\(\int \frac {\cot ^{-1}(a x)}{(c+d x^2)^2} \, dx\) [6]

Optimal result
Mathematica [A] (warning: unable to verify)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [F]
Sympy [F]
Maxima [A] (verification not implemented)
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 14, antiderivative size = 801 \[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx=\frac {x \cot ^{-1}(a x)}{2 c \left (c+d x^2\right )}+\frac {\cot ^{-1}(a x) \arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )}{2 c^{3/2} \sqrt {d}}-\frac {i a \log \left (\frac {\sqrt {d} \left (1-\sqrt {-a^2} x\right )}{i \sqrt {-a^2} \sqrt {c}+\sqrt {d}}\right ) \log \left (1-\frac {i \sqrt {d} x}{\sqrt {c}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i a \log \left (-\frac {\sqrt {d} \left (1+\sqrt {-a^2} x\right )}{i \sqrt {-a^2} \sqrt {c}-\sqrt {d}}\right ) \log \left (1-\frac {i \sqrt {d} x}{\sqrt {c}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i a \log \left (-\frac {\sqrt {d} \left (1-\sqrt {-a^2} x\right )}{i \sqrt {-a^2} \sqrt {c}-\sqrt {d}}\right ) \log \left (1+\frac {i \sqrt {d} x}{\sqrt {c}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}}-\frac {i a \log \left (\frac {\sqrt {d} \left (1+\sqrt {-a^2} x\right )}{i \sqrt {-a^2} \sqrt {c}+\sqrt {d}}\right ) \log \left (1+\frac {i \sqrt {d} x}{\sqrt {c}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {a \log \left (1+a^2 x^2\right )}{4 c \left (a^2 c-d\right )}-\frac {a \log \left (c+d x^2\right )}{4 c \left (a^2 c-d\right )}-\frac {i a \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (\sqrt {c}-i \sqrt {d} x\right )}{\sqrt {-a^2} \sqrt {c}-i \sqrt {d}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i a \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (\sqrt {c}-i \sqrt {d} x\right )}{\sqrt {-a^2} \sqrt {c}+i \sqrt {d}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}}-\frac {i a \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (\sqrt {c}+i \sqrt {d} x\right )}{\sqrt {-a^2} \sqrt {c}-i \sqrt {d}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i a \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (\sqrt {c}+i \sqrt {d} x\right )}{\sqrt {-a^2} \sqrt {c}+i \sqrt {d}}\right )}{8 \sqrt {-a^2} c^{3/2} \sqrt {d}} \] Output:

