Integrand size = 8, antiderivative size = 91 \[ \int e^{\sec ^{-1}(a x)} x \, dx=-\frac {\left (\frac {8}{5}+\frac {4 i}{5}\right ) e^{(1+2 i) \sec ^{-1}(a x)} \operatorname {Hypergeometric2F1}\left (1-\frac {i}{2},2,2-\frac {i}{2},-e^{2 i \sec ^{-1}(a x)}\right )}{a^2}+\frac {\left (\frac {16}{5}+\frac {8 i}{5}\right ) e^{(1+2 i) \sec ^{-1}(a x)} \operatorname {Hypergeometric2F1}\left (1-\frac {i}{2},3,2-\frac {i}{2},-e^{2 i \sec ^{-1}(a x)}\right )}{a^2} \] Output:
(-8/5-4/5*I)*exp((1+2*I)*arcsec(a*x))*hypergeom([2, 1-1/2*I],[2-1/2*I],-(1 /a/x+I*(1-1/a^2/x^2)^(1/2))^2)/a^2+(16/5+8/5*I)*exp((1+2*I)*arcsec(a*x))*h ypergeom([3, 1-1/2*I],[2-1/2*I],-(1/a/x+I*(1-1/a^2/x^2)^(1/2))^2)/a^2
Time = 0.14 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.18 \[ \int e^{\sec ^{-1}(a x)} x \, dx=\frac {\left (\frac {1}{5}+\frac {i}{10}\right ) e^{\sec ^{-1}(a x)} \left ((-2+i) a x \left (\sqrt {1-\frac {1}{a^2 x^2}}-a x\right )+(1+2 i) \operatorname {Hypergeometric2F1}\left (-\frac {i}{2},1,1-\frac {i}{2},-e^{2 i \sec ^{-1}(a x)}\right )-e^{2 i \sec ^{-1}(a x)} \operatorname {Hypergeometric2F1}\left (1,1-\frac {i}{2},2-\frac {i}{2},-e^{2 i \sec ^{-1}(a x)}\right )\right )}{a^2} \] Input:
Integrate[E^ArcSec[a*x]*x,x]
Output:
((1/5 + I/10)*E^ArcSec[a*x]*((-2 + I)*a*x*(Sqrt[1 - 1/(a^2*x^2)] - a*x) + (1 + 2*I)*Hypergeometric2F1[-1/2*I, 1, 1 - I/2, -E^((2*I)*ArcSec[a*x])] - E^((2*I)*ArcSec[a*x])*Hypergeometric2F1[1, 1 - I/2, 2 - I/2, -E^((2*I)*Arc Sec[a*x])]))/a^2
Time = 0.32 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.98, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5789, 27, 4974, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x e^{\sec ^{-1}(a x)} \, dx\) |
\(\Big \downarrow \) 5789 |
\(\displaystyle \frac {\int a^2 e^{\sec ^{-1}(a x)} \sqrt {1-\frac {1}{a^2 x^2}} x^3d\sec ^{-1}(a x)}{a}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\int a^3 e^{\sec ^{-1}(a x)} \sqrt {1-\frac {1}{a^2 x^2}} x^3d\sec ^{-1}(a x)}{a^2}\) |
\(\Big \downarrow \) 4974 |
\(\displaystyle \frac {\int \left (\frac {8 i e^{(1+2 i) \sec ^{-1}(a x)}}{\left (1+e^{2 i \sec ^{-1}(a x)}\right )^3}-\frac {4 i e^{(1+2 i) \sec ^{-1}(a x)}}{\left (1+e^{2 i \sec ^{-1}(a x)}\right )^2}\right )d\sec ^{-1}(a x)}{a^2}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {\left (\frac {16}{5}+\frac {8 i}{5}\right ) e^{(1+2 i) \sec ^{-1}(a x)} \operatorname {Hypergeometric2F1}\left (1-\frac {i}{2},3,2-\frac {i}{2},-e^{2 i \sec ^{-1}(a x)}\right )-\left (\frac {8}{5}+\frac {4 i}{5}\right ) e^{(1+2 i) \sec ^{-1}(a x)} \operatorname {Hypergeometric2F1}\left (1-\frac {i}{2},2,2-\frac {i}{2},-e^{2 i \sec ^{-1}(a x)}\right )}{a^2}\) |
