Integrand size = 21, antiderivative size = 138 \[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=-\frac {b c x \sqrt {-1+c^2 x^2}}{3 d \left (c^2 d+e\right ) \sqrt {c^2 x^2} \sqrt {d+e x^2}}-\frac {a+b \sec ^{-1}(c x)}{3 e \left (d+e x^2\right )^{3/2}}-\frac {b c x \arctan \left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-1+c^2 x^2}}\right )}{3 d^{3/2} e \sqrt {c^2 x^2}} \] Output:
-1/3*b*c*x*(c^2*x^2-1)^(1/2)/d/(c^2*d+e)/(c^2*x^2)^(1/2)/(e*x^2+d)^(1/2)-1 /3*(a+b*arcsec(c*x))/e/(e*x^2+d)^(3/2)-1/3*b*c*x*arctan((e*x^2+d)^(1/2)/d^ (1/2)/(c^2*x^2-1)^(1/2))/d^(3/2)/e/(c^2*x^2)^(1/2)
Result contains higher order function than in optimal. Order 6 vs. order 3 in optimal.
Time = 0.41 (sec) , antiderivative size = 132, normalized size of antiderivative = 0.96 \[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=\frac {-\frac {b \sqrt {1+\frac {d}{e x^2}} \left (d+e x^2\right ) \operatorname {AppellF1}\left (1,\frac {1}{2},\frac {1}{2},2,\frac {1}{c^2 x^2},-\frac {d}{e x^2}\right )}{c d e x}+\frac {2 \left (-a-\frac {b c e \sqrt {1-\frac {1}{c^2 x^2}} x \left (d+e x^2\right )}{d \left (c^2 d+e\right )}-b \sec ^{-1}(c x)\right )}{e}}{6 \left (d+e x^2\right )^{3/2}} \] Input:
Integrate[(x*(a + b*ArcSec[c*x]))/(d + e*x^2)^(5/2),x]
Output:
(-((b*Sqrt[1 + d/(e*x^2)]*(d + e*x^2)*AppellF1[1, 1/2, 1/2, 2, 1/(c^2*x^2) , -(d/(e*x^2))])/(c*d*e*x)) + (2*(-a - (b*c*e*Sqrt[1 - 1/(c^2*x^2)]*x*(d + e*x^2))/(d*(c^2*d + e)) - b*ArcSec[c*x]))/e)/(6*(d + e*x^2)^(3/2))
Time = 0.33 (sec) , antiderivative size = 126, normalized size of antiderivative = 0.91, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {5759, 354, 107, 104, 217}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx\) |
\(\Big \downarrow \) 5759 |
\(\displaystyle \frac {b c x \int \frac {1}{x \sqrt {c^2 x^2-1} \left (e x^2+d\right )^{3/2}}dx}{3 e \sqrt {c^2 x^2}}-\frac {a+b \sec ^{-1}(c x)}{3 e \left (d+e x^2\right )^{3/2}}\) |
\(\Big \downarrow \) 354 |
\(\displaystyle \frac {b c x \int \frac {1}{x^2 \sqrt {c^2 x^2-1} \left (e x^2+d\right )^{3/2}}dx^2}{6 e \sqrt {c^2 x^2}}-\frac {a+b \sec ^{-1}(c x)}{3 e \left (d+e x^2\right )^{3/2}}\) |
\(\Big \downarrow \) 107 |
\(\displaystyle \frac {b c x \left (\frac {\int \frac {1}{x^2 \sqrt {c^2 x^2-1} \sqrt {e x^2+d}}dx^2}{d}-\frac {2 e \sqrt {c^2 x^2-1}}{d \left (c^2 d+e\right ) \sqrt {d+e x^2}}\right )}{6 e \sqrt {c^2 x^2}}-\frac {a+b \sec ^{-1}(c x)}{3 e \left (d+e x^2\right )^{3/2}}\) |
\(\Big \downarrow \) 104 |