1/2*x*arccot(a*x)/c/(d*x^2+c)+1/2*arccot(a*x)*arctan(d^(1/2)*x/c^(1/2))/c^ 
(3/2)/d^(1/2)-1/8*I*a*ln(d^(1/2)*(1-(-a^2)^(1/2)*x)/(I*(-a^2)^(1/2)*c^(1/2 
)+d^(1/2)))*ln(1-I*d^(1/2)*x/c^(1/2))/(-a^2)^(1/2)/c^(3/2)/d^(1/2)+1/8*I*a 
*ln(-d^(1/2)*(1+(-a^2)^(1/2)*x)/(I*(-a^2)^(1/2)*c^(1/2)-d^(1/2)))*ln(1-I*d 
^(1/2)*x/c^(1/2))/(-a^2)^(1/2)/c^(3/2)/d^(1/2)+1/8*I*a*ln(-d^(1/2)*(1-(-a^ 
2)^(1/2)*x)/(I*(-a^2)^(1/2)*c^(1/2)-d^(1/2)))*ln(1+I*d^(1/2)*x/c^(1/2))/(- 
a^2)^(1/2)/c^(3/2)/d^(1/2)-1/8*I*a*ln(d^(1/2)*(1+(-a^2)^(1/2)*x)/(I*(-a^2) 
^(1/2)*c^(1/2)+d^(1/2)))*ln(1+I*d^(1/2)*x/c^(1/2))/(-a^2)^(1/2)/c^(3/2)/d^ 
(1/2)+1/4*a*ln(a^2*x^2+1)/c/(a^2*c-d)-1/4*a*ln(d*x^2+c)/c/(a^2*c-d)-1/8*I* 
a*polylog(2,(-a^2)^(1/2)*(c^(1/2)-I*d^(1/2)*x)/((-a^2)^(1/2)*c^(1/2)-I*d^( 
1/2)))/(-a^2)^(1/2)/c^(3/2)/d^(1/2)+1/8*I*a*polylog(2,(-a^2)^(1/2)*(c^(1/2 
)-I*d^(1/2)*x)/((-a^2)^(1/2)*c^(1/2)+I*d^(1/2)))/(-a^2)^(1/2)/c^(3/2)/d^(1 
/2)-1/8*I*a*polylog(2,(-a^2)^(1/2)*(c^(1/2)+I*d^(1/2)*x)/((-a^2)^(1/2)*c^( 
1/2)-I*d^(1/2)))/(-a^2)^(1/2)/c^(3/2)/d^(1/2)+1/8*I*a*polylog(2,(-a^2)^(1/ 
2)*(c^(1/2)+I*d^(1/2)*x)/((-a^2)^(1/2)*c^(1/2)+I*d^(1/2)))/(-a^2)^(1/2)/c^ 
(3/2)/d^(1/2)
 

Mathematica [A] (warning: unable to verify)

Time = 4.88 (sec) , antiderivative size = 806, normalized size of antiderivative = 1.01 \[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx =\text {Too large to display} \] Input:

Integrate[ArcCot[a*x]/(c + d*x^2)^2,x]
 

Output:

-1/8*(a*((2*Log[(a^2*c + d + (-(a^2*c) + d)*Cos[2*ArcCot[a*x]])/(a^2*c + d 
)])/(a^2*c - d) + (2*ArcCos[(a^2*c + d)/(a^2*c - d)]*ArcTanh[(a*c)/(Sqrt[- 
(a^2*c*d)]*x)] + 4*ArcCot[a*x]*ArcTanh[(a*d*x)/Sqrt[-(a^2*c*d)]] + (ArcCos 
[(a^2*c + d)/(a^2*c - d)] - (2*I)*ArcTanh[(a*c)/(Sqrt[-(a^2*c*d)]*x)])*Log 
[((2*I)*d*(I*a^2*c + Sqrt[-(a^2*c*d)])*(I + a*x))/((a^2*c - d)*(Sqrt[-(a^2 
*c*d)] - a*d*x))] + (ArcCos[(a^2*c + d)/(a^2*c - d)] + (2*I)*ArcTanh[(a*c) 
/(Sqrt[-(a^2*c*d)]*x)])*Log[(2*d*(a^2*c + I*Sqrt[-(a^2*c*d)])*(-I + a*x))/ 
((a^2*c - d)*(-Sqrt[-(a^2*c*d)] + a*d*x))] - (ArcCos[(a^2*c + d)/(a^2*c - 
d)] + (2*I)*ArcTanh[(a*c)/(Sqrt[-(a^2*c*d)]*x)] + (2*I)*ArcTanh[(a*d*x)/Sq 
rt[-(a^2*c*d)]])*Log[(Sqrt[2]*Sqrt[-(a^2*c*d)])/(Sqrt[a^2*c - d]*E^(I*ArcC 
ot[a*x])*Sqrt[-(a^2*c) - d + (a^2*c - d)*Cos[2*ArcCot[a*x]]])] - (ArcCos[( 
a^2*c + d)/(a^2*c - d)] - (2*I)*ArcTanh[(a*c)/(Sqrt[-(a^2*c*d)]*x)] - (2*I 
)*ArcTanh[(a*d*x)/Sqrt[-(a^2*c*d)]])*Log[(Sqrt[2]*Sqrt[-(a^2*c*d)]*E^(I*Ar 
cCot[a*x]))/(Sqrt[a^2*c - d]*Sqrt[-(a^2*c) - d + (a^2*c - d)*Cos[2*ArcCot[ 
a*x]]])] + I*(PolyLog[2, ((a^2*c + d - (2*I)*Sqrt[-(a^2*c*d)])*(Sqrt[-(a^2 
*c*d)] + a*d*x))/((a^2*c - d)*(Sqrt[-(a^2*c*d)] - a*d*x))] - PolyLog[2, (( 
a^2*c + d + (2*I)*Sqrt[-(a^2*c*d)])*(Sqrt[-(a^2*c*d)] + a*d*x))/((a^2*c - 
d)*(Sqrt[-(a^2*c*d)] - a*d*x))]))/Sqrt[-(a^2*c*d)] - (4*ArcCot[a*x]*Sin[2* 
ArcCot[a*x]])/(a^2*c + d + (-(a^2*c) + d)*Cos[2*ArcCot[a*x]])))/c
 

