e^{-2 i \arcsin (a x)} \log \left (1-e^{2 i \arcsin (a x)}\right )de^{2 i \arcsin (a x)}\right )-\frac {1}{2} i \arcsin (a x)^2\right )\) |
\(\Big \downarrow \) 2838 |
\(\displaystyle -\frac {\sqrt {1-a^2 x^2} \arcsin (a x)^2}{x}+2 a \left (-2 i \left (\frac {1}{4} \operatorname {PolyLog}\left (2,e^{2 i \arcsin (a x)}\right )+\frac {1}{2} i \arcsin (a x) \log \left (1-e^{2 i \arcsin (a x)}\right )\right )-\frac {1}{2} i \arcsin (a x)^2\right )\) |
Input:
Int[ArcSin[a*x]^2/(x^2*Sqrt[1 - a^2*x^2]),x]
Output:
-((Sqrt[1 - a^2*x^2]*ArcSin[a*x]^2)/x) + 2*a*((-1/2*I)*ArcSin[a*x]^2 - (2* I)*((I/2)*ArcSin[a*x]*Log[1 - E^((2*I)*ArcSin[a*x])] + PolyLog[2, E^((2*I) *ArcSin[a*x])]/4))
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ ((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp [((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si mp[d*(m/(b*f*g*n*Log[F])) Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x )))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Simp[1/(d*e*n*Log[F]) Subst[Int[Log[a + b*x]/x, x], x, (F^(e*(c + d*x) ))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 , (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol ] :> Simp[I*((c + d*x)^(m + 1)/(d*(m + 1))), x] - Simp[2*I Int[(c + d*x)^ m*E^(2*I*k*Pi)*(E^(2*I*(e + f*x))/(1 + E^(2*I*k*Pi)*E^(2*I*(e + f*x)))), x] , x] /; FreeQ[{c, d, e, f}, x] && IntegerQ[4*k] && IGtQ[m, 0]
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/(x_), x_Symbol] :> Subst[Int[( a + b*x)^n*Cot[x], x], x, ArcSin[c*x]] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0]
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_)*((d_) + (e_. )*(x_)^2)^(p_), x_Symbol] :> Simp[(f*x)^(m + 1)*(d + e*x^2)^(p + 1)*((a + b *ArcSin[c*x])^n/(d*f*(m + 1))), x] - Simp[b*c*(n/(f*(m + 1)))*Simp[(d + e*x ^2)^p/(1 - c^2*x^2)^p] Int[(f*x)^(m + 1)*(1 - c^2*x^2)^(p + 1/2)*(a + b*A rcSin[c*x])^(n - 1), x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[c^ 2*d + e, 0] && GtQ[n, 0] && EqQ[m + 2*p + 3, 0] && NeQ[m, -1]
Time = 0.41 (sec) , antiderivative size = 141, normalized size of antiderivative = 1.86
method | result | size |
default | \(\frac {\left (i a x -\sqrt {-a^{2} x^{2}+1}\right ) \arcsin \left (a x \right )^{2}}{x}-2 i a \left (i \arcsin \left (a x \right ) \ln \left (1-i a x -\sqrt {-a^{2} x^{2}+1}\right )+i \arcsin \left (a x \right ) \ln \left (1+i a x +\sqrt {-a^{2} x^{2}+1}\right )+\arcsin \left (a x \right )^{2}+\operatorname {polylog}\left (2, i a x +\sqrt {-a^{2} x^{2}+1}\right )+\operatorname {polylog}\left (2, -i a x -\sqrt {-a^{2} x^{2}+1}\right )\right )\) | \(141\) |
Input:
int(arcsin(a*x)^2/x^2/(-a^2*x^2+1)^(1/2),x,method=_RETURNVERBOSE)
Output:
(I*a*x-(-a^2*x^2+1)^(1/2))*arcsin(a*x)^2/x-2*I*a*(I*arcsin(a*x)*ln(1-I*a*x -(-a^2*x^2+1)^(1/2))+I*arcsin(a*x)*ln(1+I*a*x+(-a^2*x^2+1)^(1/2))+arcsin(a *x)^2+polylog(2,I*a*x+(-a^2*x^2+1)^(1/2))+polylog(2,-I*a*x-(-a^2*x^2+1)^(1 /2)))
\[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=\int { \frac {\arcsin \left (a x\right )^{2}}{\sqrt {-a^{2} x^{2} + 1} x^{2}} \,d x } \] Input:
integrate(arcsin(a*x)^2/x^2/(-a^2*x^2+1)^(1/2),x, algorithm="fricas")
Output:
integral(-sqrt(-a^2*x^2 + 1)*arcsin(a*x)^2/(a^2*x^4 - x^2), x)
\[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=\int \frac {\operatorname {asin}^{2}{\left (a x \right )}}{x^{2} \sqrt {- \left (a x - 1\right ) \left (a x + 1\right )}}\, dx \] Input:
integrate(asin(a*x)**2/x**2/(-a**2*x**2+1)**(1/2),x)
Output:
Integral(asin(a*x)**2/(x**2*sqrt(-(a*x - 1)*(a*x + 1))), x)
\[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=\int { \frac {\arcsin \left (a x\right )^{2}}{\sqrt {-a^{2} x^{2} + 1} x^{2}} \,d x } \] Input:
integrate(arcsin(a*x)^2/x^2/(-a^2*x^2+1)^(1/2),x, algorithm="maxima")
Output:
-(sqrt(a*x + 1)*sqrt(-a*x + 1)*arctan2(a*x, sqrt(a*x + 1)*sqrt(-a*x + 1))^ 2 - 2*a*x*integrate(arctan2(a*x, sqrt(a*x + 1)*sqrt(-a*x + 1))/x, x))/x
\[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=\int { \frac {\arcsin \left (a x\right )^{2}}{\sqrt {-a^{2} x^{2} + 1} x^{2}} \,d x } \] Input:
integrate(arcsin(a*x)^2/x^2/(-a^2*x^2+1)^(1/2),x, algorithm="giac")
Output:
integrate(arcsin(a*x)^2/(sqrt(-a^2*x^2 + 1)*x^2), x)
Timed out. \[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=\int \frac {{\mathrm {asin}\left (a\,x\right )}^2}{x^2\,\sqrt {1-a^2\,x^2}} \,d x \] Input:
int(asin(a*x)^2/(x^2*(1 - a^2*x^2)^(1/2)),x)
Output:
int(asin(a*x)^2/(x^2*(1 - a^2*x^2)^(1/2)), x)
\[ \int \frac {\arcsin (a x)^2}{x^2 \sqrt {1-a^2 x^2}} \, dx=\int \frac {\mathit {asin} \left (a x \right )^{2}}{\sqrt {-a^{2} x^{2}+1}\, x^{2}}d x \] Input:
int(asin(a*x)^2/x^2/(-a^2*x^2+1)^(1/2),x)
Output:
int(asin(a*x)**2/(sqrt( - a**2*x**2 + 1)*x**2),x)