Integrand size = 10, antiderivative size = 56 \[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=i \sec ^{-1}\left (\sqrt {x}\right )^2-2 \sec ^{-1}\left (\sqrt {x}\right ) \log \left (1+e^{2 i \sec ^{-1}\left (\sqrt {x}\right )}\right )+i \operatorname {PolyLog}\left (2,-e^{2 i \sec ^{-1}\left (\sqrt {x}\right )}\right ) \] Output:
I*arcsec(x^(1/2))^2-2*arcsec(x^(1/2))*ln(1+(1/x^(1/2)+I*(1-1/x)^(1/2))^2)+ I*polylog(2,-(1/x^(1/2)+I*(1-1/x)^(1/2))^2)
Time = 0.02 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.96 \[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=i \left (\sec ^{-1}\left (\sqrt {x}\right ) \left (\sec ^{-1}\left (\sqrt {x}\right )+2 i \log \left (1+e^{2 i \sec ^{-1}\left (\sqrt {x}\right )}\right )\right )+\operatorname {PolyLog}\left (2,-e^{2 i \sec ^{-1}\left (\sqrt {x}\right )}\right )\right ) \] Input:
Integrate[ArcSec[Sqrt[x]]/x,x]
Output:
I*(ArcSec[Sqrt[x]]*(ArcSec[Sqrt[x]] + (2*I)*Log[1 + E^((2*I)*ArcSec[Sqrt[x ]])]) + PolyLog[2, -E^((2*I)*ArcSec[Sqrt[x]])])
Time = 0.46 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.11, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {7267, 5741, 5137, 3042, 4202, 2620, 2715, 2838}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx\) |
\(\Big \downarrow \) 7267 |
\(\displaystyle 2 \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{\sqrt {x}}d\sqrt {x}\) |
\(\Big \downarrow \) 5741 |
\(\displaystyle -2 \int \frac {\arccos \left (\frac {1}{\sqrt {x}}\right )}{\sqrt {x}}d\frac {1}{\sqrt {x}}\) |
\(\Big \downarrow \) 5137 |
\(\displaystyle 2 \int \sqrt {1-\frac {1}{x}} \sqrt {x} \arccos \left (\frac {1}{\sqrt {x}}\right )d\arccos \left (\frac {1}{\sqrt {x}}\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle 2 \int \arccos \left (\frac {1}{\sqrt {x}}\right ) \tan \left (\arccos \left (\frac {1}{\sqrt {x}}\right )\right )d\arccos \left (\frac {1}{\sqrt {x}}\right )\) |
\(\Big \downarrow \) 4202 |
\(\displaystyle 2 \left (\frac {i x}{2}-2 i \int \frac {e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )} \arccos \left (\frac {1}{\sqrt {x}}\right )}{1+e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}}d\arccos \left (\frac {1}{\sqrt {x}}\right )\right )\) |
\(\Big \downarrow \) 2620 |
\(\displaystyle 2 \left (\frac {i x}{2}-2 i \left (\frac {1}{2} i \int \log \left (1+e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}\right )d\arccos \left (\frac {1}{\sqrt {x}}\right )-\frac {1}{2} i \arccos \left (\frac {1}{\sqrt {x}}\right ) \log \left (1+e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}\right )\right )\right )\) |
\(\Big \downarrow \) 2715 |
\(\displaystyle 2 \left (\frac {i x}{2}-2 i \left (\frac {1}{4} \int e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )} \log \left (1+e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}\right )de^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}-\frac {1}{2} i \arccos \left (\frac {1}{\sqrt {x}}\right ) \log \left (1+e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}\right )\right )\right )\) |
\(\Big \downarrow \) 2838 |
\(\displaystyle 2 \left (\frac {i x}{2}-2 i \left (-\frac {1}{4} \operatorname {PolyLog}\left (2,-e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}\right )-\frac {1}{2} i \arccos \left (\frac {1}{\sqrt {x}}\right ) \log \left (1+e^{2 i \arccos \left (\frac {1}{\sqrt {x}}\right )}\right )\right )\right )\) |
Input:
Int[ArcSec[Sqrt[x]]/x,x]
Output:
2*((I/2)*x - (2*I)*((-1/2*I)*ArcCos[1/Sqrt[x]]*Log[1 + E^((2*I)*ArcCos[1/S qrt[x]])] - PolyLog[2, -E^((2*I)*ArcCos[1/Sqrt[x]])]/4))
