Integrand size = 32, antiderivative size = 191 \[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=-\frac {2 b^2 e \left (1-c^2 x^2\right )}{c \sqrt {d+c d x} \sqrt {e-c e x}}-\frac {2 b e x \sqrt {1-c^2 x^2} (a+b \arcsin (c x))}{\sqrt {d+c d x} \sqrt {e-c e x}}+\frac {e \left (1-c^2 x^2\right ) (a+b \arcsin (c x))^2}{c \sqrt {d+c d x} \sqrt {e-c e x}}+\frac {e \sqrt {1-c^2 x^2} (a+b \arcsin (c x))^3}{3 b c \sqrt {d+c d x} \sqrt {e-c e x}} \] Output:
-2*b^2*e*(-c^2*x^2+1)/c/(c*d*x+d)^(1/2)/(-c*e*x+e)^(1/2)-2*b*e*x*(-c^2*x^2 +1)^(1/2)*(a+b*arcsin(c*x))/(c*d*x+d)^(1/2)/(-c*e*x+e)^(1/2)+e*(-c^2*x^2+1 )*(a+b*arcsin(c*x))^2/c/(c*d*x+d)^(1/2)/(-c*e*x+e)^(1/2)+1/3*e*(-c^2*x^2+1 )^(1/2)*(a+b*arcsin(c*x))^3/b/c/(c*d*x+d)^(1/2)/(-c*e*x+e)^(1/2)
Time = 2.19 (sec) , antiderivative size = 296, normalized size of antiderivative = 1.55 \[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=\frac {3 \sqrt {d+c d x} \sqrt {e-c e x} \left (-2 a b c x+a^2 \sqrt {1-c^2 x^2}-2 b^2 \sqrt {1-c^2 x^2}\right )-6 b \sqrt {d+c d x} \sqrt {e-c e x} \left (b c x-a \sqrt {1-c^2 x^2}\right ) \arcsin (c x)+3 b \sqrt {d+c d x} \sqrt {e-c e x} \left (a+b \sqrt {1-c^2 x^2}\right ) \arcsin (c x)^2+b^2 \sqrt {d+c d x} \sqrt {e-c e x} \arcsin (c x)^3-3 a^2 \sqrt {d} \sqrt {e} \sqrt {1-c^2 x^2} \arctan \left (\frac {c x \sqrt {d+c d x} \sqrt {e-c e x}}{\sqrt {d} \sqrt {e} \left (-1+c^2 x^2\right )}\right )}{3 c d \sqrt {1-c^2 x^2}} \] Input:
Integrate[(Sqrt[e - c*e*x]*(a + b*ArcSin[c*x])^2)/Sqrt[d + c*d*x],x]
Output:
(3*Sqrt[d + c*d*x]*Sqrt[e - c*e*x]*(-2*a*b*c*x + a^2*Sqrt[1 - c^2*x^2] - 2 *b^2*Sqrt[1 - c^2*x^2]) - 6*b*Sqrt[d + c*d*x]*Sqrt[e - c*e*x]*(b*c*x - a*S qrt[1 - c^2*x^2])*ArcSin[c*x] + 3*b*Sqrt[d + c*d*x]*Sqrt[e - c*e*x]*(a + b *Sqrt[1 - c^2*x^2])*ArcSin[c*x]^2 + b^2*Sqrt[d + c*d*x]*Sqrt[e - c*e*x]*Ar cSin[c*x]^3 - 3*a^2*Sqrt[d]*Sqrt[e]*Sqrt[1 - c^2*x^2]*ArcTan[(c*x*Sqrt[d + c*d*x]*Sqrt[e - c*e*x])/(Sqrt[d]*Sqrt[e]*(-1 + c^2*x^2))])/(3*c*d*Sqrt[1 - c^2*x^2])