\(\displaystyle \frac {b c x \left (\frac {2 \int \frac {1}{-x^4-d}d\frac {\sqrt {e x^2+d}}{\sqrt {c^2 x^2-1}}}{d}-\frac {2 e \sqrt {c^2 x^2-1}}{d \left (c^2 d+e\right ) \sqrt {d+e x^2}}\right )}{6 e \sqrt {c^2 x^2}}-\frac {a+b \sec ^{-1}(c x)}{3 e \left (d+e x^2\right )^{3/2}}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {b c x \left (-\frac {2 \arctan \left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {c^2 x^2-1}}\right )}{d^{3/2}}-\frac {2 e \sqrt {c^2 x^2-1}}{d \left (c^2 d+e\right ) \sqrt {d+e x^2}}\right )}{6 e \sqrt {c^2 x^2}}-\frac {a+b \sec ^{-1}(c x)}{3 e \left (d+e x^2\right )^{3/2}}\) |
Input:
Int[(x*(a + b*ArcSec[c*x]))/(d + e*x^2)^(5/2),x]
Output:
-1/3*(a + b*ArcSec[c*x])/(e*(d + e*x^2)^(3/2)) + (b*c*x*((-2*e*Sqrt[-1 + c ^2*x^2])/(d*(c^2*d + e)*Sqrt[d + e*x^2]) - (2*ArcTan[Sqrt[d + e*x^2]/(Sqrt [d]*Sqrt[-1 + c^2*x^2])])/d^(3/2)))/(6*e*Sqrt[c^2*x^2])
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x _)), x_] :> With[{q = Denominator[m]}, Simp[q Subst[Int[x^(q*(m + 1) - 1) /(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^(1/q)], x] ] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && L tQ[-1, m, 0] && SimplerQ[a + b*x, c + d*x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[b*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1 )/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + Simp[(a*d*f*(m + 1) + b*c*f*(n + 1) + b*d*e*(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)) Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x ] && EqQ[Simplify[m + n + p + 3], 0] && (LtQ[m, -1] || SumSimplerQ[m, 1])
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.), x_S ymbol] :> Simp[1/2 Subst[Int[x^((m - 1)/2)*(a + b*x)^p*(c + d*x)^q, x], x , x^2], x] /; FreeQ[{a, b, c, d, p, q}, x] && NeQ[b*c - a*d, 0] && IntegerQ [(m - 1)/2]
Int[((a_.) + ArcSec[(c_.)*(x_)]*(b_.))*(x_)*((d_.) + (e_.)*(x_)^2)^(p_.), x _Symbol] :> Simp[(d + e*x^2)^(p + 1)*((a + b*ArcSec[c*x])/(2*e*(p + 1))), x ] - Simp[b*c*(x/(2*e*(p + 1)*Sqrt[c^2*x^2])) Int[(d + e*x^2)^(p + 1)/(x*S qrt[c^2*x^2 - 1]), x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[p, -1]
\[\int \frac {x \left (a +b \,\operatorname {arcsec}\left (c x \right )\right )}{\left (e \,x^{2}+d \right )^{\frac {5}{2}}}d x\]
Input:
int(x*(a+b*arcsec(c*x))/(e*x^2+d)^(5/2),x)
Output:
int(x*(a+b*arcsec(c*x))/(e*x^2+d)^(5/2),x)
Leaf count of result is larger than twice the leaf count of optimal. 275 vs. \(2 (114) = 228\).
