\(\int \arctan (c+(-1-i c) \cot (a+b x)) \, dx\) [71]

Optimal result
Mathematica [B] (warning: unable to verify)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [A] (verification not implemented)
Sympy [F(-2)]
Maxima [B] (verification not implemented)
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 17, antiderivative size = 86 \[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx=-\frac {b x^2}{2}+x \arctan (c-(1+i c) \cot (a+b x))-\frac {1}{2} i x \log \left (1+i c e^{2 i a+2 i b x}\right )-\frac {\operatorname {PolyLog}\left (2,-i c e^{2 i a+2 i b x}\right )}{4 b} \] Output:

-1/2*b*x^2-x*arctan(-c+(1+I*c)*cot(b*x+a))-1/2*I*x*ln(1+I*c*exp(2*I*a+2*I* 
b*x))-1/4*polylog(2,-I*c*exp(2*I*a+2*I*b*x))/b
 

Mathematica [B] (warning: unable to verify)

Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(872\) vs. \(2(86)=172\).

Time = 5.75 (sec) , antiderivative size = 872, normalized size of antiderivative = 10.14 \[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx=x \arctan (c+(-1-i c) \cot (a+b x))+\frac {i x \csc (a+b x) \left (2 b x \log (2 \cos (b x) (\cos (b x)-i \sin (b x)))+i \log \left (\frac {\sec (b x) (\cos (a)-i \sin (a)) ((-i+c) \cos (a+b x)+i (i+c) \sin (a+b x))}{2 c}\right ) \log (1-i \tan (b x))-i \log \left (\frac {1}{2} \sec (b x) (\cos (a)+i \sin (a)) ((1+i c) \cos (a+b x)-(i+c) \sin (a+b x))\right ) \log (1+i \tan (b x))+i \operatorname {PolyLog}(2,-\cos (2 b x)+i \sin (2 b x))+i \operatorname {PolyLog}\left (2,\frac {\sec (b x) ((i+c) \cos (a)+(1+i c) \sin (a)) (\cos (a+b x)-i \sin (a+b x))}{2 c}\right )-i \operatorname {PolyLog}\left (2,\frac {1}{2} (\cos (a)+i \sin (a)) ((i+c) \cos (a)+(1+i c) \sin (a)) (-i+\tan (b x))\right )\right ) (\cos (b x)-i \sin (b x)) (\cos (b x)+i \sin (b x))}{(i+\cot (a+b x)) ((-i+c) \cos (a+b x)+i (i+c) \sin (a+b x)) \left (-2 i b x-\log \left (1-\frac {\sec (b x) ((i+c) \cos (a)+(1+i c) \sin (a)) (\cos (a+b x)-i \sin (a+b x))}{2 c}\right )-\frac {\log (1-i \tan (b x)) ((i+c) \cos (a+b x)+(1+i c) \sin (a+b x))}{(-i+c) \cos (a+b x)+i (i+c) \sin (a+b x)}+\frac {\log (1+i \tan (b x)) ((i+c) \cos (a+b x)+(1+i c) \sin (a+b x))}{(-i+c) \cos (a+b x)+i (i+c) \sin (a+b x)}+\frac {\log \left (\frac {1}{2} \sec (b x) (\cos (a)+i \sin (a)) ((1+i c) \cos (a+b x)-(i+c) \sin (a+b x))\right ) \sec ^2(b x)}{1+i \tan (b x)}-2 b x \tan (b x)-i \log \left (1-\frac {\sec (b x) ((i+c) \cos (a)+(1+i c) \sin (a)) (\cos (a+b x)-i \sin (a+b x))}{2 c}\right ) \tan (b x)+i \log (1-i \tan (b x)) \tan (b x)-i \log (1+i \tan (b x)) \tan (b x)+\frac {i \log \left (1-\frac {1}{2} (\cos (a)+i \sin (a)) ((i+c) \cos (a)+(1+i c) \sin (a)) (-i+\tan (b x))\right ) \sec ^2(b x)}{-i+\tan (b x)}+\frac {i \log \left (\frac {\sec (b x) (\cos (a)-i \sin (a)) ((-i+c) \cos (a+b x)+i (i+c) \sin (a+b x))}{2 c}\right ) \sec ^2(b x)}{i+\tan (b x)}\right )} \] Input:

Integrate[ArcTan[c + (-1 - I*c)*Cot[a + b*x]],x]
 