Rubi [A] (verified)

Time = 1.46 (sec) , antiderivative size = 797, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {5448, 27, 7276, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx\)

\(\Big \downarrow \) 5448

\(\displaystyle a \int \frac {\frac {x}{c \left (d x^2+c\right )}+\frac {\arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )}{c^{3/2} \sqrt {d}}}{2 \left (a^2 x^2+1\right )}dx+\frac {\cot ^{-1}(a x) \arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )}{2 c^{3/2} \sqrt {d}}+\frac {x \cot ^{-1}(a x)}{2 c \left (c+d x^2\right )}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{2} a \int \frac {\frac {x}{c \left (d x^2+c\right )}+\frac {\arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )}{c^{3/2} \sqrt {d}}}{a^2 x^2+1}dx+\frac {\cot ^{-1}(a x) \arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )}{2 c^{3/2} \sqrt {d}}+\frac {x \cot ^{-1}(a x)}{2 c \left (c+d x^2\right )}\)

\(\Big \downarrow \) 7276

\(\displaystyle \frac {1}{2} a \int \left (\frac {x}{c \left (a^2 x^2+1\right ) \left (d x^2+c\right )}+\frac {\arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )}{c^{3/2} \sqrt {d} \left (a^2 x^2+1\right )}\right )dx+\frac {\cot ^{-1}(a x) \arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )}{2 c^{3/2} \sqrt {d}}+\frac {x \cot ^{-1}(a x)}{2 c \left (c+d x^2\right )}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right ) \cot ^{-1}(a x)}{2 c^{3/2} \sqrt {d}}+\frac {x \cot ^{-1}(a x)}{2 c \left (d x^2+c\right )}+\frac {1}{2} a \left (-\frac {i \log \left (\frac {\sqrt {d} \left (1-\sqrt {-a^2} x\right )}{i \sqrt {-a^2} \sqrt {c}+\sqrt {d}}\right ) \log \left (1-\frac {i \sqrt {d} x}{\sqrt {c}}\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i \log \left (-\frac {\sqrt {d} \left (\sqrt {-a^2} x+1\right )}{i \sqrt {-a^2} \sqrt {c}-\sqrt {d}}\right ) \log \left (1-\frac {i \sqrt {d} x}{\sqrt {c}}\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i \log \left (-\frac {\sqrt {d} \left (1-\sqrt {-a^2} x\right )}{i \sqrt {-a^2} \sqrt {c}-\sqrt {d}}\right ) \log \left (\frac {i \sqrt {d} x}{\sqrt {c}}+1\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}-\frac {i \log \left (\frac {\sqrt {d} \left (\sqrt {-a^2} x+1\right )}{i \sqrt {-a^2} \sqrt {c}+\sqrt {d}}\right ) \log \left (\frac {i \sqrt {d} x}{\sqrt {c}}+1\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {\log \left (a^2 x^2+1\right )}{2 c \left (a^2 c-d\right )}-\frac {\log \left (d x^2+c\right )}{2 c \left (a^2 c-d\right )}-\frac {i \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (\sqrt {c}-i \sqrt {d} x\right )}{\sqrt {-a^2} \sqrt {c}-i \sqrt {d}}\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (\sqrt {c}-i \sqrt {d} x\right )}{\sqrt {-a^2} \sqrt {c}+i \sqrt {d}}\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}-\frac {i \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (i \sqrt {d} x+\sqrt {c}\right )}{\sqrt {-a^2} \sqrt {c}-i \sqrt {d}}\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}+\frac {i \operatorname {PolyLog}\left (2,\frac {\sqrt {-a^2} \left (i \sqrt {d} x+\sqrt {c}\right )}{\sqrt {-a^2} \sqrt {c}+i \sqrt {d}}\right )}{4 \sqrt {-a^2} c^{3/2} \sqrt {d}}\right )\)