Time = 0.23 (sec) , antiderivative size = 571, normalized size of antiderivative = 4.14 \[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=\left [-\frac {{\left (b c^{2} d^{3} + {\left (b c^{2} d e^{2} + b e^{3}\right )} x^{4} + b d^{2} e + 2 \, {\left (b c^{2} d^{2} e + b d e^{2}\right )} x^{2}\right )} \sqrt {-d} \log \left (\frac {{\left (c^{4} d^{2} - 6 \, c^{2} d e + e^{2}\right )} x^{4} - 8 \, {\left (c^{2} d^{2} - d e\right )} x^{2} - 4 \, \sqrt {c^{2} x^{2} - 1} {\left ({\left (c^{2} d - e\right )} x^{2} - 2 \, d\right )} \sqrt {e x^{2} + d} \sqrt {-d} + 8 \, d^{2}}{x^{4}}\right ) + 4 \, {\left (a c^{2} d^{3} + a d^{2} e + {\left (b c^{2} d^{3} + b d^{2} e\right )} \operatorname {arcsec}\left (c x\right ) + {\left (b d e^{2} x^{2} + b d^{2} e\right )} \sqrt {c^{2} x^{2} - 1}\right )} \sqrt {e x^{2} + d}}{12 \, {\left (c^{2} d^{5} e + d^{4} e^{2} + {\left (c^{2} d^{3} e^{3} + d^{2} e^{4}\right )} x^{4} + 2 \, {\left (c^{2} d^{4} e^{2} + d^{3} e^{3}\right )} x^{2}\right )}}, -\frac {{\left (b c^{2} d^{3} + {\left (b c^{2} d e^{2} + b e^{3}\right )} x^{4} + b d^{2} e + 2 \, {\left (b c^{2} d^{2} e + b d e^{2}\right )} x^{2}\right )} \sqrt {d} \arctan \left (-\frac {\sqrt {c^{2} x^{2} - 1} {\left ({\left (c^{2} d - e\right )} x^{2} - 2 \, d\right )} \sqrt {e x^{2} + d} \sqrt {d}}{2 \, {\left (c^{2} d e x^{4} + {\left (c^{2} d^{2} - d e\right )} x^{2} - d^{2}\right )}}\right ) + 2 \, {\left (a c^{2} d^{3} + a d^{2} e + {\left (b c^{2} d^{3} + b d^{2} e\right )} \operatorname {arcsec}\left (c x\right ) + {\left (b d e^{2} x^{2} + b d^{2} e\right )} \sqrt {c^{2} x^{2} - 1}\right )} \sqrt {e x^{2} + d}}{6 \, {\left (c^{2} d^{5} e + d^{4} e^{2} + {\left (c^{2} d^{3} e^{3} + d^{2} e^{4}\right )} x^{4} + 2 \, {\left (c^{2} d^{4} e^{2} + d^{3} e^{3}\right )} x^{2}\right )}}\right ] \] Input:
integrate(x*(a+b*arcsec(c*x))/(e*x^2+d)^(5/2),x, algorithm="fricas")
Output:
[-1/12*((b*c^2*d^3 + (b*c^2*d*e^2 + b*e^3)*x^4 + b*d^2*e + 2*(b*c^2*d^2*e + b*d*e^2)*x^2)*sqrt(-d)*log(((c^4*d^2 - 6*c^2*d*e + e^2)*x^4 - 8*(c^2*d^2 - d*e)*x^2 - 4*sqrt(c^2*x^2 - 1)*((c^2*d - e)*x^2 - 2*d)*sqrt(e*x^2 + d)* sqrt(-d) + 8*d^2)/x^4) + 4*(a*c^2*d^3 + a*d^2*e + (b*c^2*d^3 + b*d^2*e)*ar csec(c*x) + (b*d*e^2*x^2 + b*d^2*e)*sqrt(c^2*x^2 - 1))*sqrt(e*x^2 + d))/(c ^2*d^5*e + d^4*e^2 + (c^2*d^3*e^3 + d^2*e^4)*x^4 + 2*(c^2*d^4*e^2 + d^3*e^ 3)*x^2), -1/6*((b*c^2*d^3 + (b*c^2*d*e^2 + b*e^3)*x^4 + b*d^2*e + 2*(b*c^2 *d^2*e + b*d*e^2)*x^2)*sqrt(d)*arctan(-1/2*sqrt(c^2*x^2 - 1)*((c^2*d - e)* x^2 - 2*d)*sqrt(e*x^2 + d)*sqrt(d)/(c^2*d*e*x^4 + (c^2*d^2 - d*e)*x^2 - d^ 2)) + 2*(a*c^2*d^3 + a*d^2*e + (b*c^2*d^3 + b*d^2*e)*arcsec(c*x) + (b*d*e^ 2*x^2 + b*d^2*e)*sqrt(c^2*x^2 - 1))*sqrt(e*x^2 + d))/(c^2*d^5*e + d^4*e^2 + (c^2*d^3*e^3 + d^2*e^4)*x^4 + 2*(c^2*d^4*e^2 + d^3*e^3)*x^2)]
