\(\int x \arctan (\sinh (x)) \, dx\) [74]

Optimal result

Integrand size = 5, antiderivative size = 74 \[ \int x \arctan (\sinh (x)) \, dx=-x^2 \arctan \left (e^x\right )+\frac {1}{2} x^2 \arctan (\sinh (x))+i x \operatorname {PolyLog}\left (2,-i e^x\right )-i x \operatorname {PolyLog}\left (2,i e^x\right )-i \operatorname {PolyLog}\left (3,-i e^x\right )+i \operatorname {PolyLog}\left (3,i e^x\right ) \] Output:

-x^2*arctan(exp(x))+1/2*x^2*arctan(sinh(x))+I*x*polylog(2,-I*exp(x))-I*x*p 
olylog(2,I*exp(x))-I*polylog(3,-I*exp(x))+I*polylog(3,I*exp(x))
 

Mathematica [A] (verified)

Time = 0.03 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.26 \[ \int x \arctan (\sinh (x)) \, dx=\frac {1}{2} x^2 \arctan (\sinh (x))-\frac {1}{2} i \left (x^2 \log \left (1-i e^x\right )-x^2 \log \left (1+i e^x\right )-2 x \operatorname {PolyLog}\left (2,-i e^x\right )+2 x \operatorname {PolyLog}\left (2,i e^x\right )+2 \operatorname {PolyLog}\left (3,-i e^x\right )-2 \operatorname {PolyLog}\left (3,i e^x\right )\right ) \] Input:

Integrate[x*ArcTan[Sinh[x]],x]
 

Output:

(x^2*ArcTan[Sinh[x]])/2 - (I/2)*(x^2*Log[1 - I*E^x] - x^2*Log[1 + I*E^x] - 
 2*x*PolyLog[2, (-I)*E^x] + 2*x*PolyLog[2, I*E^x] + 2*PolyLog[3, (-I)*E^x] 
 - 2*PolyLog[3, I*E^x])
 

Rubi [A] (verified)

Time = 0.43 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.04, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.200, Rules used = {5728, 3042, 4668, 3011, 2720, 7143}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int x \arctan (\sinh (x)) \, dx\)

\(\Big \downarrow \) 5728

\(\displaystyle \frac {1}{2} x^2 \arctan (\sinh (x))-\frac {1}{2} \int x^2 \text {sech}(x)dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{2} x^2 \arctan (\sinh (x))-\frac {1}{2} \int x^2 \csc \left (i x+\frac {\pi }{2}\right )dx\)

\(\Big \downarrow \) 4668

\(\displaystyle \frac {1}{2} x^2 \arctan (\sinh (x))+\frac {1}{2} \left (2 i \int x \log \left (1-i e^x\right )dx-2 i \int x \log \left (1+i e^x\right )dx-2 x^2 \arctan \left (e^x\right )\right )\)

\(\Big \downarrow \) 3011

\(\displaystyle \frac {1}{2} x^2 \arctan (\sinh (x))+\frac {1}{2} \left (-2 i \left (\int \operatorname {PolyLog}\left (2,-i e^x\right )dx-x \operatorname {PolyLog}\left (2,-i e^x\right )\right )+2 i \left (\int \operatorname {PolyLog}\left (2,i e^x\right )dx-x \operatorname {PolyLog}\left (2,i e^x\right )\right )-2 x^2 \arctan \left (e^x\right )\right )\)

\(\Big \downarrow \) 2720

\(\displaystyle \frac {1}{2} x^2 \arctan (\sinh (x))+\frac {1}{2} \left (-2 i \left (\int e^{-x} \operatorname {PolyLog}\left (2,-i e^x\right )de^x-x \operatorname {PolyLog}\left (2,-i e^x\right )\right )+2 i \left (\int e^{-x} \operatorname {PolyLog}\left (2,i e^x\right )de^x-x \operatorname {PolyLog}\left (2,i e^x\right )\right )-2 x^2 \arctan \left (e^x\right )\right )\)

\(\Big \downarrow \) 7143

\(\displaystyle \frac {1}{2} x^2 \arctan (\sinh (x))+\frac {1}{2} \left (-2 x^2 \arctan \left (e^x\right )-2 i \left (\operatorname {PolyLog}\left (3,-i e^x\right )-x \operatorname {PolyLog}\left (2,-i e^x\right )\right )+2 i \left (\operatorname {PolyLog}\left (3,i e^x\right )-x \operatorname {PolyLog}\left (2,i e^x\right )\right )\right )\)