Input:

Int[ArcCot[a*x]/(c + d*x^2)^2,x]
 

Output:

(x*ArcCot[a*x])/(2*c*(c + d*x^2)) + (ArcCot[a*x]*ArcTan[(Sqrt[d]*x)/Sqrt[c 
]])/(2*c^(3/2)*Sqrt[d]) + (a*(((-1/4*I)*Log[(Sqrt[d]*(1 - Sqrt[-a^2]*x))/( 
I*Sqrt[-a^2]*Sqrt[c] + Sqrt[d])]*Log[1 - (I*Sqrt[d]*x)/Sqrt[c]])/(Sqrt[-a^ 
2]*c^(3/2)*Sqrt[d]) + ((I/4)*Log[-((Sqrt[d]*(1 + Sqrt[-a^2]*x))/(I*Sqrt[-a 
^2]*Sqrt[c] - Sqrt[d]))]*Log[1 - (I*Sqrt[d]*x)/Sqrt[c]])/(Sqrt[-a^2]*c^(3/ 
2)*Sqrt[d]) + ((I/4)*Log[-((Sqrt[d]*(1 - Sqrt[-a^2]*x))/(I*Sqrt[-a^2]*Sqrt 
[c] - Sqrt[d]))]*Log[1 + (I*Sqrt[d]*x)/Sqrt[c]])/(Sqrt[-a^2]*c^(3/2)*Sqrt[ 
d]) - ((I/4)*Log[(Sqrt[d]*(1 + Sqrt[-a^2]*x))/(I*Sqrt[-a^2]*Sqrt[c] + Sqrt 
[d])]*Log[1 + (I*Sqrt[d]*x)/Sqrt[c]])/(Sqrt[-a^2]*c^(3/2)*Sqrt[d]) + Log[1 
 + a^2*x^2]/(2*c*(a^2*c - d)) - Log[c + d*x^2]/(2*c*(a^2*c - d)) - ((I/4)* 
PolyLog[2, (Sqrt[-a^2]*(Sqrt[c] - I*Sqrt[d]*x))/(Sqrt[-a^2]*Sqrt[c] - I*Sq 
rt[d])])/(Sqrt[-a^2]*c^(3/2)*Sqrt[d]) + ((I/4)*PolyLog[2, (Sqrt[-a^2]*(Sqr 
t[c] - I*Sqrt[d]*x))/(Sqrt[-a^2]*Sqrt[c] + I*Sqrt[d])])/(Sqrt[-a^2]*c^(3/2 
)*Sqrt[d]) - ((I/4)*PolyLog[2, (Sqrt[-a^2]*(Sqrt[c] + I*Sqrt[d]*x))/(Sqrt[ 
-a^2]*Sqrt[c] - I*Sqrt[d])])/(Sqrt[-a^2]*c^(3/2)*Sqrt[d]) + ((I/4)*PolyLog 
[2, (Sqrt[-a^2]*(Sqrt[c] + I*Sqrt[d]*x))/(Sqrt[-a^2]*Sqrt[c] + I*Sqrt[d])] 
)/(Sqrt[-a^2]*c^(3/2)*Sqrt[d])))/2
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 5448
Int[((a_.) + ArcCot[(c_.)*(x_)]*(b_.))*((d_.) + (e_.)*(x_)^2)^(q_.), x_Symb 
ol] :> With[{u = IntHide[(d + e*x^2)^q, x]}, Simp[(a + b*ArcCot[c*x])   u, 
x] + Simp[b*c   Int[SimplifyIntegrand[u/(1 + c^2*x^2), x], x], x]] /; FreeQ 
[{a, b, c, d, e}, x] && (IntegerQ[q] || ILtQ[q + 1/2, 0])
 