\[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=\int \frac {x \left (a + b \operatorname {asec}{\left (c x \right )}\right )}{\left (d + e x^{2}\right )^{\frac {5}{2}}}\, dx \] Input:
integrate(x*(a+b*asec(c*x))/(e*x**2+d)**(5/2),x)
Output:
Integral(x*(a + b*asec(c*x))/(d + e*x**2)**(5/2), x)
Exception generated. \[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(x*(a+b*arcsec(c*x))/(e*x^2+d)^(5/2),x, algorithm="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(e>0)', see `assume?` for more de tails)Is e
\[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=\int { \frac {{\left (b \operatorname {arcsec}\left (c x\right ) + a\right )} x}{{\left (e x^{2} + d\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate(x*(a+b*arcsec(c*x))/(e*x^2+d)^(5/2),x, algorithm="giac")
Output:
integrate((b*arcsec(c*x) + a)*x/(e*x^2 + d)^(5/2), x)
Timed out. \[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=\int \frac {x\,\left (a+b\,\mathrm {acos}\left (\frac {1}{c\,x}\right )\right )}{{\left (e\,x^2+d\right )}^{5/2}} \,d x \] Input:
int((x*(a + b*acos(1/(c*x))))/(d + e*x^2)^(5/2),x)
Output:
int((x*(a + b*acos(1/(c*x))))/(d + e*x^2)^(5/2), x)
\[ \int \frac {x \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx=\frac {-\sqrt {e \,x^{2}+d}\, a +3 \left (\int \frac {\mathit {asec} \left (c x \right ) x}{\sqrt {e \,x^{2}+d}\, d^{2}+2 \sqrt {e \,x^{2}+d}\, d e \,x^{2}+\sqrt {e \,x^{2}+d}\, e^{2} x^{4}}d x \right ) b \,d^{2} e +6 \left (\int \frac {\mathit {asec} \left (c x \right ) x}{\sqrt {e \,x^{2}+d}\, d^{2}+2 \sqrt {e \,x^{2}+d}\, d e \,x^{2}+\sqrt {e \,x^{2}+d}\, e^{2} x^{4}}d x \right ) b d \,e^{2} x^{2}+3 \left (\int \frac {\mathit {asec} \left (c x \right ) x}{\sqrt {e \,x^{2}+d}\, d^{2}+2 \sqrt {e \,x^{2}+d}\, d e \,x^{2}+\sqrt {e \,x^{2}+d}\, e^{2} x^{4}}d x \right ) b \,e^{3} x^{4}}{3 e \left (e^{2} x^{4}+2 d e \,x^{2}+d^{2}\right )} \] Input:
int(x*(a+b*asec(c*x))/(e*x^2+d)^(5/2),x)
Output:
( - sqrt(d + e*x**2)*a + 3*int((asec(c*x)*x)/(sqrt(d + e*x**2)*d**2 + 2*sq rt(d + e*x**2)*d*e*x**2 + sqrt(d + e*x**2)*e**2*x**4),x)*b*d**2*e + 6*int( (asec(c*x)*x)/(sqrt(d + e*x**2)*d**2 + 2*sqrt(d + e*x**2)*d*e*x**2 + sqrt( d + e*x**2)*e**2*x**4),x)*b*d*e**2*x**2 + 3*int((asec(c*x)*x)/(sqrt(d + e* x**2)*d**2 + 2*sqrt(d + e*x**2)*d*e*x**2 + sqrt(d + e*x**2)*e**2*x**4),x)* b*e**3*x**4)/(3*e*(d**2 + 2*d*e*x**2 + e**2*x**4))