Integrand size = 22, antiderivative size = 52 \[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=-2 \arccos (a x) \text {arctanh}\left (e^{i \arccos (a x)}\right )+i \operatorname {PolyLog}\left (2,-e^{i \arccos (a x)}\right )-i \operatorname {PolyLog}\left (2,e^{i \arccos (a x)}\right ) \] Output:
-2*arccos(a*x)*arctanh(a*x+I*(-a^2*x^2+1)^(1/2))+I*polylog(2,-a*x-I*(-a^2* x^2+1)^(1/2))-I*polylog(2,a*x+I*(-a^2*x^2+1)^(1/2))
Time = 0.05 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.08 \[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=i \left (2 \arccos (a x) \arctan \left (e^{i \arccos (a x)}\right )-\operatorname {PolyLog}\left (2,-i e^{i \arccos (a x)}\right )+\operatorname {PolyLog}\left (2,i e^{i \arccos (a x)}\right )\right ) \] Input:
Integrate[ArcCos[a*x]/(x*Sqrt[1 - a^2*x^2]),x]
Output:
I*(2*ArcCos[a*x]*ArcTan[E^(I*ArcCos[a*x])] - PolyLog[2, (-I)*E^(I*ArcCos[a *x])] + PolyLog[2, I*E^(I*ArcCos[a*x])])
Time = 0.40 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.15, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {5219, 3042, 4669, 2715, 2838}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx\) |
\(\Big \downarrow \) 5219 |
\(\displaystyle -\int \frac {\arccos (a x)}{a x}d\arccos (a x)\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\int \arccos (a x) \csc \left (\arccos (a x)+\frac {\pi }{2}\right )d\arccos (a x)\) |
\(\Big \downarrow \) 4669 |
\(\displaystyle \int \log \left (1-i e^{i \arccos (a x)}\right )d\arccos (a x)-\int \log \left (1+i e^{i \arccos (a x)}\right )d\arccos (a x)+2 i \arccos (a x) \arctan \left (e^{i \arccos (a x)}\right )\) |
\(\Big \downarrow \) 2715 |
\(\displaystyle -i \int e^{-i \arccos (a x)} \log \left (1-i e^{i \arccos (a x)}\right )de^{i \arccos (a x)}+i \int e^{-i \arccos (a x)} \log \left (1+i e^{i \arccos (a x)}\right )de^{i \arccos (a x)}+2 i \arccos (a x) \arctan \left (e^{i \arccos (a x)}\right )\) |
\(\Big \downarrow \) 2838 |
\(\displaystyle 2 i \arccos (a x) \arctan \left (e^{i \arccos (a x)}\right )-i \operatorname {PolyLog}\left (2,-i e^{i \arccos (a x)}\right )+i \operatorname {PolyLog}\left (2,i e^{i \arccos (a x)}\right )\) |
Input:
Int[ArcCos[a*x]/(x*Sqrt[1 - a^2*x^2]),x]
Output:
(2*I)*ArcCos[a*x]*ArcTan[E^(I*ArcCos[a*x])] - I*PolyLog[2, (-I)*E^(I*ArcCo s[a*x])] + I*PolyLog[2, I*E^(I*ArcCos[a*x])]
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Simp[1/(d*e*n*Log[F]) Subst[Int[Log[a + b*x]/x, x], x, (F^(e*(c + d*x) ))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 , (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
Int[csc[(e_.) + Pi*(k_.) + (f_.)*(x_)]*((c_.) + (d_.)*(x_))^(m_.), x_Symbol ] :> Simp[-2*(c + d*x)^m*(ArcTanh[E^(I*k*Pi)*E^(I*(e + f*x))]/f), x] + (-Si mp[d*(m/f) Int[(c + d*x)^(m - 1)*Log[1 - E^(I*k*Pi)*E^(I*(e + f*x))], x], x] + Simp[d*(m/f) Int[(c + d*x)^(m - 1)*Log[1 + E^(I*k*Pi)*E^(I*(e + f*x ))], x], x]) /; FreeQ[{c, d, e, f}, x] && IntegerQ[2*k] && IGtQ[m, 0]