rule 7276
Int[(u_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{v = RationalFunctionE 
xpand[u/(a + b*x^n), x]}, Int[v, x] /; SumQ[v]] /; FreeQ[{a, b}, x] && IGtQ 
[n, 0]
 
Maple [B] (verified)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 2140 vs. \(2 (593 ) = 1186\).

Time = 2.55 (sec) , antiderivative size = 2141, normalized size of antiderivative = 2.67

method result size
risch \(\text {Expression too large to display}\) \(2141\)
derivativedivides \(\text {Expression too large to display}\) \(2275\)
default \(\text {Expression too large to display}\) \(2275\)

Input:

int(arccot(a*x)/(d*x^2+c)^2,x,method=_RETURNVERBOSE)
 

Output:

1/8*a^4*ln(1-I*a*x)/(a^2*c-d)/(-a^2*d*x^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^( 
1/2)-(1-I*a*x)*d+d)/(a*(c*d)^(1/2)+d))*d*x^2-1/8*a^4*ln(1-I*a*x)/(a^2*c-d) 
/(-a^2*d*x^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^(1/2)+(1-I*a*x)*d-d)/(a*(c*d)^ 
(1/2)-d))*d*x^2-1/4*I*a^2*ln(1-I*a*x)/c/(a^2*c-d)/(-a^2*d*x^2-a^2*c)*d*x-1 
/4*a^3*ln(1-I*a*x)/(a^2*c-d)/(-a^2*d*x^2-a^2*c)-1/8*a/c/(a^2*c-d)*ln((1-I* 
a*x)^2*d-a^2*c-2*(1-I*a*x)*d+d)-1/4*a^2/(a^2*c-d)/(c*d)^(1/2)*arctanh(1/2* 
(2*(1-I*a*x)*d-2*d)/a/(c*d)^(1/2))-1/8*a^2*ln(1-I*a*x)/c/(a^2*c-d)/(-a^2*d 
*x^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^(1/2)-(1-I*a*x)*d+d)/(a*(c*d)^(1/2)+d) 
)*d^2*x^2+1/8*a^2*ln(1-I*a*x)/c/(a^2*c-d)/(-a^2*d*x^2-a^2*c)/(c*d)^(1/2)*l 
n((a*(c*d)^(1/2)+(1-I*a*x)*d-d)/(a*(c*d)^(1/2)-d))*d^2*x^2-1/8*a^2*ln(1+I* 
a*x)/c/(a^2*c-d)/(-a^2*d*x^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^(1/2)-(1+I*a*x 
)*d+d)/(a*(c*d)^(1/2)+d))*d^2*x^2+1/8*a^2*ln(1+I*a*x)/c/(a^2*c-d)/(-a^2*d* 
x^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^(1/2)+(1+I*a*x)*d-d)/(a*(c*d)^(1/2)-d)) 
*d^2*x^2-1/8*a^4*ln(1-I*a*x)*c/(a^2*c-d)/(-a^2*d*x^2-a^2*c)/(c*d)^(1/2)*ln 
((a*(c*d)^(1/2)+(1-I*a*x)*d-d)/(a*(c*d)^(1/2)-d))-1/4*a^3*ln(1-I*a*x)/c/(a 
^2*c-d)/(-a^2*d*x^2-a^2*c)*d*x^2+1/8*a^4*ln(1-I*a*x)*c/(a^2*c-d)/(-a^2*d*x 
^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^(1/2)-(1-I*a*x)*d+d)/(a*(c*d)^(1/2)+d))+ 
1/8*a^2*ln(1-I*a*x)/(a^2*c-d)/(-a^2*d*x^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^( 
1/2)+(1-I*a*x)*d-d)/(a*(c*d)^(1/2)-d))*d-1/8*a^2*ln(1-I*a*x)/(a^2*c-d)/(-a 
^2*d*x^2-a^2*c)/(c*d)^(1/2)*ln((a*(c*d)^(1/2)-(1-I*a*x)*d+d)/(a*(c*d)^(...
 