Output:

x*ArcTan[c + (-1 - I*c)*Cot[a + b*x]] + (I*x*Csc[a + b*x]*(2*b*x*Log[2*Cos 
[b*x]*(Cos[b*x] - I*Sin[b*x])] + I*Log[(Sec[b*x]*(Cos[a] - I*Sin[a])*((-I 
+ c)*Cos[a + b*x] + I*(I + c)*Sin[a + b*x]))/(2*c)]*Log[1 - I*Tan[b*x]] - 
I*Log[(Sec[b*x]*(Cos[a] + I*Sin[a])*((1 + I*c)*Cos[a + b*x] - (I + c)*Sin[ 
a + b*x]))/2]*Log[1 + I*Tan[b*x]] + I*PolyLog[2, -Cos[2*b*x] + I*Sin[2*b*x 
]] + I*PolyLog[2, (Sec[b*x]*((I + c)*Cos[a] + (1 + I*c)*Sin[a])*(Cos[a + b 
*x] - I*Sin[a + b*x]))/(2*c)] - I*PolyLog[2, ((Cos[a] + I*Sin[a])*((I + c) 
*Cos[a] + (1 + I*c)*Sin[a])*(-I + Tan[b*x]))/2])*(Cos[b*x] - I*Sin[b*x])*( 
Cos[b*x] + I*Sin[b*x]))/((I + Cot[a + b*x])*((-I + c)*Cos[a + b*x] + I*(I 
+ c)*Sin[a + b*x])*((-2*I)*b*x - Log[1 - (Sec[b*x]*((I + c)*Cos[a] + (1 + 
I*c)*Sin[a])*(Cos[a + b*x] - I*Sin[a + b*x]))/(2*c)] - (Log[1 - I*Tan[b*x] 
]*((I + c)*Cos[a + b*x] + (1 + I*c)*Sin[a + b*x]))/((-I + c)*Cos[a + b*x] 
+ I*(I + c)*Sin[a + b*x]) + (Log[1 + I*Tan[b*x]]*((I + c)*Cos[a + b*x] + ( 
1 + I*c)*Sin[a + b*x]))/((-I + c)*Cos[a + b*x] + I*(I + c)*Sin[a + b*x]) + 
 (Log[(Sec[b*x]*(Cos[a] + I*Sin[a])*((1 + I*c)*Cos[a + b*x] - (I + c)*Sin[ 
a + b*x]))/2]*Sec[b*x]^2)/(1 + I*Tan[b*x]) - 2*b*x*Tan[b*x] - I*Log[1 - (S 
ec[b*x]*((I + c)*Cos[a] + (1 + I*c)*Sin[a])*(Cos[a + b*x] - I*Sin[a + b*x] 
))/(2*c)]*Tan[b*x] + I*Log[1 - I*Tan[b*x]]*Tan[b*x] - I*Log[1 + I*Tan[b*x] 
]*Tan[b*x] + (I*Log[1 - ((Cos[a] + I*Sin[a])*((I + c)*Cos[a] + (1 + I*c)*S 
in[a])*(-I + Tan[b*x]))/2]*Sec[b*x]^2)/(-I + Tan[b*x]) + (I*Log[(Sec[b*...
 

Rubi [A] (verified)

Time = 0.45 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.26, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {5688, 2615, 2620, 2715, 2838}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx\)

\(\Big \downarrow \) 5688

\(\displaystyle x \arctan (c-(1+i c) \cot (a+b x))-i b \int \frac {x}{i-c e^{2 i a+2 i b x}}dx\)

\(\Big \downarrow \) 2615

\(\displaystyle x \arctan (c-(1+i c) \cot (a+b x))-i b \left (-i c \int \frac {e^{2 i a+2 i b x} x}{i-c e^{2 i a+2 i b x}}dx-\frac {i x^2}{2}\right )\)

\(\Big \downarrow \) 2620

\(\displaystyle x \arctan (c-(1+i c) \cot (a+b x))-i b \left (-i c \left (\frac {i x \log \left (1+i c e^{2 i a+2 i b x}\right )}{2 b c}-\frac {i \int \log \left (i e^{2 i a+2 i b x} c+1\right )dx}{2 b c}\right )-\frac {i x^2}{2}\right )\)