Int[(((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_))/Sqrt[(d_) + (e_.)* (x_)^2], x_Symbol] :> Simp[(-(c^(m + 1))^(-1))*Simp[Sqrt[1 - c^2*x^2]/Sqrt[ d + e*x^2]] Subst[Int[(a + b*x)^n*Cos[x]^m, x], x, ArcCos[c*x]], x] /; Fr eeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[n, 0] && IntegerQ[m]
Time = 0.35 (sec) , antiderivative size = 119, normalized size of antiderivative = 2.29
method | result | size |
default | \(\arccos \left (a x \right ) \ln \left (1+i \left (a x +i \sqrt {-a^{2} x^{2}+1}\right )\right )-\arccos \left (a x \right ) \ln \left (1-i \left (a x +i \sqrt {-a^{2} x^{2}+1}\right )\right )-i \operatorname {dilog}\left (1+i \left (a x +i \sqrt {-a^{2} x^{2}+1}\right )\right )+i \operatorname {dilog}\left (1-i \left (a x +i \sqrt {-a^{2} x^{2}+1}\right )\right )\) | \(119\) |
Input:
int(arccos(a*x)/x/(-a^2*x^2+1)^(1/2),x,method=_RETURNVERBOSE)
Output:
arccos(a*x)*ln(1+I*(a*x+I*(-a^2*x^2+1)^(1/2)))-arccos(a*x)*ln(1-I*(a*x+I*( -a^2*x^2+1)^(1/2)))-I*dilog(1+I*(a*x+I*(-a^2*x^2+1)^(1/2)))+I*dilog(1-I*(a *x+I*(-a^2*x^2+1)^(1/2)))
\[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=\int { \frac {\arccos \left (a x\right )}{\sqrt {-a^{2} x^{2} + 1} x} \,d x } \] Input:
integrate(arccos(a*x)/x/(-a^2*x^2+1)^(1/2),x, algorithm="fricas")
Output:
integral(-sqrt(-a^2*x^2 + 1)*arccos(a*x)/(a^2*x^3 - x), x)
\[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=\int \frac {\operatorname {acos}{\left (a x \right )}}{x \sqrt {- \left (a x - 1\right ) \left (a x + 1\right )}}\, dx \] Input:
integrate(acos(a*x)/x/(-a**2*x**2+1)**(1/2),x)
Output:
Integral(acos(a*x)/(x*sqrt(-(a*x - 1)*(a*x + 1))), x)
\[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=\int { \frac {\arccos \left (a x\right )}{\sqrt {-a^{2} x^{2} + 1} x} \,d x } \] Input:
integrate(arccos(a*x)/x/(-a^2*x^2+1)^(1/2),x, algorithm="maxima")
Output:
integrate(arccos(a*x)/(sqrt(-a^2*x^2 + 1)*x), x)
\[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=\int { \frac {\arccos \left (a x\right )}{\sqrt {-a^{2} x^{2} + 1} x} \,d x } \] Input:
integrate(arccos(a*x)/x/(-a^2*x^2+1)^(1/2),x, algorithm="giac")
Output:
integrate(arccos(a*x)/(sqrt(-a^2*x^2 + 1)*x), x)
Timed out. \[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=\int \frac {\mathrm {acos}\left (a\,x\right )}{x\,\sqrt {1-a^2\,x^2}} \,d x \] Input:
int(acos(a*x)/(x*(1 - a^2*x^2)^(1/2)),x)
Output:
int(acos(a*x)/(x*(1 - a^2*x^2)^(1/2)), x)
\[ \int \frac {\arccos (a x)}{x \sqrt {1-a^2 x^2}} \, dx=\int \frac {\mathit {acos} \left (a x \right )}{\sqrt {-a^{2} x^{2}+1}\, x}d x \] Input:
int(acos(a*x)/x/(-a^2*x^2+1)^(1/2),x)
Output:
int(acos(a*x)/(sqrt( - a**2*x**2 + 1)*x),x)