Input:

Int[x*ArcTan[Sinh[x]],x]
 

Output:

(x^2*ArcTan[Sinh[x]])/2 + (-2*x^2*ArcTan[E^x] - (2*I)*(-(x*PolyLog[2, (-I) 
*E^x]) + PolyLog[3, (-I)*E^x]) + (2*I)*(-(x*PolyLog[2, I*E^x]) + PolyLog[3 
, I*E^x]))/2
 

Defintions of rubi rules used

rule 2720

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] 
   Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct 
ionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ 
[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) 
*(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
 

rule 3011

Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) 
*(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + 
b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F]))   Int[(f + g*x)^( 
m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e 
, f, g, n}, x] && GtQ[m, 0]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4668

Int[csc[(e_.) + Pi*(k_.) + (Complex[0, fz_])*(f_.)*(x_)]*((c_.) + (d_.)*(x_ 
))^(m_.), x_Symbol] :> Simp[-2*(c + d*x)^m*(ArcTanh[E^((-I)*e + f*fz*x)/E^( 
I*k*Pi)]/(f*fz*I)), x] + (-Simp[d*(m/(f*fz*I))   Int[(c + d*x)^(m - 1)*Log[ 
1 - E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x] + Simp[d*(m/(f*fz*I))   Int[(c 
+ d*x)^(m - 1)*Log[1 + E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x]) /; FreeQ[{c 
, d, e, f, fz}, x] && IntegerQ[2*k] && IGtQ[m, 0]
 

rule 5728

Int[((a_.) + ArcTan[u_]*(b_.))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Sim 
p[(c + d*x)^(m + 1)*((a + b*ArcTan[u])/(d*(m + 1))), x] - Simp[b/(d*(m + 1) 
)   Int[SimplifyIntegrand[(c + d*x)^(m + 1)*(D[u, x]/(1 + u^2)), x], x], x] 
 /; FreeQ[{a, b, c, d, m}, x] && NeQ[m, -1] && InverseFunctionFreeQ[u, x] & 
&  !FunctionOfQ[(c + d*x)^(m + 1), u, x] && FalseQ[PowerVariableExpn[u, m + 
 1, x]]
 

rule 7143

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S 
ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d 
, e, n, p}, x] && EqQ[b*d, a*e]
 

Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 1.30 (sec) , antiderivative size = 632, normalized size of antiderivative = 8.54

method	result	size
risch	\(\text {Expression too large to display}\)	\(632\)

Input:

int(x*arctan(sinh(x)),x,method=_RETURNVERBOSE)
 

Output:

1/2*I*x^2*ln(exp(x)+I)-1/2*I*x^2*ln(exp(x)-I)+1/2*I*x^2*ln(1+I*exp(x))+I*x 
*polylog(2,-I*exp(x))-I*polylog(3,-I*exp(x))-1/8*Pi*(csgn(I*(exp(x)-I))^2* 
csgn(I*(exp(x)-I)^2)-2*csgn(I*(exp(x)-I))*csgn(I*(exp(x)-I)^2)^2+csgn(I*(e 
xp(x)-I)^2)^3+csgn(I*(exp(x)-I)^2)*csgn(I*exp(-x))*csgn(I*exp(-x)*(exp(x)- 
I)^2)-csgn(I*(exp(x)-I)^2)*csgn(I*exp(-x)*(exp(x)-I)^2)^2-csgn(I*(exp(x)+I 
))^2*csgn(I*(exp(x)+I)^2)+2*csgn(I*(exp(x)+I))*csgn(I*(exp(x)+I)^2)^2-csgn 
(I*(exp(x)+I)^2)^3-csgn(I*(exp(x)+I)^2)*csgn(I*exp(-x))*csgn(I*exp(-x)*(ex 
p(x)+I)^2)+csgn(I*(exp(x)+I)^2)*csgn(I*exp(-x)*(exp(x)+I)^2)^2-csgn(I*exp( 
-x))*csgn(I*exp(-x)*(exp(x)-I)^2)^2+csgn(I*exp(-x))*csgn(I*exp(-x)*(exp(x) 
+I)^2)^2-csgn(I*exp(-x)*(exp(x)+I)^2)*csgn(exp(-x)*(exp(x)+I)^2)+csgn(exp( 
-x)*(exp(x)+I)^2)^2+csgn(I*exp(-x)*(exp(x)-I)^2)*csgn(exp(-x)*(exp(x)-I)^2 
)+csgn(exp(-x)*(exp(x)-I)^2)^2+csgn(I*exp(-x)*(exp(x)-I)^2)^3-csgn(I*exp(- 
x)*(exp(x)-I)^2)*csgn(exp(-x)*(exp(x)-I)^2)^2-csgn(I*exp(-x)*(exp(x)+I)^2) 
^3+csgn(I*exp(-x)*(exp(x)+I)^2)*csgn(exp(-x)*(exp(x)+I)^2)^2-csgn(exp(-x)* 
(exp(x)+I)^2)^3-csgn(exp(-x)*(exp(x)-I)^2)^3-2)*x^2-1/2*I*x^2*ln(1-I*exp(x 
))-I*x*polylog(2,I*exp(x))+I*polylog(3,I*exp(x))
 