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ ((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp [((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si mp[d*(m/(b*f*g*n*Log[F])) Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x )))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Simp[1/(d*e*n*Log[F]) Subst[Int[Log[a + b*x]/x, x], x, (F^(e*(c + d*x) ))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 , (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[I *((c + d*x)^(m + 1)/(d*(m + 1))), x] - Simp[2*I Int[(c + d*x)^m*(E^(2*I*( e + f*x))/(1 + E^(2*I*(e + f*x)))), x], x] /; FreeQ[{c, d, e, f}, x] && IGt Q[m, 0]
Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)/(x_), x_Symbol] :> -Subst[Int[ (a + b*x)^n*Tan[x], x], x, ArcCos[c*x]] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0 ]
Int[((a_.) + ArcSec[(c_.)*(x_)]*(b_.))/(x_), x_Symbol] :> -Subst[Int[(a + b *ArcCos[x/c])/x, x], x, 1/x] /; FreeQ[{a, b, c}, x]
Int[u_, x_Symbol] :> With[{lst = SubstForFractionalPowerOfLinear[u, x]}, Si mp[lst[[2]]*lst[[4]] Subst[Int[lst[[1]], x], x, lst[[3]]^(1/lst[[2]])], x ] /; !FalseQ[lst] && SubstForFractionalPowerQ[u, lst[[3]], x]]
Time = 0.34 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.12
method | result | size |
derivativedivides | \(i \operatorname {arcsec}\left (\sqrt {x}\right )^{2}-2 \,\operatorname {arcsec}\left (\sqrt {x}\right ) \ln \left (1+\left (\frac {1}{\sqrt {x}}+i \sqrt {1-\frac {1}{x}}\right )^{2}\right )+i \operatorname {polylog}\left (2, -\left (\frac {1}{\sqrt {x}}+i \sqrt {1-\frac {1}{x}}\right )^{2}\right )\) | \(63\) |
default | \(i \operatorname {arcsec}\left (\sqrt {x}\right )^{2}-2 \,\operatorname {arcsec}\left (\sqrt {x}\right ) \ln \left (1+\left (\frac {1}{\sqrt {x}}+i \sqrt {1-\frac {1}{x}}\right )^{2}\right )+i \operatorname {polylog}\left (2, -\left (\frac {1}{\sqrt {x}}+i \sqrt {1-\frac {1}{x}}\right )^{2}\right )\) | \(63\) |
Input:
int(arcsec(x^(1/2))/x,x,method=_RETURNVERBOSE)
Output:
I*arcsec(x^(1/2))^2-2*arcsec(x^(1/2))*ln(1+(1/x^(1/2)+I*(1-1/x)^(1/2))^2)+ I*polylog(2,-(1/x^(1/2)+I*(1-1/x)^(1/2))^2)
\[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=\int { \frac {\operatorname {arcsec}\left (\sqrt {x}\right )}{x} \,d x } \] Input:
integrate(arcsec(x^(1/2))/x,x, algorithm="fricas")
Output:
integral(arcsec(sqrt(x))/x, x)
\[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=\int \frac {\operatorname {asec}{\left (\sqrt {x} \right )}}{x}\, dx \] Input:
integrate(asec(x**(1/2))/x,x)
Output:
Integral(asec(sqrt(x))/x, x)
\[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=\int { \frac {\operatorname {arcsec}\left (\sqrt {x}\right )}{x} \,d x } \] Input:
integrate(arcsec(x^(1/2))/x,x, algorithm="maxima")
Output:
integrate(arcsec(sqrt(x))/x, x)
Exception generated. \[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=\text {Exception raised: NotImplementedError} \] Input:
integrate(arcsec(x^(1/2))/x,x, algorithm="giac")
Output:
Exception raised: NotImplementedError >> unable to parse Giac output: Inva lid series expansion: non tractable function acos at +infinity
Timed out. \[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=\int \frac {\mathrm {acos}\left (\frac {1}{\sqrt {x}}\right )}{x} \,d x \] Input:
int(acos(1/x^(1/2))/x,x)
Output:
int(acos(1/x^(1/2))/x, x)
\[ \int \frac {\sec ^{-1}\left (\sqrt {x}\right )}{x} \, dx=\int \frac {\mathit {asec} \left (\sqrt {x}\right )}{x}d x \] Input:
int(asec(x^(1/2))/x,x)
Output:
int(asec(sqrt(x))/x,x)