Time = 0.77 (sec) , antiderivative size = 123, normalized size of antiderivative = 0.64, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {5178, 27, 5262, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {c d x+d}} \, dx\) |
\(\Big \downarrow \) 5178 |
\(\displaystyle \frac {\sqrt {1-c^2 x^2} \int \frac {e (1-c x) (a+b \arcsin (c x))^2}{\sqrt {1-c^2 x^2}}dx}{\sqrt {c d x+d} \sqrt {e-c e x}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {e \sqrt {1-c^2 x^2} \int \frac {(1-c x) (a+b \arcsin (c x))^2}{\sqrt {1-c^2 x^2}}dx}{\sqrt {c d x+d} \sqrt {e-c e x}}\) |
\(\Big \downarrow \) 5262 |
\(\displaystyle \frac {e \sqrt {1-c^2 x^2} \int \left (\frac {(a+b \arcsin (c x))^2}{\sqrt {1-c^2 x^2}}-\frac {c x (a+b \arcsin (c x))^2}{\sqrt {1-c^2 x^2}}\right )dx}{\sqrt {c d x+d} \sqrt {e-c e x}}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {e \sqrt {1-c^2 x^2} \left (\frac {\sqrt {1-c^2 x^2} (a+b \arcsin (c x))^2}{c}+\frac {(a+b \arcsin (c x))^3}{3 b c}-2 a b x-2 b^2 x \arcsin (c x)-\frac {2 b^2 \sqrt {1-c^2 x^2}}{c}\right )}{\sqrt {c d x+d} \sqrt {e-c e x}}\) |
Input:
Int[(Sqrt[e - c*e*x]*(a + b*ArcSin[c*x])^2)/Sqrt[d + c*d*x],x]
Output:
(e*Sqrt[1 - c^2*x^2]*(-2*a*b*x - (2*b^2*Sqrt[1 - c^2*x^2])/c - 2*b^2*x*Arc Sin[c*x] + (Sqrt[1 - c^2*x^2]*(a + b*ArcSin[c*x])^2)/c + (a + b*ArcSin[c*x ])^3/(3*b*c)))/(Sqrt[d + c*d*x]*Sqrt[e - c*e*x])
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((d_) + (e_.)*(x_))^(p_)*((f_) + (g_.)*(x_))^(q_), x_Symbol] :> Simp[(d + e*x)^q*((f + g*x)^q/(1 - c^2*x^ 2)^q) Int[(d + e*x)^(p - q)*(1 - c^2*x^2)^q*(a + b*ArcSin[c*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && EqQ[e*f + d*g, 0] && EqQ[c^2*d^2 - e^2, 0] && HalfIntegerQ[p, q] && GeQ[p - q, 0]
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.)*((d_ ) + (e_.)*(x_)^2)^(p_), x_Symbol] :> Int[ExpandIntegrand[(d + e*x^2)^p*(a + b*ArcSin[c*x])^n, (f + g*x)^m, x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] & & EqQ[c^2*d + e, 0] && IGtQ[m, 0] && IntegerQ[p + 1/2] && GtQ[d, 0] && IGtQ [n, 0] && (m == 1 || p > 0 || (n == 1 && p > -1) || (m == 2 && p < -2))
Result contains complex when optimal does not.