\(\Big \downarrow \) 2715

\(\displaystyle x \arctan (c-(1+i c) \cot (a+b x))-i b \left (-i c \left (\frac {i x \log \left (1+i c e^{2 i a+2 i b x}\right )}{2 b c}-\frac {\int e^{-2 i a-2 i b x} \log \left (i e^{2 i a+2 i b x} c+1\right )de^{2 i a+2 i b x}}{4 b^2 c}\right )-\frac {i x^2}{2}\right )\)

\(\Big \downarrow \) 2838

\(\displaystyle x \arctan (c-(1+i c) \cot (a+b x))-i b \left (-i c \left (\frac {\operatorname {PolyLog}\left (2,-i c e^{2 i a+2 i b x}\right )}{4 b^2 c}+\frac {i x \log \left (1+i c e^{2 i a+2 i b x}\right )}{2 b c}\right )-\frac {i x^2}{2}\right )\)

Input:

Int[ArcTan[c + (-1 - I*c)*Cot[a + b*x]],x]
 

Output:

x*ArcTan[c - (1 + I*c)*Cot[a + b*x]] - I*b*((-1/2*I)*x^2 - I*c*(((I/2)*x*L 
og[1 + I*c*E^((2*I)*a + (2*I)*b*x)])/(b*c) + PolyLog[2, (-I)*c*E^((2*I)*a 
+ (2*I)*b*x)]/(4*b^2*c)))
 

Defintions of rubi rules used

rule 2615
Int[((c_.) + (d_.)*(x_))^(m_.)/((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x 
_))))^(n_.)), x_Symbol] :> Simp[(c + d*x)^(m + 1)/(a*d*(m + 1)), x] - Simp[ 
b/a   Int[(c + d*x)^m*((F^(g*(e + f*x)))^n/(a + b*(F^(g*(e + f*x)))^n)), x] 
, x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
 

rule 2620
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ 
((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp 
[((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si 
mp[d*(m/(b*f*g*n*Log[F]))   Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x 
)))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
 

rule 2715
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] 
:> Simp[1/(d*e*n*Log[F])   Subst[Int[Log[a + b*x]/x, x], x, (F^(e*(c + d*x) 
))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
 

rule 2838
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 
, (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
 

rule 5688
Int[ArcTan[(c_.) + Cot[(a_.) + (b_.)*(x_)]*(d_.)], x_Symbol] :> Simp[x*ArcT 
an[c + d*Cot[a + b*x]], x] - Simp[I*b   Int[x/(c - I*d - c*E^(2*I*a + 2*I*b 
*x)), x], x] /; FreeQ[{a, b, c, d}, x] && EqQ[(c - I*d)^2, -1]
 
Maple [B] (verified)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 624 vs. \(2 (72 ) = 144\).

Time = 1.60 (sec) , antiderivative size = 625, normalized size of antiderivative = 7.27

method result size
derivativedivides \(-\frac {-\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right ) c^{2}}{2 i-2 c}+\frac {2 i \arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right ) c}{2 i-2 c}+\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )}{2 i-2 c}+\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) c^{2}}{2 i-2 c}-\frac {2 i \arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) c}{2 i-2 c}-\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right )}{2 i-2 c}+\left (i c +1\right )^{2} \left (-\frac {\frac {i \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )^{2}}{4}-\frac {i \left (\left (\ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )-\ln \left (-\frac {i \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )}{2}\right )\right ) \ln \left (-\frac {i \left (i-\left (i c +1\right ) \cot \left (b x +a \right )+c \right )}{2}\right )-\operatorname {dilog}\left (-\frac {i \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )}{2}\right )\right )}{2}}{2 \left (i-c \right )}+\frac {-\frac {i \left (\operatorname {dilog}\left (\frac {i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{2 c}\right )+\ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) \ln \left (\frac {i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{2 c}\right )\right )}{2}+\frac {i \left (\operatorname {dilog}\left (\frac {-i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{-2 i+2 c}\right )+\ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) \ln \left (\frac {-i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{-2 i+2 c}\right )\right )}{2}}{2 i-2 c}\right )}{b \left (i c +1\right )}\) \(625\)
default \(-\frac {-\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right ) c^{2}}{2 i-2 c}+\frac {2 i \arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right ) c}{2 i-2 c}+\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )}{2 i-2 c}+\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) c^{2}}{2 i-2 c}-\frac {2 i \arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) c}{2 i-2 c}-\frac {\arctan \left (-c +\left (i c +1\right ) \cot \left (b x +a \right )\right ) \ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right )}{2 i-2 c}+\left (i c +1\right )^{2} \left (-\frac {\frac {i \ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )^{2}}{4}-\frac {i \left (\left (\ln \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )-\ln \left (-\frac {i \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )}{2}\right )\right ) \ln \left (-\frac {i \left (i-\left (i c +1\right ) \cot \left (b x +a \right )+c \right )}{2}\right )-\operatorname {dilog}\left (-\frac {i \left (i+\left (i c +1\right ) \cot \left (b x +a \right )-c \right )}{2}\right )\right )}{2}}{2 \left (i-c \right )}+\frac {-\frac {i \left (\operatorname {dilog}\left (\frac {i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{2 c}\right )+\ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) \ln \left (\frac {i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{2 c}\right )\right )}{2}+\frac {i \left (\operatorname {dilog}\left (\frac {-i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{-2 i+2 c}\right )+\ln \left (-\left (i c +1\right ) \cot \left (b x +a \right )-c +i\right ) \ln \left (\frac {-i-\left (i c +1\right ) \cot \left (b x +a \right )+c}{-2 i+2 c}\right )\right )}{2}}{2 i-2 c}\right )}{b \left (i c +1\right )}\) \(625\)
risch \(\text {Expression too large to display}\) \(1248\)