Fricas [F]

\[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx=\int { \frac {\operatorname {arccot}\left (a x\right )}{{\left (d x^{2} + c\right )}^{2}} \,d x } \] Input:

integrate(arccot(a*x)/(d*x^2+c)^2,x, algorithm="fricas")
 

Output:

integral(arccot(a*x)/(d^2*x^4 + 2*c*d*x^2 + c^2), x)
 

Sympy [F]

\[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx=\int \frac {\operatorname {acot}{\left (a x \right )}}{\left (c + d x^{2}\right )^{2}}\, dx \] Input:

integrate(acot(a*x)/(d*x**2+c)**2,x)
 

Output:

Integral(acot(a*x)/(c + d*x**2)**2, x)
 

Maxima [A] (verification not implemented)

Time = 0.18 (sec) , antiderivative size = 628, normalized size of antiderivative = 0.78 \[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx=\frac {1}{2} \, {\left (\frac {x}{c d x^{2} + c^{2}} + \frac {\arctan \left (\frac {d x}{\sqrt {c d}}\right )}{\sqrt {c d} c}\right )} \operatorname {arccot}\left (a x\right ) + \frac {{\left (4 \, a c d \log \left (a^{2} x^{2} + 1\right ) - 4 \, a c d \log \left (d x^{2} + c\right ) + {\left (4 \, {\left (a^{2} c - d\right )} \arctan \left (a x\right ) \arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right ) + 4 \, {\left (a^{2} c - d\right )} \arctan \left (\frac {\sqrt {d} x}{\sqrt {c}}\right ) \arctan \left (-\frac {a \sqrt {d} x}{a \sqrt {c} - \sqrt {d}}, -\frac {\sqrt {d}}{a \sqrt {c} - \sqrt {d}}\right ) + {\left (a^{2} c - d\right )} \log \left (d x^{2} + c\right ) \log \left (\frac {a^{2} c d + {\left (a^{4} c d + a^{2} d^{2}\right )} x^{2} + 2 \, {\left (a^{3} d x^{2} + a d\right )} \sqrt {c} \sqrt {d} + d^{2}}{a^{4} c^{2} + 6 \, a^{2} c d + 4 \, {\left (a^{3} c + a d\right )} \sqrt {c} \sqrt {d} + d^{2}}\right ) - {\left (a^{2} c - d\right )} \log \left (d x^{2} + c\right ) \log \left (\frac {a^{2} c d + {\left (a^{4} c d + a^{2} d^{2}\right )} x^{2} - 2 \, {\left (a^{3} d x^{2} + a d\right )} \sqrt {c} \sqrt {d} + d^{2}}{a^{4} c^{2} + 6 \, a^{2} c d - 4 \, {\left (a^{3} c + a d\right )} \sqrt {c} \sqrt {d} + d^{2}}\right ) + 2 \, {\left (a^{2} c - d\right )} {\rm Li}_2\left (\frac {a^{2} c + i \, a d x + {\left (i \, a^{2} x + a\right )} \sqrt {c} \sqrt {d}}{a^{2} c + 2 \, a \sqrt {c} \sqrt {d} + d}\right ) + 2 \, {\left (a^{2} c - d\right )} {\rm Li}_2\left (\frac {a^{2} c - i \, a d x - {\left (i \, a^{2} x - a\right )} \sqrt {c} \sqrt {d}}{a^{2} c + 2 \, a \sqrt {c} \sqrt {d} + d}\right ) - 2 \, {\left (a^{2} c - d\right )} {\rm Li}_2\left (\frac {a^{2} c + i \, a d x - {\left (i \, a^{2} x + a\right )} \sqrt {c} \sqrt {d}}{a^{2} c - 2 \, a \sqrt {c} \sqrt {d} + d}\right ) - 2 \, {\left (a^{2} c - d\right )} {\rm Li}_2\left (\frac {a^{2} c - i \, a d x + {\left (i \, a^{2} x - a\right )} \sqrt {c} \sqrt {d}}{a^{2} c - 2 \, a \sqrt {c} \sqrt {d} + d}\right )\right )} \sqrt {c} \sqrt {d}\right )} a}{16 \, {\left (a^{3} c^{3} d - a c^{2} d^{2}\right )}} \] Input:

integrate(arccot(a*x)/(d*x^2+c)^2,x, algorithm="maxima")
 

Output:

1/2*(x/(c*d*x^2 + c^2) + arctan(d*x/sqrt(c*d))/(sqrt(c*d)*c))*arccot(a*x) 
+ 1/16*(4*a*c*d*log(a^2*x^2 + 1) - 4*a*c*d*log(d*x^2 + c) + (4*(a^2*c - d) 
*arctan(a*x)*arctan(sqrt(d)*x/sqrt(c)) + 4*(a^2*c - d)*arctan(sqrt(d)*x/sq 
rt(c))*arctan2(-a*sqrt(d)*x/(a*sqrt(c) - sqrt(d)), -sqrt(d)/(a*sqrt(c) - s 
qrt(d))) + (a^2*c - d)*log(d*x^2 + c)*log((a^2*c*d + (a^4*c*d + a^2*d^2)*x 
^2 + 2*(a^3*d*x^2 + a*d)*sqrt(c)*sqrt(d) + d^2)/(a^4*c^2 + 6*a^2*c*d + 4*( 
a^3*c + a*d)*sqrt(c)*sqrt(d) + d^2)) - (a^2*c - d)*log(d*x^2 + c)*log((a^2 
*c*d + (a^4*c*d + a^2*d^2)*x^2 - 2*(a^3*d*x^2 + a*d)*sqrt(c)*sqrt(d) + d^2 
)/(a^4*c^2 + 6*a^2*c*d - 4*(a^3*c + a*d)*sqrt(c)*sqrt(d) + d^2)) + 2*(a^2* 
c - d)*dilog((a^2*c + I*a*d*x + (I*a^2*x + a)*sqrt(c)*sqrt(d))/(a^2*c + 2* 
a*sqrt(c)*sqrt(d) + d)) + 2*(a^2*c - d)*dilog((a^2*c - I*a*d*x - (I*a^2*x 
- a)*sqrt(c)*sqrt(d))/(a^2*c + 2*a*sqrt(c)*sqrt(d) + d)) - 2*(a^2*c - d)*d 
ilog((a^2*c + I*a*d*x - (I*a^2*x + a)*sqrt(c)*sqrt(d))/(a^2*c - 2*a*sqrt(c 
)*sqrt(d) + d)) - 2*(a^2*c - d)*dilog((a^2*c - I*a*d*x + (I*a^2*x - a)*sqr 
t(c)*sqrt(d))/(a^2*c - 2*a*sqrt(c)*sqrt(d) + d)))*sqrt(c)*sqrt(d))*a/(a^3* 
c^3*d - a*c^2*d^2)
 