Fricas [A] (verification not implemented)

Time = 0.11 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.26 \[ \int x \arctan (\sinh (x)) \, dx=\frac {1}{2} \, x^{2} \arctan \left (\sinh \left (x\right )\right ) + \frac {1}{2} i \, x^{2} \log \left (i \, \cosh \left (x\right ) + i \, \sinh \left (x\right ) + 1\right ) - \frac {1}{2} i \, x^{2} \log \left (-i \, \cosh \left (x\right ) - i \, \sinh \left (x\right ) + 1\right ) - i \, x {\rm Li}_2\left (i \, \cosh \left (x\right ) + i \, \sinh \left (x\right )\right ) + i \, x {\rm Li}_2\left (-i \, \cosh \left (x\right ) - i \, \sinh \left (x\right )\right ) + i \, {\rm polylog}\left (3, i \, \cosh \left (x\right ) + i \, \sinh \left (x\right )\right ) - i \, {\rm polylog}\left (3, -i \, \cosh \left (x\right ) - i \, \sinh \left (x\right )\right ) \] Input:

integrate(x*arctan(sinh(x)),x, algorithm="fricas")
 

Output:

1/2*x^2*arctan(sinh(x)) + 1/2*I*x^2*log(I*cosh(x) + I*sinh(x) + 1) - 1/2*I 
*x^2*log(-I*cosh(x) - I*sinh(x) + 1) - I*x*dilog(I*cosh(x) + I*sinh(x)) + 
I*x*dilog(-I*cosh(x) - I*sinh(x)) + I*polylog(3, I*cosh(x) + I*sinh(x)) - 
I*polylog(3, -I*cosh(x) - I*sinh(x))
 

Sympy [F]

\[ \int x \arctan (\sinh (x)) \, dx=\int x \operatorname {atan}{\left (\sinh {\left (x \right )} \right )}\, dx \] Input:

integrate(x*atan(sinh(x)),x)
 

Output:

Integral(x*atan(sinh(x)), x)
 

Maxima [F]

\[ \int x \arctan (\sinh (x)) \, dx=\int { x \arctan \left (\sinh \left (x\right )\right ) \,d x } \] Input:

integrate(x*arctan(sinh(x)),x, algorithm="maxima")
 

Output:

1/2*x^2*arctan(1/2*(e^(2*x) - 1)*e^(-x)) - integrate(x^2*e^x/(e^(2*x) + 1) 
, x)
 

Giac [F]

\[ \int x \arctan (\sinh (x)) \, dx=\int { x \arctan \left (\sinh \left (x\right )\right ) \,d x } \] Input:

integrate(x*arctan(sinh(x)),x, algorithm="giac")
 

Output:

integrate(x*arctan(sinh(x)), x)
 

Mupad [F(-1)]

Timed out. \[ \int x \arctan (\sinh (x)) \, dx=\int x\,\mathrm {atan}\left (\mathrm {sinh}\left (x\right )\right ) \,d x \] Input:

int(x*atan(sinh(x)),x)
 

Output:

int(x*atan(sinh(x)), x)
                                                                                    
                                                                                    
 

Reduce [F]

\[ \int x \arctan (\sinh (x)) \, dx=\int \mathit {atan} \left (\sinh \left (x \right )\right ) x d x \] Input:

int(x*atan(sinh(x)),x)
 

Output:

int(atan(sinh(x))*x,x)