Input:

int(-arctan(-c-(-1-I*c)*cot(b*x+a)),x,method=_RETURNVERBOSE)
 

Output:

-1/b/(1+I*c)*(-arctan(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(I+(1+I*c)*cot(b* 
x+a)-c)*c^2+2*I*arctan(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(I+(1+I*c)*cot(b 
*x+a)-c)*c+arctan(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(I+(1+I*c)*cot(b*x+a) 
-c)+arctan(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(-(1+I*c)*cot(b*x+a)-c+I)*c^ 
2-2*I*arctan(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(-(1+I*c)*cot(b*x+a)-c+I)* 
c-arctan(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(-(1+I*c)*cot(b*x+a)-c+I)+(1+I 
*c)^2*(-1/2/(I-c)*(1/4*I*ln(I+(1+I*c)*cot(b*x+a)-c)^2-1/2*I*((ln(I+(1+I*c) 
*cot(b*x+a)-c)-ln(-1/2*I*(I+(1+I*c)*cot(b*x+a)-c)))*ln(-1/2*I*(I-(1+I*c)*c 
ot(b*x+a)+c))-dilog(-1/2*I*(I+(1+I*c)*cot(b*x+a)-c))))+1/2/(I-c)*(-1/2*I*( 
dilog(1/2*(I-(1+I*c)*cot(b*x+a)+c)/c)+ln(-(1+I*c)*cot(b*x+a)-c+I)*ln(1/2*( 
I-(1+I*c)*cot(b*x+a)+c)/c))+1/2*I*(dilog((-I-(1+I*c)*cot(b*x+a)+c)/(-2*I+2 
*c))+ln(-(1+I*c)*cot(b*x+a)-c+I)*ln((-I-(1+I*c)*cot(b*x+a)+c)/(-2*I+2*c))) 
)))
 

Fricas [A] (verification not implemented)

Time = 0.08 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.30 \[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx=-\frac {2 \, b^{2} x^{2} - 2 i \, b x \log \left (-\frac {{\left (c e^{\left (2 i \, b x + 2 i \, a\right )} - i\right )} e^{\left (-2 i \, b x - 2 i \, a\right )}}{c - i}\right ) - 2 \, a^{2} + 2 \, {\left (i \, b x + i \, a\right )} \log \left (i \, c e^{\left (2 i \, b x + 2 i \, a\right )} + 1\right ) - 2 i \, a \log \left (\frac {c e^{\left (2 i \, b x + 2 i \, a\right )} - i}{c}\right ) + {\rm Li}_2\left (-i \, c e^{\left (2 i \, b x + 2 i \, a\right )}\right )}{4 \, b} \] Input:

integrate(-arctan(-c-(-1-I*c)*cot(b*x+a)),x, algorithm="fricas")
 

Output:

-1/4*(2*b^2*x^2 - 2*I*b*x*log(-(c*e^(2*I*b*x + 2*I*a) - I)*e^(-2*I*b*x - 2 
*I*a)/(c - I)) - 2*a^2 + 2*(I*b*x + I*a)*log(I*c*e^(2*I*b*x + 2*I*a) + 1) 
- 2*I*a*log((c*e^(2*I*b*x + 2*I*a) - I)/c) + dilog(-I*c*e^(2*I*b*x + 2*I*a 
)))/b
 