Giac [F]

\[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx=\int { \frac {\operatorname {arccot}\left (a x\right )}{{\left (d x^{2} + c\right )}^{2}} \,d x } \] Input:

integrate(arccot(a*x)/(d*x^2+c)^2,x, algorithm="giac")
 

Output:

integrate(arccot(a*x)/(d*x^2 + c)^2, x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx=\int \frac {\mathrm {acot}\left (a\,x\right )}{{\left (d\,x^2+c\right )}^2} \,d x \] Input:

int(acot(a*x)/(c + d*x^2)^2,x)
 

Output:

int(acot(a*x)/(c + d*x^2)^2, x)
 

Reduce [F]

\[ \int \frac {\cot ^{-1}(a x)}{\left (c+d x^2\right )^2} \, dx =\text {Too large to display} \] Input:

int(acot(a*x)/(d*x^2+c)^2,x)
                                                                                    
                                                                                    
 

Output:

( - acot(a*x)**2*a**5*c**2 - acot(a*x)**2*a**5*c*d*x**2 + acot(a*x)**2*a** 
3*c*d + acot(a*x)**2*a**3*d**2*x**2 + 2*acot(a*x)*a**4*c*d*x - 2*acot(a*x) 
*a**2*d**2*x - 6*int(atan(1/(a*x))/(3*a**4*c**3*x**2 + 6*a**4*c**2*d*x**4 
+ 3*a**4*c*d**2*x**6 + 3*a**2*c**3 + 5*a**2*c**2*d*x**2 + a**2*c*d**2*x**4 
 - a**2*d**3*x**6 - c**2*d - 2*c*d**2*x**2 - d**3*x**4),x)*a**8*c**5 - 6*i 
nt(atan(1/(a*x))/(3*a**4*c**3*x**2 + 6*a**4*c**2*d*x**4 + 3*a**4*c*d**2*x* 
*6 + 3*a**2*c**3 + 5*a**2*c**2*d*x**2 + a**2*c*d**2*x**4 - a**2*d**3*x**6 
- c**2*d - 2*c*d**2*x**2 - d**3*x**4),x)*a**8*c**4*d*x**2 + 20*int(atan(1/ 
(a*x))/(3*a**4*c**3*x**2 + 6*a**4*c**2*d*x**4 + 3*a**4*c*d**2*x**6 + 3*a** 
2*c**3 + 5*a**2*c**2*d*x**2 + a**2*c*d**2*x**4 - a**2*d**3*x**6 - c**2*d - 
 2*c*d**2*x**2 - d**3*x**4),x)*a**6*c**4*d + 20*int(atan(1/(a*x))/(3*a**4* 
c**3*x**2 + 6*a**4*c**2*d*x**4 + 3*a**4*c*d**2*x**6 + 3*a**2*c**3 + 5*a**2 
*c**2*d*x**2 + a**2*c*d**2*x**4 - a**2*d**3*x**6 - c**2*d - 2*c*d**2*x**2 
- d**3*x**4),x)*a**6*c**3*d**2*x**2 - 24*int(atan(1/(a*x))/(3*a**4*c**3*x* 
*2 + 6*a**4*c**2*d*x**4 + 3*a**4*c*d**2*x**6 + 3*a**2*c**3 + 5*a**2*c**2*d 
*x**2 + a**2*c*d**2*x**4 - a**2*d**3*x**6 - c**2*d - 2*c*d**2*x**2 - d**3* 
x**4),x)*a**4*c**3*d**2 - 24*int(atan(1/(a*x))/(3*a**4*c**3*x**2 + 6*a**4* 
c**2*d*x**4 + 3*a**4*c*d**2*x**6 + 3*a**2*c**3 + 5*a**2*c**2*d*x**2 + a**2 
*c*d**2*x**4 - a**2*d**3*x**6 - c**2*d - 2*c*d**2*x**2 - d**3*x**4),x)*a** 
4*c**2*d**3*x**2 + 12*int(atan(1/(a*x))/(3*a**4*c**3*x**2 + 6*a**4*c**2...