Input:
Int[E^ArcSec[a*x]*x,x]
Output:
((-8/5 - (4*I)/5)*E^((1 + 2*I)*ArcSec[a*x])*Hypergeometric2F1[1 - I/2, 2, 2 - I/2, -E^((2*I)*ArcSec[a*x])] + (16/5 + (8*I)/5)*E^((1 + 2*I)*ArcSec[a* x])*Hypergeometric2F1[1 - I/2, 3, 2 - I/2, -E^((2*I)*ArcSec[a*x])])/a^2
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(F_)^((c_.)*((a_.) + (b_.)*(x_)))*(G_)[(d_.) + (e_.)*(x_)]^(m_.)*(H_)[( d_.) + (e_.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigToExp[F^(c*(a + b*x)), G[d + e*x]^m*H[d + e*x]^n, x], x] /; FreeQ[{F, a, b, c, d, e}, x] && IGtQ[ m, 0] && IGtQ[n, 0] && TrigQ[G] && TrigQ[H]
Int[(u_.)*(f_)^(ArcSec[(a_.) + (b_.)*(x_)]^(n_.)*(c_.)), x_Symbol] :> Simp[ 1/b Subst[Int[(u /. x -> -a/b + Sec[x]/b)*f^(c*x^n)*Sec[x]*Tan[x], x], x, ArcSec[a + b*x]], x] /; FreeQ[{a, b, c, f}, x] && IGtQ[n, 0]
\[\int {\mathrm e}^{\operatorname {arcsec}\left (a x \right )} x d x\]
Input:
int(exp(arcsec(a*x))*x,x)
Output:
int(exp(arcsec(a*x))*x,x)
\[ \int e^{\sec ^{-1}(a x)} x \, dx=\int { x e^{\left (\operatorname {arcsec}\left (a x\right )\right )} \,d x } \] Input:
integrate(exp(arcsec(a*x))*x,x, algorithm="fricas")
Output:
integral(x*e^(arcsec(a*x)), x)
\[ \int e^{\sec ^{-1}(a x)} x \, dx=\int x e^{\operatorname {asec}{\left (a x \right )}}\, dx \] Input:
integrate(exp(asec(a*x))*x,x)
Output:
Integral(x*exp(asec(a*x)), x)
\[ \int e^{\sec ^{-1}(a x)} x \, dx=\int { x e^{\left (\operatorname {arcsec}\left (a x\right )\right )} \,d x } \] Input:
integrate(exp(arcsec(a*x))*x,x, algorithm="maxima")
Output:
integrate(x*e^(arcsec(a*x)), x)
\[ \int e^{\sec ^{-1}(a x)} x \, dx=\int { x e^{\left (\operatorname {arcsec}\left (a x\right )\right )} \,d x } \] Input:
integrate(exp(arcsec(a*x))*x,x, algorithm="giac")
Output:
integrate(x*e^(arcsec(a*x)), x)
Timed out. \[ \int e^{\sec ^{-1}(a x)} x \, dx=\int x\,{\mathrm {e}}^{\mathrm {acos}\left (\frac {1}{a\,x}\right )} \,d x \] Input:
int(x*exp(acos(1/(a*x))),x)
Output:
int(x*exp(acos(1/(a*x))), x)
\[ \int e^{\sec ^{-1}(a x)} x \, dx=\int e^{\mathit {asec} \left (a x \right )} x d x \] Input:
int(exp(asec(a*x))*x,x)
Output:
int(e**asec(a*x)*x,x)