Sympy [F(-2)]

Exception generated. \[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx=\text {Exception raised: CoercionFailed} \] Input:

integrate(-atan(-c-(-1-I*c)*cot(b*x+a)),x)
 

Output:

Exception raised: CoercionFailed >> Cannot convert _t0**2*exp(2*I*a) - 1 o 
f type <class 'sympy.core.add.Add'> to QQ_I[b,_t0,exp(I*a)]
 

Maxima [B] (verification not implemented)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 458 vs. \(2 (63) = 126\).

Time = 0.15 (sec) , antiderivative size = 458, normalized size of antiderivative = 5.33 \[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx =\text {Too large to display} \] Input:

integrate(-arctan(-c-(-1-I*c)*cot(b*x+a)),x, algorithm="maxima")
 

Output:

-1/8*((I*c + 1)*(4*I*(b*x + a)*log(-2*(I*c^2 - (c^2 + 1)*tan(b*x + a) + I) 
/(-2*I*c^2 + 2*(c^2 + 1)*tan(b*x + a) - 4*c + 2*I))/(I*c + 1) + I*(4*(b*x 
+ a)*(log(-I*c^2 + (c^2 + 1)*tan(b*x + a) - 2*c + I) - log(-I*c^2 + (c^2 + 
 1)*tan(b*x + a) - I)) - 2*I*log(-I*c^2 + (c^2 + 1)*tan(b*x + a) - 2*c + I 
)*log(-1/2*((I*c - 1)*tan(b*x + a) + c - I)/c + 1) + 2*I*log(-I*c^2 + (c^2 
 + 1)*tan(b*x + a) - 2*c + I)*log(tan(b*x + a) - I) - 2*I*log(-1/2*(c + I) 
*tan(b*x + a) + 1/2*I*c + 1/2)*log(tan(b*x + a) - I) - I*log(tan(b*x + a) 
- I)^2 - 2*I*log(c^2 + 1)*log(I*tan(b*x + a) + 1) + 2*I*log(tan(b*x + a) - 
 I)*log(-1/2*I*tan(b*x + a) + 1/2) + 2*I*log(c^2 + 1)*log(-I*tan(b*x + a) 
+ 1) - 2*I*dilog(1/2*(c + I)*tan(b*x + a) - 1/2*I*c + 1/2) - 2*I*dilog(1/2 
*((I*c - 1)*tan(b*x + a) + c - I)/c) + 2*I*dilog(1/2*I*tan(b*x + a) + 1/2) 
)/(I*c + 1)) - 8*(b*x + a)*arctan(c + (-I*c - 1)/tan(b*x + a)) + 4*(-I*b*x 
 - I*a)*log(-2*(I*c^2 - (c^2 + 1)*tan(b*x + a) + I)/(-2*I*c^2 + 2*(c^2 + 1 
)*tan(b*x + a) - 4*c + 2*I)))/b
 

Giac [F]

\[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx=\int { -\arctan \left (-{\left (-i \, c - 1\right )} \cot \left (b x + a\right ) - c\right ) \,d x } \] Input:

integrate(-arctan(-c-(-1-I*c)*cot(b*x+a)),x, algorithm="giac")
 

Output:

integrate(-arctan(-(-I*c - 1)*cot(b*x + a) - c), x)
 

Mupad [F(-1)]

Timed out. \[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx=\int \mathrm {atan}\left (c-\mathrm {cot}\left (a+b\,x\right )\,\left (1+c\,1{}\mathrm {i}\right )\right ) \,d x \] Input:

int(atan(c - cot(a + b*x)*(c*1i + 1)),x)
 

Output:

int(atan(c - cot(a + b*x)*(c*1i + 1)), x)
 

Reduce [F]

\[ \int \arctan (c+(-1-i c) \cot (a+b x)) \, dx=-\left (\int \mathit {atan} \left (\cot \left (b x +a \right ) c i +\cot \left (b x +a \right )-c \right )d x \right ) \] Input:

int(-atan(-c-(-1-I*c)*cot(b*x+a)),x)
 

Output:

 - int(atan(cot(a + b*x)*c*i + cot(a + b*x) - c),x)