Time = 2.65 (sec) , antiderivative size = 542, normalized size of antiderivative = 2.84
method | result | size |
default | \(\frac {a^{2} \sqrt {-c x e +e}\, \sqrt {c d x +d}}{c d}+\frac {a^{2} e \sqrt {\left (c d x +d \right ) \left (-c x e +e \right )}\, \arctan \left (\frac {\sqrt {c^{2} d e}\, x}{\sqrt {-c^{2} d \,x^{2} e +d e}}\right )}{\sqrt {-c x e +e}\, \sqrt {c d x +d}\, \sqrt {c^{2} d e}}+b^{2} \left (-\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \sqrt {-c^{2} x^{2}+1}\, \arcsin \left (c x \right )^{3}}{3 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (c^{2} x^{2}-i \sqrt {-c^{2} x^{2}+1}\, c x -1\right ) \left (\arcsin \left (c x \right )^{2}-2+2 i \arcsin \left (c x \right )\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\left (\arcsin \left (c x \right )^{2}-2-2 i \arcsin \left (c x \right )\right ) \sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (i \sqrt {-c^{2} x^{2}+1}\, c x +c^{2} x^{2}-1\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}\right )+2 a b \left (-\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \sqrt {-c^{2} x^{2}+1}\, \arcsin \left (c x \right )^{2}}{2 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (c^{2} x^{2}-i \sqrt {-c^{2} x^{2}+1}\, c x -1\right ) \left (\arcsin \left (c x \right )+i\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\left (\arcsin \left (c x \right )-i\right ) \sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (i \sqrt {-c^{2} x^{2}+1}\, c x +c^{2} x^{2}-1\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}\right )\) | \(542\) |
parts | \(\frac {a^{2} \sqrt {-c x e +e}\, \sqrt {c d x +d}}{c d}+\frac {a^{2} e \sqrt {\left (c d x +d \right ) \left (-c x e +e \right )}\, \arctan \left (\frac {\sqrt {c^{2} d e}\, x}{\sqrt {-c^{2} d \,x^{2} e +d e}}\right )}{\sqrt {-c x e +e}\, \sqrt {c d x +d}\, \sqrt {c^{2} d e}}+b^{2} \left (-\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \sqrt {-c^{2} x^{2}+1}\, \arcsin \left (c x \right )^{3}}{3 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (c^{2} x^{2}-i \sqrt {-c^{2} x^{2}+1}\, c x -1\right ) \left (\arcsin \left (c x \right )^{2}-2+2 i \arcsin \left (c x \right )\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\left (\arcsin \left (c x \right )^{2}-2-2 i \arcsin \left (c x \right )\right ) \sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (i \sqrt {-c^{2} x^{2}+1}\, c x +c^{2} x^{2}-1\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}\right )+2 a b \left (-\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \sqrt {-c^{2} x^{2}+1}\, \arcsin \left (c x \right )^{2}}{2 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (c^{2} x^{2}-i \sqrt {-c^{2} x^{2}+1}\, c x -1\right ) \left (\arcsin \left (c x \right )+i\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}+\frac {\left (\arcsin \left (c x \right )-i\right ) \sqrt {-e \left (c x -1\right )}\, \sqrt {d \left (c x +1\right )}\, \left (i \sqrt {-c^{2} x^{2}+1}\, c x +c^{2} x^{2}-1\right )}{2 \left (c x +1\right ) d c \left (c x -1\right )}\right )\) | \(542\) |
Input:
int((-c*e*x+e)^(1/2)*(a+b*arcsin(c*x))^2/(c*d*x+d)^(1/2),x,method=_RETURNV ERBOSE)
Output:
a^2/c/d*(-c*e*x+e)^(1/2)*(c*d*x+d)^(1/2)+a^2*e*((c*d*x+d)*(-c*e*x+e))^(1/2 )/(-c*e*x+e)^(1/2)/(c*d*x+d)^(1/2)/(c^2*d*e)^(1/2)*arctan((c^2*d*e)^(1/2)* x/(-c^2*d*e*x^2+d*e)^(1/2))+b^2*(-1/3*(-e*(c*x-1))^(1/2)*(d*(c*x+1))^(1/2) *(-c^2*x^2+1)^(1/2)/(c*x+1)/d/c/(c*x-1)*arcsin(c*x)^3+1/2*(-e*(c*x-1))^(1/ 2)*(d*(c*x+1))^(1/2)*(c^2*x^2-I*c*x*(-c^2*x^2+1)^(1/2)-1)*(arcsin(c*x)^2-2 +2*I*arcsin(c*x))/(c*x+1)/d/c/(c*x-1)+1/2*(arcsin(c*x)^2-2-2*I*arcsin(c*x) )*(-e*(c*x-1))^(1/2)*(d*(c*x+1))^(1/2)*(I*(-c^2*x^2+1)^(1/2)*c*x+c^2*x^2-1 )/(c*x+1)/d/c/(c*x-1))+2*a*b*(-1/2*(-e*(c*x-1))^(1/2)*(d*(c*x+1))^(1/2)*(- c^2*x^2+1)^(1/2)/(c*x+1)/d/c/(c*x-1)*arcsin(c*x)^2+1/2*(-e*(c*x-1))^(1/2)* (d*(c*x+1))^(1/2)*(c^2*x^2-I*c*x*(-c^2*x^2+1)^(1/2)-1)*(arcsin(c*x)+I)/(c* x+1)/d/c/(c*x-1)+1/2*(arcsin(c*x)-I)*(-e*(c*x-1))^(1/2)*(d*(c*x+1))^(1/2)* (I*(-c^2*x^2+1)^(1/2)*c*x+c^2*x^2-1)/(c*x+1)/d/c/(c*x-1))
\[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=\int { \frac {\sqrt {-c e x + e} {\left (b \arcsin \left (c x\right ) + a\right )}^{2}}{\sqrt {c d x + d}} \,d x } \] Input:
integrate((-c*e*x+e)^(1/2)*(a+b*arcsin(c*x))^2/(c*d*x+d)^(1/2),x, algorith m="fricas")
Output:
integral((b^2*arcsin(c*x)^2 + 2*a*b*arcsin(c*x) + a^2)*sqrt(-c*e*x + e)/sq rt(c*d*x + d), x)
\[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=\int \frac {\sqrt {- e \left (c x - 1\right )} \left (a + b \operatorname {asin}{\left (c x \right )}\right )^{2}}{\sqrt {d \left (c x + 1\right )}}\, dx \] Input:
integrate((-c*e*x+e)**(1/2)*(a+b*asin(c*x))**2/(c*d*x+d)**(1/2),x)
Output:
Integral(sqrt(-e*(c*x - 1))*(a + b*asin(c*x))**2/sqrt(d*(c*x + 1)), x)
Exception generated. \[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=\text {Exception raised: ValueError} \] Input:
integrate((-c*e*x+e)^(1/2)*(a+b*arcsin(c*x))^2/(c*d*x+d)^(1/2),x, algorith m="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(e>0)', see `assume?` for more de tails)Is e
\[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=\int { \frac {\sqrt {-c e x + e} {\left (b \arcsin \left (c x\right ) + a\right )}^{2}}{\sqrt {c d x + d}} \,d x } \] Input:
integrate((-c*e*x+e)^(1/2)*(a+b*arcsin(c*x))^2/(c*d*x+d)^(1/2),x, algorith m="giac")
Output:
integrate(sqrt(-c*e*x + e)*(b*arcsin(c*x) + a)^2/sqrt(c*d*x + d), x)
Timed out. \[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=\int \frac {{\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )}^2\,\sqrt {e-c\,e\,x}}{\sqrt {d+c\,d\,x}} \,d x \] Input:
int(((a + b*asin(c*x))^2*(e - c*e*x)^(1/2))/(d + c*d*x)^(1/2),x)
Output:
int(((a + b*asin(c*x))^2*(e - c*e*x)^(1/2))/(d + c*d*x)^(1/2), x)
\[ \int \frac {\sqrt {e-c e x} (a+b \arcsin (c x))^2}{\sqrt {d+c d x}} \, dx=\frac {\sqrt {e}\, \left (-2 \mathit {asin} \left (\frac {\sqrt {-c x +1}}{\sqrt {2}}\right ) a^{2}+\sqrt {c x +1}\, \sqrt {-c x +1}\, a^{2}+2 \left (\int \frac {\sqrt {-c x +1}\, \mathit {asin} \left (c x \right )}{\sqrt {c x +1}}d x \right ) a b c +\left (\int \frac {\sqrt {-c x +1}\, \mathit {asin} \left (c x \right )^{2}}{\sqrt {c x +1}}d x \right ) b^{2} c \right )}{\sqrt {d}\, c} \] Input:
int((-c*e*x+e)^(1/2)*(a+b*asin(c*x))^2/(c*d*x+d)^(1/2),x)
Output:
(sqrt(e)*( - 2*asin(sqrt( - c*x + 1)/sqrt(2))*a**2 + sqrt(c*x + 1)*sqrt( - c*x + 1)*a**2 + 2*int((sqrt( - c*x + 1)*asin(c*x))/sqrt(c*x + 1),x)*a*b*c + int((sqrt( - c*x + 1)*asin(c*x)**2)/sqrt(c*x + 1),x)*b**2*c))/(sqrt(d)* c)